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  • Supply some basic auth credentials to a WebView?

    - by user246114
    Hi, I have a WebView. I'd like to show some page from my server, but I require some basic authentication. Is there a way I can specify basic auth credentials when calling WebView.loadData() somehow? I can do this on iphone with the equivalent webview class, thinking maybe same is possible with android? Thanks

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  • basic modal dialog hiding problem

    - by senzacionale
    I am using basic modal dialog: http://www.ericmmartin.com/projects/simplemodal-demos/ $(document).ready(function() { $("#bodyTxt .basic").click(function() { var text = $(this).attr("title"); $("#basicModalContent").html(text).modal(); return false; }); }); but when i click on X code is now visible in page. How can after i close model dialog delete html code and add #basicModalContent display to none?

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  • Basic multicast network performance problems

    - by davedavedave
    I've been using mpong from 29west's mtools package to get some basic idea of multicast latency across various Cisco switches: 1Gb 2960G, 10Gb 4900M and 10Gb Nexus N5548P. The 1Gb is just for comparison. I have the following results for ~400 runs of mpong on each switch (sending 65536 "ping"-like messages to a receiver which then sends back -- all over multicast). Numbers are latencies measured in microseconds. Switch Average StdDev Min Max 2960 (1Gb) 109.68463 0.092816 109.4328 109.9464 4900M (10Gb) 705.52359 1.607976 703.7693 722.1514 NX 5548(10Gb) 58.563774 0.328242 57.77603 59.32207 The result for 4900M is very surprising. I've tried unicast ping and I see the 4900 has ~10us higher latency than the N5548P (average 73us vs 64us). Iperf (with no attempt to tune it) shows both 10Gb switches give me 9.4Gbps line speed. The two machines are connected to the same switch and we're not doing any multicast routing. OS is RHEL 6. 10Gb NICs are HP 10GbE PCI-E G2 Dual-port NICs (I believe they are rebranded Mellanox cards). The 4900 switch is used in a project with tight access control so I'm waiting for approval before I can access it and check the config. The other two I have full access to configure. I've looked at the Cisco document[2] detailing differences between NX-OS and IOS w.r.t multicast so I've got some ideas to try out but this isn't an area where I have much expertise. Does anyone have any idea what I should be looking at once I get access to the switch? [1] http://docwiki.cisco.com/wiki/Cisco_NX-OS/IOS_Multicast_Comparison

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  • Python coding with VLC player (quite a basic query I expect)

    - by Todd
    I'm fairly new to the whole coding realm so my knowledge is fairly limited, and I can't seem to find any basic tutorials on how to use scripts with VLC player. More specifically, the reason I'm asking here is because I stumbled across a post on this site about playing random clips from random videos on VLC player automatically. This is the forum post: Playback random section from multiple videos changing every 5 minutes My situation is similar to this lovely gentleman's was, though he clearly knows a lot more about coding than I do. In short, I'd like to copy this coding into a file of some sort and apply it to VLC player myself. Only I'm not sure what file type I'd have to save it as (I have Python by the way, and I tried saving it as a .py file but I didn't know if it was correct or where to go from there). Additionally, I'm not sure how to get VLC to "read" the script, so to speak - is there a specific location the file needs to be, and do I run the script from another program or through VLC? I'll reiterate that I'm relatively new to this, so if anybody would be so kind as to post a quick list of steps on how to save/place the file and use it with VLC player I really would appreciate it! P.S. I'm not computer illiterate, I'm fine with most programs and I'd understand if you just said things like "C:\Program Files (x86)\VideoLAN\VLC\plugins" or "in VLC, select Tools Plugins and extensions", I just wouldn't catch on to anything about adding a line of coding that does something without being told exactly what to write! Many thanks in advance! :) Todd

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  • Centos 6.2 Fresh 'Basic Server' install networking issues

