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  • What production software have you written in F# in the past year or so that you would previously hav

    - by Peter McGrattan
    Over the last few years F# has evolved into one of Microsoft's fully supported languages employing many ideas incubated in OCaml, ML and Haskell. Over the last several years C# has extended it's general purpose features by introducing more and more functional language features: LINQ (list comprehension), Lamdas, Closures, Anonymous Delegates and more... Given C#'s adoption of these functional features and F#'s taxonomy as an impure functional language (it allows YOU to access framework libraries or change shared state when a function is called if you want to) there is a strong similarity between the two languages although each has it's own polar opposite primary emphasis. I'm interested in any successful models employing these two languages in your production polyglot programs and also the areas within production software (web apps, client apps, server apps) you have written in F# in the past year or so that you would previously have written in C#.

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  • where to store information like gender and year of birth?

    - by fayer
    i have users and i need them to specify a gender (male, female) and year of birth (1930, 1931...1999, 2000). i wonder where i should store these values: in the database? in php file? if i store them in the database i have to manually create all entries first. but a good thing is that the user table will have constraints so the gender field will always be male or female, it cannot be something else. if i store them in the php file (eg. as html) then i can easily add/remove values. but a con is that i dont have the constraints in database, so another value could be stored as gender by mistake, even though i could add validation in php backend so even if someone hacked the html it is not stored unless it's either male or female. what is best practice to do this? thanks

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  • The script not working as expected files dump path

    - by user3319390
    I have a script needs to be dump matching cname from my file contains and then matching scode to dump file to $cname/$year/$month/$day/ into files like access and error logs #!/bin/sh #base_dir="/home/vizion/Desktop" path="/home/vizion/Desktop/adn_DF9D_20140515_0005.log" name=$(basename "$path" ".log") for x in *.log; do year=${x:9:4}; month=${x:13:2}; day=${x:15:2}; done while read -r line do cname=$(echo ${line} | awk '{split($7,c,"/"); print c[3]}') scode=$(echo ${line} | awk -F"[ ]" '{print $9}') [[ ! -d "$cname/$year/$month/$day" ]] && mkdir -p "$cname/$year/$month/$day/" [[ ( ${scode} -ge 200 ) && ( ${scode} -le 399 ) ]] && { # [[ ! -d "$cname/$year/$month/$day" ]] && mkdir -p "$cname/$year/$month/$day/" echo ${line} >> /home/vizion/Desktop/$cname/$year/$month/$day/${cname}_${name}_access.log } [[ ( ${scode} -ge 400 ) && ( ${scode} -le 599 ) ]] && { [[ ! -d "$cname/$year/$month/$day" ]] && mkdir -p "$cname/$year/$month/$day" echo ${line} >> ${cname}_${name}_error.log } done < $path i am able to filter logs but not not dumping the exact location It's going other locations suggest to me correction in script

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  • Die glücklichen Gewinner der Oracle Partner Awards Germany 2012

    - by A&C Redaktion
    Es war ein Höhepunkt des Oracle Partner Days: Die Award Ceremony, auf der deutsche Oracle Partner für ihr besonderes Engagement und herausragende Erfolge bei der Spezialisierung ausgezeichnet wurden. Jeder Preisträger erhielt neben dem Award eine Urkunde sowie einen Wertscheck in Höhe von 2.000 Euro für eine Demand Generation Kampagne. Wir gratulieren allen Gewinnern ganz herzlich und stellen sie Ihnen im Folgenden kurz vor:Database Partner of the Year Germany: inforsacom Informationssysteme GmbHDass der EMEA Database Partner of the Year inforsacom auch im bundesweiten Vergleich überzeugen würde, war keine große Überraschung, ist aber ein Riesenerfolg! Übrigens war inforsacom auch schon 2011 unter den Preisträgern des OPN Day Satellite (wir berichteten). Der Platinum Partner inforsacom Informationssysteme GmbH entwickelt und liefert seit 1997 integrierte IT-Lösungen im Data-Center. Als „trusted advisor“ ist es ein Schwerpunkt von Inforsacom, in der Beratung den größtmöglichen Kundennutzen aufzuzeigen. inforsacom setzt einen deutlichen Fokus auf Oracle Datenbanktechnologien sowie das Hardware und Engineered Systems Portfolio -  inklusive der damit verbundenen Spezialisierung und Ausbildung der Mitarbeiter. Middleware Partner of the Year Germany: People at Work Systems AGZum Middleware Partner of the Year wurde die People at Work Systems AG gekürt, ein Software- und Beratungsunternehmen aus München, das  Kunden individuelle Dienstleistungen und Lösungen für Customer Relationship Management (CRM) und  Business Process Management (BPM) auf der Basis von Oracle anbietet. Seit Jahren zeigt der Oracle Partner ein hohes Commitment zu Oracle, unter anderem durch sein umfassendes Engagement im Rahmen der Solution Partner Community SOA. Die große technologische und vertriebliche Kompetenz in Sachen BPM, SOA & Integration hat die People at Work GmbH in verschiedenen komplexen Fusion Middleware-Projekten erfolgreich unter Beweis gestellt. Applications Partner of the Year Germany: ifb AGDie ifb-group deckt als einer der wenigen Partner das komplette Hyperion, Oracle EPM und BI Portfolio ab. Dabei ist das Markenzeichen der ifb die enge Verbindung von Fachexpertise und Umsetzungsstärke, denn weltweit setzen über 800 Unternehmen seit vielen Jahren erfolgreich auf Lösungen der ifb. Der Award „Applications Partner of the Year“ würdigt die Spezialisierung der ifb auf EPM. Industry Partner of the Year Germany: PORTRIX LOGISTIC SOFTWARE GmbHÜber den Preis als bester Industry Partner freute sich die PORTRIX LOGISTIC SOFTWARE GmbH aus Hamburg, eine Tochter der portrix.net GmbH. Mit einer eigenen Software-Lösung bietet der ISV Speditionen eine Lösung an, die die Abrechnung und Transparenz von Vertragskonditionen über die ganze Transportkette hinweg vereinfacht. Die Unternehmensgruppe portrix.net ist mit mehr als vier Spezialisierungen mit sehr gutem Oracle Know-how ausgestattet und somit in der Lage, zu unterschiedlichsten Anforderungen von Endkunden und Oracle Partnern exzellent zu beraten. Oracle Accelerate Partner of the Year Germany: ICP Solution GmbHICP Solution unterstützt als "One-Stop-Shop" auf dem europäischen Markt Kunden in allen Fragen rund um PLM und Agile von Oracle. Das Leistungsspektrum reicht dabei von der Prozessoptimierung und PLM Einführung, über ERP Integration bis hin zum Wartungsvertrag und speziellen Schulungen.Server & Storage Systems Partner of the Year Germany: CCF AGDie CCF AG ist schon seit 19 Jahren ein überzeugter Sun/Oracle Partner, der ca. 90% seines Umsatzes mit Sun/Oracle Produkten macht. Als flexibles regionales Unternehmen mit angeschlossener Consulting Firma, die auf Solaris und Unix spezialisiert ist, ist die CCF einer der wenigen Oracle Partner mit eigenen Solaris Administratoren. Der Award würdigt auch die herausragenden Umsatzergebnisse von CCF im Hardware Segment.Oracle on Oracle Partner of the Year Germany: anykey GmbHAuch ankey ist bereits ein langjähriger Partner von Sun/Oracle und verfügt über hohes Consulting-Know-how. 2012 ist anykey richtig durchgestartet: Viele Zertifizierungen sowie Datenbankspezialisierung wurden erworben und der Platinum Partner hat sich damit den Bereich „Oracle on Oracle“ erschlossen. Durch die erfolgreiche Platzierung bei Kunden konnte anykey im letzten Fiskaljahr sogar den Umsatz verdoppeln.

