Search Results

Search found 15323 results on 613 pages for 'db2 connect'.

Page 147/613 | < Previous Page | 143 144 145 146 147 148 149 150 151 152 153 154  | Next Page >

  • Enable PyGTK Eventbox motion-notify-event while is a Layout child

    - by mkotechno
    I noticed when a Eventbox is added into a Layout some events are missed, this does not happend for example adding it to a Fixed (very similar widget), I tried to restore the event mask in this way with no sucess: import pygtk import gtk def foo(widget, event): print event pygtk.require('2.0') window = gtk.Window(gtk.WINDOW_TOPLEVEL) window.connect('destroy', lambda x: gtk.main_quit()) eventbox = gtk.EventBox() eventbox.connect('button-press-event', foo) # works eventbox.connect('motion-notify-event', foo) # fail eventbox.set_events( gtk.gdk.BUTTON_MOTION_MASK| # restoring missed masks gtk.gdk.BUTTON1_MOTION_MASK| gtk.gdk.BUTTON2_MOTION_MASK| gtk.gdk.BUTTON3_MOTION_MASK) layout = gtk.Layout() image = gtk.image_new_from_file('/home/me/picture.jpg') layout.add(image) eventbox.add(layout) window.add(eventbox) window.show_all() gtk.main() How should I restore the missed event/mask?

    Read the article

  • creating a wrapper around a 3rd party assembly - swap out and decouple

    - by mrblah
    I have an email component that I am integrating into my application, looking for some tips on how should build a wrapper around it so I can swap it out with another 3rd party component if needed. My approach right now is it: build an interface will the functionality I need. create a class that implements the interface, using my 3rd party component inside this class. any usage of this component will be via the interface so like: IPop3 pop3 = new AcmeIncePop3Wrapper(); pop3.connect(); and inside AcmeIncePop3Wrapper will be: public void connect() { AcmeIncePop3 pop = new AcmeIncePop3(); pop.connect(); } Is that a good approach? I could probably add another abstraction by using ninject so I could swap out implementations, but really this seems to be all I need as i don't expect to be changing 3rd party assemblies every day, just don't want to make things so tightly coupled.

    Read the article

  • Qt - arguments in signal-slots

    - by bullettime
    I have a QPushButton, QDateEdit and another custom object. I want to connect the button to the date edit object in a way that when I click the button, the date edit object will change its set date to a date defined on the custom object. Kinda like this: connect(pushbutton,SIGNAL(clicked()),dateedit,SLOT(setDate(custom_object.getDate()))); but I can't do that. Apparently, the connect statement doesn't specify what's the information being passed from the signal to the slot, only the type of the information being passed. Is there a way to do this without having to create a new class?

    Read the article

  • SQL server 2005 remote connection problem, cannot solve it help please thank you

    - by user287745
    note:- if this question does not fit this site please do not just close it but also redirect the question to the fitting sister site, thank you" the steps taken and the error are mentioned please help, i am stuck here! installed sql server 2005 express on both computers installed sql server management studio express on both computers ran each management studio and connect to instance sqlserver using windows authentication ( one computer connection example "A-63A9D4D7E7834\SQLEXPRESS" ) created a database in the databases named as "test1" created a few tables with data saved and exit. did everything what this site says " How to configure SQL Server 2005 to allow remote connections" [add h t t p here as spam prevention] ://support.microsoft.com/kb/914277/en-us" but i have just disable the firewalls completely :turn off connecting to A-63A9D4D7E7834 started "SQL Server Management Studio Express" on computer A-63A9D4D7E7834 sever name: "ALL-E425BE6C41D\SQLEXPRESS" authentication: "windows authentication" and CONNECT I GET THE FOLLOWING ERROR Cannot connect to ALL-E425BE6C41D\SQLEXPRESS. ADDITIONAL INFORMATION: Login failed for user 'ALL-E425BE6C41D\Guest'. (Microsoft SQL Server, Error: 18456) For help, click: http://go.microsoft.com/fwlink?ProdName=Microsoft+SQL+Server&EvtSrc=MSSQLServer&EvtID=18456&LinkId=20476 BUTTONS: OK HELP

    Read the article

  • Connecting PC via Bluetooth SNP

    - by Nicholas
    Hi, I have a widcomm example BluChat "WIDCOMM SDK RFComm Service" running on my PC with an USB dongle (BT-2400P). I would like to connect this chat from my HTC Desire. So I stared with the Java example http://developer.android.com/resources/samples/BluetoothChat/index.html. This is also using BT RFComm. If I'm using my HTC as a server it work's fine, but I would like to use my PC as a server. Then .connect() comes back with "Service Discovery Failure". I have modified the UUID string in the Java example to match the PC-application mmSocket = mmDevice.createRfcommSocketToServiceRecord(UUID.fromString("5fc2a42e-144e-4bb5-b43f-4e61711d1c32")); mmSocket.connect(); What is missing? Any help appreciated. Nicholas

    Read the article

  • C# Proxy using Sockets, how should I do this?

