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  • LINQ to SQL: To Attach or Not To Attach

    - by bradhe
    So I'm have a really hard time figuring out when I should be attaching to an object and when I shouldn't be attaching to an object. First thing's first, here is a small diagram of my (very simplified) object model. Edit: Okay, apparently I'm not allowed to post images...here you go: http://i.imgur.com/2ROFI.png In my DAL I create a new DataContext every time I do a data-related operation. Say, for instance, I want to save a new user. In my business layer I create a new user. var user = new User(); user.FirstName = "Bob"; user.LastName = "Smith"; user.Username = "bob.smith"; user.Password = StringUtilities.EncodePassword("MyPassword123"); user.Organization = someOrganization; // Assume that someOrganization was loaded and it's data context has been garbage collected. Now I want to go save this user. var userRepository = new RepositoryFactory.GetRepository<UserRepository>(); userRepository.Save(user); Neato! Here is my save logic: public void Save(User user) { if (!DataContext.Users.Contains(user)) { user.Id = Guid.NewGuid(); user.CreatedDate = DateTime.Now; user.Disabled = false; //DataContext.Organizations.Attach(user.Organization); DataContext.Users.InsertOnSubmit(user); } else { DataContext.Users.Attach(user); } DataContext.SubmitChanges(); // Finished here as well. user.Detach(); } So, here we are. You'll notice that I comment out the bit where the DataContext attachs to the organization. If I attach to the organization I get the following exception: NotSupportedException: An attempt has been made to Attach or Add an entity that is not new, perhaps having been loaded from another DataContext. This is not supported. Hmm, that doesn't work. Let me try it without attaching (i.e. comment out that line about attaching to the organization). DuplicateKeyException: Cannot add an entity with a key that is already in use. WHAAAAT? I can only assume this is trying to insert a new organization which is obviously false. So, what's the deal guys? What should I do? What is the proper approach? It seems like L2S makes this quite a bit harder than it should be...

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  • How to call Named Query

    - by sandeep
    I wrote a named query in the entity class Voter NamedQuery(name = "Voter.findvoter", query = "SELECT count(*) FROM Voter v WHERE v.voterID = :voterID" and where v.password= : password), I want to call this named query and I also need to set voterID and password. Can you help me. Thank you

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  • Flex+JPA/Hibernate+BlazeDS+MySQL how to debug this monster?!

    - by Zenzen
    Ok so I'm making a "simple" web app using the technologies from the topic, recently I found http://www.adobe.com/devnet/flex/articles/flex_hibernate.html so I'm following it and I try to apply it to my app, the only difference being I'm working on a Mac and I'm using MAMP for the database (so no command line for me). The thing is I'm having some trouble with retrieving/connecting to the database. I have the remoting-config.xml, persistance.xml, a News.java class (my Entity), a NewsService.java class, a News.as class - all just like in the tutorial. I have of course this line in one of my .mxmls: <mx:RemoteObject id="loaderService" destination="newsService" result="handleLoadResult(event)" fault="handleFault(event)" showBusyCursor="true" /> And my remoting-config.xml looks like this (well part of it): <destination id="newsService"> <properties><source>com.gamelist.news.NewsService</source></properties> </destination> NewsService has a method: public List<News> getLatestNews() { EntityManagerFactory emf = Persistence.createEntityManagerFactory(PERSISTENCE_UNIT); EntityManager em = emf.createEntityManager(); Query findLatestQuery = em.createNamedQuery("news.findLatest"); List<News> news = findLatestQuery.getResultList(); return news; } And the named query is in the News class: @Entity @Table(name="GLT_NEWS") @NamedQueries({ @NamedQuery(name="news.findLatest", query="from GLT_NEWS order by new_date_added limit 5 ") }) The handledLoadResult looks like this: private function handleLoadResult(ev:ResultEvent):void { newsList = ev.result as ArrayCollection; newsRecords = newsList.length; } Where: [Bindable] private var newsList:ArrayCollection = new ArrayCollection(); But when I try to trigger: loaderService.getLatestNews(); nothing happens, newsList is empty. Few things I need to point out: 1) as I said I didn't install mysql manually, but I'm using MAMP (yes, the server's running), could this cause some trouble? 2) I already have a "gladm" database and I have a "GLT_NEWS" table with all the fields, is this bad? Basically the question is how am I suppose to debug this thing so I can find the mistake I'm making? I know that loadData() is executed (did a trace()), but I have no idea what happens with loaderService.getLatestNews()... @EDIT: ok so I see I'm getting an error in the "fault handler" which says "Error: Client.Error.MessageSend - Channel.Connect.Failed error NetConnection.Call.Failed: HTTP: Status 404: url: 'http://localhost:8080/WebContent/messagebroker/amf' - "