    - by RWC
    I've had a /29 provisioned on a network port for a server and am trying to at least configure the machine so I can ssh into it. It's Centos 6.2 x64 with the Basic Server install. Currently not able to ping gateway or any address for that matter. For reference: Default Interface: em2 Network ID: 66.*.*.0/29 Gateway: 66.*.*.1 Broadcast: 66.*.*.7 Please see my following configs: /etc/sysconfig/network-scripts/ifcfg-em2 DEVICE=em2 NM_CONTROLLED=yes ONBOOT=yes HWADDR=Not Important TYPE=Ethernet BOOTPROTO=none IPADDR=66.*.*.2 PREFIX=29 DNS1=8.8.8.8 DNS2=8.8.4.4 DEFROUTE=yes IPV4_FAILURE_FATAL=yes IPV6INIT=no NAME="System em2" NETMASK=255.255.255.248 USERCTL=no $: route -n Destination // Gateway // Genmask // Flags // Metric // Ref // Use // Iface 66.*.*.0 0.0.0.0 255.255.255.248 U 0 0 0 em2 169.254.0.0 0.0.0.0 255.255.0.0 U 0 1003 0 em2 0.0.0.0 66.*.*.1 0.0.0.0 UG 0 0 0 em2 $: route Destination // Gateway // Genmask // Flags // Metric // Ref // Use // Iface 66.*.*.0 * 255.255.255.248 U 0 0 0 em2 link-local * 255.255.0.0 U 0 1003 0 em2 default 66.*.*.1 0.0.0.0 UG 0 0 0 em2 $: cat /etc/sysconfig/network NETWORKING=yes HOSTNAME=excalibur.domain.com GATEWAY=66.*.*.1 Keep in mind that I cannot even currently ping the gateway which is quite confusing for me. My /etc/hosts are configured correctly with the *.2 address. I'm not concerned with getting all of the addresses on the /29 up and running yet, just one so I can at least ssh in. Thanks! Edit: Adding in ifconfig. $: ifconfig em2 Link encap:Ethernet HWaddr XX:XX:XX:XX:XX:XX inet addr:66.*.*.2 Bcat:66.*.*.7 Mask:255.255.255.248 inet6 addr: UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:5536 errors:0 dropped:0 overruns:0 frame:0 TX packets:10 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:2599469 (2.4 MiB) TX bytes: 748 (748.0 b) Interrupt:48 Memory:dc000000-dc012800 lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:34 errors:0 etc etc

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  • Basic Apache setup is not seeing my site

    - by Jakobud
    Sorry that is a horrible thread subject, but I cannot think of a better more descriptive subject. We are running a Fedora 11 server that is currently hosting some CRM on it. I want to use a VirtualHost directive to add another site to the server. So I created this conf: /etc/httpd/conf.d/mysite.ourdomain.com.conf And here is the content: <VirtualHost *:80> ServerName mysite.ourdomain.com DocumentRoot /www/mysite ServerAdmin [email protected] ErrorLog /var/log/mysite.ourdomain.com-error.log CustomLog /var/log/mysite.ourdomain.com-access.log common </VirtualHost> I restarted apache, getting the following warning: [warn] NameVirtualHost *:80 has no VirtualHosts From what I read, this warning is not related and I can ignore it and my site should still be up and running, correct? (I'll troubleshoot this error later if so) Well I have our DNS server setup to point mysite.ourdomain.com to goto this server. I can ping it and it points to the correct LAN IP, etc.. Now when I try to access it in the browswer I get nothing. It just says Connecting... and never gets there. If I try mysite.ourdomain.com or the IP address, neither one doesn't get there. It's a very simple and basic apache setup so I'm not sure what I'm doing wrong... Like I said, the other thing that is running on this server is a crm and it's .conf looks something like this: Listen x.x.x.x:443 <VirtualHost x.x.x.x:443> ServerAdmin [email protected] ServerName crm.ourdomain.com ErrorLog /var/log/httpd/ourdomain/crm-error.log CustomLog /var/log/httpd/ourdomain/crm-access.log common DocumentRoot /www/ourdomain/crm <IfModule mod_dir.c> DirectoryIndex /index.php </IfModule> </VirtualHost> There is also some LDAP authentication stuff in that config but I left it out cause I assumed it wasn't necessary to post. Anyone have any clue where I should start or what settings I can post from httpd.conf that would help?

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  • IPSec for LAN traffic: Basic considerations?

