Search Results

Search found 803 results on 33 pages for 'xpath 1 0'.

Page 16/33 | < Previous Page | 12 13 14 15 16 17 18 19 20 21 22 23  | Next Page >

  • Succinct LINQ to XML Query

    - by Kent Boogaart
    Assuming you have the following XML: <?xml version="1.0" encoding="utf-8"?> <content> <info> <media> <image> <info> <imageType>product</imageType> </info> <imagedata fileref="http://www.example.com/image1.jpg" /> </image> <image> <info> <imageType>manufacturer</imageType> </info> <imagedata fileref="http://www.example.com/image2.jpg" /> </image> </media> </info> </content> Using LINQ to XML, what is the most succinct, robust way to obtain a System.Uri for an image of a given type? At the moment I have this: private static Uri GetImageUri(XElement xml, string imageType) { return (from imageTypeElement in xml.Descendants("imageType") where imageTypeElement.Value == imageType && imageTypeElement.Parent != null && imageTypeElement.Parent.Parent != null from imageDataElement in imageTypeElement.Parent.Parent.Descendants("imagedata") let fileRefAttribute = imageDataElement.Attribute("fileref") where fileRefAttribute != null && !string.IsNullOrEmpty(fileRefAttribute.Value) select new Uri(fileRefAttribute.Value)).FirstOrDefault(); } This works, but feels way too complicated. Especially when you consider the XPath equivalent. Can anyone point out a better way?

    Read the article

  • xslt (table) by matching the attribute value.

    - by Magesh
    i need to generate an xsl table for the xml below , for atrributes fname and lname.. i have done something worng in xpath i guess.could someone help me out writing an xsl table for the xml below.. <sparql> - <head> <variable name="s"/> <variable name="fname"/> <variable name="lname"/> </head> - <results> - <result> - <binding name="s"> <uri>http://tn.gov.in/Person/41</uri> </binding> - <binding name="fname"> <literal>Gayathri</literal> </binding> - <binding name="lname"> <literal>Vasudevan</literal> </binding> </result> - <result> - <binding name="s"> <uri>http://tn.gov.in/Person/43</uri> </binding> - <binding name="fname"> <literal>Vivek</literal> </binding> - <binding name="lname"> <literal>Vasudevan</literal> </binding> </result> - <result> - <binding name="s"> <uri>http://tn.gov.in/Person/37</uri> </binding> - <binding name="fname"> <literal>Magesh</literal> </binding> - <binding name="lname"> <literal>Vasudevan</literal> </binding> </result> - <result> - <binding name="s"> <uri>http://tn.gov.in/Person/39</uri> </binding> - <binding name="fname"> <literal>Vasudevan </literal> </binding> - <binding name="lname"> <literal>Srinivasan</literal> </binding> </result> </results>

