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  • Transformation of records 1 column 3 row -> 1 row 3 column

    - by Nehal Rupani
    First look at below query SELECT count(id) as total_record, id, modeller, MONTHNAME(completed_date) as current_month, Quarter(completed_date) as current_quarter, Difficulty, YEAR(completed_date) as current_year FROM model WHERE modeller != '' AND completed_date BETWEEN '2010-04-01' AND '2010-05-31' AND Difficulty != '' Group by Difficulty, Month(completed_date) Order by Month(completed_date) ASC Results I am getting is Modeller Month Year Difficulty ------------------------------------- XYZ Jan 2010 23 XYZ Jan 2010 14 XYZ Jan 2010 15 ABC Feb 2010 5 ABC Feb 2010 14 ABC Feb 2010 6 I want result like Modeller Month Year Difficulty -------------------------------------- XYZ Jan 2010 23, 14, 15 ABC Feb 2010 5, 14, 6 My database is Mysql for application i am developing so any help would be greatly appericated.

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  • Doubt in stored procedure in asp.net

    - by Surya sasidhar
    hi, i am writing a sotreprocedure displaying month and year it is working but it is not coming in a order descending order can u help me my procedure like below... ALTER procedure [dbo].[audioblog_getarchivedates] as begin select DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) as ArchiveDate from audio_blog a group by DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) order by DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) desc end result will come like this March 2010 January 2010 February 2010 but it is not in a order (desc) can u help me

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  • Detect months with 31 days

    - by daddycardona
    Is there an analogous form of the following code: if(month == 4,6,9,11) { do something; } Or must it be: if(month == 4 || month == 6 etc...) { do something; } I am trying to write an if statement that checks if this month has more than 31 days.

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  • onDateSet does not get called from DatePickerDialog on tablet

    - by cit
    I am using a DatePickerDialog to prompt the user for a date. It works fine in the simulator and on my Samsung Galaxy Nexus, but onDateSet does not get called on my Samsung Galaxy Tab 2. I noticed, that the dialog is bigger and shows a calendar besides the normal spin view. Can that be the problem? Here is some code: import java.util.Calendar; import java.util.Date; import android.app.DatePickerDialog; import android.app.Dialog; import android.content.DialogInterface; import android.content.Intent; import android.os.Bundle; import android.support.v4.app.DialogFragment; import android.widget.DatePicker; import com.cbit.gtbetapp.R; import com.cbit.gtbetapp.gui.racedata.MeetingDataActivity; import com.cbit.gtbetapp.gui.racedata.MeetingListFragment; import com.cbit.gtbetapp.logic.Utility; public class DatePickerFragment extends DialogFragment implements DatePickerDialog.OnDateSetListener { protected Date date = null; @Override public Dialog onCreateDialog(Bundle savedInstanceState) { // Use the current date as the default date in the picker final Calendar c = Utility.getToday(); int year = c.get(Calendar.YEAR); int month = c.get(Calendar.MONTH); int day = c.get(Calendar.DAY_OF_MONTH); date = c.getTime(); // Create a new instance of DatePickerDialog and return it DatePickerDialog dialog = new DatePickerDialog(getActivity(), this, year, month, day) { @Override public void onDateChanged(DatePicker view, int year, int month, int day) { super.onDateChanged(view, year, month, day); setTitle(getString(R.string.date_picker_title)); } }; dialog.setTitle(getString(R.string.date_picker_title)); dialog.setButton(DatePickerDialog.BUTTON_POSITIVE, getString(android.R.string.ok), new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { dialog.cancel(); Intent intent = new Intent(getActivity(), MeetingDataActivity.class); intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP); intent.putExtra(MeetingListFragment.EXTRA_DATE, date.getTime()); startActivity(intent); } }); dialog.setButton(DatePickerDialog.BUTTON_NEGATIVE, getString(R.string.button_cancel), new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { dialog.cancel(); } }); return dialog; } public void onDateSet(DatePicker view, int year, int month, int day) { Calendar c = Calendar.getInstance(); c.clear(); c.set(Calendar.YEAR, year); c.set(Calendar.MONTH, month); c.set(Calendar.DAY_OF_MONTH, day); date = c.getTime(); } } What could cause this? A bug in the tablet? Am I missing something? Can anyone think of a workaround? Thanks a lot!

