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  • Please suggest me the ( Interaction model of view model) MVVM design in the simple scenario discusse

    - by Jack
    Data Layer I have an Order class as an entity. This Order entity is my model object. Order can be different types, let it be A B C D Also Order class may have common properties like Name, Time of creation, etc. Also based on the order type there are different fields that are not common. View Layer The view contains the following Main Menu ListView The Main Menu contains the drop down menu button which is used to create the order based on the type selected from the drop down. The drop down contains the Order types ( A ,B , C and D). There are different user control based on the order type. Like for example if user chooses to create an order of type A then different view with different inputs field is popped up. Hence, there are four user control for each order type. If user selects A option from the drop down then Order of type A is created and vica versa. Now below is the List View that contains the List of orders so far created by the user. To Edit any particular order user may double click the list view row. Based on the order type clicked by the user in the listview, the view of that order type opens in edit mode. For example if user selects an order type A from the list view then view for order type A open in edit mode. Please suggest me interaction model for view model's in the scenario discussed above. Please excume me if the query is very basic, since I am new new to MVVM and WPF ,

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  • MVC multi page form losing session

    - by Bryan
    I have a multi-page form that's used to collect leads. There are multiple versions of the same form that we call campaigns. Some campaigns are 3 page forms, others are 2 pages, some are 1 page. They all share the same lead model and campaign controller, etc. There is 1 action for controlling the flow of the campaigns, and a separate action for submitting all the lead information into the database. I cannot reproduce this locally, and there are checks in place to ensure users can't skip pages. Session mode is InProc. This runs after every POST action which stores the values in session: protected override void OnActionExecuted(ActionExecutedContext filterContext) { base.OnActionExecuted(filterContext); if (this.Request.RequestType == System.Net.WebRequestMethods.Http.Post && this._Lead != null) ParentStore.Lead = this._Lead; } This is the Lead property within the controller: private Lead _Lead; /// <summary> /// Gets the session stored Lead model. /// </summary> /// <value>The Lead model stored in session.</value> protected Lead Lead { get { if (this._Lead == null) this._Lead = ParentStore.Lead; return this._Lead; } } ParentStore class: public static class ParentStore { internal static Lead Lead { get { return SessionStore.Get<Lead>(Constants.Session.Lead, new Lead()); } set { SessionStore.Set(Constants.Session.Lead, value); } } Campaign POST action: [HttpPost] public virtual ActionResult Campaign(Lead lead, string campaign, int page) { if (this.Session.IsNewSession) return RedirectToAction("Campaign", new { campaign = campaign, page = 0 }); if (ModelState.IsValid == false) return View(GetCampaignView(campaign, page), this.Lead); TrackLead(this.Lead, campaign, page, LeadType.Shared); return RedirectToAction("Campaign", new { campaign = campaign, page = ++page }); } The problem is occuring between the above action, and before the following Submit action executes: [HttpPost] public virtual ActionResult Submit(Lead lead, string campaign, int page) { if (this.Session.IsNewSession || this.Lead.Submitted || !this.LeadExists) return RedirectToAction("Campaign", new { campaign = campaign, page = 0 }); lead.AddCustomQuestions(); MergeLead(campaign, lead, this.AdditionalQuestionsType, false); if (ModelState.IsValid == false) return View(GetCampaignView(campaign, page), this.Lead); var sharedLead = this.Lead.ToSharedLead(Request.Form.ToQueryString(false)); //Error occurs here and sends me an email with whatever values are in the form collection. EAUtility.ProcessLeadProxy.SubmitSharedLead(sharedLead); this.Lead.Submitted = true; VisitorTracker.DisplayConfirmationPixel = true; TrackLead(this.Lead, campaign, page, LeadType.Shared); return RedirectToAction(this.ConfirmationView); } Every visitor to our site gets a unique GUID visitorID. But when these error occurs there is a different visitorID between the Campaign POST and the Submit POST. Because we track each form submission via the TrackLead() method during campaign and submit actions I can see session is being lost between calls, despite the OnActionExecuted firing after every POST and storing the form in session. So when there are errors, we get half the form under one visitorID and the remainder of the form under a different visitorID. Luckily we use a third party service which sends an API call every time a form value changes which uses it's own ID. These IDs are consistent between the first half of the form, and the remainder of the form, and the only way I can save the leads from the lost session issues. I should also note that this works fine 99% of the time. EDIT: I've modified my code to explicitly store my lead object in TempData and used the TempData.Keep() method to persist the object between subsequent requests. I've only deployed this behavior to 1 of my 3 sites but so far so good. I had also tried storing my lead objects in Session directly in the controller action i.e., Session.Add("lead", this._Lead); which uses HTTPSessionStateBase, attempting to circumvent the wrapper class, instead of HttpContext.Current.Session which uses HTTPSessionState. This modification made no difference on the issue, as expected.

