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  • Removing whitespace in Java string?

    - by waitinforatrain
    Hi guys, I'm writing a parser for some LISP files. I'm trying to get rid of leading whitespace in a string. The string contents are along the lines of: :FUNCTION (LAMBDA (DELTA PLASMA-IN-0) (IF (OR (>= #61=(+ (* 1 DELTA) PLASMA-IN-0) 100) (<= #61# 0)) PLASMA-IN-0 #61#)) The tabs are all printed as 4 spaces in the file, so I want to get rid of these leading tabs. I tried to do this: string.replaceAll("\\s{4}", " ") - but it had no effect at all on the string. Does anyone know what I'm doing wrong? Is it because it is a multi-line string? Thanks

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  • VB.Net Split A Group Of Text

    - by Ben
    I am looking to split up multiple lines of text to single them out, for example: Url/Host:ftp://server.com/1 Login:Admin1 Password:Password1 Url/Host:ftp://server.com/2 Login:Admin2 Password:Password2 Url/Host:ftp://server.com/3 Login:Admin3 Password:Password3 How can I split each section into a different textbox, so that section one would be put into TextBox1.Text on its own: Url/Host:ftp://server.com/1 Login:Admin1 Password:Password1 Thanks in advance :)!

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  • How would I create a VIM or Vi command to delete all text after a certain character for every line i

    - by Jason Down
    Scenario: I have a text file that has pipe (as in the "|" character) delimited data. Each field of data in the pipe delimited fields can be of variable length, so counting characters won't work (or using some sort of substring function... if that even exists in VIM). Is it possible, using VIM / Vi to delete all data from the second pipe to the end of the line for the entire file? There are approx 150,000 lines, so doing this manually would only be appealing to a masochist... e.g. Change the following lines from: 1111|random sized text 12345|more random data la la la|1111|abcde 2222|random sized text abcdefghijk|la la la la|2222|defgh 3333|random sized text|more random data|33333|ijklmnop to: 1111|random sized text 12345 2222|random sized text abcdefghijk 3333|random sized text I'm sure this can be done somehow... I hope. TIA UPDATE: I should have mentioned that I'm running this on Windows XP, so I don't have access to some of the mentioned *nix commands (CUT is not recognized on Windows).

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  • Perl Strip Comments with Regex Unique Request

    - by YoDar
    Hello, I'm running a code that read files, do some parsing but need to ignore all comments. There are good explanations how to conduct it. like this link $/ = undef; $_ = <>; s#/\*[^*]*\*+([^/*][^*]*\*+)*/|("(\\.|[^"\\])*"|'(\\.|[^'\\])*'|.[^/"'\\]*)#defined $2 ? $2 : ""#gse; print; My first problem is that after run this line $/ = undef; my code doesn't work properly. Actually, I don't know what it does. But if I could turn it back after ignoring all comments it will be helpful. In general, What is the useful way to ignore all comments without changing the rest of the code ? Thanks, YoDar

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  • User will input some filter criteria -- how can I turn it into a regular expression for String.match

    - by envinyater
    I have a program where the user will enter a string such as PropertyA = "abc_*" and I need to have the asterisk match any character. In my code, I'm grabbing the property value and replacing PropertyA with the actual value. For instance, it could be abc_123. I also pull out the equality symbol into a variable. It should be able to cover this type of criteria PropertyB = 'cba' PropertyC != '*-this' valueFromHeader is the lefthand side and value is the righthand side. if (equality.equals("=")) { result = valueFromHeader.matches(value); } else if (equality.equals("!=")) { result = !valueFromHeader.matches(value); } EDIT: The existing code had this type of replacement for regular expressions final String ESC = "\\$1"; final String NON_ALPHA = "([^A-Za-z0-9@])"; final String WILD = "*"; final String WILD_RE_TEMP = "@"; final String WILD_RE = ".*"; value = value.replace(WILD, WILD_RE_TEMP); value = value.replaceAll(NON_ALPHA,ESC); value = value.replace(WILD_RE_TEMP, WILD_RE); It doesn't like the underscore here... abcSite_123 != abcSite_123 (evaluates to true) abcSite_123$1.matches("abcSite$1123") It doesn't like the underscore...

