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  • How to define a function which repeats itself when passed an argument

    - by ~unutbu
    Is there an easy way to define a function which repeats itself when passed an argument? For example, I've defined the following function (defun swap-sign () (interactive) (search-forward-regexp "[+-]") (if (equal (match-string 0) "-") (replace-match "+") (replace-match "-")) ) I'd like C-u swap-sign to call swap-sign four times. I've tried (defun swap-sign (&optional num) (interactive) (let ((counter 0) (num (if num (string-to-number num) 0))) (while (<= counter num) (search-forward-regexp "[+-]") (if (equal (match-string 0) "-") (replace-match "+") (replace-match "-")) (setq counter (1+ counter))))) but C-u swap-sign still only runs swap-sign (or perhaps more precisely, the body of the while-loop) once. I'm guessing it is because if num is not the right way to test if num is an empty string. Am I on the right track, or is there a better/easier way to extend swap-sign?

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  • How can I get penetration depth from Minkowski Portal Refinement / Xenocollide?

    - by Raven Dreamer
    I recently got an implementation of Minkowski Portal Refinement (MPR) successfully detecting collision. Even better, my implementation returns a good estimate (local minimum) direction for the minimum penetration depth. So I took a stab at adjusting the algorithm to return the penetration depth in an arbitrary direction, and was modestly successful - my altered method works splendidly for face-edge collision resolution! What it doesn't currently do, is correctly provide the minimum penetration depth for edge-edge scenarios, such as the case on the right: What I perceive to be happening, is that my current method returns the minimum penetration depth to the nearest vertex - which works fine when the collision is actually occurring on the plane of that vertex, but not when the collision happens along an edge. Is there a way I can alter my method to return the penetration depth to the point of collision, rather than the nearest vertex? Here's the method that's supposed to return the minimum penetration distance along a specific direction: public static Vector3 CalcMinDistance(List<Vector3> shape1, List<Vector3> shape2, Vector3 dir) { //holding variables Vector3 n = Vector3.zero; Vector3 swap = Vector3.zero; // v0 = center of Minkowski sum v0 = Vector3.zero; // Avoid case where centers overlap -- any direction is fine in this case //if (v0 == Vector3.zero) return Vector3.zero; //always pass in a valid direction. // v1 = support in direction of origin n = -dir; //get the differnce of the minkowski sum Vector3 v11 = GetSupport(shape1, -n); Vector3 v12 = GetSupport(shape2, n); v1 = v12 - v11; //if the support point is not in the direction of the origin if (v1.Dot(n) <= 0) { //Debug.Log("Could find no points this direction"); return Vector3.zero; } // v2 - support perpendicular to v1,v0 n = v1.Cross(v0); if (n == Vector3.zero) { //v1 and v0 are parallel, which means //the direction leads directly to an endpoint n = v1 - v0; //shortest distance is just n //Debug.Log("2 point return"); return n; } //get the new support point Vector3 v21 = GetSupport(shape1, -n); Vector3 v22 = GetSupport(shape2, n); v2 = v22 - v21; if (v2.Dot(n) <= 0) { //can't reach the origin in this direction, ergo, no collision //Debug.Log("Could not reach edge?"); return Vector2.zero; } // Determine whether origin is on + or - side of plane (v1,v0,v2) //tests linesegments v0v1 and v0v2 n = (v1 - v0).Cross(v2 - v0); float dist = n.Dot(v0); // If the origin is on the - side of the plane, reverse the direction of the plane if (dist > 0) { //swap the winding order of v1 and v2 swap = v1; v1 = v2; v2 = swap; //swap the winding order of v11 and v12 swap = v12; v12 = v11; v11 = swap; //swap the winding order of v11 and v12 swap = v22; v22 = v21; v21 = swap; //and swap the plane normal n = -n; } /// // Phase One: Identify a portal while (true) { // Obtain the support point in a direction perpendicular to the existing plane // Note: This point is guaranteed to lie off the plane Vector3 v31 = GetSupport(shape1, -n); Vector3 v32 = GetSupport(shape2, n); v3 = v32 - v31; if (v3.Dot(n) <= 0) { //can't enclose the origin within our tetrahedron //Debug.Log("Could not reach edge after portal?"); return Vector3.zero; } // If origin is outside (v1,v0,v3), then eliminate v2 and loop if (v1.Cross(v3).Dot(v0) < 0) { //failed to enclose the origin, adjust points; v2 = v3; v21 = v31; v22 = v32; n = (v1 - v0).Cross(v3 - v0); continue; } // If origin is outside (v3,v0,v2), then eliminate v1 and loop if (v3.Cross(v2).Dot(v0) < 0) { //failed to enclose the origin, adjust points; v1 = v3; v11 = v31; v12 = v32; n = (v3 - v0).Cross(v2 - v0); continue; } bool hit = false; /// // Phase Two: Refine the portal int phase2 = 0; // We are now inside of a wedge... while (phase2 < 20) { phase2++; // Compute normal of the wedge face n = (v2 - v1).Cross(v3 - v1); n.Normalize(); // Compute distance from origin to wedge face float d = n.Dot(v1); // If the origin is inside the wedge, we have a hit if (d > 0 ) { //Debug.Log("Do plane test here"); float T = n.Dot(v2) / n.Dot(dir); Vector3 pointInPlane = (dir * T); return pointInPlane; } // Find the support point in the direction of the wedge face Vector3 v41 = GetSupport(shape1, -n); Vector3 v42 = GetSupport(shape2, n); v4 = v42 - v41; float delta = (v4 - v3).Dot(n); float separation = -(v4.Dot(n)); if (delta <= kCollideEpsilon || separation >= 0) { //Debug.Log("Non-convergance detected"); //Debug.Log("Do plane test here"); return Vector3.zero; } // Compute the tetrahedron dividing face (v4,v0,v1) float d1 = v4.Cross(v1).Dot(v0); // Compute the tetrahedron dividing face (v4,v0,v2) float d2 = v4.Cross(v2).Dot(v0); // Compute the tetrahedron dividing face (v4,v0,v3) float d3 = v4.Cross(v3).Dot(v0); if (d1 < 0) { if (d2 < 0) { // Inside d1 & inside d2 ==> eliminate v1 v1 = v4; v11 = v41; v12 = v42; } else { // Inside d1 & outside d2 ==> eliminate v3 v3 = v4; v31 = v41; v32 = v42; } } else { if (d3 < 0) { // Outside d1 & inside d3 ==> eliminate v2 v2 = v4; v21 = v41; v22 = v42; } else { // Outside d1 & outside d3 ==> eliminate v1 v1 = v4; v11 = v41; v12 = v42; } } } return Vector3.zero; } }

