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  • 13.10 Desktop - Stop Suspension on Lid Closure

    - by bpmitche
    I'm having a problem with power management settings on my ASUS K52-F Laptop. Upgraded from 13.04 to 13.10 earlier today; closing the laptop lid puts the laptop into suspension (even on AC Power - tried fixing it in gnome power settings, tried fixing it in Cinnamon power settings, tried changing it in DCONF-Editor, but no matter where I change the setting the laptop lid still suspends). After resuming from suspend, I restore to the gnome window/login manager (instead of Cinnamon login manager). Wifi doesn't reconnect, but the icon in Cinnamon shows that I'm connected. IFCONFIG shows that the interface is up and working normally, but still not reconnecting. ifconfig wlan0 down / up doesn't change anything. Any help would be greatly appreciated.

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  • Dual Monitor Lock Screen Problem

    - by Justin Carver
    Ubuntu 12.04 Nvidia GTX 550-Ti x-swat Nvidia driver Problem: Using 2 monitors. When screen locks there is a blue box on top of the wallpaper and password dialog box that hides the field for entering your password or switching users. Problem is on 2 systems with similar hardware (Nvidia card, x-swat driver, dual monitors) You can still type your password in blindly and hit enter to login but it's irritating to not be able to see the dialog box.

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  • X11 forwarding from one server to other

    - by n3oblit7
    I have a setup where I need to forward X11 from my local machine (laptop) to a Virtual machine. The server hosting this VM cannot be reached directly from my laptop. I need to first login to a gateway and from this gateway, I can access the VM. How can I forward X11 from my laptop to this VM? I have tried following but these do not work: [laptop # ] ssh -X [gateway] [gateway # ] ssh -X [VM] [laptop # ] ssh -tX [gateway] ssh -X [VM] I could forward X11 only till the gateway. (DISPLAY variable gets set on gateway)

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  • MAC filtering after DHCP

    - by user1655161
    How to manage filtering by MAC in Ubuntu? Scenario: Ubuntu DHCP is configured and working (network 192.168.1.0) a) Laptop 1 is set in configuration on Ubuntu as static IP Laptop 1 is configured for automatic IP and when is connected to server everything works. I'm taking laptop 2 which is configured as static IP 192.168.1.10 and his configuration is not set in Ubuntu dhcpd.conf After laptop 2 is connected internet working. It is possible to do MAC filtering which disallow to connect PCs with address IP set as static but MAC address is not configured in Ubuntu (something like: intruder in network)?

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  • Dual monitor not working after an update

    - by Nimonika
    I did a package manager update yesterday and it turns out that my dual monitor setup has stopped working. I have poor vision so I really need to connect to a much bigger screen, but since yesterday, when I connect the screen to my laptop, the screen does not automatically reset itself to the laptop display. Even after lots of trial and error with the display settings, I am getting different dispalys on the laptop and external screen and right now only the big screen is active while the laptop has blanked out. Please can someone help me setup my dual screens for 11.10 properly. lspci -v | grep -i vga output 00:02.0 VGA compatible controller: Intel Corporation Mobile 4 Series Chipset Integrated Graphics Controller (rev 07) (prog-if 00 [VGA controller]

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  • Problem with Lenovo x200s Wifi under Ubutu Karmic

    - by oneself
    Hi, I have just gotten my Lenovo X200s laptop, and I am install Ubuntu 9.10 Karmic on it. The installation went through without a hitch, but I can't get my wifi to work. lspci | grep Network Produces the following results: 00:19.0 Ethernet controller: Intel Corporation 82567LM Gigabit Network Connection (rev 03) 03:00.0 Network controller: Realtek Semiconductor Co., Ltd. Device 8172 (rev 10) The weird part is that when I turn the wifi hardware stitch on and off on the side of the laptop, I get the following printed in /var/log messages: Dec 30 23:24:48 temp-laptop kernel: [ 213.432302] usb 4-2: USB disconnect, address 2 Dec 30 23:24:52 temp-laptop kernel: [ 217.276310] usb 4-2: new full speed USB device using uhci_hcd and address 3 Dec 30 23:24:52 temp-laptop kernel: [ 217.441759] usb 4-2: configuration #1 chosen from 1 choice Does Ubuntu think my wifi card is a USB device? Am I missing some driver? What can I do to fix this? Please, help!