    - by Kin
    I'm writing a proxy using .NET and C#. I haven't done much Socket programming, and I am not sure the best way to go about it. What would be the best way to implement this? Should I use Synchronous Sockets, Asynchronous sockets? Please help! It must... Accept Connections from the client on two different ports, and be able to receive data on both ports at the same time. Connect to the server on two different ports, and be able to send data on both ports as the same time. Immediately connect to the server and start forwarding packets as soon as a client connection is made. Forward packets in the same order they were received. Be as low latency as possible. I don't need the ability for multiple clients to connect to the proxy, but it would be a nice feature if its easy to implement. Client --------- Proxy ------- Server ---|-----------------|----------------| Port <-------- Port <------- Port Port <-------- Port <------- Port

    Read the article

  • FBConnect - uploading images to Wall

    - by SteveU
    Hi All, i've configured FBConnect and it uploads to the wall, but what i want to do is take a screenshot and then upload the screenshot to FB. In the below code there is an image but as a url. Can i intersect this and put in my screenshot image? FBStreamDialog *dialog = [[[FBStreamDialog alloc] init]autorelease]; dialog.userMessagePrompt = @"Tell your friends about Fridgit!!:"; dialog.attachment = [NSString stringWithFormat:@"{\"name\":\"Facebook Connect for iPhone\",\"href\":\"http://developers.facebook.com/connect.phptab=iphone\",\"caption\":\"Caption\",\"description\":\"Description\",\"media\":[{\"type\":\"image\",\"src\":\"screenShot\",\"href\":\"http://developers.facebook.com/connect.php?tab=iphone/\"}],\"properties\":{\"another link\":{\"text\":\"Facebook home page\",\"href\":\"http://www.facebook.com\"}}}", self.screenShot]; [dialog show]; } i know all the code is default i haven't edited it yet incase i can't do what i want to do. Cheers

    Read the article

  • Active Directory public key use

    - by Chris Meadows
    I have a client who has a requirement to validate users logging into my web application against his active directory using LDAP. In trying to connect using the DirectoryEntry and DirectorySearcher .NET classes, I can connect to his AD Server but not access it. The client's AD server has an SSL Certificate for which he has given me a public key file but I don't know how to use this public key file in my C# code. When I issue the connect command through code, I see, via Wireshark, my application sending the connection request. I then see the server responding with "Server Hello, Certificate, Certificate Request, Server Hello Done". Then my application never responds after that. In using another application, written by somebody else for which I do not have code, I see the same request from the server and then see the application respond with "Certificate, Client Key Exchange" and then the application connects and runs. With that said, my question then becomes, how can I get my C# application to load and send the key file I got from the client?

    Read the article

  • Setting up a SQL server outside the domain

    - by Ben
    Hi, im very new to this. I've set up an account "SQLBOX" thats on the a network, but not connected to the domain. I have installed an instance of SQL Server 2008 and am trying to connect to it from another machine on the network but am getting "Cannot connect to "SQLBOX"". From the "SQLBOX" i can connect to sqlservers on the domain, but not vice-versa. Any help would be greatly appreciated. Sorry if the description isn't great. EDIT I can ping the box from a machine on the domain

    Read the article

  • Reading data from a socket

    - by Bobby
    I am having issues reading data from a socket. Supposedly, there is a server socket that is waiting for clients to connect. When I write a client to connect() to the server socket/port, it appears that I am connected. But when I try to read() data that the server is supposedly writing on the socket, the read() function hangs until the server app is stopped. Why would a read() call ever hang if the socket is connected? I believe that I am not ever really connected to the socket/port but I can't prove it, b/c the connect() call did not return an error. The read() call is not returning an error either, it is just never returning at all.

    Read the article

  • How to replace a Widget with another using Qt ?

