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  • Google says: Sort parameters in URL problematic

    - by feklee
    From Google's recommendations for URL structure: Sorting parameters. Some large shopping sites provide multiple ways to sort the same items, resulting in a much greater number of URLs. For example: http://www.example.com/results?search_type=search_videos&search_query=tpb&search_sort=relevance&search_category=25" When linking from outside, then having URLs differing only by sort parameters is obviously a bad idea: Google will not understand that these links point to the same item, i.e. that the item is popular. Therefore ranking will be lower than it should. But what's the alternative? Using a fragment identifier (#), and then doing the sorting in JavaScript? What else? Some settings in Webmaster tools?

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  • Variable function name Javascript.

    - by Vladimir
    I'm sorting array: myArray.sort(comparators.some_comparator); and I have several comparator to choose from: comparators = { asc_firstname_comparator : function(o1, o2){ ... } desc_firstname_comparator : function(o1, o2){ ... } etc... } I want to write function which returns certain comparator depending on input data. It should figure out comparator from string inputs, something like this: function chooseComparator(field, order){ return "comparators."+order+"_"+field+"_comparator"; } So is it possible to pass only function name string to sort() method or I'll need to pass reference to correct comparator somehow?

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  • Sort collection within collection using Linq

    - by user327066
    Hi, I have a one-to-many Linq query and I would like to sort on a property within the "many" collection. For example in the pseudo-code below, I am returned a List from the Linq query but I would like to sort / order the Products property based on the SequenceNumber property of the Product class. How can I do this? Any information is appreciated. Thanks. class Order { int OrderId; List<Product> Products; } class Product { string name; int SequenceNumber; }

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  • Sort Java List/Map by order in which items are in an XML File

    - by Brandon Smith
    Hello everyone, What I'm looking to do is to sorta a Java List or Map in the order the items are in a XML File. For Example I have a list of function names as so: functionOne functionThree functionTwo The XML File looks like this: <xml> <function>functionOne</function> <function>functionTwo</function> <function>functionThree</function> </xml> So I would like to sort the list so the function names are as so: functionOne functionTwo functionThree Now Im trying to do this for Variables as well, so there are around 500+ unique 'items'. Does anyone have any idea how I can go about doing this? Now for the file that determines that sort order doesn't have to be XML it just what I use the most, it can be anything that can get the job done. Thanks in advance for your time.

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  • Quick-sort doesn't work with middle pivot element

    - by Bobby
    I am trying to sort an array of elements using quick-sort algorithm.But I am not sure where am I going wrong.I choose the middle element as pivot every time and then I am checking the conditions.Here is my code below. void quicksort(int *temp,int p,int r) { if(r>p+1) { int mid=(p+r)/2; int piv=temp[mid]; int left=p+1; int right=r; while(left < right) { if(temp[left]<=piv) left++; else swap(&temp[left],&temp[--right]); } swap(&temp[--left],&temp[p]); quicksort(temp,p,left); quicksort(temp,right,r); } }

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  • Python sort 2-D list by time string

    - by Mark Kennedy
    How do I sort a multi dimensional list like this based on a time string? The sublists can be of different sizes (i.e. 4 and 5, here) I want to sort by comparing the first time string in each sublist (sublist[-4]) x = (['1513', '08:19PM', '10:21PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['0690', '07:25AM', '09:19AM', 1, 4], ['0201', '08:50AM', '10:50AM', 1, 4], ['1166', '04:35PM', '06:36PM', 1, 4], ['0845', '05:40PM', '07:44PM', 1, 4], ['1267', '07:05PM', '09:07PM', 1, 4], ['1513', '08:19PM', '10:21PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['8772', '0159', '12:33PM', '02:43PM', 1, 5], ['0888', '0570', '09:42PM', '12:20AM', 1, 5], ['2086', '2231', '04:10PM', '06:20PM', 1, 5]) The sorted result would be sortedX = (['0690', '07:25AM', '09:19AM', 1, 4], ['0201', '08:50AM', '10:50AM', 1, 4], ['1166', '04:35PM', '06:36PM', 1, 4], ['0845', '05:40PM', '07:44PM', 1, 4], ['1267', '07:05PM', '09:07PM', 1, 4], ['1513', '08:19PM', '10:21PM', 1, 4], ['1513', '08:19PM', '10:21PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['8772', '0159', '12:33PM', '02:43PM', 1, 5], ['2086', '2231', '04:10PM', '06:20PM', 1, 5], ['0888', '0570', '09:42PM', '12:20AM', 1, 5]) I tried the following: sortedX = sorted(x, key=lambda k : k[-4]) #k[-4] is the first time string and it works but it doesn't respect the sublist size ordering

