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  • after return PartialView() Url.Actionlink("Action", "Controller"), the Controller is lost

    - by Johannes
    Well the Question is related to a problem I posted before (http://stackoverflow.com/questions/2403899/asp-net-mvc-partial-view-does-not-call-my-action). In practice I've a partial view which contains a Form, after submitting the Form the Controller returns the Partial View. Well the Problem is if I reload the page which contains the partial view the function <%= Url.Action("ChangePassword", "Account") %> returns "Account/ChangePassword", if I submit the form and the partial is returned by the controller. Using return PartialView() the function <%= Url.Action("ChangePassword", "Account") %> returns only "ChangePassword". Any Idea because? The View looks like: <form action="<%= Url.Action("ChangePassword", "Account") %>" method="post" id="jform"> <div> <fieldset> <legend>Account Information</legend> <p> <label for="currentPassword">Current password:</label> <%= Html.Password("currentPassword") %> <%= Html.ValidationMessage("currentPassword") %> </p> <p> <label for="newPassword">New password:</label> <%= Html.Password("newPassword") %> <%= Html.ValidationMessage("newPassword") %> </p> <p> <label for="confirmPassword">Confirm new password:</label> <%= Html.Password("confirmPassword") %> <%= Html.ValidationMessage("confirmPassword") %> </p> <p> <input type="submit" value="Change Password" /> </p> </fieldset> </div> </form> </div> <script> $(function() { $('#jform').submit(function() { $('#jform').ajaxSubmit({ target: '#FmChangePassword' }); return false; }); }); </script> Part of the Controller: if (!ValidateChangePassword(currentPassword, newPassword, confirmPassword)) { return PartialView(ViewData); }

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  • How to use Bouncy Castle lightweight API with AES and PBE

    - by Adrian
    I have a block of ciphertext that was created using the JCE algorithim "PBEWithSHA256And256BitAES-CBC-BC". The provider is BouncyCastle. What I'd like to do it decrypt this ciphertext using the BouncyCastle lightweight API. I don't want to use JCE because that requires installing the Unlimited Strength Jurisdiction Policy Files. Documentation seems to be thin on the ground when it comes to using BC with PBE and AES. Here's what I have so far. The decryption code runs without exception but returns rubbish. The encryption code, String password = "qwerty"; String plainText = "hello world"; byte[] salt = generateSalt(); byte[] cipherText = encrypt(plainText, password.toCharArray(), salt); private static byte[] generateSalt() throws NoSuchAlgorithmException { byte salt[] = new byte[8]; SecureRandom saltGen = SecureRandom.getInstance("SHA1PRNG"); saltGen.nextBytes(salt); return salt; } private static byte[] encrypt(String plainText, char[] password, byte[] salt) throws NoSuchAlgorithmException, InvalidKeySpecException, NoSuchPaddingException, InvalidKeyException, InvalidAlgorithmParameterException, IllegalBlockSizeException, BadPaddingException { Security.addProvider(new BouncyCastleProvider()); PBEParameterSpec pbeParamSpec = new PBEParameterSpec(salt, 20); PBEKeySpec pbeKeySpec = new PBEKeySpec(password); SecretKeyFactory keyFac = SecretKeyFactory.getInstance("PBEWithSHA256And256BitAES-CBC-BC"); SecretKey pbeKey = keyFac.generateSecret(pbeKeySpec); Cipher encryptionCipher = Cipher.getInstance("PBEWithSHA256And256BitAES-CBC-BC"); encryptionCipher.init(Cipher.ENCRYPT_MODE, pbeKey, pbeParamSpec); return encryptionCipher.doFinal(plainText.getBytes()); } The decryption code, byte[] decryptedText = decrypt(cipherText, password.getBytes(), salt); private static byte[] decrypt(byte[] cipherText, byte[] password, byte[] salt) throws DataLengthException, IllegalStateException, InvalidCipherTextException, InvalidKeyException, NoSuchAlgorithmException, NoSuchPaddingException, IllegalBlockSizeException, BadPaddingException { BlockCipher engine = new AESEngine(); CBCBlockCipher cipher = new CBCBlockCipher(engine); PKCS5S1ParametersGenerator keyGenerator = new PKCS5S1ParametersGenerator(new SHA256Digest()); keyGenerator.init(password, salt, 20); CipherParameters keyParams = keyGenerator.generateDerivedParameters(256); cipher.init(false, keyParams); byte[] decryptedBytes = new byte[cipherText.length]; int numBytesCopied = cipher.processBlock(cipherText, 0, decryptedBytes, 0); return decryptedBytes; }

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  • ASP.NET MVC partial view does not call my Action

    - by Johannes
    I just started building a small simple Website on ASP.NET MVC, in a page I am using a Partial view, the Partial View represents a simple Form which should be submitted on button click, and If I click the first Time it is submitted with success and does return my partial view with my validation Messages (if the content is invalid) but if I wish to try again the Action isn't called again. Any Idea? View: <form action="<%= Url.Action("ChangePassword", "Account") %>" method="post" id="jform"> <div> <fieldset> <legend>Account Information</legend> <p> <label for="currentPassword">Current password:</label> <%= Html.Password("currentPassword") %> <%= Html.ValidationMessage("currentPassword") %> </p> <p> <label for="newPassword">New password:</label> <%= Html.Password("newPassword") %> <%= Html.ValidationMessage("newPassword") %> </p> <p> <label for="confirmPassword">Confirm new password:</label> <%= Html.Password("confirmPassword") %> <%= Html.ValidationMessage("confirmPassword") %> </p> <p> <input type="submit" value="Change Password" /> </p> </fieldset> </div> </form> <!--<% } %>--> </div> <script> $(function() { $('#jform').submit(function() { $('#jform').ajaxSubmit({ target: '#FmChangePassword' }); return false; }); }); /*$(document).ready(function() { $('#jform').live('submit', function() { $.post($(this).attr('action'), $(this).serialize(), function(data) { $("#jform").replaceWith($(data)); }); return false; }); });*/ </script> Part of the Controller: if (!ValidateChangePassword(currentPassword, newPassword, confirmPassword)) { return PartialView(ViewData); }

