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  • HTML Markup in einem APEX Tree - ganz einfach per Plugin!

    - by carstenczarski
    Die APEX Tree Region kennt sicherlich jeder APEX-Entwickler. Und vielfach besteht der Bedarf, das Aussehen des APEX Tree mit Hilfe von HTML Markup zu beeinflussen. Leider ist es seit APEX 4.0 nicht mehr möglich, eigenes HTML-Markup in einen APEX-Tree aufzunehmen - aus Sicherheitsgründen (Schutz vor Cross-Site-Scripting) werden alle HTML Sonderzeichen maskiert. Wenn kein XSS-Risiko besteht (die vom Tree dargestellten Inhalte basieren nicht auf Benutzereingaben und werden komplett vom Entwickler bestimmt), kann dies mit wenigen Zeilen JavaScript und jQuery-Code erreicht werden. Damit es noch einfacher wird,  haben wir die Funktionalität für Sie in einem APEX-Plugin gekapselt. Und so funktioniert es: APEX Plugin "HTML Markup for APEX Tree Region" herunterladenhttp://apex-plugin.com/oracle-apex-plugins/dynamic-action-plugin/html-markup-for-apex-tree_174.html APEX Plugin in die Anwendung importieren APEX Tree Region erzeugen und eigene Ersetzungen für HTML-Sonderzeichen verwenden, also bspw."[" für "<", "]" für ">" und "§" für "&". Eine neue dynamische Aktion erzeugen, die beim Laden der Seite ausgeführt wird und mit Hilfe des Plugins die Ersetzungen im Tree durch die "richtigen" HTML-Sonderzeichen ersetzt. Fertig. Wie das Plugin wirkt, können Sie sich auf einer Demo-Seite ansehen.

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  • Tool to compute SHA256 Tree Hash

    - by Benjamin
    I've started using AWS Glacier, and noticed that it hashes the files using an algorithm called SHA-256 Tree Hash. To my surprise, this algorithm is different from SHA-256, so I can't use the tools I'm used to, to compare hashes and verify file integrity. Do you know a Windows tool, if possible integrated in the context menu, to compute the SHA-256 Tree Hash of a file? I'd also accept a Linux command-line tool, as a second choice :-)

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  • Binary Search Tree in C

    - by heapzero
    Hi, I'm a Python guy. Learning C language and I've been trying to implement Binary Search Tree in C. I wrote down the code, and I've been trying from few hours but, not able to get the output as expected. Please help! Please correct me. #include<stdlib.h> #include<stdio.h> typedef int ElementType; typedef struct TreeNode { ElementType element; struct TreeNode *left, *right; } TreeNode; TreeNode *createTree(){ //Create the root of tree TreeNode *tempNode; tempNode = malloc(sizeof(TreeNode)); tempNode->element = 0; tempNode->left = NULL; tempNode->right = NULL; return tempNode; } TreeNode *createNode(ElementType X){ //Create a new leaf node and return the pointer TreeNode *tempNode; tempNode = malloc(sizeof(TreeNode)); tempNode->element = X; tempNode->left = NULL; tempNode->right = NULL; return tempNode; } TreeNode *insertElement(TreeNode *node, ElementType X){ //insert element to Tree if(node==NULL){ return createNode(X); } else{ if(X < node->element){ node->left = insertElement(node->left, X); } else if(X > node->element){ node->right = insertElement(node->right, X); } else if(X == node->element){ printf("Oops! the element is already present in the tree."); } } } TreeNode *displayTree(TreeNode *node){ //display the full tree if(node==NULL){ return; } displayTree(node->left); printf("| %d ", node->element); displayTree(node->right); } main(){ //pointer to root of tree #2 TreeNode *TreePtr; TreeNode *TreeRoot; TreeNode *TreeChild; //Create the root of tree TreePtr = createTree(); TreeRoot = TreePtr; TreeRoot->element = 32; printf("%d\n",TreeRoot->element); insertElement(TreeRoot, 8); TreeChild = TreeRoot->left; printf("%d\n",TreeChild->element); insertElement(TreeRoot, 2); insertElement(TreeRoot, 7); insertElement(TreeRoot, 42); insertElement(TreeRoot, 28); insertElement(TreeRoot, 1); insertElement(TreeRoot, 4); insertElement(TreeRoot, 5); // the output is not as expected :( displayTree(TreeRoot); }