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  • C#/.NET Little Wonders: Interlocked Read() and Exchange()

    - by James Michael Hare
    Once again, in this series of posts I look at the parts of the .NET Framework that may seem trivial, but can help improve your code by making it easier to write and maintain. The index of all my past little wonders posts can be found here. Last time we discussed the Interlocked class and its Add(), Increment(), and Decrement() methods which are all useful for updating a value atomically by adding (or subtracting).  However, this begs the question of how do we set and read those values atomically as well? Read() – Read a value atomically Let’s begin by examining the following code: 1: public class Incrementor 2: { 3: private long _value = 0; 4:  5: public long Value { get { return _value; } } 6:  7: public void Increment() 8: { 9: Interlocked.Increment(ref _value); 10: } 11: } 12:  It uses an interlocked increment, as we discuss in my previous post (here), so we know that the increment will be thread-safe.  But, to realize what’s potentially wrong we have to know a bit about how atomic reads are in 32 bit and 64 bit .NET environments. When you are dealing with an item smaller or equal to the system word size (such as an int on a 32 bit system or a long on a 64 bit system) then the read is generally atomic, because it can grab all of the bits needed at once.  However, when dealing with something larger than the system word size (reading a long on a 32 bit system for example), it cannot grab the whole value at once, which can lead to some problems since this read isn’t atomic. For example, this means that on a 32 bit system we may read one half of the long before another thread increments the value, and the other half of it after the increment.  To protect us from reading an invalid value in this manner, we can do an Interlocked.Read() to force the read to be atomic (of course, you’d want to make sure any writes or increments are atomic also): 1: public class Incrementor 2: { 3: private long _value = 0; 4:  5: public long Value 6: { 7: get { return Interlocked.Read(ref _value); } 8: } 9:  10: public void Increment() 11: { 12: Interlocked.Increment(ref _value); 13: } 14: } Now we are guaranteed that we will read the 64 bit value atomically on a 32 bit system, thus ensuring our thread safety (assuming all other reads, writes, increments, etc. are likewise protected).  Note that as stated before, and according to the MSDN (here), it isn’t strictly necessary to use Interlocked.Read() for reading 64 bit values on 64 bit systems, but for those still working in 32 bit environments, it comes in handy when dealing with long atomically. Exchange() – Exchanges two values atomically Exchange() lets us store a new value in the given location (the ref parameter) and return the old value as a result. So just as Read() allows us to read atomically, one use of Exchange() is to write values atomically.  For example, if we wanted to add a Reset() method to our Incrementor, we could do something like this: 1: public void Reset() 2: { 3: _value = 0; 4: } But the assignment wouldn’t be atomic on 32 bit systems, since the word size is 32 bits and the variable is a long (64 bits).  Thus our assignment could have only set half the value when a threaded read or increment happens, which would put us in a bad state. So instead, we could write Reset() like this: 1: public void Reset() 2: { 3: Interlocked.Exchange(ref _value, 0); 4: } And we’d be safe again on a 32 bit system. But this isn’t the only reason Exchange() is valuable.  The key comes in realizing that Exchange() doesn’t just set a new value, it returns the old as well in an atomic step.  Hence the name “exchange”: you are swapping the value to set with the stored value. So why would we want to do this?  Well, anytime you want to set a value and take action based on the previous value.  An example of this might be a scheme where you have several tasks, and during every so often, each of the tasks may nominate themselves to do some administrative chore.  Perhaps you don’t want to make this thread dedicated for whatever reason, but want to be robust enough to let any of the threads that isn’t currently occupied nominate itself for the job.  An easy and lightweight way to do this would be to have a long representing whether someone has acquired the “election” or not.  So a 0 would indicate no one has been elected and 1 would indicate someone has been elected. We could then base our nomination strategy as follows: every so often, a thread will attempt an Interlocked.Exchange() on the long and with a value of 1.  The first thread to do so will set it to a 1 and return back the old value of 0.  We can use this to show that they were the first to nominate and be chosen are thus “in charge”.  Anyone who nominates after that will attempt the same Exchange() but will get back a value of 1, which indicates that someone already had set it to a 1 before them, thus they are not elected. Then, the only other step we need take is to remember to release the election flag once the elected thread accomplishes its task, which we’d do by setting the value back to 0.  In this way, the next thread to nominate with Exchange() will get back the 0 letting them know they are the new elected nominee. Such code might look like this: 1: public class Nominator 2: { 3: private long _nomination = 0; 4: public bool Elect() 5: { 6: return Interlocked.Exchange(ref _nomination, 1) == 0; 7: } 8: public bool Release() 9: { 10: return Interlocked.Exchange(ref _nomination, 0) == 1; 11: } 12: } There’s many ways to do this, of course, but you get the idea.  Running 5 threads doing some “sleep” work might look like this: 1: var nominator = new Nominator(); 2: var random = new Random(); 3: Parallel.For(0, 5, i => 4: { 5:  6: for (int j = 0; j < _iterations; ++j) 7: { 8: if (nominator.Elect()) 9: { 10: // elected 11: Console.WriteLine("Elected nominee " + i); 12: Thread.Sleep(random.Next(100, 5000)); 13: nominator.Release(); 14: } 15: else 16: { 17: // not elected 18: Console.WriteLine("Did not elect nominee " + i); 19: } 20: // sleep before check again 21: Thread.Sleep(1000); 22: } 23: }); And would spit out results like: 1: Elected nominee 0 2: Did not elect nominee 2 3: Did not elect nominee 1 4: Did not elect nominee 4 5: Did not elect nominee 3 6: Did not elect nominee 3 7: Did not elect nominee 1 8: Did not elect nominee 2 9: Did not elect nominee 4 10: Elected nominee 3 11: Did not elect nominee 2 12: Did not elect nominee 1 13: Did not elect nominee 4 14: Elected nominee 0 15: Did not elect nominee 2 16: Did not elect nominee 4 17: ... Another nice thing about the Interlocked.Exchange() is it can be used to thread-safely set pretty much anything 64 bits or less in size including references, pointers (in unsafe mode), floats, doubles, etc.  Summary So, now we’ve seen two more things we can do with Interlocked: reading and exchanging a value atomically.  Read() and Exchange() are especially valuable for reading/writing 64 bit values atomically in a 32 bit system.  Exchange() has value even beyond simply atomic writes by using the Exchange() to your advantage, since it reads and set the value atomically, which allows you to do lightweight nomination systems. There’s still a few more goodies in the Interlocked class which we’ll explore next time! Technorati Tags: C#,CSharp,.NET,Little Wonders,Interlocked

