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  • folder deleting not working

    - by user1150440
    If System.IO.Directory.Exists(HttpContext.Current.Server.MapPath(Server.MapPath("images/TravelogueGallery/" & getMaxID()))) Then System.IO.Directory.Delete(HttpContext.Current.Server.MapPath("images/TravelogueGallery/" & getMaxID()), True) End If I am using the above code snippet to delete a directory but i get this error "'G:\Projects\Latest\LTCIndia 05-04-12 1415\images\TravelogueGallery\19' is not a valid virtual path. " Whats wrong with the code?

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  • Get a random folder C# .NET

    - by Joshua
    Hi. public sealed static class FolderHelper { public static string GetRandomFolder() { // do work } } But.... How? Like start at c:\ (or whatever the main drive is) and then randomly take routes? Not even sure how to do that.

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  • Move one folder up in nant script

    - by Or A
    Hi, i'm not an expert of Nant, so i'll have to ask this redicolus question. i have a variable called svn.source.root which point to c:\folderA\FolderB\FolderC how can i make svn.source.root.modified variable to point to 2 folders up? i.e, folderA Obviously, the following didn't work: please help. thanks

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  • wp+sql+image not goin in the folder

    - by happy
    this is my code for uploading image in database but image are going to the desird forlder...but when i m tryin to retrieve the images to diaplay,,they are not displayed..anyone help me...... $category=$_POST['category']; $uploadDir = 'D:/xampp/htdocs/js/wordpress/wp-content/plugins/img/imagess/ '; $fileName = $_FILES['Photo']['name']; $tmpName = $_FILES['Photo']['tmp_name']; $fileSize = $_FILES['Photo']['size']; $fileType = $_FILES['Photo']['type']; $filePath = $uploadDir . $fileName; $result = move_uploaded_file($tmpName,$filePath); if (!$result) { echo "Error uploading file"; exit; } if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); $filePath = addslashes($filePath); } global $wpdb; //$insert=$wpdb->insert('images',array('image_name'=>$filePath,'cat_name'=>$category),array('%b','%s')); $insert=$wpdb->insert('images',array('image_name'=>$filePath,'cat_name'=>$category)); $wpdb->insert('categories',array('cat_name'=>$category)); echo "Successfully Submitted";

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  • List View Array from Database

    - by leenolasco
    I have retrieved data and successfully shown it in text view. What do i modify in my codes to make it look like a list view? And also how do modify my listview programatically(adding size and padding)? Here is my a part of my DBclass in selecting the items that I've displayed getFAData() { // TODO Auto-generated method stub String [] columns = new String[]{Row_Name}; Cursor c = ourDB.query(db_Table, columns, null, null, null, null, null); String res = ""; int iRow = c.getColumnIndex(Row_Name); //int iDesc = c.getColumnIndex(Row_Desc); //int iID = c.getColumnIndex(Row_id); for (c.moveToFirst(); !c.isAfterLast(); c.moveToNext()) { res = res + c.getString(iRow) + "\n"; } return res; } And here is class file: public class FirstAid extends Activity { @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.firstaid); displayresult(); } public void displayresult (){ TextView tvFa = (TextView) findViewById(R.id.tvFA); tvFa.setMovementMethod(new ScrollingMovementMethod()); DbHelper tblFa = new DbHelper(this); tblFa.open(); String result = tblFa.getFAData(); tblFa.close(); tvFa.setText(result); } }

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  • Calling a view from the second project

    - by user3128303
    I have 2 projects in the Solution (asp.net-mvc). The first project is main, the other project (1 simple controller and views (Index, Layout). I want directly from the menu in the project 1, to refer to the Index view of the second project. I added a reference but I do not know what to do. Someone help? Ps: Sorry for my english. Project 1 _Layout.cshtml <!DOCTYPE html> <html> <head> <meta charset="utf-8" /> <title>@ViewBag.Title</title> <link href="@Url.Content("~/Content/Site.css")" rel="stylesheet" type="text/css" /> <script src="@Url.Content("~/Scripts/jquery-1.5.1.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/modernizr-1.7.min.js")" type="text/javascript"></script> </head> <body> <div> <nav> <a href="@Url.Content("~")" id="current">Home</a> <a href="@Url.Content( /* via a link you want to get to the index from Project 2 */)">TEST</a> </nav> </div> <div id="main"> @RenderBody() </div> <div id="footer"> </div> </body> </html> Project 2 HomeController.cs namespace Panel.Controllers { public class HomeController : Controller { public ActionResult Index() { return View(); } } }

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  • How to get the path to the lib folder for an installed package

    - by Zardos
    Shared libraries .so files are placed in lib/armeabi in an apk file. I have read after installation the libs gets extracted to /data/data/application_package/lib How can I get the exact path to this directory in my application at run time? Is this directory readable by the application? Or is only executeable access allowed? If it is readable - Is this still true for copy protected applications?

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  • Should Item Grouping/Filter be in the ViewModel or View layer?

    - by ronag
    I'm in a situation where I have a list of items that need to be displayed depending on their properties. What I'm unsure of is where is the best place to put the filtering/grouping logic of the viewmodel state? Currently I have it in my view using converters, but I'm unsure whether I should have the logic in the viewmodel? e.g. ViewModel Layer: class ItemViewModel { DateTime LastAccessed { get; set; } bool IsActive { get; set; } } class ContainerViewModel { ObservableCollection<Item> Items {get; set;} } View Layer: <TextView Text="Active Items"/> <List ItemsSource={Binding Items, Converter=GroupActiveItemsByDay}/> <TextView Text="Active Items"/> <List ItemsSource={Binding Items, Converter=GroupInActiveItemsByDay}/> or should I build it like this? ViewModel Layer: class ContainerViewModel { ObservableCollection<IGrouping<string, Item>> ActiveItemsByGroup {get; set;} ObservableCollection<IGrouping<string, Item>> InActiveItemsByGroup {get; set;} } View Layer: <TextView Text="Active Items"/> <List ItemsSource={Binding ActiveItemsGroupByDate }/> <TextView Text="Active Items"/> <List ItemsSource={Binding InActiveItemsGroupByDate }/> Or maybe something in between? ViewModel Layer: class ContainerViewModel { ObservableCollection<IGrouping<string, Item>> ActiveItems {get; set;} ObservableCollection<IGrouping<string, Item>> InActiveItems {get; set;} } View Layer: <TextView Text="Active Items"/> <List ItemsSource={Binding ActiveItems, Converter=GroupByDate }/> <TextView Text="Active Items"/> <List ItemsSource={Binding InActiveItems, Converter=GroupByDate }/> I guess my question is what is good practice in terms as to what logic to put into the ViewModel and what logic to put into the Binding in the View, as they seem to overlap a bit?

