Search Results

Search found 8349 results on 334 pages for 'entity groups'.

Page 153/334 | < Previous Page | 149 150 151 152 153 154 155 156 157 158 159 160  | Next Page >

  • Iterator

    Imagine that you are game developer. Your game is war stategy. Army has complicated structure: it consists with Hero and three Groups. When King gives decree to treat all soldiers (Hero is also soldier) you want to iterate through all soldiers and call treat() method on each soldier instance. How ca

    Read the article

  • ComboBox Data Binding

    - by Geertjan
    Let's create a databound combobox, levering MVC in a desktop application. The result will be a combobox, provided by the NetBeans ChoiceView, that displays data retrieved from a database: What follows is not much different from the NetBeans Platform CRUD Application Tutorial and you're advised to consult that document if anything that follows isn't clear enough. One kind of interesting thing about the instructions that follow is that it shows that you're able to create an application where each element of the MVC architecture can be located within a separate module: Start by creating a new NetBeans Platform application named "MyApplication". Model We're going to start by generating JPA entity classes from a database connection. In the New Project wizard, choose "Java Class Library". Click Next. Name the Java Class Library "MyEntities". Click Finish. Right-click the MyEntities project, choose New, and then select "Entity Classes from Database". Work through the wizard, selecting the tables of interest from your database, and naming the package "entities". Click Finish. Now a JPA entity is created for each of the selected tables. In the Project Properties dialog of the project, choose "Copy Dependent Libraries" in the Packaging panel. Build the project. In your project's "dist" folder (visible in the Files window), you'll now see a JAR, together with a "lib" folder that contains the JARs you'll need. In your NetBeans Platform application, create a module named "MyModel", with code name base "org.my.model". Right-click the project, choose Properties, and in the "Libraries" panel, click Add Dependency button in the Wrapped JARs subtab to add all the JARs from the previous step to the module. Also include "derby-client.jar" or the equivalent driver for your database connection to the module. Controler In your NetBeans Platform application, create a module named "MyControler", with code name base "org.my.controler". Right-click the module's Libraries node, in the Projects window, and add a dependency on "Explorer & Property Sheet API". In the MyControler module, create a class with this content: package org.my.controler; import org.openide.explorer.ExplorerManager; public class MyUtils { static ExplorerManager controler; public static ExplorerManager getControler() { if (controler == null) { controler = new ExplorerManager(); } return controler; } } View In your NetBeans Platform application, create a module named "MyView", with code name base "org.my.view".  Create a new Window Component, in "explorer" view, for example, let it open on startup, with class name prefix "MyView". Add dependencies on the Nodes API and on the Explorer & Property Sheet API. Also add dependencies on the "MyModel" module and the "MyControler" module. Before doing so, in the "MyModel" module, make the "entities" package and the "javax.persistence" packages public (in the Libraries panel of the Project Properties dialog) and make the one package that you have in the "MyControler" package public too. Define the top part of the MyViewTopComponent as follows: public final class MyViewTopComponent extends TopComponent implements ExplorerManager.Provider { ExplorerManager controler = MyUtils.getControler(); public MyViewTopComponent() { initComponents(); setName(Bundle.CTL_MyViewTopComponent()); setToolTipText(Bundle.HINT_MyViewTopComponent()); setLayout(new BoxLayout(this, BoxLayout.PAGE_AXIS)); controler.setRootContext(new AbstractNode(Children.create(new ChildFactory<Customer>() { @Override protected boolean createKeys(List list) { EntityManager entityManager = Persistence. createEntityManagerFactory("MyEntitiesPU").createEntityManager(); Query query = entityManager.createNamedQuery("Customer.findAll"); list.addAll(query.getResultList()); return true; } @Override protected Node createNodeForKey(Customer key) { Node customerNode = new AbstractNode(Children.LEAF, Lookups.singleton(key)); customerNode.setDisplayName(key.getName()); return customerNode; } }, true))); controler.addPropertyChangeListener(new PropertyChangeListener() { @Override public void propertyChange(PropertyChangeEvent evt) { Customer selectedCustomer = controler.getSelectedNodes()[0].getLookup().lookup(Customer.class); StatusDisplayer.getDefault().setStatusText(selectedCustomer.getName()); } }); JPanel row1 = new JPanel(new FlowLayout(FlowLayout.LEADING)); row1.add(new JLabel("Customers: ")); row1.add(new ChoiceView()); add(row1); } @Override public ExplorerManager getExplorerManager() { return controler; } ... ... ... Now run the application and you'll see the same as the image with which this blog entry started.

