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  • Parameter cannot be null error after success save

    - by tigermain
    I am getting the following nhibernate error when saving an entity (via: NHibernateSession.Save(entity);) despite it being persisted to the database fine "Value cannot be null.\r\nParameter name: id" This is my hbm file <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" namespace="JeanieMaster.Domain.Entities" assembly="JeanieMaster.Domain"> <class name="ActionLog" table="ActionLog" schema="[DBSVR1].[mydatabase].[dbo]" select-before-update="false" optimistic-lock="none"> <id name="Id" column="ActionLogId" type="Int32"> <generator class="identity"/> </id> <property name="ActionId" type="Int32"/> <many-to-one name="User" class="JeanieUser" column="UserId" /> <many-to-one name="ApplicationProvider" class="ApplicationProvider" column="ApplicationProviderId" /> <many-to-one name="ContentProvider" class="ContentProvider" column="ContentProviderId" /> <many-to-one name="SearchLog" class="SearchLog" column="SearchLogId" /> <property name="Data" type="string"/> <property name="DateCreated" type="DateTime"/> <property name="ActionDuration" type="Double"/> </class> </hibernate-mapping>

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  • how to save sitecore webpage in html file on local disk or server

    - by Sam
    WebRequest mywebReq ; WebResponse mywebResp ; StreamReader sr ; string strHTML ; StreamWriter sw; mywebReq = WebRequest.Create("http://domain/sitecore/content/test/page10.aspx"); mywebResp = mywebReq.GetResponse(); sr = new StreamReader(mywebResp.GetResponseStream()); strHTML = sr.ReadToEnd(); sw = File.CreateText(Server.MapPath("hello.html")); sw.WriteLine(strHTML); sw.Close(); Hi , I want to save sitecore .aspx page into html file on local disk , but i am getting exception. But if i use any other webpage example(google.com) it works fine. The exception : System.Net.WebException was caught HResult=-2146233079 Message=The remote server returned an error: (404) Not Found. Source=System StackTrace: at System.Net.WebClient.DownloadFile(Uri address, String fileName) at System.Net.WebClient.DownloadFile(String address, String fileName) at BlueDiamond.addmodule.btnSubmit(Object sender, EventArgs e) in c:\inetpub\wwwroot\STGLocal\Website\addmodule.aspx.cs:line 97 InnerException: Any help. Thanks in advance

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  • Multiple winform data save problem

    - by Mahesh
    hi am using C# with VS-2005 I have a form1 and about two textBox and one Combobox on it. like below textBox1 texbox2 ComboBox I have bind combobox by sql database. first user type in textbox1 and textbox2 and then goes to comboBox in which "BuyerName" available on it. if user not found the data in the comboBox then press ALT+C for opening of Form2 where they create data and save it. My problem is when I closed the form2 by saving data of "BuyerName" the form1 is open as per my requirement but the data of textBox1 and textBox2 which user typed before opening of form2 is lost and therefore user have to re-type on it. which i don't want as it wasting of time. I want when form2 closed and form1 open the data will be available on it. and when u create fresh "BuyerName" from form2 the "BuyerName" will be automaticaly available on form1 comboBox on closing of form2. Hope u will get it. am new here in programing so kindly suggest me by proper codeing. thx in Advance.

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  • How to bring a modal to the front of the page using bootstrap?

    - by sharataka
    I am trying to implement a modal using bootstrap. When I click on the button the screen fades and the modal appears, but it appears behind the images in and is unreadable for the user. How do I bring the modal forward? <div class ="container-fluid"> <div class = "row-fluid"> <div class = "span2"> <!-- Modal --> <div class="modal hide fade" id="myModal"> <div class="modal-header"> <a class="close" data-dismiss="modal">×</a> <h3>Modal header</h3> </div> <div class="modal-body"> <p>One fine body…</p> </div> <div class="modal-footer"> <a href="#" class="btn">Close</a> <a href="#" class="btn btn-primary">Save changes</a> </div> </div> <a data-toggle="modal" href="#myModal" class="btn btn-primary">Launch demo modal</a> </div> <div class = "span8"> #a lot of images in this div </div> </div> </div>

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  • drupal themes: .info file: how do I add more than 1 css file / js file to my theme?