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  • Algorithm to Render a Horizontal Binary-ish Tree in Text/ASCII form

    - by Justin L.
    It's a pretty normal binary tree, except for the fact that one of the nodes may be empty. I'd like to find a way to output it in a horizontal way (that is, the root node is on the left and expands to the right). I've had some experience expanding trees vertically (root node at the top, expanding downwards), but I'm not sure where to start, in this case. Preferably, it would follow these couple of rules: If a node has only one child, it can be skipped as redundant (an "end node", with no children, is always displayed) All nodes of the same depth must be aligned vertically; all nodes must be to the right of all less-deep nodes and to the left of all deeper nodes. Nodes have a string representation which includes their depth. Each "end node" has its own unique line; that is, the number of lines is the number of end nodes in the tree, and when an end node is on a line, there may be nothing else on that line after that end node. As a consequence of the last rule, the root node should be in either the top left or the bottom left corner; top left is preferred. For example, this is a valid tree, with six end nodes (node is represented by a name, and its depth): [a0]------------[b3]------[c5]------[d8] \ \ \----------[e9] \ \----[f5] \--[g1]--------[h4]------[i6] \ \--------------------[j10] \-[k3] Which represents the horizontal, explicit binary tree: 0 a / \ 1 g * / \ \ 2 * * * / \ \ 3 k * b / / \ 4 h * * / \ \ \ 5 * * f c / \ / \ 6 * i * * / / \ 7 * * * / / \ 8 * * d / / 9 * e / 10 j (branches folded for compactness; * representing redundant, one-child nodes; note that *'s are actual nodes, storing one child each, just with names omitted here for presentation sake) (also, to clarify, I'd like to generate the first, horizontal tree; not this vertical tree) I say language-agnostic because I'm just looking for an algorithm; I say ruby because I'm eventually going to have to implement it in ruby anyway. Assume that each Node data structure stores only its id, a left node, and a right node. A master Tree class keeps tracks of all nodes and has adequate algorithms to find: A node's nth ancestor A node's nth descendant The generation of a node The lowest common ancestor of two given nodes Anyone have any ideas of where I could start? Should I go for the recursive approach? Iterative?

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  • Regex to match a whole string only if it lacks a given substring/suffix

    - by Ivan Krechetov
    I've searched for questions like this, but all the cases I found were solved in a problem-specific manner, like using !g in vi to negate the regex matches, or matching other things, without a regex negation. Thus, I'm interested in a “pure” solution to this: Having a set of strings I need to filter them with a regular expression matcher so that it only leaves (matches) the strings lacking a given substring. For example, filtering out "Foo" in: Boo Foo Bar FooBar BooFooBar Baz Would result in: Boo Bar Baz I tried constructing it with negative look aheads/behinds (?!regex)/(?<!regex), but couldn't figure it out. Is that even possible?

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  • Efficient most common suffix algorithm?

    - by taw
    I have a few GBs worth of strings, and for every prefix I want to find 10 most common suffixes. Is there an efficient algorithm for that? An obvious solution would be: Store sorted list of <string, count> pairs. Identify by binary search extent for prefix we're searching. Find 10 highest counts in this extent. Possibly precompute it for all short prefixes, so it doesn't ever need to look at large portion of data. I'm not sure if that would actually be efficient at all. Is there a better way I overlooked? Answers must be real time, but it can take as much preprocessing as necessary.

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  • How can I convert this PHP script to Ruby? (build tree from tabbed string)

