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  • Binary Search Tree in C

    - by heapzero
    Hi, I'm a Python guy. Learning C language and I've been trying to implement Binary Search Tree in C. I wrote down the code, and I've been trying from few hours but, not able to get the output as expected. Please help! Please correct me. #include<stdlib.h> #include<stdio.h> typedef int ElementType; typedef struct TreeNode { ElementType element; struct TreeNode *left, *right; } TreeNode; TreeNode *createTree(){ //Create the root of tree TreeNode *tempNode; tempNode = malloc(sizeof(TreeNode)); tempNode->element = 0; tempNode->left = NULL; tempNode->right = NULL; return tempNode; } TreeNode *createNode(ElementType X){ //Create a new leaf node and return the pointer TreeNode *tempNode; tempNode = malloc(sizeof(TreeNode)); tempNode->element = X; tempNode->left = NULL; tempNode->right = NULL; return tempNode; } TreeNode *insertElement(TreeNode *node, ElementType X){ //insert element to Tree if(node==NULL){ return createNode(X); } else{ if(X < node->element){ node->left = insertElement(node->left, X); } else if(X > node->element){ node->right = insertElement(node->right, X); } else if(X == node->element){ printf("Oops! the element is already present in the tree."); } } } TreeNode *displayTree(TreeNode *node){ //display the full tree if(node==NULL){ return; } displayTree(node->left); printf("| %d ", node->element); displayTree(node->right); } main(){ //pointer to root of tree #2 TreeNode *TreePtr; TreeNode *TreeRoot; TreeNode *TreeChild; //Create the root of tree TreePtr = createTree(); TreeRoot = TreePtr; TreeRoot->element = 32; printf("%d\n",TreeRoot->element); insertElement(TreeRoot, 8); TreeChild = TreeRoot->left; printf("%d\n",TreeChild->element); insertElement(TreeRoot, 2); insertElement(TreeRoot, 7); insertElement(TreeRoot, 42); insertElement(TreeRoot, 28); insertElement(TreeRoot, 1); insertElement(TreeRoot, 4); insertElement(TreeRoot, 5); // the output is not as expected :( displayTree(TreeRoot); }

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  • Algorithm to Render a Horizontal Binary-ish Tree in Text/ASCII form

    - by Justin L.
    It's a pretty normal binary tree, except for the fact that one of the nodes may be empty. I'd like to find a way to output it in a horizontal way (that is, the root node is on the left and expands to the right). I've had some experience expanding trees vertically (root node at the top, expanding downwards), but I'm not sure where to start, in this case. Preferably, it would follow these couple of rules: If a node has only one child, it can be skipped as redundant (an "end node", with no children, is always displayed) All nodes of the same depth must be aligned vertically; all nodes must be to the right of all less-deep nodes and to the left of all deeper nodes. Nodes have a string representation which includes their depth. Each "end node" has its own unique line; that is, the number of lines is the number of end nodes in the tree, and when an end node is on a line, there may be nothing else on that line after that end node. As a consequence of the last rule, the root node should be in either the top left or the bottom left corner; top left is preferred. For example, this is a valid tree, with six end nodes (node is represented by a name, and its depth): [a0]------------[b3]------[c5]------[d8] \ \ \----------[e9] \ \----[f5] \--[g1]--------[h4]------[i6] \ \--------------------[j10] \-[k3] Which represents the horizontal, explicit binary tree: 0 a / \ 1 g * / \ \ 2 * * * / \ \ 3 k * b / / \ 4 h * * / \ \ \ 5 * * f c / \ / \ 6 * i * * / / \ 7 * * * / / \ 8 * * d / / 9 * e / 10 j (branches folded for compactness; * representing redundant, one-child nodes; note that *'s are actual nodes, storing one child each, just with names omitted here for presentation sake) (also, to clarify, I'd like to generate the first, horizontal tree; not this vertical tree) I say language-agnostic because I'm just looking for an algorithm; I say ruby because I'm eventually going to have to implement it in ruby anyway. Assume that each Node data structure stores only its id, a left node, and a right node. A master Tree class keeps tracks of all nodes and has adequate algorithms to find: A node's nth ancestor A node's nth descendant The generation of a node The lowest common ancestor of two given nodes Anyone have any ideas of where I could start? Should I go for the recursive approach? Iterative?