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  • Duplication in parallel inheritance hierarchies

    - by flamingpenguin
    Using an OO language with static typing (like Java), what are good ways to represent the following model invariant without large amounts of duplication. I have two (actually multiple) flavours of the same structure. Each flavour requires its own (unique to that flavour data) on each of the objects within that structure as well as some shared data. But within each instance of the aggregation only objects of one (the same) flavour are allowed. FooContainer can contain FooSources and FooDestinations and associations between the "Foo" objects BarContainer can contain BarSources and BarDestinations and associations between the "Bar" objects interface Container() { List<? extends Source> sources(); List<? extends Destination> destinations(); List<? extends Associations> associations(); } interface FooContainer() extends Container { List<? extends FooSource> sources(); List<? extends FooDestination> destinations(); List<? extends FooAssociations> associations(); } interface BarContainer() extends Container { List<? extends BarSource> sources(); List<? extends BarDestination> destinations(); List<? extends BarAssociations> associations(); } interface Source { String getSourceDetail1(); } interface FooSource extends Source { String getSourceDetail2(); } interface BarSource extends Source { String getSourceDetail3(); } interface Destination { String getDestinationDetail1(); } interface FooDestination extends Destination { String getDestinationDetail2(); } interface BarDestination extends Destination { String getDestinationDetail3(); } interface Association { Source getSource(); Destination getDestination(); } interface FooAssociation extends Association { FooSource getSource(); FooDestination getDestination(); String getFooAssociationDetail(); } interface BarAssociation extends Association { BarSource getSource(); BarDestination getDestination(); String getBarAssociationDetail(); }

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  • Django: Summing values of records grouped by foreign key

    - by Dan0
    Hi there In django, given the following models (slightly simplified), I'm struggling to work out how I would get a view including sums of groups class Client(models.Model): api_key = models.CharField(unique=True, max_length=250, primary_key=True) name = models.CharField(unique=True, max_length=250) class Purchase(models.Model): purchase_date = models.DateTimeField() client = models.ForeignKey(SavedClient, to_field='api_key') amount_to_invoice = models.FloatField(null=True) For a given month, I'd like to see e.g. April 2010 For Each Client that purchased this month: * CLient: Name * Total amount of Purchases for this month * Total cost of purchases for this month For each Purchase made by client: * Date * Amount * Etc I've been looking into django annotation, but can't get my head around how to sum values of a field for a particular group over a particular month and send the information to a template as a variable/tag. Any info would be appreciated

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  • How do I use timezones with a datetime object in python?

    - by jidar
    How do I properly represent a different timezone in my timezone? The below example only works because I know that EDT is one hour ahead of me, so I can uncomment the subtraction of myTimeZone() import datetime, re from datetime import tzinfo class myTimeZone(tzinfo): """docstring for myTimeZone""" def utfoffset(self, dt): return timedelta(hours=1) def myDateHandler(aDateString): """u'Sat, 6 Sep 2008 21:16:33 EDT'""" _my_date_pattern = re.compile(r'\w+\,\s+(\d+)\s+(\w+)\s+(\d+)\s+(\d+)\:(\d+)\:(\d+)') day, month, year, hour, minute, second = _my_date_pattern.search(aDateString).groups() month = [ 'JAN', 'FEB', 'MAR', 'APR', 'MAY', 'JUN', 'JUL', 'AUG', 'SEP', 'OCT', 'NOV', 'DEC' ].index(month.upper()) + 1 dt = datetime.datetime( int(year), int(month), int(day), int(hour), int(minute), int(second) ) # dt = dt - datetime.timedelta(hours=1) # dt = dt - dt.tzinfo.utfoffset(myTimeZone()) return (dt.year, dt.month, dt.day, dt.hour, dt.minute, dt.second, 0, 0, 0) def main(): print myDateHandler("Sat, 6 Sep 2008 21:16:33 EDT") if __name__ == '__main__': main()

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  • sqlite3 date and interval functions

    - by umuthorax
    Hi, I wonder whether sqlite3 supports interval function. The following statement is accepted by PostgreSQL, however sqlite3 failed to parse it; select ... from orders where ... and o_orderdate < date '1995-03-01' + interval '3' month Error: near line 4: near "'1995-03-01'": syntax error Then, I modified the statement a little bit such as; and o_orderdate < date('1995-03-01') + interval '3' month This time the error was; Error: near line 4: near "'3'": syntax error Unfortunately, same trick did not work for the interval function i.e. and o_orderdate < date('1995-03-01') + interval('3' month) or and o_orderdate < date('1995-03-01') + interval('3') month or even and o_orderdate < date('1995-03-01') + interval(3 month) still gave me the syntax error. Maybe sqlite3 does not support interval function or am I missing something in its usage? Thanks a lot