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  • linux thread synchronization

    - by johnnycrash
    I am new to linux and linux threads. I have spent some time googling to try to understand the differences between all the functions available for thread synchronization. I still have some questions. I have found all of these different types of synchronizations, each with a number of functions for locking, unlocking, testing the lock, etc. gcc atomic operations futexes mutexes spinlocks seqlocks rculocks conditions semaphores My current (but probably flawed) understanding is this: semaphores are process wide, involve the filesystem (virtually I assume), and are probably the slowest. Futexes might be the base locking mechanism used by mutexes, spinlocks, seqlocks, and rculocks. Futexes might be faster than the locking mechanisms that are based on them. Spinlocks dont block and thus avoid context swtiches. However they avoid the context switch at the expense of consuming all the cycles on a CPU until the lock is released (spinning). They should only should be used on multi processor systems for obvious reasons. Never sleep in a spinlock. The seq lock just tells you when you finished your work if a writer changed the data the work was based on. You have to go back and repeat the work in this case. Atomic operations are the fastest synch call, and probably are used in all the above locking mechanisms. You do not want to use atomic operations on all the fields in your shared data. You want to use a lock (mutex, futex, spin, seq, rcu) or a single atomic opertation on a lock flag when you are accessing multiple data fields. My questions go like this: Am I right so far with my assumptions? Does anyone know the cpu cycle cost of the various options? I am adding parallelism to the app so we can get better wall time response at the expense of running fewer app instances per box. Performances is the utmost consideration. I don't want to consume cpu with context switching, spinning, or lots of extra cpu cycles to read and write shared memory. I am absolutely concerned with number of cpu cycles consumed. Which (if any) of the locks prevent interruption of a thread by the scheduler or interrupt...or am I just an idiot and all synchonization mechanisms do this. What kinds of interruption are prevented? Can I block all threads or threads just on the locking thread's CPU? This question stems from my fear of interrupting a thread holding a lock for a very commonly used function. I expect that the scheduler might schedule any number of other workers who will likely run into this function and then block because it was locked. A lot of context switching would be wasted until the thread with the lock gets rescheduled and finishes. I can re-write this function to minimize lock time, but still it is so commonly called I would like to use a lock that prevents interruption...across all processors. I am writing user code...so I get software interrupts, not hardware ones...right? I should stay away from any functions (spin/seq locks) that have the word "irq" in them. Which locks are for writing kernel or driver code and which are meant for user mode? Does anyone think using an atomic operation to have multiple threads move through a linked list is nuts? I am thinking to atomicly change the current item pointer to the next item in the list. If the attempt works, then the thread can safely use the data the current item pointed to before it was moved. Other threads would now be moved along the list. futexes? Any reason to use them instead of mutexes? Is there a better way than using a condition to sleep a thread when there is no work? When using gcc atomic ops, specifically the test_and_set, can I get a performance increase by doing a non atomic test first and then using test_and_set to confirm? *I know this will be case specific, so here is the case. There is a large collection of work items, say thousands. Each work item has a flag that is initialized to 0. When a thread has exclusive access to the work item, the flag will be one. There will be lots of worker threads. Any time a thread is looking for work, they can non atomicly test for 1. If they read a 1, we know for certain that the work is unavailable. If they read a zero, they need to perform the atomic test_and_set to confirm. So if the atomic test_and_set is 500 cpu cycles because it is disabling pipelining, causes cpu's to communicate and L2 caches to flush/fill .... and a simple test is 1 cycle .... then as long as I had a better ratio of 500 to 1 when it came to stumbling upon already completed work items....this would be a win.* I hope to use mutexes or spinlocks to sparilngly protect sections of code that I want only one thread on the SYSTEM (not jsut the CPU) to access at a time. I hope to sparingly use gcc atomic ops to select work and minimize use of mutexes and spinlocks. For instance: a flag in a work item can be checked to see if a thread has worked it (0=no, 1=yes or in progress). A simple test_and_set tells the thread if it has work or needs to move on. I hope to use conditions to wake up threads when there is work. Thanks!