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  • Login Script for PostGreSQL and PHP not working =[

    - by MrEnder
    Ok I'm quite new at logins what not so bare with me here lol but I gota learn so don't discourage me. I tried this so far <?php $error = ""; $conn = pg_connect("host=localhost dbname=brittains_db user=brittains password=XXXX" ); $sql = "SELECT * FROM logins"; $result = pg_query($conn, $sql); if($_SERVER["REQUEST_METHOD"] == "GET") { $userName=""; $password=""; } else if($_SERVER["REQUEST_METHOD"] == "POST") { $userName=trim($_POST["userNameLogin"]); $password=trim($_POST["passwordLogin"]); if(pg_fetch_result($results, $userName, "userName")==true && pg_fetch_result($results, $password, "userName")==true) { setcookie("userIDforDV", $userName, time()+43200); } else { $error = "Your username and or password is incorrect"; } } $userName = $_COOKIE['userIDforDV']; if(isset($userName) && $userName!="") { echo "Welcome " . $userName; } echo $error; ?> <form> <table> <tr> <td class="signupTd"> User Name:&nbsp; </td> <td> <input type="text" name="userNameLogin" value="" size="20" /> </td> </tr> <tr> <td class="signupTd"> Password:&nbsp; </td> <td> <input type="password" name="passwordLogin" value="" size="20" /> </td> </tr> <tr> <td class="signupTd" colspan="2"> <input type="submit" name="submit" value="Submit"/> </td> </tr> </table> </form> that was the idea I came up with... but its prolly a really bad idea and it doesn't work... how might I go about this properly? I need really detailed descriptions please. Thanks a tun Shelby

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  • Issues with Rails 3.1 API with Query String to Create action on Mac OSX Mountain Lion

    - by hjaved
    Hi I've been stuck on this problem for a while and would appreciate your help. I'm writing an API to allow an external source like a Browser Query String or a smartphone to enter some model User info in a form and hit the User create action to write the data to the db. Please tell me what I'm doing wrong with the code below. I've also observed that if I have code like @user = User.new(params[:user]), that this approach only works when a user enters their data within the form. And that if I have code such as @user = User.new( name: params[:name], location: params[:location], password = params[:password], email: params[:email]), that this code ONLY works for a Query string entry, but NOT both Query string AND regular form submission. Why is that and how can I write the code above in the Users Controller Create action, so that it takes care of both situations? URL used: localhost:3000/users/create?name=John&&[email protected]&&password=secret&&location=SanFrancisco&date=06122012 The date is of type string but it doesn't show up in the database. Why? Everything else does. UsersController.rb def create @user = User.new(params[:user]) if @user.save session[:uid] = @user.id redirect_to thanks_path, notice: "Welcome #{@user.name}!" else redirect_to root_path end end New User Form: <%=u.text_field :name, placeholder: "Name"%><br> <%=u.text_field :email, placeholder: "Email"%><br> <%=u.password_field :password, placeholder: "Password"%><br> <%=u.text_field :location, placeholder: "City"%><br> <%=u.text_field :date, placeholder: "Date"%><br> <%if params[:partner_id]%> <%=u.hidden_field :partner_id, value: params[:partner_id]%> <%end%> <button class="btn btn-large btn-primary">Enter</button> I also tried to create a separate method called remotecreate for User creation for something other than a regular web form. I entered remotecreate in the Query string but it didn't work. def remotecreate @user = User.create(name: params[:name], email: params[:email], password: params[:password], location: params[:location], date: params[:date]) if @user.save session[:uid] = @user.id redirect_to thanks_path, notice: "Welcome #{@user.name}" else redirect_to root_path end end Thanks!

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  • Problem to focus JTextField

    - by Tom Brito
    I have used the approach of the ComponentListener to call focus in JTextField within a dialog, but for this case is just not working, I don't know why. It shows the focus in the text field and fast change to the button. Run and see: import java.awt.Component; import java.awt.GridLayout; import java.awt.event.ComponentEvent; import java.awt.event.ComponentListener; import javax.swing.JDialog; import javax.swing.JLabel; import javax.swing.JOptionPane; import javax.swing.JPanel; import javax.swing.JPasswordField; import javax.swing.JTextField; public class User { private String username = ""; private String password = ""; public User() { // default constructor } public User(String username, String password) { this.username = username; this.password = password; } /** Create a panel containing the componet and tha label. */ public JPanel createLabeledComponent(JLabel label, Component comp) { GridLayout layout = new GridLayout(2, 1); JPanel panel = new JPanel(layout); panel.add(label); panel.add(comp); label.setLabelFor(comp); return panel; } public void showEditDialog() { JLabel usernameLbl = new JLabel(username); final JTextField usernameField = new JTextField(); usernameField.setText(username); JPanel usernamePnl = createLabeledComponent(usernameLbl, usernameField); JLabel passwordLbl = new JLabel(password); JPasswordField passwordField = new JPasswordField(password); JPanel passwordPnl = createLabeledComponent(passwordLbl, passwordField); Object[] fields = { "User:", usernamePnl, "Password:", passwordPnl }; JOptionPane optionPane = new JOptionPane(fields, JOptionPane.PLAIN_MESSAGE, JOptionPane.OK_CANCEL_OPTION, null, null); JDialog dialog = optionPane.createDialog("User Data"); dialog.addComponentListener(new ComponentListener() { public void componentShown(ComponentEvent e) { usernameField.requestFocusInWindow(); } public void componentResized(ComponentEvent e) {} public void componentMoved(ComponentEvent e) {} public void componentHidden(ComponentEvent e) {} }); dialog.setVisible(true); } public static void main(String[] args) { new User().showEditDialog(); } } Any idea how to solve this?

