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  • How do you submit a rails 3 form without refreshing the page?

    - by Anthony H
    I've seen this done using ajax & php, but not rails 3. I've tried using: <%= form_for(:technician, :url => {:controller => 'pos', :action => 'create_ticket'}, :remote => true) do |f| %> but the page still refreshes each time. I'm building a point of sale program, so I don't want the page to refresh. How do I send the form data to the controller to process and store in the database without refreshing?

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  • MVC Validator numberOfInvalids not working

    - by user965445
    I dynamically add some elements to a form so I know I need to re-parse the form. Even if I have old invalid elements they don't get identified in numberOfInvalids It always comes back = 0 even though the invalid fields are highlighted on the page. var form = $("#form"); //Form Savingform.submit(function (e) { e.preventDefault(); form.removeData("validator"); form.removeData("unobtrusiveValidation"); $.validator.unobtrusive.parse(form); var val = form.validate(); if (val.numberOfInvalids() == 0) { $.blockUI({ fadeIn: 1000 }); AjaxRequest({ data: $(this).serializeArray(), success: function (data, status, xhr) { alert('sucess save or submit, use "'); }, complete: function () { $.unblockUI(); } }); } });

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  • question about adding another column to a sql statement

    - by every_answer_gets_a_point
    i am starting with this table: SELECT [Lab Occurrence Form].[Practice Code], [Lab Occurrence Form].[1 0 Preanalytical (Before Testing)], Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) AS [CountOf1 0 Preanalytical (Before Testing)] FROM [Lab Occurrence Form] WHERE ((([Lab Occurrence Form].[Occurrence Date]) Between [Forms]![By Number]![Text4] And [Forms]![By Number]![Text2])) GROUP BY [Lab Occurrence Form].[Practice Code], [Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] HAVING ((([Lab Occurrence Form].[Practice Code])<>"") AND ((Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]))<>0)); it selects 3 columns but i need to aggregate the comments and put it in the fourth column where the first two values are the same

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  • How do submit an object to a struts2 action using jQuery?

    - by James Drinkard
    I have an object that I'm populating from a selection off a table row that a user selects. I have a jQuery function that captures the click event and a hidden form field populates an id I need. However, I'm not sure as to the proper way to send off that object to a struts2 action? I tried using this: $(function() { $('#tbl tr').click(function() { var id = $(this).closest('tr').find('input:hidden').val(); var page = "<s:url action='update/deleteInfo.action'/>?model.isDelete=true&model.info.id=id"; console.log(page); window.location.href=(page); }); }); The model object has an isDelete boolean variable and the model has a nested info object that has an id variable with getter/setters. However, when I send this across, the model object isn't populated with these entries. Is there a way to do this or a better way than the url tag?

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  • php - correct search expression for bbpress

    - by billn
    I have a very purdy styled search box in my wordpress install, and looking for continuity I want the same for my bbpress forum - currently I'm failing. For WP I have: <div id="search"> <form action="<?php bloginfo('home') ?>" method="get"> <div class="hiddenFields"></div> <p><input name="s" id="s" maxlength="100" size="18" /><input class="submit" id="submit-button" type="submit" value="submit" /></p></form> </div> For bbPress The form 'method="get"' gets kicked out and of-course I need another expression. bbpress generally seems to use: <div class="search"><?php search_form(); ?></div> This wrecks everything - I get no styling attributes at all other than position... I can make it look fine (and consistent) with by removing the - but then it's obviously just a dummy with no search - any ideas to fix the latter? Thanks <div id="search"> <div class="hiddenFields"></div> <p><input name="s" id="s" maxlength="100" size="18" /><input class="submit" id="submit-button" type="submit" value="submit" /></p> </div>

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  • Has form post behavior changed in modern browsers? (or How are double clicks handled by the browser)