    - by Natim
    Hi, I have an QHBoxLayout with a QTreeWidget on the left, a separator on the middle and a widget on the right. When I click on the QTreeWidget, I want to change the widget on the right to modify the QTreeWidgetItem I tried to do this with this code : def new_rendez_vous(self): self.ui.horizontalLayout_4.removeWidget(self.ui.editionFormWidget) del self.ui.editionFormWidget self.ui.editionFormWidget = RendezVousManagerDialog(self.parent) self.ui.editionFormWidget.show() self.ui.horizontalLayout_4.addWidget(self.ui.editionFormWidget) self.connect(self.ui.editionFormWidget, QtCore.SIGNAL('saved'), self.scheduleTreeWidget.updateData) def edit(self, category, rendez_vous): self.ui.horizontalLayout_4.removeWidget(self.ui.editionFormWidget) del self.ui.editionFormWidget self.ui.editionFormWidget = RendezVousManagerDialog(self.parent, category, rendez_vous) self.ui.editionFormWidget.show() self.ui.horizontalLayout_4.addWidget(self.ui.editionFormWidget) self.connect(self.ui.editionFormWidget, QtCore.SIGNAL('saved'), self.scheduleTreeWidget.updateData) def edit_category(self, category): self.ui.horizontalLayout_4.removeWidget(self.ui.editionFormWidget) del self.ui.editionFormWidget self.ui.editionFormWidget = CategoryManagerDialog(self.parent, category) self.ui.editionFormWidget.show() self.ui.horizontalLayout_4.addWidget(self.ui.editionFormWidget) self.connect(self.ui.editionFormWidget, QtCore.SIGNAL('saved'), self.scheduleTreeWidget.updateData) But it doesn't work and all the widgets are stacked up on each other : . Do you know how I can remove the old widget and next display the new one ?

    Read the article

  • Weird Rails URL issue when rendering a new action

    - by Tony
    I am rendering a new action but somehow getting the "index" URL. To be more specific, my create action looks like this: class ListingsController < ApplicationController def create @listing = Listing.new(params[:listing]) @listing.user = @current_user if @listing.save redirect_to @listing else flash[:error] = "There were errors" render :action => "new" end end end When there are errors, I get the "new" action but my URL is the index URL - http://domain.com/listings Anyone know why this would happen? My routes file is fairly standard: map.connect 'listings/send_message', :controller => 'listings', :action => 'send_message' map.resources :listings map.root :controller => "listings" map.connect ':controller/:action/:id' map.connect ':controller/:action/:id.:format'

    Read the article

  • How Do I insert Data in a table From the Model MVC?

    - by user54197
    I have data coming into my Model, how do I setup to insert the data in a table? public string Name { get; set; } public string Address { get; set; } public string City { get; set; } public string State { get; set; } public string Zip { get; set; } public Info() { using (SqlConnection connect = new SqlConnection(connections)) { string query = "Insert Into Personnel_Data (Name, StreetAddress, City, State, Zip, HomePhone, WorkPhone)" + "Values('" + Name + "','" + Address + "','" + City + "','" + State + "','" + Zip + "','" + ContactHPhone + "','" + ContactWPhone + "')"; SqlCommand command = new SqlCommand(query, connect); connect.Open(); command.ExecuteNonQuery(); } } The Name, Address, City, and so on is null when the query is being run. How do I set this up?

    Read the article

  • Recognition source of event in PyQT

    - by xTrol
    Hi, I`m starting with PyQt4 and right now I have a problem with events. I have one main class let say MainWindow. MainWindow has a list of buttons of type ButtonX (inherence form QPushButton). I would like to achieve one of 2 solutions (depends which is easier). 1) After click one of the button from the list I would like to run a one method of MainWindow. I would like to be able to read a source of event there (recognize clicked button) 2) Second solution is to run a method defined in ButtonX class. What I tried is: QtCore.QObject.connect(self.getButton(0, 0), QtCore.SIGNAL("clicked()"), self.getButton(0, 0).buttonMethod()) QtCore.QObject.connect(self.getButton(0, 0), QtCore.SIGNAL("clicked()"), self.getButton(0, 0), QtCore.SLOT("incrementValue()")) and even this line occure suspend Python interpreter QtCore.QObject.connect(self.getButton(0, 0), QtCore.SIGNAL("clicked()"), self.getButton(0, 0), QtCore.SLOT("incrementValue"))