    Read the article

  • Parsing Web Service Response in Oracle 9i

    - by zechariahs
    I'm having trouble parsing an XML response from a web service. I have a feeling this is due to a namespace issue. But, after 4 hours of research, trial-and-error, and head-banging I haven't been able to resolve it. Please help. My goal is to get a dbms_xmldom.DOMNodeList that contains "ERRORS" nodes. XML Response: <?xml version="1.0" encoding="ISO-8859-1"?> <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soap:Body> <GetMailDataResponse xmlns="https://www.customnamespacehost.com/webservicename"> <GetMailDataResult> <Errors xmlns=""> <ErrorDetail>Access Credentials Invalid</ErrorDetail> </Errors> </GetMailDataResult> </GetMailDataResponse> </soap:Body> Code: Unfortunately this code compiles but doesn't work. Error: "ORA-31013: Invalid XPATH expression." I believe this is due to the multiple namespaces defined in L_NS variable. I tried setting L_XPATH: "/soap:Envelope/soap:Body" and L_NS: "xmlns:soap="http://schemas.xmlsoap.org/soap/envelope"" but L_NL_RESULTS ends up being null. -- Variable Declarations -- P_XML XMLTYPE; L_CODE_NAME VARCHAR2(1000) := 'PKG_CIS_WS.FNC_STAGE_DATA'; L_XML_DOC dbms_xmldom.DOMDocument; L_NL_RESULTS dbms_xmldom.DOMNodeList; L_NL_DONOR_SCREENING_RESULTS dbms_xmldom.DOMNodeList; L_N_RESULT dbms_xmldom.DOMNode; L_XPATH VARCHAR2(4000); L_NS VARCHAR2(4000); L_TEMP VARCHAR2(4000); -- Code Snippet -- L_XML_DOC := dbms_xmldom.newDOMDocument(P_XML); L_XPATH := '/soap:Envelope/soap:Body/a:GetMailDataResponse/GetMailDataResult'; L_NS := 'xmlns:soap="http://schemas.xmlsoap.org/soap/envelope"' || 'xmlns:a="https://www.customnamespacehost.com/webservicename"'; L_NL_RESULTS := dbms_xslprocessor.selectNodes( dbms_xmldom.makeNode(L_XML_DOC) , L_XPATH , L_NS); if not DBMS_XMLDOM.ISNULL(L_NL_RESULTS) then FOR RESULTS_REC IN 0 .. dbms_xmldom.getLength(L_NL_RESULTS) - 1 LOOP L_N_RESULT := dbms_xmldom.item(L_NL_RESULTS, RESULTS_REC); L_TEMP := dbms_xmldom.GETNODENAME(L_N_RESULT); prc_bjm(L_CODE_NAME, 'L_TEMP = ' || L_TEMP, SQLCODE); dbms_xslprocessor.valueOf(L_N_RESULT, 'Errors/ErrorDetail/text()', L_TEMP); prc_bjm(L_CODE_NAME, 'L_TEMP = ' || L_TEMP, SQLCODE); END LOOP; else prc_bjm(L_CODE_NAME, 'No nodes for: ' || L_XPATH || '(' || L_NS || ')', SQLCODE); end if; -- if not DBMS_XMLDOM.ISNULL(L_NL_RESULTS)

    Read the article

  • How to limit results in a SharePoint XSL query

    - by David
    Hello all, I am creating a SharePoint site that we will use to report issues with trucks used in our business. Linked to the list I have created will be a page that will display an overview of the trucks and a little truck icon will show the trucks current status. Green and the truck is okay (no open issues), Red and the truck have an open issue with status "Undrivable", Orange and there is two issues open that requires the user to look further into the truck before using it and finally a Gray truck for when there is a new issue created that has not been looked into (not sure if it is drivable or not). I have managed to create the "Dashboard" and with my limit XSL/XPATH knowledge been able to add a truck and replicate the description above but... in my test I have created 4 issues, for example if three of them are changed to status Closed and one left to Undrivable I will get four icons on the page, three with Green trucks and the last one Red. So in theory it works but I obviously only want to see the last truck, one truck. I am not interested in seeing the others. <xsl:template name="dvt_1.rowview"> <xsl:variable name="CountReport" select="count(/dsQueryResponse/Rows/Row[@Highloader='GGEU12' and @Status!='Closed'])" /> <xsl:variable name="MoreThan" select="$CountReport &gt; 1" /> <xsl:variable name="NoReports" select="$CountReport = 0" /> <xsl:variable name="Closed" select=" @Highloader='GGEU12' and @Status='Closed'" /> <xsl:choose> <xsl:when test="$MoreThan"> <div class="ms-vb"><img title='More than one report exist!' border='0' alt='In Progress' src='highloader/Library/hl-orange.png' /></div> </xsl:when> <xsl:otherwise> <div class="ms-vb"><xsl:value-of disable-output-escaping="yes" select="@Icon" /></div> </xsl:otherwise> </xsl:choose> </xsl:template> My hope is that someone with slightly more knowledge can find the last piece of the puzzle for me! Thanks for reading and asking questions to fill any gap I left above. David