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  • CodeIgniter: Can't load database from within a model

    - by thedp
    Hello, I've written a new model for my CodeIgniter framework. I'm trying to load the database from within the constructor function, but I'm getting the following error: Severity: Notice Message: Undefined property: userdb::$load Filename: models/userdb.php Line Number: 7 Fatal error: Call to a member function database() on a non-object in /var/www/abc/system/application/models/userdb.php on line 7 Here is my model: <?php class userdb extends Model { function __construct() { $this->load->database(); } ?> What am I doing wrong here? Thank you.

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  • ASP.NET MVC model binding foreign key relationship

    - by Rory Fitzpatrick
    Is it possible to bind a foreign key relationship on my model to a form input? Say I have a one-to-many relationship between Car and Manufacturer. I want to have a form for updating Car that includes a select input for setting Manufacturer. I was hoping to be able to do this using the built-in model binding, but I'm starting to think I'll have to do it myself. My action method signature looks like this: public JsonResult Save(int id, [Bind(Include="Name, Description, Manufacturer")]Car car) The form posts the values Name, Description and Manufacturer, where Manufacturer is a primary key of type int. Name and Description get set properly, but not Manufacturer, which makes sense since the model binder has no idea what the PK field is. Does that mean I would have to write a custom IModelBinder that it aware of this? I'm not sure how that would work since my data access repositories are loaded through an IoC container on each Controller constructor.

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  • Default value for field in Django model

    - by Daniel Garcia
    Suppose I have a model: class SomeModel(models.Model): id = models.AutoField(primary_key=True) a = models.IntegerField(max_length=10) b = models.CharField(max_length=7) Currently I am using the default admin to create/edit objects of this type. How do I set the field 'a' to have the same number as id? (default=???) Other question Suppose I have a model: event_date = models.DateTimeField( null=True) year = models.IntegerField( null=True) month = models.CharField(max_length=50, null=True) day = models.IntegerField( null=True) How can i set the year, month and day fields by default to be the same as event_date field?

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  • MVC: Model View Controller -- does the View call the Model?

    - by Gary Green
    I've been reading about MVC design for a while now and it seems officially the View calls objects and methods in the Model, builds and outputs a view. I think this is mainly wrong. The Controller should act and retrieve/update objects inside the Model, select an appropriate View and pass the information to it so it may display. Only crude and rudiementary PHP variables/simple if statements should appear inside the View. If the View gets the information it needs to display from the Model, surely there will be a lot of PHP inside the View -- completely violating the point of seperating presentation logic.

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  • Filtering model results for Django admin select box

    - by blcArmadillo
    I just started playing with Django today and so far am finding it rather difficult to do simple things. What I'm struggling with right now is filtering a list of status types. The StatusTypes model is: class StatusTypes(models.Model): status = models.CharField(max_length=50) type = models.IntegerField() def __unicode__(self): return self.status class Meta: db_table = u'status_types' In one admin page I need all the results where type = 0 and in another I'll need all the results where type = 1 so I can't just limit it from within the model. How would I go about doing this?