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  • How can I convert this PHP script to Ruby? (build tree from tabbed string)

    - by Jon Sunrays
    I found this script below online, and I'm wondering how I can do the same thing with a Ruby on Rails setup. So, first off, I ran this command: rails g model Node node_id:integer title:string Given this set up, how can I make a tree from a tabbed string like the following? <?php // Make sure to have "Academia" be root node with nodeID of 1 $data = " Social sciences Anthropology Biological anthropology Forensic anthropology Gene-culture coevolution Human behavioral ecology Human evolution Medical anthropology Paleoanthropology Population genetics Primatology Anthropological linguistics Synchronic linguistics (or Descriptive linguistics) Diachronic linguistics (or Historical linguistics) Ethnolinguistics Sociolinguistics Cultural anthropology Anthropology of religion Economic anthropology Ethnography Ethnohistory Ethnology Ethnomusicology Folklore Mythology Political anthropology Psychological anthropology Archaeology ...(goes on for a long time) "; //echo "Checkpoint 2\n"; $lines = preg_split("/\n/", $data); $parentids = array(0 => null); $db = new PDO("host", 'username', 'pass'); $sql = 'INSERT INTO `TreeNode` SET ParentID = ?, Title = ?'; $stmt = $db->prepare($sql); foreach ($lines as $line) { if (!preg_match('/^([\s]*)(.*)$/', $line, $m)) { continue; } $spaces = strlen($m[1]); //$level = intval($spaces / 4); //assumes four spaces per indent $level = strlen($m[1]); // if data is tab indented $title = $m[2]; $parentid = ($level > 0 ? $parentids[$level - 1] : 1); //All "roots" are children of "Academia" which has an ID of "1"; $rv = $stmt->execute(array($parentid, $title)); $parentids[$level] = $db->lastInsertId(); echo "inserted $parentid - " . $parentid . " title: " . $title . "\n"; } ?>

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  • How do I force all Tree itemrenderers to refresh?

    - by Richard Haven
    I have item renderers in an mx.controls.Tree that I need to refresh on demand. I have code in the updateDisplayList that fires for only some of the visible nodes no matter what I do. I've tried triggering a change that they should all be listening for; I have tried clearing and resetting the dataProvider and the itemRenderer properties. private function forceCategoryTreeRefresh(event : Event = null) : void { trace("forceCategoryTreeRefresh"); var prevDataProvider : Object = CategoryTree.dataProvider; CategoryTree.dataProvider = null; CategoryTree.validateNow(); CategoryTree.dataProvider = prevDataProvider; var prevItemRenderer : IFactory = CategoryTree.itemRenderer; CategoryTree.itemRenderer = null; CategoryTree.itemRenderer = prevItemRenderer as IFactory; _categoriesChangeDispatcher.dispatchEvent(new Event(Event.CHANGE)); } The nodes refresh properly when I scroll them into view (e.g. the .data gets set), but I cannot force the ones that already exist to refresh or reset themselves. Any ideas?

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  • How to find sum of node's value for given depth in binary tree?

    - by masato-san
    I've been scratching my head for several hours for this... problem: Binary Tree (0) depth 0 / \ 10 20 depth 1 / \ / \ 30 40 50 60 depth 2 I am trying to write a function that takes depth as argument and return the sum of values of nodes of the given depth. For instance, if I pass 2, it should return 180 (i.e. 30+40+50+60) I decided to use breath first search and when I find the node with desired depth, sum up the value, but I just can't figure out how to find out the way which node is in what depth. But with this approach I feel like going to totally wrong direction. function level_order($root, $targetDepth) { $q = new Queue(); $q->enqueue($root); while(!$q->isEmpty) { //how to determin the depth of the node??? $node = $q->dequeue(); if($currentDepth == $targetDepth) { $sum = $node->value; } if($node->left != null) { $q->enqueue($node->left); } if($node->right != null) { $q->enqueue($node->right); } //need to reset this somehow $currentDepth ++; } }

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  • Approaches to create a nested tree structure of NSDictionaries?

