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  • why can't you use the debug/release version of a lib interchangeably

    - by user205834
    In C++, most of the libs come in Debug/Release versions. Question 1. What are the big difference between Debug and Release versions (e.g. what advantages do you have using one versus the other). Question 2. A lib is just has an implementation of the functions, how does a function implementation change if you are using debug/release versions? Question 3. Can you ever build your app in debug mode and use a release version of a lib? Thanks.

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  • Why use C typedefs rather than #defines?

    - by me_and
    What advantage (if any) is there to using typedef in place of #define in C code? As an example, is there any advantage to using typedef unsigned char UBYTE over #define UBYTE unsigned char when both can be used as void func() { UBYTE byte_value = 0; /* Do some stuff */ return byte_value; } Obviously the pre-processor will try to expand a #define wherever it sees one, which wouldn't happen with a typedef, but that doesn't seem to me to be any particular advantage or disadvantage; I can't think of a situation where either use wouldn't result in a build error if there was a problem.

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  • Why do I have to use the "origin" for the pull to be successfull

    - by yan bellavance
    when I do : git pull BranchName it tells me everything is up to date but I know that is not true. When I do: git pull origin BranchName then I get the files I was expecting. Is there an easy way to answer this or do I need to provide more details. PS One thing I did do just to understant themechanics of git is give the branch name in my cloned repo a different name than on the remote repo. I did however put the right name in the config file like so: [branch "myUDPspinoff"] remote = origin merge = refs/heads/UDPspinoff this worked before on another repo but not this one. And when I put everything in the same name thenI did not need to use origin anymore.

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  • Why doesn't this work?

    - by Kyle W
    take = raw_input('Please enter the string of numbers that compose code\n\n\t') y = str(take) l = [] for i in xrange(0, len(y), 3):         l.append(str(y[i:i+3])) b = len(l) a = 0 while(a!=b):         c = l[a].replace('444', ' ')         c = l[a].replace('111', 'a')         c = l[a].replace('112', 'b')         c = l[a].replace('113', 'c')         c = l[a].replace('114', 'd')         c = l[a].replace('115', 'e')         etc...         a = a + 1 filename = 'decmes.txt' file = open(filename, 'w') file.write(c) file.close() I can enter anything, just 111 for example and it gives me back the same thing I put in. Maybe it's something dumb, but I can't figure it out.

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  • There's @interface in my @implementation — why is that?

    - by Mark McDonald
    This is a pretty noobish question – I'm looking at some Cocoa sample code and there's @interface blocks in the .m files as well as the headers. For instance, in the AppDelegate class header, a UIWindow and UI navigation are defined as instance variables, but the @property declarations are actually made in the implementation file. Is there a functional reason for this, is it a stylistic choice, or… ?

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  • RoR: Condition Always False - Why?

    - by Matt Hollingsworth
    Working in RoR 2.3.x. My quiz_results table has a row for user_id (3907) and result (0.1), and two users I'm looking at with no rows in the quiz_results table. This line keeps returining false: -if QuizResult.find_by_user_id(@user_id).present? But if I change it to anything that returns true, the next line reports an error on the * method: ="#{(QuizResult.average('score', :conditions => 'user_id = #{@user.id}') * 100).round}%" The beginning of the code is a loop: [email protected] do |user| Any ideas how to fix? Have tried unsuccessfully all day.

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  • Why does this program stop running?