    - by Alex Czarto
    Background: We are in the process of writing a registration/payment page, and our philosophy was to code all validation and error checking on the server side first, and then add client side validation as a second step (un-obstructive jQuery). We wanted to disable double clicks server side, so we wrote some locking, thread-safe code to handle simultaneous posts/race conditions. When we tried to test this, we realized that we could not cause a simultaneous post or race condition to occur. I thought that (in older browsers anyway) double clicking a submit button worked as follows: User double clicks submit button. Browser sends a post on the first click On the second click, browser cancels/ignores initial post, and initiates a second post (before the first post has returned with a response). Browser waits for second post to return, ignoring initial post response. I thought that from the server side it looked like this: Server gets two simultaneous post requests, executes and responds to them both (unaware that no one is listening to the first response). From our testing (FireFox 3.0, IE 8.0) this is what actually happens: User double clicks submit button Browser sends a post for the first click Browser queues up second click, but waits for the response from the first click. Response returns from first click (response is ignored?). Browser sends a post for the second click. So from a server side: Server receives a single post which it executes and responds to. Then, server receives a second request wich it executes and responds to. My question is, has this always worked this way (and I'm losing my mind)? Or is this a new feature in modern browsers that prevents simultaneous posts to be sent to the server? It seems that for server side double click prevention, we don't have to worry about simultaneous posts or race conditions. Only need to worry about queued up posts. Thanks in advance for any feedback / comments. Alex

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  • jQuery class selector oddness

    - by x3sphere
    I'm using jQuery to change the background image of a button depending on the class associated with it on hover. It only works if I put the hover statements in separate functions, however. Why is this? Here's the NON working code, always evaluates to the .submit hover statement, even when that class is removed via the keyup event. $(function() { { $('.submit-getinfo').hover(function () { $(this).css( {backgroundPosition: "right bottom"} ); }, function() { $(this).css( {backgroundPosition: "right top"} ); //$(this).removeClass('submithover'); }); $('.submit').hover(function () { $(this).css( {backgroundPosition: "left bottom"} ); }, function() { $(this).css( {backgroundPosition: "left top"} ); //$(this).removeClass('submithover'); }); }}); Working code: $(function() { { $('.submit').hover(function () { $(this).css( {backgroundPosition: "left bottom"} ); }, function() { $(this).css( {backgroundPosition: "left top"} ); //$(this).removeClass('submithover'); }); }}); $('#test').bind('keyup', function() { if (url == 'devel') { $("#submit").addClass("submit-getinfo").removeClass("submit"); $('.submit-getinfo').hover(function () { $(this).css( {backgroundPosition: "right bottom"} ); }, function() { $(this).css( {backgroundPosition: "right top"} ); //$(this).removeClass('submithover'); }); } } ); I just fail to see why I have to put the hover statements in separate functions, instead of sticking both in the main DOM.

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  • How to animate button text? (loading type of animation) - jquery?

    - by AL
    I got something that I want to do and want to see what you guys think and how can it be implemented. I got a form in a page and the form will submit to itself to perform some process (run functions) in a class. Upon clicking the submit button, I want to animate the button text to “SUBMIT .” -> “SUBMIT ..” -> “SUBMIT …” -> “SUBMIT ….” -> “SUBMIT ….” and then back again. Sort of “animate” the button text. Once the whole process is done, the button text will goes back to be “SUBMIT” text again. Please note that I am not looking for image button solution, meaning that I do not want to implement gif animated button image. Anyone done this before or know how this can be done? I have google but seems nothing of this kind to be found. Thanks! AL

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  • why my form is doing postback when i am calling asynchronously?

