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  • Stored procedure optimization

    - by George Zacharia
    Hi, i have a stored procedure which takes lot of time to execure .Can any one suggest a better approch so that the same result set is achived. ALTER PROCEDURE [dbo].[spFavoriteRecipesGET] @USERID INT, @PAGENUMBER INT, @PAGESIZE INT, @SORTDIRECTION VARCHAR(4), @SORTORDER VARCHAR(4),@FILTERBY INT AS BEGIN DECLARE @ROW_START INT DECLARE @ROW_END INT SET @ROW_START = (@PageNumber-1)* @PageSize+1 SET @ROW_END = @PageNumber*@PageSize DECLARE @RecipeCount INT DECLARE @RESULT_SET_TABLE TABLE ( Id INT NOT NULL IDENTITY(1,1), FavoriteRecipeId INT, RecipeId INT, DateAdded DATETIME, Title NVARCHAR(255), UrlFriendlyTitle NVARCHAR(250), [Description] NVARCHAR(MAX), AverageRatingId FLOAT, SubmittedById INT, SubmittedBy VARCHAR(250), RecipeStateId INT, RecipeRatingId INT, ReviewCount INT, TweaksCount INT, PhotoCount INT, ImageName NVARCHAR(50) ) INSERT INTO @RESULT_SET_TABLE SELECT FavoriteRecipes.FavoriteRecipeId, Recipes.RecipeId, FavoriteRecipes.DateAdded, Recipes.Title, Recipes.UrlFriendlyTitle, Recipes.[Description], Recipes.AverageRatingId, Recipes.SubmittedById, COALESCE(users.DisplayName,users.UserName,Recipes.SubmittedBy) As SubmittedBy, Recipes.RecipeStateId, RecipeReviews.RecipeRatingId, COUNT(RecipeReviews.Review), COUNT(RecipeTweaks.Tweak), COUNT(Photos.PhotoId), dbo.udfGetRecipePhoto(Recipes.RecipeId) AS ImageName FROM FavoriteRecipes INNER JOIN Recipes ON FavoriteRecipes.RecipeId=Recipes.RecipeId AND Recipes.RecipeStateId <> 3 LEFT OUTER JOIN RecipeReviews ON RecipeReviews.RecipeId=Recipes.RecipeId AND RecipeReviews.ReviewedById=@UserId AND RecipeReviews.RecipeRatingId= ( SELECT MAX(RecipeReviews.RecipeRatingId) FROM RecipeReviews WHERE RecipeReviews.ReviewedById=@UserId AND RecipeReviews.RecipeId=FavoriteRecipes.RecipeId ) OR RecipeReviews.RecipeRatingId IS NULL LEFT OUTER JOIN RecipeTweaks ON RecipeTweaks.RecipeId = Recipes.RecipeId AND RecipeTweaks.TweakedById= @UserId LEFT OUTER JOIN Photos ON Photos.RecipeId = Recipes.RecipeId AND Photos.UploadedById = @UserId AND Photos.RecipeId = FavoriteRecipes.RecipeId AND Photos.PhotoTypeId = 1 LEFT OUTER JOIN users ON Recipes.SubmittedById = users.UserId WHERE FavoriteRecipes.UserId=@UserId GROUP BY FavoriteRecipes.FavoriteRecipeId, Recipes.RecipeId, FavoriteRecipes.DateAdded, Recipes.Title, Recipes.UrlFriendlyTitle, Recipes.[Description], Recipes.AverageRatingId, Recipes.SubmittedById, Recipes.SubmittedBy, Recipes.RecipeStateId, RecipeReviews.RecipeRatingId, users.DisplayName, users.UserName, Recipes.SubmittedBy; WITH SortResults AS ( SELECT ROW_NUMBER() OVER ( ORDER BY CASE WHEN @SORTDIRECTION = 't' AND @SORTORDER='a' THEN TITLE END ASC, CASE WHEN @SORTDIRECTION = 't' AND @SORTORDER='d' THEN TITLE END DESC, CASE WHEN @SORTDIRECTION = 'r' AND @SORTORDER='a' THEN AverageRatingId END ASC, CASE WHEN @SORTDIRECTION = 'r' AND @SORTORDER='d' THEN AverageRatingId END DESC, CASE WHEN @SORTDIRECTION = 'mr' AND @SORTORDER='a' THEN RecipeRatingId END ASC, CASE WHEN @SORTDIRECTION = 'mr' AND @SORTORDER='d' THEN RecipeRatingId END DESC, CASE WHEN @SORTDIRECTION = 'd' AND @SORTORDER='a' THEN DateAdded END ASC, CASE WHEN @SORTDIRECTION = 'd' AND @SORTORDER='d' THEN DateAdded END DESC ) RowNumber, FavoriteRecipeId, RecipeId, DateAdded, Title, UrlFriendlyTitle, [Description], AverageRatingId, SubmittedById, SubmittedBy, RecipeStateId, RecipeRatingId, ReviewCount, TweaksCount, PhotoCount, ImageName FROM @RESULT_SET_TABLE WHERE ((@FILTERBY = 1 AND SubmittedById= @USERID) OR ( @FILTERBY = 2 AND (SubmittedById <> @USERID OR SubmittedById IS NULL)) OR ( @FILTERBY <> 1 AND @FILTERBY <> 2)) ) SELECT RowNumber, FavoriteRecipeId, RecipeId, DateAdded, Title, UrlFriendlyTitle, [Description], AverageRatingId, SubmittedById, SubmittedBy, RecipeStateId, RecipeRatingId, ReviewCount, TweaksCount, PhotoCount, ImageName FROM SortResults WHERE RowNumber BETWEEN @ROW_START AND @ROW_END print @ROW_START print @ROW_END SELECT @RecipeCount=dbo.udfGetFavRecipesCount(@UserId) SELECT @RecipeCount AS RecipeCount SELECT COUNT(Id) as FilterCount FROM @RESULT_SET_TABLE WHERE ((@FILTERBY = 1 AND SubmittedById= @USERID) OR (@FILTERBY = 2 AND (SubmittedById <> @USERID OR SubmittedById IS NULL)) OR (@FILTERBY <> 1 AND @FILTERBY <> 2)) END

