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• Python unicode search not giving correct answer

  - by user1318912

  I am trying to search hindi words contained one line per file in file-1 and find them in lines in file-2. I have to print the line numbers with the number of words found. This is the code: import codecs hypernyms = codecs.open("hindi_hypernym.txt", "r", "utf-8").readlines() words = codecs.open("hypernyms_en2hi.txt", "r", "utf-8").readlines() count_arr = [] for counter, line in enumerate(hypernyms): count_arr.append(0) for word in words: if line.find(word) >=0: count_arr[counter] +=1 for iterator, count in enumerate(count_arr): if count>0: print iterator, ' ', count This is finding some words, but ignoring some others The input files are: File-1: ???? ??????? File-2: ???????, ????-???? ?????-???, ?????-???, ?????_???, ?????_??? ????_????, ????-????, ???????_???? ????-???? This gives output: 0 1 3 1 Clearly, it is ignoring ??????? and searching for ???? only. I have tried with other inputs as well. It only searches for one word. Any idea how to correct this?

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• How do I execute SQL_CALC_FOUND_ROWS in python MySQLDB

  - by alex

  cursor.execute("SELECT SQL_CALC_FOUND_ROWS user_id FROM...limit 5") rows = cursor.fetchall() ... total_rows = cursor.execute("SELECT FOUND_ROWS()") #this doesn't work for some reason. Edit: I tried SELECT FOUND_ROWS() FROM my_table...and the numbers are funky.

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• python logparse search specific text

  - by krisdigitx

  hi, I am using this function in my code to return the strings i want from reading the log file, I want to grep the "exim" process and return the results, but running the code gives no error, but the output is limited to three lines, how can i just get the output only related to exim process.. #output: {'date': '13', 'process': 'syslogd', 'time': '06:27:33', 'month': 'May'} {'date': '13', 'process': 'exim[23168]:', 'time': '06:27:33', 'month': 'May'} {'May': ['syslogd']} #function: def generate_log_report(logfile): report_dict = {} for line in logfile: line_dict = dictify_logline(line) print line_dict try: month = line_dict['month'] date = line_dict['date'] time = line_dict['time'] #process = line_dict['process'] if "exim" in line_dict['process']: process = line_dict['process'] break else: process = line_dict['process'] except ValueError: continue report_dict.setdefault(month, []).append(process) return report_dict

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• Replacing python docstrings

  - by tomaz

  I have written a epytext to reST markup converter, and now I want to convert all the docstrings in my entire library from epytext to reST format. Is there a smart way to read the all the docstrings in a module and write back the replacements? ps: ast module perhaps?

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• strip spaces in python.

  - by Richard

  ok I know that this should be simple... anyways say: line = "$W5M5A,100527,142500,730301c44892fd1c,2,686.5 4,333.96,0,0,28.6,123,75,-0.4,1.4*49" I want to strip out the spaces. I thought you would just do this line = line.strip() but now line is still '$W5M5A,100527,142500,730301c44892fd1c,2,686.5 4,333.96,0,0,28.6,123,75,-0.4,1.4*49' instead of '$W5M5A,100527,142500,730301c44892fd1c,2,686.54,333.96,0,0,28.6,123,75,-0.4,1.4*49' any thoughts?

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• Check if command had some trouble in Python?

  - by Shady

  I have this command h = urllib.urlopen("http://google.com/") How can I check if it retrieves me some error, internet down or something I don't expect? For example, something like if error print 'ERROR' Thank you

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• Dynamic variable name in python

  - by PhilGo20

  I'd like to call a query with a field name filter that I wont know before run time... Not sure how to construct the variable name ...Or maybe I am tired. field_name = funct() locations = Locations.objects.filter(field_name__lte=arg1) where if funct() returns name would equal to locations = Locations.objects.filter(name__lte=arg1) Not sure how to do that ...

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• Dynamic Operator Overloading on dict classes in Python

  - by Ishpeck

  I have a class that dynamically overloads basic arithmetic operators like so... import operator class IshyNum: def __init__(self, n): self.num=n self.buildArith() def arithmetic(self, other, o): return o(self.num, other) def buildArith(self): map(lambda o: setattr(self, "__%s__"%o,lambda f: self.arithmetic(f, getattr(operator, o))), ["add", "sub", "mul", "div"]) if __name__=="__main__": number=IshyNum(5) print number+5 print number/2 print number*3 print number-3 But if I change the class to inherit from the dictionary (class IshyNum(dict):) it doesn't work. I need to explicitly def __add__(self, other) or whatever in order for this to work. Why?