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  • Cannot convert parameter 1 from 'short *' to 'int *' [closed]

    - by Torben Carrington
    I'm trying to learn pointers and since I recently learned that short int takes up less memory [2 bytes as apposed to the long int's memory usage of 4 which is the default for int] I wanted to create a pointer that uses the memory address of a short integer. I'm following a tutorial in my book about Pointers and it's using the Swap function. The problem is I receive this error the moment I change everything from int to short int: error C2664: 'Swap' : cannot convert parameter 1 from 'short *' to 'int *' 1 Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast Since my code is so small here is the whole thing: void Swap(short int *sipX, short int *sipY) { short int siTemp = *sipX; *sipX = *sipY; *sipY = siTemp; } int main() { short int siBig = 100; short int siSmall = 1; std::cout << "Pre-Swap: " << siBig << " " << siSmall << std::endl; Swap(&siBig, &siSmall); std::cout << "Post-Swap: " << siBig << " " << siSmall << std::endl; return 0; }

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  • Partition does not start on physical sector boundary?

    - by jasmines
    I've one HD on my laptop, with two partitions (one ext3 with Ubuntu 12.04 installed and one swap). fdisk is giving me a Partition 1 does not start on physical sector boundary warning. What is the cause and do I need to fix it? If so, how? This is sudo fdisk -l: Disk /dev/sda: 750.2 GB, 750156374016 bytes 255 testine, 63 settori/tracce, 91201 cilindri, totale 1465149168 settori Unità = settori di 1 * 512 = 512 byte Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Identificativo disco: 0x5a25087f Dispositivo Boot Start End Blocks Id System /dev/sda1 * 63 1448577023 724288480+ 83 Linux Partition 1 does not start on physical sector boundary. /dev/sda2 1448577024 1465147391 8285184 82 Linux swap / Solaris This is sudo lshw related result: *-disk description: ATA Disk product: WDC WD7500BPKT-0 vendor: Western Digital physical id: 0 bus info: scsi@0:0.0.0 logical name: /dev/sda version: 01.0 serial: WD-WX21CC1T0847 size: 698GiB (750GB) capabilities: partitioned partitioned:dos configuration: ansiversion=5 signature=5a25087f *-volume:0 description: EXT3 volume vendor: Linux physical id: 1 bus info: scsi@0:0.0.0,1 logical name: /dev/sda1 logical name: / version: 1.0 serial: cc5c562a-bc59-4a37-b589-805b27b2cbd7 size: 690GiB capacity: 690GiB capabilities: primary bootable journaled extended_attributes large_files recover ext3 ext2 initialized configuration: created=2010-02-27 09:18:28 filesystem=ext3 modified=2012-06-23 18:33:59 mount.fstype=ext3 mount.options=rw,relatime,errors=remount-ro,user_xattr,barrier=1,data=ordered mounted=2012-06-28 00:20:47 state=mounted *-volume:1 description: Linux swap volume physical id: 2 bus info: scsi@0:0.0.0,2 logical name: /dev/sda2 version: 1 serial: 16a7fee0-be9e-4e34-9dc3-28f4eeb61bf6 size: 8091MiB capacity: 8091MiB capabilities: primary nofs swap initialized configuration: filesystem=swap pagesize=4096 These are related /etc/fstab lines: UUID=cc5c562a-bc59-4a37-b589-805b27b2cbd7 / ext3 errors=remount-ro,user_xattr 0 1 UUID=16a7fee0-be9e-4e34-9dc3-28f4eeb61bf6 none swap sw 0 0

