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• How to represent a 3-way relation with JPA?

  - by simpatico

  A user may have several labels, and links. Then, a user associates a label (or more) to a link. How does one represent the later relationship? A solution could be a many-to-many relationship btw user and link with the optional attribute label. http://en.wikibooks.org/wiki/Java_Persistence/ManyToMany#Mapping_a_Join_Table_with_Additional_Columns In this case the relationship btw user and label may better be 'virtual'. Any alternative I'm not seeing? PS: I've used google bookmarks terminology, as it matches my case quite well.

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• JPA: How do I get a scalar result of type Long-- not BigNumber-- from Oracle NUMBER?

  - by rektide

  The default mapping from an Oracle NUMBER value is into BigNumber... How can I get a scalar result query to return a Long instead?

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• How to dynamically order many-to-many relationship with JPA or HQl?

  - by Indrek

  I have a mapping like this: @ManyToMany(cascade = CascadeType.PERSIST) @JoinTable( name="product_product_catalog", joinColumns={@JoinColumn(name="product_catalog", referencedColumnName="product_catalog")}, inverseJoinColumns={@JoinColumn(name="product", referencedColumnName="product")}) public List<Product> products = new ArrayList<Product>(); I can fetch the products for the catalog nicely, but I can't (dynamically) order the products. How could I order them? I probably have to write a many-to-many HQL query with the order-by clause? I though of passing the orderBy field name string to the query, or is there a better solution? Tables are: products, product_catalog, product_product_catalog (associative table) P.S. Using Play! Framework JPASupport for my entities.

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• How do I check that an entity is unreferenced in JPA?

  - by Martin

  I have the following model @Entity class Element { @Id int id; @Version int version; @ManyToOne Type type; } @Entity class Type { @Id int id; @Version int version; @OneToMany(mappedBy="type") Collection<Element> elements; @Basic(optional=false) boolean disabled; } and would like to allow Type.disabled = true only if Type.elements is empty. Is there a way to do it atomically? I would like to prevent an insertion of an Element in a transaction while the corresponding Type is being disabled by an other transaction.

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• Having an issue with Onejar-Maven-Plugin