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  • sorting group of lines

    - by benjamin button
    I have a text file like below iv_destination_code_10 TAP310_mapping_RATERUSG_iv_destination_code_10 RATERUSG.iv_destination_code_10 = WORK.maf_feature_info[53,6] iv_destination_code_2 TAP310_mapping_RATERUSG_iv_destination_code_2 RATERUSG.iv_destination_code_2 = WORK.maf_feature_info[1,6] iv_destination_code_3 TAP310_mapping_RATERUSG_iv_destination_code_3 RATERUSG.iv_destination_code_3 = WORK.maf_feature_info[7,6] iv_destination_code_4 TAP310_mapping_RATERUSG_iv_destination_code_4 RATERUSG.iv_destination_code_4 = WORK.maf_feature_info[13,6] iv_destination_code_5 TAP310_mapping_RATERUSG_iv_destination_code_5 RATERUSG.iv_destination_code_5 = WORK.maf_feature_info[19,6] iv_destination_code_6 TAP310_mapping_RATERUSG_iv_destination_code_6 RATERUSG.iv_destination_code_6 = WORK.maf_feature_info[29,6] iv_destination_code_7 TAP310_mapping_RATERUSG_iv_destination_code_7 RATERUSG.iv_destination_code_7 = WORK.maf_feature_info[35,6] iv_destination_code_8 TAP310_mapping_RATERUSG_iv_destination_code_8 RATERUSG.iv_destination_code_8 = WORK.maf_feature_info[41,6] iv_destination_code_9 TAP310_mapping_RATERUSG_iv_destination_code_9 RATERUSG.iv_destination_code_9 = WORK.maf_feature_info[47,6] combination of three lines form a unit: iv_destination_code_9 TAP310_mapping_RATERUSG_iv_destination_code_9 RATERUSG.iv_destination_code_9 = WORK.maf_feature_info[47,6] is one unit. iv_destination_code_9 9 indicates the number by which i have to sort 10 9 8.... i need a shell script/awk which will sort the units in a descending order. how is it possible?

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  • Retain Delimiters when Splitting String

    - by JoeC
    Edit: OK, I can't read, thanks to Col. Shrapnel for the help. If anyone comes here looking for the same thing to be answered... print_r(preg_split('/([\!|\?|\.|\!\?])/', $string, null, PREG_SPLIT_DELIM_CAPTURE)); Is there any way to split a string on a set of delimiters, and retain the position and character(s) of the delimiter after the split? For example, using delimiters of ! ? . !? turning this: $string = 'Hello. A question? How strange! Maybe even surreal!? Who knows.'; into this array('Hello', '.', 'A question', '?', 'How strange', '!', 'Maybe even surreal', '!?', 'Who knows', '.'); Currently I'm trying to use print_r(preg_split('/([\!|\?|\.|\!\?])/', $string)); to capture the delimiters as a subpattern, but I'm not having much luck.

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  • JavaScript Regular expressions, match and replace link

    - by Thoman
    Hello please help me <html> <body> http://domainname.com/abc/xyz.zip http://domainname2.com/abc/xyz.zip </body> </html> I want replace with link and out put like <html> <body> <a href="http://domainname.com/abc/xyz.zip">http://domainname.com/abc/xyz.zip</a> <a href="http://domainname2.com/abc/xyz.zip">http://domainname2.com/abc/xyz.zip</a> </body> </html> Great Thank

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  • How to grep lines having specific format.

    - by Nitin
    I have got a file with following format. 1234, 'US', 'IN',...... 324, 'US', 'IN',...... ... ... 53434, 'UK', 'XX', .... ... ... 253, 'IN', 'UP',.... 253, 'IN', 'MH',.... Here I want to extract only those lines having 'IN' as 2nd keyword. i.e. 253, 'IN', 'UP',.... 253, 'IN', 'MH',.... Can any one please tell me a command to grep it.

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  • How to start matching and saving matched from exact point in a text

    - by yuliya
    I have a text and I write a parser for it using regular expressions and perl. I can match what I need with two empty lines (I use regexp), because there is a pattern that allows recognize blocks of text after two empty lines. But the problem is that the whole text has Introduction part and some text in the end I do not need. Here is a code which matches text when it finds two empty lines #!/usr/bin/perl use strict; use warnings; my $file = 'first'; open(my $fh, '<', $file); my $empty = 0; my $block_num = 1; open(OUT, '>', $block_num . '.txt'); while (my $line = <$fh>) { chomp ($line); if ($line =~ /^\s*$/) { $empty++; } elsif ($empty == 2) { close(OUT); open(OUT, '>', ++$block_num . '.txt'); $empty = 0; } else { $empty = 0;} print OUT "$line\n"; } close(OUT); This is example of the text I need (it's really small :)) this is file example I think that I need to iterate over the text till the moment it will find the word LOREM IPSUM with regexps this kind "/^LOREM IPSUM/", because it is the point from which needed text starts(and save the text in one file when i reach the word). And I need to finish iterating over the text when INDEX word is fount or save the text in separate file. How could I implement it. Should I use next function to proceed with lines or what? BR, Yuliya

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  • Regular Expression - Capture and Replace Select Sequences

    - by Chad
    Take the following file... ABCD,1234,http://example.com/mpe.exthttp://example/xyz.ext EFGH,5678,http://example.com/wer.exthttp://example/ljn.ext Note that "ext" is a constant file extension throughout the file. I am looking for an expression to turn that file into something like this... ABCD,1234,http://example.com/mpe.ext ABCD,1234,http://example/xyz.ext EFGH,5678,http://example.com/wer.ext EFGH,5678,http://example/ljn.ext In a nutshell I need to capture everything up to the urls. Then I need to capture each URL and put them on their own line with the leading capture. I am working with sed to do this and I cannot figure out how to make it work correctly. Any ideas?