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  • Die glücklichen Gewinner der Oracle Partner Awards Germany 2012

    - by A&C Redaktion
    Es war ein Höhepunkt des Oracle Partner Days: Die Award Ceremony, auf der deutsche Oracle Partner für ihr besonderes Engagement und herausragende Erfolge bei der Spezialisierung ausgezeichnet wurden. Jeder Preisträger erhielt neben dem Award eine Urkunde sowie einen Wertscheck in Höhe von 2.000 Euro für eine Demand Generation Kampagne. Wir gratulieren allen Gewinnern ganz herzlich und stellen sie Ihnen im Folgenden kurz vor:Database Partner of the Year Germany: inforsacom Informationssysteme GmbHDass der EMEA Database Partner of the Year inforsacom auch im bundesweiten Vergleich überzeugen würde, war keine große Überraschung, ist aber ein Riesenerfolg! Übrigens war inforsacom auch schon 2011 unter den Preisträgern des OPN Day Satellite (wir berichteten). Der Platinum Partner inforsacom Informationssysteme GmbH entwickelt und liefert seit 1997 integrierte IT-Lösungen im Data-Center. Als „trusted advisor“ ist es ein Schwerpunkt von Inforsacom, in der Beratung den größtmöglichen Kundennutzen aufzuzeigen. inforsacom setzt einen deutlichen Fokus auf Oracle Datenbanktechnologien sowie das Hardware und Engineered Systems Portfolio -  inklusive der damit verbundenen Spezialisierung und Ausbildung der Mitarbeiter. Middleware Partner of the Year Germany: People at Work Systems AGZum Middleware Partner of the Year wurde die People at Work Systems AG gekürt, ein Software- und Beratungsunternehmen aus München, das  Kunden individuelle Dienstleistungen und Lösungen für Customer Relationship Management (CRM) und  Business Process Management (BPM) auf der Basis von Oracle anbietet. Seit Jahren zeigt der Oracle Partner ein hohes Commitment zu Oracle, unter anderem durch sein umfassendes Engagement im Rahmen der Solution Partner Community SOA. Die große technologische und vertriebliche Kompetenz in Sachen BPM, SOA & Integration hat die People at Work GmbH in verschiedenen komplexen Fusion Middleware-Projekten erfolgreich unter Beweis gestellt. Applications Partner of the Year Germany: ifb AGDie ifb-group deckt als einer der wenigen Partner das komplette Hyperion, Oracle EPM und BI Portfolio ab. Dabei ist das Markenzeichen der ifb die enge Verbindung von Fachexpertise und Umsetzungsstärke, denn weltweit setzen über 800 Unternehmen seit vielen Jahren erfolgreich auf Lösungen der ifb. Der Award „Applications Partner of the Year“ würdigt die Spezialisierung der ifb auf EPM. Industry Partner of the Year Germany: PORTRIX LOGISTIC SOFTWARE GmbHÜber den Preis als bester Industry Partner freute sich die PORTRIX LOGISTIC SOFTWARE GmbH aus Hamburg, eine Tochter der portrix.net GmbH. Mit einer eigenen Software-Lösung bietet der ISV Speditionen eine Lösung an, die die Abrechnung und Transparenz von Vertragskonditionen über die ganze Transportkette hinweg vereinfacht. Die Unternehmensgruppe portrix.net ist mit mehr als vier Spezialisierungen mit sehr gutem Oracle Know-how ausgestattet und somit in der Lage, zu unterschiedlichsten Anforderungen von Endkunden und Oracle Partnern exzellent zu beraten. Oracle Accelerate Partner of the Year Germany: ICP Solution GmbHICP Solution unterstützt als "One-Stop-Shop" auf dem europäischen Markt Kunden in allen Fragen rund um PLM und Agile von Oracle. Das Leistungsspektrum reicht dabei von der Prozessoptimierung und PLM Einführung, über ERP Integration bis hin zum Wartungsvertrag und speziellen Schulungen.Server & Storage Systems Partner of the Year Germany: CCF AGDie CCF AG ist schon seit 19 Jahren ein überzeugter Sun/Oracle Partner, der ca. 90% seines Umsatzes mit Sun/Oracle Produkten macht. Als flexibles regionales Unternehmen mit angeschlossener Consulting Firma, die auf Solaris und Unix spezialisiert ist, ist die CCF einer der wenigen Oracle Partner mit eigenen Solaris Administratoren. Der Award würdigt auch die herausragenden Umsatzergebnisse von CCF im Hardware Segment.Oracle on Oracle Partner of the Year Germany: anykey GmbHAuch ankey ist bereits ein langjähriger Partner von Sun/Oracle und verfügt über hohes Consulting-Know-how. 2012 ist anykey richtig durchgestartet: Viele Zertifizierungen sowie Datenbankspezialisierung wurden erworben und der Platinum Partner hat sich damit den Bereich „Oracle on Oracle“ erschlossen. Durch die erfolgreiche Platzierung bei Kunden konnte anykey im letzten Fiskaljahr sogar den Umsatz verdoppeln.

