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  • how to make PHP lists all Linux Users?

    - by Data-Base
    Hello I want to build a php based site that (automate) some commands on my Ubuntu Server first thing I did was going to the file (sudoers) and add the user www-data so I can execute php commands with root privileges! # running the web apps with root power!!! www-data ALL=(ALL) NOPASSWD: ALL then my PHP code was <?php $command = "cat /etc/passwd | cut -d\":\" -f1"; echo 'running the command: <b>'.$command."</b><br />"; echo exec($command); ?> it returns only one user (the last user) !!! how to make it return all users? thank you

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  • Why won't my PHP script work?

    - by sadicool
    I have a script that reports the following error: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'admin'@'localhost' (using password: YES) in C:\wamp\www\bits\includes\connect.inc.php on line 10 Notice: Undefined variable: l_error in C:\wamp\www\bits\includes\connect.inc.php on line 12 Notice: Undefined variable: l_cannotconnecttodatabase in C:\wamp\www\bits\includes\connect.inc.php on line 12 Why would this be?

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  • Building html structure in php or javascript?

    - by Adam
    I've been doing a lot of ajax calls and using the returned data to build html with javascript. However, I've noticed some people are returning the constructed html in the ajax calls since they're doing it all in php. What is the preferred method? I have a bunch of stuff already using javascript, so I guess I would prefer not changing everything to use just php. But, I'm assuming php would be more "secure."? The following is what I've been doing: $main_frag = $("<div class='order-container'/>"); $contact_frag = $("<div class='group'><div class='line-data'>Name: "+data.name+"</div><div class='line-data'>Email: "+data.email+"</div><div class='line-data'>Phone: "+data.phone+"</div></div>"); $address_frag = $("<div class='group'><div class='line-data'>Address 1: "+data.address_one+"</div><div class='line-data'>Address 2: "+address2+"</div><div class='line-data'>City: "+data.city+"</div><div class='line-data'>Province: "+data.province+"</div><div class='line-data'>Postal Code: "+data.postal+"</div></div>"); etc.. I just want to hear the opinions of the community.

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  • javascript send one way message to php

    - by user360322
    How can I use javascript to send a one way message to php? I would like to get the browser information from javascript and just send it to php in the background. I know I can get some of this from php, but I'd rather use javascript. Is there a way to do this without a framework like jquery?

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  • Vertically And Horizonatally center main wrap div

    - by Hello you all men
    Now i try <html> <head> <title>?????????????????</title> <style type="text/css"> body { margin-left: auto; margin-right:auto; } #wrap { background: black; margin-left: auto; margin-right:auto; height:450px; width:450px; position:absolute; top:50%; right:50%; left:50%; margin-top:-225px; } </style> </head> <body> <div id="wrap"> Hello </div> </body> </html> ?????

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  • Broken php/localhost/something

    - by ghego1
    I was trying to install the mcrypt libraries following this tutorial (http://www.glenscott.co.uk/blog/2011/08/29/install-mcrypt-php-extension-on-mac-os-x-lion/), but something must have gone wrong and now when I load a php page on my localhost I see this: query="SELECT DISTINCT ".$field." as a,".$field2." as b FROM ".$tab." ".$where. " Group by ".$field." order By ".$orderBy; return $this->query; } And all the remaining code of the php page that should get loaded. I've retrieved the previous versions of the private/etc folder and usr/lib/php folder with time machine but it didn't help. And now if I execute sudo pachectl restart it gives me this error: sudo: no valid sudoers sources found, quitting (while before it worked. PS I'm on a mac with Mountain Lion

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  • I want the actual file name that is returned by a PHP script

    - by Aymon Fournier
    I am writing a python script that downloads a file given by a URL. Unfortuneatly the URL is in the form of a PHP script i.e. www.website.com/generatefilename.php?file=5233 If you visit the link in a browser, you are prompted to download the actual file and extension. I need to send this link to the downloader, but I can't send the downloader the PHP link. How would I get the full file name in a usable variable?