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  • Used mountmanager now Ubuntu hangs on boot

    - by fpghost
    I was using MountManager in Ubuntu 12.04 to set user permissions in mounting hard drives. I set each partititon to be mountable by everyone instead of admin only. Then I clicked Apply in the file menu and it gave me the message successfully updated. Upon restarting Ubuntu, just hangs on the splash screen and does not boot any further. Windows still boots fine. How can I fix these? please help thanks From LiveUSB: my fstab looks like: overlayfs / overlayfs rw 0 0 tmpfs /tmp tmpfs nosuid,nodev 0 0 /dev/sda5 swap swap defaults 0 0 /dev/sda7 swap swap defaults 0 0 Is this corrupted? Other things that may be helpful: blkid returns /dev/loop0: TYPE="squashfs" /dev/sda1: LABEL="System Reserved" UUID="0AF26C31F26C22E5" TYPE="ntfs" /dev/sda2: UUID="5E1C88E31C88B813" TYPE="ntfs" /dev/sda3: UUID="94B2BB7DB2BB6282" TYPE="ntfs" /dev/sda5: UUID="41b66b9a-2b48-45cf-b59d-cd50e41ec971" TYPE="swap" /dev/sda6: UUID="c73ca79e-4fa4-4bde-967e-670593736f6a" TYPE="ext4" /dev/sda7: UUID="c05d659f-103c-4444-9dc4-3121b9e081d6" TYPE="swap" /dev/sdb1: LABEL="PENDRIVE" UUID="1DE8-0A49" TYPE="vfat" and cat /proc/mounts rootfs / rootfs rw 0 0 sysfs /sys sysfs rw,nosuid,nodev,noexec,relatime 0 0 proc /proc proc rw,nosuid,nodev,noexec,relatime 0 0 udev /dev devtmpfs rw,relatime,size=1950000k,nr_inodes=206759,mode=755 0 0 devpts /dev/pts devpts rw,nosuid,noexec,relatime,gid=5,mode=620,ptmxmode=000 0 0 tmpfs /run tmpfs rw,nosuid,relatime,size=783056k,mode=755 0 0 /dev/sdb1 /cdrom vfat rw,relatime,fmask=0022,dmask=0022,codepage=cp437,iocharset=iso8859-1,shortname=mixed,erro rs=remount-ro 0 0 /dev/loop0 /rofs squashfs ro,noatime 0 0 tmpfs /cow tmpfs rw,noatime,mode=755 0 0 /cow / overlayfs rw,relatime,lowerdir=//filesystem.squashfs,upperdir=/cow 0 0 none /sys/fs/fuse/connections fusectl rw,relatime 0 0 none /sys/kernel/debug debugfs rw,relatime 0 0 none /sys/kernel/security securityfs rw,relatime 0 0 tmpfs /tmp tmpfs rw,nosuid,nodev,relatime 0 0 none /run/lock tmpfs rw,nosuid,nodev,noexec,relatime,size=5120k 0 0 none /run/shm tmpfs rw,nosuid,nodev,relatime 0 0 gvfs-fuse-daemon /home/ubuntu/.gvfs fuse.gvfs-fuse-daemon rw,nosuid,nodev,relatime,user_id=999,group_id=999 0 0

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  • how to swap array-elements to transfer the array from a column-like into a row-like representation

    - by Christian Ammer
    For example: the array a1, a2, a3, b1, b2, b3, c1, c2, c3, d1, d2, d3 represents following table a1, b1, c1, d1 a2, b2, c2, d2 a3, b3, c3, d3 now i like to bring the array into following form a1, b1, c1, d1, a2, b2, c2, d2, a3, b3, c3, d3 Does an algorithm exist, which takes the array (from the first form) and the dimensions of the table as input arguments and which transfers the array into the second form? I thougt of an algorithm which doesn't need to allocate additional memory, instead i think it should be possible to do the job with element-swap operations.

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  • Normalisation and 'Anima notitia copia' (Soul of the Database)