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  • PASS Summit 2013 Review

    - by Ajarn Mark Caldwell
    As a long-standing member of PASS who lives in the greater Seattle area and has attended about nine of these Summits, let me start out by saying how GREAT it was to go to Charlotte, North Carolina this year.  Many of the new folks that I met at the Summit this year, upon hearing that I was from Seattle, commented that I must have been disappointed to have to travel to the Summit this year after 5 years in a row in Seattle.  Well, nothing could be further from the truth.  I cheered loudly when I first heard that the 2013 Summit would be outside Seattle.  I have many fond memories of trips to Orlando, Florida and Grapevine, Texas for past Summits (missed out on Denver, unfortunately).  And there is a funny dynamic that takes place when the conference is local.  If you do as I have done the last several years and saved my company money by not getting a hotel, but rather just commuting from home, then both family and coworkers tend to act like you’re just on a normal schedule.  For example, I have a young family, and my wife and kids really wanted to still see me come home “after work”, but there are a whole lot of after-hours activities, social events, and great food to be enjoyed at the Summit each year.  Even more so if you really capitalize on the opportunities to meet face-to-face with people you either met at previous summits or have spoken to or heard of, from Twitter, blogs, and forums.  Then there is also the lovely commuting in Seattle traffic from neighboring cities rather than the convenience of just walking across the street from your hotel.  So I’m just saying, there are really nice aspects of having the conference 2500 miles away. Beyond that, the training was fantastic as usual.  The SQL Server community has many outstanding presenters and experts with deep knowledge of the tools who are extremely willing to share all of that with anyone who wants to listen.  The opening video with PASS President Bill Graziano in a NASCAR race turned dream sequence was very well done, and the keynotes, as usual, were great.  This year I was particularly impressed with how well attended were the Professional Development sessions.  Not too many years ago, those were very sparsely attended, but this year, the two that I attended were standing-room only, and these were not tiny rooms.  I would say this is a testament to both the maturity of the attendees realizing how important these topics are to career success, as well as to the ever-increasing skills of the presenters and the program committee for selecting speakers and topics that resonated with people.  If, as is usually the case, you were not able to get to every session that you wanted to because there were just too darn many good ones, I encourage you to get the recordings. Overall, it was a great time as these events always are.  It was wonderful to see old friends and make new ones, and the people of Charlotte did an awesome job hosting the event and letting their hospitality shine (extra kudos to SQLSentry for all they did with the shuttle, maps, and other event sponsorships).  We’re back in Seattle next year (it is a release year, after all) but I would say that with the success of this year’s event, I strongly encourage the Board and PASS HQ to firmly reestablish the location rotation schedule.  I’ll even go so far as to suggest standardizing on an alternating Seattle – Charlotte schedule, or something like that. If you missed the Summit this year, start saving now, and register early, so you can join us!

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  • Query to find the data for every month of last year from the given date using mysql?

    - by Salil
    Hi All, I want data for the the last 1 year from the given date For ex:- I have date "2013-06-01" and i want data as follows also data i want is from three table using Group By or something else Month             Amount         Total_Data June 2013     100                5 May 2013       80                  4 -                     100                5 -                     100                5 July 2012       10                  2 I try following query but didn't workout SELECT DATE_FORMAT(rf.period, '%M %Y') as Month , sum(p.amount * ((100-q.amount)/100)) as Amount ,count(distinct q.label_id) as Total Data FROM table1 rf , table2 p , table3 q ,table4 a where rf.period BETWEEN '2013-06-01' AND '2013-06-01' and q.royalty_period BETWEEN '2013-06-01' AND '2013-06-01' and a.id = q.album_id and p.file_id = rf.id and p.upc = a.upc and p.local_revenue is not null GROUP BY Month Thanks in Advance, Salil Gaikwad

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  • SQL : where vs. on in join

    - by Erwin
    Perhaps a dumb question, but consider these 2 tables : T1 Store Year 01 2009 02 2009 03 2009 01 2010 02 2010 03 2010 T2 Store 02 Why is this INNER JOIN giving me the results I want (filtering the [year] in the ON clause) : select t1.* from t1 inner join t2 on t1.store = t2.store and t1.[year] = '2009' Store Year 02 2009 And why the LEFT OUTER JOIN include records of year 2010 ? select t1.* from t1 left outer join t2 on t1.store = t2.store and t1.year = '2009' where t2.store is null 01 2009 03 2009 01 2010 02 2010 03 2010 And I have to write the [year] filter in the 'WHERE' clause : select t1.* from t1 left outer join t2 on t1.store = t2.store where t2.store is null and t1.year = '2009' 01 2009 03 2009 Like I said, perhaps a dumb question, but it's bugging me !

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  • jQuery DatePicker - How to highlight certain days every month?

    - by Sergio
    Hi I have a jquery datepicker which is renders the current date by default as a full calendar. Before this is rendered I get a list of days from the server via ajax of days that need to be highlighted for the current month. The code for this is as follows: $.get("Note/GetActionDates/?orgID=" + orgID + "&month=" + month +"&year=" + year, null, function(result) { RenderCalendar(result); }, "json"); function RenderCalendar(dates) { $("#actionCal").datepicker({ dateFormat: 'dd/mm/yy', beforeShowDay: function(thedate) { var theday = thedate.getDate(); if ($.inArray(theday, dates) == -1) { return [true, "", ""]; } else { return [true, "specialDate", "Actions Today"]; } } }); } This is all good, but I would like the highlighted dates to update when the user clicks to a different month. I can modify the jquery datepicker initialise code with the following code: onChangeMonthYear: function(year, month, inst) { //get new array of dates for that month $.get("Note/GetActionDates/?orgID=" + orgID + "&month=" + month + "&year=" + year, null, function(result) { RenderCalendar(result); }, "json"); } But this doesn't seem to work. Could anyone show me what I'm doing wrong? Thanks! :) UPDATE - Working Code Thanks for the help! I have tweaked the code from petersendidit as follows and it now works. Gonna add a little more code to remove duplicate dates from the dates array but aside from that its all good. $("#actionCal").datepicker({ dateFormat: 'dd/mm/yyyy', beforeShowDay: function(thedate) { var theday = thedate.getDate() + "/" + (thedate.getMonth() + 1) + "/" + thedate.getFullYear(); if ($.inArray(theday, actionCalDates) == -1) { return [true, "", ""]; } else { return [true, "specialDate", "Actions Today"]; } }, onChangeMonthYear: function(year, month, inst) { dateCount = 0; getDates(orgID, month, year); } }); function getDates(orgID, month, year) { dateCount += 1; if (dateCount < 4) { $.ajax({ url: "Note/GetActionDates/", data: { 'orgID': orgID, 'month': month, 'year': year }, type: "GET", dataType: "json", success: function(result) { actionCalDates = actionCalDates.concat(result); getDates(orgID, month + 1, year); getDates(orgID, month - 1, year); } }); } }

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  • Date problem in MYSQL Query

    - by davykiash
    Am looking for a query to sum values in a particular time duration say an year or a particular month in an year using MYSQL syntax.Note that my transaction_date column stores daily amount transacted. Am example of a query that returns total sales in an year query would look something like this SELECT SUM(transaction_amount) WHERE transaction_date = (YEAR) Am example of a query that returns total sales in an particular month and year would look something like this SELECT SUM(transaction_amount) WHERE transaction_date = (YEAR)(MONTH) How achievable is this?

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  • Most efficient way to check if a date falls between two dates?

