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  • Can I update window.location.hash without having the web page scroll?

    - by Jonathon Watney
    Using JavaScript, is there a way to update window.location.hash without scrolling the web page? I have clickable title elements that toggle the visibility of a div directly beneath them. I want the /foo#bar in the history when clicking titles but don't want the page scrolling about. So when navigating away from /foo#bar I'll be able to use the back button and have the div whose ID is in window.location.hash be visible upon return. Is this behavior possible?

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  • python how to find the median of a list

    - by user3450574
    I'm trying to write a function named median that takes a list as an input and returns the median value of the list. I'm working with Python 2.7.2 The list can be of any size and the numbers are not guaranteed to be in any particular order. If the list contains an even number of elements, the function should return the average of the middle two. This is the code I'm starting with: def median(list): print(median([7,12,3,1,6,9]))

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  • How to use length indicator in a C++ program

    - by cj
    I want to make a program in C++ that reads a file where each field will have a number before it that indicates how long it is. The problem is I read every record in object of a class; how do I make the attributes of the class dynamic? For example if the field is "john" it will read it in a 4 char array. I don't want to make an array of 1000 elements as minimum memory usage is very important.

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  • PHP's form bracket trick is to Django's ___?

    - by Matt
    In PHP you can create form elements with names like: category[1] category[2] or even category[junk] category[test] When the form is posted, category is automatically turned into a nice dictionary like: category[1] => "the input value", category[2] => "the other input value" Is there a way to do that in Django? request.POST.getlist isn't quite right, because it simply returns a list, not a dictionary. I need the keys too.

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  • Arrow in nav menus in CSS/JS (e.g. playframework.org)

    - by manmal
    The navigation menu at the top of the www.playframework.org site features a small arrow pointing upward for the currently selected section (Home, Learn, Download,...). I tried to get behind the implementation they used, but I can't wrap my head around it - the resource does not show up in Chrome's Resources window, and an inspection of the elements did not show any signs of a background image, nor a JS interceptor (although I might have missed that). What in hellhound's name is going on there? :)

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  • XSLT for-each loop for element collection

    - by brain_pusher
    Is it possible to make a for-each loop in XSLT not for a node set, but for my own collection of elements? For example, I split some string and have a string collection as a result. And I need to create a node for each item in the collection. I know that issue can be solved with a recursive template, but I want to know if it is possible to avoid a recursion.

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  • HTML: how to set children element width = browser window width ?

    - by Patrick
    hi, I want to display a children element of my html page all over the browser window.. in other words I would like to enlarge it and keep it the same size the browser window also when it is resized after loading. I was wondering if I have to move this object outside the parent elements or I can set these properties with css. At the moment if I set width:100% and height:100%, it fits the parent (of course) and not the window. thanks

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  • Python: combine two neighbor list components

    - by kame
    When i use this code I get elements wich containing one number or letter. How to combine two neighbors? data = '4D41544C414220352E30204D41542D66696C652C20506C6174666F726D3A20504357494E2C2043726561746564206F6E3A20576564204D61792030352031363A31393A3337203230313020202020202020202020202020202020202020202020202020202020202020202020202020202020202020202020202020200001494D0F00000026000000789CE36360607000623620E680D220C00AE53343312310BA00692620E604F351010025BE00C8' data2 = list(data) print data2

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  • O(log n) algorithm for merging lists and computing rank?

    - by Eternal Learner
    Given two sorted lists, each containing n real numbers, is there a O(log?n) time algorithm to compute the element of rank i (where i coresponds to index in increasing order) in the union of the two lists, assuming the elements of the two lists are distinct? I can think of using a Merge procedure to merge the 2 lists and then find the A[i] element in constant time. But the Merge would take O(n) time. How do we solve it in O(log n) time?

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  • How to let Zend render a dynamic footer on every page?

    - by koko
    In the app I'm building, I'd like to have a nice footer with data from the database (tags) and a contact-form. All the parts are scripted, but now I'd like to put them all together. The elements of the footer are the same for every page loaded, only the content is different. How can I do this, without having to put too much code on every controller?

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  • In jQuery, is there any way to only bind a click once?

    - by Chris Henry
    I have an ajax app that will run functions on every interaction. I'd like to be able to run my setup function each time so all my setup code for that function remains encapsulated. However, binding elements more than once means that the handler will run more than once, which is obviously undesirable. Is there an elegant way in jQuery to call bind on an element more than once without the handler being called more than once?

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  • What is wrong with this list comprehension code?

    - by suresh
    My aim is to list all elements of the array a whose values are greater than their index positions. I wrote a Haskell code like this. [a|i<-[0..2],a<-[1..3],a!!i>i] When tested on ghci prelude prompt, I get the following error message which I am unable to understand. No instance for (Num [a]) arising from the literal 3 at <interactive>:1:20 Possible fix: add an instance declaration for (Num [a])

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  • How to replace {tag_INDEX} with array[INDEX] element

    - by ekapek
    Hi, I have string like this; "String {tag_0} text {tag_2} and {tag_1}" Now i need to replace all {tag_INDEX} with elements from array $myArray = array('a','b','c'); so after replacement it should looks like: "String a text c and b" What is the best way to do this? I'm trying with preg_replace and preg_replace_callback but without any good results

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  • How do I best catch up with the latest developments in java?

    - by Fredriku73
    I am applying for a job as java developer. I programmed some hobby apps in java until 2001, after that I have mostly worked in c++ and other languages. Meanwhile, it feels like java has grown a lot, and there are all kinds of acronyms (EJB, spring, etc) unknown to me. Where can I find a concise, clear explanation of the recent (5 years) development of java? What are key elements to understand?

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  • linq to xml return second element

    - by Phil
    Hi Im trying to return to the second element in the xml from flickr. This always returns the first element: ImageUrl = item.Element(ns + "link").Attribute("href").Value, and this errors? ImageUrl = item.Elements(ns + "link")[1].Attribute("href").Value, Thanks

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  • How can I add a function reference to an object literal

    - by rob
    I need to add binders to DOM elements after rendering is done. Therefore I want to pass a list with (ID, callback) tuples to the rendering function so it can bind it after the rendering is done. So i would like to create a list of such objects and pass it to the rendering function: {id:'#someDOMelement', callback: someObject.someFunction} and bind it after the rendering like this: $(binders[i].id).bind('click', binders[i].callback);

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  • How to count how many items for distinct items in mysql?

    - by Vincent Duprez
    Imagine a have a table with a column named status: status ------ A A A B C C D D D How can I count how many rows have A, how many rows have B etc? this kind of output: A |B |C |D |E ------------------ 3 |1 |2 |3 |0 As for E = O , this will always be A,B,C,D and E Output should be one row (thus 1 query). When doing a distinct count (most returning answer on my searches, it does return how many different elements there are, 4 in this case...)

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