    - by Jon Sunrays
    I found this script below online, and I'm wondering how I can do the same thing with a Ruby on Rails setup. So, first off, I ran this command: rails g model Node node_id:integer title:string Given this set up, how can I make a tree from a tabbed string like the following? <?php // Make sure to have "Academia" be root node with nodeID of 1 $data = " Social sciences Anthropology Biological anthropology Forensic anthropology Gene-culture coevolution Human behavioral ecology Human evolution Medical anthropology Paleoanthropology Population genetics Primatology Anthropological linguistics Synchronic linguistics (or Descriptive linguistics) Diachronic linguistics (or Historical linguistics) Ethnolinguistics Sociolinguistics Cultural anthropology Anthropology of religion Economic anthropology Ethnography Ethnohistory Ethnology Ethnomusicology Folklore Mythology Political anthropology Psychological anthropology Archaeology ...(goes on for a long time) "; //echo "Checkpoint 2\n"; $lines = preg_split("/\n/", $data); $parentids = array(0 => null); $db = new PDO("host", 'username', 'pass'); $sql = 'INSERT INTO `TreeNode` SET ParentID = ?, Title = ?'; $stmt = $db->prepare($sql); foreach ($lines as $line) { if (!preg_match('/^([\s]*)(.*)$/', $line, $m)) { continue; } $spaces = strlen($m[1]); //$level = intval($spaces / 4); //assumes four spaces per indent $level = strlen($m[1]); // if data is tab indented $title = $m[2]; $parentid = ($level > 0 ? $parentids[$level - 1] : 1); //All "roots" are children of "Academia" which has an ID of "1"; $rv = $stmt->execute(array($parentid, $title)); $parentids[$level] = $db->lastInsertId(); echo "inserted $parentid - " . $parentid . " title: " . $title . "\n"; } ?>

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  • How do I force all Tree itemrenderers to refresh?

    - by Richard Haven
    I have item renderers in an mx.controls.Tree that I need to refresh on demand. I have code in the updateDisplayList that fires for only some of the visible nodes no matter what I do. I've tried triggering a change that they should all be listening for; I have tried clearing and resetting the dataProvider and the itemRenderer properties. private function forceCategoryTreeRefresh(event : Event = null) : void { trace("forceCategoryTreeRefresh"); var prevDataProvider : Object = CategoryTree.dataProvider; CategoryTree.dataProvider = null; CategoryTree.validateNow(); CategoryTree.dataProvider = prevDataProvider; var prevItemRenderer : IFactory = CategoryTree.itemRenderer; CategoryTree.itemRenderer = null; CategoryTree.itemRenderer = prevItemRenderer as IFactory; _categoriesChangeDispatcher.dispatchEvent(new Event(Event.CHANGE)); } The nodes refresh properly when I scroll them into view (e.g. the .data gets set), but I cannot force the ones that already exist to refresh or reset themselves. Any ideas?

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  • How to find sum of node's value for given depth in binary tree?

    - by masato-san
    I've been scratching my head for several hours for this... problem: Binary Tree (0) depth 0 / \ 10 20 depth 1 / \ / \ 30 40 50 60 depth 2 I am trying to write a function that takes depth as argument and return the sum of values of nodes of the given depth. For instance, if I pass 2, it should return 180 (i.e. 30+40+50+60) I decided to use breath first search and when I find the node with desired depth, sum up the value, but I just can't figure out how to find out the way which node is in what depth. But with this approach I feel like going to totally wrong direction. function level_order($root, $targetDepth) { $q = new Queue(); $q->enqueue($root); while(!$q->isEmpty) { //how to determin the depth of the node??? $node = $q->dequeue(); if($currentDepth == $targetDepth) { $sum = $node->value; } if($node->left != null) { $q->enqueue($node->left); } if($node->right != null) { $q->enqueue($node->right); } //need to reset this somehow $currentDepth ++; } }

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  • Approaches to create a nested tree structure of NSDictionaries?