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  • text in div not going to next line

    - by Kia Dull
    for some reason the text in my div doesn't go to the next line, i've tried several different css elements which don't seem to work.... word-wrap:break word, just jumbles the letters... what i want is for one there is an extra word it goes down to the next line like it's supposed to here is my code this is the div it's in #top7 { width: 150px; height:auto; margin: 5px; display: block; float: left; word-wrap:break-word; } text that it's in #p6 { font-family: Myriad Pro; margin: 1px; font-size: 22px; background-color:#540f45; padding: 5px 5px 3px 4px; margin:4px; } a { text-decoration: none; color: white; text-align: right; font-family: Myriad Pro; } here is the php function that retrieves the data from the database <p id='p6'><?php echo "<a href='' "</a>"; ?></p> this is all wrapped in these two id's body { background:#603e4f; display: block; } #foursquare { background-color:#603e4f; width: 290px; display: block; position: absolute; }

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  • need to loop through a PHP array in JavaScript

    - by user296516
    Hi guys, For example I have a PHP array, such as this one <?php $s= array('a','b','c','d','e','f') ; ?> And I need to loop through it in JavaScript, any ideas how do I do that? for ( i=0 ; i < <?php echo sizeof($s) ?> ; i++) { document.write('<?php echo $s [somehow need to get the 'i' value into here] ?>'); } Any suggestions? Thanks!

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  • Google app engine-php: script handler

    - by Eve
    I try to create php web app using GAE. In the GAE tutorial, "A script handler executes a PHP script to handle the request that matches the URL pattern. The mapping defines a URL pattern to match, and the script to be executed" Now I want to map the url with the file having same name in the folder, e.g. if the url is /hello.* , it will map the file name hello.php in the folder. And if it is /hello1.*, hello1.php in the folder will be responded to the server. I thought this should be done directly by mapping the name of the url with the name in the folder. But if I left empty for the handler in the app.yaml, I got an error. So I want to know how to set up the handler in app.yaml?

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  • trying to use PHP extract() within a function

    - by samuelf
    Hi, I have the two following files: main.php include("functions.php") __EXTRACT(); echo $testvar; functions.php function __EXTRACT(){ extract($_POST, EXTR_SKIP); } However, having a form with a textbox called testvar I can't get the extract function to extract the data.. if I remove the function call and insert it the extract statement directly into main.php it works. The include is not a problem as other functions in it works. Any ideas? Cheers

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  • Execute PHP file in background

    - by Spyric
    I have some php code, that execute for a very long time. I need to realise next scheme: User enter on some page(page 1) This page starts execution of my large PHP script in background .(Every change is writting to database) We sent every N seconds query to database to get current status of execution. I don't want to use exec command because 1000 users makes 1000 php processes. It's not way for me...

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  • PHP Localhost Application connect to server database

    - by Cross Vander
    I want to ask about how to connect my localhost application (C:xampp/htdocs/myproject) to database at my server host (www.someweb.somedomain)? Am I possible to do that? If it is, how to connect it at my php config? Right now my config (server.php) is: <?php $host = "my web IP public:3306"; $user = "root"; $pass = ""; $db = "dispatcherDB"; $conn = mysql_connect($host, $user, $pass) or die ("Cant connect to mySQL"); mysql_select_db($db); ?> what I got: Warning: mysql_connect(): No connection could be made because the target machine actively refused it. in C:\xampp\htdocs\XMS\server.php on line 7 So, what must I filled for $host? I'm trying using website IP, it still can't connect. Maybe there's someone here have experience at this problem? Sorry for my bad English

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  • Javascript in php

    - by user506539
    I have a form where user enters category, it gets inserted into db and it has to go to other page to select an image, after selection image id has to get into category table. I am doing some thing like this <?php error_reporting(E_ALL ^ E_NOTICE); $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mydocair", $con); $ThirdPartyCategoryName =$_POST['ThirdPartyCategoryName']; $checkformembers = mysql_query("SELECT * FROM thirdpartycategorymaster WHERE ThirdPartyCategoryName = '$ThirdPartyCategoryName'"); if(mysql_num_rows($checkformembers) != 0) { header('location:newcat.php?msg=category exists'); } else { $sql="INSERT INTO thirdpartycategorymaster (ThirdPartyCategoryID, ThirdPartyCategoryName) VALUES ('$_POST[ThirdPartyCategoryID]', '$_POST[ThirdPartyCategoryName]' )"; } if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } mysql_close($con); ?> <?php $res = mysql_query("SELECT ThirdPartyCategoryID FROM thirdpartycategorymaster"); while($row = mysql_fetch_array($res)) { "<script type='text/javascript'> if(window.confirm("Do you want to insert image for category?")) { document.location = "imgcat.php?id="<?php echo row2['ThirdPartyCategoryID']; ?>"" } </script>"; } ?>