    Read the article

  • Help connecting to Windows Shares on 2003/2008 server Ubuntu 12.04

    - by Murphy1138
    Can anyone help me , I'm really struggling to connect to Windows shares via Nautilus using the Connect to server command - anyone know the correct Syntax to use for user names and domain names or work groups? Its driving me nuts, I would fully use Ubuntu for work if I could make it connect to my Windows 2003/2008/ Windows 7 shares/ File servers seamlessly. How do you do it? I have been googling my a$%S off but can't work it out I have no issues with SSH or FTP

    Read the article

  • SSMS Tools Pack 3.0 is out. Full SSMS 2014 support and improved features.

    - by Mladen Prajdic
    With version 3.0 the SSMS 2014 is fully supported. Since this is a new major version you'll eventually need a new license. Please check the EULA to see when. As a thank you for your patience with this release, everyone that bought the SSMS Tools Pack after April 1st, the release date of SQL Server 2014, will receive a free upgrade. You won't have to do anything for this to take effect. First thing you'll notice is that the UI has been completely changed. It's more in line with SSMS and looks less web-like. Also the core has been updated and rewritten in some places to be better suited for future features. Major improvements for this release are: Window Connection Coloring Something a lot of people have asked me over the last 2 years is if there's a way to color the tab of the window itself. I'm very glad to say that now it is. In SSMS 2012 and higher the actual query window tab is also colored at the top border with the same color as the already existing strip making it much easier to see to which server your query window is connected to even when a window is not focused. To make it even better, you can not also specify the desired color based on the database name and not just the server name. This makes is useful for production environments where you need to be careful in which database you run your queries in. Format SQL The format SQL core was rewritten so it'll be easier to improve it in future versions. New improvement is the ability to terminate SQL statements with semicolons. This is available only in SSMS 2012 and up. Execution Plan Analyzer A big request was to implement the Problems and Solutions tooltip as a window that you can copy the text from. This is now available. You can move the window around and copy text from it. It's a small improvement but better stuff will come. SQL History Current Window History has been improved with faster search and now also shows the color of the server/database it was ran against. This is very helpful if you change your connection in the same query window making it clear which server/database you ran query on. The option to Force Save the history has been added. This is a menu item that flushes the execution and tab content history save buffers to disk. SQL Snippets Added an option to generate snippet from selected SQL text on right click menu. Run script on multiple databases Configurable database groups that you can save and reuse were added. You can create groups of preselected databases to choose from for each server. This makes repetitive tasks much easier New small team licensing option A lot of requests came in for 1 computer, Unlimited VMs option so now it's here. Hope it serves you well.

    Read the article

  • Try Out the New Microsoft Desktop Player

    Microsoft Desktop Player allows developers to access technical content (such as videos, webcasts, podcasts, and white papers) and links to resources (including developer evangelists, local training opportunities, and local user groups) in your area. View it online or download the WPF application to view offline. Try it today!...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

    Read the article

  • WIF in .NET 4.5&ndash;First Observations (2)

    - by Your DisplayName here!
      WindowsIdentity, FormsIdentity and GenericIdentity now derive from ClaimsIdentity WindowsIdentity.GetCurrent() converts Windows token details (groups for the current Windows versions) to claims. Claims for Windows identities now distinguish between user claims and device claims (Windows 8 feature) WCF now populates Thread.CurrentPrincipal with a ClaimsPrincipal derived type

    Read the article

  • How to make this design closer to proper DDD?