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• Python and classes

  - by Artyom

  Hello, i have 2 classes. How i call first.TQ in Second ? Without creating object First in Second. class First: def __init__(self): self.str = "" def TQ(self): pass def main(self): T = Second(self.str) # Called here class Second(): def __init__(self): list = {u"RANDINT":first.TQ} # List of funcs maybe called in first ..... ..... return data

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• Python string formatting too slow

  - by wich

  I use the following code to log a map, it is fast when it only contains zeroes, but as soon as there is actual data in the map it becomes unbearably slow... Is there any way to do this faster? log_file = open('testfile', 'w') for i, x in ((i, start + i * interval) for i in range(length)): log_file.write('%-5d %8.3f %13g %13g %13g %13g %13g %13g\n' % (i, x, map[0][i], map[1][i], map[2][i], map[3][i], map[4][i], map[5][i]))

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• Find last match with python regular expression

  - by SDD

  I wanto to match the last occurence of a simple pattern in a string, e.g. list = re.findall(r"\w+ AAAA \w+", "foo bar AAAA foo2 AAAA bar2) print "last match: ", list[len(list)-1] however, if the string is very long, a huge list of matches is generated. Is there a more direct way to match the second occurence of "AAAA" or should I use this workaround?

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• PYTHON: Look for match in a nested list

  - by elfuego1

  Hello everybody, I have two nested lists of different sizes: A = [[1, 7, 3, 5], [5, 5, 14, 10]] B = [[1, 17, 3, 5], [1487, 34, 14, 74], [1487, 34, 3, 87], [141, 25, 14, 10]] I'd like to gather all nested lists from list B if A[2:4] == B[2:4] and put it into list L: L = [[1, 17, 3, 5], [141, 25, 14, 10]] Would you help me with this?

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• Python: Unpack arbitary length bits for database storage

  - by sberry2A

  I have a binary data format consisting of 18,000+ packed int64s, ints, shorts, bytes and chars. The data is packed to minimize it's size, so they don't always use byte sized chunks. For example, a number whose min and max value are 31, 32 respectively might be stored with a single bit where the actual value is bitvalue + min, so 0 is 31 and 1 is 32. I am looking for the most efficient way to unpack all of these for subsequent processing and database storage. Right now I am able to read any value by using either struct.unpack, or BitBuffer. I use struct.unpack for any data that starts on a bit where (bit-offset % 8 == 0 and data-length % 8 == 0) and I use BitBuffer for anything else. I know the offset and size of every packed piece of data, so what is going to be the fasted way to completely unpack them? Many thanks.

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• python httplib httpexception error codes

  - by Xavier

  Does httplib.HTTPException have error codes? If so how do I get at them from the exception instance? Any help is appreciated.

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• Rectangle Rotation in Python/Pygame

  - by mramazingguy

  Hey I'm trying to rotate a rectangle around its center and when I try to rotate the rectangle, it moves up and to the left at the same time. Does anyone have any ideas on how to fix this? def rotatePoint(self, angle, point, origin): sinT = sin(radians(angle)) cosT = cos(radians(angle)) return (origin[0] + (cosT * (point[0] - origin[0]) - sinT * (point[1] - origin[1])), origin[1] + (sinT * (point[0] - origin[0]) + cosT * (point[1] - origin[1]))) def rotateRect(self, degrees): center = (self.collideRect.centerx, self.collideRect.centery) self.collideRect.topleft = self.rotatePoint(degrees, self.collideRect.topleft, center) self.collideRect.topright = self.rotatePoint(degrees, self.collideRect.topright, center) self.collideRect.bottomleft = self.rotatePoint(degrees, self.collideRect.bottomleft, center) self.collideRect.bottomright = self.rotatePoint(degrees, self.collideRect.bottomright, center)

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• Regular expressions in python unicode

  - by Remy

  I need to remove all the html tags from a given webpage data. I tried this using regular expressions: import urllib2 import re page = urllib2.urlopen("http://www.frugalrules.com") from bs4 import BeautifulSoup, NavigableString, Comment soup = BeautifulSoup(page) link = soup.find('link', type='application/rss+xml') print link['href'] rss = urllib2.urlopen(link['href']).read() souprss = BeautifulSoup(rss) description_tag = souprss.find_all('description') content_tag = souprss.find_all('content:encoded') print re.sub('<[^>]*>', '', content_tag) But the syntax of the re.sub is: re.sub(pattern, repl, string, count=0) So, I modified the code as (instead of the print statement above): for row in content_tag: print re.sub(ur"<[^>]*>",'',row,re.UNICODE But it gives the following error: Traceback (most recent call last): File "C:\beautifulsoup4-4.3.2\collocation.py", line 20, in <module> print re.sub(ur"<[^>]*>",'',row,re.UNICODE) File "C:\Python27\lib\re.py", line 151, in sub return _compile(pattern, flags).sub(repl, string, count) TypeError: expected string or buffer What am I doing wrong?

