Search Results

Search found 14260 results on 571 pages for 'regex group'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 156/571 | < Previous Page | 152 153 154 155 156 157 158 159 160 161 162 163  | Next Page >

  • Correct syntax for matching a string inside a variable against an array

    - by Jamex
    Hi, I have a variable, $var, that contains a string of characters, this is a dynamic variable that contains the values from inputs. $var could be 'abc', or $var could be 'blu', I want to match the string inside variable against an array, and return all the matches. $array = array("blue", "red", "green"); What is the correct syntax for writing the code in php, my rough code is below $match = preg_grep($var, $array); (incorrect syntax of course) I tried to put quotes and escape slashes, but so far no luck. Any suggestion? TIA

    Read the article

  • Using `rack-rewrite` to Remove the Month and Date from a Permlink

    - by Bryan Veloso
    I've started the process of moving my blog to Octopress, but unfortunately, a limitation of Jekyll doesn't allow me to use abbreviated month names for my permalinks. Therefore I'm looking to just get rid of the month and day bits altogether. I'ved read in this article that you can use rack-rewrite to take care of the redirection, since I am using Heroku to host this. So how would I turn: This: example.com/journal/2012/jan/03/post-of-the-day/ Into this: example.com/journal/2012/post-of-the-day/ Extra points: If I had another rule that redirected /blog/ to /journal/, would that rule still adhere to the above one as well? So from: This: example.com/blog/2012/jan/03/post-of-the-day/ To this: example.com/journal/2012/jan/03/post-of-the-day/ And finally to: example.com/journal/2012/post-of-the-day/ Thanks for the assistance in advance. :)

    Read the article

  • String pattern matching in Javascript

    - by kwokwai
    Hi all, I am doing some self learning about Patern Matching in Javascript. I got a simple input text field in a HTML web page, and I have done some Javascript to capture the string and check if there are any strange characters other than numbers and characters in the string. But I am not sure if it is correct. Only numbers, characters or a mixture of numbers and characters are allowed. var pattern = /^[a-z]+|[A-Z]+|[0-9]+$/; And I have another question about Pattern Matching in Javascript, what does the percentage symbol mean in Pattern matching. For example: var pattern = '/[A-Z0-9._%-]+@[A-Z0-9.-]+\.[A-Z]{2,4}/';

    Read the article

  • How to make WPF Listview works same as Photoshop layer

    - by Youngjae
    As we can see in Photoshop layer window (or other image editting tool also), it has several features: groups with folder-like header (collapse/expandable) ungroupped item (no header) sort "manually" by dragging. In case of No 1, I made groupped item with expander control. (ref: http://www.dotnetspark.com/kb/1753-expand-and-collapse-listbox-group-header.aspx) In case of No 3, Sort manually can be solved with this code. (ref: codeproject.com/kb/WPF/ListViewDragDropManager.aspx) but I don't know how to list ungroupped items together. Of course, the ungroupped items may not have a header. I am using ICollectionView and MVVM. Does ICollectionView can make it?

    Read the article

  • regexp target last main li in list

    - by veilig
    I need to target the starting tag of the last top level LI in a list that may or may-not contain sublists in various positions - without using CSS or Javascript. Is there a simple/elegant regexp that can help with this? I'm no guru w/ them, but it appears the need for greedy/non-greedy selectors when I'm selecting all the middle text (.*) / (.+) changes as nested lists are added and moved around in the list - and this is throwing me off. $pattern = '/^(<ul>.*)<li>(.+<\/li><\/ul>)$/'; $replacement = '$1<li id="lastLi">$3'; Perhaps there is an easier approach?? converting to XML to target the LI and then convert back? ie: Single Element <ul> <li>TARGET</li> </ul> Multiple Elements <ul> <li>foo</li> <li>TARGET</li> </ul> Nested Lists before end <ul> <li> foo <ul> <li>bar</li> </ul> <li> <li>TARGET</li> </ul> Nested List at end <ul> <li>foo</li> <li> TARGET <ul> <li>bar</li> </ul> </li> </ul>