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  • Run PHP code on a specific domain only

    - by curtismchale
    I need to echo out some specific php code only on the sub-domain of a site. This is where I am so far. <?php if($_SERVER['SERVER_NAME'] != "http://support.demo.com") echo "<?php bb_head(); ?>"; ?> Of course if this worked I'd not be asking a question. Help is appreciated.

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  • Wordpress nav not visible in pages like articles, blog & search

    - by kwek-kwek
    My wordpress*(a custom template)* nav is all working on all of the pages but now I found out that the Main nav doesn't show on this pages All pages e.g. search.php, single.php, index.php, page.php all has <?php get_header(); ?> I really don't know whats wrong. Here is the code for my header.php <?php /** * @package WordPress * @subpackage Default_Theme */ ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" <?php language_attributes() ?>> <head> <meta http-equiv="Content-Type" content="<?php bloginfo('html_type'); ?>; charset=<?php bloginfo('charset'); ?>" /> <title><?php bloginfo('name'); ?> <?php wp_title(); ?></title> <link rel="stylesheet" href="<?php bloginfo('stylesheet_url'); ?>" type="text/css" media="screen,projection" /> <link rel="stylesheet" href="<?php bloginfo('template_url'); ?>/css/sifr.css" type="text/css" /> <script src="<?php bloginfo('template_url'); ?>/js/sifr.js" type="text/javascript"></script> <script src="<?php bloginfo('template_url'); ?>/js/sifr-config.js" type="text/javascript"></script> <script src="http://cdn.jquerytools.org/1.1.2/jquery.tools.min.js"></script> <?php wp_head(); ?> </head> <?php $current_page = $post->ID; $parent = 1; while($parent) { $page_query = $wpdb->get_row("SELECT post_name, post_parent FROM $wpdb->posts WHERE ID = '$current_page'"); $parent = $current_page = $page_query->post_parent; if(!$parent) $parent_name = $page_query->post_name; } ?> <body id="<?php echo (is_page()) ? "$parent_name" : ((is_home()) ? "blog" : ((is_search()) ? "other" : ((is_single()) ? "blog" : "blog"))); ?>"> <div id="BGtie"> <!--HEAD WRAPPER--> <div id="headwrapper"> <!--HEADER--> <div id="headContainer"> <div id="nameTag"> <a href="<?php echo get_option('home'); ?>/"><?php bloginfo('name'); ?></a> </div> <!--TOP NAV--> <div id="topNav"> <ul> <li><a href="<?php bloginfo('url'); ?>home">Home</a></li> <li><a href="#">Request info</a></li> <li><a href="#">Contact us</a></li> <?php do_action('icl_language_selector'); ?> </ul> </div> <!--END TOP NAV--> <!--MAIN NAV--> <?php if ( is_page() AND (strtolower(ICL_LANGUAGE_CODE) == 'fr') ) {include("main-nav-fr.php");} ?> <?php if (is_page() AND (strtolower(ICL_LANGUAGE_CODE) == 'en')) include("main-nav-en.php") ?> <!--END MAIN NAV--> </div> <!--END HEADER--> </div> <!--END HEAD WRAPPER--> </div>

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  • Using JQuery tabs in an HTML 5 page