    - by Abu Hamzah
    i am using simple asp.net webpage with few fields on it and when the user click on submit button i am calling asynchronously and posting the data. BUT, my whole page is posting back and i dont even see the message that i am trying to display if my data got posted succfully. here is my page. Requester Page Name: <asp:Label runat="server" ID='Label4' >Host Name:</asp:Label> <asp:TextBox ID="txtHost" runat='server'></asp:TextBox> <asp:Label runat="server" ID='Label2' >Start Date:</asp:Label> <asp:TextBox ID="txtStartDate" runat='server' ></asp:TextBox> <asp:Label runat="server" ID='Label6' >End Date:</asp:Label> <asp:TextBox ID="txtEndDate" runat='server' ></asp:TextBox> <ul> <li> <button id="btnCancel" name="btnCancel" type="button"> Cancel</button></li> <li> <button id="btnReset" name="btnReset" type="reset"> Reset</button></li> <li> <button id="btnSubmit" name="btnSubmit" type="submit"> Submit</button></li> </ul> </p> </form> </div> //Store new Contract Request Methods function processCompletedContactStore(response) { if (!response) { showErrorMsg('No Contacts Returned'); return; } else { if (response.Message == 'update') { $("#status").fadeTo(500, 1, function() { $(this).html("Updated successfully!").fadeTo(500, 150); }) } } }

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  • .NET MVC Ajax Form - How do you hide it?

    - by Tommy
    Ok, everything is 'functionally' working with what I am attempting to accomplish and once again, I am sure this is something dumb, but I cannot figure out how to do this one thing. I have an edit form for an entity, lets say a car. This 'car' can have 0 - many passengers. So on my edit form, I have all the fields for the car, then a list view showing each passenger (partial). I also have a 'add new passenger' button that will render a new partial view that allows you to enter a passenger. This has a cancel link and an add button to submit an Ajax form. When you add a passenger, the passenger is automatically added to the list, but I need the enter passenger form to go away. I have tried using the onSuccess and onComplete functions to hide the div that the form is in, but both render just the partial view HTML elements (white screen, text) and not the partialView in the context of the entire page. Sources: 1) Main Edit View <script type="text/javascript"> Function hideForm(){ document.getElementById('newPassenger').style.display = 'none'; } </script> <h2>Edit</h2> <%-- The following line works around an ASP.NET compiler warning --%> <%= ""%> <%Html.RenderPartial("EditCar", Model)%> <h2>Passengers for this car</h2> <%=Ajax.ActionLink("Add New Passenger", "AddPassenger", New With {.ID = Model.carID}, New AjaxOptions With {.UpdateTargetId = "newPassenger", .InsertionMode = InsertionMode.Replace})%> <div id="newPassenger"></div> <div id="passengerList"> <%Html.RenderPartial("passengerList", Model.Passengers)%> </div> <div> <%= Html.ActionLink("Back to List", "Index") %> </div> 2) AddPassenger View. The cancel link below is an action that returns nothing, thus removing the information in the div. <% Using Ajax.BeginForm("AddPassengerToCar", New With {.id = ViewData("carID")}, New AjaxOptions With {.UpdateTargetId = "passengerList", .InsertionMode = InsertionMode.Replace})%> <%=Html.DropDownList("Passengers")%> <input type="submit" value="Add" /> <%=Ajax.ActionLink("Cancel", "CancelAddControl", _ New AjaxOptions With {.UpdateTargetId = "newPassenger", .InsertionMode = InsertionMode.Replace})%><% end using %>

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  • Reading POST data from html form sent to serversocket.