    Read the article

  • Getting key/value pairs from plist-style xml using simplexml in php

    - by Anthony
    Here is an example bit from the xml file: <array> <dict> <key>Name</key> <string>Joe Smith</string> <key>Type</key> <string>Profile</string> <key>Role</key> <string>User</string> <key>Some Number</key> <integer>1</integer> <key>Some Boolean</key> <true/> </dict> </array> I have two separate goals. The first is to extract an array from the dictnode that would look like: [Name] => Joe Smith [Type] => Profile [Role] => User [Some Number] => 1 [Some Boolean] => true It's not crucial that the boolean be included, so if that adds too much complexity, I'd rather just know how to deal with the others for now. The second goal is to be able to select the value node (<string>, <integer>,etc) so that I can change the value. I would need to select it based on the text value of the preceding key element. I think the following XPath should work: //key[.=$keyname]/following-sibling[1] But I'm not sure. Basically, this whole system that Apple uses seems logical, but totally contrary to the XML is supposed to work. If I ran the world, the original XML would look more like: <dict type="array"> <value key="Name" type="string">Joe Smith</value> <value key="Type" type="string">Profile</value> <value key="Role type="string">User</value> <value key="Some Number" type="integer">1</value> <value key="Some Boolean" type="boolean">true</value> </dict> But since it is fairly logical, I am wondering if I'm missing some obvious way of handling it.

    Read the article

  • XML Path needed

    - by user3696029
    I have the following XML file: <?xml version="1.0" encoding="UTF-8"?> <bookstore> <book category="COOKING"> <title lang="en">Everyday Italian</title> <author>Giada De Laurentiis</author> <year>2005</year> <price>30.00</price> </book> <book category="CHILDREN"> <title lang="en">Harry Potter</title> <author>J K. Rowling</author> <year>2005</year> <price>29.99</price> </book> <book category="WEB"> <title lang="en">XQuery Kick Start</title> <author>James McGovern</author> <author>Per Bothner</author> <author>Kurt Cagle</author> <author>James Linn</author> <author>Vaidyanathan Nagarajan</author> <year>2003</year> <price>49.99</price> </book> <book category="WEB"> <title lang="en">Learning XML</title> <author>Erik T. Ray</author> <year>2003</year> <price>39.95</price> </book> </bookstore> I need to write a XML path that returns a book published after 2003, category is children and I just need to display the author and title of the book? What is frustrating is that I have everything in the XPATH that wrote except I am missing the author.

    Read the article

  • XSLT Select all nodes containing a specific substing

    - by Mike
    I'm trying to write an XPath that will select certain nodes that contain a specific word. In this case the word is, "Lockwood". The correct answer is 3. Both of these paths give me 3. count(//*[contains(./*,'Lockwood')]) count(BusinessLetter/*[contains(../*,'Lockwood')]) But when I try to output the text of each specific node //*[contains(./*,'Lockwood')][1] //*[contains(./*,'Lockwood')][2] //*[contains(./*,'Lockwood')][3] Node 1 ends up containing all the text and nodes 2 and 3 are blank. Can some one please tell me what's happening or what I'm doing wrong. Thanks. <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xsl" href="XPathFunctions.xsl"?> <BusinessLetter> <Head> <SendDate>November 29, 2005</SendDate> <Recipient> <Name Title="Mr."> <FirstName>Joshua</FirstName> <LastName>Lockwood</LastName> </Name> <Company>Lockwood &amp; Lockwood</Company> <Address> <Street>291 Broadway Ave.</Street> <City>New York</City> <State>NY</State> <Zip>10007</Zip> <Country>United States</Country> </Address> </Recipient> </Head> <Body> <List> <Heading>Along with this letter, I have enclosed the following items:</Heading> <ListItem>two original, execution copies of the Webucator Master Services Agreement</ListItem> <ListItem>two original, execution copies of the Webucator Premier Support for Developers Services Description between Lockwood &amp; Lockwood and Webucator, Inc.</ListItem> </List> <Para>Please sign and return all four original, execution copies to me at your earliest convenience. Upon receipt of the executed copies, we will immediately return a fully executed, original copy of both agreements to you.</Para> <Para>Please send all four original, execution copies to my attention as follows: <Person> <Name> <FirstName>Bill</FirstName> <LastName>Smith</LastName> </Name> <Address> <Company>Webucator, Inc.</Company> <Street>4933 Jamesville Rd.</Street> <City>Jamesville</City> <State>NY</State> <Zip>13078</Zip> <Country>USA</Country> </Address> </Person> </Para> <Para>If you have any questions, feel free to call me at <Phone>800-555-1000 x123</Phone> or e-mail me at <Email>[email protected]</Email>.</Para> </Body> <Foot> <Closing> <Name> <FirstName>Bill</FirstName> <LastName>Smith</LastName> </Name> <JobTitle>VP of Operations</JobTitle> </Closing> </Foot> </BusinessLetter>

    Read the article

  • Why does this XSL fails to retrieve value from xml ?