    Read the article

  • Device Emulator Mananger and ActiveSync

    - by Vaccano
    I use Device Emulator Manager to fire up my Windows Mobile 5 Emulator. I then right click on the device (in the Device Emulator Manager list) and select cradle. ActiveSync then ties to connect. After a few seconds I get this message: Then if I open up the connection options and press connect: Then it works just fine. So, my question is, how can I get it to connect every time. Right as I cradle. I do this enough times that it is annoying to have the extra step. Has anyone ever been able to figure this out? (Does anyone have this problem too?) FYI My co-workers have the same issue Connecting a real device does not have this issue (It is just when I use an emulator)

    Read the article

  • Excel File opened under Ubuntu, read by R, OpenOffice

    - by Vishal Belsare
    I have a bunch of Excel files which are updated on a daily basis on a Windows machine. I transfer them to a Ubuntu machine and want to open them there. Specifically, I want to read the files as a database under R. A couple years ago, I used ODBC under a Windows machine to open Excel files through R. Is there any way, I can do this with R under Ubuntu? I could make a database .ODB file for the corresponding XLS files using OpenOffice, but I don't know of a way to connect to a .ODB database. OpenOffice seems to have ways to connect TO databases, but no way to connect to ODB. Thanks for any potential solutions.

    Read the article

  • iPhone StoreKit development: Can't create a test user?

    - by Cruinh
    I'm trying to get up to speed on how to develop an in-app store using the new 3.0 SDK... but I'm a bit stuck in that I don't seem to be able to create a test account. The iTunes Connect FAQ states "To create test users for your sandbox environment, go to the Manage Users section of iTunes Connect and select In App Purchase Test User. Your test users will not have iTunes Connect access. They will just have access to the sandbox environment." ...but when I go to that Manage Users section, there's no mention of any sort of "In App Purschase Test User" or how to make one. Did I miss doing something to enable that? There is another section of that same FAQ that seems to suggest I need to have a paid app in the store first? Is that the reason I can't even use the test environment?

    Read the article

  • resetting the image in an NSView

    - by Josan
    I think this is a very simple question, but I’m new to programming so I may be going about it in a wrong-headed way. I have a basic understanding of Objective-C writing terminal applications and am teaching myself how to use the Cocoa GUI. I understand how to use IBOutlet and IBAction to connect a simple button to a method that will repeatedly send random numbers to a textfield . I understand how to add a NSView file, connect it to a custom view in interface builder and draw a path through random points in the view when the application launches. (I’ve been putting this code inside the - (void)drawRect:(NSRect)dirtyRect method that is declared when the file is created). What I can’t seem to figure out is how to connect a button to an action that will then ‘refresh’ the view – in this case repopulate it with another set of random points connected with a path. Looking at the documentation, I think I should somehow be using – (void) setNeedsDisplay(BOOL)flag but nothing I have tried so far had worked. Please tell me, what am I missing here?

    Read the article

  • Obtaining the server IP address in WCF?

    - by chris
    How can I obtain the server IP address that was used to connect to a service? The server has multiple IP addresses and I need to know which one the client is connected to. So far I only found that OperationContext.Current.EndpointDispatcher.EndpointAddress and OperationContext.Current.Channel.LocalAddress contain the address from .config (e.g. localhost) OperationContext.Current.IncomingMessageProperties.Via contains the Url that the client used to connect to the server (but this might just be a name from the clients hosts file). EDIT - Sorry, I wasn't being clear enough: The server needs to know which of its IP addresses were used by the client. E.g. the server has the addresses 10.0.0.1 and 10.0.0.2. when processing the request the server service needs to know if 10.0.0.1 or 10.0.0.2 was used by the client to connect to it.

    Read the article

  • SQL server 2055 remote connection problem, cannot solve it help please thank you

