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  • Is Movable Type among the most secure PHP blogs? How secure are the various PHP blog applications?

    - by user6025
    Basically I'm trying to find a blog for a website, and security is the highest priority in our case. We don't need any features that I would imagine are special. Wordpress was our first idea, but its reputation precedes it, and though it may have cleaned up its act lately, I'm not seeing much solid evidence. I get the impression that Movable Type (at least the Perl version) has a much better reputation for security than Wordpress (historically at least). I'm not sure I want to take a chance with Wordpress at this point, but is there some objective source I can got to to back up (or counter) the notion that MT is at least among the best? Secunia doesn't recommend using their stats for comparisons, and securityfocus.com doesn't have stats at all that I can see. Searching here http://web.nvd.nist.gov makes MT look way better than WP (at least in 2007), but this site was referenced by MT's own page boasting about their security, so I don't know how relevant it is or how seriously people take it. Any suggestions on sites where I could/should make a somewhat objective comparison?

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  • I'm confused about encryption and SSL

    - by ChowKiko
    while my friends and I planning to run our own website, we're confused about the encryption where hackers can TAPPING or in social engineering it's WIRE TAPPING, but I don't know how do they call it in Computers today... Well guys, I just want to know how encryption works with websites if we are using PHP+MYSQL? Is it ok to use user login ---- (PHP) encrypt inputted value then (PHP) will decrypt and validate it going to (MySQL) user login ---- (PHP) encrypt inputted value and decrypt the (MySQL) data if they are similar... Is it similar if we use $_SESSION without encryption inside PHP going to MySQL?or PHP encryption also helps the manipulation of binaries?..I'm so confused T_T... In regards to what I stated above, can a hacker hook the data if the server uses $_SESSION? Is $_SESSION safe?... IF THE HACKER CAN HOOK it? is it necessary to use SSL on our website? and why do some Merchandise websites use SSL and likewise facebook also uses SSL? what is the best suit for you if there is no SSL? encrypting the DATA using PHP going to MySQL or even without encryption while the PHP server uses $_SESSION?...

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  • Microsoft sort un SDK pour SQL Server Reporting Services, qui permet l'interopérabilité avec les API

    Microsoft sort un SDK pour SQL Server Reporting Services, qui permet l'interopérabilité avec les API en PHP Microsoft a sorti ce matin un SDK gratuit pour SQL Server Reporting Services qui est compatible PHP. Ce toolkit permet aux développeurs de créer des applications tournant sous Microsoft SQL Server Reporting Services, tout en boostant l'interopérabilité entre les applications en PHP et les logiciels de Microsoft dédiés au reporting et à la business intelligence. Les rapports peuvent être réalisés puis intégrés avec des applications d'entreprise en ligne, ce qui offre un meilleur accès aux informations contenant des données graphiques et du contenu riche, d'après Microsoft. Les développeurs travaillant avec PHP p...

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  • How do I get away from PHP in the web industry?

    - by Kurtis
    I'm just looking for some tips on getting away from using PHP for web development. I'm self-employed but it seems like all of the work I find deals with PHP. I'm not complaining about the work -- just the poor choice of a language that is incredibly popular. I'd love to do my web development in Python, Perl, C#, or even a fun and fancy functional language. There's the old saying that you don't tell a carpenter what kind of a hammer to use. At the same time, you do tell them what kind of material to build your house out of and how much you're willing to spend. The problem I am running in to is that I don't know how to get out of this spiral. I can't just turn down work because then I wouldn't have any. I really don't want to go work for another company -- and even if I did, I'd probably still be stuck using something I don't enjoy. I'm hoping someone has "been there" before and might have some good ideas on how to get out of this situation. Thanks!

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  • PHP FPDF PDF Page Break Question