  - by reverendgreen

  I am trying to package a simple maven java project (uses javax.persistence api) into a single jar using the onejar-maven-plugin. I can run the program fine in eclipse; however when execute the onejar I get the exception below. If someone could provide some insight, that would be appreciated. Thanks, RG Exception in thread "main" java.lang.reflect.InvocationTargetException at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Unknown Source) at com.simontuffs.onejar.Boot.run(Boot.java:306) at com.simontuffs.onejar.Boot.main(Boot.java:159) Caused by: Exception [EclipseLink-30005] (Eclipse Persistence Services - 2.0.0.v20091127-r5931): org.eclipse.persistence.exceptions.PersistenceUnitLoadingExcept Exception Description: An exception was thrown while searching for persistence archives with ClassLoader: com.simontuffs.onejar.JarClassLoader@190d11 Internal Exception: java.lang.ClassCastException: sun.misc.Launcher$AppClassLoader cannot be cast to com.simontuffs.onejar.JarClassLoader at org.eclipse.persistence.exceptions.PersistenceUnitLoadingException.exceptionSearchingForPersistenceResources(PersistenceUnitLoadingException.java:126 at org.eclipse.persistence.jpa.PersistenceProvider.createEntityManagerFactory(PersistenceProvider.java:133) at org.eclipse.persistence.jpa.PersistenceProvider.createEntityManagerFactory(PersistenceProvider.java:65) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:78) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:54) at com.test.onejartest.App.main(App.java:19) ... 6 more Caused by: java.lang.ClassCastException: sun.misc.Launcher$AppClassLoader cannot be cast to com.simontuffs.onejar.JarClassLoader at com.simontuffs.onejar.JarClassLoader.getByteStream(JarClassLoader.java:753) at com.simontuffs.onejar.Handler$1.getInputStream(Handler.java:50) at java.net.URL.openStream(Unknown Source) at org.eclipse.persistence.internal.jpa.deployment.ArchiveFactoryImpl.isJarInputStream(ArchiveFactoryImpl.java:124) at org.eclipse.persistence.internal.jpa.deployment.ArchiveFactoryImpl.createArchive(ArchiveFactoryImpl.java:106) at org.eclipse.persistence.internal.jpa.deployment.PersistenceUnitProcessor.findPersistenceArchives(PersistenceUnitProcessor.java:213) at org.eclipse.persistence.internal.jpa.deployment.JPAInitializer.findPersistenceUnitInfoInArchives(JPAInitializer.java:134) at org.eclipse.persistence.internal.jpa.deployment.JPAInitializer.findPersistenceUnitInfo(JPAInitializer.java:125) at org.eclipse.persistence.jpa.PersistenceProvider.createEntityManagerFactory(PersistenceProvider.java:98) ... 10 more pom.xml: ... <pluginRepositories> <pluginRepository> <id>onejar-maven-plugin.googlecode.com</id> <url>http://onejar-maven-plugin.googlecode.com/svn/mavenrepo</url> </pluginRepository> </pluginRepositories> ... <build> <plugins> <plugin> <groupId>org.dstovall</groupId> <artifactId>onejar-maven-plugin</artifactId> <version>1.3.0</version> <executions> <execution> <configuration> <mainClass>com.test.onejartest.App</mainClass> </configuration> <goals> <goal>one-jar</goal> </goals> </execution> </executions> </plugin> <plugin> <artifactId>maven-compiler-plugin</artifactId> <version>2.3.1</version> <configuration> <target>1.6</target> <source>1.6</source> </configuration> </plugin> </plugins> </build> ... <dependencies> <dependency> <groupId>javax.persistence</groupId> <artifactId>persistence-api</artifactId> <version>2.0.0</version> </dependency> <dependency> <groupId>org.eclipse.persistence</groupId> <artifactId>eclipselink</artifactId> <version>2.0.0</version> </dependency> <dependency> <groupId>com.microsoft.sqlserver.jdbc</groupId> <artifactId>sqljdbc</artifactId> <version>4.0.0</version> </dependency> </dependencies>

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• No unique bean of type [javax.persistence.EntityManager] is defined

  - by sebajb

  I am using JUnit 4 to test Dao Access with Spring (annotations) and JPA (hibernate). The datasource is configured through JNDI(Weblogic) with an ORacle(Backend). This persistence is configured with just the name and a RESOURCE_LOCAL transaction-type The application context file contains notations for annotations, JPA config, transactions, and default package and configuration for annotation detection. I am using Junit4 like so: ApplicationContext <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="persistenceUnitName" value="workRequest"/> <property name="dataSource" ref="dataSource" /> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="databasePlatform" value="${database.target}"/> <property name="showSql" value="${database.showSql}" /> <property name="generateDdl" value="${database.generateDdl}" /> </bean> </property> </bean> <bean id="dataSource" class="org.springframework.jndi.JndiObjectFactoryBean"> <property name="jndiName"> <value>workRequest</value> </property> <property name="jndiEnvironment"> <props> <prop key="java.naming.factory.initial">weblogic.jndi.WLInitialContextFactory</prop> <prop key="java.naming.provider.url">t3://localhost:7001</prop> </props> </property> </bean> <bean id="txManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="entityManagerFactory" /> </bean> <bean class="org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor"/> <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" /> JUnit TestCase @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations = { "classpath:applicationContext.xml" }) public class AssignmentDaoTest { private AssignmentDao assignmentDao; @Test public void readAll() { assertNotNull("assignmentDao cannot be null", assignmentDao); List assignments = assignmentDao.findAll(); assertNotNull("There are no assignments yet", assignments); } } regardless of what changes I make I get: No unique bean of type [javax.persistence.EntityManager] is defined Any hint on what this could be. I am running the tests inside eclipse.

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• deadline in google app engine application

  - by megala

  How to define deadline for google app engine datastore application using JPA thanks in advance

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• Suggest-a-Session for Oracle Develop 2010: Last chance to get your paper submitted.