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  • Wildcard DNS with URI Request

    - by gregavola
    So here is my problem. I want to redirect name.domain.com/trips/1 to domain.com?username=name&trip=1 using modrewrite. Is this possible? I have the dns set up correctly however - I am unsure about the htaccess file. Can I link all this information to one PHP or do I need to create a directory for every user? Thanks for your help.

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  • Oracle database link

    - by Sunit
    I'm currently using Windows Authentication with 2 Oracle servers - SP3DSMP1 & SP3DSMP4. I created a database link on SMP1 to connect to SMP4 as: SQL create public database link LINK_SMP4 2 connect to CURRENT_USER 3 using 'SP3DSMP4'; Database link created. However when I try to do a query, I get the error: ERROR at line 1: ORA-01017: invalid username/password; logon denied Any ideas what might be wrong here? thanks Sunit

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  • how to get inbox mails in listview using vb.net?

    - by meenakshi
    I'm trying to collect (yahoo,gmail,hotmail etc.,)inbox mails uding vb.net? i tried this using tcpclient, First i got the tcpclient connection,and get response data from server for (gmail --host-- "pop.gmail.com") got response like "+OK Gpop ready for requests from 122.174.183.249 b15pf3378725rvn.27" second,i'm trying to get response data from server for my username and password it shows message "Unable to read data from the transport connection: An established connection was aborted by the software in your host machine." how can i solve this? Please help me.

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  • How do I login to this site? [closed]

    - by Kevin Monk
    This site drives me crazy! I'm a web developer. I understand technology, I understand OpenID, but I don't have a clue how to login to this site with the username I created whilst asking another question unless I ask yet another question? Sure, this is a techie site but if I can't work out how to log in then what hope is OpenID to the rest of the non technical world?

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  • How to use Linq To Sql to get Users who has less than 2 photos?

    - by Mike108
    The scenario is I want to get the users who has less than 2 photos. There are two table: [Users] (UserId, UserName) [UserPhotos] (PhotoId, PhotoName, UserId) UserId is a Foreign Key but I do not want to use association like user.Photos. A user may have none photo in the [UserPhotos] table. How to use Linq To Sql to get List<User> who has less than 2 photos?