    - by Dave Jarvis
    Given: Start Month & Start Day End Month & End Day Any Year What SQL statement results in TRUE if a date lands between the Start and End days? 1st example: Start Date = 11-22 End Date = 01-17 Year = 2009 Specific Date = 2010-01-14 TRUE 2nd example: Start Date = 11-22 End Date = 11-16 Year = 2009 Specific Date = 2010-11-20 FALSE 3rd example: Start Date = 02-25 End Date = 03-19 Year = 2004 Specific Date = 2004-02-29 TRUE I was thinking of using the MySQL functions datediff and sign plus a CASE condition to determine whether the year wraps, but it seems rather expensive. Am looking for a simple, efficient calculation. Update The problem is the end date cannot simply use the year. The year must be increased if the end month/day combination happens before the start date. The start date is easy: Start Date = date( concat_ws( '-', year, Start Month, Start Day ) The end date is not so simple. Thank you!

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  • Range partition skip check

    - by user289429
    We have large amount of data partitioned on year value using range partition in oracle. We have used range partition but each partition contains data only for one year. When we write a query targeting a specific year, oracle fetches the information from that partition but still checks if the year is what we have specified. Since this year column is not part of the index it fetches the year from table and compares it. We have seen that any time the query goes to fetch table data it is getting too slow. Can we somehow avoid oracle comparing the year values since we for sure know that the partition contains information for only one year.

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  • linq multiple order DESCENDING

    - by ile
    .OrderBy(y => y.Year).ThenBy(m => m.Month); How to set descending order? EDIT: I tried this: var result = (from dn in db.DealNotes where dn.DealID == dealID group dn by new { month = dn.Date.Month, year = dn.Date.Year } into date orderby date.Key.year descending orderby date.Key.month descending select new DealNoteDateListView { DisplayDate = date.Key.month + "-" + date.Key.year, Month = date.Key.month, Year = date.Key.year, Count = date.Count() }) //.OrderBy(y => y.Year).ThenBy(m => m.Month) ; And it seems working. Is it wrong to use orderby twice like I used it here?

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  • Stupid newbie c++ two-dimensional array problem.

    - by paulson scott
    I've no idea if this is too newbie or generic for stackoverlflow. Apologies if that's the case, I don't intend to waste time. I've just started working through C++ Primer Plus and I've hit a little stump. This is probably super laughable but: for (int year = 0; year < YEARS; year++) { cout << "Year " << year + 1 << ":"; for (int month = 0; month < MONTHS; month++) { absoluteTotal = (yearlyTotal[year][year] += sales[year][month]); } cout << yearlyTotal[year][year] << endl; } cout << "The total number of books sold over a period of " << YEARS << " years is: " << absoluteTotal << endl; I wish to display the total of all 3 years. The rest of the code works fine: input is fine, individual yearly output is fine but I just can't get 3 years added together for one final total. I did have the total working at one point but I didn't have the individual totals working. I messed with it and reversed the situation. I've been messing with it for God knows how long. Any idea guys? Sorry if this isn't the place!

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  • bubble sort on array of c structures not sorting properly

    - by xmpirate
    I have the following program for books record and I want to sort the records on name of book. the code isn't showing any error but it's not sorting all the records. #include "stdio.h" #include "string.h" #define SIZE 5 struct books{ //define struct char name[100],author[100]; int year,copies; }; struct books book1[SIZE],book2[SIZE],*pointer; //define struct vars void sort(struct books *,int); //define sort func main() { int i; char c; for(i=0;i<SIZE;i++) //scanning values { gets(book1[i].name); gets(book1[i].author); scanf("%d%d",&book1[i].year,&book1[i].copies); while((c = getchar()) != '\n' && c != EOF); } pointer=book1; sort(pointer,SIZE); //sort call i=0; //printing values while(i<SIZE) { printf("##########################################################################\n"); printf("Book: %s\nAuthor: %s\nYear of Publication: %d\nNo of Copies: %d\n",book1[i].name,book1[i].author,book1[i].year,book1[i].copies); printf("##########################################################################\n"); i++; } } void sort(struct books *pointer,int n) { int i,j,sorted=0; struct books temp; for(i=0;(i<n-1)&&(sorted==0);i++) //bubble sort on the book name { sorted=1; for(j=0;j<n-i-1;j++) { if(strcmp((*pointer).name,(*(pointer+1)).name)>0) { //copy to temp val strcpy(temp.name,(*pointer).name); strcpy(temp.author,(*pointer).author); temp.year=(*pointer).year; temp.copies=(*pointer).copies; //copy next val strcpy((*pointer).name,(*(pointer+1)).name); strcpy((*pointer).author,(*(pointer+1)).author); (*pointer).year=(*(pointer+1)).year; (*pointer).copies=(*(pointer+1)).copies; //copy back temp val strcpy((*(pointer+1)).name,temp.name); strcpy((*(pointer+1)).author,temp.author); (*(pointer+1)).year=temp.year; (*(pointer+1)).copies=temp.copies; sorted=0; } *pointer++; } } } My Imput The C Programming Language X Y Z 1934 56 Inferno Dan Brown 1993 453 harry Potter and the soccers stone J K Rowling 2012 150 Ruby On Rails jim aurther nil 2004 130 Learn Python Easy Way gmaps4rails 1967 100 And the output ########################################################################## Book: Inferno Author: Dan Brown Year of Publication: 1993 No of Copies: 453 ########################################################################## ########################################################################## Book: The C Programming Language Author: X Y Z Year of Publication: 1934 No of Copies: 56 ########################################################################## ########################################################################## Book: Ruby On Rails Author: jim aurther nil Year of Publication: 2004 No of Copies: 130 ########################################################################## ########################################################################## Book: Learn Python Easy Way Author: gmaps4rails Year of Publication: 1967 No of Copies: 100 ########################################################################## ########################################################################## Book: Author: Year of Publication: 0 No of Copies: 0 ########################################################################## We can see the above sorting is wrong? What I'm I doing wrong?

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  • Announcing Fusion Middleware Innovation Awards

    - by Michelle Kimihira
    Author: Neela Chaudhari Every year at OpenWorld, Oracle announces the winners to its most prestigious awards in Middleware, the Fusion Middleware Innovation Awards. This year, we’ll be announcing the winners and highlighting a few of their original implementations during this key session in the Middleware stream: 11:45 AM on Tuesday, October 2nd, CON9162 Oracle Fusion Middleware: Meet This Year's Most Impressive Customer Projects in Moscone West, 3001. In addition, we’ll give a sneak peak of a few winners during GEN9394: Fusion Middleware General Session with Hasan Rizvi at 10:15 AM on Tuesday, October 2nd in Moscone West, Hall D! What kinds of customers win the Fusion Middleware Innovation Awards? Winners are selected based on the uniqueness of their business case, business benefits, level of impact relative to the size of the organization, complexity and magnitude of implementation, and the originality of architecture. The winners are selected by a panel of judges that score each entry across multiple different scoring categories. This year, the following categories included: Oracle Exalogic Cloud Application Foundation Service Integration (SOA) and BPM WebCenter Identity Management Data Integration Application Development Framework and Fusion Development Business Analytics (BI, EPM and Exalytics) Last year at OpenWorld 2011 we had standing room only in our session, so come early!  We had over 30 innovative customers that won the award, including companies like BT, Choice Hotels, Electronic Arts, Clorox Company, ING, Dunkin Brands, Telenor, Haier, AT&T, Manpower, Herbal Life and many others. Did you miss your chance this year to nominate your company? Come join with us in the awards session to get an edge in your next year’s submission and watch for the next opportunity for 2013 on this blog. There’s other awards as part of Oracle’s Excellence awards program or subscribe to our regular Fusion Middleware newsletter to get the latest reminders.