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  • Rails 3 ActiveRecord group_by sort by count

    - by Craig
    The following view code generates a series of links with totals (as expected): <% @jobs.group_by(&:employer_name).sort.each do |employer, jobs| %> <%= link_to employer, jobs_path() %> <%= "(#{jobs.length})" %> <% end %> However, when I refactor the view's code and move the logic to a helper, the code doesn't work as expect. view: <%= employer_filter(@jobs_clone) %> helper: def employer_filter(jobs) jobs.group_by(&:employer_name).sort.each do |employer,jobs| link_to employer, jobs_path() end end The following output is generated: <Job:0x10342e628>#<Job:0x10342e588>#<Job:0x10342e2e0>Employer A#<Job:0x10342e1c8>Employer B#<Job:0x10342e0d8>Employer C#<Job:0x10342ded0>Employer D# What am I not understanding? At first blush, the code seems to be equivalent.

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  • please help me to implement such kind of sort

    - by davit-datuashvili
    hi i need to write sucj kind of sorting maybe it is similary to radix sort and also (this is not homework because i created it problem myself and please if anobody can help me) problem is like this suppose i have array int x[]=new int[]{4,5,3,2,1}; let write it into binary form 5 -0101 4- 0100 3-0011 2-0010 1-0001 i want to sort this elements by using bitwise operatos or check each bit and if less exchange it can anybody help me for example take 5 and 4 check first rightmost bit 0==0 so continue in the 1 index also 1==1 next the same 0=0 and last one 10 it means that first element is greater then second so exchange it please help me

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  • C++ struct sorting error

    - by Betamoo
    I am trying to sort a vector of custom struct in C++ struct Book{ public:int H,W,V,i; }; with a simple functor class CompareHeight { public: int operator() (Book lhs,Book rhs) { return lhs.H-rhs.H; } }; when trying : vector<Book> books(X); ..... sort(books.begin(),books.end(), CompareHeight()); it gives me exception "invalid operator <" What is the meaning of this error? Thanks

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  • Force an array to recalcuate length after sort

    - by Rhyono
    If you take an array and do the following: arr = []; arr[100] = 1; The length will be 101, which makes sense due to 0-99 being set as undefined Now if we sort that array: arr.sort() it will look like this: [1, undefined x100] since keys are not preserved. However, the length is still 101, since the undefined have all been moved to the end, instead of removed. Is this behavior intentional and if so: is there a built-in function that removes undefined and recalculates and why is it intentional? I am not asking how to write my own function to recalculate length. A sorted array's length can easily be forced with for (x = 0; arr[x] != undefined; x++);arr.length = x;

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  • Sort List based on dynamically generated numbers in C++

    - by user367322
    I have a list of objects ("Move"'s in this case) that I want to sort based on their calculated evaluation. So, I have the List, and a bunch of numbers that are "associated" with an element in the list. I now want to sort the List elements with the first element having the lowest associated number, and the last having the highest. Once the items are order I can discard the associated number. How do I do this? This is what my code looks like (kind've): list<Move> moves = board.getLegalMoves(board.turn); for(i = moves.begin(); i != moves.end(); ++i) { //... a = max; // <-- number associated with current Move }

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  • How to sort & Group in Android?

