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• JAVA - Download PDF file from Webserver

  - by Augusto Picciani

  I need to download a pdf file from a webserver to my pc and save it locally. I used Httpclient to connect to webserver and get the content body: HttpEntity entity=response.getEntity(); InputStream in=entity.getContent(); String stream = CharStreams.toString(new InputStreamReader(in)); int size=stream.length(); System.out.println("stringa html page LENGTH:"+stream.length()); System.out.println(stream); SaveToFile(stream); Then i save content in a file: //check CRLF (i don't know if i need to to this) String[] fix=stream.split("\r\n"); File file=new File("C:\\Users\\augusto\\Desktop\\progetti web\\test\\test2.pdf"); PrintWriter out = new PrintWriter(new FileWriter(file)); for (int i = 0; i < fix.length; i++) { out.print(fix[i]); out.print("\n"); } out.close(); I also tried to save a String content to file directly: OutputStream out=new FileOutputStream("pathPdfFile"); out.write(stream.getBytes()); out.close(); But the result is always the same: I can open pdf file but i can see white pages only. Does the mistake is around pdf stream and endstream charset encoding? Does pdf content between stream and endStream need to be manipulate in some others way?

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• Threads in Java

  - by owca

  I've created simple program to test Threads in Java. I'd like it to print me numbers infinitely, like 123123123123123. Dunno why, but currently it stops after one cycle finishing 213 only. Anyone knows why ? public class Main { int number; public Main(int number){ } public static void main(String[] args) { new Infinite(2).start(); new Infinite(1).start(); new Infinite(3).start(); } } class Infinite extends Thread { static int which=1; static int order=1; int id; int number; Object console = new Object(); public Infinite(int number){ id = which; which++; this.number = number; } @Override public void run(){ while(1==1){ synchronized(console){ if(order == id){ System.out.print(number); order++; if(order >= which){ order = 1; } try{ console.notifyAll(); console.wait(); } catch(Exception e) {} } else { try{ console.notifyAll(); console.wait(); } catch(Exception e) {} } } try{Thread.sleep(0);} catch(Exception e) {} } } }

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• What is the scope of TRANSACTION in Sql server

  - by Shantanu Gupta

  I was creating a stored procedure and i got stuck in the writing methodology of me and my collegue. I am using SQL Server 2005 I was writing Stored procedure like this BEGIN TRAN BEGIN TRY INSERT INTO Tags.tblTopic (Topic, TopicCode, Description) VALUES(@Topic, @TopicCode, @Description) INSERT INTO Tags.tblSubjectTopic (SubjectId, TopicId) VALUES(@SubjectId, @@IDENTITY) COMMIT TRAN END TRY BEGIN CATCH DECLARE @Error VARCHAR(1000) SET @Error= 'ERROR NO : '+ERROR_NUMBER() + ', LINE NO : '+ ERROR_LINE() + ', ERROR MESSAGE : '+ERROR_MESSAGE() PRINT @Error ROLLBACK TRAN END CATCH And my collegue was writing it like the below one BEGIN TRY BEGIN TRAN INSERT INTO Tags.tblTopic (Topic, TopicCode, Description) VALUES(@Topic, @TopicCode, @Description) INSERT INTO Tags.tblSubjectTopic (SubjectId, TopicId) VALUES(@SubjectId, @@IDENTITY) COMMIT TRAN END TRY BEGIN CATCH DECLARE @Error VARCHAR(1000) SET @Error= 'ERROR NO : '+ERROR_NUMBER() + ', LINE NO : '+ ERROR_LINE() + ', ERROR MESSAGE : '+ERROR_MESSAGE() PRINT @Error ROLLBACK TRAN END CATCH Here the only difference that you will find is the position of writing Begin TRAN. According to me the methodology of my collegue should not work when an exception occurs i.e. Rollback should not get executed because TRAN does'nt have scope. But when i tried to run both the code, both was working in the same way. I am confused to know how does TRANSACTION works. Is it scope free or what ?

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• Python to C# with openSSL requirement