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  • mySQL Left Join on multiple tables

    - by Jarrod
    Hi I'm really struggling with this query. I have 4 tables (http://oberto.co.nz/db-sql.png): Invoice_Payement, Invoice, Client and Calendar. I'm trying to create a report by summing up the 'paid_amount' col, in Invoice_Payment, by month/year. The query needs to include all months, even those with no data There query needs the condition (Invoice table): registered_id = [id] I have tried with the below query, which works, but falls short when 'paid_date' does not have any records for a month. The outcome is that month does not show in the results I added a Calendar table to resolved this but not sure how to left join to it. SELECT MONTHNAME(Invoice_Payments.date_paid) as month, SUM(Invoice_Payments.paid_amount) AS total FROM Invoice, Client, Invoice_Payments WHERE Client.registered_id = 1 AND Client.id = Invoice.client_id And Invoice.id = Invoice_Payments.invoice_id AND date_paid IS NOT NULL GROUP BY YEAR(Invoice_Payments.date_paid), MONTH(Invoice_Payments.date_paid) Please see the above link for a basic ERD diagram of my scenario. Thanks for reading. I've posted this Q before but I think I worded it badly.

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  • How to position a UIToolbar at the top of the screen?

    - by Mr_Nizzle
    I've figured out how to hide the navigation bar and then show the toolbar it has built-in but the toolbar appears at the bottom os the screen how can i position the toolbar on the top of the scren? here's some of my code UIBarButtonItem *yesterday = [[UIBarButtonItem alloc]initWithTitle:@"Yesterday" style:UIBarButtonItemStyleBordered target:self action:@selector(yesterday:)]; UIBarButtonItem *today = [[UIBarButtonItem alloc]initWithTitle:@"Today" style:UIBarButtonItemStyleDone target:self action:@selector(today:)]; UIBarButtonItem *tomorrow = [[UIBarButtonItem alloc]initWithTitle:@"Tomorrow" style:UIBarButtonItemStyleBordered target:self action:@selector(tomorrow:)]; UIBarButtonItem *month = [[UIBarButtonItem alloc]initWithTitle:@"Month" style:UIBarButtonItemStyleBordered target:self action:@selector(month:)]; NSArray *items = [NSArray arrayWithObjects:yesterday,today,tomorrow,month, nil]; [yesterday release]; [today release]; [tomorrow release]; [month release]; [self setToolbarItems:items]; [[self navigationController] setNavigationBarHidden:YES animated:NO]; [[self navigationController] setToolbarHidden:NO animated:YES]; Thanks.

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  • MDX - how to filter on children of nextmember

    - by Raj
    I have a user defined hierarchy in SSAS as follows: Calendar Year Month Of Year I want to create following named set in BIDS. Set1 should include "Month of Year" values of 1-9 for current Calendar Year Set2 should include "Month of Year" values of 10-12 for current Calendar Year Set3 shoud include "Month of Year" values of 1-3 for next Calendar Year Set4 shoud include "Month of Year" values of 4-6 for next Calendar Year The "current calendar year" will come through a join with another dimension though a fact table. I would appreciate help with MDX. And, can I use CurrentMember in the named sets?

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  • mysql : Recieve data only per months

    - by Tristan
    Hello, few times ago, i asked how to do to display datas per month, i must told a bad explanation because i just figured out that it's not what i want : Here's what I got : $req1 = ... AND v.date > (DATE_SUB(CURDATE(), INTERVAL 2 MONTH)) AND v.date < (DATE_SUB(CURDATE(), INTERVAL 1 MONTH)) $req2= ... AND v.date > (DATE_SUB(CURDATE(), INTERVAL 3 MONTH)) AND v.date < (DATE_SUB(CURDATE(), INTERVAL 2 MONTH)) But the problem, imagine that today you are the 10th june, it's going to calculate ALL the data between the 10 june to the 10 may then the 10 may until the 10 april... But what i want is data : from 1st may to 1 st june, from 1st june to 1st july... do you see what i mean ? thank you ;)