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  • An AuthLogic form is giving me incorrect validation errors -- why?

    - by sscirrus
    Hi everyone, I set up AuthLogic for Rails according to the AuthLogic example: http://github.com/binarylogic/authlogic_example. I can log on successfully to the system, but when accessing users/new.html.erb to register a new user, the form returns the following validation errors: Email is too short (minimum is 6 characters) Email should look like an email address. Login is too short (minimum is 3 characters) Login should use only letters, numbers, spaces, and .-_@ please. Password is too short (minimum is 4 characters) Password confirmation is too short (minimum is 4 characters) None of these errors exist in the data I am entering. # new.html.erb <%= form.label :login, nil, :class => "label" %><br /> <%= form.text_field :login, :class => "inputBox", :name => "login", :type => "text" %><br /> <%= form.label :password, form.object.new_record? ? nil : "Change password", :class => "label" %><br /> <%= form.password_field :password, :class => "inputBox", :name => "password", :type => "text" %><br /> <%= form.label "Confirm password", nil, :class => "label" %><br /> <%= form.password_field :password_confirmation, :class => "inputBox", :name => "password_confirmation", :type => "text" %><br /> <%= form.label :email, nil, :class => "label" %><br /> <%= form.text_field :email, :class => "inputBox", :name => "email", :type => "text" %><br /> # Users controller def new @user = User.new render :layout => "forms" end I think the problem is that the data isn't being transferred somehow and therefore AuthLogic doesn't think the inputs are sufficient. Do you have any idea why AuthLogic is telling me the data doesn't satisfy its validation?

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  • Simaltaneous connections with PHP and SOAP?

    - by Dov
    I'm new to using SOAP and understanding the utmost basics of it. I create a client resource/connection, I then run some queries in a loop and I'm done. The issue I am having is when I increase the iterations of the loop, ie: from 100 to 1000, it seems to run out of memory and drops an internal server error. How could I possibly run either a) multiple simaltaneous connections or b) create a connection, 100 iterations, close connection, create connection.. etc. "a)" looks to be the better option but I have no clue as to how to get it up and running whilst keeping memory (I assume opening and closing connections) at a minimum. Thanks in advance! index.php <?php // set loops to 0 $loops = 0; // connection credentials and settings $location = 'https://theconsole.com/'; $wsdl = $location.'?wsdl'; $username = 'user'; $password = 'pass'; // include the console and client classes include "class_console.php"; include "class_client.php"; // create a client resource / connection $client = new Client($location, $wsdl, $username, $password); while ($loops <= 100) { $dostuff; } ?> class_console.php <?php class Console { // the connection resource private $connection = NULL; /** * When this object is instantiated a connection will be made to the console */ public function __construct($location, $wsdl, $username, $password, $proxyHost = NULL, $proxyPort = NULL) { if(is_null($proxyHost) || is_null($proxyPort)) $connection = new SoapClient($wsdl, array('login' => $username, 'password' => $password)); else $connection = new SoapClient($wsdl, array('login' => $username, 'password' => $password, 'proxy_host' => $proxyHost, 'proxy_port' => $proxyPort)); $connection->__setLocation($location); $this->connection = $connection; return $this->connection; } /** * Will print any type of data to screen, where supported by print_r * * @param $var - The data to print to screen * @return $this->connection - The connection resource **/ public function screen($var) { print '<pre>'; print_r($var); print '</pre>'; return $this->connection; } /** * Returns a server / connection resource * * @return $this->connection - The connection resource */ public function srv() { return $this->connection; } } ?>

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  • Combined sign in and registration page?

    - by Ryan
    This is somewhat against rails convention but I am trying to have one controller that manages both user session authentication and user registration. I am having troubles figuring out how to go about this. So far I am merging the User Controller and the Sessions Controller and having the 'new' method deliver both a new usersession and a new user instance. With the new routes in rails 3 though, I am having trouble figuring out how to generate forms for these items. Below is the code: user_controller.rb class UserController < ApplicationController def new @user_session = UserSession.new @user = User.new end def create_user @user = User.new(params[:user]) if @user.save flash[:notice] = "Account Successfully Registered" redirect_back_or_default signup_path else render :action => new end end def create_session @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Login successful!" redirect_back_or_default login_path else render :action => new end end end views/user/new.html.erb <div id="login_section"> <% form_for @user_session do |f| -%> <%= f.label :email_address, "Email Address" %> <%= f.text_field :email %> <%= f.label :password, "Password" %> <%= f.text_field :password %> <%= f.submit "Login", :disable_with => 'Logining...' %> <% end -%> </div> <div id="registration_section"> <% form_for @user do |f| -%> <%= f.label :email_address, "Email Address" %> <%= f.text_field :email %> <%= f.label :password, "Password" %> <%= f.text_field :password %> <%= f.label :password_confirmation, "Password Confirmation" %> <%= f.text_field :password_confirmation %> <%= f.submit "Register", :disable_with => 'Logining...' %> <% end -%> </div> I imagine I will need to use :url = something for those forms, but I am unsure how to specify. Within routes.rb I have yet to specify either Usersor UserSessions as resources (not convinced that this is the best way to do it... but I could be). I would like, however, the registration and login on the same page and have implemented this by doing the following: routes.rb match 'signup' => 'user#new' match 'login' => 'user#new' What's the best way to go about solving this?

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  • How to navigate to another html page?