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  • Variable in one query is getting into another query in view

    - by Jason Shultz
    I have two foreach statements. The variable from one one is somehow getting into another and i'm not sure how to fix it. Here's my controller: // Categories Page Code function categories($id) { $this->load->model('Business_model'); $data['businessList'] = $this->Business_model->categoryPageList($id); $data['catList'] = $this->Business_model->categoryList(); $data['featured'] = $this->Business_model->frontPageList(); $data['user_id'] = $this->tank_auth->get_user_id(); $data['username'] = $this->tank_auth->get_username(); $data['page_title'] = 'Welcome To Jerome - Largest Ghost Town in America'; $data['page'] = 'category_view'; // pass the actual view to use as a parameter $this->load->view('container',$data); } What happens is categories will only show the businesses in a certain category. The businesses are pulled from the database using the categoryPageList($id) function. Here is that function: function categoryPageList($id) { $this->db->select('b.id, b.busname, b.busowner, b.webaddress, p.thumb, v.title, c.catname, s.specname, p.thumb, c.id'); $this->db->from ('business AS b'); $this->db->where('b.category', $id); $this->db->join('photos AS p', 'p.busid = b.id', 'left'); $this->db->join('video AS v', 'v.busid = b.id', 'left'); $this->db->join('specials AS s', 's.busid = b.id', 'left'); $this->db->join('category As c', 'b.category = c.id', 'left'); $this->db->group_by("b.id"); return $this->db->get(); } And here is the view: <h2>Welcome to Jerome, Arizona</h2> <p>Choose the Category of Business you are interested in:<br/> <?php foreach ($catList->result() as $row): ?> <a href="/site/categories/<?=$row->id?>"><?=$row->catname?></a>, &nbsp; <?php endforeach; ?></p> <table id="businessTable" class="tablesorter"> <thead><tr><th>Business Name</th><th>Business Owner</th><th>Web</th><th>Photos</th><th>Videos</th><th>Specials</th></tr></thead> <?php if(count($businessList) > 0) : foreach ($businessList->result() as $crow): ?> <tr> <td><a href="/site/business/<?=$crow->id?>"><?=$crow->busname?></a></td> <td><?=$crow->busowner?></td> <td><a href="<?=$crow->webaddress?>">Visit Site</a></td> <td> <?php if(isset($crow->thumb)):?> yes <?php else:?> no <?php endif?> </td> <td> <?php if(isset($crow->title)):?> yes <?php else:?> no <?php endif?> </td> <td> <?php if(isset($crow->specname)):?> yes <?php else:?> no <?php endif?> </td> </tr> <?php endforeach; ?> <?php else : ?> <td colspan="4"><p>No Category Selected</p></td> <?php endif; ?> </table> The problem occurs here. <?=$crow->id?> should be showing the row id from the business table. Instead, it's showing the row ID of the category table. so, if i'm viewing /site/categories/6 <?=$crow->id?> will show 6 when it should be showing 10 (the row ID of the only business in that category at this time. How can I fix this?

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  • Android image click in horizontal page view