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  • How can I get Windows 7 to switch audio from a monitor (with built-in speakers) to headphones when t

    - by tnorthcutt
    I have an HP dv5t laptop running Windows 7 64 bit with an Acer H235H monitor connected to it via an HDMI cable. The monitor has built-in speakers, which are a huge improvement over the laptop's speakers. However, when I want to use headphones, right now, I have to connect them to the laptop, then right-click the sound icon in the task bar, select Playback Devices, right click the monitor, and disable it. Is there any way to get Windows 7 to automatically switch the output to the headphones when they're plugged in? That's the behavior that happens without the monitor attached (i.e. it will switch from the laptop speakers to headphones when headphones are plugged in). I have the same issue with a Sony Vaio laptop running Windows 7 64-bit and an identical monitor, for reference.

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  • USB 3.0 randomly disconnecting and reconnecting

    - by user1624552
    I had an old laptop that died so I have bought a new one. I have taken the 2.5 SATA hard drive from the old laptop and I have put it into an external 2.5 SATA enclosure usb 3.0 and I connect it to the new laptop. My new laptop has Windows 8 64 bit installed. When I connect the external hard drive to the new laptop throught USB 3.0 port, it gets randomly disconnecting and reconnecting continuously, even when I am not using it. Also happens if I connect to another usb 3.0 port. Also I have observed that If I connect the external hard drive to a USB 2.0 port instead of an USB 3.0 port all work ok, no randomly disconnection and reconnection occurs. It only happens when I connect it to an USB 3.0 port. Some ideas to solve this issue?

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  • External monitor turning black intermittently

    - by coding crow
    I have installed an external monitor (Dell ST2220L, 21.5 inch) on my laptop (Sony Vaio). I am using a DVI-D cable for connection. Since the laptop does not have a DVI-D port, I have connected a DVI-D to HDMI connector on the laptop end and inserted the cable in HDMI port of the laptop.. I have switched off the laptop display and adjusted the screen resolution on the Dell external monitor to 1920 x 1080 and adjusted colors for the Windows 7 and brightness and contrast from the monitor. The problem is the monitor turns of blank intermittently for 1-2 seconds and turns on again at random interval. What could be the reason for this and how to get rid of this problem?

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  • Remote connect to mysql server?

    - by LF4
    I've been trying to figure out why I keep getting this error when I try to connect to the MySQL server with the following commands. $~ mysql -u username -h SQLserver -p Enter password: ERROR 1045 (28000): Access denied for user 'username'@'myIP' (using password: YES) I've done the following: Port is open in the firewall other wise I wouldn't get the error it'd just timeout. MySQL server not running with skip-networking or bind-address username has host as '%' and I can connect locally so the password is correct. GRANT USAGE ON *.* TO username@% IDENTIFIED BY 'password'; FLUSH PRIVILEGES; I wanted to know if anyone had ideas or ran into this issue before and solved it? mysql> select user, host from mysql.user where user='username'; +----------+------+ | user | host | +----------+------+ | username | % | +----------+------+ 1 row in set (0.00 sec) mysql> show grants for 'username'; +----------------------------------------------------------------------------------------------------------------+ | Grants for username@% | +----------------------------------------------------------------------------------------------------------------+ | GRANT ALL PRIVILEGES ON *.* TO 'username'@'%' IDENTIFIED BY PASSWORD '*F42AD03PASSWORDHASHADF4021C86B' | | GRANT ALL PRIVILEGES ON `DB2`.* TO 'username'@'%' | +----------------------------------------------------------------------------------------------------------------+ 2 rows in set (0.00 sec)

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  • Limiting what resumes computer from suspend

    - by user1399195
    I'm having a ton of trouble getting Suspend to work with my laptop. I want to start using Ubuntu but this is a pretty important aspect since I take my laptop with me everywhere. Anyways, I wanted to narrow down the possible problem with my laptop. What happens is that when I suspend my computer, within seconds, it just boots back up. I have changed /proc/acpi/wakeup to where everything is disabled but that did nothing. Is there a way where I can disable every feature from waking up the laptop except the power button?

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  • Having problem to login after upgrading from 11.10 to 12.04

    - by LinuxIsMyFriend
    I just update to 12.04 from 11.10 and I get to the login screen w/o problems. When I enter my password the screen turns black and returns to the login screen half a second later. There is a related question out there which was solved by creating more space on the disk but my disks (or rather partitions) are all below 30%. I can log in as guest. I can also login at the cmd prompt (going to tty with Alt+Ctrl+F1) with my normal user credentials. When logged in as guest I can also install programs using my normal account password. There is the normal authentication error when I mistype my password so I'm also sure the password works. Any suggestions?