    - by d11wtq
    I'm parsing some input which produces a tree structure containing NSDictionary instances on the branches and NSString instance at the nodes. After parsing, the whole structure should be immutable. I feel like I'm jumping through hoops to create the structure and then make sure it's immutable when it's returned from my method. We can probably all relate to the input I'm parsing, since it's a query string from a URL. In a string like this: a=foo&b=bar&a=zip We expect a structure like this: NSDictionary { "a" => NSDictionary { 0 => "foo", 1 => "zip" }, "b" => "bar" } I'm keeping it just two-dimensional in this example for brevity, though in the real-world we sometimes see var[key1][key2]=value&var[key1][key3]=value2 type structures. The code hasn't evolved that far just yet. Currently I do this: - (NSDictionary *)parseQuery:(NSString *)queryString { NSMutableDictionary *params = [NSMutableDictionary dictionary]; NSArray *pairs = [queryString componentsSeparatedByString:@"&"]; for (NSString *pair in pairs) { NSRange eqRange = [pair rangeOfString:@"="]; NSString *key; id value; // If the parameter is a key without a specified value if (eqRange.location == NSNotFound) { key = [pair stringByReplacingPercentEscapesUsingEncoding:NSASCIIStringEncoding]; value = @""; } else { // Else determine both key and value key = [[pair substringToIndex:eqRange.location] stringByReplacingPercentEscapesUsingEncoding:NSASCIIStringEncoding]; if ([pair length] > eqRange.location + 1) { value = [[pair substringFromIndex:eqRange.location + 1] stringByReplacingPercentEscapesUsingEncoding:NSASCIIStringEncoding]; } else { value = @""; } } // Parameter already exists, it must be a dictionary if (nil != [params objectForKey:key]) { id existingValue = [params objectForKey:key]; if (![existingValue isKindOfClass:[NSDictionary class]]) { value = [NSDictionary dictionaryWithObjectsAndKeys:existingValue, [NSNumber numberWithInt:0], value, [NSNumber numberWithInt:1], nil]; } else { // FIXME: There must be a more elegant way to build a nested dictionary where the end result is immutable? NSMutableDictionary *newValue = [NSMutableDictionary dictionaryWithDictionary:existingValue]; [newValue setObject:value forKey:[NSNumber numberWithInt:[newValue count]]]; value = [NSDictionary dictionaryWithDictionary:newValue]; } } [params setObject:value forKey:key]; } return [NSDictionary dictionaryWithDictionary:params]; } If you look at the bit where I've added FIXME it feels awfully clumsy, pulling out the existing dictionary, creating an immutable version of it, adding the new value, then creating an immutable dictionary from that to set back in place. Expensive and unnecessary? I'm not sure if there are any Cocoa-specific design patterns I can follow here?

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  • How to structure classes in the filesystem?

    - by da_b0uncer
    I have a few (view) classes. Table, Tree, PagingColumn, SelectionColumn, SparkLineColumn, TimeColumn. currently they're flat under app/view like this: app/view/Table app/view/Tree app/view/PagingColumn ... I thought about restructuring it, because the Trees and Tables use the columns, but there are some columns, which only work in a tree, some who work in trees and tables and in the future there are probably some who only work in tables, I don't know. My first idea was like this: app/view/Table app/view/Tree app/view/column/PagingColumn app/view/column/SelectionColumn app/view/column/SparkLineColumn app/view/column/TimeColumn But since the SelectionColumn is explicitly for trees, I have the fear that future developers could get the idea of missuse them. But how to restructure it probably? Like this: app/view/table/panel/Table app/view/tree/panel/Tree app/view/tree/column/PagingColumn app/view/tree/column/SelectionColumn app/view/column/SparkLineColumn app/view/column/TimeColumn Or like this: app/view/Table app/view/Tree app/view/column/SparkLineColumn app/view/column/TimeColumn app/view/column/tree/PagingColumn app/view/column/tree/SelectionColumn

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  • How to speed up calculation of length of longest common substring?

    - by eSKay
    I have two very large strings and I am trying to find out their Longest Common Substring. One way is using suffix trees (supposed to have a very good complexity, though a complex implementation), and the another is the dynamic programming method (both are mentioned on the Wikipedia page linked above). Using dynamic programming The problem is that the dynamic programming method has a huge running time (complexity is O(n*m), where n and m are lengths of the two strings). What I want to know (before jumping to implement suffix trees): Is it possible to speed up the algorithm if I only want to know the length of the common substring (and not the common substring itself)?

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  • XML transform element appearing in wrong place in document