    - by JaseemAmeer
    I've implemented horizontal page view with many images. And I'm trying to create a click event on the image. public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.pbase); ImageView binfo,bheacno; tvHeacno=(TextView) findViewById(R.id.tvheacno); heacno=getHeacno(); tvHeacno.setText(heacno); MyPagerAdapter adapter=new MyPagerAdapter(); ViewPager myPager=(ViewPager)findViewById(R.id.mythreepanelpager); myPager.setAdapter(adapter); myPager.setCurrentItem(0); binfo=(ImageView) findViewById(R.id.ivinfo); bheacno=(ImageView) findViewById(R.id.ivheacno); binfo.setOnClickListener(this); bheacno.setOnClickListener(this); } then i've MyPagerAdapter class and the onclik method. it returns null to binfo and hence fails at binfo.setOnClickListener(this) I've done image click before on normal pages successfully. Is it because of horizontal page views? How can I solve this issue?? <FrameLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="match_parent" android:layout_height="match_parent"> <LinearLayout android:orientation="vertical" android:layout_width="match_parent" android:layout_height="match_parent"> <LinearLayout android:layout_weight="33" android:layout_gravity="top" android:orientation="horizontal" android:layout_width="match_parent" android:layout_height="match_parent"> <LinearLayout android:layout_weight="33" android:layout_gravity="center_horizontal" android:orientation="vertical" android:layout_width="wrap_content" android:layout_height="wrap_content"> <ImageView android:gravity="center" android:layout_weight="50" android:id="@+id/ivinfo" android:layout_width="wrap_content" android:layout_gravity="center" android:layout_height="wrap_content" android:src="@drawable/information" /> <TextView android:layout_height="wrap_content" android:layout_width="wrap_content" android:textColor="@android:color/black" android:layout_weight="50" android:layout_gravity="center" android:gravity="center" android:text=" Information " /> </LinearLayout> <LinearLayout android:layout_weight="33" android:layout_gravity="center_horizontal" android:orientation="vertical" android:layout_width="wrap_content" android:layout_height="wrap_content"> <ImageView android:gravity="center" android:layout_weight="50" android:id="@+id/ivheacno" android:layout_width="wrap_content" android:layout_gravity="center" android:layout_height="wrap_content" android:src="@drawable/heacno" /> <TextView android:layout_height="wrap_content" android:layout_width="wrap_content" android:textColor="@android:color/black" android:layout_weight="50" android:layout_gravity="center" android:gravity="center" android:text="Get HEAC Number" /> </LinearLayout> <LinearLayout android:layout_weight="33" android:layout_gravity="center_horizontal" android:orientation="vertical" android:layout_width="wrap_content" android:layout_height="wrap_content"> <ImageView android:gravity="center" android:layout_weight="50" android:id="@+id/ivpi" android:layout_width="wrap_content" android:layout_gravity="center" android:layout_height="wrap_content" android:src="@drawable/pi" /> <TextView android:layout_height="wrap_content" android:layout_width="wrap_content" android:textColor="@android:color/black" android:layout_weight="50" android:layout_gravity="center" android:gravity="center" android:text="Personal Information" /> </LinearLayout> </LinearLayout> <LinearLayout android:layout_weight="33" android:layout_gravity="center" android:orientation="horizontal" android:layout_width="match_parent" android:layout_height="match_parent"> <LinearLayout android:layout_weight="33" android:layout_gravity="left" android:orientation="vertical" android:layout_width="wrap_content" android:layout_height="wrap_content"> <ImageView android:gravity="center" android:layout_weight="50" android:id="@+id/ivassn" android:layout_width="wrap_content" android:layout_gravity="center" android:layout_height="wrap_content" android:src="@drawable/assn" /> <TextView android:layout_height="wrap_content" android:layout_width="wrap_content" android:textColor="@android:color/black" android:layout_weight="50" android:layout_gravity="center" android:gravity="center" android:text="Add Social Security Number" /> </LinearLayout> <LinearLayout android:layout_weight="33" android:layout_gravity="left" android:orientation="vertical" android:layout_width="wrap_content" android:layout_height="wrap_content"> <ImageView android:gravity="center" android:layout_weight="50" android:id="@+id/ivvssn" android:layout_width="wrap_content" android:layout_gravity="center" android:layout_height="wrap_content" android:src="@drawable/vssn" /> <TextView android:layout_height="wrap_content" android:layout_width="wrap_content" android:textColor="@android:color/black" android:layout_weight="50" android:layout_gravity="center" android:gravity="center" android:text="View Social Security Number" /> </LinearLayout> <LinearLayout android:layout_weight="33" android:layout_gravity="left" android:orientation="vertical" android:layout_width="wrap_content" android:layout_height="wrap_content"> <ImageView android:gravity="center" android:layout_weight="50" android:id="@+id/ivdssn" android:layout_width="wrap_content" android:layout_gravity="center" android:layout_height="wrap_content" android:src="@drawable/dssn" /> <TextView android:layout_height="wrap_content" android:layout_width="wrap_content" android:textColor="@android:color/black" android:layout_weight="50" android:layout_gravity="center" android:gravity="center" android:text="Delete Social Security Number" /> </LinearLayout> </LinearLayout> <LinearLayout android:layout_weight="33" android:layout_gravity="bottom" android:orientation="horizontal" android:layout_width="match_parent" android:layout_height="match_parent"> <LinearLayout android:layout_weight="33" android:layout_gravity="left" android:orientation="vertical" android:layout_width="wrap_content" android:layout_height="wrap_content"> <ImageView android:gravity="center" android:layout_weight="50" android:id="@+id/ivali" android:layout_width="wrap_content" android:layout_gravity="center" android:layout_height="wrap_content" android:src="@drawable/ali" /> <TextView android:layout_height="wrap_content" android:layout_width="wrap_content" android:textColor="@android:color/black" android:layout_weight="50" android:layout_gravity="center" android:gravity="center" android:text="Add Low Income" /> </LinearLayout> <LinearLayout android:layout_weight="33" android:layout_gravity="left" android:orientation="vertical" android:layout_width="wrap_content" android:layout_height="wrap_content"> <ImageView android:gravity="center" android:layout_weight="50" android:id="@+id/ivvli" android:layout_width="wrap_content" android:layout_gravity="center" android:layout_height="wrap_content" android:src="@drawable/vli" /> <TextView android:layout_height="wrap_content" android:layout_width="wrap_content" android:textColor="@android:color/black" android:layout_weight="50" android:layout_gravity="center" android:gravity="center" android:text="View Low Income" /> </LinearLayout> <LinearLayout android:layout_weight="33" android:layout_gravity="left" android:orientation="vertical" android:layout_width="wrap_content" android:layout_height="wrap_content"> <ImageView android:gravity="center" android:layout_weight="50" android:id="@+id/ivdli" android:layout_width="wrap_content" android:layout_gravity="center" android:layout_height="wrap_content" android:src="@drawable/dli" /> <TextView android:layout_height="wrap_content" android:layout_width="wrap_content" android:textColor="@android:color/black" android:layout_weight="50" android:layout_gravity="center" android:gravity="center" android:text="Delete Low Income" /> </LinearLayout> </LinearLayout> </LinearLayout>

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  • View bound to paged collection view not updating all of the time.