    - by egarcia
    I'm creating a new Drupal theme. Until now, I only needed to include a single css file and a single js file. So my theme.info file had something like this: stylesheets[all][] = css/style.css scripts[] = js/script.js Now I must include jquery and jquery-ui in order to use a calendar date. These come with 2 new javascript files, and 1 additonal css file that I must add to the site. The calendar input form is going to be used in all pages (on a side block) so it is ok for me to load the extra css/javascript on all pages. I think the easiest thing would be to reference them on the .info file itself. At first I tried to just put them there with separate spaces: stylesheets[all][] = css/style.css css/ui-lightness/jquery-ui-1.8.1.custom.css scripts[] = js/jquery-1.4.2.min.js js/jquery-ui-1.8.1.custom.min.js js/reservations.js I emptied drupal's cache and... none of them loaded. I then tried separating each file with a comma, and flushing the cache again. Same result. I've browsed some drupal pages, but could not find how to add several javascript/css files on one theme (they always seem to add just 1 of each). So, how do I include several css/javascript files on the .info file?

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  • Save PowerPoint slides as images

    - by nihi_l_ist
    I want to save some presentation file as images into some directory and use the code: OpenFileDialog o = new OpenFileDialog(); o.ShowDialog(); if (o.FileName != null) { ApplicationClass pptApplication = new ApplicationClass(); Presentation pptPresentation = pptApplication.Presentations.Open(o.FileName, MsoTriState.msoFalse, MsoTriState.msoFalse, MsoTriState.msoFalse); FolderBrowserDialog fb = new FolderBrowserDialog(); fb.ShowDialog(); for (int i = 0; i < pptPresentation.Slides.Count; i++) { pptPresentation.Slides[i].Export(fb.SelectedPath + "Slide" + (i + 1) + ".jpg", "jpg", 320, 240); } } use namespaces: using Microsoft.Office.Core; using Microsoft.Office.Interop.PowerPoint; But i get the following error: 'Microsoft.Office.Interop.PowerPoint.ApplicationClass' does not contain a definition for 'Presentations' and no extension method 'Presentations' accepting a first argument of type 'Microsoft.Office.Interop.PowerPoint.ApplicationClass' could be found (are you missing a using directive or an assembly reference?) Tho it seems that it has property called Presentations.. What am i doing incorrectly?

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  • how do i save time to a file?

    - by blood
    hi, i have a program that saves data to file and i want to put a time stamp of the current date/time on that log but when i try to write the time to the file it will not show up. #include <iostream> #include <windows.h> #include <fstream> #include <string> #include <sstream> #include <direct.h> #include <stdio.h> #include <time.h> using namespace std; string header_str = ("NULL"); int main() { for(;;) { stringstream header(stringstream::in | stringstream::out); header << "datasdasdasd_"; time_t rawtime; time ( &rawtime ); header << ctime (&rawtime); header_str = header.str(); fstream filestr; filestr.open ("C:\\test.txt", fstream::in | fstream::out | fstream::app | ios_base::binary | ios_base::out); for(;;) { filestr << (header_str); } filestr.close(); } return 0; } anyone know how to fix this?

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  • Android - Take a photo, save it in app drawables and display it in an ImageButton

    - by Andres7X
    I have an Android app with an ImageButton. When user clicks on it, intent launches to show camera activity. When user capture the image, I'd like to save it in drawable folder of the app and display it in the same ImageButton clicked by the user, replacing the previous drawable image. I used the activity posted here: Capture Image from Camera and Display in Activity ...but when I capture an image, activity doesn't return to activity which contains ImageButton. Edit code is: public void manage_shop() { static final int CAMERA_REQUEST = 1888; [...] ImageView photo = (ImageView)findViewById(R.id.getimg); photo.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Intent camera = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE); startActivityForResult(camera, CAMERA_REQUEST); } }); [...] } And onActivityResult(): protected void onActivityResult(int requestCode, int resultCode, Intent data) { ImageButton getimage = (ImageButton)findViewById(R.id.getimg); if (requestCode == CAMERA_REQUEST && resultCode == RESULT_OK) { Bitmap getphoto = (Bitmap) data.getExtras().get("data"); getimage.setImageBitmap(getphoto); } } How can I also store the captured image in drawable folder?

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  • Android - save/restore state of custom class

    - by user1209216
    I have some class for ssh support - it uses jsch internally. I use this class on main activity, this way: public class MainActivity extends Activity { SshSupport ssh = new SshSupport(); ..... @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //Handle events for ssh ssh.eventHandler = new ISshEvents() { @Override public void SshCommandExecuted(SshCommandsEnum commandType, String result) { } //other overrides here } //Ssh operations on gui item click @Override public void onItemClick(AdapterView<?> arg0, View v, int position, long arg3) { if (ssh.IsConnected() == false) { try { ssh.ConnectAsync(/*parameters*/); } catch (Exception e) { e.printStackTrace(); } } try { ssh.ExecuteCommandAsync(SshCommandsEnum.values()[position]); } catch (Exception e) { e.printStackTrace(); } } }); } It works very well. My application connects to ssh, performs all needed operation in background thread and results are reported to gui, via events as shown above. But nothing works after user change device orientation. It's clear for me - activity is re-created and all state is lost. Unfortunately, my SshSupport class object is lost as well. It's pretty easy to store gui state for dynamically changed/added objects (using put/get serializable etc methods). But I have no idea how to prevent my ssh object, ssh connected session being lost. Since my class is not serializable, I can't save it to bundle. Also, even if I make my SshSupport class serializable, jsch objects it uses still are not serializable. So what is the best way to solve this?

