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  • Email attachment problem

    - by Alan Harris-Reid
    Hi there, I want to send an email with an attachment using the following code (Python 3.1) (greatly simplified to show the example) from email.mime.multipart import MIMEMultipart from email.mime.text import MIMEText msg = MIMEMultipart() msg['From'] = from_addr msg['To'] = to_addr msg['Subject'] = subject msg.attach(MIMEText(body)) fp = open(att_file) msg1 = MIMEText(fp.read()) attachment = msg1.add_header('Content-Disposition', 'attachment', filename=att_file) msg.attach(attachment) # set string to be sent as 3rd parameter to smptlib.SMTP.sendmail() send_string = msg.as_string() The attachment object msg1 returns 'email.mime.text.MIMEText' object at ', but when the msg1.add_header(...) line runs the result is None, hence the program falls-over in msg.as_string() because no part of the attachment can have a None value. (Traceback shows "'NoneType' object has no attribute 'get_content_maintype'" in line 118 of _dispatch in generator.py, many levels down from msg.as_string()) Has anyone any idea what the cause of the problem might be? Any help would be appreciated. Alan Harris-Reid

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  • Install TurboGears on windows xp

    - by coder
    I've been trying to get TurboGears installed on Windows by following this site. I've installed virtualenv but when I execute the command "virtualenv --no-site-packages testproj", I get the following message: New python executable in testproj\Scripts\python.exe Traceback (most recent call last): File "C:\Python26\Scripts\virtualenv-script.py", line 8, in load_entry_point('virtualenv==1.4.5', 'console_scripts', 'virtualenv')() File "C:\Python26\lib\site-packages\virtualenv-1.4.5-py2.6.egg\virtualenv.py", line 529, in main use_distribute=options.use_distribute) File "C:\Python26\lib\site-packages\virtualenv-1.4.5-py2.6.egg\virtualenv.py", line 612, in create_environment site_packages=site_packages, clear=clear)) File "C:\Python26\lib\site-packages\virtualenv-1.4.5-py2.6.egg\virtualenv.py", line 837, in install_python stdout=subprocess.PIPE) File "C:\Python26\lib\subprocess.py", line 621, in __init__ errread, errwrite) File "C:\Python26\lib\subprocess.py", line 830, in _execute_child startupinfo) WindowsError: [Error 14001] This application has failed to start because the application configuration is incorrect. Reinstalling the application may fix this problem Can someone help me debug this ? If any one knows a better tutorial to install turbogears, please let me know.

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  • How to log python exception ?

    - by Maxim Veksler
    Hi, Coming from java, being familiar with logback I used to do try { ... catch (Exception e) { log("Error at X", e); } I would like the same functionality of being able to log the exception and the stacktrace into a file. How would you recommend me implementing this? Currently using boto logging infrastructre, boto.log.info(...) I've looked at some options and found out I can access the actual exception details using this code: import sys try: 1/0 except: exc_type, exc_value, exc_traceback = sys.exc_info() traceback.print_exception(exc_type, exc_value, exc_traceback) I would like to somehow get the string print_exception() throws to stdout so that I can log it. Thank you, Maxim.

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  • Python IDLE: How to type correct indentation?

    - by user2988464
    Mac: Maverick Python: 3.4 I tried to testtimeit module in Python's IDLE import timeit >>> timeit.timeit( "obj.method", """ class SomeClass: def method(self): pass obj = SomeClass() """) When I tried to type def method(self): on the next line of class SomeClass, I hit Tab, it prompted a window showing the files inside my Document directory. So I hit Ctrl+Tab instead. But I still got the error: Traceback (most recent call last): File "<pyshell#26>", line 6, in <module> """) File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/timeit.py", line 213, in timeit return Timer(stmt, setup, timer).timeit(number) File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/timeit.py", line 122, in __init__ code = compile(src, dummy_src_name, "exec") File "<timeit-src>", line 9 _t0 = _timer() ^ IndentationError: unindent does not match any outer indentation level Can someone explain: how to fix it, and how to avoid the prompt of My Document appear? Thx!!!