    - by Thomas
    I new to silverlight and trying to make a business application using the mvvm pattern and ria services. I have a view model class that contains a PagedCollectoinView and it is set to the item source of a datagrid. When I update the PagedCollectionView the datagrid is only updated the first time then after that subsequent changes to the data to not reflect in the view until after another edit. Things seem to be delayed one edit. Below is a summarized example of my xaml and code behind. This is the code for my view model public class CustomerContactLinks : INotifyPropertyChanged { private ObservableCollection<CustomerContactLink> _CustomerContact; public ObservableCollection<CustomerContactLink> CustomerContact { get { if (_CustomerContact == null) _CustomerContact = new ObservableCollection<CustomerContactLink>(); return _CustomerContact; } set { _CustomerContact = value; } } private PagedCollectionView _CustomerContactPaged; public PagedCollectionView CustomerContactPaged { get { if (_CustomerContactPaged == null) _CustomerContactPaged = new PagedCollectionView(CustomerContact); return _CustomerContactPaged; } } private TicketSystemDataContext _ctx; public TicketSystemDataContext ctx { get { if (_ctx == null) _ctx = new TicketSystemDataContext(); return _ctx; } } public void GetAll() { ctx.Load(ctx.GetCustomerContactInfoQuery(), LoadCustomerContactsComplete, null); } private void LoadCustomerContactsComplete(LoadOperation<CustomerContactLink> lo) { foreach (var entity in lo.Entities) { CustomerContact.Add(entity as CustomerContactLink); } } #region INotifyPropertyChanged Members public event PropertyChangedEventHandler PropertyChanged; private void RaisePropertyChanged(string propertyName) { if (PropertyChanged != null) { this.PropertyChanged(this, new PropertyChangedEventArgs(propertyName)); } } #endregion } Here is the basics of my XAML <Data:DataGrid x:Name="GridCustomers" MinHeight="100" MaxWidth="1000" IsReadOnly="True" AutoGenerateColumns="False"> <Data:DataGrid.Columns> <Data:DataGridTextColumn Header="First Name" Binding="{Binding Customer.FirstName}" Width="105" /> <Data:DataGridTextColumn Header="MI" Binding="{Binding Customer.MiddleName}" Width="35" /> <Data:DataGridTextColumn Header="Last Name" Binding="{Binding Customer.LastName}" Width="105"/> <Data:DataGridTextColumn Header="Address1" Binding="{Binding Contact.Address1}" Width="130"/> <Data:DataGridTextColumn Header="Address2" Binding="{Binding Contact.Address2}" Width="130"/> <Data:DataGridTextColumn Header="City" Binding="{Binding Contact.City}" Width="110"/> <Data:DataGridTextColumn Header="State" Binding="{Binding Contact.State}" Width="50"/> <Data:DataGridTextColumn Header="Zip" Binding="{Binding Contact.Zip}" Width="45"/> <Data:DataGridTextColumn Header="Home" Binding="{Binding Contact.PhoneHome}" Width="85"/> <Data:DataGridTextColumn Header="Cell" Binding="{Binding Contact.PhoneCell}" Width="85"/> <Data:DataGridTextColumn Header="Email" Binding="{Binding Contact.Email}" Width="118"/> </Data:DataGrid.Columns> </Data:DataGrid> <DataForm:DataForm x:Name="CustomerDetails" Header="Customer Details" AutoGenerateFields="False" AutoEdit="False" AutoCommit="False" CommandButtonsVisibility="Edit" Width="1000" Margin="0,5,0,0"> <DataForm:DataForm.EditTemplate> </DataForm:DataForm.EditTemplate> </DataForm:DataForm> And here is my code behind public Customers() { InitializeComponent(); BusyDialogIndicator.IsBusy = true; Loaded += new RoutedEventHandler(Customers_Loaded); CustomerDetails.BeginningEdit += new EventHandler(CustomerDetails_BeginningEdit); } void CustomerDetails_BeginningEdit(object sender, System.ComponentModel.CancelEventArgs e) { CustomerContacts.CustomerContactPaged.EditItem(CustomerDetails.CurrentItem); } private void Customers_Loaded(object sender, RoutedEventArgs e) { CustomerContacts = new CustomerContactLinks(); CustomerContacts.GetAll(); GridCustomers.ItemsSource = CustomerContacts.CustomerContactPaged; GridCustomerPager.Source = CustomerContacts.CustomerContactPaged; GridCustomers.SelectionChanged += new SelectionChangedEventHandler(GridCustomers_SelectionChanged); BusyDialogIndicator.IsBusy = false; } void GridCustomers_SelectionChanged(object sender, SelectionChangedEventArgs e) { CustomerDetails.CurrentItem = GridCustomers.SelectedItem as CustomerContactLink; } private void SaveChanges_Click(object sender, RoutedEventArgs e) { if (WebContext.Current.User.IsAuthenticated) { bool commited = CustomerDetails.CommitEdit(); if (commited && (!CustomerDetails.IsItemChanged && CustomerDetails.IsItemValid)) { CustomerContacts.Update(CustomerDetails.CurrentItem as CustomerContactLink); CustomerContacts.ctx.SubmitChanges(); CustomerContacts.CustomerContactPaged.CommitEdit(); CustomerContacts.CustomerContactPaged.Refresh(); (GridCustomers.ItemsSource as PagedCollectionView).Refresh(); } } }

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  • Only show items owned by the currently logged in user in category list view