    Read the article

  • Need help parsing HTML with a regex in python

    - by laspal
    Hi, My string is mystring = "<tr><td><span class='para'><b>Total Amount : </b>INR (Indian Rupees) 100.00</span></td></tr>" My problem here is I have to search and get the total amount test = re.search("(Indian Rupees)(\d{2})(?:\D|$)", mystring) but my test give me None. How can I get the values and values can be 10.00, 100.00, 1000.00 Thanks

    Read the article

  • Simple PHP form Validation and the validation symbols

    - by Cool Hand Luke UK
    Hi have some forms that I want to use some basic php validation (regular expressions) on, how do you go about doing it? I have just general text input, usernames, passwords and date to validate. I would also like to know how to check for empty input boxes. I have looked on the interenet for this stuff but I haven't found any good tutorials. Thanks

    Read the article

  • How Do You Parse Column Data ?

    - by discwiz
    I am trying to parse a file generated by LGA Tracon that lists the position data for aircraft over a given time frame. The data of interest starts with TRACKING DATA and ends with SST and there are thousands of entries per file. The system generating the file, Common ARTS, is very rigid in its formatting and we can expect the column spacing to be consistent. Any help would be greatly appreciated. Thanks, Here is an image to preserve the exact formatting Here is a reduced text file. link text

    Read the article

  • Dealing with regular expressions, Python

    - by Gusto
    I want to remove some symbols from a string using a regular expression, for example: == (that occur both at the beginning and at the end of a line), * (at the beginning of a line ONLY). def some_func(): clean = re.sub(r'= {2,}', '', clean) #Removes 2 or more occurrences of = at the beg and at the end of a line. clean = re.sub(r'^\* {1,}', '', clean) #Removes 1 or more occurrences of * at the beginning of a line. What's wrong with my code? It seems like expressions are wrong. How do I remove a character/symbol if it's at the beginning or at the end of the line (with one or more occurrences)?

    Read the article

  • Regular Expression with Names and Emails

    - by Nina
    I am having a problem with regular expressions at the moment. What I'm trying to do is that for each line through the iteration, it checks for this type of pattern: Lastname, Firstname If it finds the name, then it will take the first letter of the first name, and the first six letters of the lastname and form it as an email. I have the following: $checklast = "[A-z],"; $checkfirst = "[A-z]"; if (ereg($checklast, $parts[1])||ereg($checkfirst, $parts[2])){ $first = preg_replace($checkfirst, $checkfirst{1,1}, $parts[2]); print "<a href='mailto:[email protected];'> $parts[$i] </a>"; } This one obviously broke the code. But I was initially attempting to find only the first letter of the firstname and then after that the first six letters of the lastname followed by the @email.com This didn't work out too well. I'm not sure what to do at this point. Any help is much appreciated.

    Read the article

  • [Python] OR in regular expression?

    - by www.yegorov-p.ru
    Hello. I have text file with several thousands lines. I want to parse this file into database and decided to write a regexp. Here's part of file: blablabla checked=12 unchecked=1 blablabla unchecked=13 blablabla checked=14 As a result, I would like to get something like (12,1) (0,13) (14,0) Is it possible?

    Read the article

  • How can I execute a bunch of editor commands stored in a file in VIM?

    - by LES2
    I have read the other posts, e.g., http://stackoverflow.com/questions/1830886/vim-executing-a-list-of-editor-commands and others. The answer isn't clear to me for my case. I have some editor commands that I generated from an SQL query. It uses :s/foo/bar to change country codes (from FIPS to a non-standard code set). Here's a sample of the file: :s/CB/CAMBO :s/CQ/NMARI :s/KV/KOSOV :s/PP/PAPUA ... I have saved that in a file called fipsToNonStd.vim (unsure about the correct extension). I want to run those commands one after another. What's the easiest way to do so? Thanks a bunch! SO Rocks!