    - by Michael
    I am using PHP and FPDF to generate a PDF with a list of items. My problem is if the item list goes on to a second or third page, I want to keep the Item Name, Quantity and Description together. Right now, it will go to a second page, but it may split up all of the details for a particular item. PLEASE HELP! <?php require_once('auth.php'); require_once('config.php'); require_once('connect.php'); $sqlitems="SELECT * FROM $tbl_items WHERE username = '" . $_SESSION['SESS_LOGIN'] . "'"; $resultitems=mysql_query($sqlitems); require_once('pdf/fpdf.php'); require_once('pdf/fpdi.php'); $pdf =& new FPDI(); $pdf->AddPage('P', 'Letter'); $pdf->setSourceFile('pdf/files/healthform/meds.pdf'); $tplIdx = $pdf->importPage(1); $pdf->useTemplate($tplIdx); $pdf->SetAutoPageBreak(on, 30); $pdf->SetTextColor(0,0,0); $pdf->Ln(10); while($rowsitems=mysql_fetch_array($resultitems)){ $pdf->SetFont('Arial','B',10); $pdf->Cell(50,4,'Item Name:',0,0,'L'); $pdf->SetFont(''); $pdf->Cell(100,4,$rowsitems['itemname'],0,0,'L'); $pdf->SetFont('Arial','B',10); $pdf->Cell(50,4,'Quantity:',0,0,'L'); $pdf->SetFont(''); $pdf->Cell(140,4,$rowsitems['itemqty'],0,1,'L'); $pdf->SetFont('Arial','B'); $pdf->Cell(50,4,'Description:',0,0,'L'); $pdf->SetFont(''); $pdf->Cell(140,4,$rowsitems['itemdesc'],0,1,'L'); } $pdf->Output('Items.pdf', 'I'); ?>

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  • [solved] PHP-called hyperlink stopped showing when CSS table implemented

    - by Luke
    EDIT: Solved - was not flutter's tag stripping, should work as advertised. I'm using Flutter (which creates custom fields) in Wordpress to display profile information entered as a Post. Before I implemented the CSS tables the link showed up and was clickable. Now I get nothing returned, even when I try to call the link outside the table. If you know anything about this, here's my code in the index.php file and I remain available for any questions. <?php if (in_category('Profile')) { ?> <table id="mytable" cellspacing="0"> -snip- <tr> <th class="row1" valign="top">Website </td> <td>Link: <a href="<?php echo get_post_meta($post->ID, 'FrWebsite', $single=true) ?>"> <?php echo get_post_meta($post->ID, 'FrWebsite', $single=true) ?></a></td> </tr> -snip- </table> Thanks, L Edit: @Josh - there is a foreach looping construct in the table and it is reading and displaying the code correctly, I see what you're getting at now: <tr> <th class="row2" valign="top">Specialities </td> <td class="alt" valign="top"><?php $my_array = get('Expertise'); $output = ""; foreach($my_array as $check) { $output .= "<span>$check</span><br/> "; } echo $output; ?></td> </tr> Edit - @Josh - here's the old code as far as I can remember it, there was no major difference just a <td> tag where there now stands a <th>, there wasn't the class="" and there was no "Link:" and FrWebsite was called Website, but it still didn't work when called Website so I changed to see if that was the error. <tr> <td width="200" valign="top">Website </td> <td><a href="<?php echo get_post_meta($post->ID, 'Website', $single=true) ?>"><?php echo get_post_meta($post->ID, 'Website', $single=true) ?></a></td> </tr>

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  • I have a php form dropdown menu that needs to send information

    - by shinjuo
    I have a dropdown menu that is filled by a mysql database. I need to select one and have it send the information for use on the next page after clicking submit. It does populate the drop down menu like it is supposed to it just does not seem to catch the data on the next page. Here is what I have: removeMain.php <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <form action="remove.php" method="post"> <?php $link = mysql_connect('********', '********', '*********'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("********", $link); $res = mysql_query("SELECT * FROM cardLists order by cardID") or die(mysql_error()); echo "<select name = CardID>"; while($row=mysql_fetch_assoc($res)) { echo "<option value=$row[ID]>$row[cardID]</a></option>"; } echo "</select>"; ?> Amount to Remove: <input type="text" name="Remove" /> <input type="submit" /> </form> <body> </body> </html> remove.php <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <body> <?php $link = mysql_connect('*********', '*********', '*********'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("***********y", $link); $query = sprintf("UPDATE cardLists SET AmountLeft = AmountLeft - %s WHERE cardID = '%s'", mysql_real_escape_string($_POST["Remove"]), mysql_real_escape_string($_POST["CardID"])); mysql_query($query); mysql_close($link); ?> <br /> <a href="removeMain.php"> <input type="submit" name="return" id="return" value="Update More" /></a> <a href="index.php"> <input type="submit" name="main" id="main" value="Return To Main" /></a> </body> </html>

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  • Newbie's problems with MySQL and php