    - by newbie
    In my application there's a usual login page sending username and password to the server script, where it needs to be authenticated, and in case of an authentic user, the server should redirect to a page student.html. This is my code var ports = 3000; var portt = 3001; var express = require('express'); var student = require('express')(); var teacher = require('express')(); var server_s = require('http').createServer(student); var server_t = require('http').createServer(teacher); var ios = require('socket.io').listen(server_s); var iot = require('socket.io').listen(server_t); var path = require('path'); server_s.listen(ports); server_t.listen(portt); student.use(express.static(path.join(__dirname, 'public'))); student.get('/', function(req,res){ res.sendfile(__dirname + '/login.html'); }); teacher.use(express.static(path.join(__dirname, 'public'))); teacher.get('/', function(req,res){ res.sendfile(__dirname + '/mytry.html'); }); ios.sockets.on('connection', function(socket){ var username, password; socket.on('check',function(data){ username = data[0]; password = data[1]; //************* Database connection and query ************* var mysql = require('mysql'); var connection = mysql.createConnection({ host : 'localhost', user : 'user', password: '*******', database: 'my_db' }); connection.connect(); var qstring = 'SELECT s_id FROM login_student WHERE username='+username+'AND password='+password; connection.query(qstring, function(err, rows, fields) { if (err) { console.log('ERROR: ' + err); socket.emit('login_failure','DB error'); return; } console.log('The solution is: ', rows[0].solution); if (rows>0) //***** Here i want redirection to another page ****** else socket.emit('login_failure','Invalid Username or password'); }); connection.end(); }); }); iot.sockets.on('connection', function(socket){ ; }); }); Can anyone suggest what should I do?

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  • Why i get everytime the error-message that i've already sent the headers

    - by mikep
    Hey, i've another question about web-programming. I programmed a login script, but everytime when i try to login it says that i've send the header informations already. Here are the 2 files: <?php if($_GET['logout'] == 1) { setcookie('authorized', 1, time()-3600); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Login - photoAdminSite</title> </head> <style type="text/css"> body { text-align: center; font-family: helvetica; } #loginForm { padding: 1em; background: #e3e3e3; width: 260px; margin: 3em auto 0; text-align: left; } </style> <body> <div id="loginForm"> <form method="post" action="confirm_login_credentials.php"> <h2>LOGIN</h2> <p>Username: <input type="text" name="username" /></p> <p>Password: <input type="password" name="password" /></p> <p><input type="submit" value="Login" name="submit" /></p> </form> </div> </body> </html> <?php $username = $_POST['username']; $password = $_POST['password']; require 'database.php'; $q = "SELECT id FROM users_photoadminsite WHERE user_name = '$username' AND password = '$password'"; $result = $mysqli->query($q) or die(mysqli_error()); if (mysqli_num_rows($result) == 1) { setcookie('authorized', 1, 0); header("Location: index.php"); } else { header("Location: login.php"); } ?> i would be really happy about some helpful answers.

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  • How can I set an image for background of GUI interface?

    - by enriched
    hey everyone, im having some troubles displaying the background image for a GUI interface in java. Here is what i have at the moment, and with current stage of code it shows default(gray) background. import javax.swing.*; import java.awt.event.*; import java.util.Scanner; import java.awt.*; import java.io.File; import javax.imageio.ImageIO; import java.awt.image.BufferedImage; import java.io.IOException; ////////////////////////////////// // 3nriched Games Presents: // // MIPS The Mouse!! // ////////////////////////////////// public class mipsMouseGUI extends JFrame implements ActionListener { private static String ThePDub = ("mouse"); //the password JPasswordField pass; JPanel panel; JButton btnEnter; JLabel lblpdub; public mipsMouseGUI() { BufferedImage image = null; try { //attempts to read picture from the folder image = ImageIO.read(getClass().getResource("/mousepics/mousepic.png")); } catch (IOException e) { //catches exceptions e.printStackTrace(); } ImagePanel panel = new ImagePanel(new ImageIcon("/mousepics/neonglowOnwill.png").getImage()); setIconImage(image); //sets icon picture setTitle("Mips The Mouse Login"); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); pass = new JPasswordField(5); //sets password length to 5 pass.setEchoChar('@'); //hide characters as @ symbol pass.addActionListener(this); //adds action listener add(panel); //adds panel to frame btnEnter = new JButton("Enter"); //creates a button btnEnter.addActionListener(this);// Register the action listener. lblpdub = new JLabel(" Your Password: "); // label that says enter password panel.add(lblpdub, BorderLayout.CENTER);// adds label and inputbox panel.add(pass, BorderLayout.CENTER); // to panel and sets location panel.add(btnEnter, BorderLayout.CENTER); //adds button to panel pack(); // packs controls and setLocationRelativeTo(null); // Implicit "this" if inside JFrame constructor. setVisible(true);// makes them visible (duh) } public void actionPerformed(ActionEvent a) { Object source = a.getSource(); //char array that holds password char[] passy = pass.getPassword(); //characters array to string String p = new String(passy); //determines if user entered correct password if(p.equals(ThePDub)) { JOptionPane.showMessageDialog(null, "Welcome beta user: USERNAME."); } else JOptionPane.showMessageDialog(null, "You have enter an incorrect password. Please try again."); } public class ImagePanel extends JPanel { private BufferedImage img; public ImagePanel(String img) { this(new ImageIcon(img).getImage()); } public ImagePanel(Image img) { Dimension size = new Dimension(img.getWidth(null), img.getHeight(null)); } public void paintComponent(Graphics g) { g.drawImage(img, 0, 0, null); } } }

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  • Linking Post Title to Specific Page ID