  - by olaf.heimburger

  While working with Oracle Technologies at customer projects we all come across solutions and ideas that are worth to share with a greater audience. When you missed the Call For Paper for Oracle OpenWorld and Oracle Develop you have the chance to get in. The Oracle Mix Community provides a tool called Suggest-a-Session for submitting and voting the sessions you would like to attend. My Suggestions When you pass by, do not forget to vote for my sessions. These are: Real-World Single Sign-On and ADF Security The Personal Newsletter Generator: Implement Cool Applications with ADF Faces Thank you for your support.

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• Is Java's ElementCollection Considered a Bad Practice?

  - by SoulBeaver

  From my understanding, an ElementCollection has no primary key, is embedded with the class, and cannot be queried. This sounds pretty hefty, but it allows me the comfort of writing an enum class which also helps with internationalization (using the enum key for lookup in my ResourceBundle). Example: We have a user on a media site and he can choose in which format he downloads the files @Entity @Table(name = "user") public class User { /* snip other fields */ @Enumerated @ElementCollection( targetClass = DownloadFilePreference.class, fetch = FetchType.EAGER ) @CollectionTable(name = "download_file_preference", joinColumns = @JoinColumn(name = "user_id") ) @Column(name = "name") private Set<DownloadFilePreference> downloadFilePreferences = new HashSet<>(); } public enum DownloadFilePreference { MP3, WAV, AIF, OGG; } This seems pretty great to me, and I suppose it comes down to "it depends on your use case", but I also know that I'm quite frankly only an initiate when it comes to Database design. Some best practices suggest to never have a class without a primary key- even in this case? It also doesn't seem very extensible- should I use this and gamble on the chance I will never need to query on the FilePreferences?

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• Invalid XML in persistence.xml : Init method

