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  • extract associative array within an array in php

    - by I Like PHP
    i have an array like this Array ( [0] => Array ( [s_id] => 4 [si_id] => sec_1 [d_id] => dep_4 [s_name] => sec1 [s_location] => LA [s_visibility] => yes [s_created_date] => 1273639343 [s_last_updated_date] => 1273639343 [s_created_by] => someone [s_last_updated_by] => everyone ) ) now i want to extract array[0] into an array... means i want this Array ( [s_id] => 4 [si_id] => sec_1 [d_id] => dep_4 [s_name] => sec1 [s_location] => LA [s_visibility] => yes [s_created_date] => 1273639343 [s_last_updated_date] => 1273639343 [s_created_by] => someone [s_last_updated_by] => everyone ) how do i get above results?

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  • iPhone SDK: Data Synchronization

    - by buzzappsoftware
    I am looking for an overview of data synchronization techniques available on the iPhone platform. We need the ability to be able to sync a subset of content from a server to a local database residing on the iPhone. On other projects I have worked on, the data synchronization was handled by the database. Is that available in SQLite? If not, any suggestions on techniques? Rolling our own would not be my first choice. Thanks in advance.

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  • Iterating through facebook comments JSON object failing

    - by user1594304
    I tried the option of students.item["http://www.myurl.com"].comments.data.length. However, the item["http://www.myurl.com"] call is not working. If I take out the URL from JSON object and write the iterator with students.comments.data, it works. Here is my code, any help highly appreciated. var students = { "http://www.myurl.com":{ "comments":{ "data" : [ { "id": "123456778", "from": { "name": "XYZ", "id": "1000005" }, "message": "Hey", "can_remove": false, "created_time": "2012-09-03T03:16:01+0000", "like_count": 0, "user_likes": false } ] } } } var i=0 var arrayObject = new Array(); alert("Parsing 2: "+students.item["http://www.myurl.com"].comments.data.length); for(i=0;i<students.item["http://www.myurl.com"].comments.data.length;i++) { alert("Parsing 1: "+i); arrayObject.push(students.item["http://www.myurl.com"].comments.data[i].id); arrayObject.push(students.item["http://www.myurl.com"].comments.data[i].message); arrayObject.push(students.item["http://www.myurl.com"].comments.data[i].created_time); }

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  • (php) regexto remove comments but ignore occurances within strings

    - by David
    Hi there, I am writing a comment-stripper and trying to accommodate for all needs here. I have the below stack of code which removes pretty much all comments, but it actually goes too far. A lot of time was spent trying and testing and researching the regex patterns to match, but I don't claim that they are the best at each. My problem is that I also have situation where I have 'PHP comments' (that aren't really comments' in standard code, or even in PHP strings, that I don't actually want to have removed. Example: <?php $Var = "Blah blah //this must not comment"; // this must comment. ?> What ends up happening is that it strips out religiously, which is fine, but it leaves certain problems: <?php $Var = "Blah blah ?> Also: will also cause problems, as the comment removes the rest of the line, including the ending ? See the problem? So this is what I need... Comment characters within '' or "" need to be ignored PHP Comments on the same line, that use double-slashes, should remove perhaps only the comment itself, or should remove the entire php codeblock. Here's the patterns I use at the moment, feel free to tell me if there's improvement I can make in my existing patterns? :) $CompressedData = $OriginalData; $CompressedData = preg_replace('!/\*.*?\*/!s', '', $CompressedData); // removes /* comments */ $CompressedData = preg_replace('!//.*?\n!', '', $CompressedData); // removes //comments $CompressedData = preg_replace('!#.*?\n!', '', $CompressedData); // removes # comments $CompressedData = preg_replace('/<!--(.*?)-->/', '', $CompressedData); // removes HTML comments Any help that you can give me would be greatly appreciated! :)

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  • How can I secure my $_GETs in PHP?