    - by Pavitar
    Following is an extract of the XSL stylesheet that I have written. It says my '.xsl' is well formed but it somehow does not retrieve values from the xml,instead jus pastes the header and table headings. EDIT <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions"> <xsl:template match="/" > <html> <head> <title>GlenMark Pharma</title> </head> <h1 align="center"><font face="Monotype Corsiva" color="red">GlenMarkPharma</font></h1> <body> <table> <tbody> <tr> <th>ID</th> <th>ENAME</th> <th>Mobile</th> <th>EMAIL</th> <th>PWD</th> </tr> <xsl:for-each select="employees/employee"> <tr> <td><xsl:value-of select="@empID" /></td> <td><xsl:value-of select="name" /></td> <td><xsl:value-of select="mobile" /></td> <td><xsl:value-of select="email" /></td> <td><xsl:value-of select="pwd" /></td> </tr> </xsl:for-each> </tbody> </table> </body> </html> </xsl:template> </xsl:stylesheet> Here is my XML doc: <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xsl" href="MyfirstXsl.xsl"?> <!DOCTYPE employees SYSTEM "Mydtd.dtd"> <me:employees xmlns:me="[email protected]" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="[email protected] Mycomplex.xsd"> <me:employee empID="EMP101"> <me:name>Vicky</me:name> <me:mobile>9870582356</me:mobile> <me:email>[email protected]</me:email> <me:pwd>&defPWD;</me:pwd> </me:employee> </me:employees> I have also tried writing: <xsl:for-each select="employees/employee"> <tr> <td><xsl:value-of select="@empID" /></td> <td><xsl:value-of select="me:name" /></td> in the XSL since I have an alias to the namespace in my XML Doc.But it gives me an error of Invalid Pre-fix.I don't know what I'm doing wrong.

    Read the article

  • XSLT1.0: remove duplicates combined with an xsl:key

    - by Jannibal
    I have the following piece of XML: <research> <research.record> <research.record_number>1</research.record_number> <research.type> <value lang="en-US">some research type</value> </research.type> <research.type> <value lang="en-US">some other type of research</value> </research.type> <project.record> <priref>101</priref> <project.type> <value lang="en-US">some type of project</value> </project.type> </project.record> </research.record> </research> <research> <research.record> <research.record_number>2</research.record_number> <research.type> <value lang="en-US">some other type of research</value> </research.type> <research.type> <value lang="en-US">a third type of research</value> </research.type> <project.record> <priref>101</priref> <project.type> <value lang="en-US">some type of project</value> </project.type> </project.record> </research.record> </research> <research> <research.record> <research.record_number>3</research.record_number> <research.type> <value lang="en-US">some other type of research</value> </research.type> <research.type> <value lang="en-US">a fourth type</value> </research.type> <project.record> <priref>201</priref> <project.type> <value lang="en-US">some other type of project</value> </project.type> </project.record> </research.record> </research> <research> ... etc ... With XSLT 1.0 I transform this XML into a list of unique project records by using xsl:key. So far, so good... The problem is: I also want to show unique research types for each unique project record. My wanted output would be: project.record 101: some research type, some other type of research, a third type of research project.record 201: some other type of research, a fourth type Hope someone can help me out with the right XSLT/XPATH. (Can only use XSLT1.0)