  - by James.Elsey

  I'm getting the following error when I try to startup my application on google app engine: Failed startup of context com.google.apphosting.utils.jetty.RuntimeAppEngineWebAppContext@8fcc7b{/,/base/data/home/apps/sales-tracker/3.340980411948080671} org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'clientDao' defined in ServletContext resource [/WEB-INF/applicationContext.xml]: Cannot resolve reference to bean 'entityManagerFactory' while setting bean property 'entityManagerFactory'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in ServletContext resource [/WEB-INF/applicationContext.xml]: Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Invalid XML in persistence unit from URL [file:/base/data/home/apps/sales-tracker/3.340980411948080671/WEB-INF/classes/META-INF/persistence.xml] at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:275) at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveValueIfNecessary(BeanDefinitionValueResolver.java:104) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyPropertyValues(AbstractAutowireCapableBeanFactory.java:1245) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1010) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:472) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:409) at java.security.AccessController.doPrivileged(Native Method) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:380) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:264) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:261) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:185) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:164) at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:429) at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:728) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:380) at org.springframework.web.context.ContextLoader.createWebApplicationContext(ContextLoader.java:255) at org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:199) at org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:45) at org.mortbay.jetty.handler.ContextHandler.startContext(ContextHandler.java:548) at org.mortbay.jetty.servlet.Context.startContext(Context.java:136) at org.mortbay.jetty.webapp.WebAppContext.startContext(WebAppContext.java:1250) at org.mortbay.jetty.handler.ContextHandler.doStart(ContextHandler.java:517) at org.mortbay.jetty.webapp.WebAppContext.doStart(WebAppContext.java:467) at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:50) at com.google.apphosting.runtime.jetty.AppVersionHandlerMap.createHandler(AppVersionHandlerMap.java:191) at com.google.apphosting.runtime.jetty.AppVersionHandlerMap.getHandler(AppVersionHandlerMap.java:168) at com.google.apphosting.runtime.jetty.JettyServletEngineAdapter.serviceRequest(JettyServletEngineAdapter.java:123) at com.google.apphosting.runtime.JavaRuntime.handleRequest(JavaRuntime.java:243) at com.google.apphosting.base.RuntimePb$EvaluationRuntime$6.handleBlockingRequest(RuntimePb.java:5485) at com.google.apphosting.base.RuntimePb$EvaluationRuntime$6.handleBlockingRequest(RuntimePb.java:5483) at com.google.net.rpc.impl.BlockingApplicationHandler.handleRequest(BlockingApplicationHandler.java:24) at com.google.net.rpc.impl.RpcUtil.runRpcInApplication(RpcUtil.java:398) at com.google.net.rpc.impl.Server$2.run(Server.java:852) at com.google.tracing.LocalTraceSpanRunnable.run(LocalTraceSpanRunnable.java:56) at com.google.tracing.LocalTraceSpanBuilder.internalContinueSpan(LocalTraceSpanBuilder.java:536) at com.google.net.rpc.impl.Server.startRpc(Server.java:807) at com.google.net.rpc.impl.Server.processRequest(Server.java:369) at com.google.net.rpc.impl.ServerConnection.messageReceived(ServerConnection.java:442) at com.google.net.rpc.impl.RpcConnection.parseMessages(RpcConnection.java:319) at com.google.net.rpc.impl.RpcConnection.dataReceived(RpcConnection.java:290) at com.google.net.async.Connection.handleReadEvent(Connection.java:474) at com.google.net.async.EventDispatcher.processNetworkEvents(EventDispatcher.java:831) at com.google.net.async.EventDispatcher.internalLoop(EventDispatcher.java:207) at com.google.net.async.EventDispatcher.loop(EventDispatcher.java:103) at com.google.net.rpc.RpcService.runUntilServerShutdown(RpcService.java:251) at com.google.apphosting.runtime.JavaRuntime$RpcRunnable.run(JavaRuntime.java:404) at java.lang.Thread.run(Unknown Source) Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in ServletContext resource [/WEB-INF/applicationContext.xml]: Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Invalid XML in persistence unit from URL [file:/base/data/home/apps/sales-tracker/3.340980411948080671/WEB-INF/classes/META-INF/persistence.xml] at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1338) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:473) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:409) at java.security.AccessController.doPrivileged(Native Method) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:380) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:264) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:261) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:185) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:164) at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:269) ... 47 more Caused by: java.lang.IllegalArgumentException: Invalid XML in persistence unit from URL [file:/base/data/home/apps/sales-tracker/3.340980411948080671/WEB-INF/classes/META-INF/persistence.xml] at org.springframework.orm.jpa.persistenceunit.PersistenceUnitReader.readPersistenceUnitInfos(PersistenceUnitReader.java:151) at org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager.readPersistenceUnitInfos(DefaultPersistenceUnitManager.java:303) at org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager.preparePersistenceUnitInfos(DefaultPersistenceUnitManager.java:275) at org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager.afterPropertiesSet(DefaultPersistenceUnitManager.java:260) at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:192) at org.springframework.orm.jpa.AbstractEnti My persistence.xml looks as follows, as taken from the GAE documentation <?xml version="1.0" encoding="UTF-8" ?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"version="1.0"> <persistence-unit name="transactions-optional"> <provider>org.datanucleus.store.appengine.jpa.DatastorePersistenceProvider</provider> <properties> <property name="datanucleus.NontransactionalRead" value="true" /> <property name="datanucleus.NontransactionalWrite" value="true" /> <property name="datanucleus.ConnectionURL" value="appengine" /> </properties> </persistence-unit> </persistence> Is there something wrong with my persistence file? Or could my errors be caused elsewhere? Can someone please give me some pointers thanks

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• Inserting the record into Database through JPA

  - by vinay123

  In my code I am using JSF - Front end , EJB-Middile Tier and JPA connect to DB.Calling the EJB using the Webservices.Using MySQL as DAtabase. I have created the Voter table in which I need to insert the record. I ma passing the values from the JSF to EJB, it is working.I have created JPA controller class (which automatcally generates the persistence code based on the data base classes) Ex: getting the entity manager etc., em = getEntityManager(); em.getTransaction().begin(); em.persist(voter); em.getTransaction().commit(); I have created the named query also: @NamedQuery(name = "Voter.insertRecord", query = "INSERT INTO Voter v values v.voterID = :voterID,v.password = :password,v.partSSN = :partSSN, v.address = :address, v.zipCode = :zipCode,v.ssn = :ssn, v.vFirstName = :vFirstName,v.vLastName = :vLastName,v.dob = :dob"), But still not able to insert the record? Can anyone help me in inserting the record into the Data base through JPA.(Persistence object)?