    - by ggfan
    My profile.php displays all the user's postings,comments,pictures. If the user wants to delete, it sends the posting's id to the remove.php so it's like remove.php?action=removeposting&posting_id=2. If they want to remove a picture, it's remove.php?action=removepicture&picture_id=1. Using the get data, I do a query to the database to display the info they want to delete and if they want to delete it, they click "yes". So the data is deleted via $POST NOT $GET to prevent cross-site request forgery. My question is how do I make sure the GETs are not some javascript code, sql injection that will mess me up. here is my remove.php //how do I make $action safe? //should I use mysqli_real_escape_string? //use strip_tags()? $action=trim($_GET['action']); if (($action != 'removeposting') && ($action != 'removefriend') && ($action != 'removecomment')) { echo "please don't change the action. go back and refresh"; header("Location: index.php"); exit(); } if ($action == 'removeposting') { //get the info and display it in a form. if user clicks "yes", deletes } if ($action =='removepicture') { //remove pic } I know I can't be 100% safe, but what are some common defenses I can use. EDIT Do this to prevent xss $action=trim($_GET['action']); htmlspecialchars(strip_tags($action)); Then when I am 'recalling' the data back via POST, I would use $posting_id = mysqli_real_escape_string($dbc, trim($_POST['posting_id']));

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  • JavaScript two-dimensional Array to PHP

    - by vi
    Hi I have to send a two-dimensional JavaScript Array to a PHP page. Indeed, I'm working on a form-builder, in which the user can add or remove fields. These fields are added (or removed) using JavaScript (jQuery). When the user is done and hit a 'publish' button, I have to get all the fields concerned and send them to a PHP page which would build a real form with it. I found a way to do it but I'm pretty sure it's not very clean : addedFields = new Array(); $("#add-info .field").each(function() { addedFields.push(new Array($(this).find('.name').val(), $(this).find('.type').val(), $(this).find('.size').val())); }); Basically, the ".field" class objects are <tr> and the ".name", ".type" and ".size" objects are inputs. So I get an array of [name, type, size], then I convert it into a string using addedFields = addedFields.join(";"); Finally, I go to the PHP form that way ; document.location.href = "create.php?addedfields=" + addedFields; Concerning the PHP code, I create a PHP array using the explode() function: $addedFields = explode(";", $_GET['addedfields']); and then I use it again for each element in the array: foreach ($addedFields as $field) { $field = explode(",", $field); echo "<li>Field with name : '$field[0]', of '$field[1]' type and with a size of $field[2]"; }

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  • iPhone SDK File Handler with iOS 4 Background Processes

    - by David Higgins
    The "application:applicationDidFinishLaunchingWithOptions:" message does not get called when an application is sitting in the background in iOS 4, and I'm trying to figure out how to be notified when the application is brought back into the foreground by another application. My application registers itself as a handler for certain file types, and Safari and other supported applications allow passing the files over to my app. This works great if the app is closed before I try to use it, but fails otherwise. In my application:applicationDidFinishLaunchingWithOptions: I have: NSURL *url = (NSURL *)[launchOptions valueForKey:UIApplicationLaunchOptionsURLKey]; if([url isFileURL]) { } [self.window makeKeyAndVisible]; return YES; As stated already, this works great so far for starting the app when it's not sitting in the background - but when I switch back over to Safari or Mail and try to open a new file that is supported, my application wakes up from the background and becomes active again but I can't see any "withOptions" overrides for application:applicationWillEnterForeground: or any way to identify what was passed in when it enters the foreground. What would be the appropriate way to receive these "open file notifications" when the application is in the background?

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  • SDK 3.2 - Trigger video from UIScrollView Subview (Audio but no video)

    - by stalure
    I am having a hard time getting video to play in an application that I am working on and I think the answer has to do with the views and view controllers. I have the flow depicted below. When the button is clicked, the audio from the video is playing, but nothing is displayed on screen. Anyone have any ideas? -(IBAction) playMovie { Play Movie Code } ViewController UIScrollView UIView UIButton - (playMovie)

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  • Textbox auto generate by php and html

    - by user2892997
    i have few field of data such as product , amount and barcode.The system just show 1 row of data insert form that contain the 3 field.when i completed insert the first row, then second row of textbox will auto generate, i can do it by microsoft access, can i do so for php ? <?php $i=0; ?> <form method="post" action=""> <input type="text" name="<?php echo $i; ?>" /> </form> <?php if(isset($_POST[$i])){ $i++; ?> <form method="post" action=""> <input type="text" name="<?php echo $i; ?>" /> </form> <?php }?> it work for the first and second textbox, but how can i continue to create more textbox accordingly?