    - by ThatMacLad
    I've created a form to update my websites homepage with content but I wanted to know how I could set it up so that a posts title links to a specific post ID. I'd also like to add a Read More link that directs anybody reading the blog to the correct post. Here is my PHP code: <html> <head> <title>Blog Name</title> </head> <body> <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "SELECT * FROM php_blog ORDER BY timestamp DESC LIMIT 5"; $result = mysql_query($sql) or print ("Can't select entries from table php_blog.<br />" . $sql . "<br />" . mysql_error()); while($row = mysql_fetch_array($result)) { $date = date("l F d Y", $row['timestamp']); $title = stripslashes($row['title']); $entry = stripslashes($row['entry']); $password = $row['password']; $id = $row['id']; if ($password == 1) { echo "<p><strong>" . $title . "</strong></p>"; printf("<p>This is a password protected entry. If you have a password, log in below.</p>"); printf("<form method=\"post\" action=\"post.php?id=%s\"><p><strong><label for=\"username\">Username:</label></strong><br /><input type=\"text\" name=\"username\" id=\"username\" /></p><p><strong><label for=\"pass\">Password:</label></strong><br /><input type=\"password\" name=\"pass\" id=\"pass\" /></p><p><input type=\"submit\" name=\"submit\" id=\"submit\" value=\"submit\" /></p></form>",$id); print "<hr />"; } else { ?> <p><strong><?php echo $title; ?></strong><br /><br /> <?php echo $entry; ?><br /><br /> Posted on <?php echo $date; ?> <hr /></p> <?php } } ?> </body> </html> Thanks for any help. I really appreciate any input!

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  • C# ApplicationContext usage

    - by rd42
    Apologies if my terminology is off, I'm new to C#. I'm trying to use an ApplicationContext file to store mysql conn values, like dbname, username, password. The class with mysql conn string is "using" the namespace for the ApplicationContext, but when I print out the connection string, the values are making it. A friend said, "I'm not initializing it" but couldn't stay to expand on what "it" was. and the "Console.WriteLine("1");" in ApplicationContext.cs never shows up. Do I need to create an ApplicationContext object and the call Initialize() on that object? Thanks for any help. ApplicationContext.cs: namespace NewApplication.Context { class ApplicationContext { public static string serverName; public static string username; public static string password; public static void Initialize() { //need to read through config here try { Console.WriteLine("1"); XmlDocument xDoc = new XmlDocument(); xDoc.Load(".\\Settings.xml"); XmlNodeList serverNodeList = xDoc.GetElementsByTagName("DatabaseServer"); XmlNodeList usernameNodeList = xDoc.GetElementsByTagName("UserName"); XmlNodeList passwordNodeList = xDoc.GetElementsByTagName("Password"); } catch (Exception ex) { // MessageBox.Show(ex.ToString()); //TODO: Future write to log file username = "user"; password = "password"; serverName = "localhost"; } } } } MySQLManager.cs: note: dbname is the same as the username as you'll see in the code, I copied this from a friend who does that. using System; using System.Collections.Generic; using System.Linq; using System.Text; using MySql.Data; using MySql.Data.MySqlClient; using NewApplication.Context; namespace NewApplication.DAO { class MySQLManager { private static MySqlConnection conn; public static MySqlConnection getConnection() { if (conn == null || conn.State == System.Data.ConnectionState.Closed) { string connStr = "server=" + ApplicationContext.serverName + ";user=" + ApplicationContext.username + ";database=" + ApplicationContext.username + ";port=3306;password=" + ApplicationContext.password + ";"; conn = new MySqlConnection(connStr); try { Console.WriteLine("Connecting to MySQL... "); Console.WriteLine("Connection string: " + connStr + "\n"); conn.Open(); // Perform databse operations // conn.Close(); } catch (Exception ex) { Console.WriteLine(ex.ToString()); } } return conn; } } } and, thanks for still reading, this is the code that uses the two previous files: class LogDAO { MySqlConnection conn; public LogDAO() { conn = MySQLManager.getConnection(); } Thank you, rd42

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  • WebSphere Plugin Keystore Unreadable by IHS - GSK_ERROR_BAD_KEYFILE_PASSWORD

    - by Seer
    Running WAS 6.1.xx in a network deployment. The IBM provided plugin keystore's "plugin-key.kdb" password expires on april 26th along with the personal cert inside it. So no problem right? Create new cert and set new password on the kdb, restash the password and off we go! Well no! On restart of IBM HTTP Server we see [Tue Apr 24 14:11:22 2012] 00b00004 00000001 - ERROR: lib_security: logSSLError: str_security (gsk error 408): GSK_ERROR_BAD_KEYFILE_PASSWORD [Tue Apr 24 14:11:22 2012] 00b00004 00000001 - ERROR: lib_security: initializeSecurity: Failed to initialize GSK environment [Tue Apr 24 14:11:22 2012] 00b00004 00000001 - ERROR: ws_transport: transportInitializeSecurity: Failed to initialize security [Tue Apr 24 14:11:22 2012] 00b00004 00000001 - ERROR: ws_server: serverAddTransport: Failed to initialize security [Tue Apr 24 14:11:22 2012] 00b00004 00000001 - ERROR: ws_server: serverAddTransport: HTTPS Transport is skipped [Tue Apr 24 14:11:22 2012] 00b00004 00000001 - ERROR: lib_security: logSSLError: str_security (gsk error 408): GSK_ERROR_BAD_KEYFILE_PASSWORD [Tue Apr 24 14:11:22 2012] 00b00004 00000001 - ERROR: lib_security: initializeSecurity: Failed to initialize GSK environment [Tue Apr 24 14:11:22 2012] 00b00004 00000001 - ERROR: ws_transport: transportInitializeSecurity: Failed to initialize security [Tue Apr 24 14:11:22 2012] 00b00004 00000001 - ERROR: ws_server: serverAddTransport: Failed to initialize security [Tue Apr 24 14:11:22 2012] 00b00004 00000001 - ERROR: ws_server: serverAddTransport: HTTPS Transport is skipped Here is the thing ... I can open the keystore using the new password with ikeyman and keytool. Using some "slightly dodgy" script, I can reverse the stash file and see that indeed the new password is set. Then, even if I restore the old keystore files (plugin-key.kdb,plugin-key.crl,plugin-key.sth,plugin-key.rdb) they no longer work either! So it must be permissions right? Well the permissions are the same as before, if I switch to apache user I can browse right through to the files and read them. I have even chown'ed them to apache:apache and/or chmod 777 and still its the same error! Does anyone have a clue what is going on here? Its pretty urgent as our site will be without HTTPS in a couple of days if this isn't resolved - thats bad for a retail web site :)

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  • How do I connect two computers with a LAN cabel?