    - by crickpatel0024
    I have ArrayList and I want to sort and group all data by header in Android. How it is possible in Android? please help me.below me from owner And set header Me And Joe Manager From owner And set Header in listview. How to do that in Android? My code in below:: public class Request extends Activity { private String assosiatetoken; private ArrayList<All_Request_data_dto> list = new ArrayList<All_Request_data_dto>(); ListView lv; Button back; private Spinner spndata; String[] reqspinner = { "Request Date", "Last Update", "Type", "Owner", "State" }; ArrayAdapter<String> adapter; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.request); assosiatetoken = MyApplication.getToken(); new doinbackground(this).execute(); back = (Button) findViewById(R.id.button1); spndata = (Spinner) findViewById(R.id.list_all_quize_req); adapter = new ArrayAdapter<String>(this, android.R.layout.simple_spinner_item, reqspinner); spndata.setAdapter(adapter); lv = (ListView) findViewById(R.id.listrequestdata); lv.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView<?> a, View v, int position, long id) { Intent edit = new Intent(Request.this, Request_webview.class); // edit.putExtra("Cat_url", url_link); startActivity(edit); } }); spndata.setOnItemSelectedListener(new OnItemSelectedListener() { public void onItemSelected(AdapterView<?> arg0, View arg1, int position, long arg3) { switch (position) { case 0: list = DBAdpter.requestUserData(assosiatetoken); Collections.sort(list, byDate1); // Collections.reverse(list); for (int i = 0; i < list.size(); i++) { if (list.get(i).submitDate != null) { lv.setAdapter(new MyListAdapter( getApplicationContext(), list)); } } break; case 1: list = DBAdpter.requestUserData(assosiatetoken); Collections.sort(list, byDate); for (int i = 0; i < list.size(); i++) { if (list.get(i).lastModifiedDate != null) { lv.setAdapter(new MyListAdapter( getApplicationContext(), list)); } } break; case 2: list = DBAdpter.requestUserData(assosiatetoken); Collections.sort(list, byDate3); // Collections.reverse(list); for (int i = 0; i < list.size(); i++) { if (list.get(i).state != null) { lv.setAdapter(new MyListAdapter( getApplicationContext(), list)); } } break; case 3: list = DBAdpter.requestUserData(assosiatetoken); for (int i = 0; i < list.size(); i++) { lv.setAdapter(new MyListAdapter( getApplicationContext(), list)); } break; default: break; } } public void onNothingSelected(AdapterView<?> arg0) { } }); back.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { finish(); } }); } static final Comparator<All_Request_data_dto> byDate = new Comparator<All_Request_data_dto>() { SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy hh:mm:ss a"); public int compare(All_Request_data_dto ord1, All_Request_data_dto ord2) { java.util.Date d1 = null; java.util.Date d2 = null; try { d1 = sdf.parse(ord1.lastModifiedDate); d2 = sdf.parse(ord2.lastModifiedDate); } catch (java.text.ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } return (d1.getTime() > d2.getTime() ? -1 : 1); // descending // return (d1.getTime() > d2.getTime() ? 1 : -1); //ascending } }; static final Comparator<All_Request_data_dto> byDate1 = new Comparator<All_Request_data_dto>() { SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy hh:mm:ss a"); public int compare(All_Request_data_dto ord1, All_Request_data_dto ord2) { java.util.Date d1 = null; java.util.Date d2 = null; try { d1 = sdf.parse(ord1.submitDate); d2 = sdf.parse(ord2.submitDate); } catch (java.text.ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } return (d1.getTime() > d2.getTime() ? -1 : 1); // descending // return (d1.getTime() > d2.getTime() ? 1 : -1); //ascending } }; static final Comparator<All_Request_data_dto> byDate3 = new Comparator<All_Request_data_dto>() { public int compare(All_Request_data_dto ord1, All_Request_data_dto ord2) { String d1 = null; String d2 = null; d1 = ord1.state; d2 = ord2.state; return d1.compareToIgnoreCase(d2); } }; class doinbackground extends AsyncTask<Void, Void, Void> { ProgressDialog pd; private Context ctx; public doinbackground(Context c) { ctx = c; } @Override protected void onPreExecute() { super.onPreExecute(); pd = new ProgressDialog(ctx); pd.setMessage("Loading..."); pd.show(); } @Override protected Void doInBackground(Void... Params) { return null; } @Override protected void onPostExecute(Void result) { super.onPostExecute(result); pd.cancel(); } } public class MyListAdapter extends BaseAdapter { private ArrayList<All_Request_data_dto> list; public MyListAdapter(Context mContext, ArrayList<All_Request_data_dto> list) { this.list = list; } public int getCount() { return list.size(); } public All_Request_data_dto getItem(int position) { return list.get(position); } public long getItemId(int position) { return position; } public View getView(int position, View convertView, ViewGroup parent) { // if (convertView == null) { LayoutInflater inflator = (LayoutInflater) getSystemService(LAYOUT_INFLATER_SERVICE); convertView = inflator.inflate(R.layout.custom_request_data, null); TextView req_id = (TextView) convertView.findViewById(R.id.req_txt); TextView date = (TextView) convertView.findViewById(R.id.date_txt); TextView owner = (TextView) convertView .findViewById(R.id.owner_txt); TextView state = (TextView) convertView .findViewById(R.id.state_txt); req_id.setText(list.get(position).requestId + " - " + list.get(position).title); date.setText(list.get(position).lastModifiedDate + " - " + list.get(position).submitDate); owner.setText(list.get(position).owner); state.setText(list.get(position).state); // } return convertView; } } }