    - by jalbasri
    I'd like to be able to provide a "Category List" view that only shows Articles that the currently logged in user owns. Is there somewhere I can edit the query used to populate the Category List view or an extension that provides this functionality. Thank you for any help you can provide. -J. Thank you for your answer. I've written the plugin. Instead of passing in an array of Articles the onContentBeforeDisplay function is called for every article and an ArrayObject of the single article gets passed in. I've been able to identify the articles I want not to be displayed but still cannot get them not to display. The $params variable has values such as "list_show_xxx" but I can't seem to change or access them. here is a var_dump($params): object(Joomla\Registry\Registry)#190 (1) { ["data":protected]=> object(stdClass)#250 (83) { ["article_layout"]=> string(9) "_:default" ["show_title"]=> string(1) "1" ["link_titles"]=> string(1) "1" ["show_intro"]=> string(1) "1" ["info_block_position"]=> string(1) "1" ["show_category"]=> string(1) "1" ["link_category"]=> string(1) "1" ["show_parent_category"]=> string(1) "0" ["link_parent_category"]=> string(1) "0" ["show_author"]=> string(1) "1" ["link_author"]=> string(1) "0" ["show_create_date"]=> string(1) "0" ["show_modify_date"]=> string(1) "0" ["show_publish_date"]=> string(1) "1" ["show_item_navigation"]=> string(1) "1" ["show_vote"]=> string(1) "0" ["show_readmore"]=> string(1) "1" ["show_readmore_title"]=> string(1) "1" ["readmore_limit"]=> string(3) "100" ["show_tags"]=> string(1) "1" ["show_icons"]=> string(1) "1" ["show_print_icon"]=> string(1) "1" ["show_email_icon"]=> string(1) "1" ["show_hits"]=> string(1) "1" ["show_noauth"]=> string(1) "0" ["urls_position"]=> string(1) "0" ["show_publishing_options"]=> string(1) "0" ["show_article_options"]=> string(1) "0" ["save_history"]=> string(1) "1" ["history_limit"]=> int(10) ["show_urls_images_frontend"]=> string(1) "0" ["show_urls_images_backend"]=> string(1) "1" ["targeta"]=> int(0) ["targetb"]=> int(0) ["targetc"]=> int(0) ["float_intro"]=> string(4) "left" ["float_fulltext"]=> string(4) "left" ["category_layout"]=> string(9) "_:default" ["show_category_heading_title_text"]=> string(1) "1" ["show_category_title"]=> string(1) "0" ["show_description"]=> string(1) "0" ["show_description_image"]=> string(1) "0" ["maxLevel"]=> string(1) "1" ["show_empty_categories"]=> string(1) "0" ["show_no_articles"]=> string(1) "1" ["show_subcat_desc"]=> string(1) "1" ["show_cat_num_articles"]=> string(1) "0" ["show_base_description"]=> string(1) "1" ["maxLevelcat"]=> string(2) "-1" ["show_empty_categories_cat"]=> string(1) "0" ["show_subcat_desc_cat"]=> string(1) "1" ["show_cat_num_articles_cat"]=> string(1) "1" ["num_leading_articles"]=> string(1) "1" ["num_intro_articles"]=> string(1) "4" ["num_columns"]=> string(1) "1" ["num_links"]=> string(1) "4" ["multi_column_order"]=> string(1) "0" ["show_subcategory_content"]=> string(1) "0" ["show_pagination_limit"]=> string(1) "1" ["filter_field"]=> string(5) "title" ["show_headings"]=> string(1) "1" ["list_show_date"]=> string(1) "0" ["date_format"]=> string(0) "" ["list_show_hits"]=> string(1) "1" ["list_show_author"]=> string(1) "1" ["orderby_pri"]=> string(5) "order" ["orderby_sec"]=> string(5) "rdate" ["order_date"]=> string(9) "published" ["show_pagination"]=> string(1) "2" ["show_pagination_results"]=> string(1) "1" ["show_feed_link"]=> string(1) "1" ["feed_summary"]=> string(1) "0" ["feed_show_readmore"]=> string(1) "0" ["display_num"]=> string(2) "10" ["menu_text"]=> int(1) ["show_page_heading"]=> int(0) ["secure"]=> int(0) ["page_title"]=> string(16) "Non-K2 News List" ["page_description"]=> string(33) "Bahrain Business Incubator Centre" ["page_rights"]=> NULL ["robots"]=> NULL ["access-edit"]=> bool(true) ["access-view"]=> bool(true) } } I've tried $params-data-list_show_author = "0" but then the page doesn't load, problem is accessing and changing the variables in $param. So the last step is to figure out how not to show the article. Any ideas?

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  • File Access problems with SLES 10 SP2 OES2 SP1

    - by Blackhawk131
    We have identified a couple of repeatable, demonstrable scenarios with unexplained rejected folder access on our servers for Mac users. Hopefully, this can be presented to Novell for a solution. What we did to demonstrate scenario 1; 1. setup a PC and Mac side-by-side 2. login to our server and open up to a central location on both Mac and PC 3. on the PC in that central location create a folder 4. on the Mac in that central location drag the created folder to the Mac desktop, this should work fine, no problem 5. on the PC rename that folder 6. on the Mac drag a file to that renamed folder, this should error with the following message; a. You cannot copy some of these items to the destination because their names are too long for the destination. Do you want to skip copying these items and continue copying the other items? b. Select skip, response is the filename is copied to the location with zero or small byte size. Try opening it and you get file is corrupted error message. What we did to demonstrate scenario 2; 1. setup a PC and Mac side-by-side 2. login to our server and open up to a central location on both Mac and PC 3. on the PC in that central location create a folder then create a subfolder 4. copy some content into the subfolder 5. on the Mac in that central location drag the created top level folder to the Mac desktop, this should work fine, no problem 6. on the PC rename that subfolder 7. on the Mac drag that top level folder to the Mac desktop, this should error on the Mac with the following; a. The operation cannot be completed because you do not have sufficient privileges for b. The operation cannot be completed because you do not have sufficient privileges for 8. on the Mac, if you open that subfolder you can see the file copied in step 4 above but, you can not open that file, you get the following message if you try; a. There was an error opening this document. You do not have permission to open this file. 9. on the PC drag some content into the top level folder 10. on the Mac you can open that file directly from the server or copy it locally, no problem, however-the subfolder is still corrupted or locked, whichever 11. on the PC rename the top level folder 12. on the Mac that same file just opened in step 10 above is now not accessible, get the following message; a. The document could not be opened. I have observed some variances in the above. For instance, a change on the PC side may take a moment before you can observer or act on the Mac side - kind of like the server is slow to respond. Also, the error message may vary. However, the key is once a folder, or subfolder, gets renamed by a PC, Mac problems commence. The solution is to create a new folder from a PC and copy the contents of the corrupted folder to the new folder and not rename the folder name. This has to be done on a PC because the corrupted folder is not accessible by a Mac user. Another problem that dovetails with the above is that we know certain characters are not allowed for PC folder or filenames. If a Mac user creates a folder with a slash in the file name, from the PC the user does not see that slash in the name. As soon as the PC user copies a file to that folder, the Mac user is locked from that folder. Will get the following error message; - Sorry, the operation could not be completed because an unexpected error occurred. - (Error code - 50) In addition to the above mentioned character issue with folders, the problem is more evil with filenames. If, for example, you create a file with a slash in the filename on a Mac and copy it to the server you will get the following error message; - You cannot copy some of these items to the destination because their names are too long for the destination. Do you want to skip copying these items and continue copying the other items? Select either Stop or Skip buttons. It does not matter which button is selected. The file name gets copied to the destination location at a reduced size. Depending on the file type, the icon associated with the file may or may not be present. Furthermore, if you open that file on the server you will get the following message; - Couldnt open the file. It may be corrupt or a file format that doesnt recognize. From the users perspective, if they are not observant of the icon or file size, they may disregard the error message and think their file has copied as intended. Only later do they discover the file is corrupt if they open that file. I want to make a note on this problem. It is the PC causing the issue. You can change folder and file names all day on a MAC and you don't have a problem as long as a character is not the issue. Once you change the file name or folder name from a PC the entire folder structure from that level down is corrupted. But it has to be resolved from a PC by creating a new folder and copying the contents to the new folder like stated above. Is something not configured correctly? SUSE Linux Enterprise Server 10 (x86_64) VERSION = 10 PATCHLEVEL = 2 LSB_VERSION="core-2.0-noarch:core-3.0-noarch:core-2.0-x86_64:core-3.0-x86_64" Novell Open Enterprise Server 2.0.1 (x86_64) VERSION = 2.0.1 PATCHLEVEL = 1 BUILD Note: We use Novell clients on all windows systems to connect to the servers for file access and network storage. We use AFP to allow OSx systems to connect to servers.