    - by d11wtq
    I'm parsing some input which produces a tree structure containing NSDictionary instances on the branches and NSString instance at the nodes. After parsing, the whole structure should be immutable. I feel like I'm jumping through hoops to create the structure and then make sure it's immutable when it's returned from my method. We can probably all relate to the input I'm parsing, since it's a query string from a URL. In a string like this: a=foo&b=bar&a=zip We expect a structure like this: NSDictionary { "a" => NSDictionary { 0 => "foo", 1 => "zip" }, "b" => "bar" } I'm keeping it just two-dimensional in this example for brevity, though in the real-world we sometimes see var[key1][key2]=value&var[key1][key3]=value2 type structures. The code hasn't evolved that far just yet. Currently I do this: - (NSDictionary *)parseQuery:(NSString *)queryString { NSMutableDictionary *params = [NSMutableDictionary dictionary]; NSArray *pairs = [queryString componentsSeparatedByString:@"&"]; for (NSString *pair in pairs) { NSRange eqRange = [pair rangeOfString:@"="]; NSString *key; id value; // If the parameter is a key without a specified value if (eqRange.location == NSNotFound) { key = [pair stringByReplacingPercentEscapesUsingEncoding:NSASCIIStringEncoding]; value = @""; } else { // Else determine both key and value key = [[pair substringToIndex:eqRange.location] stringByReplacingPercentEscapesUsingEncoding:NSASCIIStringEncoding]; if ([pair length] > eqRange.location + 1) { value = [[pair substringFromIndex:eqRange.location + 1] stringByReplacingPercentEscapesUsingEncoding:NSASCIIStringEncoding]; } else { value = @""; } } // Parameter already exists, it must be a dictionary if (nil != [params objectForKey:key]) { id existingValue = [params objectForKey:key]; if (![existingValue isKindOfClass:[NSDictionary class]]) { value = [NSDictionary dictionaryWithObjectsAndKeys:existingValue, [NSNumber numberWithInt:0], value, [NSNumber numberWithInt:1], nil]; } else { // FIXME: There must be a more elegant way to build a nested dictionary where the end result is immutable? NSMutableDictionary *newValue = [NSMutableDictionary dictionaryWithDictionary:existingValue]; [newValue setObject:value forKey:[NSNumber numberWithInt:[newValue count]]]; value = [NSDictionary dictionaryWithDictionary:newValue]; } } [params setObject:value forKey:key]; } return [NSDictionary dictionaryWithDictionary:params]; } If you look at the bit where I've added FIXME it feels awfully clumsy, pulling out the existing dictionary, creating an immutable version of it, adding the new value, then creating an immutable dictionary from that to set back in place. Expensive and unnecessary? I'm not sure if there are any Cocoa-specific design patterns I can follow here?

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  • How do I add a default namespace with no prefix using XMLSerializer

    - by OldBob
    Hi Using C# and .Net 3.5; I am trying to generate an XML document that contains the default namespace without a prefix using XMLSerializer. eg. <?xml version="1.0" encoding="utf-8" ?> <MyRecord ID="9266" xmlns="http://www.website.com/MyRecord"> <List> <SpecificItem> using the following code string xmlizedString = null; MemoryStream memoryStream = new MemoryStream(); XmlSerializer xs = new XmlSerializer(typeof(ExportMyRecord)); XmlSerializerNamespaces xmlnsEmpty = new XmlSerializerNamespaces(); xmlnsEmpty.Add(string.Empty, string.Empty); XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8); xs.Serialize(xmlTextWriter, myRecord, xmlnsEmpty); memoryStream = (MemoryStream)xmlTextWriter.BaseStream; xmlizedString = this.UTF8ByteArrayToString(memoryStream.ToArray()); and class structure [Serializable] [XmlRoot("MyRecord")] public class ExportMyRecord { [XmlAttribute("ID")] public int ID { get; set; } Now, I've tried various options XmlSerializer xs = new XmlSerializer(typeof(ExportMyRecord),"http://www.website.com/MyRecord"); or [XmlRoot(Namespace = "http://www.website.com/MyRecord", ElementName="MyRecord")] gives me <?xml version="1.0" encoding="utf-8"?> <q1:MylRecord ID="9266" xmlns:q1="http://www.website.com/MyRecord"> <q1:List> <q1:SpecificItem> I need the XML to have the namespace without the prefix as it's going to a third party provider and they reject all other alternatives. Any suggestions? No responses so far. Has anyone experienced this or know how to solve it?

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  • Grails - Language prefix in url mappings