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  • PHP: parse $_FILES[] data in multidimesional array

    - by superUntitled
    Example form here: http://jsfiddle.net/superuntitled/uaTtx/1/ I have a form that allows for dynamic duplication of the form fields. The form allows for file uploads and text input, so the data is sent in both $_POST and $_FILES arrays. The the initial set of inputs look like this: <input type="text" name="question[1][text]" /> <input type="file" name="question[1][file]" /> <input type="text" class="a" name="answer[1][text][]" /> <input type="file" name="answer[1][file][]" /> When duplicated the fields are incremented, they look like this: <input type="text" name="question[2][text]" /> <input type="file" name="question[2][file]" /> <input type="text" class="a" name="answer[2][text][]" /> <input type="file" name="answer[2][file][]" /> To complicate matters, the "answer" form fields can also be duplicated (thus the [] at the end of the 'answer' name array. How can I parse the posted $_FILES array? I have tried something like this: foreach ($_FILES['question'] as $p_num) { echo $p_num['file']['name']; foreach ($_FILES['answer'] as $a_num) { echo $a_num['file']['name']; } } but I get an "Undefined index: file... " error. How can I parse out the posted values.

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  • Reading and writing to files simultaneously?

    - by vipersnake005
    Moved the question here. Suppose, I want to store 1,000,000,000 integers and cannot use my memory. I would use a file(which can easily handle so much data ). How can I let it read and write and the same time. Using fstream file("file.txt', ios::out | ios::in ); doesn't create a file, in the first place. But supposing the file exists, I am unable to use to do reading and writing simultaneously. WHat I mean is this : Let the contents of the file be 111111 Then if I run : - #include <fstream> #include <iostream> using namespace std; int main() { fstream file("file.txt",ios:in|ios::out); char x; while( file>>x) { file<<'0'; } return 0; } Shouldn't the file's contents now be 101010 ? Read one character and then overwrite the next one with 0 ? Or incase the entire contents were read at once into some buffer, should there not be atleast one 0 in the file ? 1111110 ? But the contents remain unaltered. Please explain. Thank you.

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  • Save many-to-one relationship from JSON into Core Data

    - by Snow Crash
    I'm wanting to save a Many-to-one relationship parsed from JSON into Core Data. The code that parses the JSON and does the insert into Core Data looks like this: for (NSDictionary *thisRecipe in recipes) { Recipe *recipe = [NSEntityDescription insertNewObjectForEntityForName:@"Recipe" inManagedObjectContext:insertionContext]; recipe.title = [thisRecipe objectForKey:@"Title"]; NSDictionary *ingredientsForRecipe = [thisRecipe objectForKey:@"Ingredients"]; NSArray *ingredientsArray = [ingredientsForRecipe objectForKey:@"Results"]; for (NSDictionary *thisIngredient in ingredientsArray) { Ingredient *ingredient = [NSEntityDescription insertNewObjectForEntityForName:@"Ingredient" inManagedObjectContext:insertionContext]; ingredient.name = [thisIngredient objectForKey:@"Name"]; } } NSSet *ingredientsSet = [NSSet ingredientsArray]; [recipe setIngredients:ingredientsSet]; Notes: "setIngredients" is a Core Data generated accessor method. There is a many-to-one relationship between Ingredients and Recipe However, when I run this I get the following error: NSCFDictionary managedObjectContext]: unrecognized selector sent to instance If I remove the last line (i.e. [recipe setIngredients:ingredientsSet];) then, taking a peek at the SQLite database, I see the Recipe and Ingredients have been stored but no relationship has been created between Recipe and Ingredients Any suggestions as to how to ensure the relationship is stored correctly?