    - by John
    I have two machines - Windows XP and a laptop using Windows 7. I connected them with a WLAN cable. On the Windows XP machine, I set the IP address to 192.168.0.10. On the Windows 7 laptop, I set the IP address to 192.168.0.20. The laptop can see the Windows XP machine, but Windows XP machine cannot see the Windows 7 machine. But this does NOT concern me. I want to move the files from my desktop (Windows XP) to Windows 7 (laptop). That's why I'm going through all this. The problem is that when I try to connect from Windows 7 to Windows XP machine, I get this window: I don't understand what username/password is needed. I use none on the Windows XP machine. I tried all usernames - no success. Please explain in deep details how to solve my problem so I can connect to my Windows XP machine. EDIT: Maybe this can help: the Windows XP machine is named 'I' and '???????? III' is the name of the laptop. Both computers share one workgroup - WORKGROUP.

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  • Windows 7 - SyncToy alternative - Sync folder with Network drive...

    - by alex
    I have a Windows 7 laptop, which i want to back up to a network folder. There is a drive (partition) on my laptop machine that i want to backup to a network drive- if i delete a file in the folder on my laptop, it should also be deleted from the backup... I used to use syncToy, however i understand this does not work correctly with windows 7 - at least not with a large number of files. Are there any alternatives?

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  • LDAP authentication issue with Kerio Connect

    - by djk
    We have Kerio Connect (mail server) running on a Windows Server 2003 server on a domain. In the webmail client, users are able to change their domain password. This functionality used to work fine until a user tried to change their password a few days ago, when every password they'd try would result in the webmail client claiming their password was "invalid". I spoke to Kerio about this and they claim that this error is returned by the domain controller, which supports my initial investigations. The error that the DC is logging when an attempt is made to change the password is this: "80090308: LdapErr: DSID-0C090334, comment: AcceptSecurityContext error, data 52e, vece" The "data 52e" part indicates that this is an "invalid credentials" error. I don't see how this can be as I've tried (in the Kerio Connect configuration) various accounts that have privileges to modify accounts, including my own as I am a domain admin. I have ran 'dcdiag' (all tests) on the DC and it came back passing every single one of them. I've searched high and low for an answer to this and came up empty. Does anyone have any idea why this may have suddenly started happening? Thanks! Edit: I should mention that the passwords we are changing to do comply with the complexity policy.

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  • Ubuntu 9.10 RSA authentication: ssh fails, filezilla runs fine

    - by MariusPontmercy
    This is quite a mistery for me. I usually use passwordless RSA authentication to login into my remote *nix servers with ssh and sftp. Never had any problem until now. I cannot connect to an Ubuntu 9.10 machine: user@myclient$ ssh -i .ssh/Ganymede_key [email protected] [...] debug1: Host 'ganymede.server.com' is known and matches the RSA host key. debug1: Found key in /home/user/.ssh/known_hosts:14 debug2: bits set: 494/1024 debug1: ssh_rsa_verify: signature correct debug2: kex_derive_keys debug2: set_newkeys: mode 1 debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug2: set_newkeys: mode 0 debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug2: service_accept: ssh-userauth debug1: SSH2_MSG_SERVICE_ACCEPT received debug2: key: .ssh/Ganymede_key (0xb96a0ef8) debug2: key: .ssh/Ganymede_key ((nil)) debug1: Authentications that can continue: publickey,password,keyboard-interactive debug1: Next authentication method: publickey debug1: Offering public key: .ssh/Ganymede_key debug2: we sent a publickey packet, wait for reply debug1: Authentications that can continue: publickey,password,keyboard-interactive debug1: Trying private key: .ssh/Ganymede_key debug1: read PEM private key done: type RSA debug2: we sent a publickey packet, wait for reply debug1: Authentications that can continue: publickey,password,keyboard-interactive debug2: we did not send a packet, disable method debug1: Next authentication method: keyboard-interactive debug2: userauth_kbdint debug2: we sent a keyboard-interactive packet, wait for reply debug2: input_userauth_info_req debug2: input_userauth_info_req: num_prompts 1 Then it falls back to password authentication. If I disable password authentication on the remote machine my connection attempt just fails with a "Permission denied (publickey)." state. Same thing for sftp from command line. The "funny" thing is that the exact same RSA key works like a charm with a Filezilla sftp session instead: 12:08:00 Trace: Offered public key from "/home/user/.filezilla/keys/Ganymede_key" 12:08:00 Trace: Offer of public key accepted, trying to authenticate using it. 12:08:01 Trace: Access granted 12:08:01 Trace: Opened channel for session 12:08:01 Trace: Started a shell/command 12:08:01 Status: Connected to ganymede.server.com 12:08:02 Trace: CSftpControlSocket::ConnectParseResponse() 12:08:02 Trace: CSftpControlSocket::ResetOperation(0) 12:08:02 Trace: CControlSocket::ResetOperation(0) 12:08:02 Status: Retrieving directory listing... 12:08:02 Trace: CSftpControlSocket::SendNextCommand() 12:08:02 Trace: CSftpControlSocket::ChangeDirSend() 12:08:02 Command: pwd 12:08:02 Response: Current directory is: "/root" 12:08:02 Trace: CSftpControlSocket::ResetOperation(0) 12:08:02 Trace: CControlSocket::ResetOperation(0) 12:08:02 Trace: CSftpControlSocket::ParseSubcommandResult(0) 12:08:02 Trace: CSftpControlSocket::ListSubcommandResult() 12:08:02 Trace: CSftpControlSocket::ResetOperation(0) 12:08:02 Trace: CControlSocket::ResetOperation(0) 12:08:02 Status: Directory listing successful Any thoughts? M