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  • Show image on hover with PHP

    - by Sorosh
    I have a small problem with my PHP code and It would be very nice if someone could help me. I want to display an image when hovering over a link. This is the link with the PHP code that I have now: <a href="<?php the_permalink(); ?>"><?php if ( has_post_thumbnail() ) {the_post_thumbnail();} else if ( has_post_video() ) {the_post_video_image();}?></a> This code shows a image, but I want to execute this code when hovering over the link with the image: <?php echo print_image_function(); ?> The code also shows a image that belongs to a category. I don't want the initial image to disappear I simply want to show the second image on top off the first image when hovering over the first image. I don't know if it is helpful but I use Wordpress and I am not a PHP expert. I even don't know if this is going to work. Thats why I am asking if somebody can help me with this. Thanks in advance

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  • php mysql_fetch_array() error

    - by user1877823
    I am getting this error while i am trying to delete a record the query is working but this line remains on the page. i want to echo "Deleted" written in the while should show up but the while loop is not working, i have tried and searched alot nothing helps! mysql_fetch_array() expects parameter 1 to be resource, boolean given in delete.php on line 27 delete.php <html> <body> <form method="post"> Id : <input type="text" name="id"> Name : <input type="text" name="name"> Description : <input type="text" name="des"> <input type="submit" value="delete" name="delete"> </form> <?php include("connect.php"); $id = $_POST['id']; $name = $_POST['name']; $des = $_POST['des']; $result = mysql_query("DELETE FROM fact WHERE id='$id'") or die(mysql_error()); while($row = mysql_fetch_array($result)) { echo "Deleted"; } mysql_close($con); ?> </body> </html> connect.php <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Dataentry", $con); ?> How should i make the while loop work..

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  • PHP, Apache and curl: Differences between Windows and Linux?

    - by beginner_
    I'm trying to run my php App on Ubuntu Server 11.10. This App works fine under Apache + PHP in windows. I have other applications that I can simply copy&paste between the 2 OS and they work on both. (These don't use cURL). However this one uses the php library tonic (RESTful webservices) and makes us of php cURL module. The issue is I'm not getting an error message which makes it impossible to find the issue. I (must) use NTLM authentication and this is done with AuthenNTLM Apache Module: Order allow,deny Allow from all PerlAuthenHandler Apache2::AuthenNTLM AuthType ntlm AuthName "Protected Access" require valid-user PerlAddVar ntdomain "domainName server" PerlSetVar defaultdomain domainName PerlSetVar ntlmsemtimeout 2 PerlSetVar ntlmdebug 1 PerlSetVar splitdomainprefix 0 All files that cURL needs to fetch override AuthenNTLM authentication: order deny,allow deny from all allow from 127.0.0.1 Satisfy any Since these files are only fectehd by cURL from same server, access can be limited to localhost. Possible issues are: NTLM auth isn't overridden for files requested through cURL (even though AllowOverride All is set) curl works differently on linux $ch = curl_init(); curl_setopt($ch, CURLOPT_COOKIE, $strCookie); curl_setopt($ch, CURLOPT_URL, $baseUrl . $queryString); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $html = curl_exec($ch); curl_close($ch); other? Apache log says: [error] Bad/Missing NTLM/Basic Authorization Header for /myApp/webservice/local/viewList.php But this directory should override NTLM authentication using curl command line from windows to access same resource i get: <!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN"> <html> <head> <title>406 Not Acceptable</title> </head> <body> <h1>Not Acceptable</h1> <p>An appropriate representation of the requested resource /myApp/webservice/myResource could not be found on this server.</p> Available variants: <ul> <li><a href="myResource.php">myResource.php</a> , type application/x-httpd-php</li> </ul> <hr> <address>Apache/2.2.20 (Ubuntu) Server at localhost Port 80</address> </body> </html> Note: This is duplicate from http://stackoverflow.com/questions/9821979/php-curl-on-linux-what-is-the-difference-to-curl-on-windows Is it was suggested I post it here. EDIT: Please see Ubuntu Server: Apache2 seems to attach .php to URI as I discovered why it does not work but need help so the issue does not occur anymore. ANSWER: The issue is the default Apache configuration on Ubuntu: Options Indexes FollowSymLinks MultiViews MultiViews is changing request_uri from myResource to myResource.php. Solutions: disable MultiViews in .htaccess: Options -MultiViews remove MultiViews from default config rename the file as example to myResourceClass I chose last option because that should work regardless of configuration and I only have 3 such files so the change took about 30 secs...

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  • I am getting a 400 Bad Request error when using Nginx and PHP-FPM, why?