    - by chris_l
    This is a follow-up to my Encrypting absolutely everything... question. Important: This is not about the more usual IPSec setup, where you want to encrypt traffic between two LANs. My basic goal is to encrypt all traffic within a small company's LAN. One solution could be IPSec. I have just started to learn about IPSec, and before I decide on using it and dive in more deeply, I'd like to get an overview of how this could look like. Is there good cross-platform support? It must work on Linux, MacOS X and Windows clients, Linux servers, and it shouldn't require expensive network hardware. Can I enable IPSec for an entire machine (so there can be no other traffic incoming/outgoing), or for a network interface, or is it determined by firewall settings for individual ports/...? Can I easily ban non-IPSec IP packets? And also "Mallory's evil" IPSec traffic that is signed by some key, but not ours? My ideal conception is to make it impossible to have any such IP traffic on the LAN. For LAN-internal traffic: I would choose "ESP with authentication (no AH)", AES-256, in "Transport mode". Is this a reasonable decision? For LAN-Internet traffic: How would it work with the internet gateway? Would I use "Tunnel mode" to create an IPSec tunnel from each machine to the gateway? Or could I also use "Transport mode" to the gateway? The reason I ask is, that the gateway would have to be able to decrypt packages coming from the LAN, so it will need the keys to do that. Is that possible, if the destination address isn't the gateway's address? Or would I have to use a proxy in this case? Is there anything else I should consider? I really just need a quick overview of these things, not very detailed instructions.

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  • Why isn't Apache Basic authentication working?

    - by Brad
    I just upgraded Apache from it's 2003 build, to a squeaky-clean, brand-new 2.4.1 build. All seems pretty good except for one glaring thing: In my httpd.conf file I have the following: <Directory /> AllowOverride none Options FollowSymLinks AuthType Basic AuthName "Enter Password" AuthUserFile /var/www/.htpasswd Require valid-user </Directory> This should allow only users in the specified auth file to access the server - just as it had under the older version of Apache. (Right?) However, it's not working. Requests are granted with no authentication provided. When I switch logging to LogLevel Debug, for the accesses, it says: [Sat Mar 24 21:32:00.585139 2012] [authz_core:debug] [pid 10733:tid 32771] mod_authz_core.c(783): [client 192.168.1.181:57677] AH01626: authorization result of Require all granted: granted [Sat Mar 24 21:32:00.585446 2012] [authz_core:debug] [pid 10733:tid 32771] mod_authz_core.c(783): [client 192.168.1.181:57677] AH01626: authorization result of <RequireAny>: granted I really don't know what this means - and I (to the best of my knowledge) don't have any "Require all granted" or "" statements in any of my files. Any ideas why this isn't working, or where to debug??

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  • Basic IPTables setup for OpenVPN/HTTP/HTTPS server

    - by Afronautica
    I'm trying to get a basic IPTables setup on my server which will allow HTTP/SSH access, as well as enable the use of the server as an OpenVPN tunnel. The following is my current rule setup - the problem is OpenVPN queries (port 1194) seemed to be getting dropped as a result of this ruleset. Pinging a website while logged into the VPN results in teh response: Request timeout for icmp_seq 1 92 bytes from 10.8.0.1: Destination Port Unreachable When I clear the IPTable rules pinging from the VPN works fine. Any ideas? iptables -t nat -A POSTROUTING -s 10.8.0.0/24 -o eth0 -j MASQUERADE iptables -A INPUT -p tcp --dport 1194 -j ACCEPT iptables -A FORWARD -p tcp --dport 1194 -j ACCEPT iptables -A INPUT -i lo -j ACCEPT iptables -A INPUT -i ! lo -d 127.0.0.0/8 -j REJECT iptables -A INPUT -m state --state ESTABLISHED,RELATED -j ACCEPT iptables -A OUTPUT -j ACCEPT iptables -A INPUT -p tcp --dport 80 -j ACCEPT iptables -A INPUT -p tcp --dport 443 -j ACCEPT iptables -A INPUT -p tcp -m state --state NEW --dport 22 -j ACCEPT iptables -A INPUT -p icmp -m icmp --icmp-type 8 -j ACCEPT iptables -A INPUT -j REJECT iptables -A FORWARD -j REJECT

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  • HP DL380 G3 2U For Basic Web Server in 2012

    - by ryandlf
    I have an opportunity to pick up a used HP DL380 G3 2U for $100. I'm looking for a basic entry level web server that I can host a small - medium size website on and more or less learn the ins and outs of running my own web server before I bite the bullet and spend a couple grand on a server. The specs are: Dual (2) Intel Xeon 2.4GHz 400MHz 512KB Cache 4GB PC2100 ECC Registered Memory 6 x 72GB 10K U320 SCSI Hard Drives Smart Array 5i RAID Controller Redundant Power Supplies DVD/Floppy, Dual Intel GB NIC's, USB Or would I be better off spending a couple hundred bucks on something like: this new HP Seems like the only major difference is SATA and a bit of storage, but I will likely be implementing a separate storage system of some sort anyways. I guess it also wouldn't hurt to mention that I plan on running a linux server distro, so would the hardware be likely to support linux with a system that is 4 generations old? I don't mind spending a couple hundred extra dollars if its a better solution, but as mentioned previously I am simple looking for a server to learn on and probably use for a year or so while I put together a small - medium size website.