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  • Cannot connect to a VPN server - authentication failed with error code 691

    - by stacker
    When trying to connect to a VPN server, I get the 691 error code on the client, which say: Error Description: 691: The remote connection was denied because the user name and password combination you provided is not recognized, or the selected authentication protocol is not permitted on the remote access server. I validated that the username and password are correct. I also installed a certification to use with the IKEv2 security type. I also validated that the VPN server support security method. But I cannot login. In the server log I get this log: Network Policy Server denied access to a user. The user DomainName\UserName connected from IP address but failed an authentication attempt due to the following reason: The remote connection was denied because the user name and password combination you provided is not recognized, or the selected authentication protocol is not permitted on the remote access server. Any idea of what can I do? Thanks in advance! Log Name: Security Source: Microsoft-Windows-Security-Auditing Date: 12/29/2010 7:12:20 AM Event ID: 6273 Task Category: Network Policy Server Level: Information Keywords: Audit Failure User: N/A Computer: VPN.domain.com Description: Network Policy Server denied access to a user. Contact the Network Policy Server administrator for more information. User: Security ID: domain\Administrator Account Name: domain\Administrator Account Domain: domani Fully Qualified Account Name: domain.com/Users/Administrator Client Machine: Security ID: NULL SID Account Name: - Fully Qualified Account Name: - OS-Version: - Called Station Identifier: 192.168.147.171 Calling Station Identifier: 192.168.147.191 NAS: NAS IPv4 Address: - NAS IPv6 Address: - NAS Identifier: VPN NAS Port-Type: Virtual NAS Port: 0 RADIUS Client: Client Friendly Name: VPN Client IP Address: - Authentication Details: Connection Request Policy Name: Microsoft Routing and Remote Access Service Policy Network Policy Name: All Authentication Provider: Windows Authentication Server: VPN.domain.home Authentication Type: EAP EAP Type: Microsoft: Secured password (EAP-MSCHAP v2) Account Session Identifier: 313933 Logging Results: Accounting information was written to the local log file. Reason Code: 16 Reason: Authentication failed due to a user credentials mismatch. Either the user name provided does not map to an existing user account or the password was incorrect.

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  • Configure a wireless network that accepts any WPA2-PSK network key

    - by Michel
    I recently bought a UART WiFi module ( this one ) and configured it with right SSID but wrong password( and I don't know what it is ). The problem is that I can't reset this module to its manufacture settings and I can't connect to this module via serial port to configure it with some wire or cable. But I'm sure that my module is trying to connect my access point but with wrong network key ( because in logs of my access point I can see my module that trying to connect but it can't ) So, I wonder to know is there any way to create or configure a network (using some access point or something else) based on WPA2 Personal security that accepts any WPA2-PSK passwords ? Or is there any other solution for this problem ? If no, is there anyway to see what password this module using to connect to that network ? ( If yes, then I can change password of my network to that password and access to this module's admin panel ) I tried create an open network ( without any security key ) but my module just searches for WPA2 based networks ( I think ).

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  • IIS 7.5 Basic authorization issue

    - by Alsin
    When I log on using correct user name\password (I always copy-paste them) I get 401.1 error. User name and password are correct (user is created on server locally, not a domain one). I can run program as this user (runas /noprofile /user:tmp notepad.exe). Basic authorization's default domain is a server name, realm is empty. I've saved FailedReqLogFile. AUTH_BASIC_LOGON_FAILED shows ErrorCode="Logon failure: unknown user name or bad password. (0x8007052e)" and MODULE_SET_RESPONSE_ERROR_STATUS shows ModuleName="BasicAuthenticationModule", Notification="AUTHENTICATE_REQUEST", HttpStatus="401", HttpReason="Unauthorized", HttpSubStatus="1", ErrorCode="Logon failure: unknown user name or bad password. (0x8007052e)", ConfigExceptionInfo="" And one more thing - if I use my domain login\password it woks! Basic Authentications is only enabled authentication in application... Could you please suggest me how I can troubleshoot and fix this issue? Maybe somebody hit it before... Best regards, Alex UPDATE: I get 401.1 when I trying to access site from local host. I can actually access files from remote host.

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  • MySQL is hogging my server resources