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  • django sending emails

    - by dotty
    Hay, i can't seem to send emails using send_mail(), and I'm not sure why. Here's my details settins.py EMAIL_HOST = 'localhost', EMAIL_PORT = 25 My view from django.core.mail import send_mail send_mail('Subject here', 'Here is the message.', '[email protected]', ['[email protected]'], fail_silently=False) This fails with the error getaddrinfo() argument 1 must be string or None Anyone have any ideas? I'm developing on OS X Leopard Heres the last traceback /System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/smtplib.py in connect for res in socket.getaddrinfo(host, port, 0, socket.SOCK_STREAM): ... ? Local vars Variable Value host ('localhost',) msg 'getaddrinfo returns an empty list' port 25 self <smtplib.SMTP instance at 0x153b1e8>

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  • metaclass multiple inheritance inconsistency

    - by Matt Anderson
    Why is this: class MyType(type): def __init__(cls, name, bases, attrs): print 'created', cls class MyMixin: __metaclass__ = MyType class MyList(list, MyMixin): pass okay, and works as expected: created <class '__main__.MyMixin'> created <class '__main__.MyList'> But this: class MyType(type): def __init__(cls, name, bases, attrs): print 'created', cls class MyMixin: __metaclass__ = MyType class MyObject(object, MyMixin): pass Is not okay, and blows up thusly?: created <class '__main__.MyMixin'> Traceback (most recent call last): File "/tmp/junk.py", line 11, in <module> class MyObject(object, MyMixin): pass TypeError: Error when calling the metaclass bases Cannot create a consistent method resolution order (MRO) for bases object, MyMixin

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  • Converting python objects for rpy2

    - by bgbg
    The following code is supposed to created a heatmap in rpy2 import numpy as np from rpy2.robjects import r data = np.random.random((10,10)) r.heatmap(data) However, it results in the following error Traceback (most recent call last): File "z.py", line 8, in <module> labRow=rowNames, labCol=colNames) File "C:\Python25\lib\site-packages\rpy2\robjects\__init__.py", line 418, in __call__ new_args = [conversion.py2ri(a) for a in args] File "C:\Python25\lib\site-packages\rpy2\robjects\__init__.py", line 93, in default_py2ri raise(ValueError("Nothing can be done for the type %s at the moment." %(type(o)))) ValueError: Nothing can be done for the type <type 'numpy.ndarray'> at the moment. From the documentation I learn that r.heatmap expects "a numeric matrix". How do I convert np.array to the required data type?

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  • How come string.maketrans does not work in Python 3.1?

    - by ShaChris23
    I'm a Python newbie. How come this doesn't work in Python 3.1? from string import maketrans # Required to call maketrans function. intab = "aeiou" outtab = "12345" trantab = maketrans(intab, outtab) str = "this is string example....wow!!!"; print str.translate(trantab); When I executed the above code, I get the following instead: Traceback (most recent call last): File "<pyshell#119>", line 1, in <module> transtab = maketrans(intab, outtab) File "/Library/Frameworks/Python.framework/Versions/3.1/lib/python3.1/string.py", line 60, in maketrans raise TypeError("maketrans arguments must be bytes objects") TypeError: maketrans arguments must be bytes objects What does "must be bytes objects" mean? Could anyone please help post a working code for Python 3.1 if it's possible?

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  • __getattr__ on a module

    - by Matt Joiner
    How can implement the equivalent of a __getattr__ on a class, on a module? Example When calling a function that does not exist in a module's statically defined attributes, I wish to create an instance of a class in that module, and invoke the method on it with the same name as failed in the attribute lookup on the module. class A(object): def salutation(self, accusative): print "hello", accusative def __getattr__(mod, name): return getattr(A(), name) if __name__ == "__main__": salutation("world") Which gives: matt@stanley:~/Desktop$ python getattrmod.py Traceback (most recent call last): File "getattrmod.py", line 9, in <module> salutation("world") NameError: name 'salutation' is not defined Evidently something is not right about my assumed implementation.

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  • I keep Getting KeyError: 'tried' Whenever I Tried to Run Django Dev Server from Remote Machine

    - by Spikie
    I am running django on python2.6.1, and did start the django web server like this manage.py runserver 192.0.0.1:8000 then tried to connect to the django dev web server on http://192.0.0.1:8000/ keep getting this message on the remote computer Traceback (most recent call last): File "C:\Python26\Lib\site-packages\django\core\servers\basehttp.py", line 279, in run self.result = application(self.environ, self.start_response) File "C:\Python26\Lib\site-packages\django\core\servers\basehttp.py", line 651, in call return self.application(environ, start_response) File "C:\Python26\lib\site-packages\django\core\handlers\wsgi.py", line 241, in call response = self.get_response(request) File "C:\Python26\lib\site-packages\django\core\handlers\base.py", line 115, in get_response return debug.technical_404_response(request, e) File "C:\Python26\Lib\site-packages\django\views\debug.py", line 247, in technical_404_response tried = exception.args[0]['tried'] KeyError: 'tried' what i am doing wrong ? it seen to work ok if i run http://192.0.0.1:8000/ on the computer that runs the Django web server and have that ip 192.0.0.1:8000