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• Inserting the record into Data Base through JPA

  - by vinay123

  In my code I am using JSF - Front end , EJB-Middile Tier and JPA connect to DB.Calling the EJB using the Webservices.Using MySQL as DAtabase. I have created the Voter table in which I need to insert the record. I ma passing the values from the JSF to EJB, it is working.I have created JPA controller class (which automatcally generates the persistence code based on the data base classes) Ex: getting the entity manager etc., em = getEntityManager(); em.getTransaction().begin(); em.persist(voter); em.getTransaction().commit(); I have created the named query also: @NamedQuery(name = "Voter.insertRecord", query = "INSERT INTO Voter v values v.voterID = :voterID,v.password = :password,v.partSSN = :partSSN,v.address = :address, v.zipCode = :zipCode,v.ssn = :ssn, v.vFirstName = :vFirstName,v.vLastName = :vLastName,v.dob = :dob"),But still not able to insert the record? Can anyone help me in inserting the record into the Data base through JPA.(Persistence object)?

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• EntityManagerFactory error on Websphere

  - by neverland

  I have a very weird problem. Have an application using Hibernate and spring.I have an entitymanger defined which uses a JNDI lookup .It looks something like this <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="persistenceUnitName" value="ConfigAPPPersist" /> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="showSql" value="true" /> <property name="generateDdl" value="false" /> <property name="databasePlatform" value="org.hibernate.dialect.Oracle9Dialect" /> </bean> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.WebSphereDataSourceAdapter"> <property name="targetDataSource"> <bean class="org.springframework.jndi.JndiObjectFactoryBean"> <property name="jndiName" value="jdbc/pmp" /> </bean> </property> </bean> This application runs fine in DEV. But when we move to higher envs the team that deploys this application does it successfully initially but after a few restarts of the application the entitymanager starts giving this problem Caused by: javax.persistence.PersistenceException: [PersistenceUnit: ConfigAPPPersist] Unable to build EntityManagerFactory at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:677) at org.hibernate.ejb.HibernatePersistence.createContainerEntityManagerFactory(HibernatePersistence.java:132) at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:224) at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:291) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1368) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1334) ... 32 more Caused by: org.hibernate.MappingException: **property mapping has wrong number of columns**: com.***.***.jpa.marketing.entity.MarketBrands.$performasure_j2eeInfo type: object Now you would say this is pretty obvious the entity MarketBrands is incorrect. But its not it maps to the table just fine. And the same code works on DEV. Also the jndi cannot be incorrect since it deploys and works fine initially but throws uo this error after a restart. This is weird and not very logical. But if someone has faced this or has any idea on what might be causing this Please!! help The persistence.xml for the persitence unit has very little <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="ConfigAPPPersist"> <!-- commented code --> </persistence-unit> </persistence>

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• Spring and hibernate.cfg.xml

  - by Steve Kuo

  How do I get Spring to load Hibernate's properties from hibernate.cfg.xml? We're using Spring and JPA (with Hibernate as the implementation). Spring's applicationContext.xml specifies the JPA dialect and Hibernate properties: <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean"> <property name="jpaDialect"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaDialect" /> </property> <property name="jpaProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQLInnoDBDialect</prop> </props> </property> </bean> In this configuration, Spring is reading all the Hibernate properties via applicationContext.xml . When I create a hibernate.cfg.xml (located at the root of my classpath, the same level as META-INF), Hibernate doesn't read it at all (it's completely ignored). What I'm trying to do is configure Hibernate second level cache by inserting the cache properties in hibernate.cfg.xml: <cache usage="transactional|read-write|nonstrict-read-write|read-only" region="RegionName" include="all|non-lazy" />