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  • Wordpress curl save Images

    - by Jeton Ramadani
    I am working on saving images from external sites into a folder in my wordpress theme. And I was wondering if its Ok to call curl twice or can it be done with one time. Example: $data = get_url('http://www.veoh.com/watch/v19935546Y8hZPgbZ'); // getting the url first curl instance preg_match('/fullHighResImagePath="(.*?)"/', $data, $thumbnail); // find the image from content savePhoto($thumbnail, $post->ID); //2nd instance of curl to save the image function get_url($url) { $user_agent = "Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.2)"; $ytc = curl_init(); // initialize curl handle curl_setopt($ytc, CURLOPT_URL, $url); // set url to post to curl_setopt($ytc, CURLOPT_FAILONERROR, 1); // Fail on errors curl_setopt($ytc, CURLOPT_FOLLOWLOCATION, 1); // allow redirects curl_setopt($ytc, CURLOPT_RETURNTRANSFER, 1); // return into a variable curl_setopt($ytc, CURLOPT_PORT, 80); //Set the port number curl_setopt($ytc, CURLOPT_TIMEOUT, 15); // times out after 15s curl_setopt($ytc, CURLOPT_HEADER, 1); // include HTTP headers curl_setopt($ytc, CURLOPT_USERAGENT, $user_agent); $source = curl_exec($ytc); curl_close($ytc); $data = trim( $source ); return $data; } function savePhoto($remoteImage, $isbn) { $ch = curl_init(); curl_setopt ($ch, CURLOPT_URL, $remoteImage); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_CONNECTTIMEOUT, 0); $fileContents = curl_exec($ch); curl_close($ch); if (DIRECTORY_SEPARATOR=='/'){ $absolute_path = dirname(__FILE__).'/'; } else { $absolute_path = str_replace('\\', '/', dirname(__FILE__)).'/'; } $newImg = imagecreatefromstring($fileContents); return imagejpeg($newImg, $absolute_path ."video_images/{$isbn}.jpg",100); }

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  • Windows 7: Can't see ISO file in C:\

    - by cbp
    I used DVD shrink to create an ISO file and saved it into C:\ The ISO file is visible with some programs but not with others. The file is not hidden as far as I am aware. But it cannot be seen by Windows Explorer, DVD Decrypter or a bunch of other programs. If I search for the file using Windows 7's Start Menu search tool, I can see the file and I can right click and select Properties. The Properties window appears OK, but if I try to change tabs on the property window, I receive an error message as though the file is not there. DVD Shrink can still open the file OK. I can also find the file using Agent Ransack (a file searching tool), but then I cannot open it. What gives?

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  • optimizing file share performance on Win2k8?

    - by Kirk Marple
    We have a case where we're accessing a RAID array (drive E:) on a Windows Server 2008 SP2 x86 box. (Recently installed, nothing other than SQL Server 2005 on the server.) In one scenario, when directly accessing it (E:\folder\file.xxx) we get 45MBps throughput to a video file. If we access the same file on the same array, but through UNC path (\server\folder\file.xxx) we get about 23MBps throughput with the exact same test. Obviously the second test is going through more layers of the stack, but that's a major performance hit. What tuning should we be looking at for making the UNC path be closer in performance to the direct access case? Thanks, Kirk (corrected: it is CIFS not SMB, but generalized title to 'file share'.) (additional info: this happens during the read from a single file, not an issue across multiple connections. the file is on the local machine, but exposed via file share. so client and file server are both same Windows 2008 server.)

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  • undelete big files - mission impossible?

    - by johnrembo
    Hi, I've accidentaly deleted outlook.pst (6.7GB) file, while there was only 400MB free space left on primary NTFS partition (winxp). I've tried several recovery tools to get this file back. "Ontrack Easy Recovery Pro" found 0 pst files (complete scan mode), while "Recover My Files" in sector scan mode found 5 pst's, but 4 of them of sizes from 3 to 28 KB, while the 5th one - 1Gb. I've managed to succesfuly recover 1Gb pst file, which was 1 year old copy (the one used after the latest windows reinstall). Now, I'm frustrated and confused Why 1 year old file was succesfuly recovered if there were only 400MB left on primary partition? Where's 6.7GB file gone? I did some reading (i.e. here), and it seems that there's almost no probability to retrieve the file I'm looking for, but wait - none of recovery tools i've used found zero-sized pst file, moreover - if due to fragmentation a file might be corrupted - we could use scanpst.exe to fix some errors and survive with 10 or 100 emails missing - whatever. Could you please recommend some more sophisticated recovery tools for this particular task? Appretiate your help - thanks in advance

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  • Is it possible to download extremely large files intelligently or in parts via SSH from Linux to Windows?