    - by Bob
    I am trying to run a website (that requires PHP - it technically doesn't require MySQL at this time, but it may sometime in the near future as I continue developing it, so I went ahead and installed that as well) using nginx 1.2.4 and PHP-FPM 5.3.3 on Ubuntu 12.04.1 LTS. As far as I know, I haven't done anything wrong, but clearly something is not quite right - I seem to be getting a 400 Bad Request error whenever I try to browse to my website. I've been mostly following one guide, and I've done more or less everything it recommends, except for not setting up PHP-FPM to use a Unix Socket and I used service as opposed to /etc/init.d/ when starting/stopping nginx, PHP, and MySQL. Anyways, here are my relevant configuration files (I have only censored personal/sensitive details, like my domain name - which contains my real name): /etc/nginx/nginx.conf user www-data; worker_processes 4; pid /var/run/nginx.pid; events { worker_connections 768; # multi_accept on; } http { ## # Basic Settings ## sendfile on; tcp_nopush on; tcp_nodelay on; keepalive_timeout 15; types_hash_max_size 2048; # server_tokens off; # server_names_hash_bucket_size 64; # server_name_in_redirect off; include /etc/nginx/mime.types; default_type application/octet-stream; ## # Logging Settings ## access_log /var/log/nginx/access.log; error_log /var/log/nginx/error.log; ## # Gzip Settings ## gzip on; gzip_disable "msie6"; # gzip_vary on; # gzip_proxied any; # gzip_comp_level 6; # gzip_buffers 16 8k; # gzip_http_version 1.1; # gzip_types text/plain text/css application/json application/x-javascript text/xml application/xml application/xml+rss text/javascript; ## # nginx-naxsi config ## # Uncomment it if you installed nginx-naxsi ## #include /etc/nginx/naxsi_core.rules; ## # nginx-passenger config ## # Uncomment it if you installed nginx-passenger ## #passenger_root /usr; #passenger_ruby /usr/bin/ruby; ## # Virtual Host Configs ## include /etc/nginx/conf.d/*.conf; include /etc/nginx/sites-enabled/*; } /etc/nginx/sites-enabled/subdomain.mydomain.net server { listen 80; # listen for IPv4 listen [::]:80; # listen for IPv6 server_name www.subdomain.mydomain.net subdomain.mydomain.net; access_log /srv/www/subdomain.mydomain.net/logs/access.log; error_log /srv/www/subdomain.mydomain.net/logs/error.log; location / { root /srv/www/subdomain.mydomain.net/public; index index.php; } location ~ \.php$ { try_files $uri =400; include fastcgi_params; fastcgi_split_path_info ^(.+\.php)(/.+)$; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME /srv/www/subdomain.mydomain.net/public$fastcgi_script_name; } } All the directories listed in the configuration files above are correct on my server (to the extent of my knowledge). I have not included /etc/php5/fpm/pool.d/www.conf or /etc/php5/fpm/php.ini in this post as they're rather long, but I have posted them on Pastebin: http://pastebin.com/ensErJD8 and http://pastebin.com/T23dt7vM, respectively. Although, the only thing I've changed in either of the two files was in php.ini, where I set expose_php to off so as to hide the .php file extension from users. What can I do to resolve my issue? Please let me know if I need to supply any additional details.

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  • Am I correctly handling duplicate URLs for my homepage?

    - by Rob Goldstein
    I own a Job Search site named www.conservationjobboard.com and have a concern about how the domain is viewed by search engines. The issue is that when the site was first designed, the default page was left as default.php, but the homepage was actually JobBoard.php. To handle this, the default.php page performed a redirect to the JobBoard.php file when www.conservationjobboard.com/ was requested. The main problem resulted because the redirect was a temporary redirect causing search engines to index conservationjobboard.com/ and conservationjobboard.com/JobBoard.php as 2 separate pages. This has since been corrected to use the .htaccess file so that JobBoard.php is now the default file for the root directory eliminating the need for the redirect. Problem is that search engines still show both URL's in search results (one including JobBoard.php and one that ends with /). Another potential problem is that some of my early backlinks are to conservationjobboard.com/JobBoard.php while the rest are to conservationjobboard.com The 2 outstanding questions are as follows: 1. Is my domain still being penalized by search engines like Google for having duplicate homepage URL's? 2. Are all of the back links to my homepage being considered as the same now or is the total number of back links being split between the 2 different URL's? If you think there are still issues with how we have this set-up, I was wondering if you could give me advice on what we should do differently. Thanks.