    - by user287745
    note:- if this question does not fit this site please do not just close it but also redirect the question to the fitting sister site, thank you" the steps taken and the error are mentioned please help, i am stuck here! installed sql server 2005 express on both computers installed sql server management studio express on both computers ran each management studio and connect to instance sqlserver using windows authentication ( one computer connection example "A-63A9D4D7E7834\SQLEXPRESS" ) created a database in the databases named as "test1" created a few tables with data saved and exit. did everything what this site says " How to configure SQL Server 2005 to allow remote connections" [add h t t p here as spam prevention] ://support.microsoft.com/kb/914277/en-us" but i have just disable the firewalls completely :turn off connecting to A-63A9D4D7E7834 started "SQL Server Management Studio Express" on computer A-63A9D4D7E7834 sever name: "ALL-E425BE6C41D\SQLEXPRESS" authentication: "windows authentication" and CONNECT I GET THE FOLLOWING ERROR Cannot connect to ALL-E425BE6C41D\SQLEXPRESS. ADDITIONAL INFORMATION: Login failed for user 'ALL-E425BE6C41D\Guest'. (Microsoft SQL Server, Error: 18456) For help, click: http://go.microsoft.com/fwlink?ProdName=Microsoft+SQL+Server&EvtSrc=MSSQLServer&EvtID=18456&LinkId=20476 BUTTONS: OK HELP

    Read the article

  • changing src reference based upon https

    - by spody
    I'm adding a facebook comment widget to a website. I'm placing this widget in a file that is included on everypage. The navigation is relatively linked so it switches back and forth from http and https. But for some reason the comment widget only shows up if both the src linked file and webpage is secure or both the src linked file and webpage is NOT secure. The widget does not display of the src file is secure and the webpage is not secure. So... I've tried this but doesn't work. if (window.location.protocol == 'https:') script.setAttribute('src', 'https://ssl.connect.facebook.com/js/api_lib/v0.4/FeatureLoader.js.php'); } else { script.setAttribute('src', 'http://static.ak.connect.facebook.com/connect.php/en_US') }

    Read the article

  • PHP fsockopen doesnt return anything

    - by Industrial
    Hi! I am modifying a PHP db wrapper for the redis database. Here's how my function looks: public function connect() { $sock = @fsockopen('localhost', '6379', $errno, $errstr, 2); if ($sock === FALSE) { return FALSE; } else { stream_set_timeout($sock, 2); return $sock; } } What I want to do is to call this function from another part in my wrapper: if ($this->connect() !== FALSE) { // Do stuff } How can I get my connect function to send a FALSE when the fsockopen isn't working? Thanks!

    Read the article

  • How to make a remote connection to a MySQL Database Server?

    - by MLB
    Hello: I am trying to connect to a MySQL database server (remote), but I can't. I am using an user with grant privileges (not root user). The error message is the following: Can't obtain database list from the server. Access denied for user 'myuser'@'mypcname' (using password: YES) "myuser" is an user I created with grant access. This user allows me to connect locally to every database. I am using the same software versions in both hosts: MySQL Server 4.1 (server) and EMS SQL Manager 2005 for MySQL, edition 3.7.0.1 (client). The point is that I need to connect to the remote server using a different user, not root user. So, how to make the connection? Thanks.

    Read the article

  • mysql_close(): supplied argument is not a valid MySQL-Link resource

    - by Illes Peter
    Here's what I'm trying to do: I've got a db.php file that does all the db manipulation. It has 2 static methods, connect and deconnect. In my other file i simply use db::connect() and db::deconnect(). The mysql_close($con) in the deconnect method just doesn't know who $con is. Since I don't want to instantiate my class static is the only way to go. Declaring 'private $con' in class db doesn't seem to have an effect. Any ideas? class db { public static function connect() { $dbData = parse_ini_file($_SERVER['DOCUMENT_ROOT'].'/config.ini'); $con = mysql_connect($dbData['host'],$dbData['user'],$dbData['pass']); $db = mysql_select_db($dbData['db']); if ((!$con) || (!$db)) return 0; else return 1; } public static function deconnect() { mysql_close($con); } }

    Read the article

  • ActionController::RoutingError

    - by Steve
    Hi All, I am just learning Rails. I had encountered a routing error, though I think I have specified the correct rules in the routing.rb. I have attached the code. Please help routing.rb map.connect ':controller/:action' map.connect ':controller/:action/:id' map.connect ':controller/:action/:id.:format' Controller class EntriesController < ApplicationController def sign_in @name = params[:visitor_name] end end View <html> <head><title>Hello <%=h @name %></title></head> <body> <%=h @name %> <% form_tag :action => 'sign_in' do %> <p>Enter your name: <%= text_field_tag 'visitor_name', @name %></p> <%= submit_tag 'Sign in' %> <% end %> </body> </html> Thanks

    Read the article

< Previous Page | 143 144 145 146 147 148 149 150 151 152 153 154  | Next Page >