  - by fonix232

  Hey there again! Today I ran into a problem when I was making a new theme creator for chrome. As you may know, Chrome uses a "new" file format, called CRX, to manage it's plugins and themes. It is a basic zip file, but a bit modified: "Cr24" + derkey + signature + zipFile And here comes the problem. There are only two CRX creators, written in Ruby or Python. I don't know neither language too much (had some basic experience in Python though, but mostly with PyS60), so I would like to ask you to help me convert this python app to a C# class. Also, here is the source of crxmake.py: #!/usr/bin/python # Cribbed from http://github.com/Constellation/crxmake/blob/master/lib/crxmake.rb # and http://src.chromium.org/viewvc/chrome/trunk/src/chrome/tools/extensions/chromium_extension.py?revision=14872&content-type=text/plain&pathrev=14872 # from: http://grack.com/blog/2009/11/09/packing-chrome-extensions-in-python/ import sys from array import * from subprocess import * import os import tempfile def main(argv): arg0,dir,key,output = argv # zip up the directory input = dir + ".zip" if not os.path.exists(input): os.system("cd %(dir)s; zip -r ../%(input)s . -x '.svn/*'" % locals()) else: print "'%s' already exists using it" % input # Sign the zip file with the private key in PEM format signature = Popen(["openssl", "sha1", "-sign", key, input], stdout=PIPE).stdout.read(); # Convert the PEM key to DER (and extract the public form) for inclusion in the CRX header derkey = Popen(["openssl", "rsa", "-pubout", "-inform", "PEM", "-outform", "DER", "-in", key], stdout=PIPE).stdout.read(); out=open(output, "wb"); out.write("Cr24") # Extension file magic number header = array("l"); header.append(2); # Version 2 header.append(len(derkey)); header.append(len(signature)); header.tofile(out); out.write(derkey) out.write(signature) out.write(open(input).read()) os.unlink(input) print "Done." if __name__ == '__main__': main(sys.argv) Please could you help me?

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• Why two subprocesses created by Java behave differently?

  - by Lily

  I use Java Runtime.getRuntime().exec(command) to create a subprocess and print its pid as follows: public static void main(String[] args) { Process p2; try { p2 = Runtime.getRuntime().exec(cmd); Field f2 = p2.getClass().getDeclaredField("pid"); f2.setAccessible(true); System.out.println( f2.get( p2 ) ); } catch (Exception ie) { System.out.println("Yikes, you are not supposed to be here"); } } I tried both C++ executable and Java executable (.jar file). Both executables will continuously print out "Hello World" to stdout. When cmd is the C++ executable, the pid is printed out to console but the subprocess gets killed as soon as main() returns. However, when I call the .jar executable in cmd, the subprocess does not get killed, which is the desired behavior. I don't understand why same Java code, with different executables can behave so differently. How should I modify my code so that I could have persistent subprocesses in Java. Newbie in this field. Any suggestion is welcomed. Lily

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• Windows cmd encoding change causes Python crash.

  - by Alex

  First I chage Windows CMD encoding to utf-8 and run Python interpreter: chcp 65001 python Then I try to print a unicode sting inside it and when i do this Python crashes in a peculiar way (I just get a cmd prompt in the same window). >>> import sys >>> print u'ëèæîð'.encode(sys.stdin.encoding) Any ideas why it happens and how to make it work? UPD: sys.stdin.encoding returns 'cp65001' UPD2: It just came to me that the issue might be connected with the fact that utf-8 uses multi-byte character set (kcwu made a good point on that). I tried running the whole example with 'windows-1250' and got 'ëeaî?'. Windows-1250 uses single-character set so it worked for those characters it understands. However I still have no idea how to make 'utf-8' work here. UPD3: Oh, I found out it is a known Python bug. I guess what happens is that Python copies the cmd encoding as 'cp65001 to sys.stdin.encoding and tries to apply it to all the input. Since it fails to understand 'cp65001' it crushes on any input that contains non-ascii characters.

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• Increment part of a string in Ruby

  - by Rik

  I have a method in a Ruby script that is attempting to rename files before they are saved. It looks like this: def increment (path) if path[-3,2] == "_#" print " Incremented file with that name already exists, renaming\n" count = path[-1].chr.to_i + 1 return path.chop! << count.to_s else print " A file with that name already exists, renaming\n" return path << "_#1" end end Say you have 3 files with the same name being saved to a directory, we'll say the file is called example.mp3. The idea is that the first will be saved as example.mp3 (since it won't be caught by if File.exists?("#{file_path}.mp3") elsewhere in the script), the second will be saved as example_#1.mp3 (since it is caught by the else part of the above method) and the third as example_#2.mp3 (since it is caught by the if part of the above method). The problem I have is twofold. 1) if path[-3,2] == "_#" won't work for files with an integer of more than one digit (example_#11.mp3 for example) since the character placement will be wrong (you'd need it to be path[-4,2] but then that doesn't cope with 3 digit numbers etc). 2) I'm never reaching problem 1) since the method doesn't reliably catch file names. At the moment it will rename the first to example_#1.mp3 but the second gets renamed to the same thing (causing it to overwrite the previously saved file). This is possibly too vague for Stack Overflow but I can't find anything that addresses the issue of incrementing a certain part of a string. Thanks in advance!