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• JPQL get most recent rows

  - by Vinnie

  Let's say I have the following tables my_profile_data ------------- integer: profile_id date: date_changed string: value my_profile ------------- integer: profile_id string: name I want to get the most recent profile information. In plain SQL this would look something like: select mpd.profile_id, mpd.value, max(mpd.date_changed) from my_profile_data mpd, my_profile mp where mpd.profile_id = mp.profile_id and mp.name='The Profile I Want' group by mpd.profile_id I've tried different variants of the following JPQL query, but cant get it to work. SELECT mpd FROM MyProfileData mpd LEFT JOIN (SELECT mpd.profileId profileId, MAX(mpd.dateChanged) FROM MyProfileData mpd LEFT JOIN mp.profile WHERE mp.name = :name GROUP BY mpd.profileId) recent ON (rp.profileid = recent.profileId) Is this query doable in JPA? I'm using EclipseLink as my JPA provider. The innermost exception I get when I try to run this is Caused by: NoViableAltException(81!=[506:7: (n= joinAssociationPathExpression ( AS )? i= IDENT | t= FETCH n= joinAssociationPathExpression )]) at org.eclipse.persistence.internal.jpa.parsing.jpql.antlr.JPQLParser.join(JPQLParser.java:3669) ... 73 more

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• using JDBC with persistence.xml

  - by moshe shamy

  I am building a framework that manage the access to the database. the framework getting tasks from the user and handle a connection pooling that manage the access to the database. the user just send me SQL commands. One of the feature that i would like to support is working with JPA, in this case i will provide entity manager. in some cases i would like to provide JDBC access as well as JPA access. the arguments for the database are written in XML file. so for JPA i need to write the property in persistence.xml so it will be not so smart to write again the same arguments for JDBC. do you know if i can get the arguments of the database from persistence.xml, do you know if there is a source code that do it. or should i parse persistence.xml by myself?

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• Indexed element access in JPQL

  - by Timo Westkämper

  Is it possible to do indexed element access in JPQL like in HQL : select o from Order o where o.items[0].id = 1234 I couldn't find something related in the JPA 2 specs, I am targeting EclipseLink JPA here, so if you come up with an EclipseLink solution, that's ok as well, although a JPQL standard solution is preferred.

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• Annotations present at compile time but absent at runtime

  - by deamon

  It is possible to use Java class files which includes annotations that are not present at runtime? Example: I want to write a class with the JPA @Embeddable annotation, which would be present at compile time (maven scope: "provided"). But the annoatation definition could be absent at runtime, if the class is used outside a JPA application.

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• How can I validate two or more fields in combination?

  - by DR

  I'm using JPA 2.0/Hibernate validation to validate my models. I now have a situation where the combination of two fields has to be validated: public class MyModel { public Integer getValue1() { //... } public String getValue2() { //... } } The model is invalid if both getValue1() and getValue2() are null and valid otherwise. How can I perform this kind of validation with JPA 2.0/Hibernate? With a simple @NotNull annotation both getters must be non-null to pass validation.

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• A concise, clear list of what is new in JPA2?

  - by Benju

  Does anybody know of a good list of what is new in JPA 2? Not what is new with Hibernate/TopLink in the version that supports JPA 2 but what is new in the actual spec.

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• JPA 2.0 Implementations comparison : Hibernate 3.5 vs EclipseLink 2 vs OpenJPA 2

  - by peperg

  What's your choice? Do You have any suggestions and experience? I'm developing an application with Hibernate 3.5 and Spring 3.0 Pros: Good documentation Easy configuration and helpful logs Popularity - wide community Some extensions to JPA Some additional Tools - JBoss Tools for Eclipse, hbm2ddl, generating static metamodel etc... Cons: Bugs! (Sequences, collections etc...) Lots of reatures are doubled with "pure" Hibernate. There's a mess in legacy Hibernate and JPA annotations. I'm considering to switch to EclipseLink. What do You think ? Edit: I've tried EclipseLink and have very bad experiences. It seems like EclipseLink needs LoadTimeWeaver and likes to run on OSGi platform rather than simple Jetty or Tomcat environment. I just don't have time for all this configuration stuff.

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• GQL query language inside of jpa program

  - by megala

  How we use GQL query language inside of jpa program.