    - by Mike
    I am having some problems with an XML transform and need some help. The stylesheet should iterate through all suffix elements and place the contents without the suffix tag next to the last text node within its first ancestor quote-block element (see desired ouput). It works when only a single suffix is present, but not when 2 are present, when 2 are present it places both suffixes next to each other in the last text node of the first quote-block. Any ideas? I have tried limiting the selections to ancestor::quote-block[1] in various places but that doesn't have the desired effect. Source XML <paragraph> <para> <quote-block> <list prefix-rules="specified"> <item prefix="“B42"> <para id="0a84d149-91b7-4012-ac6d-9f4eb8ed6c37">In June 2000, EME and EWS reached an agreement to negotiate towards a direct contract for coal haulage by rail (on a DIY basis), which would replace the previous indirect E2E arrangements that EME had in place with ECSL. An internal EWS e-mail noted: <quote-block> <quote-para>‘We did the deal with Edison Mission yesterday morning for LBT-Fiddlers @ £[…]/tonne as agreed. This rate until 16th September pending a contract.</quote-para> <quote-para><emphasis strength="strong">Enron are now off our hands so far as Edison are concerned. The Enron flows we have left are to British Energy’s station at Eggborough; from Immingham, Redcar and Hull</emphasis>. Also to Enron’s own power station at Wilton – 250,000 tonnes/year. I think we are stuck Enron [sic] on the Eggborough traffic until next April when British Energy will, hopefully take over their own coal procurement. <emphasis strength="strong">But we have got them out of Fiddlers Ferry and Ferrybridge – a big step forward</emphasis>.’</quote-para> <suffix>(Emphasis added.)</suffix> </quote-block> </para> </item> <item prefix="B43"> <para id="d64a5a72-0a02-476f-9a7b-7c07bbc93a8a">This e-mail is evidence of both EWS’s intent and, indeed, its success in stopping ECSL from carrying out indirect supplies to EME, one of the new generating companies.”</para> </item> </list> <suffix>(emphasis in original)</suffix> </quote-block> </para> </paragraph> Stylesheet <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://xml.sm.com/schema/cases/report" xmlns:sm="http://xml.sm.com/functions" xmlns:saxon="http://saxon.sf.net/" xpath-default-namespace="http://sm.com/schema/cases/report" exclude-result-prefixes="xs sm" version="2.0"> <xsl:output method="xml" indent="no"/> <xsl:template match="/"> <xsl:apply-templates/> </xsl:template> <xsl:template match="*"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> <!-- Match quote-blocks with open or close attributes. --> <xsl:template match="*[*:quote-block and descendant::*:suffix]"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- Match inline quote with open or close attributes --> <xsl:template match="*[*:quote and descendant::*:suffix]"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- Process the quote block --> <xsl:template name="process-quote-block"> <xsl:variable name="quoteBlockCopy"> <xsl:copy-of select="."/> </xsl:variable> <xsl:apply-templates select="$quoteBlockCopy" mode="append-suffix"> <xsl:with-param name="suffix" select="sm:get-suffix-note(.)"/> <xsl:with-param name="end-node" select="sm:get-last-text-node($quoteBlockCopy)"/> </xsl:apply-templates> </xsl:template> <!-- Match quote-blocks with open or close attributes. --> <xsl:template match="*[*:quote-block and descendant::*:suffix][ancestor::*:quote-block[1]]" mode="create-copy"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- Match inline quote with open or close attributes --> <xsl:template match="*[*:quote and descendant::*:suffix]" mode="create-copy"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- This will match all elements. Just copy and pass through the parameters. --> <xsl:template match="*" mode="append-suffix"> <xsl:param name="suffix"/> <xsl:param name="end-node"/> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates mode="append-suffix"> <xsl:with-param name="suffix" select="$suffix"/> <xsl:with-param name="end-node" select="$end-node"/> </xsl:apply-templates> </xsl:copy> </xsl:template> <!-- Apply the text node to the content. If the node is equal to the last node then append the descendants of suffix --> <xsl:template match="text()[normalize-space() != '']" mode="append-suffix"> <xsl:param name="suffix"/> <xsl:param name="end-node"/> <xsl:choose> <xsl:when test="count(. | $end-node) = 1"> <xsl:value-of select="."/> <xsl:apply-templates select="$suffix"/> </xsl:when> <xsl:otherwise> <!-- Or maybe neither. --> <xsl:value-of select="."/> </xsl:otherwise> </xsl:choose> </xsl:template> <!-- Dont copy suffix as --> <xsl:template match="*:suffix" mode="append-suffix"/> <xsl:function name="sm:get-suffix-note"> <xsl:param name="node"/> <xsl:sequence select="$node/descendant::*:suffix/node()"/> </xsl:function> <xsl:function name="sm:get-last-text-node"> <!-- Finds last non-empty text() node, ignoring <suffix> elements that are a child of this specific quote-block. --> <xsl:param name="node"/> <xsl:sequence select="reverse($node//text()[not(ancestor::*:suffix) and normalize-space() != ''])[1]"/> </xsl:function> </xsl:stylesheet> Current Output XML <paragraph> <para> <quote-block> <list prefix-rules="specified"> <item prefix="“B42"> <para id="0a84d149-91b7-4012-ac6d-9f4eb8ed6c37">In June 2000, EME and EWS reached an agreement to negotiate towards a direct contract for coal haulage by rail (on a DIY basis), which would replace the previous indirect E2E arrangements that EME had in place with ECSL. An internal EWS e-mail noted: <quote-block> <quote-para>‘We did the deal with Edison Mission yesterday morning for LBT-Fiddlers @ £[…]/tonne as agreed. This rate until 16th September pending a contract.</quote-para> <quote-para><emphasis strength="strong">Enron are now off our hands so far as Edison are concerned. The Enron flows we have left are to British Energy’s station at Eggborough; from Immingham, Redcar and Hull</emphasis>. Also to Enron’s own power station at Wilton – 250,000 tonnes/year. I think we are stuck Enron [sic] on the Eggborough traffic until next April when British Energy will, hopefully take over their own coal procurement. <emphasis strength="strong">But we have got them out of Fiddlers Ferry and Ferrybridge – a big step forward</emphasis>.’</quote-para> </quote-block> </para> </item> <item prefix="B43"> <para id="d64a5a72-0a02-476f-9a7b-7c07bbc93a8a">This e-mail is evidence of both EWS’s intent and, indeed, its success in stopping ECSL from carrying out indirect supplies to EME, one of the new generating companies.”(Emphasis added.)(emphasis in original)</para> </item> </list> </quote-block> </para> </paragraph> Desired Ouput <paragraph> <para> <quote-block> <list prefix-rules="specified"> <item prefix="“B42"> <para id="0a84d149-91b7-4012-ac6d-9f4eb8ed6c37">In June 2000, EME and EWS reached an agreement to negotiate towards a direct contract for coal haulage by rail (on a DIY basis), which would replace the previous indirect E2E arrangements that EME had in place with ECSL. An internal EWS e-mail noted: <quote-block> <quote-para>‘We did the deal with Edison Mission yesterday morning for LBT-Fiddlers @ £[…]/tonne as agreed. This rate until 16th September pending a contract.</quote-para> <quote-para><emphasis strength="strong">Enron are now off our hands so far as Edison are concerned. The Enron flows we have left are to British Energy’s station at Eggborough; from Immingham, Redcar and Hull</emphasis>. Also to Enron’s own power station at Wilton – 250,000 tonnes/year. I think we are stuck Enron [sic] on the Eggborough traffic until next April when British Energy will, hopefully take over their own coal procurement. <emphasis strength="strong">But we have got them out of Fiddlers Ferry and Ferrybridge – a big step forward</emphasis>.’(Emphasis added.)</quote-para> </quote-block> </para> </item> <item prefix="B43"> <para id="d64a5a72-0a02-476f-9a7b-7c07bbc93a8a">This e-mail is evidence of both EWS’s intent and, indeed, its success in stopping ECSL from carrying out indirect supplies to EME, one of the new generating companies.”(emphasis in original)</para> </item> </list> </quote-block> </para> </paragraph>