    - by Phil Factor
    (A Guest Editorial for Simple-Talk) The other day, I was staring  at the sys.syslanguages  table in SQL Server with slightly-raised eyebrows . I’d just been reading Chris Date’s  interesting book ‘SQL and Relational Theory’. He’d made the point that you’re not necessarily doing relational database operations by using a SQL Database product.  The same general point was recently made by Dino Esposito about ASP.NET MVC.  The use of ASP.NET MVC doesn’t guarantee you a good application design: It merely makes it possible to test it. The way I’d describe the sentiment in both cases is ‘you can hit someone over the head with a frying-pan but you can’t call it cooking’. SQL enables you to create relational databases. However,  even if it smells bad, it is no crime to do hideously un-relational things with a SQL Database just so long as it’s necessary and you can tell the difference; not only that but also only if you’re aware of the risks and implications. Naturally, I’ve never knowingly created a database that Codd would have frowned at, but around the edges are interfaces and data feeds I’ve written  that have caused hissy fits amongst the Normalisation fundamentalists. Part of the problem for those who agonise about such things  is the misinterpretation of Atomicity.  An atomic value is one for which, in the strange virtual universe you are creating in your database, you don’t have any interest in any of its component parts.  If you aren’t interested in the electrons, neutrinos,  muons,  or  taus, then  an atom is ..er.. atomic. In the same way, if you are passed a JSON string or XML, and required to store it in a database, then all you need to do is to ask yourself, in your role as Anima notitia copia (Soul of the database) ‘have I any interest in the contents of this item of information?’.  If the answer is ‘No!’, or ‘nequequam! Then it is an atomic value, however complex it may be.  After all, you would never have the urge to store the pixels of images individually, under the misguided idea that these are the atomic values would you?  I would, of course,  ask the ‘Anima notitia copia’ rather than the application developers, since there may be more than one application, and the applications developers may be designing the application in the absence of full domain knowledge, (‘or by the seat of the pants’ as the technical term used to be). If, on the other hand, the answer is ‘sure, and we want to index the XML column’, then we may be in for some heavy XML-shredding sessions to get to store the ‘atomic’ values and ensure future harmony as the application develops. I went back to looking at the sys.syslanguages table. It has a months column with the months in a delimited list January,February,March,April,May,June,July,August,September,October,November,December This is an ordered list. Wicked? I seem to remember that this value, like shortmonths and days, is treated as a ‘thing’. It is merely passed off to an external  C++ routine in order to format a date in a particular language, and never accessed directly within the database. As far as the database is concerned, it is an atomic value.  There is more to normalisation than meets the eye.

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  • Is it a good idea to create seperate root, home, swap prior to installing Ubuntu or just Installing Ubuntu on a Single partition is a Good Choice?

    - by Curious Apprentice
    I wish to go for dual boot installation with already installed windows 7. Now, should I choose " Install along Side of Windows 7 " or go to advanced and make separate partitions for home, swap ,root etc ? What are the advantages of doing it ? There are similar topics on askubuntu.com. But here I want a complete answer. Edit : What is / and /root ? How i can allocate maximum space for software installation ? (70% for software and 30 % for home)

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  • Permuting a binary tree without the use of lists

    - by Banang
    I need to find an algorithm for generating every possible permutation of a binary tree, and need to do so without using lists (this is because the tree itself carries semantics and restraints that cannot be translated into lists). I've found an algorithm that works for trees with the height of three or less, but whenever I get to greater hights, I loose one set of possible permutations per height added. Each node carries information about its original state, so that one node can determine if all possible permutations have been tried for that node. Also, the node carries information on weather or not it's been 'swapped', i.e. if it has seen all possible permutations of it's subtree. The tree is left-centered, meaning that the right node should always (except in some cases that I don't need to cover for this algorithm) be a leaf node, while the left node is always either a leaf or a branch. The algorithm I'm using at the moment can be described sort of like this: if the left child node has been swapped swap my right node with the left child nodes right node set the left child node as 'unswapped' if the current node is back to its original state swap my right node with the lowest left nodes' right node swap the lowest left nodes two childnodes set my left node as 'unswapped' set my left chilnode to use this as it's original state set this node as swapped return null return this; else if the left child has not been swapped if the result of trying to permute left child is null return the permutation of this node else return the permutation of the left child node if this node has a left node and a right node that are both leaves swap them set this node to be 'swapped' The desired behaviour of the algoritm would be something like this: branch / | branch 3 / | branch 2 / | 0 1 branch / | branch 3 / | branch 2 / | 1 0 <-- first swap branch / | branch 3 / | branch 1 <-- second swap / | 2 0 branch / | branch 3 / | branch 1 / | 0 2 <-- third swap branch / | branch 3 / | branch 0 <-- fourth swap / | 1 2 and so on... Sorry for the ridiculisly long and waddly explanation, would really, really apreciate any sort of help you guys could offer me. Thanks a bunch!

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  • External HDD incorrectly detected as internal - how change to enable hot swap/eject?

    - by Sam
    Hi All, I have win 7 x64 Home Prem. The HDD is a seagate barracuda, 7200.7 ST3120827AS. 3.5", Serial: 3ms006n6, Firmware: 3.42 (no further updates) NexStar CX External case (drivers installed). I have three drives: WD320 with OS installed WD750 data storage (internal) seagate 120 (external) - connected via esata board connected to sata on motherboard (MSI p43 neo) Tried uninstalling HDD in device manager to no effect. Also the internal WD750 is detected as an external drive and win taskbar icon allows for it to be ejected (unlike the seagate). All drives are configured - Online, Simple, Basic, NTFS, Active, Primary Partition (except c drive). The seagate was previously used as a primary disk with XP operating system so I deleted the volume and created/reformatted (not quick). HDD is no longer "Active". But did not fix problem. Background Originally, I installed win 7 with the bios set to IDE and forgot to install the chipset drivers. Then I changed win 7 to install the AHCI drivers, changed the bios to AHCI and rebooted. Win 7 loaded drivers but WD HDD gave problems/crashed. I installed chipset drivers and latest intell storage matrix software thingie (in safe mode). Everything worked fine after that except for the problem of not corrrectly detecting the external drive] I have noticed that under the driver properties (and similarly in the registry) the two drives are configured differently (e.g. in driver details property capabilities for the WD the value is set to 0000006, CM_DEVCAP_REMOVABLE & EJECTSUPPORTED - whereas the seagate shows 0000080 & CM_DEVCAP_SURPRISEREMOVALOK). Any easy way to configure things? I tried physically swapping the sata connections on the mainboard without success So far I have found that a solution to my problem might be to perform some reg changes: http://superuser.com/questions/12955/how-do-i-remove-the-option-to-eject-sata-drives-from-the-windows-7-tray-icon

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  • External HDD incorrectly detected as internal - how change to enable hot swap/eject?