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  • iPhone: how to keep integer value on UILabel

    - by Nandakishore
    i am working on Twitter on iPhone now i have to keep the count of Friend, Tweets, Followers etc on UILabel how to work with this (void)userInfoReceived:(NSArray *)userInfo forRequest:(NSString *)connectionIdentifier { NSLog(@"User Info Received: %@", userInfo); // userInfo contains all user details like userName, screenName, count of Friends, Followers, Following, Status Count etc NSLog(@"User Info Received: %d", [userInfo count]); NSMutableDictionary *profileData = [userInfo objectAtIndex:0]; //converting userInfo array into profileData dictionary lblUserName.text = [profileData objectForKey:@"name"]; // lblUserName is UILabel, userName keeping on Label lblLocation.text = [profileData objectForKey:@"location"]; // lblLocation is UILabel, Location keeping on Label lblDescription.text = [profileData objectForKey:@"description"]; // lblDescription is UILabel, Location keeping on Label /////* Up to here all working but how to Keep integer value on UILabel *///// lblFolCount = (NSNumber *)[profileData objectForKey:@"followers_count"]; //how to keep user Followers Count on UILable lblFavCount = (NSNumber *)[profileData objectForKey:@"favourites_count"]; //how to keep user Followers Count on UILable lblStatusCount = (NSNumber *) [profileData objectForKey:@"statuses_count"]; //how to keep user statuses count on UILable lblFriends = (NSNumber *) [profileData objectForKey:@"friends_count"]; //how to keep user friends count on UILable } ////**This info Display on debugger console*/////// ////NSLog(@"User Info Received: %@", userInfo); // by this we get info on debugger console User Info Received: ( { "created_at" = "Tue Nov 02 14:42:42 +0000 2010"; description = "being honest"; favorited = false; "favourites_count" = 0; "followers_count" = 5; "friends_count" = 21; "listed_count" = 0; location = Chennai; name = "nanda kishore reddyv"; "profile_background_color" = EDECE9; "profile_background_image_url" = "http://a2.twimg.com/a/1292975674/images/themes/theme3/bg.gif"; "profile_background_tile" = false; "profile_image_url" = "http://a2.twimg.com/a/1292975674/images/default_profile_6_normal.png"; "retweet_count" = 0; "screen_name" = velugotinanda; source = "<a href=\"http://www.icodeblog.com\" rel=\"nofollow\">iCodeBlog Oauth Demo</a>"; status = "Mon Dec 27 09:22:44 +0000 2010"; "statuses_count" = 15; "time_zone" = "Indiana (East)"; verified = false; } ) 2011-01-01 10:38:29.460 IdeaTweet[471:207] User Info Received: 1 Thanks YOU can you tell me how to Keep integer Value on UILabel

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  • CFPreferences for another (or all) users

    - by James Turner
    I'm working on a background service which needs to ask several users' iTunes settings (the users will opt-in via a helper application which they run from their login). Is there an easy way to read the preferences for another user, than the current one, using CFPreferences? The docs, for example for CFPreferencesCopyValue, explicitly state: 'Do not use arbitrary user and host names, instead pass the pre-defined domain qualifier constants.', when passing the 'userName' argument to the various functions.

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  • Mercurial auto update problem.

    - by Ezequiel
    We are starting to use Mercurial for source control. We have configured the HGRC configuration file to do an auto update after we push to the "central" repository. With some PCs we get this error msg: warning: changegroup hook exited with status -1 HGRC looks like this: [ui] username=ADMIN verbose=true [hooks] changegroup = hg update >&2 Later we perform the update manually and everything works right.

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  • psql: FATAL: Ident authentication failed for user "postgres"

    - by morpheous
    I have installed PostgreSQL and pgAdminIII on my Ubuntu Karmic box. I am able to use pgAdminIII successfully (i.e. connect/log on), however when I try to login to the server using the same username/pwd on the command line (using psql), I get the error: psql: FATAL: Ident authentication failed for user "postgres" Does anyone now how to resolve this issue?

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  • trusted SQL Server connection

    - by dan_vitch
    When I attempt to make a connection from my console app to my sqlExpress. I get the following error: The user is not associated with a trusted SQL Server connection. I have: Switched users Switched passwords Switched Servers Switched Databases I always get the same error. I am using VS 2010 and Sql Server 2005 Here is my current connection string SqlDatabase sqlDatabase = new SqlDatabase(@"Server=localmachineName\SQLEXPRESS;database=database1;user id=username password=mypassword;");

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  • immplementing security with session variables, how it is insecure

    - by haansi
    Hello, I am doing web based projects in dotnet. Currently I am implementing security using session variables. I keep current user id and user type in session and authenticate user from these session variables (say Session["UserId"],Session["UserName"] and Session["UserType"]) I do authentications. Please guide me how it is insecure ? I heard such security can be broken and applications can be hacked very easily, like it is possible to get session id and directly connect to that session id etc. Please guide me on this thanks

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  • Twitter API - oauth gem - not getting callback

    - by haries
    I redirect the user of my application to Twitter for oauth style authentication using my app's request_token. The user is able to enter username and password on Twitter's page BUT then, instead of calling back my application, Twitter displays a page You've successfully granted access to MyAppName! Simply return to MyAppName and enter the following PIN to complete the process. 123456 Why is this happening? I have set the callback url in my app's settings. Thanks

