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  • mvc - how to avoid log out when refresh a page

    - by user235973457
    I have built the MVC application with WCF service. The major problem I have experienced with refreshing page. I have created a login page with session (username and password). But when you refresh the home page by pressing F5, it would automatically log out. That is my problem. I need to stay the home page after refresh. I have been googling around to find a solution but it seems not helpful. Any idea? Your advise or code example much appreciated.

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  • findBy(x) Using Zend_Navigation with custom route

    - by Stephen
    I am creating my navigation from a db generated array and defining which route to use for some of the uris. when I set the route i am no longer able to use findByUri() as the uri seems to be moved under the properties key example array being used: [id] => 7 [label] => Legal [controller] => index [uri] => /legal [route] => cmsPage [visible] => 1 [params] => Array ( [first] => legal ) snippet of the output: [_properties:protected] => Array ( [uri] => /legal [created] => 2012-10-20 10:23:23 ) When I don't define the route I am able to use findByUri() successfully. currently I am looping through each to find the property that matches the request but it seems a long / wrong approach Is there a way to search by the nested param - or am i doing something wrong with the setup (everything else behaves as expected)

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  • PHP-How to choose XML section based on an attribute?

    - by Vincent
    All, I have a config xml file in the following format: <?xml version="1.0"?> <configdata> <development> <siteTitle>You are doing Development</siteTitle> </development> <test extends="development"> <siteTitle>You are doing Testing</siteTitle> </test> <production extends="development"> <siteTitle>You are in Production</siteTitle> </production> </configdata> To read this config file to apply environment settings, currently I am using, the following code in index.php file: $appEnvironment = "production"; $config = new Zend_Config_Xml('/config/settings.xml', $appEnvironment ); To deploy this code on multiple environments, as user has to change index.php file. Instead of doing that, is it possible to maintain an attribute in the xml file, "say active=true". Based on which the Zend_Config_Xml will know which section of the xml file settings to read? Thanks

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  • encode array to JSON in PHP to get [elm1,elm2,elm3] instead of {elm1:{},elm2:{},elm3:{}}

    - by Itay Moav
    I am trying to json_encode an array, which is what returns from a Zend_DB query. var_dump gives: (Manually adding 0 member does not change the picture). array(3) { [1]=> array(3) { ["comment_id"]=> string(1) "1" ["erasable"]=> string(1) "1" ["comment"]=> string(6) "test 1" } [2]=> array(3) { ["comment_id"]=> string(1) "2" ["erasable"]=> string(1) "1" ["comment"]=> string(6) "test 1" } [3]=> array(3) { ["comment_id"]=> string(1) "3" ["erasable"]=> string(1) "1" ["comment"]=> string(6) "jhghjg" } } The encoded string looks: {"1":{"comment_id":"1","erasable":"1","comment":"test 1"}, "2":{"comment_id":"2","erasable":"1","comment":"test 1"}, "3":{"comment_id":"3","erasable":"1","comment":"jhghjg"}} While I need it as: [{"comment_id":"1","erasable":"1","comment":"test 1"}, {"comment_id":"2","erasable":"1","comment":"test 1"}, {"comment_id":"3","erasable":"1","comment":"jhghjg"}] As the php.ini/json__encode documentation says it should. Any ideas?

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  • Zend_Router requirements mismatch

    - by elbicho
    Hello you all: I have two routes that match a url with the same apparent pattern, the difference lies in the $actionRoute, this should only be matched if the variable :action on it equals 'myaction'. If I go to /en/mypage/whatever/myaction it goes as expected through $actionRoute. If I go to /en/mypage/whatever/blahblah it gets rejected by $actionRoute and matched by $genRoute. If I go to /en/mypage/whatever it should be matched by $genRoute but it gets matched by $actionRoute instead throwing and exception because the action noactionAction() does not exist. Don't know what I'm doing wrong, I'd appreciate your help. $genRoute = new Zend_Controller_Router_Route( ':lang/mypage/:var1/:var2', array( 'lang' => '', 'module' => 'mymodule', 'controller' => 'index', 'action' => 'index', 'var1' => 'noone', 'var2' => 'no' ), array( 'var1' => '[a-z\-]+?', 'lang' => '(es|en|fr|de){1}' ) ); $actionRoute = new Zend_Controller_Router_Route( ':lang/mypage/:var1/:action', array( 'lang' => '', 'module' => 'mymodule', 'controller' => 'index', 'action' => 'noaction', 'var1' => 'noone', ), array( 'action' => '(myaction)+?', 'var' => '[a-z\-]+?', 'lang' => '(es|en|fr|de){1}', ) ); $router->addRoute('genroute',$genRoute); $router->addRoute('actionroute',$actionRoute);