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  • python logparse search specific text

    - by krisdigitx
    hi, I am using this function in my code to return the strings i want from reading the log file, I want to grep the "exim" process and return the results, but running the code gives no error, but the output is limited to three lines, how can i just get the output only related to exim process.. #output: {'date': '13', 'process': 'syslogd', 'time': '06:27:33', 'month': 'May'} {'date': '13', 'process': 'exim[23168]:', 'time': '06:27:33', 'month': 'May'} {'May': ['syslogd']} #function: def generate_log_report(logfile): report_dict = {} for line in logfile: line_dict = dictify_logline(line) print line_dict try: month = line_dict['month'] date = line_dict['date'] time = line_dict['time'] #process = line_dict['process'] if "exim" in line_dict['process']: process = line_dict['process'] break else: process = line_dict['process'] except ValueError: continue report_dict.setdefault(month, []).append(process) return report_dict

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  • SQL Server adding a record record manually to a view

    - by SelectDistinct
    I have a view which contains the data seen in the image below. The view is showing me how many working days are available in each month for the current financial year taking away any school/bank holidays. As the month of August has zero days available it has excluded this month from the view. As the total number of days available will always be zero for the month of August, then it seems acceptable to hardcode the SQL to always have 0 for August, and also an April-August record which will be the same as April-July. What would be the best way to add these 2 records, and where about in the code should it be placed see example of code layout: see link (answered question) for layout of code: SQL populate total working days per month minus bank holidays for current financial year

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  • Storing/Quering multiple value in SQLite

    - by chmod
    I'm trying to store a blooming season in month for each tree in SQLite3. Currently I had the field "month" then I store the month name in the field. For example Tree Name Month Tree1 Jan,Feb,Mar Tree2 Nov,Dec,Jan Tree3 Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec Tree4 Mar,Apr,Nov,Dec Tree5 Jan,Feb,Mar,Apr I'm not sure if this is the best way to store it, Any recommendation is appreciate. Secondly, I need to perform a query where I enter in the month and it should return me the tree name that match the search criteria. For example If I search for "Jan" the result should be Tree1,Tree2,Tree3,Tree5 "Jan,Feb,Mar" the result should be Tree1,Tree3,Tree5 "Jan,Feb,Mar,Apr" the result should be Tree5 "Sep,Oct,Nov,Dec" the result should be none Which SQL query do I have to use in order to obtain the above result? Thanks

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  • Loading an XML file with todays date in the filename... need to fallback to old file if one with tod

    - by arala22
    So here is my question. Using javascript/jQuery I am currently loading in an XML file that has a file name such as carousel_large_2010-06-08.xml.. the way I am doing it is checked for todays date then grabbing a file that has that date in the filename... the issue is sometimes they wont be uploading a new file for a given day so it needs to fallback to a older date that exists.. Wondering how to do it? Here is my code: // set date for xml file var currentTime = new Date(), month = currentTime.getMonth() + 1, day = currentTime.getDate(), year = currentTime.getFullYear(); if(month.toString().length == 1){ month = '0'+month.toString(); } if(day.toString().length == 1){ day = '0'+day.toString(); } var dateObject = year+"-"+month+"-"+day; // start magic $jq.ajax({ type: "GET", url: "_xml/carousel/home/carousel_large_"+dateObject+".xml", dataType: "xml", success: HPCarousels.heroCarousel.parseXML, error: function(){ alert('Error Loading XML Content'); } });

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  • Twitter search for my recent tweets

    - by ravenspoint
    Has twitter search stopped supporting this: from:username since:2010-05-01 It used to work! The reason I care is I use the following javascript to display recent tweets on my webpage var username = '...' var od = new Date(); od.setMilliseconds( od.getMilliseconds() - 518400000 ); var month = od.getMonth() + 1 if (month<10) month = ('0'+month) var day = od.getDate() if (day<10) day = ('0'+day) var year = od.getFullYear() var sd = (year + '-' + month + '-' + day) document.write( sd ) new TWTR.Widget({ search: 'from:' + username + ' since:' + sd, This has worked for about a year, but recently stopped.

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  • How can I select all records between two dates without using date fields?