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  • Cannot change User Accounts settings

    - by eimmy
    I recently changed the name of the administrator and turned off passwords then clicked lock. After some time, I decided to add a password so I clicked on unlock and it's prompting me to enter a password. I tried typing the old password and it didn't accepted it. I also tried to set password and keys as "set to default" but still nothing happened. Now I'm stuck and can't get to change the administrator settings. I did my research but nothing seems to work. Please help.

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  • Is there any remote desktop with sound and video capabilities allowing 2 different users work simultaniousely (a local and a remote one)?

    - by psihodelia
    I have a very powerful PC with Intel processor and a small Mac laptop with PowerPC processor. Both computers are with Ubuntu Linux. Mac laptop cannot play flash videos and I cannot install any Intel-CPU program on it (like Skype). So, it means I can install only open source applications on the laptop from Ubuntu repositories. I have two different Ubuntu system users on PC, say ME and SHE (and root as well :) ). If I work as user ME on PC, then user SHE should also be able to access my PC remotely from her laptop and she should see a desktop of user SHE, not my desktop. She also must be able watch videos, flash, and listen sounds. Is it possible with Ubuntu?

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  • Why my register form don't accept spry validation in dw? [migrated]

    - by shaghayeh
    Why my register form don't accept spry validation in dw? Here is my code: <?php if(isset($_POST['go_register'])) { $last_login=jdate('Y/n/j ,H:i:s'); $firstname=trim($_POST['firstname']); $lastname=trim($_POST['lastname']); $email=trim($_POST['username']); $password=sha1($_POST['password']); $register_date=$_POST['register_date']; if(!empty($firstname)&& !empty($lastname)&& !empty($email)&& !empty($password)&& !empty($register_date)){ $reg_query="insert into users(firstname,lastname,email,password,register_date,last_login)values('$firstname','$lastname','$email','$password','$register_date','$last_login')"; $reg_result=mysqli_query($connection,$reg_query); if($reg_result){ echo "ok"; } }//end of not empty }//end of isset ?> <div class="sectionclass"> <script src="../SpryAssets/SpryValidationTextField.js" type="text/javascript"></script> <link href="../SpryAssets/SpryValidationTextField.css" rel="stylesheet" type="text/css"> <h2>??? ??? ???</h2> <form method="post" action="<?php echo $_SERVER['PHP_SELF']."?catid=2"; ?>"> <div> <span style="color:#F00">*</span> <label>??? </label> <span id="sprytextfield1"> <input type="text" name="firstname" /> <span class="textfieldRequiredMsg">A value is required.</span></span></div> <div> <span style="color:#F00">*</span> <label>??? ????????</label><input type="text" name="lastname" /> </div> <div> <span style="color:#F00">*</span> <label>??? ??????(?????)</label><input dir="ltr" type="text" name="username" /> </div> <div> <span style="color:#F00">*</span> <label>??? ????</label><input type="password" name="password" /> </div> <input type="hidden" name="register_date" value="<?php echo jdate('Y/n/j'); ?>"> <div> <input type="submit" name="go_register" value="??? ???"/> </div> </form> </div> <script type="text/javascript"> var sprytextfield1 = new Spry.Widget.ValidationTextField("sprytextfield1"); </script>

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  • Securing Web Service communication with SSL using CXF