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  • Variable disappears when I log in

    - by John
    Hello, I have profile page where the profile is retrieved via GET. The index file has this: $profile = $_GET['profile']; When I log in on the profile page, the $profile variable disappears. Here is the form action on the login function: <form name="login-form" id="login-form" method="post" action="./index.php"> (The $profile variable is separate of the login username.) How could I make the page retain the $profile variable? Thanks in advance, John

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  • change password code error

    - by ejah85
    I've created a code to change a password. Now it seem contain an error. When I fill in the form to change password, and click save the error message: Warning: mysql_real_escape_string() expects parameter 2 to be resource, null given in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 103 Warning: mysql_real_escape_string() expects parameter 2 to be resource, null given in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 103 I really don’t know what the error message means. Please guys. Help me fix it. Here's is the code: <?php session_start(); ?> <?php # change password.php //set the page title and include the html header. $page_title = 'Change Your Password'; //include('templates/header.inc'); if(isset($_POST['submit'])){//handle the form require_once('connectioncomplaint.php');//connect to the db. //include "connectioncomplaint.php"; //create a function for escaping the data. function escape_data($data){ global $dbc;//need the connection. if(ini_get('magic_quotes_gpc')){ $data=stripslashes($data); } return mysql_real_escape_string($data, $dbc); }//end function $message=NULL;//create the empty new variable. //check for a username if(empty($_POST['userid'])){ $u=FALSE; $message .='<p> You forgot enter your userid!</p>'; }else{ $u=escape_data($_POST['userid']); } //check for existing password if(empty($_POST['password'])){ $p=FALSE; $message .='<p>You forgot to enter your existing password!</p>'; }else{ $p=escape_data($_POST['password']); } //check for a password and match againts the comfirmed password. if(empty($_POST['password1'])) { $np=FALSE; $message .='<p> you forgot to enter your new password!</p>'; }else{ if($_POST['password1'] == $_POST['password2']){ $np=escape_data($_POST['password1']); }else{ $np=FALSE; $message .='<p> your new password did not match the confirmed new password!</p>'; } } if($u && $p && $np){//if everything's ok. $query="SELECT userid FROM access WHERE (userid='$u' AND password=PASSWORD('$p'))"; $result=@mysql_query($query); $num=mysql_num_rows($result); if($num == 1){ $row=mysql_fetch_array($result, MYSQL_NUM); //make the query $query="UPDATE access SET password=PASSWORD('$np') WHERE userid=$row[0]"; $result=@mysql_query($query);//run the query. if(mysql_affected_rows() == 1) {//if it run ok. //send an email,if desired. echo '<p><b>your password has been changed.</b></p>'; include('templates/footer.inc');//include the HTML footer. exit();//quit the script. }else{//if it did not run OK. $message= '<p>Your password could not be change due to a system error.We apolpgize for any inconvenience.</p><p>' .mysql_error() .'</p>'; } }else{ $message= '<p> Your username and password do not match our records.</p>'; } mysql_close();//close the database connection. }else{ $message .='<p>Please try again.</p>'; } }//end oh=f the submit conditional. //print the error message if there is one. if(isset($message)){ echo'<font color="red">' , $message, '</font>'; } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <body> <script language="JavaScript1.2">mmLoadMenus();</script> <table width="604" height="599" border="0" align="center" cellpadding="0" cellspacing="0"> <tr> <td height="130" colspan="7"><img src="images/banner(E-Complaint)-.jpg" width="759" height="130" /></td> </tr> <tr> <td width="100" height="30" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="160" bgcolor="#ABD519"> <?php include "header.php"; ?>&nbsp;</td> </tr> <tr> <td colspan="7" bgcolor="#FFFFFF"> <fieldset><legend> Enter your information in the form below:</legend> <p><b>User ID:</b> <input type="text" name="username" size="10" maxlength="20" value="<?php if(isset($_POST['userid'])) echo $_POST['userid']; ?>" /></p> <p><b>Current Password:</b> <input type="password" name="password" size="20" maxlength="20" /></p> <p><b>New Password:</b> <input type="password" name="password1" size="20" maxlength="20" /></p> <p><b>Confirm New Password:</b> <input type="password" name="password2" size="20" maxlength="20" /></p> </fieldset> <div align="center"> <input type="submit" name="submit" value="Change My Password" /></div> </form><!--End Form--> </td> </tr> </table> </body> </html>