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  • Top Partners 2010 Specialization Awards

    - by Paulo Folgado
    Portugal Top Partners 2010 Specialization Awards Be Recognized Caro Parceiro, Vão ter lugar mais uma vez os prémios Top Partners, que anualmente visam reconhecer as realizações dos parceiros Oracle em termos de negócio. Este ano, sob o signo de Partner Specialization Awards, pretendemos, a par com os resultados de negócio, premiar igualmente o esforço dos nossos parceiros em termos de especialização e de desenvolvimento da sua auto-suficiência. Outras das inovações deste ano é o processo ser baseado numa entrega de candidaturas dos parceiros, e de estas serem avaliadas, com base em critérios definidos, por um júri incluindo entidades externas. Categorias dos Prémios: ·       Database Partner of the Year ·       Middleware Partner of the Year ·       Applications Partner of the Year ·       ISV Partner of the Year ·       Midsize Partner of the Year ·       Industry Partner of the Year ·       Accelerate Partner of the Year   Um dos objectivos dos Top Partners 2010 Specialization Awards é destacar e incentivar a cooperação entre a Oracle e os seus parceiros. Por esta razão, para além dos vários critérios específicos, os parceiros têm de cumprir um conjunto de critérios gerais: ·       Cooperação com a Oracle ·       Investimento no desenvolvimento dos conhecimentos em Oracle ·       Aproximação conjunta ao mercado ·       Utilização activa dos recursos e ferramentas do Oracle PartnerNetwork através do Portal OPN   Os Top Partners 2010 Specialization Awards estão abertos a todos os parceiros em Portugal que estejam registados no OPN Specialized em uma ou mais especializações. As candidaturas podem ser enviadas até 31 de Maio de 2010. Be recognized! Para mais informação clique aqui

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  • 25 Favorite JCP Award Memories

    - by heathervc
    As we celebrated the 10th Annual JCP Awards and Party at JavaOne last week, we asked attendees to share their favorite memories.  Add yours to the retrospective list below... The 10th Award party will be the best :-) I won a DSLR camera at the 2011 JCP party and have taken many awesome photos of my family with it ever since!  Thanks JCP! Remembering the password to get in! It was very fascinating talking to all those JUG Members of last years' (2011) party and hearing about their hopes & expectations.  Especially from members of SouJava and LJC. Hanging out with my friends Best food and one of my colleagues won the raffle prize. My friend Brian won a jacket 3 years ago and my friend Craig won a camera last year. 2010 when I took home 2 awards on behalf of JSRs I'm on. When Patrick & Scott sang 'Light My Fire'! Catch up with friends! Being able to attend my first JCP party and and joining JCP community. Of course it's when some people won the award (SouJava and LJC)!   Meeting Crazy Bob! This is my first. Mike  to be JCP Member of the Year in 2011. When SouJava and London Java Community won Member of the Year award! JBoss making CDI Everything! When SouJava won the JCP Member of the Year award. I love feeling like it is the Oscars! First Party! Winning JCP Member of the Year last year. The year I was running for it (JCP Award). 2009 music and hostess. Obscured on legal advice.

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  • The Start of a Blog

    - by dbradley
    So, here's my new blog up and running, who am I and what am I planning to write here?First off - here's a little about me:I'm a recent graduate from university (coming up to a year ago since I finished) studying Software Engineering on a four year course where the third year was an industrial placement. During the industrial placement I went to work for a company called Adfero in a "Technical Consultant" role as well as a junior "Information Systems Developer". Once I completed my placement I went back to complete my final year but also continued in my developer role 2/3 days a week with the company.Working part time while at uni always seems like a great idea until you get half way through the year. For me the problem was not so much having a lack of time, but rather a lack of interest in the course content having got a chance at working on real projects in a live environment. Most people who have been graduated a little while also find this - when looking back at uni work, it seem to be much more trivial from a problem solving point of view which I found to be true and I found key to uni work to actually be your ability to prove though how you talk about something that you comprehensively understand the basics.After completing uni I then returned full time to Adfero purely in the developer role which is where I've now been for almost a year and have now also taken on the title of "Information Systems Architect" where I'm working on some of the more high level design problems within the products.What I'm wanting to share on this blog is some of the interesting things I've learnt myself over the last year, the things they don't teach you in uni and pretty much anything else I find interesting! My personal favorite areas are text indexing, search and particularly good software engineering design - good design combined with good code makes the first step towards a well-written, maintainable piece of software.Hopefully I'll also be able to share a few of the products I've worked on, the mistake I've made and the software problems I've inherited from previous developers and had to heavily re-factor.

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  • Working with Reporting Services Filters–Part 1