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  • How can i give password validation in flex

    - by praveen
    I want the validator for password text input. At least one Upper case letter At least one numeric character At least one special character such as @, #, $, etc. should be there in password how can i give it in action script or mxml.please help me. Thanks.

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  • regular expression: extract last 2 characters

    - by dotnet-practitioner
    what is the best way to extract last 2 characters of a string using regular expression. For example, I want to extract state code from the following "A_IL" I want to extract IL as string.. please provide me C# code on how to get it.. string fullexpression = "A_IL"; string StateCode = some regular expression code.... thanks

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  • Getting the title of a page in PHP

    - by Francesc
    Hi. When I want to get the title of a remote webiste, I use this script: function get_remotetitle($urlpage) { $file = @fopen(($urlpage),"r"); $text = fread($file,16384); if (preg_match('/<title>(.*?)<\/title>/is',$text,$found)) { $title = $found[1]; } else { $title = 'Title N/A'; } return $title; } But when I parase a webiste title with accents, I get "?". But if I look in PHPMyAdmin, I see the accents correctly. What's happening?

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  • validation of special characters

    - by jpallavi
    I want to validate login name with special characters !@#S%^*()+_-?/<:"';. space using regular expression in ruby on rails. These special characters should not be acceptable. What is the code for that? Thanks, Pallavi

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  • Regular Expressions .NET

    - by Fosa
    I need a regular expression for some arguments that must match on a string. here it is... The string exists out of minimum 8 en maximum 20 characters. These characters of this string may be characters of the alfabet or special chars --With other words..all charachters except from the whitespaces In the complete string there must be atleast 1 number. The string cannot start with a number or an underscore The last 2 characters of the string must be identical, But it doenst matter if those last --identical characters are capital or non-capital (case insensitive) Must match all : +234567899 a_1de*Gg xy1Me*__ !41deF_hij2lMnopq3ss C234567890123$^67800 *5555555 sDF564zer"" !!!!!!!!!4!!!!!!!!!! abcdefghijklmnopq9ss May not match : Cannot be less then 8 or more then 20 chars: a_1+Eff B41def_hIJ2lmnopq3stt Cannot contain a whitespace: A_4 e*gg b41def_Hij2l nopq3ss Cannot start with a number or an underscore: __1+Eff 841DEf_hij2lmnopq3stt cannot end on 2 diffrent characters: a_1+eFg b41DEf_hij2lmnopq3st Cannot be without a number in the string: abCDefghijklmnopqrss abcdef+++dF !!!!!!!!!!!!!!!!!!!! ------------------------------------------------------ This is what I have so far...But I'm really breaking my head on this... If you Don't know the answer completely it's not a problem... I just want to get in the right direction ([^0-9_])(?=.*\d)(\S{8,20})(?i:[\S])\1

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  • Is it safe to validate a URL with a regexp?

    - by Vilx-
    In my web app I've got a form field where the user can enter an URL. I'm already doing some preliminary client-side validation and I was wondering if I could use a regexp to validate if the entered string is a valid URL. So, two questions: Is it safe to do this with a regexp? A URL is a complex beast, and just like you shouldn't use a regexp for parsing HTML, I'm worried that it might be unsuitable for a URL as well. If it can be done, what would be a good regexp for the task? (I know that Google turns up countless regexps, but I'm worried about their quality). My goal is to prevent a situation where the URL appears in the web page and is unusable by the browser.

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  • Way to partialy match a Ruby string using Regexp

    - by Fabiano PS
    I'm working on 2 cases: assume I have those var: a = "hello" b = "hello-SP" b = "not_hello" 1 - Any partial matches I want to accept any string that has the var a inside, so b and c would match. 2 - Patterned match I want to match a string that has a inside, followed by '-', so b would match, c does not. I am having problem, because I always used the syntax /expression/ to define Regexp, so how dinamicaly define an RegExp on Ruby??

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  • Reading a line backwards

    - by Jimmy
    Hi, I'm using regular expression to count the total spaces in a line (first occurrence). match(/^\s*/)[0].length; However this reads it from the start to end, How can I read it from end to start. Thanks

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  • split with javascript

    - by Sourabh
    Hi below is something I am trying to do with JavaScript. If I have string like str = "how are you? hope you are doing good" ; now I want to split it with ? but I dont want to lose the "?". Instead I want to break the string just after the question mark such a way that question mark is with the first segment that we have after splitting str what should I get is ["how are you?","hope you are doing good"] I am not sure if it can be done with Javascript split() function ,please help.

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