Search Results

Search found 1051 results on 43 pages for 'lebland matlab'.

Page 16/43 | < Previous Page | 12 13 14 15 16 17 18 19 20 21 22 23  | Next Page >

  • Out of memory error while using clusterdata in MATLAB

    - by Hossein
    Hi, I am trying to cluster a Matrix (size: 20057x2).: T = clusterdata(X,cutoff); but I get this error: ??? Error using == pdistmex Out of memory. Type HELP MEMORY for your options. Error in == pdist at 211 Y = pdistmex(X',dist,additionalArg); Error in == linkage at 139 Z = linkagemex(Y,method,pdistArg); Error in == clusterdata at 88 Z = linkage(X,linkageargs{1},pdistargs); Error in == kmeansTest at 2 T = clusterdata(X,1); can someone help me. I have 4GB of ram, but think that the problem is from somewhere else..

    Read the article

  • How to create a function with vectors and vertical asymptote using MATLAB

    - by Pedro J Trinidad
    Plot the function f(x) = 1.5x / x-4 for -10 equal or less than X equal or less than 10. Notice that the function have a vertical asymptote at x = 4. Plot the function by creating two vectors for the domain of x. The first vector (call it x1) with elements from -10 to 3.7, and the second vector (calle it x2) with elements from 4.3 to 10. For each of the X vector create a Y vector (call them y1 and y2) with the corresponding values of Y according to the function. To plot the function make two curves in the same plot (y1 vs. x1 and y2 vs. x2).

    Read the article

  • MATLAB how to write header in text file

    - by Jessy
    How to write a text header in text file? for example in the example below, how to write the header code salay month just once? Code Salary Month 12 1000 12 14 1020 11 11 1212 9 fid = fopen('analysis1.txt','wt'); for i=1:10 array = []; % empty the array .... array = [code salary month]; format short g; fprintf(fid,'%g\t %g\t %g\n',array); % write to file end fclose(fid);

    Read the article

  • Matlab - Propagate points orthogonally on to the edge of shape boundaries

    - by Graham
    Hi I have a set of points which I want to propagate on to the edge of shape boundary defined by a binary image. The shape boundary is defined by a 1px wide white edge. I also have the coordinates of these points stored in a 2 row by n column matrix. The shape forms a concave boundary with no holes within itself made of around 2500 points. I want to cast a ray from each point from the set of points in an orthogonal direction and detect at which point it intersects the shape boundary at. What would be the best method to do this? Are there some sort of ray tracing algorithms that could be used? Or would it be a case of taking orthogonal unit vector and multiplying it by a scalar and testing after multiplication if the end point of the vector is outside the shape boundary. When the end point of the unit vector is outside the shape, just find the point of intersection? Thank you very much in advance for any help!

    Read the article

  • image processing toolbox in matlab

    - by yasuhiro89
    I've got a specific question and a related more general one... Why does imextendedmax() not give for example 9 in A(3,3) as a max? Generally... what is the best way for finding multiple maxes/peaks? The nice thing about imextended max is it allows a threshold where presumably everything under that threshold is not counted whereas imregionalmax and findpeaks are more general, less effective. A=round(rand(5)*10) A = 1 5 4 8 3 5 1 8 8 3 9 3 9 1 2 9 7 3 5 9 6 3 5 6 8 B=imextendedmax(A,8) B = 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

    Read the article

  • Draw a textured triangle (patch) in Matlab

    - by Petter
    I have a triangle in (u,v) coordinates in an image. I would like to draw this triangle at 3D coordinates (X,Y,Z) texture-mapped with the triangle in the image. Here, u,v,X,Y,Z are all vectors with three elements representing the three corners of the triangle. I have a very ugly, slow and insatisfactory solution in which I (1) extract a rectangular part of the image, (2) transform it to 3D space with the transformation defined by the three points, (3) draw it with surface, and (4) finally masking out everything that is not part of the triangle with AlphaData. Surely there must be an easier way of doing this?

    Read the article

  • matlab: figure size, same axis size

    - by Art
    I have a figure with fixed size, like that: hFig = figure(1); set(hFig, 'Position', [200 200 500 500]) But the thing is, that I want to have my AXIS with fixed size (i want them to be a square), not (necessary) the whole figure... - see image attached, Y axis is a bit longer than X axis (of course longer in a meaning of display... X and Y axis range is set to the same value). How to adjust it? Thanks!