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  • Bind to a collection's view and just call ToString() in WPF

    - by womp
    I'm binding a GridView to a collection of objects that look like this: public class Transaction { public string PersonName { get; set; } public DateTime TransactionDate { get; set; } public MoneyCollection TransactedMoney { get; set;} } MoneyCollection simply inherits from ObservableCollection<T>, and is a collection of MyMoney type object. In my GridView, I just want to bind a column to the MoneyCollection's ToString() method. However, binding it directly to the TransactedMoney property makes every entry display the text "(Collection)", and the ToString() method is never called. Note that I do not want to bind to the items in MoneyCollection, I want to bind directly to the property itself and just call ToString() on it. I understand that it is binding to the collection's default view. So my question is - how can I make it bind to the collection in such a way that it calls the ToString() method on it? This is my first WPF project, so I know this might be a bit noobish, but pointers would be very welcome.

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  • MVC JsonResult with the [Authorize] attribute going to Logon but not displaying the view

    - by likestoski
    I am seeing odd behavior with MVC 3 methods that return a JsonResult when used with the Authorize attribute. What looks like happens is the Authorize is correctly evaluated when I am not logged in but instead of redirecting to the logon form the Json response is the logon form. Is there an addition attribute that directs the response to not return a value but instead redirect the user to the logon form, preferebly with the correct returnUrl value? What I did as a demo was to setup a new MVC3 site and added AspNetMembership to my DB using the aspnet_regsql.exe command. All that is setup and logging me in correctly. The behavior of the JsonResult doesn't seem right and I'm hoping I have just missed an attribute to make it work properly. Any help is greatly appreciated, thanks in advance. Here is the Account Controller (leaving out the Post action which is not part of this question). public class AccountController : Controller { public ActionResult LogOn() { return View(); } [Authorize] public JsonResult AuthorizedAction() { return Json("Only returns if I am authorized"); } } Here is the Html markup: <script src="@Url.Content("~/Scripts/jquery-ui-1.8.11.min.js")" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function () { $("#btnTest").click(function () { $.ajax({ type: "POST", url: "Account/AuthorizedAction", data: {}, success: function (result) { $("#testMe").html(result); }, error: function (result) { $("#testMe").html('Something broke in the ajax request'); } }); }); }); </script> <input type="button" id="btnTest" value="Test me" /> <div id="testMe">I have initial text</div> The Result: 1) When logged in I get 'Only returns if I am authorized' in my test div 2) When not logged and I have a break point in my Logon() method I see this value Request["returnUrl"] "/Account/AuthorizedAction" The test div I have displays the logon form :) this seems like I'm just not handling this properly.

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  • zend_db and join

    - by premtemp
    Hello, I am trying to understand how to use Zend_DB in my program but I have some problem. The class below (DatabaseService) work when I pass it a simple query. However, if I pass it it query with a join clause my page just hangs and not error is return. I cut and paste the qry in a query browesr and it is valid Any help would be great $SQL = "select name from mytable" $db = new DatabaseService($dbinfo) $db ->fetchall($SQL ) // works ----------------------------------------------------------- $SQL = "select count(*) as cnt from EndPoints join CallID on EndPoints.`CallID` = CallID.CallID where EndPoints.LastRegister >= '2010-04-21 00:00:01' and EndPoints.LastRegister <= '2010-04-21 23:59:59' " $db = new DatabaseService($dbinfo) $db ->fetchall($SQL ) // DOES NO WORK class DatabaseService { function DatabaseService($dbinfo,$dbname="") { try { $dbConfig = array( 'host' => $this->host, 'username' => $this->username, 'password' => $password, 'dbname' => $this->dbname ); $this->db = Zend_Db::factory($this->adapter, $dbConfig); Zend_Db_Table::setDefaultAdapter($this->db); } catch(Zend_Exception $e) { $this->error = $e->getMessage(); Helper::log($this->error); return false; } } public function connnect() { if($this->db !=null) { try { $this->db->getConnection(); return true; } catch (Zend_Exception $e) { $err = "FAILED ::".$e->getMessage()." <br />"; } } return false; } public function fetchall($sql) { $res= $this->db->fetchAll($sql); return $res; } }

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  • Zend_Form: Is this really the way we should be doing things?