    - by Art79
    Hi there im having problem with language mappings. The way i want it to work is that language is encoded in the url like /appname/de/mycontroller/whatever If you go to /appname/mycontroller/action it should check your session and if there is no session pick language based on browser preference and redirect to the language prefixed site. If you have session then it will display english. English does not have en prefix (to make it harder). So i created mappings like this: class UrlMappings { static mappings = { "/$lang/$controller/$action?/$id?"{ constraints { lang(matches:/pl|en/) } } "/$lang/store/$category" { controller = "storeItem" action = "index" constraints { lang(matches:/pl|en/) } } "/$lang/store" { controller = "storeItem" action = "index" constraints { lang(matches:/pl|en/) } } "/$controller/$action?/$id?"{ lang="en" constraints { } } "/store/$category" { lang="en" controller = "storeItem" action = "index" } "/store" { lang="en" controller = "storeItem" action = "index" } "/"(view:"/index") "500"(view:'/error') } } Its not fully working and langs are hardcoded just for now. I think i did something wrong. Some of the reverse mappings work but some dont add language. If i use link tag and pass params:[lang:'pl'] then it works but if i add params:[lang:'pl', page:2] then it does not. In the second case both lang and page number become parameters in the query string. What is worse they dont affect the locale so page shows in english. Can anyone please point me to the documentation what are the rules of reverse mappings or even better how to implement such language prefix in a good way ? THANKS

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  • Java reading xml element without prefix but within the scope of a namespace

    - by wsxedc
    Functionally, the two blocks should be the same <soapenv:Body> <ns1:login xmlns:ns1="urn:soap.sof.com"> <userInfo> <username>superuser</username> <password>qapass</password> </userInfo> </ns1:login> </soapenv:Body> ----------------------- <soapenv:Body> <ns1:login xmlns:ns1="urn:soap.sof.com"> <ns1:userInfo> <ns1:username>superuser</ns1:username> <ns1:password>qapass</ns1:password> </ns1:userInfo> </ns1:login> </soapenv:Body> However, how when I read using AXIS2 and I have tested it with java6 as well, I am having a problem. MessageFactory factory = MessageFactory.newInstance(); SOAPMessage soapMsg = factory.createMessage(new MimeHeaders(), SimpleTest.class.getResourceAsStream("LoginSoap.xml")); SOAPBody body = soapMsg.getSOAPBody(); NodeList nodeList = body.getElementsByTagNameNS("urn:soap.sof.com", "login"); System.out.println("Try to get login element" + nodeList.getLength()); // I can get the login element Node item = nodeList.item(0); NodeList elementsByTagNameNS = ((Element)item).getElementsByTagNameNS("urn:soap.sof.com", "username"); System.out.println("try to get username element " + elementsByTagNameNS.getLength()); So if I replace the 2nd getElementsByTagNameNS with ((Element)item).getElementsByTagName("username");, I am able to get the username element. Doesn't username have ns1 namespace even though it doesn't have the prefix? Am I suppose to keep track of the namespace scope to read an element? Wouldn't it became nasty if my xml elements are many level deep? Is there a workaround where I can read the element in ns1 namespace without knowing whether a prefix is defined?

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  • Parsing XML elements with dynamic namespace prefix in PHP

    - by BugKiller
    I have the following XML ( you can say SOAP request ) : <SOAPENV:Envelope xmlns:SOAPENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:NS="http://xyz.gov/headerschema" > <SOAPENV:Header> <NS:myHeader> <NS:SourceID>223423</NS:SourceID> </NS:myHeader> </SOAPENV:Header> </SOAPENV:Envelope> I use the following code and it works fine : <?php $myRequest ='<SOAPENV:Envelope xmlns:SOAPENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:NS="http://xyz.gov/headerschema" > <SOAPENV:Header> <NS:myHeader> <NS:SourceID>223423</NS:SourceID> </NS:myHeader> </SOAPENV:Header> </SOAPENV:Envelope>'; $xml = simplexml_load_string($myRequest, NULL, NULL, "http://schemas.xmlsoap.org/soap/envelope/"); $namespaces = $xml->getNameSpaces(true); $soapHeader = $xml->children($namespaces['SOAPENV'])->Header; $myHeader = $soapHeader->children($namespaces['NS'])->myHeader; echo (string)$myHeader->SourceID; ?> The Problem I know the prefix ( SOAPENV + NS ) , but the clients could change the prefix to whatever they want, so they may send me xml document that has ( MY-SOAPENV + MY-NS) prefixes. My Question How can I handle this since the namespace prefixes are not static , how can I parse it ? Thanks

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  • How to structure classes in the filesystem?