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  • File Access problems with SLES 10 SP2 OES2 SP1

    - by Blackhawk131
    We have identified a couple of repeatable, demonstrable scenarios with unexplained rejected folder access on our servers for Mac users. Hopefully, this can be presented to Novell for a solution. What we did to demonstrate scenario 1; 1. setup a PC and Mac side-by-side 2. login to our server and open up to a central location on both Mac and PC 3. on the PC in that central location create a folder 4. on the Mac in that central location drag the created folder to the Mac desktop, this should work fine, no problem 5. on the PC rename that folder 6. on the Mac drag a file to that renamed folder, this should error with the following message; a. You cannot copy some of these items to the destination because their names are too long for the destination. Do you want to skip copying these items and continue copying the other items? b. Select skip, response is the filename is copied to the location with zero or small byte size. Try opening it and you get file is corrupted error message. What we did to demonstrate scenario 2; 1. setup a PC and Mac side-by-side 2. login to our server and open up to a central location on both Mac and PC 3. on the PC in that central location create a folder then create a subfolder 4. copy some content into the subfolder 5. on the Mac in that central location drag the created top level folder to the Mac desktop, this should work fine, no problem 6. on the PC rename that subfolder 7. on the Mac drag that top level folder to the Mac desktop, this should error on the Mac with the following; a. The operation cannot be completed because you do not have sufficient privileges for b. The operation cannot be completed because you do not have sufficient privileges for 8. on the Mac, if you open that subfolder you can see the file copied in step 4 above but, you can not open that file, you get the following message if you try; a. There was an error opening this document. You do not have permission to open this file. 9. on the PC drag some content into the top level folder 10. on the Mac you can open that file directly from the server or copy it locally, no problem, however-the subfolder is still corrupted or locked, whichever 11. on the PC rename the top level folder 12. on the Mac that same file just opened in step 10 above is now not accessible, get the following message; a. The document could not be opened. I have observed some variances in the above. For instance, a change on the PC side may take a moment before you can observer or act on the Mac side - kind of like the server is slow to respond. Also, the error message may vary. However, the key is once a folder, or subfolder, gets renamed by a PC, Mac problems commence. The solution is to create a new folder from a PC and copy the contents of the corrupted folder to the new folder and not rename the folder name. This has to be done on a PC because the corrupted folder is not accessible by a Mac user. Another problem that dovetails with the above is that we know certain characters are not allowed for PC folder or filenames. If a Mac user creates a folder with a slash in the file name, from the PC the user does not see that slash in the name. As soon as the PC user copies a file to that folder, the Mac user is locked from that folder. Will get the following error message; - Sorry, the operation could not be completed because an unexpected error occurred. - (Error code - 50) In addition to the above mentioned character issue with folders, the problem is more evil with filenames. If, for example, you create a file with a slash in the filename on a Mac and copy it to the server you will get the following error message; - You cannot copy some of these items to the destination because their names are too long for the destination. Do you want to skip copying these items and continue copying the other items? Select either Stop or Skip buttons. It does not matter which button is selected. The file name gets copied to the destination location at a reduced size. Depending on the file type, the icon associated with the file may or may not be present. Furthermore, if you open that file on the server you will get the following message; - Couldnt open the file. It may be corrupt or a file format that doesnt recognize. From the users perspective, if they are not observant of the icon or file size, they may disregard the error message and think their file has copied as intended. Only later do they discover the file is corrupt if they open that file. I want to make a note on this problem. It is the PC causing the issue. You can change folder and file names all day on a MAC and you don't have a problem as long as a character is not the issue. Once you change the file name or folder name from a PC the entire folder structure from that level down is corrupted. But it has to be resolved from a PC by creating a new folder and copying the contents to the new folder like stated above. Is something not configured correctly? SUSE Linux Enterprise Server 10 (x86_64) VERSION = 10 PATCHLEVEL = 2 LSB_VERSION="core-2.0-noarch:core-3.0-noarch:core-2.0-x86_64:core-3.0-x86_64" Novell Open Enterprise Server 2.0.1 (x86_64) VERSION = 2.0.1 PATCHLEVEL = 1 BUILD Note: We use Novell clients on all windows systems to connect to the servers for file access and network storage. We use AFP to allow OSx systems to connect to servers.

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  • Weight doesn't work in a custom android component