    - by smisner
    There are two ways that you can filter data in Reporting Services. The first way, which usually provides a faster performance, is to use query parameters to apply a filter using the WHERE clause in a SQL statement. In that case, the structure of the filter depends upon the syntax recognized by the source database. Another way to filter data in Reporting Services is to apply a filter to a dataset, data region, or a group. Using this latter method, you can even apply multiple filters. However, the use of filter operators or the setup of multiple filters is not always obvious, so in this series of posts, I'll provide some more information about the configuration of filters. First, why not use query parameters exclusively for filtering? Here are a few reasons: You might want to apply a filter to part of the report, but not all of the report. Your dataset might retrieve data from a stored procedure, and doesn't allow you to pass a query parameter for filtering purposes. Your report might be set up as a snapshot on the report server and, in that case, cannot be dynamically filtered based on a query parameter. Next, let's look at how to set up a report filter in general. The process is the same whether you are applying the filter to a dataset, data region, or a group. When you go to the Filters page in the Properties dialog box for whichever of these items you selected (dataset, data region, group), you click the Add button to create a new filter. The interface looks like this: The Expression field is usually a field in the dataset, so to make it easier for you to make a selection,the drop-down list displays all of the current dataset fields. But notice the expression button to the right, which means that you can set up any type of expression-not just a dataset field. To the right of the expression button, you'll find a data type drop-down list. It's important to specify the correct data type for the field or expression you're using. Now for the operators. Here's a list of the options that you have: This Operator Performs This Action =, <>, >, >=, <, <=, Like Compares expression to value Top N, Bottom N Compares expression to Top (Bottom) set of N values (N = integer) Top %, Bottom % Compares expression to Top (Bottom) N percent of values (N = integer or float) Between Determines whether expression is between two values, inclusive In Determines whether expression is found in list of values Last, the Value is what you're comparing to the expression using the operator. The construction of a filter using some operators (=, <>, >, etc.) is fairly simple. If my dataset (for AdventureWorks data) has a Category field, and I have a parameter that prompts the user for a single category, I can set up a filter like this: Expression Data Type Operator Value [Category] Text = [@Category] But if I set the parameter to accept multiple values, I need to change the operator from = to In, just as I would have to do if I were using a query parameter. The parameter expression, [@Category], which translates to =Parameters!Category.Value, doesn’t need to change because it represents an array as soon as I change the parameter to allow multiple values. The “In” operator requires an array. With that in mind, let’s consider a variation on Value. Let’s say that I have a parameter that prompts the user for a particular year – and for simplicity’s sake, this parameter only allows a single value, and I have an expression that evaluates the previous year based on the user’s selection. Then I want to use these two values in two separate filters with an OR condition. That is, I want to filter either by the year selected OR by the year that was computed. If I create two filters, one for each year (as shown below), then the report will only display results if BOTH filter conditions are met – which would never be true. Expression Data Type Operator Value [CalendarYear] Integer = [@Year] [CalendarYear] Integer = =Parameters!Year.Value-1 To handle this scenario, we need to create a single filter that uses the “In” operator, and then set up the Value expression as an array. To create an array, we use the Split function after creating a string that concatenates the two values (highlighted in yellow) as shown below. Expression Data Type Operator Value =Cstr(Fields!CalendarYear.Value) Text In =Split( CStr(Parameters!Year.Value) + ”,” + CStr(Parameters!Year.Value-1) , “,”) Note that in this case, I had to apply a string conversion on the year integer so that I could concatenate the parameter selection with the calculated year. Pay attention to the second argument of the Split function—you must use a comma delimiter for the result to work correctly with the In operator. I also had to change the Expression value from [CalendarYear] (or =Fields!CalendarYear.Value) so that the expression would return a string that I could compare with the values in the string array. More fun with filter expressions in future posts!

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  • HTG Explains: Should You Buy Extended Warranties?

    - by Chris Hoffman
    Buy something at an electronics store and you’ll be confronted by a pushy salesperson who insists you need an extended warranty. You’ll also see extended warranties pushed hard when shopping online. But are they worth it? There’s a reason stores push extended warranties so hard. They’re almost always pure profit for the store involved. An electronics store may live on razor-thin product margins and make big profits on extended warranties and overpriced HDMI cables. You’re Already Getting Multiple Warranties First, back up. The product you’re buying already includes a warranty. In fact, you’re probably getting several different types of warranties. Store Return and Exchange: Most electronics stores allow you to return a malfunctioning product within the first 15 or 30 days and they’ll provide you with a new one. The exact period of time will vary from store to store. If you walk out of the store with a defective product and have to swap it for a new one within the first few weeks, this should be easy. Manufacturer Warranty: A device’s manufacturer — whether the device is a laptop, a television, or a graphics card — offers their own warranty period. The manufacturer warranty covers you after the store refuses to take the product back and exchange it. The length of this warranty depends on the type of product. For example, a cheap laptop may only offer a one-year manufacturer warranty, while a more expensive laptop may offer a two-year warranty. Credit Card Warranty Extension: Many credit cards offer free extended warranties on products you buy with that credit card. Credit card companies will often give you an additional year of warranty. For example, if you buy a laptop with a two year warranty and it fails in the third year, you could then contact your credit card company and they’d cover the cost of fixing or replacing it. Check your credit card’s benefits and fine print for more information. Why Extended Warranties Are Bad You’re already getting a fairly long warranty period, especially if you have a credit card that offers you a free extended warranty — these are fairly common. If the product you get is a “lemon” and has a manufacturing error, it will likely fail pretty soon — well within your warranty period. The extended warranty matters after all your other warranties are exhausted. In the case of a laptop with a two-year warranty that you purchase with a credit card giving you a one-year warranty extension, your extended warranty will kick in three years after you purchase the laptop. In that many years, your current laptop will likely feel pretty old and laptops that are as good — or better — will likely be pretty cheap. If it’s a television, better television displays will be available at a lower price point. You’ll either want to upgrade to a newer model or you’ll be able to buy a new, just-as-good product for very cheap. You’ll only have to pay out-of-pocket if your device fails after the normal warranty period — in over two or three years for typical laptops purchased with a decent credit card. Save the money you would have spent on the warranty and put it towards a future upgrade. How Much Do Extended Warranties Cost? Let’s look at an example from a typical pushy retail outlet, Best Buy. We went to Best Buy’s website and found a pretty standard $600 Samsung laptop. This laptop comes with a one-year warranty period. If purchased with a fairly common credit card, you can easily get a two-year warranty period on this laptop without spending an additional penny. (Yes, such credit cards are available with no yearly fees.) During the check-out process, Best Buy tries to sell you a Geek Squad “Accidental Protection Plan.” To get an additional year of Best Buy’s extended warranty, you’d have to pay $324.98 for a “3-Year Accidental Protection Plan”. You’d basically be paying more than half the price of your laptop for an additional year of warranty — remember, the standard warranties would cover you anyway for the first two years. If this laptop did break sometime between two and three years from now, we wouldn’t be surprised if you could purchase a comparable laptop for about $325 anyway. And, if you don’t need to replace it, you’ve saved that money. Best Buy would object that this isn’t a standard extended warranty. It’s a supercharged warranty plan that will also provide coverage if you spill something on your laptop or drop it and break it. You just have to ask yourself a question. What are the odds that you’ll drop your laptop or spill something on it? They’re probably pretty low if you’re a typical human being. Is it worth spending more than half the price of the laptop just in case you’ll make an uncommon mistake? Probably not. There may be occasional exceptions to this — some Apple users swear by Apple’s AppleCare, for example — but you should generally avoid buying these things. There’s a reason stores are so pushy about extended warranties, and it’s not because they want to help protect you. It’s because they’re making lots of profit from these plans, and they’re making so much profit because they’re not a good deal for customers. Image Credit: Philip Taylor on Flickr     

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  • How to get the age from a birthdate using PHP & MySQL?