    - by da_b0uncer
    I have a few (view) classes. Table, Tree, PagingColumn, SelectionColumn, SparkLineColumn, TimeColumn. currently they're flat under app/view like this: app/view/Table app/view/Tree app/view/PagingColumn ... I thought about restructuring it, because the Trees and Tables use the columns, but there are some columns, which only work in a tree, some who work in trees and tables and in the future there are probably some who only work in tables, I don't know. My first idea was like this: app/view/Table app/view/Tree app/view/column/PagingColumn app/view/column/SelectionColumn app/view/column/SparkLineColumn app/view/column/TimeColumn But since the SelectionColumn is explicitly for trees, I have the fear that future developers could get the idea of missuse them. But how to restructure it probably? Like this: app/view/table/panel/Table app/view/tree/panel/Tree app/view/tree/column/PagingColumn app/view/tree/column/SelectionColumn app/view/column/SparkLineColumn app/view/column/TimeColumn Or like this: app/view/Table app/view/Tree app/view/column/SparkLineColumn app/view/column/TimeColumn app/view/column/tree/PagingColumn app/view/column/tree/SelectionColumn

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  • Prefix files with the current directory name using Powershell

    - by XST
    I have folders with images (*.png and *.jpg) >C:\Directory\Folder1 01.png 02.png 03.jpg 04.jpg 05.png And I want to rename all the files like this using powershell: >C:\Directory\Folder1 Folder1 - 01.png Folder1 - 02.png Folder1 - 03.jpg Folder1 - 04.jpg Folder1 - 05.png So I came up with this simple line: Get-ChildItem | Where-Object { $_.Extension -eq ".jpg" -or $_.Extension -eq ".png"} | rename-item -newname {$_.Directory.Name +" - " + $_.Name} If I have 35 or less files in the folder, I will have the wanted result, but if there is 36 or more files, I will end up with this: >C:\Directory\Folder1 Folder1Folder1Folder1 - 01.png Folder1Folder1Folder1 - 02.png Folder1Folder1Folder1 - 03.jpg Folder1Folder1Folder1 - 04.jpg Folder1Folder1Folder1 - 05.png The loop stops when the file's name exceeds 248 characters. Any ideas why it's looping?

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  • Apache mod_rewrite redirect with prefix

    - by Marc
    I am newbie with Apache's mod_rewrite and I'm having some difficulties getting it to do what I want. In my static directory, I have some javascript files (.js) with 2 kind of filename: xxxx.js which is the standard file name AT_xxxx.js (with prefixed filename) which has been duplicated from previous standard file name but also contains my customizations I would like to parse requests for each standard requested javascript file (xxxx.js) to check if a customized file exists (AT_xxxx.js) including all sub-directories. Then, in this case, use the custom file instead of the standard file (perhaps by internal redirect). I tried to figure this out for hours but something is still wrong. Note: Also, I don't know how to find custom files in sub-directories. DocumentRoot "/data/apps/dev0/custom/my_static" <filesMatch "\\.(js)$"> Options +FollowSymLinks RewriteEngine on RewriteCond %{DOCUMENT_ROOT}/AT_$1.js -f RewriteRule ^(.*[^/])/?$ %{DOCUMENT_ROOT}/AT_$1.js [QSA,L] </filesMatch>

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  • Cygwin and zsh: removing "path prefix line"

    - by Viktor
    I've installed Cygwin under Windows 7 and I've added the line exec zsh -l to C:\cygwin\home\Viktor\.bash_profile. Problem is I still get that ugly new line for every command I write: (Viktor@INET)[2] ~ $ cd D: (Viktor@INET)[3] /cygdrive/d $ ls $RECYCLE.BIN Program Files (x86) System Volume Information Viktor xampp (Viktor@INET)[4] /cygdrive/d $ _ As horizontal space is no concern with 1920 pixels I would like to have the "Linux appearance", something like this viktor@inet> _ or whatever is default. One command shouldn't take three lines. And how do I change the colors? Edit. I also have Console2 installed, which I have set to use Cygwin, if that's any help.

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  • --prefix to /usr/local or /opt?

    - by Paul Alexander
    For building apps from source like git or rails I've seen recommendations to install in both /opt or /usr/local. From what I've read so for, the designated use for both is about the same and it amounts to merely a style issue. Is there any practical difference? Best practices?

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  • Problem with mydomain.com no prefix

    - by user10711
    Short question is. I have a domain name mydomain.com, we have a company website hosted on an IIS server 2003 configuration. Going to the address bar and typing www.mydomain.com will show my website properly. Typing mydomain.com into the same address bar will return an under construction website that seems to be hosted on my webserver. My domain name is hosted by Network Solutions, and I think I have it configured correctly using their advanced DNS services. In their settings I have www.mydomain.com, * and @ also pointed to the ip address of my webserver. On my webserver itself using the IIS manager, under the Web Site, and Web Site Identification. I have configured both www.mydomain.com and mydomain.com configured to work on the IP address on the webserver. I am hosting 4 different websites on my IIS server, all the other sites use prefixes other than www, an example is mail.mydomain.com and a couple of others. None of them show an under construction page as their default homepage. I am really at a loss as to why it would show an under construction page, especially since it seems to be pointing to the correct server. The reason this is such a big deal is because when you search for my company on google, the link there is for mydomain.com and by clicking on the link it shows under construction which is really quite embarrassing. Thanks in advance for any help and if there are further questions let me know.