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  • Codeigniter: Retrieving a variable from Model to use in a Controller

    - by Craig Ward
    Hi, I bet this is easy but been trying for a while and can't seem to get it to work. Basically I am setting up pagination and in the model below I want to pass $total_rows to my controller so I can add it to the config like so '$config['total_rows'] = $total_rows;'. function get_timeline_filter($per_page, $offset, $source) { $this->db->where('source', $source); $this->db->order_by("date", "desc"); $q = $this->db->get('timeline', $per_page, $offset); $total_rows = $this->db->count_all_results(); if($q->num_rows() >0) { foreach ($q->result() as $row) { $data[] = $row; } return $data; } } I understand how to pass things form the Controller to the model using $this->example_model->example($something); but not sure how to get a variable from the model?

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  • QAbstractTableModel as a model for one QTableView and few QListViews

    - by ??????
    community. Briefly. I wrote usual model over QAbstractTableModel and using it in usual way for QTableView. But I think I need to use some columns of this model for the few QListViews in QWizard to fill main table in the right way (for user). For example: use the column2 as the QListView's model on the page1 of the wizard; column3 for page2 for its QListView etc. Please, help me to understand just two things: Am I on the right way? If yes then how can I make it simply and explicitly?

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  • Specialization hierarchy in a domain-model

    - by devoured elysium
    I'm trying to make the domain model of a management system. I have the following kinds of persons in this system: employee manager top mananger I decided to define a User, from where employee, manager and top manager will specialize from. What I don't know is what kind of specialization hierarchy I should choose from. I thought of two ways: or Which might be preferable and why? As a long time coder, every time I try to do a domain-model, I have to fight against the idea of trying to think in how I'm going to code this. From what I've understood, I should not think about those matters in the domain-model, only in object relationships. I don't have to think of code duplication or any of these kind of details here, so I can't really pick any of the options over the other. Thanks

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  • Rails - building an absolute url in a model's virtual attribute without url helper

    - by Nick
    I have a model that has paperclip attachments. The model might be used in multiple rails apps I need to return a full (non-relative) url to the attachment as part of a JSON API being consumed elsewhere. I'd like to abstract the paperclip aspect and have a simple virtual attribute like this: def thumbnail_url self.photo.url(:thumb) end This however only gives me the relative path. Since it's in the model I can't use the URL helper methods, right? What would be a good approach to prepending the application root url since I don't have helper support? I would like to avoid hardcoding something or adding code to the controller method that assembles my JSON. Thank you

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  • ASP.Net Layered app - Share Entity Data Model amongst layers

    - by Chris Klepeis
    How can I share the auto-generated entity data model (generated object classes) amongst all layers of my C# web app whilst only granting query access in the data layer? This uses the typical 3 layer approach: data, business, presentation. My data layer returns an IEnumerable<T> to my business layer, but I cannot return type T to the presentation layer because I do not want the presentation layer to know of the existence of the data layer - which is where the entity framework auto-generated my classes. It was recommended to have a seperate layer with just the data model, but I'm unsure how to seperate the data model from the query functionality the entity framework provides.

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  • How to pass parameters to report model in Reporting Services

    - by savras
    I'm developing report in RS that show top N customers based on some criteria. It also allows to select number of customers and period of time. Is it possible to do it by using report model? Thing that it seems to be difficult is how to pass parameters determined by user. Another thing that in my oppinion is very disappointing is that i cannot use SQL query as dataset query, because it uses odd and elaborate XML. Although report model items seem to map its fields to query or table fields. I m concerning using report models because i need to provide uniform data model (the same tables and fields) for more or less different database schemas. It would be very nice if somebody would explain what can be done with report models and what can not.