    Read the article

  • Matlab: Adding symbols to figure

    - by niko
    Hi, Below is the user interface I have created to simulate LDPC coding and decoding The code sequence is decoded iteratively by passing values between the left and right nodes through the connections. The first thing it would be good to add in order to improve visualization is to add arrows to the connections in the direction of passing values. The alternative is to draw a bigger arrow at the top of the connection showing the direction. Another thing I would like to do is displaying the current mathematical operation below the connection (in this example c * H'). What I don't know how to do is displaying special characters and mathematical symbols and other kinds of text such as subscript and superscript in the figure (for example sum sign and subscript "T" instead of sign ="'" to indicate transposed matrix). I would be very thankful if anyone could point to any useful resources for the questions above or show the solution. Thank you.

    Read the article

  • How to generate random numbers of lognormal distribution within specific range in Matlab

    - by Harpreet
    My grain sizes are defined as D=[1.19,1.00,0.84,0.71,0.59,0.50,0.42]. The problem is described below in steps. Grain sizes should follow lognormal distribution. The mean of the grain sizes is fixed as 0.84 and the standard deviation should be as low as possible but not zero. 90% of the grains (by weight %) fall in the size range of 1.19 to 0.59, and the rest 10% fall in size range of 0.50 to 0.42. Now I want to find the probabilities (weight percentage) of the grains falling in each grain size. It is allowable to split this grain size distribution into further small sizes but it must always be in the range of 1.19 and 0.42, i.e. 'D' can be continuous but 0.42 < D < 1.19. I need it fast. I tried on my own but I am not able to get the correct result. I am getting negative probabilities (weight percentages). Thanks to anyone who helps. I didn't incorporate the point 3 as I came to know about that condition later. Here are simple steps I tried: %% D=[1.19,1.00,0.84,0.71,0.59,0.50,0.42]; s=0.30; % std dev of the lognormal distribution m=0.84; % mean of the lognormal distribution mu=log(m^2/sqrt(s^2+m^2)); % mean of the associated normal dist. sigma=sqrt(log((s^2/m^2)+1)); % std dev of the associated normal dist. [r,c]=size(D); for i=1:c D(i)=mu+(sigma.*randn(1)); w(i)=(log(D(i))-mu)/sigma; % the probability or the wt. percentage of the grain sizes end grain_size=exp(D); %%

    Read the article

  • Automatic annotation for matlab plot?

    - by Tim
    Hi I have quite a few points plotted in a figure. I am now using annotation() function to add annotation in the same way for these points based on their locations. See my previous question. However they tend to mess up where the points are close to each other. Is there some function available to position the annotations as apart as possible? Thanks and regards!

    Read the article

  • two arrays defining 2d coordinates, as array indices, in matlab/octave

    - by Jason
    Hi, I have a 2D array, call it 'A'. I have two other 2D arrays, call them 'ix' and 'iy'. I would like to create an output array whose elements are the elements of A at the index pairs provided by x_idx and y_idx. I can do this with a loop as follows: for i=1:nx for j=1:ny output(i,j) = A(ix(i,j),iy(i,j)); end end How can I do this without the loop? If I do output = A(ix,iy), I get the value of A over the whole range of (ix)X(iy). Thank you, Jason

    Read the article

  • matlab noninteger step indexing

    - by rlbond
    So, I have a vector: k = 1:100; And I want to take 19 elements from it, which are roughly equally-spaced. So I write this: m = k(1:(99/18):end); This works great, except for a tiny problem: Warning: Integer operands are required for colon operator when used as index m = 1 7 12 18 23 29 34 40 45 51 56 62 67 73 78 84 89 95 100 Now, I understand why this comes up, but I'd like to get rid of that warning. Is there a "right" way to do this without a warning?

    Read the article

  • sorting a timer in matlab

    - by AP
    ok it seems like a simple problem, but i am having problem I have a timer for each data set which resets improperly and as a result my timing gets mixed. Any ideas to correct it? without losing any data. Example timer col ideally should be timer , mine reads 1 3 2 4 3 5 4 6 5 1 6 2 how do i change the colum 2 or make a new colum which reads like colum 1 without changing the order of ther rows which have data this is just a example as my file lengths are 86000 long , also i have missing timers which i do not want to miss , this imples no data for that period of time. thanks EDIT: I do not want to change the other columns. The coulm 1 is the gps counter and so it does not sync with the comp timer due to some other issues. I just want to change the row one such that it goes from high to low without effecting other rows. also take care of missing pts ( if i did not care for missing pts simple n=1: max would work.