    - by Mirage81
    I'm a real newbie with php and MySQL. Now I'm working on the following code which should search the database for eg. all the Lennons living in Liverpool. 1) How should I modify "get.php" to get the text "no results" to appear if there are no search results. 2) How should I modify "index.php" to get the option values (city and lastname) straight from the database instead of having to type them one by one? 3) Am I using mysql_real_escape_string the right way? 4) Any other mistakes in the code? index.php: <form action="get.php" method="post"> <p> <select name="city"> <option value="Birmingham">Birmingham</option> <option value="Liverpool">Liverpool</option> <option value="London">London</option> </select> </p> <p> <select name="lastname"> <option value="Lennon">Lennon</option> <option value="McCartney">McCartney</option> <option value="Osbourne">Osbourne</option> </select> </p> <p> <input value="Search" type="submit"> </p> </form> get.php: <?php $city = $_POST['city']; $lastname = $_POST['lastname']; $conn = mysql_connect('localhost', 'user', 'password'); mysql_select_db("database", $conn) or die("connection failed"); $query = "SELECT * FROM users WHERE city = '$city' AND lastname = '$lastname'"; $result = mysql_query($query, $conn); $city = mysql_real_escape_string($_POST['city']); $lastname = mysql_real_escape_string($_POST['lastname']); echo $rowcount; while ($row = mysql_fetch_row($result)) { if ($rowcount == '0') echo 'no results'; else { echo '<b>City: </b>'.htmlspecialchars($row[0]).'<br />'; echo '<b>Last name: </b>'.htmlspecialchars($row[1]).'<br />'; echo '<b>Information: </b>'.htmlspecialchars($row[2]); } } mysql_close($conn);

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  • php array code with regular expressions

    - by user551068
    there are few mistakes which it is showing as Warning: preg_match() [function.preg-match]: Delimiter must not be alphanumeric or backslash in array 4,9,10,11,12... can anyone resolve them <?PHP $hosts = array( array("ronmexico.kainalopallo.com/","beforename=$F_firstname%20$F_lastname&gender=$F_gender","Your Ron Mexico Name is ","/the ultimate disguise, is <u><b>([^<]+)<\/b><\/u>/s"), array("www.fjordstone.com/cgi-bin/png.pl","gender=$F_gender&submit=Name%20Me","Your Pagan name is ","/COLOR=#000000 SIZE=6> *([^<]*)<\/FONT>/"), array("rumandmonkey.com/widgets/toys/mormon/index.php","gender=$F_gender&firstname=$F_firstname&surname=$F_lastname","Your Mormon Name is ","/<p>My Mormon name is <b>([^<]+)<\/b>!<br \/>/s"), array("cyborg.namedecoder.com/index.php","acronym=$F_firstname&design=edox&design_click-edox.x=0&design_click-edox.y=0&design_click-edox=edo","","Your Cyborg Name is ","/<p>([^<]+)<\/p>/"), array("rumandmonkey.com/widgets/toys/namegen/10/","nametype=$brit&page=2&id=10&submit=God%20save%20the%20Queen!&name=$F_firstname%20$F_lastname","Your Very British Name is ","/My very British name is \&lt\;b\&gt;([^&]+)\&lt;\/b\&gt;\.\&lt;br/"), array("blazonry.com/name_generator/usname.php","realname=$F_firstname+$F_lastname&gender=$F_gender","Your U.S. Name is ","/also be known as <font size=\'\+1\'><b>([^<]+)<\/b>/s"), array("www.spacepirate.org/rogues.php","realname=$F_firstname%20$F_lastname&formentered=Yes&submit=Arrrgh","Your Space Pirate name is ","/Your pirate name is <font size=\'\+1\'><b>([^<]+)<\/b><\/font>/s"), array("rumandmonkey.com/widgets/toys/ghetto/","firstname=$F_firstname&lastname=$F_lastname","Your Ghetto Name is ","/<p align=\"center\" style=\"font-size: 36px\">\s*<br \/>\s*([^<]*)<br \/>/"), array("www.emmadavies.net/vampire/default.aspx","mf=$emgender&firstname=$F_firstname&lastname=$F_lastname&submit=Find+My+Vampire+Name","","Your Vampire Name is ","/<i class=\"vampirecontrol vampire name\">([^<]*)<\/i>/"), array("www.emmadavies.net/fairy/default.aspx","mf=$emgender&firstname=$F_firstname&lastname=$F_lastname&submit=Seek+Fairy","","Your Fairy Name is ","/<i class=\'ng fairy name\'>([^<]*)<\/i>/"), array("www.irielion.com/israel/reggaename.html","phase=3&oldname=$F_firstname%20$F_lastname&gndr=$reggender","","Your Rasta Name is ","/Yes I, your irie new name is ([^\n]*)\n/"), array("www.ninjaburger.com/fun/games/ninjaname/ninjaname.php","realname=$F_firstname+$F_lastname","Your Ninja Burger Name is ","/<BR>Ninja Burger ninja name will be<BR><BR><FONT SIZE=\'\+1\'>([^<]*)<\/FONT>/"), array("gangstaname.com/pirate_name.php","sex=$F_gender&name=$F_firstname+$F_lastname","Your Pirate Name is ","/<p><strong>We\'ll now call ye:<\/strong><\/p> *<h2 class=\"newName\">([^<]*)<\/h2>/"), array("www.xach.com/nerd-name/","name=$F_firstname+$F_lastname&gender=$F_gender","Your Nerd Name is ","/<p><div align=center class=\"nerdname\">([^<]*)<\/div>/"), array("rumandmonkey.com/widgets/toys/namegen/5941/","page=2&id=5941&nametype=$dj&name=$F_firstname+$F_lastname","Your DJ Name is ","/My disk spinnin nu name is &lt\;b&gt\;([^<]*)&lt\;\/b&gt\;\./"), array("pizza.sandwich.net/poke/pokecgi.cgi","name=$F_firstname%20$F_lastname&color=black&submit=%20send%20","Your Pokename is ","/Your Pok&eacute;name is: <h1>([^<]*)<\/h1>/") ); return $hosts; ?>