    - by Seralize
    I've read about DDD for days now and need help with this sample design. All the rules of DDD make me very confused to how I'm supposed to build anything at all when domain objects are not allowed to show methods to the application layer; where else to orchestrate behaviour? Repositories are not allowed to be injected into entities and entities themselves must thus work on state. Then an entity needs to know something else from the domain, but other entity objects are not allowed to be injected either? Some of these things makes sense to me but some don't. I've yet to find good examples of how to build a whole feature as every example is about Orders and Products, repeating the other examples over and over. I learn best by reading examples and have tried to build a feature using the information I've gained about DDD this far. I need your help to point out what I do wrong and how to fix it, most preferably with code as "I would not recomment doing X and Y" is very hard to understand in a context where everything is just vaguely defined already. If I can't inject an entity into another it would be easier to see how to do it properly. In my example there are users and moderators. A moderator can ban users, but with a business rule: only 3 per day. I did an attempt at setting up a class diagram to show the relationships (code below): interface iUser { public function getUserId(); public function getUsername(); } class User implements iUser { protected $_id; protected $_username; public function __construct(UserId $user_id, Username $username) { $this->_id = $user_id; $this->_username = $username; } public function getUserId() { return $this->_id; } public function getUsername() { return $this->_username; } } class Moderator extends User { protected $_ban_count; protected $_last_ban_date; public function __construct(UserBanCount $ban_count, SimpleDate $last_ban_date) { $this->_ban_count = $ban_count; $this->_last_ban_date = $last_ban_date; } public function banUser(iUser &$user, iBannedUser &$banned_user) { if (! $this->_isAllowedToBan()) { throw new DomainException('You are not allowed to ban more users today.'); } if (date('d.m.Y') != $this->_last_ban_date->getValue()) { $this->_ban_count = 0; } $this->_ban_count++; $date_banned = date('d.m.Y'); $expiration_date = date('d.m.Y', strtotime('+1 week')); $banned_user->add($user->getUserId(), new SimpleDate($date_banned), new SimpleDate($expiration_date)); } protected function _isAllowedToBan() { if ($this->_ban_count >= 3 AND date('d.m.Y') == $this->_last_ban_date->getValue()) { return false; } return true; } } interface iBannedUser { public function add(UserId $user_id, SimpleDate $date_banned, SimpleDate $expiration_date); public function remove(); } class BannedUser implements iBannedUser { protected $_user_id; protected $_date_banned; protected $_expiration_date; public function __construct(UserId $user_id, SimpleDate $date_banned, SimpleDate $expiration_date) { $this->_user_id = $user_id; $this->_date_banned = $date_banned; $this->_expiration_date = $expiration_date; } public function add(UserId $user_id, SimpleDate $date_banned, SimpleDate $expiration_date) { $this->_user_id = $user_id; $this->_date_banned = $date_banned; $this->_expiration_date = $expiration_date; } public function remove() { $this->_user_id = ''; $this->_date_banned = ''; $this->_expiration_date = ''; } } // Gathers objects $user_repo = new UserRepository(); $evil_user = $user_repo->findById(123); $moderator_repo = new ModeratorRepository(); $moderator = $moderator_repo->findById(1337); $banned_user_factory = new BannedUserFactory(); $banned_user = $banned_user_factory->build(); // Performs ban $moderator->banUser($evil_user, $banned_user); // Saves objects to database $user_repo->store($evil_user); $moderator_repo->store($moderator); $banned_user_repo = new BannedUserRepository(); $banned_user_repo->store($banned_user); Should the User entitity have a 'is_banned' field which can be checked with $user->isBanned();? How to remove a ban? I have no idea.

    Read the article

  • Build Sales As an Exhibitor at a Marketing Expo

    A marketing expo is the ideal opportunity to showcase products or services for groups that are most interested in a certain company's field of expertise. Most exhibitor spaces are relatively inexpensive compared to traditional advertising costs. It is easy to recover the booth rental and supply overhead with just a few good sales or networking connections.

    Read the article

  • Are the other organizations such as BSA that a small company can join?

    - by Saariko
    I am looking for other associations such as BSA. Setting aside the long debate about : should/can a software be protected?! I am currently actively looking for other, local, intentaional or even rgional groups/organizations that a small software company wants to join. I mark : small, since the BSA fees are expensive. please don't open the debate: if you are not big enough to pay the fee, than you are not big enough to join the __. Thank you

    Read the article

  • Tips For Getting Your Website Found in Google

    Websites today are used by almost everyone, in every corner of the world and by all age groups. Many people think that building back links are all you need to move up the ranks of Google, but even though they help, they are not the only answer.