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• Minimal assembler program for CP/M 3.1 (z80)

  - by Andrew J. Brehm

  I seem to be losing the battle against my stupidity. This site explains the system calls under various versions of CP/M. However, when I try to use call 2 (C_WRITE, console output), nothing much happens. I have the following code. ORG 100h LD E,'a' LD C,2 CALL 5 CALL 0 I recite this here from memory. If there are typos, rest assured they were not in the original since the file did compile and I had a COM file to start. I am thinking the lines mean the following: Make sure this gets loaded at address 100h (0h to FFh being the zero page). Load ASCII 'a' into E register for system call 2. Load integer 2 into C register for system call 2. Make system call (JMP to system call is at address 5 in zero page). End program (Exit command is at address 0 in zero page). The program starts and exits with no problems. If I remove the last command, it hangs the computer (which I guess is also expected and shows that CALL 0 works). However, it does not print the ASCII character. (But it does print an extra new line, but the system might have done that.) How can I get my CP/M program to do what the system call is supposed to do? What am I doing wrong?

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• python can't start a new thread

  - by Giorgos Komnino

  I am building a multi threading application. I have setup a threadPool. [ A Queue of size N and N Workers that get data from the queue] When all tasks are done I use tasks.join() where tasks is the queue . The application seems to run smoothly until suddently at some point (after 20 minutes in example) it terminates with the error thread.error: can't start new thread Any ideas? Edit: The threads are daemon Threads and the code is like: while True: t0 = time.time() keyword_statuses = DBSession.query(KeywordStatus).filter(KeywordStatus.status==0).options(joinedload(KeywordStatus.keyword)).with_lockmode("update").limit(100) if keyword_statuses.count() == 0: DBSession.commit() break for kw_status in keyword_statuses: kw_status.status = 1 DBSession.commit() t0 = time.time() w = SWorker(threads_no=32, network_server='http://192.168.1.242:8180/', keywords=keyword_statuses, cities=cities, saver=MySqlRawSave(DBSession), loglevel='debug') w.work() print 'finished' When the daemon threads are killed? When the application finishes or when the work() finishes? Look at the thread pool and the worker (it's from a recipe ) from Queue import Queue from threading import Thread, Event, current_thread import time event = Event() class Worker(Thread): """Thread executing tasks from a given tasks queue""" def __init__(self, tasks): Thread.__init__(self) self.tasks = tasks self.daemon = True self.start() def run(self): '''Start processing tasks from the queue''' while True: event.wait() #time.sleep(0.1) try: func, args, callback = self.tasks.get() except Exception, e: print str(e) return else: if callback is None: func(args) else: callback(func(args)) self.tasks.task_done() class ThreadPool: """Pool of threads consuming tasks from a queue""" def __init__(self, num_threads): self.tasks = Queue(num_threads) for _ in range(num_threads): Worker(self.tasks) def add_task(self, func, args=None, callback=None): ''''Add a task to the queue''' self.tasks.put((func, args, callback)) def wait_completion(self): '''Wait for completion of all the tasks in the queue''' self.tasks.join() def broadcast_block_event(self): '''blocks running threads''' event.clear() def broadcast_unblock_event(self): '''unblocks running threads''' event.set() def get_event(self): '''returns the event object''' return event

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• django: How to make one form from multiple models containing foreignkeys

  - by Tim

  I am trying to make a form on one page that uses multiple models. The models reference each other. I am having trouble getting the form to validate because I cant figure out how to get the id of two of the models used in the form into the form to validate it. I used a hidden key in the template but I cant figure out how to make it work in the views My code is below: views: def the_view(request, a_id,): if request.method == 'POST': b_form= BForm(request.POST) c_form =CForm(request.POST) print "post" if b_form.is_valid() and c_form.is_valid(): print "valid" b_form.save() c_form.save() return HttpResponseRedirect(reverse('myproj.pro.views.this_page')) else: b_form= BForm() c_form = CForm() b_ide = B.objects.get(pk=request.b_id) id_of_a = A.objects.get(pk=a_id) return render_to_response('myproj/a/c.html', {'b_form':b_form, 'c_form':c_form, 'id_of_a':id_of_a, 'b_id':b_ide }) models class A(models.Model): name = models.CharField(max_length=256, null=True, blank=True) classe = models.CharField(max_length=256, null=True, blank=True) def __str__(self): return self.name class B(models.Model): aid = models.ForeignKey(A, null=True, blank=True) number = models.IntegerField(max_length=1000) other_number = models.IntegerField(max_length=1000) class C(models.Model): bid = models.ForeignKey(B, null=False, blank=False) field_name = models.CharField(max_length=15) field_value = models.CharField(max_length=256, null=True, blank=True) forms from mappamundi.mappa.models import A, B, C class BForm(forms.ModelForm): class Meta: model = B exclude = ('aid',) class CForm(forms.ModelForm): class Meta: model = C exclude = ('bid',) B has a foreign key reference to A, C has a foreign key reference to B. Since the models are related, I want to have the forms for them on one page, 1 submit button. Since I need to fill out fields for the forms for B and C & I dont want to select the id of B from a drop down list, I need to somehow get the id of the B form into the form so it will validate. I have a hidden field in the template, I just need to figure how to do it in the views

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• Given a date range how to calculate the number of weekends partially or wholly within that range?