    - by Sam
    I have win 7 x64 Home Prem. The HDD is a seagate barracuda, 7200.7 ST3120827AS. 3.5", Serial: 3ms006n6, Firmware: 3.42 (no further updates) NexStar CX External case (drivers installed). I have three drives: WD320 with OS installed WD750 data storage (internal) seagate 120 (external) - connected via esata board connected to sata on motherboard (MSI p43 neo) Tried uninstalling HDD in device manager to no effect. Also the internal WD750 is detected as an external drive and win taskbar icon allows for it to be ejected (unlike the seagate). All drives are configured - Online, Simple, Basic, NTFS, Active, Primary Partition (except c drive). The seagate was previously used as a primary disk with XP operating system so I deleted the volume and created/reformatted (not quick). HDD is no longer "Active". But did not fix problem. Background Originally, I installed win 7 with the bios set to IDE and forgot to install the chipset drivers. Then I changed win 7 to install the AHCI drivers, changed the bios to AHCI and rebooted. Win 7 loaded drivers but WD HDD gave problems/crashed. I installed chipset drivers and latest intell storage matrix software thingie (in safe mode). Everything worked fine after that except for the problem of not corrrectly detecting the external drive] I have noticed that under the driver properties (and similarly in the registry) the two drives are configured differently (e.g. in driver details property capabilities for the WD the value is set to 0000006, CM_DEVCAP_REMOVABLE & EJECTSUPPORTED - whereas the seagate shows 0000080 & CM_DEVCAP_SURPRISEREMOVALOK). Any easy way to configure things? I tried physically swapping the sata connections on the mainboard without success So far I have found that a solution to my problem might be to perform some reg changes: How do I remove the option to eject SATA drives from the Windows 7 tray icon?

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  • Would it be possible to swap system restore points on different brands of computers?

    - by P'sao
    So I have a ThinkPad computer that I've installed a program called "Deep Freeze" which restores your computer to the "Frozen" state. I also have a Toshiba computer with no Deep Freeze on it. My question is that would it be possible to creat a system restore point on my Toshiba and then replace the system volume information folder with the one on the ThinkPad so I could restore to a point with no Deep Freeze? Would this work?

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  • Can I swap a HDD from a RAID 1 for a bigger capacity drive?

    - by Gnuffo1
    I have a RAID 1 setup with two 500GB drives. So they mirror each other. I know that if I take one of them out and put in a new 500GB drive it will set it up so that the new drive will mirror the old one. My question is if I take out one of the 500GB drives and add say a 2TB drive, will it set up the 2TB drive to mirror the 500GB? I assume if it does, it will only allow me access to 500GB. However, if I then take out the one remaining 500GB after the data has been mirrored and stick in a 2TB, once that is rebuilt, will I then have a 2TB RAID setup with the same data as what was originally on the 2x 500GB setup?

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  • Is it safe to swap SATA ports during hibernation?

    - by netvope
    I hibernated my Windows 7 desktop PC, replaced the SATA cables of my 2 hard drives (without paying attention to which ports they were connected), and resumed the system. Everything appeared normal and it entered the desktop with all the applications previously open before hibernation. However, after a few seconds, the screen became frozen and the system no longer responded to anything (mouse/keyboard/network ping). Does anyone have a definitive answer on whether changing SATA ports of the HDDs during hibernation would crash a Windows 7 system?

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  • 2 identical PCs - can I swap a single hard drive between and expect Windows 7/XP to work?

    - by rgvcorley
    I currently work in 2 different locations, traveling between the 2 every few weeks or so. I currently have screens, kb, mouse etc... in both locations, so I just pick up my tower case when I want to move to the other location. However to make moving easier I was thinking of buying 2 tower cases with hot swappable drive bays on the front and installing identical hardware in each one. This would allow me to pull the drives out and just take them with me and plug them into the PC at the other location. Would windows 7 complain? I'm not fussed about buying licenses for both PCs, but would I have any problems with drivers due to the different serial numbers of the components?

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  • 2 identical PCs - can I swap a single hard drive between and expect Windows 7 to work? [closed]

    - by rgvcorley
    I currently work in 2 different locations, traveling between the 2 every few weeks or so. I currently have screens, kb, mouse etc... in both locations, so I just pick up my tower case when I want to move to the other location. However to make moving easier I was thinking of buying 2 tower cases with hot swappable drive bays on the front and installing identical hardware in each one. This would allow me to pull the drives out and just take them with me and plug them into the PC at the other location. Would windows 7 complain? I'm not fussed about buying licenses for both PCs, but would I have any problems with drivers due to the different serial numbers of the components?