    Read the article

  • how to pull href link

    - by user1751494
    I am trying to pull a link from a page that is in a formal I can't seem to find by simply googling... it might be simple but xpath is not my area of expertise I am using c# and trying to pull the link and just write it to the console to figure out how to get the link here is my C# code var document = webGet.Load("http://classifieds.castanet.net/cat/vehicles/cars/0_-_4_years_old/"); var browser = document.DocumentNode.SelectSingleNode("//a[starts-with(@href,'/details/')]"); if (browser != null) { string htmlbody = browser.OuterHtml; Console.WriteLine(htmlbody); } the html code section is <div class="last">&hellip;</div><a href="/cat/vehicles/cars/0_-_4_years_old/?p=13">13</a><a href="/cat/vehicles/cars/0_-_4_years_old/?p=2">&raquo;</a> <select name="sortby" class="sortby" onchange="doSort(this);"> <option value="">Most Recent</option> <option value="of" >Oldest First</option> <option value="mw" >Most Views</option> <option value="lw" >Fewest Views</option> <option value="lp" >Lowest Price</option> <option value="hp" >Highest Price</option> </select><div style="clear:both"></div> </div> <br /><br /><br /> <a href="/details/2008_vw_gti/1454282/" class="prod_container" > <h2>2008 VW GTi</h2> <div style="float:left; width:122px; z-index:1000"> <div class="thumb"><img src="http://c.castanet.net/img/28/thumbs/1454282-1-1.jpg" border="0"/></div> <div class="clear"></div> mls </div> <div class="descr"> The most fun car I have owned. Dolphin Grey, 4 door, Dual Climate control, DRG Transmission with paddle shift. Leather... </div> <div class="pdate"> <p class="price">$19,000.00</p> <p class="date">Kelowna<br />Posted: Oct 15, 2:54 PM<br />Views: 349</p> </div> <div style="clear:both" ></div> <div class="seal"><img src="/images/bookmark.png" /></div> </a> <a href="/details/price_drop_gorgeous_rare_white_2009_honda_accord_ex-l_coupe/1447341/" class="prod_container" > <h2>PRICE DROP!!! Gorgeous Rare White 2009 Honda Accord EX-L Coupe </h2> <div style="float:left; width:122px; z-index:1000"> <div class="thumb"><img src="http://c.castanet.net/img/28/thumbs/1447341-1-1.jpg" border="0"/></div> <div class="clear"></div> sun2010 </div> <div class="descr"> the link I'm trying to get is the "/details/2008_vw_gti/1454282/" part. THanks

    Read the article

  • Is SecureShellz bot a virus? How does it work?

    - by ProGNOMmers
    I'm using a development server in which I found this in the crontab: [...] * * * * * /dev/shm/tmp/.rnd >/dev/null 2>&1 @weekly wget http://stablehost.us/bots/regular.bot -O /dev/shm/tmp/.rnd;chmod +x /dev/shm/tmp/.rnd;/dev/shm/tmp/.rnd [...] http://stablehost.us/bots/regular.bot contents are: #!/bin/sh if [ $(whoami) = "root" ]; then echo y|yum install perl-libwww-perl perl-IO-Socket-SSL openssl-devel zlib1g-dev gcc make echo y|apt-get install libwww-perl apt-get install libio-socket-ssl-perl openssl-devel zlib1g-dev gcc make pkg_add -r wget;pkg_add -r perl;pkg_add -r gcc wget -q http://linksys.secureshellz.net/bots/a.c -O a.c;gcc -o a a.c;mv a /lib/xpath.so;chmod +x /lib/xpath.so;/lib/xpath.so;rm -rf a.c wget -q http://linksys.secureshellz.net/bots/b -O /lib/xpath.so.1;chmod +x /lib/xpath.so.1;/lib/xpath.so.1 wget -q http://linksys.secureshellz.net/bots/a -O /lib/xpath.so.2;chmod +x /lib/xpath.so.2;/lib/xpath.so.2 exit 1 fi wget -q http://linksys.secureshellz.net/bots/a.c -O a.c;gcc -o .php a.c;rm -rf a.c;chmod +x .php; ./.php wget -q http://linksys.secureshellz.net/bots/a -O .phpa;chmod +x .phpa; ./.phpa wget -q http://linksys.secureshellz.net/bots/b -O .php_ ;chmod +x .php_;./.php_ I cannot contact the sysadmin for various reasons, so I cannot ask infos about this to him. It seems to me this script downloads some remote C source codes and binaries, compile them and execute them. I am a web developer, so I am not an expert about C language, but watching at the downloaded files it seems to me a bot injected in the cron of the server. Can you give me more infos about what this code does? About its working, its purposes?