  - by andybak

  Given a date range how to calculate the number of weekends partially or wholly within that range? (A few definitions as requested: take 'weekend' to mean Saturday and Sunday. The date range is inclusive i.e. the end date is part of the range 'wholly or partially' means that any part of the weekend falling within the date range means the whole weekend is counted.) To simplify I imagine you only actually need to know the duration and what day of the week the initial day is... I darn well now it's going to involve doing integer division by 7 and some logic to add 1 depending on the remainder but I can't quite work out what... extra points for answers in Python ;-) Edit Here's my final code. Weekends are Friday and Saturday (as we are counting nights stayed) and days are 0-indexed starting from Monday. I used onebyone's algorithm and Tom's code layout. Thanks a lot folks. def calc_weekends(start_day, duration): days_until_weekend = [5, 4, 3, 2, 1, 1, 6] adjusted_duration = duration - days_until_weekend[start_day] if adjusted_duration < 0: weekends = 0 else: weekends = (adjusted_duration/7)+1 if start_day == 5 and duration % 7 == 0: #Saturday to Saturday is an exception weekends += 1 return weekends if __name__ == "__main__": days = ['Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'] for start_day in range(0,7): for duration in range(1,16): print "%s to %s (%s days): %s weekends" % (days[start_day], days[(start_day+duration) % 7], duration, calc_weekends(start_day, duration)) print

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• Execute Stored Procedure from Classic ASP

  - by Jaco Pretorius

  For some fantastic reason I find myself debugging a problem in a Classic ASP page (at least 10 years of my life lost in the last 2 days). I'm trying to execute a stored procedure which contains some OUT parameters. The problem is that one of the OUT parameters is not being populated when the stored procedure returns. I can execute the stored proc from SQL management studio (this is 2008) and all the values are being set and returned exactly as expected. declare @inVar1 varchar(255) declare @inVar2 varchar(255) declare @outVar1 varchar(255) declare @outVar2 varchar(255) SET @inVar2 = 'someValue' exec theStoredProc @inVar1 , @inVar2 , @outVar1 OUT, @outVar2 OUT print '@outVar1=' + @outVar1 print '@outVar2=' + @outVar2 Works great. Fantastic. Perfect. The exact values that I'm expecting are being returned and printed out. Right, since I'm trying to debug a Classic ASP page I copied the code into a VBScript file to try and narrow down the problem. Here is what I came up with: Set Conn = CreateObject("ADODB.Connection") Conn.Open "xxx" Set objCommandSec = CreateObject("ADODB.Command") objCommandSec.ActiveConnection = Conn objCommandSec.CommandType = 4 objCommandSec.CommandText = "theStoredProc " objCommandSec.Parameters.Refresh objCommandSec.Parameters(2) = "someValue" objCommandSec.Execute MsgBox(objCommandSec.Parameters(3)) Doesn't work. Not even a little bit. (Another ten years of my life down the drain) The third parameter is simply NULL - which is what I'm experiencing in the Classic ASP page as well. Could someone shed some light on this? Am I completely daft for thinking that the classic ASP code would be the same as the VBScript code? I think it's using the same scripting engine and syntax so I should be ok, but I'm not 100% sure. The result I'm seeing from my VBScript is the same as I'm seeing in ASP.

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• css: make background repeat-y with growing child content?

  - by mikemikemike

  I Have a three column layout. The center div is a container which holds all of my content. The outer columns is just a .png that fades into the body's background (left and right respectively). I want the .png to repeat-y to grow with the center container's content. It will only print the image once, and ignores the repeat-y. If I specify a height to the outside columns, it will print, but only to the specified height. I tried height: 100%, which does not work. Here is my code: #ultra_contain { text-align:left; width:900px; padding: 0px; position:relative; margin:0px auto; margin-top:0px; /*border:1px dashed #996;*/ } #gradientleft { float:left; position:relative; background: url("../i/gradient_left.png") repeat-y; /*border:1px dashed #996;*/ } #gradientright { float:right; position:relative; background: url("../i/gradient_right.png") repeat-y; /*border:1px dashed #996;*/ } #container { text-align:left; width:700px; position:relative; margin:5px auto; margin-top:0px; background:#fff; /*border:1px dashed #996;*/ }