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  • Register Internet-Exploerer Adress Prefix like: dial://0011123456789

    - by hkda150
    Hi there, I want to ... use individual links that start a program with given parameters using the Internet Explorer. Normal link: http://www.google.com Adjusted link calling a registered program: dial://0011123456789 A popular example for this mechanism is eDonkey. eDonkey Links look similar to this one: e2dk://mydownload:500232 Do you have any suggestion on how to register programs using the Internet Explorer? Any help is very appreciated.

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  • Register Internet-Explorer Address Prefix like: dial://0011123456789

    - by hkda150
    Hi there, I want to ... use individual links that start a program with given parameters using the Internet Explorer. Normal link: http://www.google.com Adjusted link calling a registered program: dial://0011123456789 A popular example for this mechanism is eDonkey. eDonkey Links look similar to this one: e2dk://mydownload:500232 Do you have any suggestion on how to register programs using the Internet Explorer? Any help is very appreciated.

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  • load syntax as per file prefix

    - by Richo
    Firstly, I hope that this is the right place. I couldn't decide between here and superuser. My home directory lives in an svn repo. all my dotfiles are in version control so that I can track them across multiple machines, and they all source an unversioned .local (ie, .screenrc.local, .vimrc.local etc) which can override/make local changes to the environment in a machine specific way. The problem is that vim understands how I want to edit many of these config files, but loses it's mind when I open a .local, and honestly, I'm not really sure what it does to work out how to syntax highlight etc a file like .screenrc the pseudocode for what I'm after is: if OpenedFile.ends_with(".local") behave_as_per OpenedFile[0:-6] endif I hope this makes sense and hopefully someone can shed light on whether or not this is possible.

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  • Objective-C Xcode: Prefix.pch question?

    - by Johannes Jensen
    I have two files independant on each other. Let's just call it Class1 and Class2. In Class1, I need Class2, and in Class2 I need Class1. I have a prefix file where I include all my files, and I get some syntax errors because I do #import "Class1.h" #import "Class2.h" How would I define both of them so they can use each other? What am I doing wrong?

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  • Pseudo LRU tree algorithm.

    - by patros
    A lot of descriptions of Pseudo LRU algorithms involve using a binary search tree, and setting flags to "point away" from the node you're searching for every time you access the tree. This leads to a reasonable approximation of LRU. However, it seems from the descriptions that all of the nodes deemed LRU would be leaf nodes. Is there a pseudo-LRU algorithm that deals with a static tree that will still perform reasonably well, while determining that non-leaf nodes are suitable LRU candidates?

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  • gunit syntax for tree walker with a flat list of nodes

    - by Kaleb Pederson
    Here's a simple gunit test for a portion of my tree grammar which generates a flat list of nodes: objectOption walks objectOption: <<one:"value">> -> (one "value") Although you define a tree in ANTLR's rewrite syntax using a caret (i.e. ^(ROOT child...)), gunit matches trees without the caret, so the above represents a tree and it's not surprising that it fails: it's a flat list of nodes and not a tree. This results in a test failure: 1 failures found: test2 (objectOption walks objectOption, line17) - expected: (one \"value\") actual: one \"value\" Another option which seems intuitive is to leave off the parenthesis, like this: objectOption walks objectOption: <<one:"value">> -> one "value" But gunit doesn't like this syntax. It seems to result in a parse failure in the gunit grammar: line 17:20 no viable alternative at input 'one' line 17:24 missing ':' at 'value' line 0:-1 no viable alternative at input '<EOF>' java.lang.NullPointerException at org.antlr.gunit.OutputTest.getExpected(OutputTest.java:65) at org.antlr.gunit.gUnitExecutor.executeTests(gUnitExecutor.java:245) ... What is the correct way to match a flat tree?

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  • Parsing a given binary tree using python?

    - by kaushik
    Parse a binary tree,referring to given set of features,answering decision tree question at each node to decide left child or right child and find the path to leaf node according to answer given to the decision tree.. input wil be a set of feature which wil help in answering the question at each level to choose the left or right half and the output will be the leaf node.. i need help in implementing this can anyone suggest methods?? Please answer... thanks in advance..

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