    - by user32167
    i try to write simplest possible server app in Java, displaying html form with textarea input, which after submitting gives me possibility to parse xml typed in that textarea. For now i build simple serversocket based server like that: import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.PrintWriter; import java.net.ServerSocket; import java.net.Socket; public class WebServer { protected void start() { ServerSocket s; String gets = ""; System.out.println("Start on port 80"); try { // create the main server socket s = new ServerSocket(80); } catch (Exception e) { System.out.println("Error: " + e); return; } System.out.println("Waiting for connection"); for (;;) { try { // wait for a connection Socket remote = s.accept(); // remote is now the connected socket System.out.println("Connection, sending data."); BufferedReader in = new BufferedReader(new InputStreamReader( remote.getInputStream())); PrintWriter out = new PrintWriter(remote.getOutputStream()); String str = "."; while (!str.equals("")) { str = in.readLine(); if (str.contains("GET")){ gets = str; break; } } out.println("HTTP/1.0 200 OK"); out.println("Content-Type: text/html"); out.println(""); // Send the HTML page String method = "get"; out.print("<html><form method="+method+">"); out.print("<textarea name=we></textarea></br>"); out.print("<input type=text name=a><input type=submit></form></html>"); out.println(gets); out.flush(); remote.close(); } catch (Exception e) { System.out.println("Error: " + e); } } } public static void main(String args[]) { WebServer ws = new WebServer(); ws.start(); } } After form (textarea with xml and one additional text input) is submitted in 'gets' String-type variable I have Urlencoded values of my variables (also displayed on the screen, it looks like that: gets = GET /?we=%3Cnetwork+ip_addr%3D%2210.0.0.0%2F8%22+save_ip%3D%22true%22%3E%0D%0A%3Csubnet+interf_used%3D%22200%22+name%3D%22lan1%22+%2F%3E%0D%0A%3Csubnet+interf_used%3D%22254%22+name%3D%22lan2%22+%2F%3E%0D%0A%3C%2Fnetwork%3E&a=fooBar HTTP/1.1 What can i do to change GET to POST method (if i simply change it in form and than put " if (str.contains("POST")){" it gives me string like gets = POST / HTTP/1.1 with no variables. And after that, how i can use xml from my textarea field (called 'we')?

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  • Why the parent page get refreshed when I click the link to open thickbox-styled form?

    - by user333205
    Hi, all: I'm using Thickbox 3.1 to show signup form. The form content comes from jquery ajax post. The jquery lib is of version 1.4.2. I placed a "signup" link into a div area, which is a part of my other large pages, and the whole content of that div area is ajax+posted from my server. To make thickbox can work in my above arangement, I have modified the thickbox code a little like that: //add thickbox to href & area elements that have a class of .thickbox function tb_init(domChunk){ $(domChunk).live('click', function(){ var t = this.title || this.name || null; var a = this.href || this.alt; var g = this.rel || false; tb_show(t,a,g); this.blur(); return false; });} This modification is the only change against the original version. Beacause the "signup" link is placed in ajaxed content, so I Use live instead of binding the click event directly. When I tested on my pc, the thickbox works well. I can see the signup form quickly, without feeling the content of the parent page(here, is the other large pages) get refreshed. But after transmiting my site files into VHost, when I click the "signup" link, the signup form get presented very slowly. The large pages get refreshed evidently, because the borwser(ie6) are reloading images from server incessantly. These images are set as background images in CSS files. I think that's because the slow connection of network. But why the parent pages get refreshed? and why the browser reloads those images one more time? Havn't those images been placed in local computer's disk? Is there one way to stop that reloadding? Because the signup form can't get displayed sometimes due to slow connection of network. To verified the question, you can access http://www.juliantec.info/track-the-source.html and click the second link in left grey area, that is the "signup" link mentioned above. Thinks!

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  • How do you select form elements in JQuery based upon an html table?

    - by Swoop
    I am working on some ASP.NET web forms which involves some dynamic generation, and I need to add some onClick helpers on the client side. I have a basic outline of something working, except for one huge problem. There are multiple HTML tables, each generated by a different ASP.NET web control. Each table can contain overlapping field names, which is causing a problem with my JQuery click event handlers. The click event handler is linking to unintended form fields in addition to the intended form field. I have provided a simplified sample version of the code below. This code is trying to set the value of textbox box1 when a particular radiobutton is selected in the table with id=thing1. Obviously, the jquery code will be triggered for the form fields in both tables. The tables are dynamically added to the webpage based upon different conditions. It is possible that no tables will be loaded, only 1 table, or both tables might load. In the future, other tables could be added. Each table comes from a different .net web control. Other than renaming the form fields to make sure they are unique across all user controls, is there a way to have JQuery act only on the intended form fields? In other words, could the table ID be incorporated into the JQuery code in a manner that does not become a nightmare to maintain later? <script> $(document).ready(function() { $("[id$=radio1_0]").click(function() { $("[id$=box1]").attr("value", ""); }); $("[id$=radio1_1]").click(function() { $("[id$=box1]").attr("value", "N/A"); }); </script> <table id="thing1"> <tr><td> <radiobuttonlist id="radio1"/> <listitem>yes</listitem> <listitem>no</listitem> </td></tr> <tr><td> <textbox id="box1"/> </td></tr> </table> <table id="thing2"> <tr><td> <radiobuttonlist id="radio1"/> <listitem>yes</listitem> <listitem>no</listitem> </td></tr> <tr><td> <textbox id="box1"/> </tr></td> </table>

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  • [java] reading POST data from html form sent to serversocket.