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  • Java DriverManager Always Assigns My Driver

    - by JGB146
    I am writing a driver to act as a wrapper around two separate MySQL connections (to distributed databases). Basically, the goal is to enable interaction with my driver for all applications instead of requiring the application to sort out which database holds the desired data. Most of the code for this is in place, but I'm having a problem in that when I attempt to create connections via the MySQL Driver, the DriverManager is returning an instance of my driver instead of the MySQL Driver. I'd appreciate any tips on what could be causing this and what could be done to fix it! Below is a few relevant snippets of code. I can provide more, but there's a lot, so I'd need to know what else you want to see. First, from MyDriver.java: public MyDriver() throws SQLException { DriverManager.registerDriver(this); } public Connection connect(String url, Properties info) throws SQLException { try { return new MyConnection(info); } catch (Exception e) { return null; } } public boolean acceptsURL(String url) throws SQLException { if (url.contains("jdbc:jgb://")) { return true; } return false; } It is my understanding that this acceptsURL function will dictate whether or not the DriverManager deems my driver a suitable fit for a given URL. Hence it should only be passing connections from my driver if the URL contains "jdbc:jgb://" right? Here's code from MyConnection.java: Connection c1 = null; Connection c2 = null; /** *Constructors */ public DDBSConnection (Properties info) throws SQLException, Exception { info.list(System.out); //included for testing Class.forName("com.mysql.jdbc.Driver").newInstance(); String url1 = "jdbc:mysql://server1.com/jgb"; String url2 = "jdbc:mysql://server2.com/jgb"; this.c1 = DriverManager.getConnection( url1, info.getProperty("username"), info.getProperty("password")); this.c2 = DriverManager.getConnection( url2, info.getProperty("username"), info.getProperty("password")); } And this tells me two things. First, the info.list() call confirms that the correct user and password are being sent. Second, because we enter an infinite loop, we see that the DriverManager is providing new instances of my connection as matches for the mysql URLs instead of the desired mysql driver/connection. FWIW, I have separately tested implementations that go straight to the mysql driver using this exact syntax (al beit only one at a time), and was able to successfully interact with each database individually from a test application outside of my driver.

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  • .NET User Management Customization

    - by Oliver S
    I was wondering if anyone could point me to some resources concerning customization of the user management system that is built in .NET. What I am talking about is: http://msdn.microsoft.com/en-us/library/ms998347.aspx I would like to know, how can I extend the user fields to store more than just common password, username? I want to store for example: birthday, and other result sets.

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  • Help with IF THEN breaking when comparing results from MYSQL query.

    - by roydukkey
    I'm have a problem with an invite system. The if statement seems to break. It shows the message "Fail" but the UPDATE statement still executes. Why do both the THEN and the ELSE excute? $dbConn = new dbConn(); // Check if POST user_username and user_hash are matching and valid; both are hidden for fields $sql = "SELECT user_username " . "FROM table_users " . "WHERE user_id=".mysql_real_escape_string($_POST["user_id"])." " . "AND user_hash='".mysql_real_escape_string($_POST["user_hash"])."' " . "AND user_enabled=0;"; $objUser = $dbConn->query($sql); // If result contains 1 or more rows if( mysql_num_rows($objUser) != NULL ){ $objUser = mysql_fetch_assoc($objUser); $ssnUser->login( $objUser["user_username"] ); $sql = "UPDATE table_users SET " . "user_enabled=1, " . "user_first_name='".mysql_real_escape_string($_POST["user_first_name"])."', " . "user_last_name='".mysql_real_escape_string($_POST["user_last_name"])."', " . "user_password='".mysql_real_escape_string( md5($_POST["user_password"]) )."' " . "WHERE user_id=".mysql_real_escape_string($_POST["user_id"]).";"; $dbConn->query($sql); echo "Success"; header( "Refresh: 5; url=/account/?action=domains" ); } else { echo "Fail"; } This dbConn Class is as follows: class dbConn{ var $username = "xxxx_admin"; var $password = "xxxxxxxx"; var $server = "localhost"; var $database = "xxxx"; var $objConn; function __construct(){ $conn = mysql_connect( $this->server, $this->username, $this->password, true ); if( !$conn ){ die("Could not connect: ".mysql_error() ); } else { $this->objConn = $conn; } unset($conn); } function __destruct(){ mysql_close( $this->objConn ); unset( $this ); } function query( $query, $db = false ){ mysql_select_db( $db != false ? $db : $this->database, $this->objConn ); $result = mysql_query( $query ); unset($query,$db); return $result; } }

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