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  • How can I sort Windows 7 control panel by columns, not rows

    - by user26453
    As best as I can tell the behavior of Windows 7's control panel is as follows: When Large Icons or Small Icons display modes are used, the icons are sorted alphabetically. However they are ordered by row: a b c d e f g h as opposed to what I usually expect in any file browser: a d g b e h c f Why is this the one part of Windows 7 that behaves this way and is there any way to change this behavior?

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  • Is there a blog tool with support for tagging posts, only displaying posts with certain combinations

    - by Philip
    What I want: A blog. I can tag posts, e.g. "A" or "B" or "all," and then you can either 1) click to only view posts tagged "A" or "all" or 2) even more ideally, I can set it so you automatically see posts tagged "A" or "all" when you log in. LaTeX support--I can type in LaTeX in the editor and it will show the math properly. No anonymous anything--must sign up and be logged in to view and comment Not as important, but convenient: Admin controls, e.g. detailed statistics, see who posts or views what when, control who posts / views, etc. Hosting: Ideally, if there's some software I can install on "my" own server, that would be ideal. But if we can't host it, it'd still be good to find some free (or maybe even paid) service elsewhere that would host the blog if it provided those tools. Any thoughts? I have no experience with this. Thanks!

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  • How can I sort out Xephyr's keyboard mapping?

    - by qedi
    When I start up Xephyr inside of X, my keyboard map becomes wonky mostly just for non-printing characters. I can't use arrow keys. According to xev, The down arrow gets mapped to Super_R. The up arrow is Print Screen. PgDown is mapped to "Menu". My keyboard works fine in the original X display (:0), but in the Xephyr subdisplay (:1), nothing else quite works right. I don't have any funky xmodmap things going on in my main X display that I'm aware of. All I really do is setxkbmap -option ctrl:swapcaps.

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  • What sort of attack URL is this?

    - by Asker
    I set up a website with my own custom PHP code. It appears that people from places like Ukraine are trying to hack it. They're trying a bunch of odd accesses, seemingly to detect what PHP files I've got. They've discovered that I have PHP files called mail.php and sendmail.php, for instance. They've tried a bunch of GET options like: http://mydomain.com/index.php?do=/user/register/ http://mydomain.com/index.php?app=core&module=global§ion=login http://mydomain.com/index.php?act=Login&CODE=00 I suppose these all pertain to something like LiveJournal? Here's what's odd, and the subject of my question. They're trying this URL: http://mydomain.com?3e3ea140 What kind of website is vulnerable to a 32-bit hex number?