    - by reef
    Hi all, I am trying to secure communications via SSL/TLS for one of our Web Service using CXF 2.2.5. I am wondering how to update client and server Spring configuration file to activate this feature. I found some information on CXF's website (CXF Wiki) for the client configuration, here is the given example: <http:conduit name="{http://apache.org/hello_world}HelloWorld.http-conduit"> <http:tlsClientParameters> <sec:keyManagers keyPassword="password"> <sec:keyStore type="JKS" password="password" file="src/test/java/org/apache/cxf/systest/http/resources/Morpit.jks"/> </sec:keyManagers> <sec:trustManagers> <sec:keyStore type="JKS" password="password" file="src/test/java/org/apache/cxf/systest/http/resources/Truststore.jks"/> </sec:trustManagers> <sec:cipherSuitesFilter> <!-- these filters ensure that a ciphersuite with export-suitable or null encryption is used, but exclude anonymous Diffie-Hellman key change as this is vulnerable to man-in-the-middle attacks --> <sec:include>.*_EXPORT_.*</sec:include> <sec:include>.*_EXPORT1024_.*</sec:include> <sec:include>.*_WITH_DES_.*</sec:include> <sec:include>.*_WITH_NULL_.*</sec:include> <sec:exclude>.*_DH_anon_.*</sec:exclude> </sec:cipherSuitesFilter> </http:tlsClientParameters> <http:authorization> <sec:UserName>Betty</sec:UserName> <sec:Password>password</sec:Password> </http:authorization> <http:client AutoRedirect="true" Connection="Keep-Alive"/> </http:conduit> Concerning this configuration, the Concerning the server side configuration I am unable to launch the server properly, here is the configuration I have: <http:destination name="{urn:ihe:iti:xds-b:2007}DocumentRepository_Port_Soap12.http-destination"> </http:destination> <httpj:engine-factory> <httpj:engine port="9043"> <httpj:tlsServerParameters> <sec:keyManagers keyPassword="changeit"> <sec:keyStore type="JKS" password="changeit" file="security/keystore.jks" /> </sec:keyManagers> <sec:trustManagers> <sec:keyStore type="JKS" password="changeit" file="security/cacerts.jks" /> </sec:trustManagers> <sec:cipherSuitesFilter> <!-- these filters ensure that a ciphersuite with export-suitable or null encryption is used, but exclude anonymous Diffie-Hellman key change as this is vulnerable to man-in-the-middle attacks --> <sec:include>.*_EXPORT_.*</sec:include> <sec:include>.*_EXPORT1024_.*</sec:include> <sec:include>.*_WITH_DES_.*</sec:include> <sec:include>.*_WITH_NULL_.*</sec:include> <sec:exclude>.*_DH_anon_.*</sec:exclude> </sec:cipherSuitesFilter> <sec:clientAuthentication want="true" required="true" /> </httpj:tlsServerParameters> </httpj:engine> </httpj:engine-factory> But when I run my application server (JOnas) with this configuration I have the following error message: Line 20 in XML document from ServletContext resource [/WEB-INF/beans.xml] is invalid; nested exception is org.xml.sax.SAXParseException: cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'httpj:engine-factory'. Do you guys know how to solve this issue? Thanks in advance,

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  • ASP.NET Membership API not working on Win2008 server/IIS7