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  • [Gdata] GetAuthSubToken returns None

    - by Matt
    Hey guys, I am a little lost on how to get the auth token. Here is the code I am using on the return from authorizing my app: client = gdata.service.GDataService() gdata.alt.appengine.run_on_appengine(client) sessionToken = gdata.auth.extract_auth_sub_token_from_url(self.request.uri) client.UpgradeToSessionToken(sessionToken) logging.info(client.GetAuthSubToken()) what gets logged is "None" so that does seem right :-( if I use this: temp = client.upgrade_to_session_token(sessionToken) logging.info(dump(temp)) I get this: {'scopes': ['http://www.google.com/calendar/feeds/'], 'auth_header': 'AuthSub token=CNKe7drpFRDzp8uVARjD-s-wAg'} so I can see that I am getting a AuthSub Token and I guess I could just parse that and grab the token but that doesn't seem like the way things should work. If I try to use AuthSubTokenInfo I get this: Traceback (most recent call last): File "/Applications/GoogleAppEngineLauncher.app/Contents/Resources/GoogleAppEngine-default.bundle/Contents/Resources/google_appengine/google/appengine/ext/webapp/__init__.py", line 507, in __call__ handler.get(*groups) File "controllers/indexController.py", line 47, in get logging.info(client.AuthSubTokenInfo()) File "/Users/matthusby/Dropbox/appengine/projects/FBCal/gdata/service.py", line 938, in AuthSubTokenInfo token = self.token_store.find_token(scopes[0]) TypeError: 'NoneType' object is unsubscriptable so it looks like my token_store is not getting filled in correctly, is that something I should be doing? Also I am using gdata 2.0.9 Thanks Matt

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  • installing simplejson on the google appengine

    - by user266564
    Super nub question time! I am trying to use simplejson on the google appengine. In a terminal on my machine I have simplejson installed and working. But my when I try to import it in a script running on the appengine I get an error saying no such library exists. If open the interactive console on my machine (from the link on http://localhost:8080/_ah/admin) and type "import simplejson" I get: Traceback (most recent call last): File "/home/chris/google_appengine/google/appengine/ext/admin/init.py", line 210, in post exec(compiled_code, globals()) File "", line 1, in ImportError: No module named simplejson Any thoughts?

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  • Python encoding for pipe.communicate

    - by Brian M. Hunt
    I'm calling pipe.communicate from Python's subprocess module from Python 2.6. I get the following error from this code: from subprocess import Popen pipe = Popen(cwd) pipe.communicate( data ) For an arbitrary cwd, and where data that contains unicode (specifically 0xE9): Exec. exception: 'ascii' codec can't encode character u'\xe9' in position 507: ordinal not in range(128) Traceback (most recent call last): ... stdout, stderr = pipe.communicate( data ) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/subprocess.py", line 671, in communicate return self._communicate(input) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/subprocess.py", line 1177, in _communicate bytes_written = os.write(self.stdin.fileno(), chunk) This is happening, I presume, because pipe.communicate() is expecting ASCII encoded string, but data is unicode. Is this the problem I'm encountering, and i sthere a way to pass unicode to pipe.communicate()? Thank you for reading! Brian

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  • Exception_Record in python2.5 problem

    - by amir
    I'm using Python2.5 & the following code produce 2 errors. Can any body help me? class EXCEPTION_RECORD(Structure): _fields_ = [ ("ExceptionCode", DWORD), ("ExceptionFlags", DWORD), ("ExceptionRecord", POINTER(EXCEPTION_RECORD)), ("ExceptionAddress", LPVOID), ("NumberParameters", DWORD), ("ExceptionInformation", ULONG_PTR * EXCEPTION_MAXIMUM_PARAMETERS)] Python Error: Traceback (most recent call last): File "E:\Python25\my_debugger_defines.py", line 70, in <module> class EXCEPTION_RECORD(Structure): File "E:\Python25\my_debugger_defines.py", line 74, in EXCEPTION_RECORD ("ExceptionRecord", POINTER(EXCEPTION_RECORD)), NameError: name 'EXCEPTION_RECORD' is not defined Microsoft Document: The EXCEPTION_RECORD structure describes an exception. typedef struct _EXCEPTION_RECORD { // exr DWORD ExceptionCode; DWORD ExceptionFlags; struct _EXCEPTION_RECORD *ExceptionRecord; PVOID ExceptionAddress; DWORD NumberParameters; DWORD ExceptionInformation[EXCEPTION_MAXIMUM_PARAMETERS]; } EXCEPTION_RECORD; Thanks in advance