    - by RCB
    I wanted to create a custom bottom button bar layout, I've created a xml file : <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" style="@android:style/ButtonBar" android:layout_width="fill_parent" android:layout_height="wrap_content" android:orientation="horizontal" android:padding="0dp" > <Button android:id="@+id/media_menu_button" style="?android:attr/buttonStyleSmall" android:layout_width="0dp" android:layout_height="match_parent" android:layout_margin="0dp" android:layout_weight="1" android:text="@string/media_menu_button" /> <Button android:id="@+id/scenario_menu_button" style="?android:attr/buttonStyleSmall" android:layout_width="0dp" android:layout_height="match_parent" android:layout_margin="0dp" android:layout_weight="1" android:text="@string/scenario_menu_button" /> <Button android:id="@+id/rooms_menu_button" style="?android:attr/buttonStyleSmall" android:layout_width="0dp" android:layout_height="match_parent" android:layout_margin="0dp" android:layout_weight="1" android:text="@string/rooms_menu_button" /> <Button android:id="@+id/shortcut_menu_button" style="?android:attr/buttonStyleSmall" android:layout_width="0dp" android:layout_height="match_parent" android:layout_margin="0dp" android:layout_weight="1" android:text="@string/shortcut_menu_button" /> as you can see I've given all the buttons width 0dp and weight of 1. then, I've created a class that extends the linear layout class : public class BeLightBottomBar extends LinearLayout implements OnClickListener { private LayoutInflater mInflater; private Context contexnt; private Button mShortcutMenuButton; private Button mRoomsMenuButton; private Button mScenarioMenuButton; private Button mMediaMenuButton; public BeLightBottomBar(Context context, AttributeSet attrs) { super(context, attrs); //inflate the view this.contexnt = context; mInflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE); LinearLayout barView = (LinearLayout) mInflater.inflate(R.layout.belight_bottombar, null); addView(barView); //get all the instances of the components of the bar mShortcutMenuButton = (Button) barView.findViewById(R.id.shortcut_menu_button); mRoomsMenuButton = (Button) barView.findViewById(R.id.rooms_menu_button); mScenarioMenuButton = (Button) barView.findViewById(R.id.scenario_menu_button); mMediaMenuButton = (Button) barView.findViewById(R.id.media_menu_button); //set this as a click listener mShortcutMenuButton.setOnClickListener(this); mRoomsMenuButton.setOnClickListener(this); mScenarioMenuButton.setOnClickListener(this); mMediaMenuButton.setOnClickListener(this); ... ... ... } the problem is when i add this class to the main activity xml <belight.homecontrol.components.BeLightBottomBar android:id="@+id/button_bar" android:layout_width="match_parent" android:layout_height="wrap_content" android:layout_alignParentBottom="true" android:layout_margin="0dp" android:padding="0dp" /> the weight stops working, all the buttons are different. and I don't know why !? if I just copy paste the bottom's bar xml code to the main xml file it works fine, the problem only occurs when using it as a whole. P.S. Is it a good practice to create a component this way? Or maybe I'm doing something wrong? Thanks, Dan

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  • popView from UITabBarController inside UINavigationController

    - by Manu
    Hi, I'm building an application based on the Utility template from Xcode, to which I have added some more views. My application structure would be as follows: MainView (the app menu) Flip-side view (a calculator) UINavigationController Settings view viewDiDLoad: UITabBarController - Tab1 view (options) - Tab2 view (information text) I can navigate correctly from my MainView to my Flip-side view, which is also the root view of the Navigation Controller. From my Flip-side view, I push a second view of my Navigation Controller (Settings view) that is configured to show an UITabBarController, with two tabs, as soon as it loads (with viewDidLoad). If I remove the UITabBarController, I can return with no problems to my Flip-side view using "popViewController" from my Settings view. The problem comes if I load the UITabBarController in viewDiDLoad in my Settings view... the tabs work perfectly, but I'm not able to return to my Flip-side view (root view of the Navigation Controller) anymore. I CAN return if I use the Navigation Bar of the Navigation Controller, but I want to configure my own buttons and have the Navigation Bar hidden. So far I've tried the following methods: [self.navigationController popViewControllerAnimated:YES]; [self.navigationController popToRootViewControllerAnimated:YES]; [self.navigationController popToViewController:FlipSideViewController animated:YES]; But they don't seem to work. The first two just do nothing (the screen remains as it was), and the third one does not recognize the "FlipsideViewController" (maybe because it's a delegate of the MainViewController?). Is there a way to check what is exactly doing the "back" button of the Navigation Bar if I activate it? Should I be using delegates? Can I call a popViewController method in my Settings view from any of the two Tab views? This is my Flip-side view: - (IBAction)showSettingsView { SettingsViewController *controller = [[SettingsViewController alloc] initWithNibName:@"SettingsView" bundle:nil]; controller.title = @"Settings"; [self.navigationController pushViewController:controller animated:YES]; [controller release]; } This is my Settings view: - (void)viewDidLoad { [super viewDidLoad]; tabBarController = [[UITabBarController alloc] init]; Tab1ViewController* vc1 = [[Tab1ViewController alloc] init]; Tab2ViewController* vc2 = [[Tab2ViewController alloc] init]; NSArray* controllers = [NSArray arrayWithObjects:vc1, vc2, nil]; tabBarController.viewControllers = controllers; [self.view addSubview:tabBarController.view]; } And the method to return in one of the Tab views: - (IBAction)backFromTab1View { [self.navigationController popToViewController:FlipSideViewController animated:YES]; } Thanks very much and sorry if the question is too basic!

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  • How do I maintain coherency between model and view-model in MVVM pattern?

    - by Mike Garrett
    Problem Statement I'm writing a very basic WPF application to alter the contents of a configuration file. The data format is an XML file with a schema. I want to use it as a learning project for MVVM, so I have duly divided the code into Model: C# classes auto-generated from xsd.exe View-Model: View-friendly representation of the Model. View: Xaml and empty code behind I understand how the View-Model can make View-binding a breeze. However, doesn't that leave the View-Model <- Model semantics very awkward? Xsd.exe generates C# classes with arrays for multiple XML elements. However, at the V-VM level you need Observable Collections. Questions: Does this really mean I have to keep two completely different collection types representing the same data in coherence? What are the best practices for maintaining coherence between the Model and the View-Model?

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  • How to have the controller change its behavior depending on the view?

    - by Ian Boyd
    If from one view a user enters some invalid data, e.g.:     E-mail: [email protected]     then i want the controller to: not place the data into the model color the text box reddish not allow the user to save But it's possible that if the user enters the same invalid data in a different view i want the controller to: place the data into the model color the text box reddish allow the user to save But it's possible that if the user enters the same invalid data in a different view i want the controller to: place the data into the model color the text box bluish allow the user to save And it's possible that another view will: place the data into the model leave the text box uncolored allow the user to save And it's possible that another view will: auto-correct the data, placing it into the model color the text-box reddish allow the user to have And it's possible for another view to: auto-correct the data, placing it into the model update the view with the new data color the text-box bluish allow the user to save [ad infinitum] Without using n-controllers for n-views, how do i do this?

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  • What is the difference between "render a view" and send the response using the Response's method "sendResponse()"?