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• parsing xml using dom4j

  - by D3GAN

  My XML structure is like this: <rss> <channel> <yweather:location city="Paris" region="" country="France"/> <yweather:units temperature="C" distance="km" pressure="mb" speed="km/h"/> <yweather:wind chill="-1" direction="40" speed="11.27"/> <yweather:atmosphere humidity="87" visibility="9.99" pressure="1015.92" rising="0"/> <yweather:astronomy sunrise="8:30 am" sunset="4:54 pm"/> </channel> </rss> when I tried to parse it using dom4j SAXReader xmlReader = createXmlReader(); Document doc = null; doc = xmlReader.read( inputStream );//inputStream is input of function log.info(doc.valueOf("/rss/channel/yweather:location/@city")); private SAXReader createXmlReader() { Map<String,String> uris = new HashMap<String,String>(); uris.put( "yweather", "http://xml.weather.yahoo.com/ns/rss/1.0" ); uris.put( "geo", "http://www.w3.org/2003/01/geo/wgs84_pos#" ); DocumentFactory factory = new DocumentFactory(); factory.setXPathNamespaceURIs( uris ); SAXReader xmlReader = new SAXReader(); xmlReader.setDocumentFactory( factory ); return xmlReader; } But I got nothing in cmd but when I print doc.asXML(), my XML structure print correctly!

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• PIC C - Sending 200 values over USB, but it only sends 25 or so of them...

  - by Adam

  I have a PIC18F4455 microcontroller which I am trying to use to send 200 values over USB. Basically I am using a for loop and a printf statement to print the values to the usb output stream. However, when the code executes I see in my serial port monitor that it is only sending the first 25 or so values, then stopping. My PIC C code is below. It will send out the 25th or so value (and the comma), but not send anything after and not send a newline character. I'm trying to get it to send all the values, then a newline character at the end. I am sending them all as characters because I can convert them on the PC end of it. //print #3 for (i = 0; i <= 199; i++){if (data[i]=='\0' || data[i]=='\n'){data[i]++;}} for (i = 0; i < 199; i++){printf(usb_cdc_putc, "%c,", data[i]);} printf(usb_cdc_putc, "%c\n", data[199]);

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• retrieving multiple versions through API through hbase

  - by sammy

  hello , this is a continuation of my previous question where id used hbase shell.. http://stackoverflow.com/questions/3024417/facing-problems-while-updating-rows-in-hbase i tried the same with API.. im not able to figure out how to retrieve all versions , iterate and print their values for a specific row... i've spending hours reading... please help me out... Scan s = new Scan(Bytes.toBytes("row1")); s.addColumn(Bytes.toBytes("column"),Bytes.toBytes("address")); SETTING RANGE FOR THE VERSIONS s.setTimeRange(0L,6L); ResultScanner scanner = table.getScanner(s); for (Result r : scanner) { for(KeyValue kv : r.sorted()) { System.out.println("To"+kv.getTimestamp()); System.out.println("from "+Bytes.toString(kv.getKey())); System.out.println("To "+Bytes.toString(kv.getValue())); } scanner.close(); } here im intending to print all versions of the column..... but it gives the most recent one... im stuck here...

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• How to change a Linux user password from python

  - by Vaulor

  I'm having problems with changing a Linux user's password from python. I've tried so many things, but I couldn't manage to solve the issue, here is the sample of things I've already tried: sudo_password is the password for sudo, sudo_command is the command I want the system to run, user is get from a List and is the user who I want to change the password for, and newpass is the pass I want to assign to 'user' user = list.get(ANCHOR) sudo_command = 'passwd' f = open("passwordusu.tmp", "w") f.write("%s\n%s" % (newpass, newpass)) f.close() A=os.system('echo -e %s|sudo -S %s < %s %s' % (sudo_password, sudo_command,'passwordusu.tmp', user)) print A windowpass.destroy() 'A' is the return value for the execution of os.system, in this case 256. I tried also A=os.system('echo %s|sudo -S %s < %s %s' % (sudo_password, sudo_command,'passwordusu.tmp', user)) but it returns the same error code. I tried several other ways with 'passwd' command, but whithout succes. With 'chpasswd' command I 've tried this: user = list.get(ANCHOR) sudo_command = 'chpasswd' f = open("passwordusu.tmp", "w") f.write("%s:%s" % (user, newpass)) f.close() A=os.system('echo %s|sudo -S %s < %s %s' % (sudo_password, sudo_command,'passwordusu.tmp', user)) print A windowpass.destroy() also with: A=os.system('echo %s|sudo -S %s:%s|%s' % (sudo_password, user, newpass, sudo_command)) @;which returns 32512 A=os.system("echo %s | sudo -S %s < \"%s\"" % (sudo_password, sudo_command, "passwordusu.tmp")) @;which returns 256 I tried 'mkpasswd' and 'usermod' too like this: user = list.get(ANCHOR) sudo_command = 'mkpasswd -m sha-512' os.system("echo %s | sudo -S %s %s > passwd.tmp" % (sudo_password,sudo_command, newpass)) sudo_command="usermod -p" f = open('passwd.tmp', 'r') for line in f.readlines(): newpassencryp=line f.close() A=os.system("echo %s | sudo -S %s %s %s" % (sudo_password, sudo_command, newpassencryp, user)) @;which returns 32512 but, if you go to https://www.mkpasswd.net , hash the 'newpass' and substitute for 'newpassencryp', it returns 0 which theoretically means it has gone right, but so far it doesn't changes the password. I've searched on internet and stackoverflow for this issue or similar and tried what solutions exposed, but again,without success. I would really apreciate any help, and of course, if you need more info i'll be glad to supply it! Thanks in advance.