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• Can Hibernate be used as the JPA provider in Google App Engine

  - by Joshua

  Can Hibernate 3.5.x be used as the JPA provider instead of the default provider in the latest version of Google App Engine (1.3.2)

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• How to make an entity out of a join table without primary key

  - by tputkonen

  I'm trying to generate JPA entities out of an existing database having an "interesting" design. Database has a table called UserSet, which can have links to several other UserSets. There is a one to many relation between UserSets and LinkedUserSets. LinkedUserSets also has one to one relation to UserSets. I tried to generate a JPA Entity out of the database structure using Dali JPA Tools. The resulting entity Linkeduserset misses @Id or @EmbeddedId annotation and thus failes to compile. As the resulting entity contains only two @JoinColumns (which cannot be marked as @Id), I have not so far found a way around this issue. Database structure can not be modified in any way. Is there a way to overcome this somehow? Relevant pars of create table statements: CREATE TABLE `LinkedUserSets` ( `UsrSetID` INT(11) NOT NULL DEFAULT '0' , `ChildID` INT(11) NOT NULL DEFAULT '0' , CONSTRAINT `fk_LinkedUserSets_UserSet1` FOREIGN KEY (`UsrSetID` ) REFERENCES `UserSet` (`UsrSetID` )); CREATE TABLE `UserSet` ( `UsrSetID` INT(11) NOT NULL AUTO_INCREMENT , PRIMARY KEY (`UsrSetID`), CONSTRAINT `fk_UserSet_LinkedUserSets1` FOREIGN KEY (`UsrSetID` ) REFERENCES `LinkedUserSets` (`ChildID` )); Generated entities: @Entity @Table(name="linkedusersets") public class Linkeduserset { //bi-directional many-to-one association to Userset @ManyToOne @JoinColumn(name="UsrSetID") private Userset userset1; //bi-directional one-to-one association to Userset @OneToOne @JoinColumn(name="ChildID") private Userset userset2; } @Entity @Table(name="userset") public class Userset { private static final long serialVersionUID = 1L; @Id @Column(name="UsrSetID") private int jngSetID; //bi-directional many-to-one association to Linkeduserset @OneToMany(mappedBy="userset1") private Set<Linkeduserset> linkedusersets; //bi-directional one-to-one association to Linkeduserset @OneToOne(mappedBy="userset2") private Linkeduserset linkeduserset; } Error message: Entity "Linkeduserset" has no Id or EmbeddedId

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• Handling Denormalized Schema with Eclipselink

  - by iamrohitbanga

  Hello All I have a denormalized table containing employee information. The fields are employee id, name and department name. The primary key is a composite one consisting of all three fields. An employee can belong to multiple departments. I want to read/write the objects in the table using the Eclipselink Dynamic Persistence API (which is infact a wrapper on top of JPA descriptors etc.). Example Data: 1 e1 dep1 2 e1 dep2 3 e2 dep1 4 e2 dep3 5 e3 dep1 5 e3 dep2 5 e3 dep3 A normal ReadAllQuery (select query) on the table returns a DynamicEntity corresponding to each row in the table. However I want to club all entities based on the emp id and return all the departments he belongs to as a list. I can merge the entities after retrieving them but if I can use some Eclipselink feature out of the box then it would be better. One way to do the read is the following: I create two dynamic types corresponding to employee: Having id,name as the primary key Having id, department as the primary key, I create a OneToManyMapping from the first type to the second one. Then when I query the first type it does return the departments to which employee belongs as a list of DynamicEntity of the second type. This satisfies the read scenario. Is there a better way of doing this? Is this inherently supported by Eclipselink or JPA? I cannot get the same dynamic type configuration working for the write scenario. This is because when I write the changes using the writeObject method of UnitOfWork, it generates insert queries which enter the following entries in the table id name department 102 emp_102 102 st 102 dep_102 102 dep_102 102 dep_102 instead of: id name department 102 emp_102 st 102 emp_102 dep_102 102 emp_102 dep_102 102 emp_102 dep_102 Is there any way I can get write to work with this schema using eclipselink? I want to avoid doing the heavy lifting of merging the rows for such a denormalized schema or generating each row before doing a write. Is there no clean way of doing this using Eclipselink or JPA? Thanks in Advance.

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