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  • Included php file calling Javascript function

    - by Illes Peter
    Hi there! Here's the deal. I've got index.php which links to an internal JS file in it's header. index.php then includes another .php file, which outputs this: + add file. addFile() is a Javascript function defined in the external JS file. By doing this nothing happens, the included php does not "see" the JS function. Encapsulating the JS in the included PHP makes it all work. But I don't want to do it that way. Any ideas? EDIT: here's the source <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Archie</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"/> <link rel="stylesheet" href="/screen.css" type="text/css" media="screen"/> <script src="/lib/js/archie.js" type="text/javascript"></script> </head> <body> ... ... //included php starts here <form action="/lib/course.php" method="post"> <fieldset> <div id="addFileLocation"></div> <a href="#" onClick="addFile()">+ add file</a> <input type="hidden" id="addFileCount" value="0"/> </fieldset> </form> //ends here ... ... </body> </html> and the js: <script type="text/javascript"> //Dynamically add form fields //add file browser function addFile() { var location = document.getElementById('addFileLocation'); var num = document.getElementById('addFileCount'); var newnum = (document.getElementById('addFileCount').value -1)+ 2; num.value = newnum; var newname = 'addFile_'+newnum; var newelement = document.createElement('input'); newelement.setAttribute('name',newname); newelement.setAttribute('type','file'); location.appendChild(newelement); } </script>

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  • Display all images from outside web root folder using PHP

    - by micmola
    Hello, I want to display all images that are stored outside my web root folder. Please help me. I am only able to display one image repeatedly. For example, if I have 5 images in my folder, only one image is displayed on my browser 5 times. Please help me on this. I've been working on this problem for over a month now. I'm a newbie. Help. Thank you. Here is the code I'm using. images.php <?php // Get our database connector require("includes/copta.php"); // Grab the data from our people table $sql = "select * from people"; $result = mysql_query($sql) or die ("Could not access DB: " . mysql_error()); $imgLocation = " /uploadfile/"; while ($row = mysql_fetch_array($result)) { $imgName = $row["filename"]; $imgPath = $imgLocation . $imgName; echo "<img src=\"call_images.php?imgPath=" . $imgName . "\" alt=\"\"><br/>"; echo $row['id'] . " " . $imgName. "<br />"; } ?> call_images.php <?php // Get our database connector require("includes/copta.php"); $imgLocation = '/ uploadz/'; $sql = "select * from people"; $result = mysql_query($sql) or die ("Could not access DB: " . mysql_error()); while ($row = mysql_fetch_array($result)) { $imgName = $row["filename"]; $imgPath = $imgLocation . $imgName; // Make sure the file exists if(!file_exists($imgPath) || !is_file($imgPath)) { header('HTTP/1.0 404 Not Found'); die('The file does not exist'); } // Make sure the file is an image $imgData = getimagesize($imgPath); if(!$imgData) { header('HTTP/1.0 403 Forbidden'); die('The file you requested is not an image.'); } // Set the appropriate content-type // and provide the content-length. header("Pragma: public"); header("Expires: 0"); header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Type: image/jpg"); header("Content-length: " . filesize($imgPath)); // Print the image data readfile($imgPath); exit(); } ?>

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  • php and asp problem in uploading