    - by TaG
    I ask my users for their birthdate and store it in my database in the following way $month $day $year output May 6 1901 but I was wondering how can I get the age from the stored birthdate using PHP & MySQL? Here is the PHP code. if (isset($_POST['submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $month_options = array("Month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"); $day_options = array("Day", "1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20", "21", "22", "23", "24", "25", "26", "27", "28", "29", "30", "31"); $month = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['month']))); $day = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['day']))); $year = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['year']))); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, month, day, year) VALUES ('$user_id', '$month', '$day', '$year')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET month = '$month', day = '$day', year = '$year' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } Here is the html. <form method="post" action="index.php"> <fieldset> <ul> <li><label>Date of Birth: </label> <label for="month" class="hide">Month: </label> <?php // month options echo '<select name="month" id="month">' . "\n"; foreach($month_options as $option) { if ($option == $month) { echo '<option value="' . stripslashes(htmlentities(strip_tags($option))) . '" selected="selected">' . stripslashes(htmlentities(strip_tags($option))) . '</option>' . "\n"; } else { echo '<option value="'. stripslashes(htmlentities(strip_tags($option))) . '">' . stripslashes(htmlentities(strip_tags($option))) . '</option>'."\n"; } } echo '</select>'; ?> <label for="day" class="hide">Day: </label> <?php // day options echo '<select id="day" name="day">' . "\n"; foreach($day_options as $option) { if ($option == $day) { echo '<option value="' . stripslashes(htmlentities(strip_tags($option))) . '" selected="selected">' . stripslashes(htmlentities(strip_tags($option))) . '</option>' . "\n"; } else { echo '<option value="'. stripslashes(htmlentities(strip_tags($option))) . '">' . stripslashes(htmlentities(strip_tags($option))) . '</option>'."\n"; } } echo '</select>'; ?> <label for="year" class="hide">Year: </label><input type="text" name="year" id="year" size="4" maxlength="4" value="<?php if (isset($_POST['year'])) { echo stripslashes(htmlentities(strip_tags($_POST['year']))); } else if(!empty($year)) { echo stripslashes(htmlentities(strip_tags($year))); } ?>" /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • using java Calendar

    - by owca
    I have a simple task. There are two classes : Ticket and Date. Ticket contains event, event place and event date which is a Date object. I also need to provide a move() method for Date object, so I used Calendar and Calendar's add(). Everything looks fine apart of the output. I constantly get 5,2,1 as the date's day,month,year. Lines with asterix return proper date. The code : Ticket class : public class Ticket { private String what; private String where; private Date when; public Ticket(String s1, String s2, Data d){ this.what = s1; this.where = s2; this.when = d; } *public Date giveDate(){ System.out.println("when in giveDate() "+this.when); return this.when; } public String toString(){ return "what: "+this.what+"\n"+"where: "+this.where+"\n"+"when: "+this.when; } } Date class: import java.util.Calendar; import java.util.GregorianCalendar; public class Date { public int day; public int month; public int year; public Date(int x, int y, int z){ *System.out.println("x: "+x); *System.out.println("y: "+y); *System.out.println("z: "+z); this.day = x; this.month = y; this.year = z; *System.out.println("this.day: "+this.day); *System.out.println("this.month: "+this.month); *System.out.println("this.year: "+this.year); } public Date move(int p){ *System.out.println("before_change: "+this.day+","+this.month+","+this.year); Calendar gc = new GregorianCalendar(this.year, this.month, this.day); System.out.println("before_adding: "+gc.DAY_OF_MONTH+","+gc.MONTH+","+gc.YEAR); gc.add(Calendar.DAY_OF_YEAR, p); System.out.println("after_adding: "+gc.DAY_OF_MONTH+","+gc.MONTH+","+gc.YEAR); this.year = gc.YEAR; this.day = gc.DAY_OF_MONTH; this.month = gc.MONTH; return this; } @Override public String toString(){ return this.day+","+this.month+","+this.year; } } Main for testing : public class Main { public static void main(String[] args) { Date date1=new Date(30,4,2002); Ticket event1=new Ticket("Peter Gabriel's gig", "London",date1 ); Ticket event2=new Ticket("Diana Kroll's concert", "Glasgow",date1 ); Date date2=event2.giveDate(); date2.move(30); Ticket event3=new Ticket("X's B-day", "some place",date2 ); System.out.println(date1); System.out.println(event1); System.out.println(event2); System.out.println(event3); } } And here's my output. I just can't get it where 5,2,1 come from :/ x: 30 y: 4 z: 2002 this.day: 30 this.month: 4 this.year: 2002 when in giveDate() 6,12,2004 before_change: 6,12,2004 before_adding: 5,2,1 after_adding: 5,2,1 5,2,1 what: Peter Gabriel's gig where: London when: 5,2,1 (...)

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  • TOTD #166: Using NoSQL database in your Java EE 6 Applications on GlassFish - MongoDB for now!