    Read the article

  • Trying to create a Reg Ex for the following patterns

    - by Travis
    Here are the patterns: Red,Green (and so on...) Red (+5.00),Green (+6.00) (and so on...) Red (+5.00,+10.00),Green (+6.00,+20.00) (and so on...) Red (+5.00),Green (and so on...) Each attribute ("Red,"Green") can have 0, 1, or 2 modifiers (shown as "+5.00,+10.00", etc.). I need to capture each of the attributes and their modifiers as a single string (i.e. "Red (+5.00,+10.00)", "Green (+6.00,+20.00)". Help?

    Read the article

  • How can I match a match a null byte (0x00) in the Visual Studio binary editor with a find using a re

    - by Paul K
    Open a file in the Visual Studio binary editor that contains a null byte (0x00), then use the Quick Find feature (Ctrl +F) to find null bytes. I would have thought I could use a regular expression such as \x00 to match null bytes but it doesn't work. Searching for any other hex value using this method works fine. Is this a VS bug, 'feature', or am I just missing something? Is there a work around?

    Read the article

  • Python program to search for specific strings in hash values (coding help)

    - by Diego
    Trying to write a code that searches hash values for specific string's (input by user) and returns the hash if searchquery is present in that line. Doing this to kind of just learn python a bit more, but it could be a real world application used by an HR department to search a .csv resume database for specific words in each resume. I'd like this program to look through a .csv file that has three entries per line (id#;applicant name;resume text) I set it up so that it creates a hash, then created a string for the resume text hash entry, and am trying to use the .find() function to return the entire hash for each instance. What i'd like is if the word "gpa" is used as a search query and it is found in s['resumetext'] for three applicants(rows in .csv file), it prints the id, name, and resume for every row that has it.(All three applicants) As it is right now, my program prints the first row in the .csv file(print resume['id'], resume['name'], resume['resumetext']) no matter what the searchquery is, whether it's in the resumetext or not. lastly, are there better ways to doing this, by searching word documents, pdf's and .txt files in a folder for specific words using python (i've just started reading about the re module and am wondering if this may be the route, rather than putting everything in a .csv file.) def find_details(id2find): resumes_f=open("resume_data.csv") for each_line in resumes_f: s={} (s['id'], s['name'], s['resumetext']) = each_line.split(";") resumetext = str(s['resumetext']) if resumetext.find(id2find): return(s) else: print "No data matches your search query. Please try again" searchquery = raw_input("please enter your search term") resume = find_details(searchquery) if resume: print resume['id'], resume['name'], resume['resumetext']

    Read the article

  • Mod_rewrite works on local, not on remote, version?

    - by TylerT
    I have this site. Let's call it htp://www.mysite.com I have a rewrite rule to change htp://www.mysite.com/?q=words%20etc/0/10 into http://www.mysite.com/words%20etc/0/10 (or http://www.mysite.com//0/10 or http://www.mysite.com/0/10) .htaccess:ErrorDocument 404 htp://www.mysite.com/404.html options +FollowSymlinks rewriteEngine on rewriteCond %{REQUEST_URI} !-f rewriteCond %{REQUEST_URI} !-d rewriteCond %{REQUEST_URI} !index\.php rewriteRule ^/?([^/]+?)?/?([0-9]+?)/([0-9]+?)$ index.php/%{THE_REQUEST} [NC] Now, this works on my local apache 2.2.11 server, no errors. However on my host's apache 1.3.41 server, I get the following error: [Sat Mar 5 21:42:14 2011] [alert] [client [ip]] /home/_/public_html/mysite.com/.htaccess: RewriteRule: cannot compile regular expression '^/?([^/]+?)?/?([0-9]+?)/([0-9]+?)$'\n I imagine it's something quirky about the apache version as other sites on this host use mod_rewrite without a hitch. I've tried removing the +followSymlinks line, even the rewrite engine line. I haven't tried removing the conditions cause I don't think I should have to, I'm probably wrong.