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  • setting up a basic mod_proxy virtual host

    - by SevenProxies
    I'm trying to set up a basic virtual host to proxy all requests to test.local to a WEBrick server I have running on 127.0.0.1:8080 while keeping all requests to localhost going to my static files in /var/www. I'm running Ubuntu 10.04. I have libapache2-mod-proxy-html installed and I have the module enabled with a2enmod proxy. I also have my virtual host enabled. However, whenever I go to test.local I always get a cryptic 500 server error and all my logs are telling me is: [Thu Mar 03 01:43:10 2011] [warn] proxy: No protocol handler was valid for the URL /. If you are using a DSO version of mod_proxy, make sure the proxy submodules are included in the configuration using LoadModule. Here's my virtual host: <VirtualHost test.local:80> LoadModule proxy_module /usr/lib/apache2/modules/mod_proxy.so ServerAdmin webmaster@localhost ServerName test.local ProxyPreserveHost On # prevents this folder from being proxied ProxyPass /static ! DocumentRoot /var/www <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /var/www/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> <Proxy *> Order allow,deny Allow from all </Proxy> ProxyPass / http://localhost:8080/ ProxyPassReverse / http://localhost:8080/ ErrorLog /var/log/apache2/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /var/log/apache2/access.log combined and here's my settings for mod_proxy: <IfModule mod_proxy.c> #turning ProxyRequests on and allowing proxying from all may allow #spammers to use your proxy to send email. ProxyRequests Off <Proxy *> # default settings #AddDefaultCharset off #Order deny,allow #Deny from all ##Allow from .example.com AddDefaultCharset off Order allow,deny Allow from all </Proxy> # Enable/disable the handling of HTTP/1.1 "Via:" headers. # ("Full" adds the server version; "Block" removes all outgoing Via: headers) # Set to one of: Off | On | Full | Block ProxyVia On </IfModule> Does anybody know what I'm doing wrong? Thanks

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  • mercurial hgwebdir error with basicauth in apache2

    - by Dio
    Hello, I'm having kind of a strange error that I'm trying to track down. I was trying to setup mercurial on my home server this weekend. I seem to have it running up to the point where I'm trying to get repositories published correctly. I'm running Ubuntu 10.04 LTS Mercurial Distributed SCM (version 1.4.3) I followed the hgwebdir guide: http://mercurial.selenic.com/wiki/HgWebDirStepByStep and everything seems to work great, I can pull and push my local repositories. Then I tried to add basic auth changing ScriptAliasMatch ^/hg(.*) /var/hg/hgwebdir.cgi$1 <Directory "/var/hg"> Options ExecCGI FollowSymLinks AllowOverride None </Directory> to ScriptAliasMatch ^/hg(.*) /var/hg/hgwebdir.cgi$1 <Directory "/var/hg"> Options ExecCGI FollowSymLinks AllowOverride None AuthType Basic AuthName hgwebdir AuthUserFile /usr/local/etc/httpd/users Require valid-user </Directory> This works exactly as I'd expect it to when I navigate to the directory via my web browser, but when I hg push get a long section repeating of File "/usr/lib/python2.6/urllib2.py", line 369, in _call_chain result = func(*args) File "/usr/lib/python2.6/urllib2.py", line 855, in http_error_401 url, req, headers) File "/usr/lib/python2.6/urllib2.py", line 833, in http_error_auth_reqed return self.retry_http_basic_auth(host, req, realm) File "/usr/lib/python2.6/urllib2.py", line 843, in retry_http_basic_auth return self.parent.open(req, timeout=req.timeout) followed by File "/usr/lib/pymodules/python2.6/mercurial/keepalive.py", line 249, in do_open self._start_transaction(h, req) File "/usr/lib/pymodules/python2.6/mercurial/url.py", line 419, in _start_transaction return keepalive.HTTPHandler._start_transaction(self, h, req) File "/usr/lib/pymodules/python2.6/mercurial/keepalive.py", line 342, in _start_transaction h.endheaders() File "/usr/lib/python2.6/httplib.py", line 904, in endheaders self._send_output() File "/usr/lib/python2.6/httplib.py", line 776, in _send_output self.send(msg) File "/usr/lib/pymodules/python2.6/mercurial/url.py", line 247, in _sendfile connection.send(self, data) File "/usr/lib/pymodules/python2.6/mercurial/keepalive.py", line 519, in safesend self.connect() File "/usr/lib/pymodules/python2.6/mercurial/url.py", line 273, in connect keepalive.HTTPConnection.connect(self) RuntimeError: maximum recursion depth exceeded while calling a Python object I'm a bit at a loss on this one. I'm really not sure why adding the authorization seems to work fine via my web browser but throw these errors from hg. Any help would be greatly appreciated.