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• How can I get this week's dates in Perl?

  - by ABach

  I have the following loop to calculate the dates of the current week and print them out. It works, but I am swimming in the amount of date/time possibilities in Perl and want to get your opinion on whether there is a better way. Here's the code I've written: #!/usr/bin/env perl use warnings; use strict; use DateTime; # Calculate numeric value of today and the # target day (Monday = 1, Sunday = 7); the # target, in this case, is Monday, since that's # when I want the week to start my $today_dt = DateTime->now; my $today = $today_dt->day_of_week; my $target = 1; # Create DateTime copies to act as the "bookends" # for the date range my ($start, $end) = ($today_dt->clone(), $today_dt->clone()); if ($today == $target) { # If today is the target, "start" is already set; # we simply need to set the end date $end->add( days => 6 ); } else { # Otherwise, we calculate the Monday preceeding today # and the Sunday following today my $delta = ($target - $today + 7) % 7; $start->add( days => $delta - 7 ); $end->add( days => $delta - 1 ); } # I clone the DateTime object again because, for some reason, # I'm wary of using $start directly... my $cur_date = $start->clone(); while ($cur_date <= $end) { my $date_ymd = $cur_date->ymd; print "$date_ymd\n"; $cur_date->add( days => 1 ); } As mentioned, this works, but is it the quickest or most efficient? I'm guessing that quickness and efficiency may not necessarily go together, but your feedback is very appreciated.

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• Why is my program printing out the null termination character?

  - by Tyler Pfaff

  When I run this, it will SOMETIMES print out a null termination character. Most of the time it will, and probably 1/5 times it will print just the characters. void cryptogram::Encrypt(){ cout<<"encrypt"<tempS){ len=tempS.length(); int a=0; for(int j=0;j if(j!=len){ //if the word still has more characters j++; a=0; }else{ //if the word is done being scanned cout<<" "; } } } } } } } So that's it and this is the corresponding EXPECTED output that is printed SOMETIMES xvk bkikhxlr wggbtfkj wiylekgbdhx wjjm hko wigbtubxt xvk iwhj uedjkm glctb gvrmdiwhj iebbdielmeggtbx ctb xvtmk gbtubxvk wjjdxdthgbtubodll khvxvk imkbfdik xt xvk bkudth whj gbtfdjk hko tgxdthm whj tggtbxehdxdkm ctb mxejkhxmibdzdhtltur whj pemxdik mxejdkm mxdh cok wbk wlmt gbkgctb cteb hko zdh cgvrmdikjeiwhj qdhkmdtlturzzkjdydtivkzdmxbrw zdh zdjjlkkjeiwhj w jtixtbdh kjeiwjzdhdmxbittgkbodxv mjme whj eimj This is what normally prints though xvkÈ bkikhxlrÈ wggbtfkjÈ wiylekgbdhxÈ wjjmÈ hkoÈ wigbtubxtÈ xvkÈ iwhjÈ uedjkmÈ glctbÈ gvrmdiwhjÈ iebbdielmeggtbxÈ ctbÈ xvtmkÈ gbtubxvkÈ wjjdxdthgbtubodllÈ khvxvkÈ imkbfdikÈ xtÈ xvkÈ bkudthÈ whjÈ gbtfdjkÈ hkoÈ tgxdthmÈ whjÈ tggtbxehdxdkmÈ ctbÈ mxejkhxmibdzdhtlturÈ whjÈ pemxdikÈ mxejdkmÈ mxdhÈ cokÈ wbkÈ wlmtÈ gbkgctbÈ ctebÈ hkoÈ zdhÈ cgvrmdikjeiwhjÈ qdhkmdtlturzzkjdydtivkzdmxbrwÈ zdhÈ zdjjlkkjeiwhjÈ wÈ jtixtbdhÈ kjeiwjzdhdmxbittgkbodxvÈ mjmeÈ whjÈ eimj or some variation of an odd character at the end of each word This is what the cryptogram array is filled with by the way wyijkcuvdpqlzhtgabmxefonrs

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• Safe and polymorphic toEnum