    - by Francis Daigle
    OK. I understand how to use Zend_Form and it's implementation of the decorator pattern. My question is, is this the best way to be going about creating forms? Shouldn't a documents forms be left to to the front-end rather than generating forms programmatically? Doesn't this kinda violate the whole idea of keeping things separate? I mean, really, even providing that you have a good understanding of the methodology being employed, does it really save one that much time? I guess what I'm looking for is some guidance as to what might be considered 'best practice'. I'm not saying that Zend_Form doesn't have it's place, I'm just wondering if it should be used in all cases (or not). And this has nothing to do with validation. I'm just thinking that something more akin to using the 'ViewScript' approach might be more appropriate in most cases. Your thoughts?

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  • Building a calendar navigation in Rails (controller and view links)

    - by user532339
    Trying to get the next month when clicking the link_to. I've done the following in the view. <%= form_tag rota_days_path, :method => 'get' do %> <p> <%= hidden_field_tag(:next_month, @t1) %> <%= link_to 'Next Month', rota_days_path(:next_month => @next_month)%> </p> <% end %> class RotaDaysController < ApplicationController # GET /rota_days # GET /rota_days.json # load_and_authorize_resource respond_to :json, :html def index @rota_days = RotaDay.all @hospitals = Hospital.all @t1 = Date.today.at_beginning_of_month @t2 = Date.today.end_of_month @dates = (@t1..@t2) #Concat variable t1 + t2 together # @next_month = Date.today + 1.month(params[: ??? ] #Old if params[:next_month] # @next_month = Date.today >> 1 @next_month = params[:next_month] + 1.month @t1 = @next_month.at_beginning_of_month @t2 = @next_month.end_of_month @dates = (@t1..@t2) end @title = "Rota" respond_to do |format| format.html # index.html.erb format.json { render json: @rota_days } end end I have identified that the reason why this may not be working is in because of the following in my controller @next_month = params[:next_month] + 1.month the last two called methods is defined only on time/date objects. but not on fixnum/string objects. I understand I am missing something from this Update I have found that the actual issue is that the `params[:next_month] is a string and I am trying to add a date to to it. Which means I need to convert the string to a date/time object. Console output: Started GET "/rota_days" for 127.0.0.1 at 2012-12-14 22:14:36 +0000 Processing by RotaDaysController#index as HTML User Load (0.0ms) SELECT `users`.* FROM `users` WHERE `users`.`id` = 1 LIMIT 1 RotaDay Load (0.0ms) SELECT `rota_days`.* FROM `rota_days` Hospital Load (1.0ms) SELECT `hospitals`.* FROM `hospitals` Rendered rota_days/index.html.erb within layouts/application (23.0ms) Role Load (0.0ms) SELECT `roles`.* FROM `roles` INNER JOIN `roles_users` ON `roles`.`id` = `roles_users`.`role_id` WHERE `roles_users`.`user_id` = 1 AND `roles`.`name` = 'Administrator' LIMIT 1 Completed 200 OK in 42ms (Views: 39.0ms | ActiveRecord: 1.0ms)

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  • Zend_Registry: real life examples

    - by takeshin
    Do you find Zend_Registry useful? For which tasks it should be used? For which not? Global state for variables is not a good practice. Main objects may have global state injected via $front->setParam('paramName', $object), so what's the purpose of Zend_Registry?.