    Read the article

  • Matlab - applying low-pass filter to a vector?

    - by waitinforatrain
    If I have a simple low-pass filter, e.g. filt = fir1(20, 0.2); and a matrix with a list of numbers (a signal), e.g. [0.1, -0.2, 0.3, -0.4] etc, how do I actually apply the filter I've created to this signal? Seems like a simple question but I've been stuck for hours. Do I need to manually calculate it from the filter coefficients?

    Read the article

  • matlab fit exp2

    - by HelloWorld
    I'm unsuccessfully looking for documentation of fit function using exp2 (sum of 2 exponents). How to operate the function is clear: [curve, gof] = fit(x, y,'exp2'); But since there are multiple ways to fit a sum of exponents I'm trying to find out what algorithm is used. Particularly what happens when I'm fitting one exponent (the raw data) with a bit of noise, how the exponents are spread. I've simulated several cases, and it seems that it "drops" all the weight on the second set of coefficients, but row data analysis often shows different behavior. Does anyone have suggestions of documentation?

    Read the article

  • Pruning data for better viewing on loglog graph - Matlab

    - by Geodesic
    Hi Guys, just wondering if anyone has any ideas about an issue I'm having. I have a fair amount of data that needs to be displayed on one graph. Two theoretical lines that are bold and solid are displayed on top, then 10 experimental data sets that converge to these lines are graphed, each using a different identifier (eg the + or o or a square etc). These graphs are on a log scale that goes up to 1e6. The first few decades of the graph (< 1e3) look fine, but as all the datasets converge ( 1e3) it's really difficult to see what data is what. There's over 1000 data points points per decade which I can prune linearly to an extent, but if I do this too much the lower end of the graph will suffer in resolution. What I'd like to do is prune logarithmically, strongest at the high end, working back to 0. My question is: how can I get a logarithmically scaled index vector rather than a linear one? My initial assumption was that as my data is lenear I could just use a linear index to prune, which lead to something like this (but for all decades): //%grab indicies per decade ind12 = find(y >= 1e1 & y <= 1e2); indlow = find(y < 1e2); indhigh = find(y > 1e4); ind23 = find(y >+ 1e2 & y <= 1e3); ind34 = find(y >+ 1e3 & y <= 1e4); //%We want ind12 indexes in this decade, find spacing tot23 = round(length(ind23)/length(ind12)); tot34 = round(length(ind34)/length(ind12)); //%grab ones to keep ind23keep = ind23(1):tot23:ind23(end); ind34keep = ind34(1):tot34:ind34(end); indnew = [indlow' ind23keep ind34keep indhigh']; loglog(x(indnew), y(indnew)); But this causes the prune to behave in a jumpy fashion obviously. Each decade has the number of points that I'd like, but as it's a linear distribution, the points tend to be clumped at the high end of the decade on the log scale. Any ideas on how I can do this?

    Read the article

  • 'Array of arrays' in matlab?

    - by waitinforatrain
    Hey, having a wee bit of trouble. Trying to assign a variable length 1d array to different values of an array, e.g. a(1) = [1, 0.13,0.52,0.3]; a(2) = [1, 0, .268]; However, I get the error: ??? In an assignment A(I) = B, the number of elements in B and I must be the same. Error in ==> lab2 at 15 a(1) = [1, 0.13,0.52,0.3]; I presume this means that it's expecting a scalar value instead of an array. Does anybody know how to assign the array to this value? I'd rather not define it directly as a 2d array as it is for are doing solutions to different problems in a loop Edit: Got it! a(1,1:4) = [1, 0.13,0.52,0.3]; a(2,1:3) = [1, 0, .268];

    Read the article

  • Problem with assigning elements of a class array to individual variables in MATLAB

    - by Marc
    This is a bit of a duplicate of this question, this question, and this question, however those solutions don't work, so I'm asking mine. I've got an array of locally defined classes and I'd like to assign it to multiple, individual variables. This pattern doesn't work: %a is 2x1 of MyClass temp = mat2cell(a); [x,y] = temp{:}; %throws: ??? Insufficient number of outputs from right hand side of equal sign to satisfy assignment. Because temp is a single cell, with my 2x1 array in one cell, rather than a 2x1 cell array with one element of each of my original array in one cell. Any ideas?

    Read the article

< Previous Page | 12 13 14 15 16 17 18 19 20 21 22 23  | Next Page >