  - by jetxee

  I'd like to write a safe version of toEnum: safeToEnum :: (Enum t, Bounded t) => Int -> Maybe t A naive implementation: safeToEnum :: (Enum t, Bounded t) => Int -> Maybe t safeToEnum i = if (i >= fromEnum (minBound :: t)) && (i <= fromEnum (maxBound :: t)) then Just . toEnum $ i else Nothing main = do print $ (safeToEnum 1 :: Maybe Bool) print $ (safeToEnum 2 :: Maybe Bool) And it doesn't work: safeToEnum.hs:3:21: Could not deduce (Bounded t1) from the context () arising from a use of `minBound' at safeToEnum.hs:3:21-28 Possible fix: add (Bounded t1) to the context of an expression type signature In the first argument of `fromEnum', namely `(minBound :: t)' In the second argument of `(>=)', namely `fromEnum (minBound :: t)' In the first argument of `(&&)', namely `(i >= fromEnum (minBound :: t))' safeToEnum.hs:3:56: Could not deduce (Bounded t1) from the context () arising from a use of `maxBound' at safeToEnum.hs:3:56-63 Possible fix: add (Bounded t1) to the context of an expression type signature In the first argument of `fromEnum', namely `(maxBound :: t)' In the second argument of `(<=)', namely `fromEnum (maxBound :: t)' In the second argument of `(&&)', namely `(i <= fromEnum (maxBound :: t))' As well as I understand the message, the compiler does not recognize that minBound and maxBound should produce exactly the same type as in the result type of safeToEnum inspite of the explicit type declaration (:: t). Any idea how to fix it?

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• parse xml with elementtree, custom sorting

  - by microspace

  I want to parse xml file in utf-8 and sort it by some field. Soring is made by custom alphabet (s1 from sourcecode). History of question is here: sorting of list containing utf-8 charachters. I've found how to sort xml here. Sorting work correctly, the problem is with elementtree, I must admit that it doesn't work on python3 Here is source code: #!/usr/bin/env python # -*- coding: utf-8 -*- #import xml.etree.ElementTree as ET # Python 2.5 import elementtree.ElementTree as ET s1='aáàAâÂbBcCçÇdDeéEfFgGgGhHiIîÎíiiIjJkKlLmMnNóoOöÖpPqQrRsSsStTuUûúÛüÜvVwWxXyYzZ' s2='11111122334455666aabbccddeeeeeeffgghhiijjkklllllmmnnooppqqrrsssssttuuvvwwxxyy' trans = str.maketrans(s1, s2) def unikey(seq): return seq[0].translate(trans) tree = ET.parse("tosort.xml") container = tree.find("entries") data = [] for elem in container: keyd = elem.findtext("k") data.append((keyd, elem)) print (data) data.sort(key=unikey) print (data) container[:] = [item[-1] for item in data] tree.write("sorted.xml", encoding="utf-8") Here are instructions to import elementtree module. When I import module this way :import xml.etree.ElementTree as ET, I get a message: Traceback (most recent call last): File "pcs.py", line 19, in <module> container[:] = [item[-1] for item in data] File "/usr/lib/python3.1/xml/etree/ElementTree.py", line 210, in __setitem__ assert iselement(element) AssertionError When I use this method to import: import elementtree.ElementTree as ET, I get this message: Traceback (most recent call last): File "pcs.py", line 4, in <module> import elementtree.ElementTree as ET File "/usr/local/lib/python3.1/dist-packages/elementtree/ElementTree.py", line 794, in <module> _escape = re.compile(eval(r'u"[&<>\"\u0080-\uffff]+"')) File "<string>", line 1 u"[&<>\"\u0080-\uffff]+" ^ SyntaxError: invalid syntax I use Python 3.1.3 (r313:86834, Nov 28 2010, 11:28:10). In python2.6 elementtree work without a problem. Content of tosort.xml: <xdxf> <entries> <ar><k>zaaaa</k>definition1</ar> <ar><k>saaaa</k>definition2</ar> ... ... </entries> </xdxf>

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• Downloading a file from a PHP page in C#

  - by FoxyShadoww

  Okay, we have a PHP script that creates an download link from a file and we want to download that file via C#. This works fine with progress etc but when the PHP page gives an error the program downloads the error page and saves it as the requested file. Here is the code we have atm: PHP Code: <?php $path = 'upload/test.rar'; if (file_exists($path)) { $mm_type="application/octet-stream"; header("Pragma: public"); header("Expires: 0"); header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Cache-Control: public"); header("Content-Description: File Transfer"); header("Content-Type: " . $mm_type); header("Content-Length: " .(string)(filesize($path)) ); header('Content-Disposition: attachment; filename="'.basename($path).'"'); header("Content-Transfer-Encoding: binary\n"); readfile($path); exit(); } else { print 'Sorry, we could not find requested download file.'; } ?> C# Code: private void btnDownload_Click(object sender, EventArgs e) { string url = "http://***.com/download.php"; WebClient client = new WebClient(); client.DownloadFileCompleted += new AsyncCompletedEventHandler(client_DownloadFileCompleted); client.DownloadProgressChanged += new DownloadProgressChangedEventHandler(ProgressChanged); client.DownloadFileAsync(new Uri(url), @"c:\temp\test.rar"); } private void ProgressChanged(object sender, DownloadProgressChangedEventArgs e) { progressBar.Value = e.ProgressPercentage; } void client_DownloadFileCompleted(object sender, AsyncCompletedEventArgs e) { MessageBox.Show(print); }