    Read the article

  • Ubuntu software stack to mimic Active Directory auth

    - by WickedGrey
    I'm going to have an Ubuntu 11.10 box in a customer's data center running a custom webapp. The customer will not have ssh access to the box, but will need authentication and authorization to access the webapp. The customer needs to have the option of either pointing the webapp at something that we've installed locally on the machine, or to use an Active Directory server that they have. I plan on using a standard "users belong to groups; groups have sets of permissions; the webapp requires certain permissions to respond" auth setup. What software stack can I install locally that will allow an easy switch to and from an Active Directory server, while keeping the configuration as simple as possible (both for me and the end customer)? I would like to use as much off-the-shelf software for this as possible; I do not want to be in the business of keeping user passwords secure. I could see handling the user/group/permission relationships myself if there is not a good out-of-the-box solution (but that seems highly unlikely). I will accept answers in the form of links to "here is what you need" pages, but not "here is what Kerberos does" unless that page also tells me if it's required for my use case (essentially, I know that AD can speak Kerberos, but I can't tell if I need it to, or if I can just use LDAP, or...).

    Read the article

  • How to scope access to a service to set of users, using OpenLDAP, and only OUs

    - by JDS
    Okay, here goes. Solving this will solve several problems for me (as I can reapply this knowledge to several extant, similar problems), but luckily I have a very specific, concise problem to describe. Enough preamble. Our hosting partner is setting up VPN access for us and is connecting it to our LDAP server. They are using Cisco VPN, the docs on setting this up are here: http://www.cisco.com/en/US/products/ps6120/products_configuration_example09186a00808c3c45.shtml#maintask1 Specifically, note the screenshot in (5), under "ASDM" Now, I do NOT want to provide access to all of our users. I only want to provide access to our IT group. But I do not see a configuration option for LDAP groups on that web reference for the Cisco VPN. We are using: OpenLDAP 2.4 Static groups (i.e. "Group has the following members...") Single user OU, "ou=users,dc=mycompany,dc=com" Is it possible to provide an alias of some kind in OpenLDAP that creates another OU, "itusers", say, and lets me alias the members of that OU somehow? Something like: "cn=Jeff Silverman,ou=itusers,dc=mycompany,dc=com" is an alias for "cn=Jeff Silverman,ou=users,dc=mycompany,dc=com" And is NOT a separate, unique user account. Alternatively, should I just create a separate OU and manage it separately? It is a pain, but only 12-15 users will have to be managed that way, with two separate user accounts. But I hate this option - messy, unmanageable, unscalable. You know what I mean. I am open to any options. I've searched and read all over but I can't quite find an directly analagous example. I can't possibly be the only one who's had this problem! Thanks!

    Read the article

  • SQL 2005 AD Group permission levels

    - by jj.
    I'm trying to give permissions to a (sql 2005) database app based on AD groups. The general idea is to require a user to have a membership to "app_users" to view anything, and membership to other groups gives them write access to that group. "app_customers" gives write access to the customers module, "app_sales" to sales, etc. I've listed an example below: user1: AD member of app_users user2: AD member of app_users, app_customers For dbo.customers table: app_users - Granted: Select permission - Denied: Insert, Update, Delete app_customers - Granted: Select permission - Granted: Insert, Update, Delete I would expect user1 to be able to view the dbo.customers table, but will not be allowed to modify anything (insert/update/delete) - which works. In the same vein, I would expect user2 to be able to view AND modify the dbo.customers table, since they are a member of app_customers. However, this is not the case. Instead, user2 is denied any modifications just like user1. I seem to remember something about deny permissions winning if there was a conflict, but it's honestly been too long since I've dealt with them. Am I going about this the right way? Thanks for your time!

    Read the article

  • SVN and WebSVN with different users access restriction on multiple repositories on linux

    - by user55658
    and first of all sorry for my english. I've installed an ubuntu server 10.04.1 with apache2, subversion, svn_dav and websvn. (and others services of course, like php5, mysql 5.1, etc). I've configured my svn with multiple repositories, and each one with differents groups and users, like: /var/myrepos/repo1 group: mygroup1 /var/myrepos/repo2 group: mygroup2 /var/myrepos/repo3 user: johndoe With an easy access on svn_dav, works perfectly, ie: http://myserver/svnrepo1 accesibly only for users on mygroup1 with theirs users of linux and passwords of svn. Also works for the other repos with their users and groups. But when i tried with websvn, shows all repos without take care than if user on mygroup1 can view repo2 (that's i dont want do). You can login as any user on mygroup1, mygroup2, or johndoe, and you login into all repositories. I'll try to find a solution and I'll post the news, if anyone can helpme with this I'll preciated so much!!! Thanks for all I show my files: /etc/apache2/mods-available/dav_svn.conf <Location /svnrepo1> DAV svn SVNPath /var/myrepos/repo1 AuthType Basic AuthName "Repositorio Subversion de MD" AuthUserFile /etc/apache2/dav_svn.passwd Require valid-user </Location> <Location /websvn/> Options FollowSymLinks order allow,deny allow from all AuthType Basic AuthName "Subversion Repository" AuthUserFile /etc/apache2/dav_svn.passwd Require valid-user </Location>