    - by Andrew
    I have a ~35 GB file on a remote Linux Ubuntu server. Locally, I am running Windows XP, so I am connecting to the remote Linux server using SSH (specifically, I am using a Windows program called SSH Secure Shell Client version 3.3.2). Although my broadband internet connection is quite good, my download of the large file often fails with a Connection Lost error message. I am not sure, but I think that it fails because perhaps my internet connection goes out for a second or two every several hours. Since the file is so large, downloading it may take 4.5 to 5 hours, and perhaps the internet connection goes out for a second or two during that long time. I think this because I have successfully downloaded files of this size using the same internet connection and the same SSH software on the same computer. In other words, sometimes I get lucky and the download finishes before the internet connection drops for a second. Is there any way that I can download the file in an intelligent way -- whereby the operating system or software "knows" where it left off and can resume from the last point if a break in the internet connection occurs? Perhaps it is possible to download the file in sections? Although I do not know if I can conveniently split my file into multiple files -- I think this would be very difficult, since the file is binary and is not human-readable. As it is now, if the entire ~35 GB file download doesn't finish before the break in the connection, then I have to start the download over and overwrite the ~5-20 GB chunk that was downloaded locally so far. Do you have any advice? Thanks.

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  • Command line switching

    - by Larry
    I have read through some suggestions but I am just not technical enough to get this I think. I am a CAD designer and each file has 5 files associated with it. I have 3 sets of 5 files, and each set needs to go into its own zip file, placed on a separate server. For example: "C:\Program Files\7-zip\7z.exe" a file1.zip "O:\server2\map files\BC\BC.d*"-0 "C:\Program Files\7-zip\7z.exe" a file2.zip "O:\server2\map files\BC\ON.d*"-0 "C:\Program Files\7-zip\7z.exe" a file3.zip "O:\server2\map files\BC\AB.d*"-0 and I am in directory "S:\server\map files\provinces" (for example). These lines run within an existing batch file and by the time it reaches the 3 lines above, it's in the S: directory sample above. So it's looking on my pc for the 7-zip program, creating 3 zip file names which it does, but places those zip files on a separate server which it doesn't and the first zip file also includes all the other 10 files, the second zip file the same plus the first zip file, and the third the same with the other two zip files making me think the code isn't recognizing the part after file1.zip where I am trying to tell it what files to include and where to place the zip files. Ultimately, I want to either have the system create a new zip file if the old one was deleted, or copy the new files into the existing zip and overwrite any older files, and for these zip files to be placed in a separate location which is where we share our files with other personnel from within our company. The S: drive is for all originals, and O: is for sharing. Is there a list of all switching options with many different samples?

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  • how to write or what is the concept behind the file unlocker program

    - by Jach Many
    Recently i was trying to delete a file thinking that i had closed the program which is manipulating the file but it did not delete because the program was still running. I misunderstood that file as an unwanted file. So i used the file unlocker program to find which process is manipulating that file. That program really worked well by showing the process which was handling that file. and that file was http://download.cnet.com/Unlocker/3000-2248_4-10493998.html. What i want to know is i would like to write a program in win32 C or .net to mimic the same process. Just to find which process is handling which file. and if possible to close it. Or i want to know the concept behind that. I know this cannot be explained in a few paragraphs yet if i could get some references or external links to references then that could be nice.

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  • WinForms AcceptButton not working?

    - by Svish
    Ok, this is bugging me, and I just can't figure out what is wrong... I have made two forms. First form just has a simple button on it, which opens the other as a dialog like so: using (Form2 f = new Form2()) { if (f.ShowDialog() != DialogResult.OK) MessageBox.Show("Not OK"); else MessageBox.Show("OK"); } The second, which is that Form2, has two buttons on it. All I have done is to set the forms AcceptButton to one, and CancelButton to the other. In my head this is all that should be needed to make this work. But when I run it, I click on the button which opens up Form2. I can now click on the one set as CancelButton, and I get the "Not OK" message box. But when I click on the one set as AcceptButton, nothing happens? The InitializeComponent code of Form2 looks like this: private void InitializeComponent() { this.button1 = new System.Windows.Forms.Button(); this.button2 = new System.Windows.Forms.Button(); this.SuspendLayout(); // // button1 // this.button1.Location = new System.Drawing.Point(211, 13); this.button1.Name = "button1"; this.button1.Size = new System.Drawing.Size(75, 23); this.button1.TabIndex = 0; this.button1.Text = "button1"; this.button1.UseVisualStyleBackColor = true; // // button2 // this.button2.DialogResult = System.Windows.Forms.DialogResult.Cancel; this.button2.Location = new System.Drawing.Point(130, 13); this.button2.Name = "button2"; this.button2.Size = new System.Drawing.Size(75, 23); this.button2.TabIndex = 1; this.button2.Text = "button2"; this.button2.UseVisualStyleBackColor = true; // // Form2 // this.AcceptButton = this.button1; this.AutoScaleDimensions = new System.Drawing.SizeF(6F, 13F); this.AutoScaleMode = System.Windows.Forms.AutoScaleMode.Font; this.CancelButton = this.button2; this.ClientSize = new System.Drawing.Size(298, 59); this.Controls.Add(this.button2); this.Controls.Add(this.button1); this.Name = "Form2"; this.Text = "Form2"; this.Load += new System.EventHandler(this.Form2_Load); this.ResumeLayout(false); } I have done nothing else than add those two buttons, and set the AcceptButton and CancelButton. Why doesn't it work?