    Read the article

  • XML transform element appearing in wrong place in document

    - by Mike
    I am having some problems with an XML transform and need some help. The stylesheet should iterate through all suffix elements and place the contents without the suffix tag next to the last text node within its first ancestor quote-block element (see desired ouput). It works when only a single suffix is present, but not when 2 are present, when 2 are present it places both suffixes next to each other in the last text node of the first quote-block. Any ideas? I have tried limiting the selections to ancestor::quote-block[1] in various places but that doesn't have the desired effect. Source XML <paragraph> <para> <quote-block> <list prefix-rules="specified"> <item prefix="“B42"> <para id="0a84d149-91b7-4012-ac6d-9f4eb8ed6c37">In June 2000, EME and EWS reached an agreement to negotiate towards a direct contract for coal haulage by rail (on a DIY basis), which would replace the previous indirect E2E arrangements that EME had in place with ECSL. An internal EWS e-mail noted: <quote-block> <quote-para>‘We did the deal with Edison Mission yesterday morning for LBT-Fiddlers @ £[…]/tonne as agreed. This rate until 16th September pending a contract.</quote-para> <quote-para><emphasis strength="strong">Enron are now off our hands so far as Edison are concerned. The Enron flows we have left are to British Energy’s station at Eggborough; from Immingham, Redcar and Hull</emphasis>. Also to Enron’s own power station at Wilton – 250,000 tonnes/year. I think we are stuck Enron [sic] on the Eggborough traffic until next April when British Energy will, hopefully take over their own coal procurement. <emphasis strength="strong">But we have got them out of Fiddlers Ferry and Ferrybridge – a big step forward</emphasis>.’</quote-para> <suffix>(Emphasis added.)</suffix> </quote-block> </para> </item> <item prefix="B43"> <para id="d64a5a72-0a02-476f-9a7b-7c07bbc93a8a">This e-mail is evidence of both EWS’s intent and, indeed, its success in stopping ECSL from carrying out indirect supplies to EME, one of the new generating companies.”</para> </item> </list> <suffix>(emphasis in original)</suffix> </quote-block> </para> </paragraph> Stylesheet <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://xml.sm.com/schema/cases/report" xmlns:sm="http://xml.sm.com/functions" xmlns:saxon="http://saxon.sf.net/" xpath-default-namespace="http://sm.com/schema/cases/report" exclude-result-prefixes="xs sm" version="2.0"> <xsl:output method="xml" indent="no"/> <xsl:template match="/"> <xsl:apply-templates/> </xsl:template> <xsl:template match="*"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> <!-- Match quote-blocks with open or close attributes. --> <xsl:template match="*[*:quote-block and descendant::*:suffix]"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- Match inline quote with open or close attributes --> <xsl:template match="*[*:quote and descendant::*:suffix]"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- Process the quote block --> <xsl:template name="process-quote-block"> <xsl:variable name="quoteBlockCopy"> <xsl:copy-of select="."/> </xsl:variable> <xsl:apply-templates select="$quoteBlockCopy" mode="append-suffix"> <xsl:with-param name="suffix" select="sm:get-suffix-note(.)"/> <xsl:with-param name="end-node" select="sm:get-last-text-node($quoteBlockCopy)"/> </xsl:apply-templates> </xsl:template> <!-- Match quote-blocks with open or close attributes. --> <xsl:template match="*[*:quote-block and descendant::*:suffix][ancestor::*:quote-block[1]]" mode="create-copy"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- Match inline quote with open or close attributes --> <xsl:template match="*[*:quote and descendant::*:suffix]" mode="create-copy"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- This will match all elements. Just copy and pass through the parameters. --> <xsl:template match="*" mode="append-suffix"> <xsl:param name="suffix"/> <xsl:param name="end-node"/> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates mode="append-suffix"> <xsl:with-param name="suffix" select="$suffix"/> <xsl:with-param name="end-node" select="$end-node"/> </xsl:apply-templates> </xsl:copy> </xsl:template> <!