    - by nikolaosk
    In this post I will show you how to create a simple tabbed interface using JQuery,HTML 5 and CSS.Make sure you have downloaded the latest version of JQuery (minified version) from http://jquery.com/download.Please find here all my posts regarding JQuery.Also have a look at my posts regarding HTML 5.In order to be absolutely clear this is not (and could not be) a detailed tutorial on HTML 5. There are other great resources for that.Navigate to the excellent interactive tutorials of W3School.Another excellent resource is HTML 5 Doctor.Two very nice sites that show you what features and specifications are implemented by various browsers and their versions are http://caniuse.com/ and http://html5test.com/. At this times Chrome seems to support most of HTML 5 specifications.Another excellent way to find out if the browser supports HTML 5 and CSS 3 features is to use the Javascript lightweight library Modernizr.In this hands-on example I will be using Expression Web 4.0.This application is not a free application. You can use any HTML editor you like.You can use Visual Studio 2012 Express edition. You can download it here. Let me move on to the actual example.This is the sample HTML 5 page<!DOCTYPE html><html lang="en">  <head>    <title>Liverpool Legends</title>    <meta http-equiv="Content-Type" content="text/html;charset=utf-8" >    <link rel="stylesheet" type="text/css" href="style.css">    <script type="text/javascript" src="jquery-1.8.2.min.js"> </script>     <script type="text/javascript" src="tabs.js"></script>       </head>  <body>    <header>        <h1>Liverpool Legends</h1>    </header>     <section id="tabs">        <ul>            <li><a href="http://weblogs.asp.net/controlpanel/blogs/posteditor.aspx?SelectedNavItem=Posts§ionid=1153&postid=9143136#first-tab">Defenders</a></li>            <li><a href="http://weblogs.asp.net/controlpanel/blogs/posteditor.aspx?SelectedNavItem=Posts§ionid=1153&postid=9143136#second-tab">Midfielders</a></li>            <li><a href="http://weblogs.asp.net/controlpanel/blogs/posteditor.aspx?SelectedNavItem=Posts§ionid=1153&postid=9143136#third-tab">Strikers</a></li>        </ul>   <div id="first-tab">     <h3>Liverpool Defenders</h3>     <p> The best defenders that played for Liverpool are Jamie Carragher, Sami Hyypia , Ron Yeats and Alan Hansen.</p>   </div>   <div id="second-tab">     <h3>Liverpool Midfielders</h3>     <p> The best midfielders that played for Liverpool are Kenny Dalglish, John Barnes,Ian Callaghan,Steven Gerrard and Jan Molby.        </p>   </div>   <div id="third-tab">     <h3>Liverpool Strikers</h3>     <p>The best strikers that played for Liverpool are Ian Rush,Roger Hunt,Robbie Fowler and Fernando Torres.<br/>      </p>   </div> </div></section>            <footer>        <p>All Rights Reserved</p>      </footer>     </body>  </html>  This is very simple HTML markup. I have styled this markup using CSS.The contents of the style.css file follow* {    margin: 0;    padding: 0;}header{font-family:Tahoma;font-size:1.3em;color:#505050;text-align:center;}#tabs {    font-size: 0.9em;    margin: 20px 0;}#tabs ul {    float: left;    background: #777;    width: 260px;    padding-top: 24px;}#tabs li {    margin-left: 8px;    list-style: none;}* html #tabs li {    display: inline;}#tabs li, #tabs li a {    float: left;}#tabs ul li.active {    border-top:2px red solid;    background: #15ADFF;}#tabs ul li.active a {    color: #333333;}#tabs div {    background: #15ADFF;    clear: both;    padding: 15px;    min-height: 200px;}#tabs div h3 {    margin-bottom: 12px;}#tabs div p {    line-height: 26px;}#tabs ul li a {    text-decoration: none;    padding: 8px;    color:#0b2f20;    font-weight: bold;}footer{background-color:#999;width:100%;text-align:center;font-size:1.1em;color:#002233;}There are some CSS rules that style the various elements in the HTML 5 file. These are straight-forward rules. The JQuery code lives inside the tabs.js file $(document).ready(function(){$('#tabs div').hide();$('#tabs div:first').show();$('#tabs ul li:first').addClass('active'); $('#tabs ul li a').click(function(){$('#tabs ul li').removeClass('active');$(this).parent().addClass('active');var currentTab = $(this).attr('href');$('#tabs div').hide();$(currentTab).show();return false;});}); I am using some of the most commonly used JQuery functions like hide , show, addclass , removeClass I hide and show the tabs when the tab becomes the active tab. When I view my page I get the following result Hope it helps!!!!!

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