    - by Program.X
    I have a very odd problem. I have a web app that uses the .NET Membership API to provide login functionality. This works fine on my local dev machine, using WebDev 4.0 server. I'm using .NET 4.0 with some URL Rewriting, but not on the pages where login is required. I have a Windows Server 2008 with IIS7 However, the Membership API seemingly does not work on the server. I have set up remote debugging and the LoginUser.LoggedIn event of the LoginUser control gets fired okay, but the MembershipUser is null. I get no answer about the username/password being invalid so it seems to be recognising it. If I enter an invalid username/password, I get an invalid username/password response. Some code, if it helps: <asp:ValidationSummary ID="LoginUserValidationSummary" runat="server" CssClass="validation-error-list" ValidationGroup="LoginUserValidationGroup"/> <div class="accountInfo"> <fieldset class="login"> <legend>Account Information</legend> <p> <asp:Label ID="UserNameLabel" runat="server" AssociatedControlID="UserName">Username:</asp:Label> <asp:TextBox ID="UserName" runat="server" CssClass="textEntry"></asp:TextBox> <asp:RequiredFieldValidator ID="UserNameRequired" runat="server" ControlToValidate="UserName" CssClass="validation-error" Display="Dynamic" ErrorMessage="User Name is required." ToolTip="User Name is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p> <asp:Label ID="PasswordLabel" runat="server" AssociatedControlID="Password">Password:</asp:Label> <asp:TextBox ID="Password" runat="server" CssClass="passwordEntry" TextMode="Password"></asp:TextBox> <asp:RequiredFieldValidator ID="PasswordRequired" runat="server" ControlToValidate="Password" CssClass="validation-error" Display="Dynamic" ErrorMessage="Password is required." ToolTip="Password is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p> <asp:CheckBox ID="RememberMe" runat="server"/> <asp:Label ID="RememberMeLabel" runat="server" AssociatedControlID="RememberMe" CssClass="inline">Keep me logged in</asp:Label> </p> </fieldset> <p class="login-action"> <asp:Button ID="LoginButton" runat="server" CommandName="Login" CssClass="submitButton" Text="Log In" ValidationGroup="LoginUserValidationGroup"/> </p> and the code behind: protected void Page_Load(object sender, EventArgs e) { LoginUser.LoginError += new EventHandler(LoginUser_LoginError); LoginUser.LoggedIn += new EventHandler(LoginUser_LoggedIn); } void LoginUser_LoggedIn(object sender, EventArgs e) { // this code gets run so it appears logins work Roles.DeleteCookie(); // this behaviour has been removed for testing - no difference } void LoginUser_LoginError(object sender, EventArgs e) { HtmlGenericControl htmlGenericControl = LoginUser.FindControl("errorMessageSpan") as HtmlGenericControl; if (htmlGenericControl != null) htmlGenericControl.Visible = true; } I have "Fiddled" with the Login form reponse and I get the following Cookie-Set headers: Set-Cookie: ASP.NET_SessionId=lpyyiyjw45jjtuav1gdu4jmg; path=/; HttpOnly Set-Cookie: .ASPXAUTH=A7AE08E071DD20872D6BBBAD9167A709DEE55B352283A7F91E1066FFB1529E5C61FCEDC86E558CEA1A837E79640BE88D1F65F14FA8434AA86407DA3AEED575E0649A1AC319752FBCD39B2A4669B0F869; path=/; HttpOnly Set-Cookie: .ASPXROLES=; expires=Mon, 11-Oct-1999 23:00:00 GMT; path=/; HttpOnly I don't know what is useful here because it is obviously encrypted but I find the .APXROLES cookie having no value interesting. It seems to fail to register the cookie, but passes authentication

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  • C#, AES encryption check!

    - by Data-Base
    I have this code for AES encryption, can some one verify that this code is good and not wrong? it works fine, but I'm more concern about the implementation of the algorithm // Plaintext value to be encrypted. //Passphrase from which a pseudo-random password will be derived. //The derived password will be used to generate the encryption key. //Password can be any string. In this example we assume that this passphrase is an ASCII string. //Salt value used along with passphrase to generate password. //Salt can be any string. In this example we assume that salt is an ASCII string. //HashAlgorithm used to generate password. Allowed values are: "MD5" and "SHA1". //SHA1 hashes are a bit slower, but more secure than MD5 hashes. //PasswordIterations used to generate password. One or two iterations should be enough. //InitialVector (or IV). This value is required to encrypt the first block of plaintext data. //For RijndaelManaged class IV must be exactly 16 ASCII characters long. //KeySize. Allowed values are: 128, 192, and 256. //Longer keys are more secure than shorter keys. //Encrypted value formatted as a base64-encoded string. public static string Encrypt(string PlainText, string Password, string Salt, string HashAlgorithm, int PasswordIterations, string InitialVector, int KeySize) { byte[] InitialVectorBytes = Encoding.ASCII.GetBytes(InitialVector); byte[] SaltValueBytes = Encoding.ASCII.GetBytes(Salt); byte[] PlainTextBytes = Encoding.UTF8.GetBytes(PlainText); PasswordDeriveBytes DerivedPassword = new PasswordDeriveBytes(Password, SaltValueBytes, HashAlgorithm, PasswordIterations); byte[] KeyBytes = DerivedPassword.GetBytes(KeySize / 8); RijndaelManaged SymmetricKey = new RijndaelManaged(); SymmetricKey.Mode = CipherMode.CBC; ICryptoTransform Encryptor = SymmetricKey.CreateEncryptor(KeyBytes, InitialVectorBytes); MemoryStream MemStream = new MemoryStream(); CryptoStream CryptoStream = new CryptoStream(MemStream, Encryptor, CryptoStreamMode.Write); CryptoStream.Write(PlainTextBytes, 0, PlainTextBytes.Length); CryptoStream.FlushFinalBlock(); byte[] CipherTextBytes = MemStream.ToArray(); MemStream.Close(); CryptoStream.Close(); return Convert.ToBase64String(CipherTextBytes); } public static string Decrypt(string CipherText, string Password, string Salt, string HashAlgorithm, int PasswordIterations, string InitialVector, int KeySize) { byte[] InitialVectorBytes = Encoding.ASCII.GetBytes(InitialVector); byte[] SaltValueBytes = Encoding.ASCII.GetBytes(Salt); byte[] CipherTextBytes = Convert.FromBase64String(CipherText); PasswordDeriveBytes DerivedPassword = new PasswordDeriveBytes(Password, SaltValueBytes, HashAlgorithm, PasswordIterations); byte[] KeyBytes = DerivedPassword.GetBytes(KeySize / 8); RijndaelManaged SymmetricKey = new RijndaelManaged(); SymmetricKey.Mode = CipherMode.CBC; ICryptoTransform Decryptor = SymmetricKey.CreateDecryptor(KeyBytes, InitialVectorBytes); MemoryStream MemStream = new MemoryStream(CipherTextBytes); CryptoStream cryptoStream = new CryptoStream(MemStream, Decryptor, CryptoStreamMode.Read); byte[] PlainTextBytes = new byte[CipherTextBytes.Length]; int ByteCount = cryptoStream.Read(PlainTextBytes, 0, PlainTextBytes.Length); MemStream.Close(); cryptoStream.Close(); return Encoding.UTF8.GetString(PlainTextBytes, 0, ByteCount); } Thank you