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  • dynamic model is not loading fields

    - by Toby Justus
    I am using a dynamic model found on the forum of sencha. function modelFactory(name, fields) { alert(fields); return Ext.define(name, { extend: 'Ext.data.Model', fields: fields }); } I placed the alert(fields) to check what happens with the field because it was not working. I get this: [object Object],[object Object],[object Object] How can i change this into a correct way to use it in the fields? Is there a way to check if the model has been created? With Firebug or something? EDIT: i get this in firebug: [Object { name="ccuDesignation", type=null}, Object { name="wanNumber", type=null}, Object { name="carrierName", type=null}, Object { name="dataPackageName", type=null}, Object { name="simIccid", type=null}, Object { name="expiryTime", type=null}, Object { name="bytesRx", type=null}, Object { name="bytesTx", type=null}]

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  • Problem with altering model attributes in controller

    - by SpawnCxy
    Hi all, Today I've got a problem when I tried using following code to alter the model attribute in the controller function userlist($trigger = 1) { if($trigger == 1) { $this->User->useTable = 'betausers'; //'betausers' is completely the same structure as table 'users' } $users = $this->User->find('all'); debug($users); } And the model file is class User extends AppModel { var $name = "User"; //var $useTable = 'betausers'; function beforeFind() //only for debug { debug($this->useTable); } } The debug message in the model showed the userTable attribute had been changed to betausers.And It was supposed to show all records in table betausers.However,I still got the data in the users,which quite confused me.And I hope someone can show me some directions to solve this problem. Regards

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  • Rails Model for Playlist that can contain tracks and albums using polymorphism

    - by philk
    I struggle to find a model how to store a playlist with different type of items on it in Rails. Consider I have class Track end class Album has_many :tracks end class PlaylistItem belongs_to :playable belongs_to :playlist end class Playable belongs_to :playable, :polymorph => true end class Playlist has_many :playlist_items end I think I can use a polymorphic model "Playable" here since the Playlist can contain Tracks, Albums and maybe in the future also Movies. Also I would like to use STI for Track and Albums since they share some common attributes like title and length but also have totally different attributes. I modeled it like described here but it does not work. Anybody any idea how to model a Playlist that can contain many items of different kind?

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  • Exposing a "dumbed-down", read-only instance of a Model in GAE

    - by Blixt
    Does anyone know a clever way, in Google App Engine, to return a wrapped Model instance that only exposes a few of the original properties, and does not allow saving the instance back to the datastore? I'm not looking for ways of actually enforcing these rules, obviously it'll still be possible to change the instance by digging through its __dict__ etc. I just want a way to avoid accidental exposure/changing of data. My initial thought was to do this (I want to do this for a public version of a User model): class ReadOnlyUser(db.Model): display_name = db.StringProperty() @classmethod def kind(cls): return 'User' def put(self): raise SomeError() Unfortunately, GAE maps the kind to a class early on, so if I do ReadOnlyUser.get_by_id(1) I will actually get a User instance back, not a ReadOnlyUser instance.

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  • Can I change the datsource of report model at runtime

    - by Manab De
    I've some adhoc reports developed on some report models which are published on Report Server (we're using SSRS 2008). Everything is running well. Now in our production environment we've near about forty (40) customers who have their own database (each have the same table structures and other database objects). Now the challenge is whenever a customer will log into the report server using windows authentication and trying to view those reports we need to get the SQL data from the proper database only. Reports are designed using the report model and each model has a valid data source which is connected to particular database. We can create forty separate data sources each will be connected to specific database. My question is, is there any way through which we can change the report model data source name dynamically or during runtime based on the customer name so that during execution of the report, SSRS would fetch the data from the correct database but not from any other database. Please help me.

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  • How to send complete POST to Model in Code Igniter

    - by Constant M
    Hi there, What would be the best way to send a complete post to a model in Code Igniter? Methods I know are as follow: Name form elements as array, eg. <input type="text" name="contact[name]"> <input type="text" name="contact[surname]"> and then use: $this->Model_name->add_contact($this->input->post('contact')); The other would be to add each element to an array and then send it to the model as such: <input type="text" name="name"> <input type="text" name="surname"> and $contact_array = array('name' => $this->input->post('name'), 'surname' => $this->input->post('surname')); $this->Model_name->add_contact($this->input->post('contact')); Which one of these would be best practice, and is there a way to directly send a whole POST to a model (or a whole form maybe?)

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