    Read the article

  • How to setup Calendar permissions for group to group

    - by Sorean
    I've been scouring the internet and so far have only been able to find examples of how to grant calendar permissions from one user to another using the Add-MailboxFolderPermission command. This is great and it was okay for when they only had a handful of users. But going forward it's not realistic to have to set individual calendar permissions for all calendars for each new user. Layout of security groups already created. Each group has a few people assigned to it. Techs Managers Admin What I am trying to accomplish is set it up so that anyone that belongs to the Managers group can view the calendars of the Tech group. Admins can view and edit the Tech group. I've found an example of adding just the security group name but I get an error of: [PS] C:\Windows\system32add-MailboxFolderPermission -Identity Techs:\Calendar -User "Admin" -AccessRights Owner The user "Admin" is either not valid SMTP address, or there is no matching information. + CategoryInfo : NotSpecified: (0:Int32) [Add-MailboxFolderPermission], InvalidExternalUserIdException + FullyQualifiedErrorId : 39352699,Microsoft.Exchange.Management.StoreTasks.AddMailboxFolderPermission Am I creating groups wrong? Am I using the wrong commands? Any guidance would be greatly appreciated.

    Read the article

  • Weird permission issue with POSIX ACLs, NFS v3 on Linux

    - by jon
    I have two Linux systems, both running Debian Squeeze. Versions of (I think) the stuff involved are: kernel: 2.6.32-5-xen-amd64 ii nfs-kernel-server 1:1.2.2-4squeeze2 support for NFS kernel server ii libnfsidmap2 0.23-2 An nfs idmapping library ii nfs-common 1:1.2.2-4squeeze2 NFS support files common to client and server ii portmap 6.0.0-2 RPC port mapper (The client doesn't have nfs-kernel-server involved.) I have a directory with ACLs: # file: dirname # owner: jon # group: foogroup # flags: -s- user::rwx user:www-data:rwx group::r-x group:foogroup:rwx mask::rwx other::r-x default:... There are two users, neither one of which owns the directory: uid=3001(jake) gid=3001(jake) groups=3001(jake),104(wheel),3999(foogroup) uid=3005(nic) gid=3005(nic) groups=3005(nic),3999(foogroup) The jake user can create files in the directory without issues. The nic user can't. All UIDs/GIDs are the same on the client and server. I've verified (packet sniffing) that the right uids/gids get sent via AUTH_UNIX are correct-- uid=gid=3005, auxiliary gids=3005,3999-- and that the server replies with NFS3ERR_ACCESS, which the kernel on the client maps to EACCES (Permission denied). Can anyone help me here?

    Read the article

  • OS X AFP shares and access

    - by gbrandt
    I am running 10.5.6 Client as a mini server and am having problems with AFP shares. All clients are OS X 10.5.7 I have created three users for 'File Sharing' only on the 'server'. I have created groups and placed these users into specific groups. I have created ACL's to give each group access to certain shares. Two of those users can read and write to any share, one user cannot write to the shares, with different results: when copying a directory, only the directory is created, no files inside are copied, the OS does not give any errors when copying a single file I get three dialogs: "You may need to enter the name and password for an administrator on this computer to change the item named 'xxxx', "The item 'xxxxx' contains one or more items you do not have permission to read. Do you want to copy the items you are allowed to read?, and, The operation cannot be completed because you do not have sufficient priveleges for some of the items. With the single file, a file gets created on the server, but is empty. My ACL for the group this user belongs to is: 0: group:projectmembers allow list,add_file,search,delete,add_subdirectory,delete_child,readattr,writeattr,readextattr,writeextattr,readsecurity,file_inherit,directory_inherit 1: group:informationtechnology inherited allow list,add_file,search,delete,add_subdirectory,delete_child,readattr,writeattr,readextattr,writeextattr,readsecurity,file_inherit,directory_inherit 2: group:executive inherited allow list,add_file,search,delete,add_subdirectory,delete_child,readattr,writeattr,readextattr,writeextattr,readsecurity,file_inherit,directory_inherit 3: group:everyone inherited deny list,add_file,search,delete,add_subdirectory,delete_child,readattr,writeattr,readextattr,writeextattr,readsecurity,file_inherit,directory_inherit User 1 & 2 belong to informationtechnology and executive and projectmembers, they can read and write freely on the share. User 3 belongs to projectmembers and cannot read and write freely. I have read that this is a UID issue, however User 1 & 2 do not have matching UID's across clients and server and they work, so I don't think this is the case. Any ideas?