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  • please explain NHibernate HiLo

    - by Ben
    I'm struggling to get my head round how the HiLo generator works in NHibernate. I've read the explanation here which made things a little clearer. My understanding is that each SessionFactory retrieves the high value from the database. This improves performance because we have access to IDs without hitting the database. The explanation from the above link also states: For instance, supposing you have a "high" sequence with a current value of 35, and the "low" number is in the range 0-1023. Then the client can increment the sequence to 36 (for other clients to be able to generate keys while it's using 35) and know that keys 35/0, 35/1, 35/2, 35/3... 35/1023 are all available. How does this work in a web application as don't I only have one SessionFactory and therefore one hi value. Does this mean that in a disconnected application you can end up with duplicate (low) ids in your entity table? In my tests I used these settings: <id name="Id" unsaved-value="0"> <generator class="hilo"/> </id> I ran a test to save 100 objects. The IDs in my table went from 32768 - 32868. The next hi value was incremented to 2. Then I ran my test again and the Ids were in the range 65536 - 65636. First off, why start at 32768 and not 1, and secondly why the jump from 32868 to 65536? Now I know that my surrogate keys shouldn't have any meaning but we do use them in our application. Why can't I just have them increment nicely like a SQL Server identity field would. Finally can someone give me an explanation of how the max_lo parameter works? Is this the maximum number of low values (entity ids in my head) that can be created against the high value? This is one topic in NHibernate that I have struggled to find documentation for. I read the entire NHibernate in action book and it still doesn't go into how this works in any detail. Thanks Ben

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  • Castle ActiveRecord optimistic locking on properties

    - by Daniel T.
    Can Castle ActiveRecord do optimistic locking on properties? I found optimistic locking for the entire class, but not for an individual property. In my case, I need to make it so that adding/removing elements in a collection does not update the version number of the entity (so for example, adding a Product to a Store without changing any of Store's properties will not increment the version number).

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  • XML based WCF service layer

    - by blockoutall
    Hi Guys, we are in the process of desigining a solution as : PL(Sliver Light) | SL(??wcf??) | BL(WWF) | DL(Entity Framework) during this process our thought is decouple the PL & SL ,so we thought of going with the XML based services Can u guys suggest what would be the better solution for desiging the SL(using WCF)which can do the transctions done through XML using WCF

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  • Connect MySQL database from Android

    - by Mistry Hardik
    hello people! well this is the code snippet i use to access the getUser.php to retrive user details from a MySQL database in my application: String result = ""; //the year data to send ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); nameValuePairs.add(new BasicNameValuePair("uid","demo")); //http post try{ HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://192.xxx.xx.xxx/getUser.php"); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); HttpResponse response = httpclient.execute(httppost); HttpEntity entity = response.getEntity(); InputStream is = entity.getContent(); }catch(Exception e){ Log.e("log_tag", "Error in http connection "+e.toString()); } //convert response to string try{ InputStream is = null; BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8); StringBuilder sb = new StringBuilder(); String line = null; while ((line = reader.readLine()) != null) { sb.append(line + "\n"); } is.close(); result=sb.toString(); }catch(Exception e){ Log.e("log_tag", "Error converting result "+e.toString()); } //parse json data try{ JSONArray jArray = new JSONArray(result); for(int i=0;i<jArray.length();i++){ JSONObject json_data = jArray.getJSONObject(i); Log.i("log_tag","id: "+json_data.getInt("id")+ ", name: "+json_data.getString("fname")+ ", sex: "+json_data.getInt("sex")+ ", birthyear: "+json_data.getInt("dob") ); } } catch(JSONException e){ Log.e("log_tag", "Error parsing data "+e.toString()); } } This snippet is taken from http://helloandroid.com Everything is configured fine: the MySQL Db, IIS with FASTCGi, PHP tools and drivers. even the script below when called from browser with url: http://192.xxx.xx.x.xxx/getUser.php?uid=demo works fine, But returns error in android with java.lang.NullPointerException and org.json.JSONEXCEPTION: End of input at character 0 <?php mysql_connect("myhost","username","pwd"); mysql_select_db("mydb"); $q=mysql_query("SELECT * FROM userinfo WHERE uid ='".$_REQUEST['uid']."'"); while($e=mysql_fetch_assoc($q)) $output[]=$e; print(json_encode($output)); mysql_close(); ?> Can anybody help in this section? Regards, Mistry Hardik

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  • Declaring object type as NSManagedObject or class name

    - by Don Fulano
    In Core Data, if I have a Person entity is there any difference between: NSManagedObject *aPerson = [NSEntityDescription insertNewObjectForEntityForName:@"Person" inManagedObjectContext:[self managedObjectContext]]; or Person *aPerson = [NSEntityDescription insertNewObjectForEntityForName:@"Person" inManagedObjectContext:[self managedObjectContext]]; Should aPerson be of type Person or NSManagedObject? Is there a difference?