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  • Moving from MySQL to MySQLi? I have the code here but I don't get it

    - by MuqMan
    I have posted the code there, please help me out as I am a newbie, I don't know much in terms of deprecation and stuff. <?php session_start(); include('settings.php'); $issub = $_POST['issub']; if($issub == "yes") { require('settings.php'); $dbcon = mysql_connect($dbhost, $dbuser, $dbpword); if(!dbcon) { die('Could not connect'.mysql_error()); } $selectdb = mysql_select_db($db, $dbcon); $formset = 'yes'; $val = 0; $user = trim($_POST['username'], ' '); $luser = mysql_real_escape_string($user); $password = $_POST['password']; $lpassword = mysql_real_escape_string($password); $selectdb; $userq = mysql_query("SELECT user FROM users WHERE user='".$luser."'"); $userresult = @mysql_result($userq, 0); //echo $userresult; if($userresult == $user) { $val = $val + 1; $usercorrect = 'yes'; } else { $usercorrect = 'no'; } $dbselect; $passwordq = mysql_query("SELECT password FROM users where user='".$luser."'"); $passresult = @mysql_result($passwordq, 0); if($passresult == sha1($password)) { $val = $val + 1; $passcorrect = 'yes'; } else { $passcorrect = 'no'; } if ($val == 2) { $_SESSION['loggedin'] = 'yes'; $_SESSION['uloggedin'] = $user; header('location: logged.php'); } }?> <?php ini_set('display_errors', 1); require('testinclude.php'); ?> <body> <div id="loginform"> <form action="/login.php" method="post" > <input type="hidden" name="issub" value="yes" /> <?php if($usercorrect == 'no') { echo '<span class="required"><i><small>The email address or password you entered is incorrect, please try again.</a></small></i></span>'; } ?> <br /> email: <?php if ($issub == 'yes') { if($user == null){ echo '<br /><span class="required"><i><small>Please enter your email address</a></small></i></span>'; } } ?> <br /><input type="text" name="username" id="usename" /> <br /> password: <br /><input type="password" name="password" id="password" /> <br /> <input type="submit" value="login" /> </form> <div> </body>

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  • expanding/collapsing div using jQuery