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  • OpenJs mysql not reading database [migrated]

    - by Benedikt Wutzi
    I try to access a mysql table using OpenJs Grid. I already doublechecked if the database "partsdb" and the table "parts" exists and it can be accessed from the commandline. Currently I'm using the must basic example: members.php: <!DOCTYPE html> <html lang="en"> <head> <meta charset="utf-8"> <title>Members Page</title> <script> $(function() { $(".parts").grid(); }); </script> </head> <body> <div id="container"> <h1>Members Page</h1> <table action="ajax.php"> <tr> <th col="id">Id</th> <th col="name">Name</th> </tr> </table> <a href='<?php echo base_url()."main/logout" ?>'>Logout</a> </div> and ajax.php <?php mysql_connect("localhost","****","*****"); mysql_select_db("partsdb"); require_once("grid.php"); $grid = new Grid("parts"); ?> When I run php directly on ajax.php I get an error telling me: " Unknown column 'parts.' in 'field list' " and the table shows only the headers. What am I doing wrong?

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  • How to enabled pdo mysql in Centos 5.8

    - by nacho3d
    I have a VPS with Centos 5.8 In phpinfo displays: './configure' '--disable-fileinfo' '--disable-pdo' '--enable-bcmath' '--enable-calendar' '--enable-ftp' '--enable-libxml' '--enable-magic-quotes' '--enable-sockets' '--prefix=/usr/local' '--with-apxs2=/usr/local/apache/bin/apxs' '--with-curl=/opt/curlssl/' '--with-imap=/opt/php_with_imap_client/' '--with-imap-ssl=/usr' '--with-kerberos' '--with-libdir=lib64' '--with-libxml-dir=/opt/xml2/' '--with-mysql=/usr' '--with-mysql-sock=/var/lib/mysql/mysql.sock' '--with-openssl=/usr' '--with-openssl-dir=/usr' '--with-pcre-regex=/opt/pcre' '--with-pic' '--with-zlib' '--with-zlib-dir=/usr' I've tried this: http://www.host1free.com/forum/vps-technical-support/7248-tutoria-centos-apache-webserver-mysql-php-eaccelerator-apc.html And aparently it installed php-pdo # rpm -qa |grep php php-5.3.13-1.el5.remi php-xml-5.3.13-1.el5.remi php-common-5.3.13-1.el5.remi php-cli-5.3.13-1.el5.remi php-pdo-5.3.13-1.el5.remi php-xmlrpc-5.3.13-1.el5.remi php-mcrypt-5.3.13-1.el5.remi But I've restarted apache and it still says in my phpinfo: '--disable-pdo' Should I rebuild php? Do I need to do some other step?

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  • Entry / JR Php Programmer - What do I learn next?

    - by dtj
    I got very interested in programming toward the end of college. Took a few classes, but learned most everything on my own via books and such. Its mostly been Php and MySQL. Right out of school, I got a job working at a company for 2 years (web media) and ended up learning a lot of stuff and programming some things for them. I am no longer at that company but I am looking for my next steps as a programmer. I really enjoy Web Development and Php and MySQL seems to be my thing. Basically, I know how to do CRUD operations, i am mediocre at OOP and still have more to learn, I know HTML and CSS quite well, I know my way around a Unix terminal and can access MySQL through it and set up cron jobs and such. I know some basic Javascript. Whats a good next step? I don't anything about 3rd party services, PDO, APIs (twitter, facebook, etc), Drupal / Joomla, Unit Testing, E-Commerce, PECL, PEAR ....in other words A LOT I get easily overwhelmed by the amount of stuff there is to learn, so I'm sort of trying to find a path. Right now, I'm digging into OOP more, as that seems like a good conceptual first-step. Any suggestions?

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  • How to develop Online Shopping Portal Application using PHP ?

    - by Sarang
    I do not know PHP & I have to develop a Shopping Portal with following Definition : Scenario: Online Shopping Portal XYZ.com wants to create an online shopping portal for managing its registered customers and their shopping. The customers need to register themselves first before they do shopping using the shopping portal. However, everyone, whether registered or not, can view the various products along with the prices listed in the portal. The registered customers, after logging in, are allowed to place order for one or more products from the products listed in the portal. Once the order is placed, the customer gets a reference order number and the order status should be “order in process”. The customers can track their order using the given reference number. The management of XYZ.com should be able to modify the order status of a particular reference order number to “shipped” once the products are shipped to the shipping address entered by the customer at the time of placing the order. The Functionalities required are : Create the interface for the XYZ.com shopping portal using HTML/XHTML and CSS. Implement the client side validations using JavaScript. Create the tables using MySQL. Implement the functionality using the server side scripting language, PHP. Integrate all the above tasks and make the XYZ.com shopping portal functional. How do I develop this application with following proper steps of development ?

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