    - by Reacen
    Does anyone have any idea of what can cause this weird behaviour and how I go about fixing it? This is all coming from MySQL only (both RAM and CPU usage), for about 10 minutes after I reboot my Java game server (that has a pool of 256 connections). There are not that many queries and I think it may be more of a MySQL misconfiguration problem. My server: 3.20 GHz * 6 core / 24 GB RAM / 64 bit Windows Server 2003. My game server: Java server, with 256 MySQL connections pool (MyISAM engine), about 500,000 accounts, and 9 million rows of game items in database and about 3,000 players are connected. After about 15 minutes of the game server reboot, the server resumes its stability and CPU usage drop down to 1% ~ 5% and memory to 6 GB. Here is a copy of my MySQL configuration. Also, any advice about my MySQL configuration will be appreciated. I really set it up almost at random. # Example MySQL config file for very large systems. # # This is for a large system with memory of 1G-2G where the system runs mainly # MySQL. # # You can copy this file to # /etc/my.cnf to set global options, # mysql-data-dir/my.cnf to set server-specific options (in this # installation this directory is C:\mysql\data) or # ~/.my.cnf to set user-specific options. # # In this file, you can use all long options that a program supports. # If you want to know which options a program supports, run the program # with the "--help" option. # The following options will be passed to all MySQL clients [client] #password = your_password port = 3306 socket = /tmp/mysql.sock # Here follows entries for some specific programs # The MySQL server [mysqld] #log=c:\mysql.log port = 3306 socket = /tmp/mysql.sock skip-locking key_buffer_size = 2572M max_allowed_packet = 64M table_open_cache = 512 sort_buffer_size = 128M read_buffer_size = 128M read_rnd_buffer_size = 128M myisam_sort_buffer_size = 500M thread_cache_size = 32 query_cache_size = 1948M # Try number of CPU's*2 for thread_concurrency thread_concurrency = 12 max_connections = 5000 # Don't listen on a TCP/IP port at all. This can be a security enhancement, # if all processes that need to connect to mysqld run on the same host. # All interaction with mysqld must be made via Unix sockets or named pipes. # Note that using this option without enabling named pipes on Windows # (via the "enable-named-pipe" option) will render mysqld useless! # #skip-networking # Replication Master Server (default) # binary logging is required for replication log-bin=mysql-bin # required unique id between 1 and 2^32 - 1 # defaults to 1 if master-host is not set # but will not function as a master if omitted server-id = 1 # Replication Slave (comment out master section to use this) # # To configure this host as a replication slave, you can choose between # two methods : # # 1) Use the CHANGE MASTER TO command (fully described in our manual) - # the syntax is: # # CHANGE MASTER TO MASTER_HOST=<host>, MASTER_PORT=<port>, # MASTER_USER=<user>, MASTER_PASSWORD=<password> ; # # where you replace <host>, <user>, <password> by quoted strings and # <port> by the master's port number (3306 by default). # # Example: # # CHANGE MASTER TO MASTER_HOST='125.564.12.1', MASTER_PORT=3306, # MASTER_USER='joe', MASTER_PASSWORD='secret'; # # OR # # 2) Set the variables below. However, in case you choose this method, then # start replication for the first time (even unsuccessfully, for example # if you mistyped the password in master-password and the slave fails to # connect), the slave will create a master.info file, and any later # change in this file to the variables' values below will be ignored and # overridden by the content of the master.info file, unless you shutdown # the slave server, delete master.info and restart the slaver server. # For that reason, you may want to leave the lines below untouched # (commented) and instead use CHANGE MASTER TO (see above) # # required unique id between 2 and 2^32 - 1 # (and different from the master) # defaults to 2 if master-host is set # but will not function as a slave if omitted #server-id = 2 # # The replication master for this slave - required #master-host = <hostname> # # The username the slave will use for authentication when connecting # to the master - required #master-user = <username> # # The password the slave will authenticate with when connecting to # the master - required #master-password = <password> # # The port the master is listening on. # optional - defaults to 3306 #master-port = <port> # # binary logging - not required for slaves, but recommended #log-bin=mysql-bin # # binary logging format - mixed recommended #binlog_format=mixed # Point the following paths to different dedicated disks #tmpdir = /tmp/ #log-update = /path-to-dedicated-directory/hostname # Uncomment the following if you are using InnoDB tables #innodb_data_home_dir = C:\mysql\data/ #innodb_data_file_path = ibdata1:2000M;ibdata2:10M:autoextend #innodb_log_group_home_dir = C:\mysql\data/ # You can set .._buffer_pool_size up to 50 - 80 % # of RAM but beware of setting memory usage too high #innodb_buffer_pool_size = 384M #innodb_additional_mem_pool_size = 20M # Set .._log_file_size to 25 % of buffer pool size #innodb_log_file_size = 100M #innodb_log_buffer_size = 8M #innodb_flush_log_at_trx_commit = 1 #innodb_lock_wait_timeout = 50 [mysqldump] quick max_allowed_packet = 64M [mysql] no-auto-rehash # Remove the next comment character if you are not familiar with SQL #safe-updates [myisamchk] key_buffer_size = 256M sort_buffer_size = 256M read_buffer = 8M write_buffer = 8M [mysqlhotcopy] interactive-timeout

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  • How do I connect two computers with a LAN cable?

    - by John
    I have two machines - Windows XP and a laptop using Windows 7. I connected them with a WLAN cable. On the Windows XP machine, I set the IP address to 192.168.0.10. On the Windows 7 laptop, I set the IP address to 192.168.0.20. The laptop can see the Windows XP machine, but Windows XP machine cannot see the Windows 7 machine. But this does NOT concern me. I want to move the files from my desktop (Windows XP) to Windows 7 (laptop). That's why I'm going through all this. The problem is that when I try to connect from Windows 7 to Windows XP machine, I get this window: I don't understand what username/password is needed. I use none on the Windows XP machine. I tried all usernames - no success. Please explain in deep details how to solve my problem so I can connect to my Windows XP machine. EDIT: Maybe this can help: the Windows XP machine is named 'I' and '???????? III' is the name of the laptop. Both computers share one workgroup - WORKGROUP.

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  • Cannot log in with created user in mysql

    - by Brian G
    Using this command GRANT ALL PRIVILEGES ON *.* to brian@'%' identified by 'password'; I try to login with: mysql -u brian -ppassword The error is: ERROR 1045 (28000): Access denied for user 'brian'@'localhost' (using password: YES) I am doing this as root and I did try to flush privileges. I tried this with countless users but it does not seem to work. I can create a user with no password and login works. Command line and from phpmyadmin

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