-- Apply the text node to the content. If the node is equal to the last node then append the descendants of suffix --> <xsl:template match="text()[normalize-space() != '']" mode="append-suffix"> <xsl:param name="suffix"/> <xsl:param name="end-node"/> <xsl:choose> <xsl:when test="count(. | $end-node) = 1"> <xsl:value-of select="."/> <xsl:apply-templates select="$suffix"/> </xsl:when> <xsl:otherwise> <!-- Or maybe neither. --> <xsl:value-of select="."/> </xsl:otherwise> </xsl:choose> </xsl:template> <!-- Dont copy suffix as --> <xsl:template match="*:suffix" mode="append-suffix"/> <xsl:function name="sm:get-suffix-note"> <xsl:param name="node"/> <xsl:sequence select="$node/descendant::*:suffix/node()"/> </xsl:function> <xsl:function name="sm:get-last-text-node"> <!-- Finds last non-empty text() node, ignoring <suffix> elements that are a child of this specific quote-block. --> <xsl:param name="node"/> <xsl:sequence select="reverse($node//text()[not(ancestor::*:suffix) and normalize-space() != ''])[1]"/> </xsl:function> </xsl:stylesheet> Current Output XML <paragraph> <para> <quote-block> <list prefix-rules="specified"> <item prefix="“B42"> <para id="0a84d149-91b7-4012-ac6d-9f4eb8ed6c37">In June 2000, EME and EWS reached an agreement to negotiate towards a direct contract for coal haulage by rail (on a DIY basis), which would replace the previous indirect E2E arrangements that EME had in place with ECSL. An internal EWS e-mail noted: <quote-block> <quote-para>‘We did the deal with Edison Mission yesterday morning for LBT-Fiddlers @ £[…]/tonne as agreed. This rate until 16th September pending a contract.</quote-para> <quote-para><emphasis strength="strong">Enron are now off our hands so far as Edison are concerned. The Enron flows we have left are to British Energy’s station at Eggborough; from Immingham, Redcar and Hull</emphasis>. Also to Enron’s own power station at Wilton – 250,000 tonnes/year. I think we are stuck Enron [sic] on the Eggborough traffic until next April when British Energy will, hopefully take over their own coal procurement. <emphasis strength="strong">But we have got them out of Fiddlers Ferry and Ferrybridge – a big step forward</emphasis>.’</quote-para> </quote-block> </para> </item> <item prefix="B43"> <para id="d64a5a72-0a02-476f-9a7b-7c07bbc93a8a">This e-mail is evidence of both EWS’s intent and, indeed, its success in stopping ECSL from carrying out indirect supplies to EME, one of the new generating companies.”(Emphasis added.)(emphasis in original)</para> </item> </list> </quote-block> </para> </paragraph> Desired Ouput <paragraph> <para> <quote-block> <list prefix-rules="specified"> <item prefix="“B42"> <para id="0a84d149-91b7-4012-ac6d-9f4eb8ed6c37">In June 2000, EME and EWS reached an agreement to negotiate towards a direct contract for coal haulage by rail (on a DIY basis), which would replace the previous indirect E2E arrangements that EME had in place with ECSL. An internal EWS e-mail noted: <quote-block> <quote-para>‘We did the deal with Edison Mission yesterday morning for LBT-Fiddlers @ £[…]/tonne as agreed. This rate until 16th September pending a contract.</quote-para> <quote-para><emphasis strength="strong">Enron are now off our hands so far as Edison are concerned. The Enron flows we have left are to British Energy’s station at Eggborough; from Immingham, Redcar and Hull</emphasis>. Also to Enron’s own power station at Wilton – 250,000 tonnes/year. I think we are stuck Enron [sic] on the Eggborough traffic until next April when British Energy will, hopefully take over their own coal procurement. <emphasis strength="strong">But we have got them out of Fiddlers Ferry and Ferrybridge – a big step forward</emphasis>.’(Emphasis added.)</quote-para> </quote-block> </para> </item> <item prefix="B43"> <para id="d64a5a72-0a02-476f-9a7b-7c07bbc93a8a">This e-mail is evidence of both EWS’s intent and, indeed, its success in stopping ECSL from carrying out indirect supplies to EME, one of the new generating companies.”(emphasis in original)</para> </item> </list> </quote-block> </para> </paragraph>