    - by user32167
    i try to write simplest possible server app in Java, displaying html form with textarea input, which after submitting gives me possibility to parse xml typed in thet textarea. For now i build simple serversocket based server like that: import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.PrintWriter; import java.net.ServerSocket; import java.net.Socket; public class WebServer { protected void start() { ServerSocket s; String gets = ""; System.out.println("Start on port 80"); try { // create the main server socket s = new ServerSocket(80); } catch (Exception e) { System.out.println("Error: " + e); return; } System.out.println("Waiting for connection"); for (;;) { try { // wait for a connection Socket remote = s.accept(); // remote is now the connected socket System.out.println("Connection, sending data."); BufferedReader in = new BufferedReader(new InputStreamReader( remote.getInputStream())); PrintWriter out = new PrintWriter(remote.getOutputStream()); String str = "."; while (!str.equals("")) { str = in.readLine(); if (str.contains("GET")){ gets = str; break; } } out.println("HTTP/1.0 200 OK"); out.println("Content-Type: text/html"); out.println(""); // Send the HTML page String method = "get"; out.print("<html><form method="+method+">"); out.print("<textarea name=we></textarea></br>"); out.print("<input type=text name=a><input type=submit></form></html>"); out.println(gets); out.flush(); remote.close(); } catch (Exception e) { System.out.println("Error: " + e); } } } public static void main(String args[]) { WebServer ws = new WebServer(); ws.start(); } } After form (textarea with xml and one additional text input) is submitted in 'gets' String-type variable I have Urlencoded values of my variables (also displayed on the screen, it looks like that: gets = GET /?we=%3Cnetwork+ip_addr%3D%2210.0.0.0%2F8%22+save_ip%3D%22true%22%3E%0D%0A%3Csubnet+interf_used%3D%22200%22+name%3D%22lan1%22+%2F%3E%0D%0A%3Csubnet+interf_used%3D%22254%22+name%3D%22lan2%22+%2F%3E%0D%0A%3C%2Fnetwork%3E&a=fooBar HTTP/1.1 What can i do to change GET to POST method (if i simply change it in form and than put " if (str.contains("GET")){" it gives me string like gets = POST / HTTP/1.1 with no variables. And after that, how i can use xml from my textarea field (called 'we')?

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  • How do I use jquery validate remote validation on a field that depends on another field in the form?

    - by Kevin J
    I have a form in which I am using remote validation to check if an email address already exists in the database. However, the catch is that on this form, the user can select between several different "groups", and each group has its own distinct set of email addresses (thus the same email can exist once in each group). The group selection is a dropdown on the form, and the email address is an input field with remote validation. I have a couple issues. First, I have set up my remote rule like this: remote: { url: 'remote_script.php', data: { group_id: $('select.group_id').val() } } However, this seems to statically set the group_id parameter to whatever the first value in the select is. Meaning, if I change the select, then trigger the remote validation again, the group_id parameter does not change First, how can I make this parameter dynamic, depending on the value of a select in the form? Secondly, how do I manually trigger the remote validation on the email address field? When the group_id select is changed, I want to re-trigger the remote validation on the email address field (without changing the value of the field). I tried using $(selector).validate().element('.email_addr') But this appears to only trigger the standard validation (required, email), and not the remote call.

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  • Control 'ctl00_TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server.