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  • Setting a custom XOM EntityResolver

    - by Stefan Kendall
    I need to not validate against a doctype, so I'd like to set a custom EntityResolver that accepts everything. I'm getting data back from tagsoup, so I know my data is well-formed and correct. Furthermore, I need to rapidly hit a number of documents, so when I do this with the default EntityResolver, I get 503 from w3.org. How, then, can I use a XOM builder with a custom entity resolver?

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  • Enterprise ASP.NET MVC application architecture

    - by Ben
    I am still trying to figure out the right architecture for a complex ASP.NET MVC web application. I looked in a lot of example code and everywhere it's done differently. I would really appreciate your thoughts on this. Another Question: Would you use Linq to SQL or the Entity Framework? Thanks, -Ben

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  • How to add action related to a business object in Metawidget?

    - by Gulcan
    I use Netbeans 6.8 and try to obtain user interface by using metawidget and JPA. I cannot say @Action public void save( ActionEvent event ) { mSearchMetawidget.save(); } This annotation gives "incompatible types" error when I add following import. import org.metawidget.inspector.impl.actionstyle.Action; What to do? How can I add an action related to my User entity. I want to do "register" action. Thanks in advance

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  • Alternative of JPA

    - by Peter
    I want to use JPA for my persistence layer of my Java Desktop Application but I have the similar problem as describe at http://stackoverflow.com/questions/2562746/jpa-entity-design-problem/2563009#2563009 I didn't find a solution to the above kind of problem that's why I want to go with any other alternative of JPA. It would be better if I get the solution of the above problem.

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  • NOt able to parse "&"

    - by shishir.bobby
    HI all, my xml consist of words in few different language,latin words etc. i am able to parse these latin characters n all except the fact,that i am not able parse only "&" This is wat i am getting @gdb Entity: line 223: parser error : xmlParseEntityRef: no name Ull always be mine 4 now & 4ever.Ull always be mine 4 u r my treasure.Ull Any hint to overcome this regards shishir

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  • Eclipse Debug Mode disrupting SQL Server 2005 Stored Procedure access

    - by Sathish
    We have a strange problem in our team. When a developer is using Eclipse in Debug mode, SQL Server 2005 blocks other developers from accessing a stored procedure. Debug session typically involves opening Hibernate session to persist an entity which could be accessing a stored procedure used for Primary key generation. Debugging is done in business logic code and rarely in JDBC stored procedure call. Is there any way to configure SQL server or the stored procedure so that other developers are not blocked?

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  • Recursive Query Help

    - by Josh
    I have two tables in my database schema that represent an entity having a many-to-many relationship with itself. Role --------------------- +RoleID +Name RoleHasChildRole --------------------- +ParentRoleID +ChildRoleID Essentially, I need to to be able to write a query such that: Given a set of roles, return the unique set of all related roles recursively. This is an MSSQL 2008 Database.

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  • similarity match

    - by csetzkorn
    Many search engine have the 'did you mean' functionality. Is there a simple way to use (N)Hibernate (e.g. ICriteria) to find an entity (e.g. keyword) based on similarity. Please note that I do not mean Expression.Like or something like this. I hope this question makes sense. Thanks. Christian

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  • Multiple foreign keys to same table using Elixir

    - by Suvir
    Hello, I am new to ORMs in general. I have a table (lets call it Entity) with columns -- ID expression type ( can be 'long_word', 'short_word' or 'sentence' ) Often, the first two types occur in a 'sentence', so, I want to maintain another table which maps 'Sentences' to 'long_word' or 'short_word' using the 'ID' field. All i need is another table with 2 'Integer fields' referring to 'ID' as a foreign key. But, how do i do this in Elixir? Thanks a lot...

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  • What good alternatives are there to Google Charts?

    - by Rhubarb
    I have been experimenting with Google charts. Are there any alternatives that are reasonably as expressive but can be installed locally on your own web server? I don't like the idea of relying on an outside entity for a feature to work. Even if it is for cost, it would be preferable. Any suggestions?