    Read the article

  • Why does this regular expression for sed break inside Makefile?

    - by jcrocholl
    I'm using GNU Make 3.81, and I have the following rule in my Makefile: jslint : java org.mozilla.javascript.tools.shell.Main jslint.js mango.js \ | sed 's/Lint at line \([0-9]\+\) character \([0-9]\+\)/mango.js:\1:\2/' This works fine if I enter it directly on the command line, but the regular expression does not match if I run it with "make jslint". However, it works if I replace \+ with \{1,\} in the Makefile: jslint : java org.mozilla.javascript.tools.shell.Main jslint.js mango.js \ | sed 's/Lint at line \([0-9]\{1,\}\) character \([0-9]\{1,\}\)/mango.js:\1:\2/' Is there some special meaning to \+ in Makefiles, or is this a bug?

    Read the article

  • PHP: URL detection (regexp) includes line breaks

    - by marco92w
    I want to have a function which gets a text as the input and gives back the text with URLs made to HTML links as the output. My draft is as follows: function autoLink($text) { return preg_replace('/https?:\/\/[\S]+/i', '<a href="\0">\0</a>', $text); } But this doesn't work properly. For the input text which contains ... http://www.google.de/ ... I get the following output: <a href="http://www.google.de/<br">http://www.google.de/<br</a> /> Why does it include the line breaks? How could I limit it to the real URL? Thanks in advance!

    Read the article

  • Alter Regular Expression to Return 2 Values Instead of 3 from userAgent String

    - by Jay
    I've taken a regular expression from jQuery to detect if a browser's engine is WebKit and gets it's version number, it returns 3 values extracted from the userAgent string: webkit/….…, webkit and ….… [“….…” being the version number]. I would like the regular expression to return just 2 values: webkit and ….…. I'm rubbish at regular expressions, so please can you give an explanation of the expression with your answer. The regular expression I'm currently working with and wish to improve is: /(webkit)[\/]([\w.]+)/. I appreciate all your help, thanks in advance!

    Read the article

  • How to detect identical part(s) inside string?

    - by Horace Ho
    I try to break down the http://stackoverflow.com/questions/2711961/decoding-algorithm-wanted question into smaller questions. This is Part I. Question: two strings: s1 and s2 part of s1 is identical to part of s2 space is separator how to extract the identical part(s)? example 1: s1 = "12 November 2010 - 1 visitor" s2 = "6 July 2010 - 100 visitors" the identical parts are "2010", "-", "1" and "visitor" example 2: s1 = "Welcome, John!" s2 = "Welcome, Peter!" the identical parts are "Welcome," and "!" Python and Ruby preferred. Thanks

    Read the article

  • Which is more efficient regular expression?

    - by Vagnerr
    I'm parsing some big log files and have some very simple string matches for example if(m/Some String Pattern/o){ #Do something } It seems simple enough but in fact most of the matches I have could be against the start of the line, but the match would be "longer" for example if(m/^Initial static string that matches Some String Pattern/o){ #Do something } Obviously this is a longer regular expression and so more work to match. However I can use the start of line anchor which would allow an expression to be discarded as a failed match sooner. It is my hunch that the latter would be more efficient. Can any one back me up/shoot me down :-)

    Read the article

  • How to replace only part of the match with python re.sub

    - by Arty
    I need to match two cases by one reg expression and do replacement 'long.file.name.jpg' - 'long.file.name_suff.jpg' 'long.file.name_a.jpg' - 'long.file.name_suff.jpg' I'm trying to do the following re.sub('(\_a)?\.[^\.]*$' , '_suff.',"long.file.name.jpg") But this is cut the extension '.jpg' and I'm getting long.file.name_suff. instead of long.file.name_suff.jpg I understand that this is because of [^.]*$ part, but I can't exclude it, because I have to find last occurance of '_a' to replace or last '.' Is there a way to replace only part of the match?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 152 153 154 155 156 157 158 159 160 161 162 163  | Next Page >