    Read the article

  • Numeric UIDs/GIDs in ACLs on OS X server (10.6)

    - by Oliver Humpage
    Hi, On one (old OS X 10.4) server I'm tarring up some files which have ACLs. I'm then using ``tar -xp'' to untar the archive onto a new 10.6 server, which doesn't have any users/groups configured on it yet except the default admin (UID 501) (there's a reason for that, don't ask!). Obviously this means an "ls -lne" will list files and ACLs with numeric UIDs and GIDs. Now for the normal file permissions it makes sense: you get UIDs like "1037". And for some ACLs, it also makes sense: you get things like "AAAABBBB-CCCC-DDDD-EEEE-FFFF00000402" for groups (0x402 = GID 1026) and "FFFFEEEE-DDDD-CCCC-BBBB-AAAA000001F5" for users (0x1F5 = UID 501). However, some ACLs have a UIDs like "E51DA674-AE70-41BC-8340-9B06C243A262" or GIDs like "0A3FCD24-0012-46FA-B085-88519E55EF29" and I have absolutely no idea how to translate these IDs back into something that could be matched back to the original IDs (UID 1072 and GID 1047 respectively in this example). Can anyone help me translate these weird long hex strings? (Basically we're moving from local users to an Active Directory setup, so I want to move all files to the new server with permissions intact, then chmod, chgrp and set ACLs such that we translate old IDs to the new AD IDs. Hence needing some way to map between the sets. I don't believe there's an easier way to do this?) Many thanks, Oliver.

    Read the article

  • SQL Server Windows-only Authentication Strategy problem

    - by Mike Thien
    I would like to use Windows-only Authentication in SQL Server for our web applications. In the past we've always created the all powerful 1 SQL Login for the web application. After doing some initial testing we've decided to create Windows Active Directory groups that mimic the security roles of the application (i.e. Administrators, Managers, Users/Operators, etc...) We've created mapped logins in SQL Server to these groups and given them access to the database for the application. In addition, we've created SQL Server database roles and assigned each group the appropriate role. This is working great. My issue revolves around that for most of the applications, everyone in the company should have read access to the reports (and hence the data). As far as I can tell, I have 2 options: 1) Create a read-only/viewer AD group and put everyone in it. 2) Use the "domain\domain users" group(s) and assign them the correct roles in SQL. What is the best and/or easiest way to allow everyone read access to specific database objects using a Windows-only Authentication method?

    Read the article

  • SQL Server 2005 standard filegroups / files for performance on SAN

    - by Blootac
    I submitted this to stack overflow (here) but realised it should really be on serverfault. so apologies for the incorrect and duplicate posting: Ok so I've just been on a SQL Server course and we discussed the usage scenarios of multiple filegroups and files when in use over local RAID and local disks but we didn't touch SAN scenarios so my question is as follows; I currently have a 250 gig database running on SQL Server 2005 where some tables have a huge number of writes and others are fairly static. The database and all objects reside in a single file group with a single data file. The log file is also on the same volume. My interpretation is that separate data files should be used across different disks to lessen disk contention and that file groups should be used for partitioning of data. However, with a SAN you obviously don't really have the same issue of disk contention that you do with a small RAID setup (or at least we don't at the moment), and standard edition doesn't support partitioning. So in order to improve parallelism what should I do? My understanding of various Microsoft publications is that if I increase the number of data files, separate threads can act across each file separately. Which leads me to the question how many files should I have. One per core? Should I be putting tables and indexes with high levels of activity in separate file groups, each with the same number of data files as we have cores? Thank you

    Read the article

< Previous Page | 149 150 151 152 153 154 155 156 157 158 159 160  | Next Page >