    - by moustafa
    i have an ASP web services to change byte array that given from the client and change it to a file and save it in the web server the code is like this : [WebMethod] public string UploadFile(byte[] f, string fileName) { try { MemoryStream ms = new MemoryStream(f); String path="/myfile/"; String location=HttpContext.Current.Server.MapPath(path); FileStream fs = new FileStream(HttpContext.Current.Server.MapPath(path)+fileName, FileMode.Create); ms.WriteTo(fs); ms.Close(); fs.Close(); return "OK"; } catch (Exception ex) { return ex.Message.ToString(); } } the web services need byte array and file name.. i build the client in php upload.php the code is <html> <body> <form action="action1.php" method="post" enctype="multipart/form-data"> Pilih File Anda: <input type="file" name="myfile" /> <input type="submit" value="Upload" /> </form> </body> <html> and action1.php the code is: <?php require_once('nusoap.php'); $client = new nusoap_client('http://192.168.254.160/testuploadah/FileUploader.asmx?WSDL', 'wsdl','','', '', ''); $err = $client->getError(); if ($err) { echo '<h2>Constructor error</h2><pre>' . $err . '</pre>'; } if(is_uploaded_file($_FILES['myfile']['tmp_name'])){ $uploadFile = $_FILES['myfile']; ////how can read byte array of $uploadFile so i can send to web services??? ////are php only can send array or string ? $params[]->f=??????????????? $params[]->fileName=$_FILES['myfile']['name']; $result = $client->call('UploadFile', $params,'', '', false, true); if ($client->fault) { echo '<h2>Fault</h2><pre>'; print_r($result); echo '</pre>'; } else { //Check for errors $err = $client->getError(); if ($err) { //// Display the error echo '<h2>Error</h2><pre>' . $err . '</pre>'; } else { //// Display the result echo '<h2>Result</h2><pre>'; print_r($result); echo '</pre>'; } } } ?> how can i Send the byte array parameter to the web services,so the web services can started???? i still can resolve this problem,the web services always return an error because i can't send byte array

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  • Downloading large file with php

    - by Alessandro
    Hi, I have to write a php script to download potentially large files. The file I'm reporting here works fine most of the times. However, if the client's connection is slow the request ends (with status code 200) in the middle of the downloading, but not always at the very same point, and not at the very same time. I tried to overwrite some php.ini variables (see the first statements) but the problem remains. I don't know if it's relevant but my hosting server is SiteGround, and for simple static file requests, the download works fine also with slow connections. I've found Forced downloading large file with php but I didn't understand mario's answer. I'm new to web programming. So here's my code. <?php ini_set('memory_limit','16M'); ini_set('post_max_size', '30M'); set_time_limit(0); include ('../private/database_connection.php'); $downloadFolder = '../download/'; $fileName = $_POST['file']; $filePath = $downloadFolder . $fileName; if($fileName == NULL) { exit; } ob_start(); session_start(); if(!isset($_SESSION['Username'])) { // or redirect to login (remembering this download request) $_SESSION['previousPage'] = 'download.php?file=' . $fileName; header("Location: login.php"); exit; } if (file_exists($filePath)) { header('Content-Description: File Transfer'); header('Content-Type: application/octet-stream'); //header('Content-Disposition: attachment; filename='.$fileName); header("Content-Disposition: attachment; filename=\"$fileName\""); header('Content-Transfer-Encoding: binary'); header('Expires: 0'); header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); //header('Pragma: public'); header('Content-Length: ' . filesize($filePath)); ob_clean(); flush(); // download // 1 // readfile($filePath); // 2 $file = @fopen($filePath,"rb"); if ($file) { while(!feof($file)) { print(fread($file, 1024*8)); flush(); if (connection_status()!=0) { @fclose($file); die(); } } @fclose($file); } exit; } else { header('HTTP/1.1 404 File not found'); exit; } ?>

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  • how to increment a javascript variable title that is within a php while loop

    - by steve
    I'm building multiple countdown clocks on one page. The number of countdown clocks varies from day to day so I need to call javascript several times from within "while" code in php to produce different clocks. The following code works but it's based on knowing how many clocks are needed before I start: <script language="javascript" src="countdown.js"></script> <script language="javascript"> var cd1 = new countdown('cd1'); cd1.Div = "clock1"; cd1.TargetDate = "<?php echo "$clocktime"; ?>"; cd1.DisplayFormat = "%%D%% days, %%H%% hours, %%M%% minutes, %%S%% seconds until event AAA happens"; </script> <div id="clockwrapper"><div id="clock1">[clock]</div></div> <script language="javascript" src="countdown.js"></script> <script language="javascript"> var cd2 = new countdown('cd2'); cd2.Div = "clock2"; cd2.TargetDate = "02/01/2011 5:30:30 PM"; cd2.DisplayFormat = "%%D%% days, %%H%% hours, %%M%% minutes, %%S%% seconds until event BBB happens..."; </script> <div id="clockwrapper"><div id="clock2">[clock]</div></div> So if I keep on calling the javascript above (the code with cd1 in it) all previous "cd1" clocks change to the latest clock because it is being overwritten. Somehow I need to call javascript from within my "while" loop in php and have cd1 become cd2, then cd3 so that the clocks work as they're supposed to. How do I go about doing this? I don't know how to call the javascript several times and increment the variable cd1 within the javascript. I tried something like this but couldn't get it to work. $id=mysql_result($result,$i,"id"); while($id){ $cd = ("$cd"."$id"); ?> <script language="javascript" src="countdown.js"></script> <script language="javascript"> var <?php echo "$cd"; ?> = new countdown('<?php echo "$cd"; ?>'); .... </script> <div id="clockwrapper"><div id="<?php echo "$cd"; ?>">[clock]</div></div> <?php $id=mysql_result($result,$i,"id"); } ?> Surely there is some easy way of getting around this that I don't know about. Thanks