    - by Hayden Bech
    Hi, I have a MySQL DB and I need to be able to store dates earlier then 1970 - in my case, as early as 0 AD and earlier too, so I need a custom way to store dates. I have thought to use this format: Year - int(6) | Month -int(2) | day - int (2) | time - time | AD tinyint (1) | mya - int (11) But when it comes to actually using data in this format it becomes difficult. For example, if I want to get all records between two dates it would be like (pseudocode not SQL): get all where year between minYear and maxYear if year == minYear, month = minMonth if year == maxYear, month <= maxMonth if month == minMonth, day = minDay if month == maxMonth, day <= maxDay if day == minDay, time = minTime if day == maxDay, time <= maxTime or something, which seems like a right pain. I could store seconds before/after 0 AD, but that would take up way too much data! 2010 (EDIT: 2011) = 6.4 billion seconds since 0 AD. Does anybody have any ideas for this problem?

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  • rearranging a list of months

    - by MacUsers
    How can I list the numbers 01 to 12 (one for each of the 12 months) in such a way so that the current month always comes last where the oldest one is first. In other words, if the number is grater than the current month, it's from the previous year. e.g. 02 is Feb, 2011 (the current month right now), 03 is March, 2010 and 09 is Sep, 2010 but 01 is Jan, 2011. In this case, I'd like to have [09, 03, 01, 02]. This is what I'm doing to determine the year: for inFile in os.listdir('.'): if inFile.isdigit(): month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) I don't have a clue what to do next. What should I do here?

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  • Javascript code for serial img loading

    - by Surfer
    Hi everyone, I am new to javascript. I want a javascript code with which i can load an image which is named for every day/month/year. in a serial i have the following code : var year = new Array(); year = ["08", "09", "10", "11"]; var month = new Array(); month = ["JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JULY", "AUG", "SEP", "OCT", "NOV", "DEC"]; var date = new Array(); date = ["01", "02", "03", "04", "05", "06", "07", "08", "09", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20", "21", "22", "23", "24", "25", "26", "27", "28", "29", "30", "31"]; var ims = ""; for (var x in year) { for (var y in month) { for (var z in date) { ims += "<im src=screencover/img/" + date[z] + "" + month[y] + "20" + year[0] + ".png>"; } } } document.write(ims);

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  • Calculating for leap year [migrated]

    - by Bradley Bauer
    I've written this program using Java in Eclipse. I was able to utilize a formula I found that I explained in the commented out section. Using the for loop I can iterate through each month of the year, which I feel good about in that code, it seems clean and smooth to me. Maybe I could give the variables full names to make everything more readable but I'm just using the formula in its basic essence :) Well my problem is it doesn't calculate correctly for years like 2008... Leap Years. I know that if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) then we have a leap year. Maybe if the year is a leap year I need to subtract a certain amount of days from a certain month. Any solutions, or some direction would be great thanks :) package exercises; public class E28 { /* * Display the first days of each month * Enter the year * Enter first day of the year * * h = (q + (26 * (m + 1)) / 10 + k + k/4 + j/4 + 5j) % 7 * * h is the day of the week (0: Saturday, 1: Sunday ......) * q is the day of the month * m is the month (3: March 4: April.... January and Feburary are 13 and 14) * j is the century (year / 100) * k is the year of the century (year %100) * */ public static void main(String[] args) { java.util.Scanner input = new java.util.Scanner(System.in); System.out.print("Enter the year: "); int year = input.nextInt(); int j = year / 100; // Find century for formula int k = year % 100; // Find year of century for formula // Loop iterates 12 times. Guess why. for (int i = 1, m = i; i <= 12; i++) { // Make m = i. So loop processes formula once for each month if (m == 1 || m == 2) m += 12; // Formula requires that Jan and Feb are represented as 13 and 14 else m = i; // if not jan or feb, then set m to i int h = (1 + (26 * (m + 1)) / 10 + k + k/4 + j/4 + 5 * j) % 7; // Formula created by a really smart man somewhere // I let the control variable i steer the direction of the formual's m value String day; if (h == 0) day = "Saturday"; else if (h == 1) day = "Sunday"; else if (h == 2) day = "Monday"; else if (h == 3) day = "Tuesday"; else if (h == 4) day = "Wednesday"; else if (h == 5) day = "Thursday"; else day = "Friday"; switch (m) { case 13: System.out.println("January 1, " + year + " is " + day); break; case 14: System.out.println("Feburary 1, " + year + " is " + day); break; case 3: System.out.println("March 1, " + year + " is " + day); break; case 4: System.out.println("April 1, " + year + " is " + day); break; case 5: System.out.println("May 1, " + year + " is " + day); break; case 6: System.out.println("June 1, " + year + " is " + day); break; case 7: System.out.println("July 1, " + year + " is " + day); break; case 8: System.out.println("August 1, " + year + " is " + day); break; case 9: System.out.println("September 1, " + year + " is " + day); break; case 10: System.out.println("October 1, " + year + " is " + day); break; case 11: System.out.println("November 1, " + year + " is " + day); break; case 12: System.out.println("December 1, " + year + " is " + day); break; } } } }