    - by designloper
    Hi everyone....I am developing a card making system...nothing fancy. Right got this far but program now stops running with no error when running after the first card sample i.e. " Enter 'OK' if this card is OK, otherwise enter an alternative border character: + ". Any suggestions Java Masters? //Ask user for input //makes use of print line method System.out.println("Enter name: "); //took the variables //called the object of the scanner 'cardOrder' //and use the Scanner objects method '.nextLine' //to read the next line of the input firstName = cardOrder.nextLine(); mInitial = cardOrder.nextLine(); lastName = cardOrder.nextLine(); //Print out the "Here is a sample card" + the first name, middle initial and last name System.out.println("Here is a sample card: \n\n" + firstName + mInitial + lastName + "**************" + "**************" + firstName + mInitial + lastName + "\n* *" + "\n*" + " " + firstName + mInitial + lastName + " *" + "\n* *\n" + firstName + mInitial + lastName +"**************" + "**************" + firstName + mInitial + lastName + "\n"); //Ask user is the card is OK to proceed to order query or if they want an alternative border character: + System.out.println("Enter 'OK' if this card is OK, otherwise enter an alternative border character: + "); //Check if user entered "OK" and store it in var optionA optionA = cardOrder.nextLine(); //test if (a == optionA){ System.out.println("\nHow many cards would you like? "); cardsOrdered = cardOrder.nextInt(); equals = (int) (cardPriceA * cardsOrdered); System.out.println("The price of " + cardsOrdered + " cards"+ " is £" + equals + ".\n"); System.out.println("No Discount given."); } else if(b == optionA) { //Print out the "Here is a sample card" + the first name, middle initial and last name System.out.println("Here is a sample card: \n\n" + firstName + mInitial + lastName + "++++++++++++++" + "++++++++++++++" + firstName + mInitial + lastName + "\n+ +" + "\n+" + " " + firstName + mInitial + lastName + " +" + "\n+ +\n" + firstName + mInitial + lastName +"++++++++++++++" + "++++++++++++++" + firstName + mInitial + lastName + "\n"); //Ask user is the card is OK to proceed to order query or if they want an alternative border character: + System.out.println("Enter 'OK' if this card is OK, otherwise enter an alternative border character: OK "); //Check if user entered "OK" and store it in var optionA optionA = cardOrder.nextLine(); if (a == optionA){ System.out.println("\nHow many cards would you like? "); cardsOrdered = cardOrder.nextInt(); equals = (int) (cardPriceA * cardsOrdered); System.out.println("The price of " + cardsOrdered + " cards"+ " is £" + equals + ".\n"); System.out.println("No Discount given."); } } else if (c == optionA) {//Print out the "Here is a sample card" + the first name, middle initial and last name System.out.println("Here is a sample card: \n\n" + firstName + mInitial + lastName + "**************" + "**************" + firstName + mInitial + lastName + "\n* *" + "\n*" + " " + firstName + mInitial + lastName + " *" + "\n* *\n" + firstName + mInitial + lastName +"**************" + "**************" + firstName + mInitial + lastName + "\n"); //Ask user is the card is OK to proceed to order query or if they want an alternative border character: + System.out.println("Enter 'OK' if this card is OK, otherwise enter an alternative border character: + "); //Check if user entered "OK" and store it in var optionA optionA = cardOrder.nextLine(); if (a == optionA){ System.out.println("\nHow many cards would you like? "); cardsOrdered = cardOrder.nextInt(); equals = (int) (cardPriceA * cardsOrdered); System.out.println("The price of " + cardsOrdered + " cards"+ " is £" + equals + ".\n"); System.out.println("No Discount given."); } }

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  • Why does this PHP program not work?

    - by oncode
    I'm new to PHP and was learning about PHP functions from w3schools. It said PHP allows a function call to be made when the function name is in a variable: This program worked <?php $v = "var_dump"; $v('foo'); ?> But this program did not work: <?php $v = "echo"; $v('foo'); ?> But if I do echo('foo'); it works. What am I doing wrong?

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  • Why is it not displaying

    - by Doug
    My fieldset doesn't display onclick, what am I doing wrong? $(document).ready(function(){ $('#More').toggle( function() { $('#search', this).slideDown(); }, function() { $('#search', this).slideUp(); }); }); <div> Item 1 <a href="#" id="More">Item 2</a> Item 3 <fieldset id="search" style="display: none;"> <form> <input type="text"> </form> </fieldset> </div>

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  • Why isn't Chrome displaying my div?

    - by Kyle Sevenoaks
    Click here to see a simple example of what I want. It's really easy, but for some reason Google won't display it. It's part of a foreach loop, if needed I can add other codes. There is nothing else in the rest of the css to mess with this, I have checked about 10 times. Thanks.

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  • Why am i not getting relevant adsense ads?

    - by user329953
    most of my traffic is on video media pages, like this one http://markem.iyobo.com/7AXzCJkehsS however i have already implimented section targeting as you can see by viewing the page source. sections targeted are as follows title descp tags after waiting for some time, relevant ads still fail to show up. what seems to be the problem? and what can we do to make it better helpful and friendly tips welcome

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  • why "$(opener.document).ready()" is not working?

    - by KK
    I tried something like, below in popup-window, but not working... any correction at line 3, please suggest. function closePopup() { window.opener.history.go(0); $(opener.document).ready(function(){ window.opener.some_function(some_variable); self.close(); }); }

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  • Why is graphical emacs so ugly?

    - by Michael Gummelt
    Every hacker I know uses terminal emacs. Graphical emacs is hideous. The default text is huge and out of place, and the borders are much bigger and blockier than in any other application. Everything I've read about switching the font is confusing and completely different than the font selection used by other applications (I'm on Ubuntu). Does anyone actually use graphical emacs (vs -nw)? If so, how do you make it bearable?

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  • Why is my index view not working when I implement datepicker in my rails app

    - by user3736107
    Hi I am new to rails and would really appreciate some help, I am using the jQuery datepicker, the show view works however the index view doesn't, i get "undefined method `start_date' for nil:NilClass" in my index.html.erb file. Can you please let me know what is wrong with my index view and how i can fix it. The following are included in my app: meetups_controller.rb def show @meetup = Meetup.find(params[:id]) end def index @meetups = Meetup.where('user_id = ?', current_user.id).order('created_at DESC') end show.html.erb <h3>Title: <%= @meetup.title %></h3> <p>Start date: <%= @meetup.start_date.strftime("%B %e, %Y") %></p> <p>Start time: <%= @meetup.start_time.strftime("%l:%M %P") %></p> <p>End date: <%= @meetup.end_date.strftime("%B %e, %Y") %></p> <p>End time: <%= @meetup.end_time.strftime("%l:%M %P") %></p> index.html.erb <% if @meetups.any? %> <% @meetups.each do |meetup| %> <h3><%= link_to meetup.title, meetup_path(meetup) %></h3> <p>Start date: <%= meetup.start_date.strftime("%B %e, %Y") %></p> <p>Start time: <%= meetup.start_time.strftime("%l:%M %P") %></p> <p>End date: <%= @meetup.end_date.strftime("%B %e, %Y") %></p> <p>End time: <%= @meetup.end_time.strftime("%l:%M %P") %></p>

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  • Why doesn't this inner class compile?