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  • problem in add custom error message in zend_element

    - by user1400
    hello all i created a text element like following code $test = $this->createElement('text', 'test'); $test->setLabel('test:'); $test->addValidator(new Zend_Validate_Int()); $test->addErrorMessages(array('isEmpty'=>'u should enter a number','%value% is not integer')); $shomare->setRequired(true); $this->addElement($test); when i set empty or non integer number to textbox , it show both its own error message , if its empty errormessage="u should enter a number" and when it is not a valid integer it shows '%value% is not integer' thanks

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  • Show menu when view is long pressed

    - by swift1691
    I've been looking around on the internet regarding my question but I couldn't find a straight answer. Is it possible to create a non-blocking menu similar to the overflow menu found in Android 4.0+ when a view is long pressed? I have a number of LinearLayout instances which have an OnLongClickListener which brings up a context menu, but it's not exactly what I am looking for. I was hoping for a smoother menu which is brought up when one of these instances is clicked, and removed when the user clicks outside of the menu's region. This is very similar to the way the overflow menu behaves in the Android ActionBar. So to sum up, is it possible to replicate the look-and-fell and the behavior of the overflow menu when using context menus? Here's hoping I don't have to jump through hoops to get the implementation that I desire. Thanks in advance. EDIT: After some digging I've found the PopupMenu which is exactly what I was looking for however it works only on devices running Honeycomb and above. Does anyone know of a way with which I can replicate this menu behavior in older versions of Android without using blocking windows like dialogs?

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  • How to use the Zend_Log instance that was created using the Zend_Application_Resource_Log in a model

    - by Alex
    Our Zend_Log is initialized by only adding the following lines to application.ini resources.log.stream.writerName = "Stream" resources.log.stream.writerParams.mode = "a" So Zend_Application_Resource_Log will create the instance for us. We are already able to access this instance in controllers via the following: public function getLog() { $bootstrap = $this->getInvokeArg('bootstrap'); //if (is_null($bootstrap)) return false; if (!$bootstrap->hasPluginResource('Log')) { return false; } $log = $bootstrap->getResource('Log'); return $log; } So far, so good. Now we want to use the same log instance in model classes, where we can not access the bootstrap. Our first idea was to register the very same Log instance in Zend_Registry to be able to use Zend_Registry::get('Zend_Log') everywhere we want: in our Bootstrap class: protected function _initLog() { if (!$this->hasPluginResource('Log')) { throw new Zend_Exception('Log not enabled'); } $log = $this->getResource('Log'); assert( $log != null); Zend_Registry::set('Zend_Log', $log); } Unfortunately this assertion fails == $log IS NULL --- but why?? It is clear that we could just initialize the Zend_Log manually during bootstrapping without using the automatism of Zend_Application_Resource_Log, so this kind of answers will not be accepted.

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  • My store returns no code id and breaks 404 error. Magento

    - by numerical25
    I know what the issue is but I dont know how to fix it. I just migrated my magento store locally and I guess possibly some data may have been lost when transferring the DB. the DB is very large. Anyhow, when I login to my admin page, I get a 404 error, page was not found. I debugged the issue and got down to the wire. The exception is thrown in Mage/Core/Model/App.php. Line 759 to be exacted. The following is a snippet. Mage/Core/Model/App.php if (empty($this->_stores[$id])) { $store = Mage::getModel('core/store'); /* @var $store Mage_Core_Model_Store */ if (is_numeric($id)) { $store->load($id); // THIS ID IS FROM Mage_Core_Model_App::ADMIN_STORE_ID and its empty which causes the error } elseif (is_string($id)) { $store->load($id, 'code'); } if (!$store->getCode()) { // RETURNS FALSE HERE BECAUSE NO ID Specified $this->throwStoreException(); } $this->_stores[$store->getStoreId()] = $store; $this->_stores[$store->getCode()] = $store; } The store returns null because $id is null so it therefore does not load any model which explains why it returns false when calling getCode() [EDIT] If you want clarification, please ask for more before voting my post down. Remember I am still trying to get help not get neglected. I am using Version 1.4.1.1. When I type in the URL for admin, I get a 404 page. I walked through the code thouroughly and found that the Model MAGE_CORE_MODEL_STORE::getCode(); Returns Null which triggers the exception. and ends the script. I do not have any other detail. I further troubleshooted the issue by checking the database and that is what the screen shot is. Showing that there is infact data in the Code Colunn. So my question is why is the Model returning a empty column when the column clearly has a value. What can I do to further troubleshoot and figure out why its not working [EDIT UPDATE NEW] I did some research. the reason its returning NULL is because the store ID is null being passed Mage::getStoreConfigFlag('web/secure/use_in_adminhtml', Mage_Core_Model_App::ADMIN_STORE_ID); // THIS IS THE ID being specified Mage_Core_Model_App::ADMIN_STORE_ID has no value in it, so this method throws the exception. Not sure why how to fix this.