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  • How to send variable to php with ajax?

    - by Dee1983
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <script type="text/javascript"> function load(thediv, thefile) { if (window.XMLHttpRequest) { xmlhttp = new XMLHttpRequest(); } else { xmlhttp = new ActiveXObject('Microsoft.XMLHTTP)'); } xmlhttp.onreadystatechange = function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById(thediv) .innerHTML = xmlhttp.responseText; } } xmlhttp.open('GET', thefile, true); xmlhttp.send(); } </script> </head> <body> <?php //connection to db and mysql query $result = mysql_query($query) or die(mysql_error()); $options=""; while ($row=mysql_fetch_array($result)) { $id=$row["idProducts"]; $thing=$row["country"]; $options.="<OPTION VALUE=\"$id\">".$thing.'</option>'; } mysql_close(); ?> <SELECT id="countrySearch" NAME=countrySearch onchange="load('divtest', 'step2.search.php')";> <OPTION VALUE=0>Choose <?=$options?> </SELECT> <div id="divtest"> test </div> </body> step2.search.php consists of: <?php echo "I want it to store the users selection as a variable for php to use"; ?> The problem I have is I want to store what the user selects from the drop down box and use it in php to do a mysql query using the variable from the user select form to form the WHERE part of the mysql statement. Then use ajax to put new data in "divtest". How can I store the user selection into a variable then send it to be used in step2.search.php?

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  • Parse error in PHP login form

    - by user225269
    I'm trying to have a login form in php. But my current code doesnt work. Here is the form: <form name="form1" method="post" action="loginverify.php"> <td><font size="3">Username:</td> <td></td> <td><input type="text" name="uname" value="" maxlength="15"/><br/></td> <td><font size="3">Password:</td> <td></td> <td><input type="text" name="pword" value="" maxlength="15"/><br/></td> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login" /></td> </form> And the verify.php <?php session_start(); ?> <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="login"; $tbl="users"; $connection=mysql_connect($host, $username, $password) or die("cannot connect"); mysql_select_db($db_name, $connection) or die("cannot select db"); $user=$_POST['uname'] $pass=$_POST['pword'] $sql="SELECT Username, Password from users where Username='$user' and Password='$pass'"; $result=mysql_query[$sql]; $count=mysql_num_rows($result); if($count==1){ $SESSION['Username']=$user; echo"<a href='searchmain.php'> CONTINUE</a>"; } else{ echo"wrong username or password"; echo"<a href='loginform.php'>Back</a>"; } ?> Is there something wrong with my code. I get this parse error at line 15, which is this: $pass=$_POST['pword'] But when I try to remove it.It goes to line 16 or line 17 again. What do I do

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  • Page not redirecting properly(php)

    - by user225269
    I want to do the login page this way so that I won't be having trouble posting the username in the userpage. But everytime I try to access login.php. I get an error in firefox, that the page is not redirecting properly. What do I do? This works when I separate them into two. Into something like, login.php and verifylogin.php as the form action. But if I do it like this, I get redirection errors: <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="school"; $tbl_name="users"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $uname = mysql_real_escape_string($_POST['username']); $pword = mysql_real_escape_string($_POST['password']); $SQL = "SELECT * FROM users WHERE username = '$uname' AND password = '$pword'"; $result = mysql_query($SQL); $num_rows = mysql_num_rows($result); if ($result) { if ($num_rows > 0) { session_start(); $_SESSION['login'] = "1"; header ("Location: userpage.php"); } else { session_start(); $_SESSION['login'] = ""; header ("Location: login.php"); } } else { $errorMessage = "Error logging on"; } ?> <tr> <form name="form1" method="post" action="login.php"> <td> <table> <tr> <td><strong><font size="2">Login User</strong></td> </tr> <tr> <td width="30" height="35"><font size="2">Username:</td> <td width="30"><input name="username" type="text" id="username" maxlength="17"></td> </tr> <tr> <td width="30" height="35" ><font size="2">Password:</td> <td width="30"><input name="password" type="password" id="password" maxlength="17"></td> </tr> <td><td align="right" width="30"><input type="submit" name="Submit" value="Submit" /></td> <td><input type="reset" name="Reset" value="Reset"></td></td> </tr> </form> please help, thanks.