    - by arungupta
    The Java EE 6 platform includes Java Persistence API to work with RDBMS. The JPA specification defines a comprehensive API that includes, but not restricted to, how a database table can be mapped to a POJO and vice versa, provides mechanisms how a PersistenceContext can be injected in a @Stateless bean and then be used for performing different operations on the database table and write typesafe queries. There are several well known advantages of RDBMS but the NoSQL movement has gained traction over past couple of years. The NoSQL databases are not intended to be a replacement for the mainstream RDBMS. As Philosophy of NoSQL explains, NoSQL database was designed for casual use where all the features typically provided by an RDBMS are not required. The name "NoSQL" is more of a category of databases that is more known for what it is not rather than what it is. The basic principles of NoSQL database are: No need to have a pre-defined schema and that makes them a schema-less database. Addition of new properties to existing objects is easy and does not require ALTER TABLE. The unstructured data gives flexibility to change the format of data any time without downtime or reduced service levels. Also there are no joins happening on the server because there is no structure and thus no relation between them. Scalability and performance is more important than the entire set of functionality typically provided by an RDBMS. This set of databases provide eventual consistency and/or transactions restricted to single items but more focus on CRUD. Not be restricted to SQL to access the information stored in the backing database. Designed to scale-out (horizontal) instead of scale-up (vertical). This is important knowing that databases, and everything else as well, is moving into the cloud. RBDMS can scale-out using sharding but requires complex management and not for the faint of heart. Unlike RBDMS which require a separate caching tier, most of the NoSQL databases comes with integrated caching. Designed for less management and simpler data models lead to lower administration as well. There are primarily three types of NoSQL databases: Key-Value stores (e.g. Cassandra and Riak) Document databases (MongoDB or CouchDB) Graph databases (Neo4J) You may think NoSQL is panacea but as I mentioned above they are not meant to replace the mainstream databases and here is why: RDBMS have been around for many years, very stable, and functionally rich. This is something CIOs and CTOs can bet their money on without much worry. There is a reason 98% of Fortune 100 companies run Oracle :-) NoSQL is cutting edge, brings excitement to developers, but enterprises are cautious about them. Commercial databases like Oracle are well supported by the backing enterprises in terms of providing support resources on a global scale. There is a full ecosystem built around these commercial databases providing training, performance tuning, architecture guidance, and everything else. NoSQL is fairly new and typically backed by a single company not able to meet the scale of these big enterprises. NoSQL databases are good for CRUDing operations but business intelligence is extremely important for enterprises to stay competitive. RDBMS provide extensive tooling to generate this data but that was not the original intention of NoSQL databases and is lacking in that area. Generating any meaningful information other than CRUDing require extensive programming. Not suited for complex transactions such as banking systems or other highly transactional applications requiring 2-phase commit. SQL cannot be used with NoSQL databases and writing simple queries can be involving. Enough talking, lets take a look at some code. This blog has published multiple blogs on how to access a RDBMS using JPA in a Java EE 6 application. This Tip Of The Day (TOTD) will show you can use MongoDB (a document-oriented database) with a typical 3-tier Java EE 6 application. Lets get started! The complete source code of this project can be downloaded here. Download MongoDB for your platform from here (1.8.2 as of this writing) and start the server as: arun@ArunUbuntu:~/tools/mongodb-linux-x86_64-1.8.2/bin$./mongod./mongod --help for help and startup optionsSun Jun 26 20:41:11 [initandlisten] MongoDB starting : pid=11210port=27017 dbpath=/data/db/ 64-bit Sun Jun 26 20:41:11 [initandlisten] db version v1.8.2, pdfile version4.5Sun Jun 26 20:41:11 [initandlisten] git version:433bbaa14aaba6860da15bd4de8edf600f56501bSun Jun 26 20:41:11 [initandlisten] build sys info: Linuxbs-linux64.10gen.cc 2.6.21.7-2.ec2.v1.2.fc8xen #1 SMP Fri Nov 2017:48:28 EST 2009 x86_64 BOOST_LIB_VERSION=1_41Sun Jun 26 20:41:11 [initandlisten] waiting for connections on port 27017Sun Jun 26 20:41:11 [websvr] web admin interface listening on port 28017 The default directory for the database is /data/db and needs to be created as: sudo mkdir -p /data/db/sudo chown `id -u` /data/db You can specify a different directory using "--dbpath" option. Refer to Quickstart for your specific platform. Using NetBeans, create a Java EE 6 project and make sure to enable CDI and add JavaServer Faces framework. Download MongoDB Java Driver (2.6.3 of this writing) and add it to the project library by selecting "Properties", "LIbraries", "Add Library...", creating a new library by specifying the location of the JAR file, and adding the library to the created project. Edit the generated "index.xhtml" such that it looks like: <h1>Add a new movie</h1><h:form> Name: <h:inputText value="#{movie.name}" size="20"/><br/> Year: <h:inputText value="#{movie.year}" size="6"/><br/> Language: <h:inputText value="#{movie.language}" size="20"/><br/> <h:commandButton actionListener="#{movieSessionBean.createMovie}" action="show" title="Add" value="submit"/></h:form> This page has a simple HTML form with three text boxes and a submit button. The text boxes take name, year, and language of a movie and the submit button invokes the "createMovie" method of "movieSessionBean" and then render "show.xhtml". Create "show.xhtml" ("New" -> "Other..." -> "Other" -> "XHTML File") such that it looks like: <head> <title><h1>List of movies</h1></title> </head> <body> <h:form> <h:dataTable value="#{movieSessionBean.movies}" var="m" > <h:column><f:facet name="header">Name</f:facet>#{m.name}</h:column> <h:column><f:facet name="header">Year</f:facet>#{m.year}</h:column> <h:column><f:facet name="header">Language</f:facet>#{m.language}</h:column> </h:dataTable> </h:form> This page shows the name, year, and language of all movies stored in the database so far. The list of movies is returned by "movieSessionBean.movies" property. Now create the "Movie" class such that it looks like: import com.mongodb.BasicDBObject;import com.mongodb.BasicDBObject;import com.mongodb.DBObject;import javax.enterprise.inject.Model;import javax.validation.constraints.Size;/** * @author arun */@Modelpublic class Movie { @Size(min=1, max=20) private String name; @Size(min=1, max=20) private String language; private int year; // getters and setters for "name", "year", "language" public BasicDBObject toDBObject() { BasicDBObject doc = new BasicDBObject(); doc.put("name", name); doc.put("year", year); doc.put("language", language); return doc; } public static Movie fromDBObject(DBObject doc) { Movie m = new Movie(); m.name = (String)doc.get("name"); m.year = (int)doc.get("year"); m.language = (String)doc.get("language"); return m; } @Override public String toString() { return name + ", " + year + ", " + language; }} Other than the usual boilerplate code, the key methods here are "toDBObject" and "fromDBObject". These methods provide a conversion from "Movie" -> "DBObject" and vice versa. The "DBObject" is a MongoDB class that comes as part of the mongo-2.6.3.jar file and which we added to our project earlier.  The complete javadoc for 2.6.3 can be seen here. Notice, this class also uses Bean Validation constraints and will be honored by the JSF layer. Finally, create "MovieSessionBean" stateless EJB with all the business logic such that it looks like: package org.glassfish.samples;import com.mongodb.BasicDBObject;import com.mongodb.DB;import com.mongodb.DBCollection;import com.mongodb.DBCursor;import com.mongodb.DBObject;import com.mongodb.Mongo;import java.net.UnknownHostException;import java.util.ArrayList;import java.util.List;import javax.annotation.PostConstruct;import javax.ejb.Stateless;import javax.inject.Inject;import javax.inject.Named;/** * @author arun */@Stateless@Namedpublic class MovieSessionBean { @Inject Movie movie; DBCollection movieColl; @PostConstruct private void initDB() throws UnknownHostException { Mongo m = new Mongo(); DB db = m.getDB("movieDB"); movieColl = db.getCollection("movies"); if (movieColl == null) { movieColl = db.createCollection("movies", null); } } public void createMovie() { BasicDBObject doc = movie.toDBObject(); movieColl.insert(doc); } public List<Movie> getMovies() { List<Movie> movies = new ArrayList(); DBCursor cur = movieColl.find(); System.out.println("getMovies: Found " + cur.size() + " movie(s)"); for (DBObject dbo : cur.toArray()) { movies.add(Movie.fromDBObject(dbo)); } return movies; }} The database is initialized in @PostConstruct. Instead of a working with a database table, NoSQL databases work with a schema-less document. The "Movie" class is the document in our case and stored in the collection "movies". The collection allows us to perform query functions on all movies. The "getMovies" method invokes "find" method on the collection which is equivalent to the SQL query "select * from movies" and then returns a List<Movie>. Also notice that there is no "persistence.xml" in the project. Right-click and run the project to see the output as: Enter some values in the text box and click on enter to see the result as: If you reached here then you've successfully used MongoDB in your Java EE 6 application, congratulations! Some food for thought and further play ... SQL to MongoDB mapping shows mapping between traditional SQL -> Mongo query language. Tutorial shows fun things you can do with MongoDB. Try the interactive online shell  The cookbook provides common ways of using MongoDB In terms of this project, here are some tasks that can be tried: Encapsulate database management in a JPA persistence provider. Is it even worth it because the capabilities are going to be very different ? MongoDB uses "BSonObject" class for JSON representation, add @XmlRootElement on a POJO and how a compatible JSON representation can be generated. This will make the fromXXX and toXXX methods redundant.

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