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  • Cancel UITouch Events When View Covered By Modal UIViewController

    - by kkrizka
    Hi there, I am writing an application where the user has to move some stuff on the screen using his fingers and drop them. To do this, I am using the touchesBegan,touchesEnded... function of each view that has to be moved. The problem is that sometimes the views are covered by a view displayed using the [UIViewController presentModalViewController] function. As soon as that happens, the UIView that I was moving stops receiving the touch events, since it was covered up. But there is no event telling me that it stopped receiving the events, so I can reset the state of the moved view. The following is an example that demonstrates this. The functions are part of a UIView that is being shown in the main window. It listens to touch events and when I drag the finger for some distance, it presents a modal view that covers everything. In the Run Log, it prints what touch events are received. - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { NSLog(@"touchesBegan"); touchStart=[[touches anyObject] locationInView:self]; } - (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { CGPoint touchAt=[[touches anyObject] locationInView:self]; float xx=(touchAt.x-touchStart.x)*(touchAt.x-touchStart.x); float yy=(touchAt.y-touchStart.y)*(touchAt.y-touchStart.y); float rr=xx+yy; NSLog(@"touchesMoved %f",rr); if(rr > 100) { NSLog(@"Show modal"); [viewController presentModalViewController:[UIViewController new] animated:NO]; } } - (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event { NSLog(@"touchesEnded"); } - (void)touchesCancelled:(NSSet *)touches withEvent:(UIEvent *)event { NSLog(@"touchesCancelled"); } But when I test the application and trigger the modal dialog to be displayed, the following is the output in the Run Log. [Session started at 2010-03-27 16:17:14 -0700.] 2010-03-27 16:17:18.831 modelTouchCancel[2594:207] touchesBegan 2010-03-27 16:17:19.485 modelTouchCancel[2594:207] touchesMoved 2.000000 2010-03-27 16:17:19.504 modelTouchCancel[2594:207] touchesMoved 4.000000 2010-03-27 16:17:19.523 modelTouchCancel[2594:207] touchesMoved 16.000000 2010-03-27 16:17:19.538 modelTouchCancel[2594:207] touchesMoved 26.000000 2010-03-27 16:17:19.596 modelTouchCancel[2594:207] touchesMoved 68.000000 2010-03-27 16:17:19.624 modelTouchCancel[2594:207] touchesMoved 85.000000 2010-03-27 16:17:19.640 modelTouchCancel[2594:207] touchesMoved 125.000000 2010-03-27 16:17:19.641 modelTouchCancel[2594:207] Show modal Any suggestions on how to reset the state of a UIView when its touch events are interrupted by a modal view?

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  • Pass string between two threads in java