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  • Lock down Wiki access to password only but remain open to a subnet via .htaccess

    - by Treffynnon
    Basically we have a Wiki that has some sensitive information stored in it - not the best I know but my predecessor set it up. I want to be able to request password access from any one who is not on the local network subnet. Those on the local subnet should be able to proceed without entering a password. The following .htaccess does not seem to work any more as it is letting non-local access without requiring the password: AuthName "Our Wiki" AuthType Basic AuthUserFile /path/to/passwd/file AuthGroupFile /dev/null Require valid-user Allow from 192.168 Satisfy Any order deny,allow And I cannot work out why. The WikkaWiki it is supposed to be protecting was recently upgraded, which clobbered the .htaccess file so I restored the above from memory/googling. Maybe I am missing an important directive? The full .htaccess is as follows: AuthName "Our Wiki" AuthType Basic AuthUserFile /path/to/passwd/file AuthGroupFile /dev/null Require valid-user Allow from 192.168 Satisfy Any SetEnvIfNoCase Referer ".*($LIST_OF_ADULT_WORDS).*" BadReferrer order deny,allow deny from env=BadReferrer <IfModule mod_rewrite.c> # turn on rewrite engine RewriteEngine on RewriteBase / # if request is a directory, make sure it ends with a slash RewriteCond %{REQUEST_FILENAME} -d RewriteRule ^(.*/[^/]+)$ $1/ # if not rewritten before, AND requested file is wikka.php # turn request into a query for a default (unspecified) page RewriteCond %{QUERY_STRING} !wakka= RewriteCond %{REQUEST_FILENAME} wikka.php RewriteRule ^(.*)$ wikka.php?wakka= [QSA,L] # if not rewritten before, AND requested file is a page name # turn request into a query for that page name for wikka.php RewriteCond %{QUERY_STRING} !wakka= RewriteRule ^(.*)$ wikka.php?wakka=$1 [QSA,L] </IfModule>

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  • .htaccess issue on Apache Web Server in Ubuntu VM

    - by Neon Flash
    I just installed Apache Web Server on Ubuntu 11.04 in VMWare Workstation. I created a basic HTML page, named it index.html and placed it in /var/www directory (document root). I am able to access this web page from my Host OS (Windows 7), by pointing the browser to: http://192.168.2.2/index.html where, 192.168.2.2 is the IP Address of the Ubuntu VM. Next, to test various configurations of .htaccess files, I created a new directory in /var/www called, members. Inside this directory, I created and placed a .htaccess file with the following configuration: AuthUserFile /www/Neon/auth/.htpasswd AuthName "neon's home" AuthType Basic require valid-user IndexIgnore */* I created a directory path like /var/www/Neon/auth/ and then placed a .htpasswd file inside it. To place the username and hash inside the .htpasswd file: I created a username "neon" and calculated the DES hash of a password and placed it inside .htpasswd file in format: username:hash Now, when I try to access the web page: http://192.168.2.2/members/ It does not prompt me to enter the username and password with a popup box. Instead it just displays the index.html which is placed inside members directory. I would like to get this configuration working :)

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  • Make a Perl-style regex interpreter behave like a basic or extended regex interpreter