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  • fd.seek() IOError: [Errno 22] Invalid argument

    - by Julian Kessel
    My Python Interpreter (v2.6.5) raises the above error in the following codepart: fd = open("some_filename", "r") fd.seek(-2, os.SEEK_END) #same happens if you exchange the second arg. w/ 2 data=fd.read(2); last call is fd.seek() Traceback (most recent call last): File "bot.py", line 250, in <module> fd.seek(iterator, os.SEEK_END); IOError: [Errno 22] Invalid argument The strange thing with this is that the exception occurs just when executing my entire code, not if only the specific part with the file opening. At the runtime of this part of code, the opened file definitely exists, disk is not full, the variable "iterator" contains a correct value like in the first codeblock. What could be my mistake? Thanks in advance

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  • Python nested function scopes

    - by Thomas O
    I have code like this: def write_postcodes(self): """Write postcodes database. Write data to file pointer. Data is ordered. Initially index pages are written, grouping postcodes by the first three characters, allowing for faster searching.""" status("POSTCODE", "Preparing to sort...", 0, 1) # This function returns the key of x whilst updating the displayed # status of the sort. ctr = 0 def keyfunc(x): ctr += 1 status("POSTCODE", "Sorting postcodes", ctr, len(self.postcodes)) return x sort_res = self.postcodes[:] sort_res.sort(key=keyfunc) But ctr responds with a NameError: Traceback (most recent call last): File "PostcodeWriter.py", line 53, in <module> w.write_postcodes() File "PostcodeWriter.py", line 47, in write_postcodes sort_res.sort(key=keyfunc) File "PostcodeWriter.py", line 43, in keyfunc ctr += 1 UnboundLocalError: local variable 'ctr' referenced before assignment How can I fix this? I thought nester scopes would have allowed me to do this. I've tried with 'global', but it still doesn't work.

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  • Loading Files in AppEngine

    - by Chris M
    I've got a tiny bit of code to display a file in app.yaml - url: /(.*\.(gif|png|jpg)) static_files: static/\1 upload: static/(.*\.(gif|png|jpg)) in main.py ... class ShowImage(webapp.RequestHandler): def get(self): rootpath = os.path.dirname(__file__) file = rootpath + "/static/tracker.gif"; fh=open(file, 'r') self.response.out.write(fh.read()) fh.close ... I can see the files gone up by going to my *.appspot.com/tracker.gif (as per the app.yaml) But using *.appspot.com/showimage returns Traceback (most recent call last): File "/base/python_lib/versions/1/google/appengine/ext/webapp/__init__.py", line 510, in __call__ handler.get(*groups) File "/base/data/home/apps/APPNAME/2.341131266814384624/main.py", line 170, in get fh=open(file, 'r') IOError: [Errno 2] No such file or directory: '/base/data/home/apps/APPNAME/2.341131266814384624/static/tracker.gif'

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  • how to get obj2.name via obj1.categories(), thanks (gae python)

    - by zjm1126
    i using google-app-engine webapp ,code is : class Post(db.Model): title = db.StringProperty(required=True) def categories(self): return (x.category for x in self.postcategory_set) class Category(db.Model): name = db.StringProperty() class PostCategory(db.Model): post = db.ReferenceProperty(Post) category = db.ReferenceProperty(Category) class sss(webapp.RequestHandler): def get(self): obj1 = Post(title='hhaa') #obj1.title = 'haha' obj1.put() obj2 = Category() obj2.name='haha-kao' obj2.put() obj3=PostCategory() obj3.post=obj1 obj3.category=obj2 obj3.put() self.response.out.write(obj1.categories().get().name) the error is : Traceback (most recent call last): File "D:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 511, in __call__ handler.get(*groups) File "D:\zjm_code\helloworld\a.py", line 131, in get self.response.out.write(obj1.categories().get().name) AttributeError: 'generator' object has no attribute 'get' so how to get the obj2.name via obj1's method thanks

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  • Why can't I get Python's urlopen() method to work?

    - by froadie
    Why isn't this simple Python code working? import urllib file = urllib.urlopen('http://www.google.com') print file.read() This is the error that I get: Traceback (most recent call last): File "C:\workspace\GarchUpdate\src\Practice.py", line 26, in <module> file = urllib.urlopen('http://www.google.com') File "C:\Python26\lib\urllib.py", line 87, in urlopen return opener.open(url) File "C:\Python26\lib\urllib.py", line 206, in open return getattr(self, name)(url) File "C:\Python26\lib\urllib.py", line 345, in open_http h.endheaders() File "C:\Python26\lib\httplib.py", line 892, in endheaders self._send_output() File "C:\Python26\lib\httplib.py", line 764, in _send_output self.send(msg) File "C:\Python26\lib\httplib.py", line 723, in send self.connect() File "C:\Python26\lib\httplib.py", line 704, in connect self.timeout) File "C:\Python26\lib\socket.py", line 514, in create_connection raise error, msg IOError: [Errno socket error] [Errno 10060] A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond I've tried it with several different pages but I can never get the urlopen method to execute correctly.

