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  • C program to display a jpeg or bmp or pcx file.

    - by Raj
    What is the code in 'c' to display a picture file like jpeg file or bmp file or pcx file. For example the picture may be available in desktop and the program during execution must be given the path of the file as input and should display the image.(If it is in command line,it'll be excellent). Platform:Windows xp Turbo c compiler(or turboc++)

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  • I get a "An attempt was made to load a program with an incorrect format" error on a SQL Server repli

    - by baldy
    The exact error is as follows "Could not load file or assembly 'Microsoft.SqlServer.Replication, Version=9.0.242.0, Culture=neutral, PublicKeyToken=89845dcd8080cc91' or one of its dependencies. An attempt was made to load a program with an incorrect format." I've recently started working on this project again after a two month move to another project. It worked perfectly before, and I've double checked all the references.

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  • How can I prevent segmentation faults in my program?

    - by worlds-apart89
    I have a C assignment. It is a lot longer than the code shown below, and we are given the function prototypes and instructions only. I have done my best at writing code, but I am stuck with segmentation faults. When I compile and run the program below on Linux, at "735 NaN" it will terminate, indicating a segfault occurred. Why? What am I doing wrong? Basically, the program does not let me access table-list_array[735]-value and table-list_array[735]-key. This is of course the first segfault. There might be more following index 735. #include <stdio.h> #include <stdlib.h> typedef struct list_node list_node_t; struct list_node { char *key; int value; list_node_t *next; }; typedef struct count_table count_table_t; struct count_table { int size; list_node_t **list_array; }; count_table_t* table_allocate(int size) { count_table_t *ptr = malloc(sizeof(count_table_t)); ptr->size = size; list_node_t *nodes[size]; int k; for(k=0; k<size; k++){ nodes[k] = NULL; } ptr->list_array = nodes; return ptr; } void table_addvalue(count_table_t *table) { int i; for(i=0; i<table->size; i++) { table->list_array[i] = malloc(sizeof(list_node_t)); table->list_array[i]->value = i; table->list_array[i]->key = "NaN"; table->list_array[i]->next = NULL; } } int main() { count_table_t *table = table_allocate(1000); table_addvalue(table); int i; for(i=0; i<table->size; i++) printf("%d %s\n", table->list_array[i]->value, table->list_array[i]->key); return 0; }

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  • Given a program's source code, what is a simple way to calculate the function points?

    - by user354822
    For class, I was told to give a function point count for Mozilla Thunderbird, however I am absolutely stumped as to how to approach this. Some methods I saw online suggested analyzing the interface of the program itself, however they used very simple methods. Thunderbird has a very complex interface and has so many FPs, I'm not sure if I could do it by hand. Some help would be very much appreciated. Thanks!

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  • Having another static method as the entry point of the java program?

    - by GK
    As we all know java program will start executing from the main method of the class. So was curious to know that is there any other way by which we can make another static method as the entry point, that is can we override this property of the JVM to start with some other method than main? many of you will ask why do you want to do this? so want to make it clear that its just a curiosity to know about. And if it is there then it might help in many ways

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  • easy, straightforward way to package a python program for debian?

    - by Jeremiah Rose
    i'm having trouble navigating the maze of distribution tools for python and debian; cdbs, debhelper, python-support, python-central, blah blah blah .. my application is a fairly straightforward one - a single python package (directory containing modules and a __init__.py), a script for running the program (script.py) and some icons and menu items (.desktop files). is there a simple straightforward way to make a .deb file out of these, or should i brave the nonsensical tools listed above?

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  • c++ i need help with this program. everytime i try to run it, i got a problem

    - by FOXMULDERIZE
    1-the program must read numeric data from a file. 2-only one line per number 3-half way between those numbers is a negative number. 4-the program must sum those who are above the negative number in a acumulator an those below the negative number in another acumulator. 5-the black screen shall print both results and determined who is grater or equal. include include using namespace std; void showvalues(int,int,int[]); void showvalues2(int,int); void sumtotal(int,int); int main() { int total1=0; int total2=0; const int SIZE_A= 9; int arreglo[SIZE_A]; int suma,total,a,b,c,d,e,f; ifstream archivo_de_entrada; archivo_de_entrada.open("numeros.txt"); //lee/// for(int count =0 ;count < SIZE_A;count++) archivo_de_entrada>>arreglo[count] ; archivo_de_entrada.close(); showvalues(0,3,arreglo); showvalues2(5,8); sumtotal(total1,total2); system("pause"); return 0; } void showvalues(int a,int b,int arreglos) { int total1=0; //muestra//////////////////////// cout<< "los num son "; for(int count = a ;count <= b;count++) total1 += arreglos[count]; cout < } void showvalues2(int c,int d) { ////////////////////////////// int total2=0; cout<< "los num 2 son "; for(count =5 ;count <=8;count++) total2 = total2 + arreglo[count]; cout < void sumtotal(int e,int f) { ///////////////////////////////// cout<<"la suma de t1 y t2 es "; total= total1 + total2; cout< }

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  • How to give focus to default program of shell-opened file, from Java ?

    - by Rabarberski
    From within Java, I am opening an Excel file with the default file handler (MS Excel, in this case :-) ) using the method described in this stackoverflow question: Desktop dt = Desktop.getDesktop(); dt.open(new File(filename)); However, the Excel program doesn't get the focus. Is there any easy way to do so? Edit: There is a related stackoverflow question for C#, but I didn't find any similar Java method.

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