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  • Sort results in Google.

    - by atch
    Guys is there a way to have results from Google displayed in predefined order? Like for example the newest at the top? Very often I'm looking for some new information on C++0x and I would like to have results sorted in that way. Thank you.

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  • Command-line sort and copy text files to one single file renders an error

    - by user169997
    I stumbled on question 217394 which explains how to copy files sorted alphabetically into one single file. Trying to implement the command myself rendered the following error message: The system cannot find the file specified. The command I am trying to run is here: for /f %i in ('dir /a-d /o-n /b O:\OrdersExport\Order*.txt') do @type %i C:\Users\Admin\Documents\OrderImport.txt The error does not appear if I browsed to the folder in question first: C:\O: C:\cd OrdersImport I simply want one line to copy from destination to that single file. By the way, if it matters, O: is a mapped folder over network

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  • Best way to manually sort random text files?

    - by Jane
    I have about 1000 text files and I need to view each, and move it to a folder if it's the correct one. I can only do basic sorting by length/size, and I can't grep because the text is random. How can I do this besides manually openiing + saving each in gedit. I'm on Ubuntu Linux. Thanks

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  • How to do complex port forwarding (sort of)

    - by adnan kamili
    I have a very different situation. My laptop named A, another machine B(ip-172.16.28.3) with ssh server installed and i have an account on that machine, the third machine C(ip-172.16.24.3) is a proxy server. All the machines are within a LAN, but 1- Machine B can connect to A as well as C 2- Machine A i.e.my pc, it can only connect to B and not C Now to use internet, i do the following: ssh -X [email protected] Then i type firefox and i use the firefox of machine B with proxy setings as 172.16.24.3:3128 Instead of using firefox of B, i want to use my local firefox. Is there a way through which i can connect to C via B and use my local firefox for browsing

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  • Sort-of Software Raid-1 on windows?

    - by ricardowong
    I have 2 windows vista computers on a lan, can i set them up with a program so that they replicate the data written in one partition to another and the other way around. basically replicating data across 2 partitions whenever each is modified. Making that data is available on the network when either of the computers are turned on, when both are, data is synchronized. Is this posible?

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  • Perfectly reproducable select statement default ordering issue....

    - by Dave
    Hi, I've recently been chasing an issue with a client's db... solution found, but impossible to recreate. Essentially, we're doing a Select * from mytable where ArbitraryColumn = 75 Where MyTable has an Identity column, called 'MyIndentityColumn' - incremented by one in each insert. Naturally, and normally I would assume that the order returned would be the order in which they are inserted (bad assumption, but one which was forced onto me, through an inherited application - which has been patched). Essentially, I would like suggestions as to why the database, when restored to my local machine (same OS, same SQL server version - 200 sp3) same collation, and same backup instance restored on it, as a test DB on the client site. When I perform the above select, I get them in order of insert (i.e. identity column ordered ascending). On the client, it seems random (but the same 'random' order each time)... A few other points: I have the same collation on my test server as client Same DB backup restored to a test only I can access Same SQL server version and service pack Same OS Test DB is a new DB - new log and MDF... I have the problem 'solved' by adding an explicit order by clause but I want to undertand the cause of the issue, given the exact nature of my attempts to recreate it beuing futile, and perfectly recreatable on the client server... Thanks in advance, Dave

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  • Gmail: sort emails on last conversation date

    - by Edoode
    I'm using Gmail (for domains) When viewing the inbox, converations are sorted by their 'last activity', usualy an email. However, when I view all conversations of a single label, by clicking the label in the box left on the screen, mails are ordered by first activity. Can anyone confirm this, and does anyone know how I can change this behaviour?

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