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  • Is it possible to "trick" PrintScreen, swap out the contents of my form with something else before c

    - by Lasse V. Karlsen
    I have a bit of a challenge. In an earlier version of our product, we had an error message window (last resort, unhandled exception) that showed the exception message, type, stack trace + various bits and pieces of information. This window was printscreen-friendly, in that if the user simply did a printscreen-capture, and emailed us the screenshot, we had almost everything we needed to start diagnosing the problem. However, the form was deemed too technical and "scary" for normal users, so it was toned down to a more friendly one, still showing the error message, but not the stack trace and some of the more gory details that I'd still like to get. In addition, the form was added the capabilities of emailing us a text file containing everything we had before + lots of other technical details as well, basically everything we need. However, users still use PrintScreen to capture the contents of the form and email that back to us, which means I now have a less than optimal amount of information to go on. So I was wondering. Would it be possible for me to pre-render a bitmap the same size as my form, with everything I need on it, detect that PrintScreen was hit and quickly swap out the form contents with my bitmap before capture, and then back again afterwards? And before you say "just educate the users", yes, that's not going to work. These are not out users, they're users at our customers place, so we really cannot tell them to wisen up all that much. Or, barring this, is there a way for me to detect PrintScreen, tell Windows to ignore it, and instead react to it, by dumping the aformentioned prerendered bitmap onto the clipboard ready for placing into an email? The code is C# 3.0 in .NET 3.5, if it matters, but pointers for something to look at/for is good enough.

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  • Given a linked list of numbers. Swap every 2 adjacent links.

    - by Learner
    Given a linked list of numbers. Swap every 2 adjacent links. For eg if a linked list given to you is- a-b-c-d-e-f O/p expected- b-a-d-c-f-e Every 2 alternate links have to be swapped. I have written a solution here. Can you suggest me some other solution. Can you comment on my solution and help me better write it? void SwapAdjacentNodes (Node head) { if (head == null) return; if (head.next == null) return; Node curr = head; Node next = curr.Next; Node temp = next.Next; while (true) { temp = next.Next; next.Next = curr; curr.Next = temp; if (curr.Next != null) curr = curr.Next; else break; if (curr.Next.Next!=null) next = curr.Next.Next; else break; } }

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  • Programmatically swap colors from a loaded bitmap to Red, Green, Blue or Gray, pixel by pixel.

    - by eyeClaxton
    Download source code here: http://www.eyeClaxton.com/download/delphi/ColorSwap.zip I would like to take a original bitmap (light blue) and change the colors (Pixel by Pixel) to the red, green, blue and gray equivalence relation. To get an idea of what I mean, I have include the source code and a screen shot. Any help would be greatly appreciated. If more information is needed, please feel free to ask. If you could take a look at the code below, I have three functions that I'm looking for help on. The functions "RGBToRed, RGBToGreen and RGBToRed" I can't seem to come up with the right formulas. unit MainUnit; interface uses Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms, Dialogs, ExtCtrls, StdCtrls; type TMainFrm = class(TForm) Panel1: TPanel; Label1: TLabel; Panel2: TPanel; Label2: TLabel; Button1: TButton; BeforeImage1: TImage; AfterImage1: TImage; RadioGroup1: TRadioGroup; procedure FormCreate(Sender: TObject); procedure Button1Click(Sender: TObject); private { Private declarations } public { Public declarations } end; var MainFrm: TMainFrm; implementation {$R *.DFM} function RGBToGray(RGBColor: TColor): TColor; var Gray: Byte; begin Gray := Round( (0.90 * GetRValue(RGBColor)) + (0.88 * GetGValue(RGBColor)) + (0.33 * GetBValue(RGBColor))); Result := RGB(Gray, Gray, Gray); end; function RGBToRed(RGBColor: TColor): TColor; var Red: Byte; begin // Not sure of the algorithm for this color Result := RGB(Red, Red, Red); end; function RGBToGreen(RGBColor: TColor): TColor; var Green: Byte; begin // Not sure of the algorithm for this color Result := RGB(Green, Green, Green); end; function RGBToBlue(RGBColor: TColor): TColor; var Blue: Byte; begin // Not sure of the algorithm for this color Result := RGB(Blue, Blue, Blue); end; procedure TMainFrm.FormCreate(Sender: TObject); begin BeforeImage1.Picture.LoadFromFile('Images\RightCenter.bmp'); end; procedure TMainFrm.Button1Click(Sender: TObject); var Bitmap: TBitmap; I, X: Integer; Color: Integer; begin Bitmap := TBitmap.Create; try Bitmap.LoadFromFile('Images\RightCenter.bmp'); for X := 0 to Bitmap.Height do begin for I := 0 to Bitmap.Width do begin Color := ColorToRGB(Bitmap.Canvas.Pixels[I, X]); case Color of $00000000: ; // Skip any Color Here! else case RadioGroup1.ItemIndex of 0: Bitmap.Canvas.Pixels[I, X] := RGBToBlue(Color); 1: Bitmap.Canvas.Pixels[I, X] := RGBToRed(Color); 2: Bitmap.Canvas.Pixels[I, X] := RGBToGreen(Color); 3: Bitmap.Canvas.Pixels[I, X] := RGBToGray(Color); end; end; end; end; AfterImage1.Picture.Graphic := Bitmap; finally Bitmap.Free; end; end; end. Okay, I apologize for not making it clearer. I'm trying to take a bitmap (blue in color) and swap the blue pixels with another color. Like the shots below.

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