    - by Hristo
    I'm trying to expand and collapse a <div> by clicking some text inside the <div>. The behavior right now is very odd. For example, if I click the text after the <div> is expanded... the <div> will collapse and then expand again. Also, if I click somewhere inside the div after it is expanded, it will collapse again, and I think that is because I'm triggering the animation since the <div> being animated is inside the wrapper <div>. Here's the code: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>Insert title here</title> <!-- Links --> <link rel="stylesheet" type="text/css" href="style.css" /> <!-- Scripts --> <script type="text/javascript" src="jQuery.js"></script> <script> // document script $(function(){ // login box event handler $('#login').click(function() { $('#loginBox').toggle( function() { $('.loginBox').animate({ height: '150px' }, '1000' ); $('#username').show(); $('#password').hide(); $('#placeHolder').show(); }, function() { $('.loginBox').animate({ height: '50px' }, '1000' ); $('#username').hide(); $('#password').hide(); $('#placeHolder').hide(); } ); }); // username field focus and blur event handlers $('#username').focus(function() { if($(this).hasClass('placeHolder')){ $(this).val(''); $(this).removeClass('placeHolder'); } }); $('#username').blur(function() { if($(this).val() == '') { $(this).val('Username'); $(this).addClass('placeHolder'); } }); // password field focus and blur event handlers $('#placeHolder').focus(function() { $(this).hide(); $('#password').show(); $('#password').focus(); $('#password').removeClass('placeHolder'); }); $('#password').blur(function() { if($(this).val() == '') { $('#placeHolder').show(); $(this).hide(); } }); }); </script> </head> <body> <div id="loginBox" class="loginBox"> <a id="login" class="login">Proceed to Login</a><br /> <div> <form> <input type="text" id="username" class="placeHolder" value="Username" /> <input type="password" id="password" class="placeHolder" value="" /> <input type="text" id="placeHolder" class="placeHolder" value="Password" /> </form> </div> </div> </body> </html> Any ideas? Thanks, Hristo

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  • Multi tenant membership provider ASP.NET MVC

    - by Masna
    Hello, I'm building a multi-tenant app with ASP.NET MVC and have a problem with validating users. Situation I have: -a table with User(ID, Name, FirstName, Email) This table is made, so that a users who is registered in two tenants doesn't need to login again. -a table with Tentantuser(ID, TenantID, UserID (FK to table User), UserName, Loginname, Password, Active) This table contains de login en password for one tenant. Example: UserX is registered in TenantA and TenantB UserX logs in on TenantA, with his login and password for TenantA System verifies or login and password are correct in the table TenantUser System validates UserX which userID corresponds to the Id in the table User UserX goes to TenantB and is automatically logged in My problem: How can I create a custom Provider so I can check the login & password in a tenant? For example: public abstract bool ValidateUser(string username,string password); How can I say to my provider on which tenant the user is? How can I change this in something like: public overrides bool ValidateUser(string username,string password, string tenant); ? Or what is another way to solve this issue?

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  • ASP.NET MVC Page - hyper links in HTML.ValidationSummary

    - by Rita
    Hi I have Registration page and if the validation fails, it displays the error messages using HTML.ValidationSummary control. Now i have to display the Hyperlink in that Validation Error Message. But it is treating href also as string. The Validation Message that I am trying to display with hyperlink is: **"User already exists in the system, please <a href='../Login.aspx'>login</a>"** Appreciate your responses. Here is my Code: <% using (Html.BeginForm()) {%> <%= Html.ValidationSummary(false) %> <fieldset> <div class="cssform">; <p> <%= Html.LabelFor(model => model.email)%><em>*</em> <%= Html.TextBoxFor(model => model.email, new { @class = "required email" })%> <%= Html.ValidationMessageFor(model => model.email)%> </p> <p> <%= Html.Label("Confirm email")%><em>*</em> <%= Html.TextBox("confirm_email")%> <%= Html.ValidationMessage("confirm_email") %> </p> <p> <%= Html.Label("Password")%><em>*</em> <%= Html.Password("Password", null, new { @class = "required" })%> <%= Html.ValidationMessage("Password")%><br /> (Note: Password should be minimum 6 characters) </p> <p> <%= Html.Label("Confirm Password")%><em>*</em> <%= Html.Password("confirm_password")%> <%= Html.ValidationMessage("confirm_password") %> </p><hr /> <% } %

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  • XMPP SASL authentication on Ejabberd with PHP