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  • Pseudo LRU tree algorithm.

    - by patros
    A lot of descriptions of Pseudo LRU algorithms involve using a binary search tree, and setting flags to "point away" from the node you're searching for every time you access the tree. This leads to a reasonable approximation of LRU. However, it seems from the descriptions that all of the nodes deemed LRU would be leaf nodes. Is there a pseudo-LRU algorithm that deals with a static tree that will still perform reasonably well, while determining that non-leaf nodes are suitable LRU candidates?

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  • gunit syntax for tree walker with a flat list of nodes

    - by Kaleb Pederson
    Here's a simple gunit test for a portion of my tree grammar which generates a flat list of nodes: objectOption walks objectOption: <<one:"value">> -> (one "value") Although you define a tree in ANTLR's rewrite syntax using a caret (i.e. ^(ROOT child...)), gunit matches trees without the caret, so the above represents a tree and it's not surprising that it fails: it's a flat list of nodes and not a tree. This results in a test failure: 1 failures found: test2 (objectOption walks objectOption, line17) - expected: (one \"value\") actual: one \"value\" Another option which seems intuitive is to leave off the parenthesis, like this: objectOption walks objectOption: <<one:"value">> -> one "value" But gunit doesn't like this syntax. It seems to result in a parse failure in the gunit grammar: line 17:20 no viable alternative at input 'one' line 17:24 missing ':' at 'value' line 0:-1 no viable alternative at input '<EOF>' java.lang.NullPointerException at org.antlr.gunit.OutputTest.getExpected(OutputTest.java:65) at org.antlr.gunit.gUnitExecutor.executeTests(gUnitExecutor.java:245) ... What is the correct way to match a flat tree?