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  • How much is a subscriber worth?

    - by Tom Lewin
    This year at Red Gate, we’ve started providing a way to back up SQL Azure databases and Azure storage. We decided to sell this as a service, instead of a product, which means customers only pay for what they use. Unfortunately for us, it makes figuring out revenue much trickier. With a product like SQL Compare, a customer pays for it, and it’s theirs for good. Sure, we offer support and upgrades, but, fundamentally, the sale is a simple, upfront transaction: we’ve made this product, you need this product, we swap product for money and everyone is happy. With software as a service, it isn’t that easy. The money and product don’t change hands up front. Instead, we provide a service in exchange for a recurring fee. We know someone buying SQL Compare will pay us $X, but we don’t know how long service customers will stay with us, or how much they will spend. How do we find this out? We use lifetime value analysis. What is lifetime value? Lifetime value, or LTV, is how much a customer is worth to the business. For Entrepreneurs has a brilliant write up that we followed to conduct our analysis. Basically, it all boils down to this equation: LTV = ARPU x ALC To make it a bit less of an alphabet-soup and a bit more understandable, we can write it out in full: The lifetime value of a customer equals the average revenue per customer per month, times the average time a customer spends with the service Simple, right? A customer is worth the average spend times the average stay. If customers pay on average $50/month, and stay on average for ten months, then a new customer will, on average, bring in $500 over the time they are a customer! Average spend is easy to work out; it’s revenue divided by customers. The problem comes when we realise that we don’t know exactly how long a customer will stay with us. How can we figure out the average lifetime of a customer, if we only have six months’ worth of data? The answer lies in the fact that: Average Lifetime of a Customer = 1 / Churn Rate The churn rate is the percentage of customers that cancel in a month. If half of your customers cancel each month, then your average customer lifetime is two months. The problem we faced was that we didn’t have enough data to make an estimate of one month’s cancellations reliable (because barely anybody cancels)! To deal with this data problem, we can take data from the last three months instead. This means we have more data to play with. We can still use the equation above, we just need to multiply the final result by three (as we worked out how many three month periods customers stay for, and we want our answer to be in months). Now these estimates are likely to be fairly unreliable; when there’s not a lot of data it pays to be cautious with inference. That said, the numbers we have look fairly consistent, and it’s super easy to revise our estimates when new data comes in. At the very least, these numbers give us a vague idea of whether a subscription business is viable. As far as Cloud Services goes, the business looks very viable indeed, and the low cancellation rates are much more than just data points in LTV equations; they show that the product is working out great for our customers, which is exactly what we’re looking for!

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  • Debugger ignores me.

    - by atch
    Having code: Date::Date(const char* day, const char* month, const char* year):is_leap__(false) { my_day_ = lexical_cast<int>(day); my_month_ = static_cast<Month>(lexical_cast<int>(month)); /*Have to check month here, other ctor assumes month is correct*/ if (my_month_ < 1 || my_month_ > 12) { throw std::exception("Incorrect month."); } my_year_ = lexical_cast<int>(year); if (!check_range_year_(my_year_)) { throw std::exception("Year out of range."); } if (check_leap_year_(my_year_))//SKIPS THIS LINE { is_leap__ = true; } if (!check_range_day_(my_day_, my_month_)) { throw std::exception("Day out of range."); } } bool Date::check_leap_year_(int year)const//IF I MARK THIS LINE WITH BREAKPOINT I'M GETTING MSG THAT THERE IS NO EXECUTABLE CODE IS ASSOSIATED WITH THIS LINE { if (!(year%400) || (year%100 && !(year%4))) { return true; } else { return false; } } Which is very strange in my opinion. There is call to this fnc in my code, why compiler ignores that. P.S. I'm trying to debug in release.

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