    - by Barry Brown
    I am writing a tool to help students learn regular expressions. I will probably be writing it in Java. The idea is this: the student types in a regular expression and the tool shows which parts of a text will get matched by the regex. Simple enough. But I want to support several different regex "flavors" such as: Basic regular expressions (think: grep) Extended regular expressions (think: egrep) A subset of Perl regular expressions, including the character classes \w, \s, etc. Sed-style regular expressions Java has the java.util.Regex class, but it supports only Perl-style regular expressions, which is a superset of the basic and extended REs. What I think I need is a way to take any given regular expression and escape the meta-characters that aren't part of a given flavor. Then I could give it to the Regex object and it would behave as if it was written for the selected RE interpreter. For example, given the following regex: ^\w+[0-9]{5}-(\d{4})?$ As a basic regular expression, it would be interpreted as: ^\\w\+[0-9]\{5\}-\(\\d\{4\}\)\?$ As an extended regular expression, it would be: ^\\w+[0-9]{5}-(\\d{4})?$ And as a Perl-style regex, it would be the same as the original expression. Is there a "regular expression for regular expressions" than I could run through a regex search-and-replace to quote the non-meta characters? What else could I do? Are there alternative Java classes I could use?

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  • HTTP Basic Authentication with HTTPService Objects in Adobe Flex/AIR

    - by Bob Somers
    I'm trying to request a HTTP resource that requires basic authorization headers from within an Adobe AIR application. I've tried manually adding the headers to the request, as well as using the setRemoteCredentials() method to set them, to no avail. Here's the code: <mx:Script> <![CDATA[ import mx.rpc.events.ResultEvent; import mx.rpc.events.FaultEvent; private function authAndSend(service:HTTPService):void { service.setRemoteCredentials('someusername', 'somepassword'); service.send(); } private function resultHandler(event:ResultEvent):void { apiResult.text = event.result.toString(); } private function resultFailed(event:FaultEvent):void { apiResult.text = event.fault.toString(); } ]]> </mx:Script> <mx:HTTPService id="apiService" url="https://mywebservice.com/someFileThatRequiresBasicAuth.xml" resultFormat="text" result="resultHandler(event)" fault="resultFailed(event)" /> <mx:Button id="apiButton" label="Test API Command" click="authAndSend(apiService)" /> <mx:TextArea id="apiResult" /> However, a standard basic auth dialog box still pops up prompting the user for their username and password. I have a feeling I'm not doing this the right way, but all the info I could find (Flex docs, blogs, Google, etc.) either hasn't worked or was too vague to help. Any black magic, oh Flex gurus? Thanks. EDIT: Changing setRemoteCredentials() to setCredentials() yields the following ActionScript error: [MessagingError message='Authentication not supported on DirectHTTPChannel (no proxy).'] EDIT: Problem solved, after some attention from Adobe. See the posts below for a full explanation. This code will work for HTTP Authentication headers of arbitrary length. import mx.utils.Base64Encoder; private function authAndSend(service:HTTPService):void { var encoder:Base64Encoder = new Base64Encoder(); encoder.insertNewLines = false; // see below for why you need to do this encoder.encode("someusername:somepassword"); service.headers = {Authorization:"Basic " + encoder.toString()}; service.send(); }

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  • Parsing basic math equations for children's educational software?

    - by Simucal
    Inspired by a recent TED talk, I want to write a small piece of educational software. The researcher created little miniature computers in the shape of blocks called "Siftables". [David Merril, inventor - with Siftables in the background.] There were many applications he used the blocks in but my favorite was when each block was a number or basic operation symbol. You could then re-arrange the blocks of numbers or operation symbols in a line, and it would display an answer on another siftable block. So, I've decided I wanted to implemented a software version of "Math Siftables" on a limited scale as my final project for a CS course I'm taking. What is the generally accepted way for parsing and interpreting a string of math expressions, and if they are valid, perform the operation? Is this a case where I should implement a full parser/lexer? I would imagine interpreting basic math expressions would be a semi-common problem in computer science so I'm looking for the right way to approach this. For example, if my Math Siftable blocks where arranged like: [1] [+] [2] This would be a valid sequence and I would perform the necessary operation to arrive at "3". However, if the child were to drag several operation blocks together such as: [2] [\] [\] [5] It would obviously be invalid. Ultimately, I want to be able to parse and interpret any number of chains of operations with the blocks that the user can drag together. Can anyone explain to me or point me to resources for parsing basic math expressions? I'd prefer as much of a language agnostic answer as possible.