    - by geeta
    I have to search a string in a file and write the matched lines to another file. I have a thread to read a file and a thread to write a file. I want to send the stringBuffer from read thread to write thread. Please help me to pass this. I amm getting null value passed. write thread: class OutputThread extends Thread{ /****************** Writes the line with search string to the output file *************/ Thread runner1,runner; File Out_File; public OutputThread() { } public OutputThread(Thread runner,File Out_File) { runner1 = new Thread(this,"writeThread"); // (1) Create a new thread. this.Out_File=Out_File; this.runner=runner; runner1.start(); // (2) Start the thread. } public void run() { try{ BufferedWriter bufferedWriter=new BufferedWriter(new FileWriter(Out_File,true)); System.out.println("inside write"); synchronized(runner){ System.out.println("inside wait"); runner.wait(); } System.out.println("outside wait"); // bufferedWriter.write(line.toString()); Buffer Buf = new Buffer(); bufferedWriter.write(Buf.buffers); System.out.println(Buf.buffers); bufferedWriter.flush(); } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } } Read Thraed: class FileThread extends Thread{ Thread runner; File dir; String search_string,stats; File Out_File,final_output; StringBuffer sb = new StringBuffer(); public FileThread() { } public FileThread(CountDownLatch latch,String threadName,File dir,String search_string,File Out_File,File final_output,String stats) { runner = new Thread(this, threadName); // (1) Create a new thread. this.dir=dir; this.search_string=search_string; this.Out_File=Out_File; this.stats=stats; this.final_output=final_output; this.latch=latch; runner.start(); // (2) Start the thread. } public void run() { try{ Enumeration entries; ZipFile zipFile; String source_file_name = dir.toString(); File Source_file = dir; String extension; OutputThread out = new OutputThread(runner,Out_File); int dotPos = source_file_name.lastIndexOf("."); extension = source_file_name.substring(dotPos+1); if(extension.equals("zip")) { zipFile = new ZipFile(source_file_name); entries = zipFile.entries(); while(entries.hasMoreElements()) { ZipEntry entry = (ZipEntry)entries.nextElement(); if(entry.isDirectory()) { (new File(entry.getName())).mkdir(); continue; } searchString(runner,entry.getName(),new BufferedInputStream(zipFile.getInputStream(entry)),Out_File,final_output,search_string,stats); } zipFile.close(); } else { searchString(runner,Source_file.toString(),new BufferedInputStream(new FileInputStream(Source_file)),Out_File,final_output,search_string,stats); } } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } /********* Reads the Input Files and Searches for the String ******************************/ public void searchString(Thread runner,String Source_File,BufferedInputStream in,File output_file,File final_output,String search,String stats) { int count = 0; int countw = 0; int countl=0; String s; String[] str; String newLine = System.getProperty("line.separator"); try { BufferedReader br2 = new BufferedReader(new InputStreamReader(in)); //OutputFile outfile = new OutputFile(); BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(output_file,true)); Buffer Buf = new Buffer(); //StringBuffer sb = new StringBuffer(); StringBuffer sb1 = new StringBuffer(); while((s = br2.readLine()) != null ) { str = s.split(search); count = str.length-1; countw += count; if(s.contains(search)){ countl++; sb.append(s); sb.append(newLine); } if(countl%100==0) { System.out.println("inside count"); Buf.setBuffers(sb.toString()); sb.delete(0,sb.length()); System.out.println("outside notify"); synchronized(runner) { runner.notify(); } //outfile.WriteFile(sb,bufferedWriter); //sb.delete(0,sb.length()); } } } synchronized(runner) { runner.notify(); } br2.close(); in.close(); if(countw == 0) { System.out.println("Input File : "+Source_File ); System.out.println("Word not found"); System.exit(0); } else { System.out.println("Input File : "+Source_File ); System.out.println("Matched word count : "+countw ); System.out.println("Lines with Search String : "+countl); System.out.println("Output File : "+output_file.toString()); System.out.println(); } } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } }

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  • Java Client-Server problem when sending multiple files

    - by Jim
    Client public void transferImage() { File file = new File(ServerStats.clientFolder); String[] files = file.list(); int numFiles = files.length; boolean done = false; BufferedInputStream bis; BufferedOutputStream bos; int num; byte[] byteArray; long count; long len; Socket socket = null ; while (!done){ try{ socket = new Socket(ServerStats.imgServerName,ServerStats.imgServerPort) ; InputStream inStream = socket.getInputStream() ; OutputStream outStream = socket.getOutputStream() ; System.out.println("Connected to : " + ServerStats.imgServerName); BufferedReader inm = new BufferedReader(new InputStreamReader(inStream)); PrintWriter out = new PrintWriter(outStream, true /* autoFlush */); for (int itor = 0; itor < numFiles; itor++) { String fileName = files[itor]; System.out.println("transfer: " + fileName); File sentFile = new File(fileName); len = sentFile.length(); len++; System.out.println(len); out.println(len); out.println(sentFile); //SENDFILE bis = new BufferedInputStream(new FileInputStream(fileName)); bos = new BufferedOutputStream(socket.getOutputStream( )); byteArray = new byte[1000000]; count = 0; while ( count < len ){ num = bis.read(byteArray); bos.write(byteArray,0,num); count++; } bos.close(); bis.close(); System.out.println("file done: " + itor); } done = true; }catch (Exception e) { System.err.println(e) ; } } } Server public static void main(String[] args) { BufferedInputStream bis; BufferedOutputStream bos; int num; File file = new File(ServerStats.serverFolder); if (!(file.exists())){ file.mkdir(); } try { int i = 1; ServerSocket socket = new ServerSocket(ServerStats.imgServerPort); Socket incoming = socket.accept(); System.out.println("Spawning " + i); try { try{ if (!(file.exists())){ file.mkdir(); } InputStream inStream = incoming.getInputStream(); OutputStream outStream = incoming.getOutputStream(); BufferedReader inm = new BufferedReader(new InputStreamReader(inStream)); PrintWriter out = new PrintWriter(outStream, true /* autoFlush */); String length2 = inm.readLine(); System.out.println(length2); String filename = inm.readLine(); System.out.println("Filename = " + filename); out.println("ACK: Filename received = " + filename); //RECIEVE and WRITE FILE byte[] receivedData = new byte[1000000]; bis = new BufferedInputStream(incoming.getInputStream()); bos = new BufferedOutputStream(new FileOutputStream(ServerStats.serverFolder + "/" + filename)); long length = (long)Integer.parseInt(length2); length++; long counter = 0; while (counter < length){ num = bis.read(receivedData); bos.write(receivedData,0,num); counter ++; } System.out.println(counter); bos.close(); bis.close(); File receivedFile = new File(filename); long receivedLen = receivedFile.length(); out.println("ACK: Length of received file = " + receivedLen); } finally { incoming.close(); } } catch (IOException e){ e.printStackTrace(); } } catch (IOException e1){ e1.printStackTrace(); } } The code is some I found, and I have slightly modified it, but I am having problems transferring multiple images over the server. Output on Client: run ServerQueue.Client Connected to : localhost transfer: Picture 012.jpg 1312743 java.lang.ArrayIndexOutOfBoundsException Connected to : localhost transfer: Picture 012.jpg 1312743 Cant seem to get it to transfer multiple images. But bothsides I think crash or something because the file never finishes transfering