    - by Hiru
    When a form with a run at server is added there will be two forms with runat server and another error occurs. Can some one give me an idea. Thankx in advance. The details of the error are as follows. Control 'ctl00_TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.Web.HttpException: Control 'ctl00_TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server. Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. Stack Trace: [HttpException (0x80004005): Control 'ctl00_TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server.] System.Web.UI.Page.VerifyRenderingInServerForm(Control control) +2052287 System.Web.UI.WebControls.TextBox.AddAttributesToRender(HtmlTextWriter writer) +49 System.Web.UI.WebControls.WebControl.RenderBeginTag(HtmlTextWriter writer) +17 System.Web.UI.WebControls.TextBox.Render(HtmlTextWriter writer) +17 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +25 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +121 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +22 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +199 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +20 System.Web.UI.Control.Render(HtmlTextWriter writer) +7 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +25 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +121 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +22 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +199 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +20 System.Web.UI.Page.Render(HtmlTextWriter writer) +26 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +25 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +121 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +22 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +2558 Version Information: Microsoft .NET Framework Version:2.0.50727.1873; ASP.NET Version:2.0.50727.1433

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  • [C#][XNA 3.1] How can I host two different XNA windows inside one Windows Form?

    - by secutos
    I am making a Map Editor for a 2D tile-based game. I would like to host two XNA controls inside the Windows Form - the first to render the map; the second to render the tileset. I used the code here to make the XNA control host inside the Windows Form. This all works very well - as long as there is only one XNA control inside the Windows Form. But I need two - one for the map; the second for the tileset. How can I run two XNA controls inside the Windows Form? While googling, I came across the terms "swap chain" and "multiple viewports", but I can't understand them and would appreciate support. Just as a side note, I know the XNA control example was designed so that even if you ran 100 XNA controls, they would all share the same GraphicsDevice - essentially, all 100 XNA controls would share the same screen. I tried modifying the code to instantiate a new GraphicsDevice for each XNA control, but the rest of the code doesn't work. The code is a bit long to post, so I won't post it unless someone needs it to be able to help me. Thanks in advance.

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  • KeyUp processed for wrong control

    - by Mikael
    I have made a simple test application for the issue, two winforms each containing a button. The button on the first form opens the other form when clicked. It also subscribes to keyup events. The second form has its button set as "AcceptButton" and in the Clicked event we sleep for 1s and then set DialogResult to true (the sleep is to simulate some processing done) When enter is used to close this second form the KeyUp event of the button on the first form is triggered, even though the key was released well before the second had passed so the second form was still shown and focused. If any key other then enter is pressed in the second form the event is not triggered for the button on the first form. First form: public Form1() { InitializeComponent(); buttonForm2.KeyUp += new KeyEventHandler(cntKeyUp); } void cntKeyUp(object sender, KeyEventArgs e) { MessageBox.Show(e.KeyCode.ToString()); } private void buttonForm2_Click(object sender, EventArgs e) { using (Form2 f = new Form2()) { f.ShowDialog(); } } Second form: private void button1_Click(object sender, EventArgs e) { Thread.Sleep(1000); this.DialogResult = DialogResult.OK; } Does anyone know why the event is triggered for the button on the non active form and what can be done to stop this from happening?

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  • Problem with multiple forms on one page

    - by Jon
    I have two forms on a web page. The first is not an actual form since this is a .NET based site. So instead I have the standard input fields, along with asp:Button PostBackURL="http:/www...". One of the fields is "email". That works fine. Then I have an XSLT file with another form, and am using Javascript (via this.form.action, .method, etc) to post that form. Besides that it has the same fields as the form above. The problem is that when someone submits the second form, the script at the PostBackURL returns an error because the "email" field appears empty. So it seems as though the form is submitting the "email" field form the top form instead of the current one. I thought maybe the wrong form is being submitted, but if I remove the "email" field from the top form, and then submit the bottom one, it works fine. Any ideas on how to fix this? Thanks.

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  • How do I insert an input's value into a separate form?

