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  • Most efficient way to check if a date falls between two dates?

    - by Dave Jarvis
    Given: Start Month & Start Day End Month & End Day Any Year What SQL statement results in TRUE if a date lands between the Start and End days? 1st example: Start Date = 11-22 End Date = 01-17 Year = 2009 Specific Date = 2010-01-14 TRUE 2nd example: Start Date = 11-22 End Date = 11-16 Year = 2009 Specific Date = 2010-11-20 FALSE 3rd example: Start Date = 02-25 End Date = 03-19 Year = 2004 Specific Date = 2004-02-29 TRUE I was thinking of using the MySQL functions datediff and sign plus a CASE condition to determine whether the year wraps, but it seems rather expensive. Am looking for a simple, efficient calculation. Update The problem is the end date cannot simply use the year. The year must be increased if the end month/day combination happens before the start date. The start date is easy: Start Date = date( concat_ws( '-', year, Start Month, Start Day ) The end date is not so simple. Thank you!

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  • How do I combine two methods into one json formatted variable?

    - by JZ
    I'm storing JSON formatted data into a var adds with the following methods: var adds = <%= raw @add.to_a.to_json %>; var adds = <%= raw @add.nearbys(1).to_json %>; The first line of code stores the location of an individual in JSON format, the second line of code searches for that person's neighbors, within a 1 mile range. How do I combine both of these lines of code and store the data in JSON format in the var adds variable? If you are interested in source, its here. The location is layout/adds.html.erb

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  • Hide button on first of two UIViews, but have it visible on second...

    - by Scott
    So I have a UIViewController (main application controller is a TabBarController). On this there is a UINavigationBar, and a UIBarButtonItem. I'm PRETTY sure I hooked up everything correctly in the Interface Builder and that the outlet in the code is connected to the button in the .xib. It should be because the method works correctly. Now I have another button on this view that brings up a second view, a UIWebView. I want this UIBarButtonItem, labeled "Back", to make the UIWebView dissapear, and bring back the first UIView, which it DOES DO correctly. However, when you are on the first UIView, there is no need to see the UIBarButtonItem, so how can I hide it but then bring it up for the UIWebView. By the way, both views use the same UINavigationBar, the UIWebView is brought up inside the tab bar and the nav bar. Here is my code: #import "WebViewController.h" @implementation WebViewController @synthesize webButton; @synthesize item; @synthesize infoView; UIWebView *webView; + (UIColor*)myColor1 { return [UIColor colorWithRed:0.0f/255.0f green:76.0f/255.0f blue:29.0f/255.0f alpha:1.0f]; } // Creates Nav Bar with default Green at top of screen with given String as title + (UINavigationBar*)myNavBar1: (NSString*)input { UIView *test = [[UIView alloc] initWithFrame:[[UIScreen mainScreen] applicationFrame]]; UINavigationBar *navBar = [[UINavigationBar alloc] initWithFrame:CGRectMake(0.0, 0.0, test.bounds.size.width, 45)]; navBar.tintColor = [WebViewController myColor1]; UINavigationItem *navItem; navItem = [UINavigationItem alloc]; navItem.title = input; [navBar pushNavigationItem:navItem animated:false]; return navBar; } - (IBAction) pushWebButton { self.navigationItem.rightBarButtonItem = item; CGRect webFrame = CGRectMake(0.0, 45.0, 320.0, 365.0); webView = [[UIWebView alloc] initWithFrame:webFrame]; [webView setBackgroundColor:[UIColor whiteColor]]; NSString *urlAddress = @"http://www.independencenavigator.com"; NSURL *url = [NSURL URLWithString:urlAddress]; NSURLRequest *requestObj = [NSURLRequest requestWithURL:url]; webView.scalesPageToFit = YES; [webView loadRequest:requestObj]; [self.view addSubview:webView]; [webView release]; } - (void) pushBackButton { [webView removeFromSuperview]; } // Implement viewDidLoad to do additional setup after loading the view, typically from a nib. - (void)viewDidLoad { self.navigationItem.rightBarButtonItem = nil; [super viewDidLoad]; } @end Anyone know?

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  • How to display a two column ListView in Android?