    - by bucabay
    I'm trying to authenticate with an XMPP server using SASL. /** * Send Authentication, SASL * @return Bool * @param $username String * @param $password String */ function authenticate($username, $password) { $this->username = $username; $this->password = $password; var_dump($username, $password, $this->domain); $auth = base64_encode($username.'@'.$this->domain."\u0000".$username."\u0000".$password); $xml = '<auth mechanism="PLAIN" xmlns="urn:ietf:params:xml:ns:xmpp-sasl">'.$auth.'</auth>'; if ($this->write($xml)) { if ($xml = $this->listen(1, true)) { if (preg_match("/<success/i", $xml)) { $this->authenticated = $this->_sendStream(); } } } $this->events->trigger('authenticate', $this->authenticated); return $this->authenticated; } The XMPP server however responds with: <failure xmlns='urn:ietf:params:xml:ns:xmpp-sasl'><bad-protocol/></failure> This is against an Ejabberd server. When I open the XMPP stream, it advertises: <stream:features><starttls xmlns='urn:ietf:params:xml:ns:xmpp-tls'/><mechanisms xmlns='urn:ietf:params:xml:ns:xmpp-sasl'><mechanism>DIGEST-MD5</mechanism><mechanism>PLAIN</mechanism></mechanisms><register xmlns='http://jabber.org/features/iq-register'/></stream:features> So it seams to me that SASL - PLAIN should work. I have a JavaScript version, that works perfectly on OpenFire server. (I can't test it on Ejabberd at the moment) sendAuthentication: function() { clearTimeout(XMPP.sendAuthentication_timer); var auth = Base64.encode(XMPP.username+'@'+XMPP.domain+'\u0000'+XMPP.username+'\u0000'+XMPP.password); mySocket.events.receive.observe(XMPP.receivedAuthSuccess, function() { mySocket.send('<auth mechanism="PLAIN" xmlns="urn:ietf:params:xml:ns:xmpp-sasl">' + auth + '</auth>'); }); } So I can't get why the PHP version is not working.

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  • how does hash element make a secure login on zend framework?

    - by ulduz114
    hello all i saw a example for login form same blow code class Form_Login extends Zend_Form { //put your code here public function init($timeout=360){ $this->addElement('hash', 'token', array( 'timeout' => $timeout )); $this->setName('Login'); $username = $this->createElement ( 'text', 'username' ); $username->setLabel('user name:') ->setRequired(); $this->addElement($username); $password=$this->createElement('password','password'); $password->setLabel('password:'); $password->setRequired(); $this->addElement($password); $login=$this->createElement('submit','login'); $login->setLabel('Login'); $this->addElement($login); $this->setMethod('post'); $this->setAction(Zend_Controller_Front::getInstance()->getBaseUrl().'/authentication/login'); } } and in submitAction a part code same below if (!$form->isValid($request->getPost())) { if (count($form->getErrors('token')) > 0) { return $this->_forward('csrf-forbidden', 'error'); } $this->view->form = $form; return $this->render('login'); } now , my question, whats the reason for use of hash element? how this hash element make secure login? anybody may help explain these? thanks

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  • Asp.net Login Status Question: It Aint Working

    - by contactmatt
    I'm starting to use Role Management in my website, and I'm current following along on the tutorial from http://www.asp.net/Learn/Security/tutorial-02-vb.aspx . I'm having a problem with the asp:LoginStatus control. It is not telling me that I am currently logged in after a successful login. This can't be true because after successfully logging in, my LoggedInTemplate is shown. The username and passwords are simply stored in a array. Heres the Login.aspx page code. Protected Sub btnLogin_Click(ByVal sender As Object, ByVal e As System.EventArgs) _ Handles btnLogin.Click ' Three valid username/password pairs: Scott/password, Jisun/password, and Sam/password. Dim users() As String = {"Scott", "Jisun", "Sam"} Dim passwords() As String = {"password", "password", "password"} For i As Integer = 0 To users.Length - 1 Dim validUsername As Boolean = (String.Compare(txtUserName.Text, users(i), True) = 0) Dim validPassword As Boolean = (String.Compare(txtPassword.Text, passwords(i), False) = 0) If validUsername AndAlso validPassword Then FormsAuthentication.RedirectFromLoginPage(txtUserName.Text, chkRemember.Checked) End If Next ' If we reach here, the user's credentials were invalid lblInvalid.Visible = True End Sub Here is the content place holder on the master page specifically designed to hold Login Information. On successfull login, the page is redirected to '/Default.aspx', and the LoggedIn Template below is shown...but the status says Log In. <asp:ContentPlaceHolder Id="LoginContent" runat="server"> <asp:LoginView ID="LoginView1" runat="server"> <LoggedInTemplate> Welcome back, <asp:LoginName ID="LoginName1" runat="server" />. </LoggedInTemplate> <AnonymousTemplate> Hello, stranger. </AnonymousTemplate> </asp:LoginView> <br /> <asp:LoginStatus ID="LoginStatus1" runat="server" LogoutAction="Redirect" LogoutPageUrl="~/Logout.aspx" /> </asp:ContentPlaceHolder> Forms authentication is enabled. I'm not sure what to do about this :o.

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