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  • Creando un File Upload

    - by jaullo
    Para iniciar hablaremos un poco sobre el control File Upload, de esta forma daremos una idea general de que es y como trabaja. El File Upload es un control de asp.net que permite que los usuarios seleccionen un archivo de cualquier ubicación en el equipo y lo suban a un directorio predeterminado a traves de una página asp.net. En principio este control esta limitado para no permitir subir archivos de mas de 4 MB. Sin embargo, desde el webconfig de nuestra aplicacón podremos cambiar ese valor, ya sea para aumentarlo o bien para disminuirlo. Nuestro ejemplo, se enfocará en crear un webcontrol que permita seleccionar un archivo y guardarlo, asi que empecemos. Lo primero será agregar a nuestra página un webcontrol que llamaremos Upload.ascx Posteriormente en nuestro webcontrol, agregamos el siguiente código: <table style="width: 100%">         <tr>             <td colspan="3">             <div align="center">                  <asp:Label ID="Label1" runat="server" Text="File Upload"></asp:Label>              </div>             </td>                    </tr>         <tr>             <td style="width: 456px" rowspan="2">                                                             &nbsp;</td>             <td style="width: 386px">                                <div align="center">                         <asp:FileUpload ID="FileUpload1" runat="server" Height="24px" Width="243px" />                         <span id="Span1" runat="server" />                            </div>                      </td>             <td rowspan="2">                                                             </td>         </tr>         <tr>             <td style="width: 386px">                 <div align="center">                      <asp:ImageButton Id="btnupload" runat="server" OnClick="btnupload_Click"                     ImageUrl="~/Styles/img/upload.png" style="text-align: center" />           </div>                  </td>         </tr>         <tr>             <td colspan="3">                 &nbsp;</td>         </tr>     </table>  De esta forma nuestro control deberá verse algo así   Por último en el code behin de nuestro control agregamos el código a nuestro boton, el cual será el encargado de leer el archivo que se encuentra en el File Upload y guardarlo en la ruta especificada.  Protected Sub btnupload_Click(ByVal sender As Object, ByVal e As System.Web.UI.ImageClickEventArgs) Handles btnupload.Click         If FileUpload1.HasFile Then             Dim fileExt As String             fileExt = System.IO.Path.GetExtension(FileUpload1.FileName)             If (fileExt = ".exe") Then                 Label1.Text = "You can´t upload .exe file!"             Else                 Try                     FileUpload1.SaveAs(decrpath & _                        FileUpload1.FileName)                     Label1.Text = "File name: " & _                       FileUpload1.PostedFile.FileName & "<br>" & _                       "File Size: " & _                       FileUpload1.PostedFile.ContentLength & " kb<br>" & _                       "Content type: " & _                       FileUpload1.PostedFile.ContentType                 Catch ex As Exception                     Label1.Text = "ERROR: " & ex.Message.ToString()                 End Try             End If         Else             Label1.Text = "You have not specified a file!"         End If            End Sub   Como vemos en el código anterior tambien hemos agregado otros elementos los cuales nos dirán el nombre del archivo, el tipo de contenido y el tamaño en kb una vez que el archivo ha sido súbido al servidor. Por último deben tomar en cuenta que decrpath es la ruta en donde será subido el archivo, la cual deben variar a su gusto.

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    I'm new to ofbiz so try to keep your answer as simple as possibly. If you can give examples that would be kind. My problem is I created a project inside the ofbiz/hot-deploy folder namely productionmgntSystem. Inside the folder ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem I created a file app_details_1.ftl. The following are the code of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server. The file is get from user " tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1". But the file is not uploaded. Give me a good solution for uploading a file to the server.

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