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  • EntityManagerFactory error on Websphere

    - by neverland
    I have a very weird problem. Have an application using Hibernate and spring.I have an entitymanger defined which uses a JNDI lookup .It looks something like this <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="persistenceUnitName" value="ConfigAPPPersist" /> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="showSql" value="true" /> <property name="generateDdl" value="false" /> <property name="databasePlatform" value="org.hibernate.dialect.Oracle9Dialect" /> </bean> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.WebSphereDataSourceAdapter"> <property name="targetDataSource"> <bean class="org.springframework.jndi.JndiObjectFactoryBean"> <property name="jndiName" value="jdbc/pmp" /> </bean> </property> </bean> This application runs fine in DEV. But when we move to higher envs the team that deploys this application does it successfully initially but after a few restarts of the application the entitymanager starts giving this problem Caused by: javax.persistence.PersistenceException: [PersistenceUnit: ConfigAPPPersist] Unable to build EntityManagerFactory at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:677) at org.hibernate.ejb.HibernatePersistence.createContainerEntityManagerFactory(HibernatePersistence.java:132) at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:224) at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:291) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1368) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1334) ... 32 more Caused by: org.hibernate.MappingException: **property mapping has wrong number of columns**: com.***.***.jpa.marketing.entity.MarketBrands.$performasure_j2eeInfo type: object Now you would say this is pretty obvious the entity MarketBrands is incorrect. But its not it maps to the table just fine. And the same code works on DEV. Also the jndi cannot be incorrect since it deploys and works fine initially but throws uo this error after a restart. This is weird and not very logical. But if someone has faced this or has any idea on what might be causing this Please!! help The persistence.xml for the persitence unit has very little <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="ConfigAPPPersist"> <!-- commented code --> </persistence-unit> </persistence>

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  • How to use second level cache for lazy loaded collections in Hibernate?

    - by Chandru
    Let's say I have two entities, Employee and Skill. Every employee has a set of skills. Now when I load the skills lazily through the Employee instances the cache is not used for skills in different instances of Employee. Let's Consider the following data set. Employee - 1 : Java, PHP Employee - 2 : Java, PHP When I load Employee - 2 after Employee - 1, I do not want hibernate to hit the database to get the skills and instead use the Skill instances already available in cache. Is this possible? If so how? Hibernate Configuration <session-factory> <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property> <property name="hibernate.connection.password">pass</property> <property name="hibernate.connection.url">jdbc:mysql://localhost/cache</property> <property name="hibernate.connection.username">root</property> <property name="hibernate.dialect">org.hibernate.dialect.MySQLInnoDBDialect</property> <property name="hibernate.cache.use_second_level_cache">true</property> <property name="hibernate.cache.use_query_cache">true</property> <property name="hibernate.cache.provider_class">net.sf.ehcache.hibernate.EhCacheProvider</property> <property name="hibernate.hbm2ddl.auto">update</property> <property name="hibernate.show_sql">true</property> <mapping class="org.cache.models.Employee" /> <mapping class="org.cache.models.Skill" /> </session-factory> The Entities with imports, getters and setters Removed @Entity @Table(name = "employee") @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public class Employee { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; public Employee() { } @ManyToMany @JoinTable(name = "employee_skills", joinColumns = @JoinColumn(name = "employee_id"), inverseJoinColumns = @JoinColumn(name = "skill_id")) @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) private List<Skill> skills; } @Entity @Table(name = "skill") @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public class Skill { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; } SQL for Loading the Second Employee and his Skills Hibernate: select employee0_.id as id0_0_, employee0_.name as name0_0_ from employee employee0_ where employee0_.id=? Hibernate: select skills0_.employee_id as employee1_1_, skills0_.skill_id as skill2_1_, skill1_.id as id1_0_, skill1_.name as name1_0_ from employee_skills skills0_ left outer join skill skill1_ on skills0_.skill_id=skill1_.id where skills0_.employee_id=? In that I specifically want to avoid the second query as the first one is unavoidable anyway.

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  • ASP.NET 2.0 - scaffolding a database table for webforms

    - by Francis Huang
    Can you recommend a tool that can analyze a SQL database table, read the table columns, and populate an .aspx page with appropriate controls (i.e. textboxes with matching labels)? See this demo of ComponentOne InputPanel for WinForms for the functionality desired. Are there any built-in tools for ASP.NET 2.0 WebForms that can help build a scaffold page for any given database table or entity? Are there any free components out there to help achieve this goal?

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