    - by Josemalive
    Hi, I have an android application that shows a grid view that shows: 1 2 3 4 GridView gridview=(GridView)findViewById(R.id.GridView_test); DataBaseHelper dbhelper=new DataBaseHelper(this); ArrayList<String> test=new ArrayList<String>(5); backlinksadapter.add("1"); backlinksadapter.add("2"); backlinksadapter.add("3"); backlinksadapter.add("4"); ArrayAdapter mAdapter=new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, test); gridview.setAdapter(mAdapter); By the moment is working, but i would like to show foreach line of the grid, 2 columns with the values of a 2 dimensional array (something like the GridView in ASP.Net - as datasource -). I would like to show: 1 | Person 1 2 | Person 2 3 | Person 3 4 | Person 4 Any idea?

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  • Can I use two different look and feels in the same Swing application?

    - by DR
    I'm using the Flamingo ribbon and the Substance Office 2007 look and feel. Of course now every control has this look and feel, even those on dialog boxes. What I want is something like in Office 2007, where the ribbons have their Office 2007 look, but other controls keep their native Vista/XP look. Is it possible to assign certain controls a different look and feel? Perhaps using some kind of chaining or a proxy look and feel?

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  • Basic example of placing two component on one JPanel container?

    - by Bernard
    Here is my code to add to component (JTextArea and JList) to a panel and put it on the frame. Can I divide half/half by BorderLayout? If yes why mine looks messy one stays up one down? What is the other alternative? Regards, Bernard import java.awt.*; import javax.swing.BorderFactory; import javax.swing.border.Border; import javax.swing.JList; import javax.swing.JScrollPane; import javax.swing.JPanel; import javax.swing.JFrame; import javax.swing.JTextArea; public class SimpleBorder { public static void main(String[] args) { JFrame frame = new JFrame(); frame.setSize(500,500); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); Border etched = (Border) BorderFactory.createEtchedBorder(); String[] items = {"A", "B", "C", "D"}; JList list = new JList(items); JTextArea text = new JTextArea(10, 40); JScrollPane scrol = new JScrollPane(text); JScrollPane scrol2 = new JScrollPane(list); JPanel panel= new JPanel(); panel.add(scrol2,BorderLayout.WEST); panel.add(scrol, BorderLayout.EAST); panel.setBorder(etched); frame.add(panel); frame.setVisible(true); } }

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  • CSS Vertical Spacing Issue (Margin?) - Vertical Space Between Two Divs

    - by Sootah
    I've got the layout of my site mostly done. On the domain I'm testing this layout on - http://networkgenius.org/ - there is a vertical space separating the content-wrapper div and the menu div. I have the margins set to 0px for the vertical spacing, and this is the only area that is separated like it is. I'd like the white content area to be pressed up right against the bottom of the menu, so that none of the body's background shows between them. What am I doing wrong?

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  • Populating PHP list() with values in an array.

    - by Mike
    Hi, I have an array: $arr = array('foo', 'bar', 'bash', 'monkey', 'badger'); I want to have the elements in that array appear as the variables in my list(): list($foo, $bar, $bash, $monkey, $badger) = $data; Without actually specifying the variables, I tried; list(implode(",$", $arr)) = $data; and list(extract($arr)) = $data; But they don't work, I get: Fatal error: Can't use function return value in write context Does anyone have any idea whether this is possible? Cheers, Mike

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  • how do i add two delegates to a ui element at run time?

    - by Michael Xu
    Hi everyone, im trying to implement some behaviors when a mapview element scrolls... by coding a delegate for the scrollview inside of a mapview. so, right now, i got a pointer to the scroll view used by the map view in my code. however, i wish to set the delegate of this scroll view inside the map view, but the issue is that the mapview already sets up a default delegate for this scroll view inside the map view. can i make my delegate implement all of the messages of the protocol, explicitly sending them to the mapview's default delegate while also implementing my own behaviors? how else can i go about adding my own delegate behavior, to an already existing default delegate....? thanks everyone, michael

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  • How to use routing in a ASP MVC website to localize in two languages - But keeping exiting URLs