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  • Parsing a given binary tree using python?

    - by kaushik
    Parse a binary tree,referring to given set of features,answering decision tree question at each node to decide left child or right child and find the path to leaf node according to answer given to the decision tree.. input wil be a set of feature which wil help in answering the question at each level to choose the left or right half and the output will be the leaf node.. i need help in implementing this can anyone suggest methods?? Please answer... thanks in advance..

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  • Psuedo LRU tree algorithm.

    - by patros
    A lot of descriptions of Pseudo LRU algorithms involve using a binary search tree, and setting flags to "point away" from the node you're searching for every time you access the tree. This leads to a reasonable approximation of LRU. However, it seems from the descriptions that all of the nodes deemed LRU would be leaf nodes. Is there a pseudo-LRU algorithm that deals with a static tree that will still perform reasonably well, while determining that non-leaf nodes are suitable LRU candidates?

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  • Output of gcc -fdump-tree-original

    - by Job
    If I dump the code generated by GCC for a virtual destructor (with -fdump-tree-original), I get something like this: ;; Function virtual Foo::~Foo() (null) ;; enabled by -tree-original { <<cleanup_point <<< Unknown tree: expr_stmt (void) (((struct Foo *) this)->_vptr.Foo = &_ZTV3Foo + 8) >>> >>; } <D.20148>:; if ((bool) (__in_chrg & 1)) { <<cleanup_point <<< Unknown tree: expr_stmt operator delete ((void *) this) >>> >>; } My question is: where is the code after "<D.20148>:;" located? It is outside of the destructor so when is this code executed?

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  • What is validating a binary search tree?

    - by dotnetdev
    I read on here of an exercise in interviews known as validating a binary search tree. How exactly does this work? What would one be looking for in validating a binary search tree? I have written a basic search tree, but never heard of this concept. Thanks

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  • Level-order in Haskell

    - by brain_damage
    I have a structure for a tree and I want to print the tree by levels. data Tree a = Nd a [Tree a] deriving Show type Nd = String tree = Nd "a" [Nd "b" [Nd "c" [], Nd "g" [Nd "h" [], Nd "i" [], Nd "j" [], Nd "k" []]], Nd "d" [Nd "f" []], Nd "e" [Nd "l" [Nd "n" [Nd "o" []]], Nd "m" []]] preorder (Nd x ts) = x : concatMap preorder ts postorder (Nd x ts) = (concatMap postorder ts) ++ [x] But how to do it by levels? "levels tree" should print ["a", "bde", "cgflm", "hijkn", "o"]. I think that "iterate" would be suitable function for the purpose, but I cannot come up with a solution how to use it. Would you help me, please?

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  • Design suggestion for expression tree evaluation with time-series data

    - by Lirik
    I have a (C#) genetic program that uses financial time-series data and it's currently working but I want to re-design the architecture to be more robust. My main goals are: sequentially present the time-series data to the expression trees. allow expression trees to access previous data rows when needed. to optimize performance of the data access while evaluating the expression trees. keep a common interface so various types of data can be used. Here are the possible approaches I've thought about: I can evaluate the expression tree by passing in a data row into the root node and let each child node use the same data row. I can evaluate the expression tree by passing in the data row index and letting each node get the data row from a shared DataSet (currently I'm passing the row index and going to multiple synchronized arrays to get the data). Hybrid: an immutable data set is accessible by all of the expression trees and each expression tree is evaluated by passing in a data row. The benefit of the first approach is that the data row is being passed into the expression tree and there is no further query done on the data set (which should increase performance in a multithreaded environment). The drawback is that the expression tree does not have access to the rest of the data (in case some of the functions need to do calculations using previous data rows). The benefit of the second approach is that the expression trees can access any data up to the latest data row, but unless I specify what that row is, I'll have to iterate through the rows and figure out which one is the last one. The benefit of the hybrid is that it should generally perform better and still provide access to the earlier data. It supports two basic "views" of data: the latest row and the previous rows. Do you guys know of any design patterns or do you have any tips that can help me build this type of system? Should I use a DataSet to hold and present the data, or are there more efficient ways to present rows of data while maintaining a simple interface? FYI: All of my code is written in C#.

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