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  • Rails 2.x provide meaningful error message with http basic authentication

    - by randombits
    I'm using basic http authentication in my rails app via the following code: class ApplicationController < ActionController::Base helper :all # include all helpers, all the time before_filter :authenticate private def authenticate authenticate_or_request_with_http_basic do |username, password| if username.nil? || password.nil? render :inline => %(xml.instruct! :xml, :version => "1.0", :encoding => "UTF-8" xml.errors do xml.error('Could not authenticate you.') end), :type => :builder, :status => 401 end end end end The problem is, if you do a curl http://127.0.0.1:3000/foo/1.xml without providing the -u username:password flag, you get a dead beat response like this: HTTP/1.1 401 Unauthorized Cache-Control: no-cache WWW-Authenticate: Basic realm="Foo" X-Runtime: 1 Content-Type: text/html; charset=utf-8 Content-Length: 27 Server: WEBrick/1.3.1 (Ruby/1.9.1/2010-01-10) Date: Thu, 03 Jun 2010 03:09:18 GMT Connection: Keep-Alive HTTP Basic: Access denied. Is it possible at all to render the inline XML I have above in the event a username and password is not provided by the user?

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  • Python urllib2 Basic Auth Problem

    - by Simon
    I'm having a problem sending basic AUTH over urllib2. I took a look at this article, and followed the example. My code: passman = urllib2.HTTPPasswordMgrWithDefaultRealm() passman.add_password(None, "api.foursquare.com", username, password) urllib2.install_opener(urllib2.build_opener(urllib2.HTTPBasicAuthHandler(passman))) req = urllib2.Request("http://api.foursquare.com/v1/user") f = urllib2.urlopen(req) data = f.read() I'm seeing the following on the Wire via wireshark: GET /v1/user HTTP/1.1 Host: api.foursquare.com Connection: close Accept-Encoding: gzip User-Agent: Python-urllib/2.5 You can see the Authorization is not sent, vs. when I send a request via curl: curl -u user:password http://api.foursquare.com/v1/user GET /v1/user HTTP/1.1 Authorization: Basic =SNIP= User-Agent: curl/7.19.4 (universal-apple-darwin10.0) libcurl/7.19.4 OpenSSL/0.9.8k zlib/1.2.3 Host: api.foursquare.com Accept: */* For some reason my code seems to not send the authentication - anyone see what I'm missing? thanks -simon

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  • Run Exchange Management Shell cmdlets from Visual Basic/C#/.NET app

    - by nowarninglabel
    Goal: Provide a web service using Visual Basic or C# or .NET that interacts with the Exchange Management Shell, sending it commands to run cmdlets, and return the results as XML. (Note that we could use any lanaguage to write the service, but since it is a Windows Box and we have Visual Studio 2008, it seemed like easiest solution would be just use it to create a VB/.NET web service. Indeed, it was quite easy to do so, just point and click.) Problem: How to run an Exchange Management Shell cmdlet from the web service, e.g, Get-DistributionGroupMember "Live Presidents" Seems that we should be able to create a PowerShell script that runs the cmdlet, and be able to call that from the command line, and thus just call it from within the program. Does this sound correct? If so how would I go about this? Thanks. Answer can be language agnostic, but Visual Basic would probably be best since that is what I loaded the test web service up in.

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  • What Are Basic Tools For A New Project?

    - by Morgan Cheng
    For a long time, I thought that to start a new project we only need 3 basic tools. 1) A Build System (e.g. Maven & CruiseControl) 2) A Version Control System (e.g. CVS & SVN & GIT) 3) A Bug Tracking System (e.g. Bugzilla) Yesterday, a senior guy told me that we need at least one thing more. That is KPI(Key Performance Index). Without KPI, it is impossible to measure whether the project is progressing well or not. KPI is kind of SOFT tool compared to Maven/SVN/Bugzilla. I believe since I missed SOFT tools, there must be some other kind of tools I missed. So, anybody get some ideas what other basic tools necessary for a new project?

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  • Opening vbp Visual Basic Project

    - by Roman
    I have got some old sources written in Visual Basic. There are *.bas, *.cls, *.frm and *.vbp files. As I understand, vbp is a project file. But I cannot open it with my Visual Studio 2008. What version of VS should I install to open *.vbp file? Google says it is Visual Studio 6, but I am not sure and I cannot find Visual Studio 6 for downloading. Is there any publicly available free edition of Visual Studio 6 with Visual Basic? Thanks.

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