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  • Serialising my JSON output problem in JQuery

    - by davykiash
    Am trying to validate my form using an AJAX call $("#button").click(function() { $.ajax({ type: "POST", url: "<?php echo $this->baseUrl() ?>/expensetypes/async", data: 'fs=' + JSON.stringify($('#myform').serialize(true)), contentType: "application/json; charset=utf-8", dataType: "json" }); }); On my controller my code is as follows //Map the form from the client-side call $myFormData = Zend_Json::decode($this->getRequest()->getParam("fs") ,Zend_Json::TYPE_ARRAY); $form = new Form_Expensetypes(); $form->isValid($myFormData); However from firebug my output is as follows fs="id=&expense_types_code=AAA&expense_types_desc=CCCC&expense_types_linkemail=XXXX&expense_types_budgetamount=22222&expense_types_budgetperiod=22222" What I expect is something similar to fs{"expense_types_code":"AAA","expense_types_desc":"CCCC","expense_types_linkemail":"XXXX","expense_types_budgetamount":"22222"} How do I achieve this type of serialisation?

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  • Pass 2-dimensional array trough view

    - by Mikael
    Hi, I'm trying to print a 2-dimensional array but can't figure it out. My controller uses this code: public ActionResult Test(string str) { DateTimeOffset offset = new DateTimeOffset(DateTime.Now); offset = offset.AddHours(-5); string[,] weekDays = new string[7,2]; for (int i = 0; i < 7; i++) { weekDays[i,0] = String.Format("{0:yyyy-MM-dd:dddd}", offset); //Date weekDays[i,1] = String.Format("{0:dddd}", offset); //Text offset = offset.AddHours(24); } weekDays[0,1] = "Today"; ViewData["weekDays"] = weekDays; return View(); } Now I wan't to print this array of weekdays as a dropdown-list and i thought this would work: <% foreach (var item in (string[,])ViewData["weekDays"]) { %> <option value=" <%= item[0] %> "> <%= item[1] %> </option> <% } %> But that's not the case, this code output just the first char of the string. So anyone got a suggestion? Thanks! /M

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  • Display TableViews corresponding to segmentedControl in a single tableview without pushing a new view

    - by user1727927
    I have a tableViewController where I have used the Interface Builder to insert a Segmented Controller having two segments. Since by default, first segment is always selected, I am not facing any problem in displaying the tableview corresponding to first segment. However, when I click on the second segment, I want to display another tableView. Here goes the problem. I am calling newTableViewController class on clicking the second segment. Hence, this view is getting pushed instead. Please suggest me a method to have these two tableViews in the main tableView upon clicking the segments. I have used switch case for switching between the segments. Here's the relevant part of the code: This method is in the FirstTableViewController since first segment is by default selected. -(IBAction) segmentedControlChanged { switch(segmentedControl.selectedSegmnentIndex) { case 0: //default first index selected. [tableView setHidden:NO]; break; case 1: NewViewController *controller=[[NewViewController alloc] initWithNibName:@"NewViewController" bundle:nil]; self.navigationController pushViewController:controller animated:YES]; [controller release]; break; default: break; } }

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  • How can I use Tier Pricing with Configurable Products? (Magento 1.4+)

    - by Rad The Mad
    How can I use/setup Tier Pricing with Configurable Products? (Magento 1.4+) There was an extension to do this but I think it is only for Magento 1.3. Tried to setup tiers in my Simple Products, but those do not show up, or do not activate when I add to cart from my Config Product page. Any help is appreciated! Thanks. Edit: In my case, I would like to use the Tier Pricing FROM the Simple Product. and not use the Tier Pricing from the Config. Product

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