    - by ryan
    I'm making a tool for my university that allows students to create a list of classes by doing the following: Searching by course title for their course via an autocomplete input field. Adding that course to a separate form that upon being submitted creates a course list. I am trying to link the autocomplete and the course list form with an 'add to course list' button that inserts a hidden input field into the course list form which can subsequently be submitted by a 'create course list' button. My question is this: How do I take the value of the autocomplete input and insert it into the course list form without using AJAX? So far I have something like the following: <%= text_field_with_auto_complete :course, :title, :size => 40 %> <%= link_to_function "Add to Course List" do |page| page.insert_html :top, :course_list, hidden_field(:courses, :course, {:value => "$('course_title').value"}) %> <% form_for(@course_list) do |f|%> <div id="course_list">Insert selected courses here.</div> <% end %>

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  • CakePHP 1.26: Bug in 'Security' component?

    - by Steve
    Okay, for those of you who may have read this earlier, I've done a little research and completely revamped my question. I've been having a problem where my form requests get blackholed by the Security component, although everything works fine when the Security component is disabled. I've traced it down to a single line in a form: <?php echo $form->create('Audition');?> <fieldset> <legend><?php __('Edit Audition');?></legend> <?php echo $form->input('ensemble'); echo $form->input('position'); echo $form->input('aud_date'); // The following line works fine... echo $form->input('owner'); // ...but the following line blackholes when Security included // and the form is submitted: // echo $form->input('owner', array('disabled'=>'disabled'); ?> </fieldset> <?php echo $form->end('Submit');?> (I've commented out the offending line for clarity) I think I'm following the rules by using the form helper; as far as I can tell, this is a bug in the Security component, but I'm too much of a CakePHP n00b to know for sure. I'd love to get some feedback, and if it's a real bug, I'll submit it to the CakePHP team. I'd also love to know if I'm just being dumb and missing something obvious here.

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  • Submitting a URL into a Form without "http://", with "www.", or with neither

    - by John
    (EDITED) Hello, In the form below, the filed for <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> fine when a URL is submitted that has a "http://" at the beginning of it. However, it doesn't work if a URL is submitted with only a "www." in front of it, or with neither a "http://" nor a "www." How can I make it work in all if the submitted URL has any or none of the following at the beginning of it: http:// www. http://www. Thanks in advance, John Form: echo '<div class="submittitle">Submit an item.</div>'; echo '<form action="http://www...com/.../submit2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <div class="submissiontitle"><label for="title">Story Title:</label></div> <div class="submissionfield"><input name="title" type="title" id="title" maxlength="1000"></div> <div class="urltitle"><label for="url">Link:</label></div> <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> <div class="submissionbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; submit2.php: <?php if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../submit2.php');} require_once "header.php"; if (isLoggedIn() == true) { $remove_array = array('http://www.', 'http://', 'https://', 'https://www.', 'www.'); $cleanurl = str_replace($remove_array, "", $_POST['url']); $cleanurl = strtolower($cleanurl); $cleanurl = preg_replace('/\/$/','',$cleanurl); $cleanurl = stripslashes($cleanurl); $title = $_POST['title']; $uid = $_POST['uid']; $title = mysql_real_escape_string($title); $title = stripslashes($title); $cleanurl = mysql_real_escape_string($cleanurl); $site1 = 'http://' . $cleanurl; $displayurl = parse_url($site1, PHP_URL_HOST); function isURL($url1 = NULL) { if($url1==NULL) return false; $protocol = '(http://|https://)'; $allowed = '[-a-z0-9]{1,63}'; $regex = "^". $protocol . // must include the protocol '(' . $allowed . '\.)'. // 1 or several sub domains with a max of 63 chars '[a-z]' . '{2,6}'; // followed by a TLD if(eregi($regex, $url1)==true) return true; else return false; } if(isURL($site1)==true) mysql_query("INSERT INTO submission VALUES (NULL, '$uid', '$title', '$cleanurl', '$displayurl', NULL)"); else echo "<p class=\"topicu\">Not a valid URL.</p>\n"; } else { show_loginform(); } if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } require_once "footer.php"; ?>

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  • What's the best way to format this simple HTML form using CSS?