    - by Green
    I've asked a question about what is "rendering a view". Got some answers: Rendering a view means showing up a View eg html part to user or browser. and So by rendering a view, the MVC framework has handled the data in the controller and done the backend work in the model, and then sends that data to the View to be output to the user. and render just means to emit. To print. To echo. To write to some source (probably stdout). but don't understand then the difference between rendering a view and using the Response class to send the output to the user using its sendResponse() method. If render a view means to echo the output to the user then why sendResponse() exists and vise versa? sendResponse() exactly sends headers and after headers outputs the body. They solve the same tasks but differently? What is the difference?

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  • Security Issue in LinkedIn &ndash; View any 3rd profile without a premium account.

    - by Shaurya Anand
    Originally posted on: http://geekswithblogs.net/shauryaanand/archive/2013/06/25/153230.aspxI discovered this accidently when my wife forwarded a contact on LinkedIn from her tablet, using the mobile interface of the website. On opening the contact on my desktop, I was surprised to see, I need to upgrade my account to view the contact. Doing some research along with my wife, I found this simple security vulnerability from LinkedIn that can let anyone view a contact’s full profile even when you have a “not upgraded” LinkedIn account and that the contact is a “3rd + Everyone Else”. Here’s an example of what I am talking about. I just made a random search on LinkedIn for a contact whose name starts with Sacha. Do note, this is just a walkthrough and I am not publicizing any Sacha. I check the “3rd + Everyone Else” and find a “LinkedIn Member”. On clicking this person’s profile to view, I am presented with the following page, asking me to upgrade. Make a note of this page’s web address and you get the profile id from it. For example, for this contact, the page address is: http://www.linkedin.com/profile/view?id=868XXX35 The Profile Id for this contact is 868XXX35. Now, open following page where the Profile Id is the same as the one we grabbed a moment earlier. https://touch.www.linkedin.com/?#profile/868XXX35 The mobile page exposes this contact information and you even get the possibility to connect to this person without an introduction mail (InMail). I hope someone from LinkedIn sees and issues a fix for this. I am pretty sure, it’s something that they don’t want the user to do without purchasing an upgrade package.

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  • How do I create a third Person View using DXUTCamera in DX10?

    - by David
    I am creating a 3d flying game and using DXUTCamera for my view. I can get the camera to take on the characters position, But I would like to view my character in the 3rd person. Here is my code for first person view: //Put the camera on the object. D3DXVECTOR3 viewerPos; D3DXVECTOR3 lookAtThis; D3DXVECTOR3 up ( 5.0f, 1.0f, 0.0f ); D3DXVECTOR3 newUp; D3DXMATRIX matView; //Set the viewer's position to the position of the thing. viewerPos.x = character->x; viewerPos.y = character->y; viewerPos.z = character->z; // Create a new vector for the direction for the viewer to look character->setUpWorldMatrix(); D3DXVECTOR3 newDir, lookAtPoint; D3DXVec3TransformCoord(&newDir, &character->initVecDir, &character->matAllRotations); // set lookatpoint D3DXVec3Normalize(&lookAtPoint, &newDir); lookAtPoint.x += viewerPos.x; lookAtPoint.y += viewerPos.y; lookAtPoint.z += viewerPos.z; g_Camera.SetViewParams(&viewerPos, &lookAtPoint); So does anyone have an ideas how I can move the camera to the third person view? preferably timed so there is a smooth action in the camera movement. (I'm hoping I can just edit this code instead of bringing in another camera class)

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  • Add separate domain name to Wordpress admin area with htaccess

    - by Marc
    I have a Wordpress installation in a seperate folder on my server (meaning it is not in the root folder). I have a htaccess rewrite rule that maps Domain A to folder A. Inside folder A is the Wordpress admin folder, let's call it folder A.B. I tried mapping Domain B to folder A.B., but I can't get it to work properly. When you log in to Wordpress via /admin, you get redirected to /wp-login.php (so from folder A.B. to folder A), maybe that is where I get into trouble. So what I would like to do is this: Domain A folder A Domain B folder A.B Note that this is not for security purposes, I just like the idea of www.domainb.com instead of www.domaina.com/wp-admin. Can this be done with Wordpress?

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  • Adobe Acrobat: How to batch to combine multiple pdf files?

    - by Andrei Andre
    I have 3 folders: Folder 1 Folder 2 Folder 3 In each folder I have 5 pdf files: Folder 1 file1.pdf file2.pdf Folder 2 file1.pdf file2.pdf Folder 3 file1.pdf file2.pdf I want that in each folder to have a combined file of those two files: Folder 1 binder.pdf Folder 2 binder.pdf Folder 3 binder.pdf Any idea? Don't tell to do it manually. This case is just to explain you my problem. Think that I have hundreds of folders. :) Maybe I can use another tool instead of Adobe Acrobat?!

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  • What do you do to balance the upper or lower case style to name file or folder between work and life? [on hold]

    - by sojyq
    I am a programmer from China. And I like to use English words to name my files and folders Whether it is for work or life. For example, suck as Movie, Work, QtProjects, Music and so on.And I keep the habit of initial the first letter for file name or folder name in Windows. But now I work on Ubuntu, and I found that all file name and folder name are lowercase in addition to the default folder such as Music, Movie and so on. And then I realize that in Linux world, most peoloe like to use all lowercase to name their files and folders for two reasons (1. Linux is Case sensitive. 2. It is fast for shell command.). And after work, when I switch from Linux to Windows, I confuse to use all lowercase or the first letter uppercase style to name my files in Windows. I'm caught in a dilemma. I think that all lowercase is more efficiency but the first letter uppercase is more readable. I thought for a long time and want to come up with a good answer to blance the two style name conversion. But I failed. I want to ask you that how you balance the uppercase or lowercase habbit in Windows, Mac, Linux between work and personal life style? Thank you very much! (My current solution is that when I am in Linux, I use all lowercase for files and folders, but when I am in Windows and Mac OS X, I couldn't find a good reason to convince me to use all lowercase ( I think in Windows and Mac OS X, the first letter uppercase style for me is more readable and beautiful).

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