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  • iPhone: image in table cell - wrong position & not scaled correctly in iPhone 3.0

    - by Karsten Silz
    Hi, I have a custom table cell in an iPhone 3.x app to show basketball player data, including a picture. Here's my code from the table controller: UIImageView *theImage = (UIImageView *) [cell viewWithTag:0]; theImage.image = [manager getSmallImageForPlayer: data.number]; theImage.frame = CGRectMake(14, 0, 30, 44); theImage.clipsToBounds = YES; theImage.contentMode = UIViewContentModeScaleAspectFit; theImage.autoresizingMask = UIViewAutoresizingFlexibleHeight && UIViewAutoresizingFlexibleWidth; theImage.autoresizesSubviews = YES; Here's what it looks like in the iPhone SDK 3.0 simulator: Here's what it looks like in the iPhone SDK 3.1.3 simulator: So I have two problems: In both versions, the image view starts at position (0,0) in the table cell, even though I set the frame to start at (14,0). In the 3.0 simulator (and 3.0 device), the image is not shrunk down correctly, even though I set the image view content mode to "UIViewContentModeScaleAspectFit". But the same code works fine in the 3.1.3 simulator / device. Who can help me with either of these two problems?

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  • How can I use Facebook JAVA API in my application?

    - by prakash.panjwani
    Hello Friends, I have downloaded facebook-java-api-3.0.2-bin from http://code.google.com/p/facebook-java-api/ for connecting to face book.I want to use this api in my java application to connect Facebook.I am developing a desktop application for this purpose.I have created account on Face book and registered as a developer. Is it possible to connect Facebook from my java application? If yes please, can some one send me the example code for that and treat me as a New Bee in this facebook integration? Thanks in advance.

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  • Conversion to Dalvik format failed error for Android Grid View

    - by Bub
    Hey Everyone, I'm on the android bandwagon and started going through google's "view" tutorials. Here is what I'm using: Eclipse Galileo Android SDK 2.1 Java SDK 6.Something I think. Everything was hunky-dory until I hit the grid view tutorial. I got errors all over the place when I started editing the "HelloGridview.java" File. I thought I'd fix it by following through with the next part of the tutorial, creating the ImageAdapter class, but it created more. I realized alot of my issues could be resolved by importing widgets which were not mentioned in the tutorial (i.e. android.widget.GridView, .ImageView, .BaseAdapter etc.) However, after all the reconciliation suggested by eclipse the files were finally showing no errors. I go to run it as an android app and bam, "Your project contains error(s)." window comes up. There are no errors showing on the files I've created. I cleared the error log and shut down eclipse and started again the error log now reads: Conversion to Dalvik format failed with error 1. I'm a little lost at this point. I think I've included the required information. If you need to know more let me know. Any help is appreciated.

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  • How can I use offline access with the Facebook javascript SDK?

    - by Tony
    In the Facebook javascript api there is a login function in which you specify extended permissions: http://developers.facebook.com/docs/reference/javascript/FB.login One of these permissions is offline access. So I can save the facebook user's session key and assume it will not expire for a long time. The question I have is simple - how do I use the session key? I understand that the session key will last longer, but I don't understand how to use it in the Facebook API. For one of my products, a user must restart his/her browser and I would like to recognize them when they restart. The problem is that they are logged out of facebook, so they must login on my site again where I would rather just use offline access. Sample code would be great! Thanks

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  • List of files and libraries that Window SDK contains?

    - by AKN
    For developing programs for windows, we need windows SDK. I understand that this SDK is what helps to create windows and handle window events and all that. I suppose it also enables us to manipulate with files and registries. (Does the same SDK is the reason for thread creation and handling?) All that is fine. I would like to know what are the files and libraries that come as a part of this SDK. Also does it come when I install the OS or when I install editors like Visual studio? Sometimes I see links to windows SDK separately as such. Is it same as the one that I get when installing Visual Studio or has something more than that.