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• Python: Taking an array and break it into subarrays based on some criteria

  - by randombits

  I have an array of files. I'd like to be able to break that array down into one array with multiple subarrays, each subarray contains files that were created on the same day. So right now if the array contains files from March 1 - March 31, I'd like to have an array with 31 subarrays (assuming there is at least 1 file for each day). In the long run, I'm trying to find the file from each day with the latest creation/modification time. If there is a way to bundle that into the iterations that are required above to save some CPU cycles, that would be even more ideal. Then I'd have one flat array with 31 files, one for each day, for the latest file created on each individual day.

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• Custom keys for Google App Engine models (Python)

  - by Cameron

  First off, I'm relatively new to Google App Engine, so I'm probably doing something silly. Say I've got a model Foo: class Foo(db.Model): name = db.StringProperty() I want to use name as a unique key for every Foo object. How is this done? When I want to get a specific Foo object, I currently query the datastore for all Foo objects with the target unique name, but queries are slow (plus it's a pain to ensure that name is unique when each new Foo is created). There's got to be a better way to do this! Thanks.

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• Get the last '/' or '\\' character in Python

  - by wowus

  If I have a string that looks like either ./A/B/c.d OR .\A\B\c.d How do I get just the "./A/B/" part? The direction of the slashes can be the same as they are passed. This problem kinda boils down to: How do I get the last of a specific character in a string? Basically, I want the path of a file without the file part of it.

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• python - from matrix to dictionary in single line

  - by Sanich

  matrix is a list of lists. I've to return a dictionary of the form {i:(l1[i],l2[i],...,lm[i])} Where the key i is matched with a tuple the i'th elements from each list. Say matrix=[[1,2,3,4],[9,8,7,6],[4,8,2,6]] so the line: >>> dict([(i,tuple(matrix[k][i] for k in xrange(len(matrix)))) for i in xrange(len(matrix[0]))]) does the job pretty well and outputs: {0: (1, 9, 4), 1: (2, 8, 8), 2: (3, 7, 2), 3: (4, 6, 6)} but fails if the matrix is empty: matrix=[]. The output should be: {} How can i deal with this?

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• (Python) Converting a dictionary to a list?

  - by Daria Egelhoff

  So I have this dictionary: ScoreDict = {"Blue": {'R1': 89, 'R2': 80}, "Brown": {'R1': 61, 'R2': 77}, "Purple": {'R1': 60, 'R2': 98}, "Green": {'R1': 74, 'R2': 91}, "Red": {'R1': 87, 'Lon': 74}} Is there any way how I can convert this dictionary into a list like this: ScoreList = [['Blue', 89, 80], ['Brown', 61, 77], ['Purple', 60, 98], ['Green', 74, 91], ['Red', 87, 74]] I'm not too familiar with dictionaries, so I really need some help here. Thanks in advance!

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• facing problem when trying to send an email using python

  - by vishnu

  i wrote the code like this import smtplib server=smtplib.SMTP('localhost') then it raising an error like error: [Errno 10061] No connection could be made because the target machine actively refused it i am new to SMTP can you tell what exactly the problem is

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• Python - Compress Ascii String

  - by n0idea

  I'm looking for a way to compress an ascii-based string, any help? I need also need to decompress it. I tried zlib but with no help. What can I do to compress the string into lesser length? code: def compress(request): if request.POST: data = request.POST.get('input') if is_ascii(data): result = zlib.compress(data) return render_to_response('index.html', {'result': result, 'input':data}, context_instance = RequestContext(request)) else: result = "Error, the string is not ascii-based" return render_to_response('index.html', {'result':result}, context_instance = RequestContext(request)) else: return render_to_response('index.html', {}, context_instance = RequestContext(request))

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• Using __str__ representation for printing objects in containers in Python

  - by BobDobbs

  I've noticed that when an instance with an overloaded str method is passed to the print() function as an argument, it prints as intended. However, when passing a container that contains one of those instances to print(), it uses the repr method instead. That is to say, print(x) displays the correct string representation of x, and print(x, y) works correctly, but print([x]) or print((x, y)) prints the repr representation instead. First off, why does this happen? Secondly, is there a way to correct that behavior of print() in this circumstance?

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• strip tags python

  - by user283405

  i want the following functionality. input : this is test bold text normal text expected output: this is test normal text the tags can be changed.

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