    - by Vincenzo
    This is my code: #include <algorithm> class A { void f() { struct CompareMe { bool operator() (int i, int j) { return i < j; } } comp; int a[] = {1, 2, 3, 4}; int found = std::min_element(a[0], a[3], comp); } } Error message: no matching function for call to ‘min_element(int&, int&, A::f()::CompareMe&) What am I doing wrong?

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  • SQL Server: Why use shorter VARCHAR(n) fields?

    - by chryss
    It is frequently advised to choose database field sizes to be as narrow as possible. I am wondering to what degree this applies to SQL Server 2005 VARCHAR columns: Storing 10-letter English words in a VARCHAR(255) field will not take up more storage than in a VARCHAR(10) field. Are there other reasons to restrict the size of VARCHAR fields to stick as closely as possible to the size of the data? I'm thinking of Performance: Is there an advantage to using a smaller n when selecting, filtering and sorting on the data? Memory, including on the application side (C++)? Style/validation: How important do you consider restricting colunm size to force non-sensical data imports to fail (such as 200-character surnames)? Anything else? Background: I help data integrators with the design of data flows into a database-backed system. They have to use an API that restricts their choice of data types. For character data, only VARCHAR(n) with n <= 255 is available; CHAR, NCHAR, NVARCHAR and TEXT are not. We're trying to lay down some "good practices" rules, and the question has come up if there is a real detriment to using VARCHAR(255) even for data where real maximum sizes will never exceed 30 bytes or so. Typical data volumes for one table are 1-10 Mio records with up to 150 attributes. Query performance (SELECT, with frequently extensive WHERE clauses) and application-side retrieval performance are paramount.

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  • why are javascript functions like this

    - by Kajal
    I am a starter to javascript. I know to write JS userdefined functions. But recently I came across some thing that I can’t recognize. Can anyone explain to me what this is? (function( window, undefined ) { var jQuery = (function() { }); window.jQuery = window.$ = jQuery; })(window); What is the meaning of this? When I Google javascript functions I am getting only function foo(){ alert("This is an alert"); } I know to use these type of functions

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  • why does twitter use the !function syntax in their embed code

    - by samccone
    I was looking at twitters embed code and saw that they are using !function ... while i know that this evaluates to false I was wondering what the point of it was. thoughts? !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs");

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  • Why are my thread being terminated ?

    - by Sephy
    Hi, I'm trying to repeat calls to methods through 3 differents threads. But after I start my threads, during the next iteration of my loop, they are all terminated so nothing is executed... The code is as follows : public static void main(String[] args) { main = new Main(); pollingThread.start(); } static Thread pollingThread = new Thread() { @Override public void run() { while (isRunning) { main.poll(); // test the state of the threads try { Thread.sleep(1000); } catch (InterruptedException e) { e.printStackTrace(); } } }; }; public void poll() { if (clientThread == null) { clientThread = new Thread(new Runnable() { @Override public void run() { //create some objects } }); clientThread.start(); } else if (clientThread.isAlive()) { // do some treatment } if (gestionnaireThread == null) { gestionnaireThread = new Thread(new Runnable() { @Override public void run() { //create some objects }; }); gestionnaireThread.start(); } else if (gestionnaireThread.isAlive()) { // do some treatment } if (marchandThread == null) { marchandThread = new Thread(new Runnable() { @Override public void run() { // create some objects }; }); marchandThread.start(); } else if (marchandThread.isAlive()) { // do some treatment } } And for some reason, when I test the state of my different threads, they appear as runnable and then a the 2nd iteration, they are all terminated... What am I doing wrong? I actually have no error, but the threads are terminated and so my loop keeps looping and telling me the threads are terminated.... Thanks for any help.

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  • Why do I get a Null Pointer Exception?

    - by Roman
    I have this code: Manager manager = new Manager("Name"); MyWindowListener windowListener = new MyWindowListener(); manager.addWindowListener(windowListener); Eclipse writes that I have a NullPointerException in the last line. What can be the reason for that. I do have constructors in the Manager and MyWindowListener. If it's important MyWindowListener implements WindowListener.

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  • Why this doesnt't work in C++?

    - by user3377450
    I'm doing something and I have this: //main.cpp file template<typename t1, typename t2> std::ostream& operator<<(std::ostream& os, const std::pair<t1, t2>& pair) { return os << "< " << pair.first << " , " << pair.second << " >"; } int main() { std::map<int, int> map = { { 1, 2 }, { 2, 3 } }; std::cout << *map.begin() << std::endl;//This works std::copy(map.begin(), map.end(), std::ostream_iterator<std::pair<int,int> >(std::cout, " "));//this doesn't work } I guess this is not working because in the std::copy algorithm the operator isn't defined, but what can I do?

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