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  • Connect.registerUsers - Need helping creating array for accounts param

    - by mw_javaguy
    I keep getting the following error when I try to invoke the Facebook REST API Call: Connect.registerUsers Error Code: 100 - param accounts must be an array JSON based response (from Facebook): {"error_code":100,"error_msg":"param accounts must be an array.","request_args": [{"key":"accounts","value":"{email_hash:5232156322_55ddgvc3db5ddcf218049dd564da2x06}"}, {"key":"api_key","value":"23b2c4c6a23445fbffssf8aab96a5e5"}, {"key":"format","value":"JSON"},{"key":"method","value":"Connect.registerUsers"},{"key":"sig","value":"3sd54153a31382fa6e72eecf3c57d7c9"},{"key":"v","value":"1.0"}],"message":"Unknown exception","code":0} I set up the Java code to invoke the REST end point using HttpClient like this: String API_KEY = "23b2c4c6a23445fbffssf8aab96a5e5"; String toConnectRegisterUsersSignature = "accounts=" + "{email_hash:" + emailHash + "}" + "api_key=" + API_KEY + "format=JSON" + "method=Connect.registerUsers" + "v=1.0" + "0c786155bd3cxe8228d924542da5gf2"; String connectRegisterUsersSignature = SimpleMd5.MD5(toConnectRegisterUsersSignature); NameValuePair[] connectRegisterUsersParameters = { new NameValuePair("accounts", "{email_hash:" + emailHash + "}"), new NameValuePair("api_key", API_KEY), new NameValuePair("format", "JSON"), new NameValuePair("method", "Connect.registerUsers"), new NameValuePair("sig", connectRegisterUsersSignature), new NameValuePair("v", "1.0") }; Tried the following combinations and I still get the same error! Signature: "accounts=" + "[email_hash=" + emailHash + "]" new NameValuePair("accounts", "[email_hash=" + emailHash + "]") Signature: "accounts=" + "email_hash[" + emailHash + "]" new NameValuePair("accounts", "email_hash[" + emailHash + "]") Signature: "accounts=" + "email_hash(" + emailHash + ")" new NameValuePair("accounts", "email_hash(" + emailHash + ")") Signature: "accounts=" + "[email_hash=" + emailHash + "]" new NameValuePair("accounts", "[email_hash=" + emailHash + "]") Signature: "accounts=" + "email_hash=" + emailHash new NameValuePair("accounts", "email_hash=" + emailHash) Signature: "accounts=" + "[{email_hash:" + emailHash + "}]" new NameValuePair("accounts", "[{email_hash:" + emailHash + "}]"), Does anyone know how to construct this array that the response is requesting? Happy programming and thank you for taking the time to read this.

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  • Is there a way to reload the page after <fb:like> is clicked?

    - by joon
    Hi, I'm wondering about this: I have a simple facebook-connect app that will only show certain content after you login and liked a certain page. It works (huzzah!) but I want to make it more user friendly by making it refresh automatically after you pressed the like button. Here's some code: <?php if ($me) { $pageid = -----------; $uid = $me['id']; $likeID = $facebook->api( array( 'method' => 'fql.query', 'query' => 'SELECT target_id FROM connection WHERE source_id = ' . $uid . ' AND target_id = ' . $pageid ) ); if ( empty($likeID) ) { // Person is LOGGED IN, but has NOT LIKED echo '<script src="MY WEBPAGE"></script><fb:like href="MY WEBPAGE" layout="box_count" show_faces="false" width="450"></fb:like>'; } else { // Person is LOGGED IN, and has LIKED, score! echo 'Download link'; } } else { // Person is NOT LOGGED IN, so we know NOTHING echo '<script src="MY WEBPAGE"></script><fb:like href="MY WEBPAGE" layout="box_count" show_faces="false" width="450"></fb:like>'; } ?> Is there anything I can do to this code (maybe in the fb:like tag?) that makes it reload the page after a like? Thanks.

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  • What access token should i use?

    - by user548458
    I made a posting scores. It worked normaly sometimes. But, now I cant post any score. If I use user accessToken: string path = meID + "/scores"; var parameters = new Dictionary<string, object> (){ { "score", score.ToString () }, { "access_token", accessToken } }; facebook.post (path, parameters, ( error, obj ) => I get error: {"error":{"message":"(#15) This method must be called with an app access_token.", "type":"OAuthException", "code":15}} If I use an app access token: string path = meID + "/scores"; var parameters = new Dictionary<string, object> () { { "score", score.ToString () }, { "access_token", appAccessToken } }; facebook.post (path, parameters, ( error, obj ) => I get other error: {"error":{"message":"A user access token is required to request this resource.", "type":"OAuthException", "code":102}} Help me please, what am i doing wrong? PS: I worked well recently, but now - dont. Cant explain it...

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