    - by Anders Pedersen
    We have a couple ASP MVC websites just using the standard VS templates default settings - Working as wanted. But now I want to localize these website ( They are now in Dutch and I will add the English language ) I would like to use routing and not Resource because: 1. Languages will differ in content, numbers of pages, etc. 2. The content is mostly text. I would like the URLs to look some thing like this - www.domain.com/en/Home/Index, www.domain.nl/nl/Home/Index. But the last one should also work with - www.domain.nl/Home/Index - Witch is the exciting URLs. I have implemented Phil Haacks areas ViewEngine from this blogpost - http://haacked.com/archive/2008/11/04/areas-in-aspnetmvc.aspx. But only putting the English website in the areas and keeping the Dutch in old structure. Witch are served as Phils default fallback. But the problem is here that I have to duplicate my controllers for both language's. So I tried the work method described in this tread - http://stackoverflow.com/questions/1712167/asp-net-mvc-localization-route. It works OK with the ?en? and /nl/ but not with the old URLs. When using this code in the global.asax the URL without the culture isn't working. public static void RegisterRoutes(RouteCollection routes) { //routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.MapRoute( "Default", // Route name "{culture}/{controller}/{action}/{id}", // URL with parameters new { culture = "nl-NL", controller = "Home", action = "Index", id = "" } // Parameter defaults ); routes.MapRoute( "DefaultWitoutCulture", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = "" } // Parameter defaults ); } I properly overlooking some thing simple but I can't get this to work for me. Or are there a better way of doing this?

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  • How to calculate both positive and negative angle between two lines?

    - by Jaanus
    There is a very handy set of 2d geometry utilities here. The angleBetweenLines has a problem, though. The result is always positive. I need to detect both positive and negative angles, so if one line is 15 degrees "above" or "below" the other line, the shape obviously looks different. The configuration I have is that one line remains stationary, while the other line rotates, and I need to understand what direction it is rotating in, by comparing it with the stationary line. EDIT: in response to swestrup's comment below, the situation is actually that I have a single line, and I record its starting position. The line then rotates from its starting position, and I need to calculate the angle from its starting position to current position. E.g if it has rotated clockwise, it is positive rotation; if counterclockwise, then negative. (Or vice versa.) How to improve the algorithm so it returns the angle as both positive or negative depending on how the lines are positioned?

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  • Singleton class design in C#, are these two classes equivalent?

    - by Oskar
    I was reading up on singleton class design in C# on this great resource and decided to go with alternative 4: public sealed class Singleton1 { static readonly Singleton1 _instance = new Singleton1(); static Singleton1() { } Singleton1() { } public static Singleton1 Instance { get { return _instance; } } } Now I wonder if this can be rewritten using auto properties like this? public sealed class Singleton2 { static Singleton2() { Instance = new Singleton2(); } Singleton2() { } public static Singleton2 Instance { get; private set; } } If its only a matter of readability I definitely prefer the second version, but I want to get it right.

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  • How do I display two different objects in a search?

    - by JZ
    github url I am using a simple search that displays search results: @adds = Add.search(params[:search]) In addition to the search results I'm trying to utilize a method, nearbys(), which displays objects that are close in proximity to the search result. The following method displays objects which are close to 2, but it does not display object 2. How do I display object 2 in conjunction with the nearby objects? @adds = Add.find(2).nearbys(10) While the above code functions, when I use search, @adds = Add.search(params[:search]).nearbys(10) a no method error is returned, undefined methodnearbys' for Array:0x30c3278` How can I search the model for an object AND use the nearbys() method AND display all results returned? Model: def self.search(search) if search find(:all, :conditions => ['address LIKE ?', "%#{search}%"]) # where('address LIKE ?', "%#{search}") else find(:all) end end

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  • Finding if a target number is the sum of two numbers in an array via LINQ and get the and Indices

    - by Dr.H
    Hello I am new to Linq , I found this thread which explain 90% of what I need http://stackoverflow.com/questions/2331882?tab=newest#tab-top , thanks "pdr" but what I need is to get the Indices too , here is my modification I get the index of the first number but I don't know how to get the index of the second number int[] numbers = { 1, 2, 3, 4, 5, 6, 7, 8, 9 }; var result = from item in numbers.Select((n1, idx) => new { n1,idx, shortList = numbers.Take(idx) }) from n2 in item.shortList where item.n1 + n2 == 7 select new { nx1 = item.n1,index1=item.idx, nx2=n2 };