    - by GregH
    I have have a simple HTML form with say four input widgets (see below)...two lines with two widgets on each line. However, when this renders it is pretty ugly. I want the whole form to be indented from the edge of the left page say 40px and I want the left edge of the widgets to line up with each other and the right edge of the labels to line up. I also want to be able to specify a minimum distance between the right edge of the first widget and the label of the widget next to it. How would I do this using CSS? Basically so it looks something like: Name: _____________ Common Names: _____________ Version: ____________ Status: ____________ See current un-formatted HTML below: <form name="detailData"> <div id="dataEntryForm"> <label> Name: <input type="text" class="input_text" name="ddName"/> Common Names: <input type="text" class="input_text" name="ddCommonNames"><P> Version: <input type="text" class="input_text" name="ddVer"/> Status: <select name="ddStatus"><option value="A" selected="selected">Active</option><option value="P">Planned</option><option value="D">Deprecated</option> </label> </div> </form>

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  • I am confused about how to use @SessionAttributes

    - by yusaku
    I am trying to understand architecture of Spring MVC. However, I am completely confused by behavior of @SessionAttributes. Please look at SampleController below , it is handling post method by SuperForm class. In fact, just field of SuperForm class is only binding as I expected. However, After I put @SessionAttributes in Controller, handling method is binding as SubAForm. Can anybody explain me what happened in this binding. ------------------------------------------------------- @Controller @SessionAttributes("form") @RequestMapping(value = "/sample") public class SampleController { @RequestMapping(method = RequestMethod.GET) public String getCreateForm(Model model) { model.addAttribute("form", new SubAForm()); return "sample/input"; } @RequestMapping(method = RequestMethod.POST) public String register(@ModelAttribute("form") SuperForm form, Model model) { return "sample/input"; } } ------------------------------------------------------- public class SuperForm { private Long superId; public Long getSuperId() { return superId; } public void setSuperId(Long superId) { this.superId = superId; } } ------------------------------------------------------- public class SubAForm extends SuperForm { private Long subAId; public Long getSubAId() { return subAId; } public void setSubAId(Long subAId) { this.subAId = subAId; } } ------------------------------------------------------- <form:form modelAttribute="form" method="post"> <fieldset> <legend>SUPER FIELD</legend> <p> SUPER ID:<form:input path="superId" /> </p> </fieldset> <fieldset> <legend>SUB A FIELD</legend> <p> SUB A ID:<form:input path="subAId" /> </p> </fieldset> <p> <input type="submit" value="register" /> </p> </form:form>

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  • WindowsFormsApplicationBase SplashScreen makes login form ignore keypresses until I click on it - how to debug?

    - by Tom Bushell
    My WinForms app has a simple modal login form, invoked at startup via ShowDialog(). When I run from inside Visual Studio, everything works fine. I can just type in my User ID, hit the Enter key, and get logged in. But when I run a release build directly, everything looks normal (the login form is active, there's a blinking cursor in the User ID MaskedEditBox), but all keypresses are ignored until I click somewhere on the login form. Very annoying if you are used to doing everything from the keyboard. I've tried to trace through the event handlers, and to set the focus directly with code, to no avail. Any suggestions how to debug this (outside of Visual Studio), or failing that - a possible workaround? Edit Here's the calling code, in my Main Form: private void OfeMainForm_Shown(object sender, EventArgs e) { OperatorLogon(); } private void OperatorLogon() { // Modal dialogs should be in a "using" block for proper disposal using (var logonForm = new C21CfrLogOnForm()) { var dr = logonForm.ShowDialog(this); if (dr == DialogResult.OK) SaveOperatorId(logonForm.OperatorId); else Application.Exit(); } } Edit 2 Didn't think this was relevant, but I'm using Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase for it's splash screen and SingleInstanceController support. I just commented out the splash screen code, and the problem has disappeared. So that's opened up a whole new line of inquiry... Edit 3 Changed title to reflect better understanding of the problem

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