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• Creating A Single Threaded Server with AnyEvent (Perl)

  - by David Williams

  I'm working on creating a local service to listen on localhost and provide a basic call and response type interface. What I'd like to start with is a baby server that you can connect to over telnet and echoes what it receives. I've heard AnyEvent is great for this, but the documentation for AnyEvent::Socket does not give a very good example how to do this. I'd like to build this with AnyEvent, AnyEvent::Socket and AnyEvent::Handle. Right now the little server code looks like this: #!/usr/bin/env perl use AnyEvent; use AnyEvent::Handle; use AnyEvent::Socket; my $cv = AnyEvent->condvar; my $host = '127.0.0.1'; my $port = 44244; tcp_server($host, $port, sub { my($fh) = @_; my $cv = AnyEvent->condvar; my $handle; $handle = AnyEvent::Handle->new( fh => $fh, poll => "r", on_read => sub { my($self) = @_; print "Received: " . $self->rbuf . "\n"; $cv->send; } ); $cv->recv; }); print "Listening on $host\n"; $cv->wait; This doesn't work and also if I telnet to localhost:44244 I get this: EV: error in callback (ignoring): AnyEvent::CondVar: recursive blocking wait attempted at server.pl line 29. I think if I understand how to make a mini, single threaded server that simply prints out whatever its given and then waits for more input, I could take it a lot further from there. Any ideas?

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• Sweave can't see a vector if run from a function ?

  - by PaulHurleyuk

  I have a function that sets a vector to a string, copies a Sweave document with a new name and then runs that Sweave. Inside the Sweave document I want to use the vector I set in the function, but it doesn't seem to see it. (Edit: I changed this function to use tempdir(() as suggested by Dirk) I created a sweave file test_sweave.rnw; % \documentclass[a4paper]{article} \usepackage[OT1]{fontenc} \usepackage{Sweave} \begin{document} \title{Test Sweave Document} \author{gb02413} \maketitle <<>>= ls() Sys.time() print(paste("The chosen study was ",chstud,sep="")) @ \end{document} and I have this function; onOK <- function(){ chstud<-"test" message(paste("Chosen Study is ",chstud,sep="")) newfile<-paste(chstud,"_report",sep="") mypath<-paste(tempdir(),"\\",sep="") setwd(mypath) message(paste("Copying test_sweave.Rnw to ",paste(mypath,newfile,".Rnw",sep=""),sep="")) file.copy("c:\\local\\test_sweave.Rnw", paste(mypath,newfile,".Rnw",sep=""), overwrite=TRUE) Sweave(paste(mypath,newfile,".Rnw",sep="")) require(tools) texi2dvi(file = paste(mypath,newfile,".tex",sep=""), pdf = TRUE) } If I run the code from the function directly, the resulting file has this output for ls(); > ls() [1] "chstud" "mypath" "newfile" "onOK" However If I call onOK() I get this output; > ls() [1] "onOK" and the print(...chstud...)) function generates an error. I suspect this is an environment problem, but I assumed because the call to Sweave occurs within the onOK function, it would be in the same enviroment, and would see all the objects created within the function. How can I get the Sweave process to see the chstud vector ? Thanks Paul.

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• How can you get the call tree with python profilers?

  - by Oliver

  I used to use a nice Apple profiler that is built into the System Monitor application. As long as your C++ code was compiled with debug information, you could sample your running application and it would print out an indented tree telling you what percent of the parent function's time was spent in this function (and the body vs. other function calls). For instance, if main called function_1 and function_2, function_2 calls function_3, and then main calls function_3: main (100%, 1% in function body): function_1 (9%, 9% in function body): function_2 (90%, 85% in function body): function_3 (100%, 100% in function body) function_3 (1%, 1% in function body) I would see this and think, "Something is taking a long time in the code in the body of function_2. If I want my program to be faster, that's where I should start." Does anyone know how I can most easily get this exact profiling output for a python program? I've seen people say to do this: import cProfile, pstats prof = cProfile.Profile() prof = prof.runctx("real_main(argv)", globals(), locals()) stats = pstats.Stats(prof) stats.sort_stats("time") # Or cumulative stats.print_stats(80) # 80 = how many to print but it's quite messy compared to that elegant call tree. Please let me know if you can easily do this, it would help quite a bit. Cheers!

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