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  • mysql prevent displaying a row ONE which has reference in another row TWO but no reference in row THREE

    - by Jayapal Chandran
    I have a table like the following id | name | pid 1 | sam | NULL 2 | sams ref | 1 3 | pam | NULL For the first time the first row gets inserted which will have pid as null I insert a row which is related to the first row and then i insert a row which is new and which may be referred by another row in future. now i want only the third row to be displayed and not the first and second row as the second row contains the reference of first row. so if any row has a reference to another row then both the rows should not be displayed. Only rows which is not having any reference should be displayed. BESIDES, IS IT A GOOD PRACTICE? PLEASE ADVICE ON THIS. Edited When i updated in server the query is always giving empty result. here is what i have and this one When pid is NULL then that row should appear but when another entry in the same table with pid as its parent id or any other rows id appears then both the rows should not appear. so if any pid has been referred then both the rows should not appear. here only one row will refer another row and not more than that. in my localhost i have mysql version 5.0.1 or something like that but when i installed xampp in another system it had 5.5 and in the live server it was 5.3 so in version around 5.0 the query is returning rows but in higher versions it is returning empty rows. so now i this case how to make a query?

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  • Two AppStore Accounts With The Same Name. I got codeSign error 'Name' appears more than once in the

    - by iTarek
    I got another new account for the AppStore, I setup the new account certificates on my MAC. Now when I try to publish XCode gives me the error CodeSign error: Certificate identity 'iPhone Distribution: 'Name' appears more than once in the keychain. The codesign tool requires there only be one. How can I change my certificate identity for the other account? While I have to leave my Name as it is on both itunes profiles. How can avoid this problem without have to remove one certificate each time I need to publish app on appstore. Thank you.

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  • Java Arrays.equals() returns false for two dimensional arrays.

    - by Achilles
    Hi there, I was just curious to know - why does Arrays.equals(double[][], double[][]) return false? when in fact the arrays have the same number of elements and each element is the same? For example I performed the following test. ` [java] double[][] a, b; int size =5; a=new double[size][size]; b=new double[size][size]; for( int i = 0; i < size; i++ ) for( int j = 0; j < size; j++ ){ a[i][j]=1.0; b[i][j]=1.0; } if(Arrays.equals(a, b)) System.out.println("Equal"); else System.out.println("Not-equal"); [/java] ` Returns false and prints "Not-equal. on the other hand, if I have something like this: [java] double[] a, b; int size =5; a=new double[size]; b=new double[size]; for( int i = 0; i < size; i++ ){ a[i]=1.0; b[i]=1.0; } if(Arrays.equals(a, b)) System.out.println("Equal"); else System.out.println("Not-equal"); } [/java] returns true and prints "Equal". Does the method only work with single dimensions? if so, is there something similar for multi-dimensional arrays in Java?

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  • MySQL - Calculating a value from two columns in each row, using the result in a WHERE or HAVING clause

    - by taber
    I have a MySQL db schema like so: id flags views done ------------------------------- 1 2 20 0 2 66 100 0 3 25 40 0 4 30 60 0 ... thousands of rows ... I want to update all of the rows whose flags / views are = 0.2. First as a test I want to try to SELECT to see how many rows would actually get updated. I tried: SELECT flags/views AS poncho FROM mytable HAVING poncho 0.2 But this only returns like 2 rows and I know there should be a lot more than that. It seems like it's calculating the poncho value on all rows or something odd. What am I doing wrong? Thanks!

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  • Show Visual Studio's Source Control Merge Wizard programmatically

    - by Mike
    Hi, I'm developing a Work item Custom Control and I need to use the standard VS's Merge Wizard for items in source control from my code to allow to user choose the target branch, resolve conflicts etc. I'm pretty sure it's possible in some way (even through the reflection), but I just can't find the proper class in any of VS client assemblies (Microsoft.TeamFoundation.VersionControl.Controls.dll, Microsoft.TeamFoundation.VersionControl.Client.dll). Any help will be appreciated. Best regards, Mike

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