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  • In Python, urllib2 giving error

    - by pythBegin
    I tried running this, >>> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl') But it is giving error like this, can anyone tell me a solution ? Traceback (most recent call last): File "<pyshell#11>", line 1, in <module> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl') File "C:\Python26\lib\urllib2.py", line 126, in urlopen return _opener.open(url, data, timeout) File "C:\Python26\lib\urllib2.py", line 391, in open response = self._open(req, data) File "C:\Python26\lib\urllib2.py", line 409, in _open '_open', req) File "C:\Python26\lib\urllib2.py", line 369, in _call_chain result = func(*args) File "C:\Python26\lib\urllib2.py", line 1161, in http_open return self.do_open(httplib.HTTPConnection, req) File "C:\Python26\lib\urllib2.py", line 1136, in do_open raise URLError(err) URLError: <urlopen error [Errno 11001] getaddrinfo failed>

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  • Python + PostgreSQL + strange ascii = UTF8 encoding error

    - by Claudiu
    I have ascii strings which contain the character "\x80" to represent the euro symbol: >>> print "\x80" € When inserting string data containing this character into my database, I get: psycopg2.DataError: invalid byte sequence for encoding "UTF8": 0x80 HINT: This error can also happen if the byte sequence does not match the encodi ng expected by the server, which is controlled by "client_encoding". I'm a unicode newbie. How can I convert my strings containing "\x80" to valid UTF-8 containing that same euro symbol? I've tried calling .encode and .decode on various strings, but run into errors: >>> "\x80".encode("utf-8") Traceback (most recent call last): File "<pyshell#14>", line 1, in <module> "\x80".encode("utf-8") UnicodeDecodeError: 'ascii' codec can't decode byte 0x80 in position 0: ordinal not in range(128)

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  • Python: saving objects and using pickle. Error using pickle.dump

    - by Peterstone
    Hello I have an Error and I don´t the reason: >>> class Fruits:pass ... >>> banana = Fruits() >>> banana.color = 'yellow' >>> banana.value = 30 >>> import pickle >>> filehandler = open("Fruits.obj",'w') >>> pickle.dump(banana,filehandler) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python31\lib\pickle.py", line 1354, in dump Pickler(file, protocol, fix_imports=fix_imports).dump(obj) TypeError: must be str, not bytes >>> I don´t know how to solve this error because I don´t understand it. Thank you so much.

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  • In Django : How to serialize dict object to json ?

    - by Rohit
    I have this very basic problem, >>> serializers.serialize("json", {'a':1}) Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/lib/pymodules/python2.6/django/core/serializers/__init__.py", line 87, in serialize s.serialize(queryset, **options) File "/usr/lib/pymodules/python2.6/django/core/serializers/base.py", line 40, in serialize for field in obj._meta.local_fields: AttributeError: 'str' object has no attribute '_meta' >>> How can this be done ? Thanks in advance !

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  • python unichr problem

    - by jacob
    I've got some problem with unichr() on my server. Please see below: On my server (Ubuntu 9.04): >>> print unichr(255) Traceback (most recent call last): File "<stdin>", line 1, in <module> UnicodeEncodeError: 'ascii' codec can't encode character u'\xff' in position 0: ordinal not in range(128) On my desktop (Ubuntu 9.10): >>> print unichr(255) ÿ I'm fairly new to python so I don't know how to solve this. Anyone care to help? Thanks.

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  • Accessing a dictionary value by custom object value in Python?

    - by Sam
    So I have a square that's made up of a series of points. At every point there is a corresponding value. What I want to do is build a dictionary like this: class Point: def __init__(self, x, y): self._x = x self._y = y square = {} for x in range(0, 5): for y in range(0, 5): point = Point(x,y) square[point] = None However, if I later create a new point object and try to access the value of the dictionary with the key of that point it doesn't work.. square[Point(2,2)] Traceback (most recent call last): File "<pyshell#19>", line 1, in <module> square[Point(2,2)] KeyError: <__main__.Point instance at 0x02E6C378> I'm guessing that this is because python doesn't consider two objects with the same properties to be the same object? Is there any way around this? Thanks

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