    Read the article

  • PHP5 : Applying a method from an extended class on an object from the original (parent) class.

    - by Glauber Rocha
    Hello, I'm trying to extend two native PHP5 classes (DOMDocument and DOMNode) to implement 2 methods (selectNodes and selectSingleNode) in order to make XPath queries easier. I thought it would be rather straighforward, but I'm stuck in a problem which I think is an OOP beginner's issue. class nDOMDocument extends DOMDocument { public function selectNodes($xpath){ $oxpath = new DOMXPath($this); return $oxpath->query($xpath); } public function selectSingleNode($xpath){ return $this->selectNodes($xpath)->item(0); } } Then I tried to do extend DOMNode to implement the same methods so I can perform an XPath query directly on a node: class nDOMNode extends DOMNode { public function selectNodes($xpath){ $oxpath = new DOMXPath($this->ownerDocument,$this); return $oxpath->query($xpath); } public function selectSingleNode($xpath){ return $this->selectNodes($xpath)->item(0); } } Now if I execute the following code (on an arbitrary XMLDocument): $xmlDoc = new nDOMDocument; $xmlDoc->loadXML(...some XML...); $node1 = $xmlDoc->selectSingleNode("//item[@id=2]"); $node2 = $node1->selectSingleNode("firstname"); The third line works and returns a DOMNode object $node1. However, the fourth line doesn't work because the selectSingleNode method belongs to the nDOMNode class, not DOMNode. So my question: is there a way at some point to "transform" the returned DOMNode object into a nDOMNode object? I feel I'm missing some essential point here and I'd greatly appreciate your help. (Sorry, this is a restatement of my question http://stackoverflow.com/questions/2573820/)

    Read the article

  • how to COPY Attribute value in a new attribute

    - by Mukesh
    How to copy data of attribute to new attribute in the same column in sql original data <root> <child attr='hello'></child> </root> Result 1 <root> <child attr='hello' attr2='hello'></child> </root> Result 2(with a modification) <root> <child attr='hello' attr2='**H**ello **W**orld'></child> </root>

    Read the article

  • HtmlAgilityPack SelectNodes expression to ignore an element with a certain attribute

    - by thaky
    I am trying to select nodes except from script nodes and a ul that has a class called 'relativeNav'. Can someone please direct me to the right path? I have been searching for this for a week and I can't find it anywhere. Currently I have this but it obviously selecting the //ul[@class='relativeNav'] as well. Is there anyway to put an NOT expression of it so that SelectNode will ignore that one? foreach (HtmlNode node in doc.DocumentNode.SelectNodes("//body//*[not(self::script)]/text()")) { Console.WriteLine("Node: " + node); singleString += node.InnerText.Trim() + "\n"; }

    Read the article

  • remember the highlighted text in html page(add annotation to html page)

    - by ganapati hegde
    Hi, I have an HTML file, i am opening it with webkit,i want to develop an app, such that after opening it, i should be able to select some text and make it highlighted(say by pressing some button 'highlight text' ). And it should remember the highlighted text so that when i open it next time it should highlight the same text automatically...which information i got to store so that i can highlight the same in the next time ? any library is available which makes my work simple?

    Read the article

  • problem with AddSort method

    - by netNewbi3
    Hi Could you let me know what the proboem is with sorting in this code? It doesn't work. My xml: CONTRACTS --CONTRACT ---SUPPLIER ---COMMODITIES ----COMMODITY -----COMODDITYNAME My code: Dim myString As StringBuilder = New StringBuilder(200) Dim xdoc As New XPathDocument("local_xml.xml") Dim nav As XPathNavigator = xdoc.CreateNavigator() Dim expr As XPathExpression expr = nav.Compile("/pf:CONTRACTS/pf:CONTRACT") Dim namespaceManager As XmlNamespaceManager = New XmlNamespaceManager(nav.NameTable) namespaceManager.AddNamespace("pf", "http://namespace.ac.uk/") expr.AddSort("pf:SUPPLIER", XmlSortOrder.Ascending, XmlCaseOrder.None, String.Empty, XmlDataType.Text) expr.SetContext(namespaceManager) Dim nodes As XPathNodeIterator = nav.Select(expr) If nodes.Count > 0 Then myString.AppendLine("<table width='96%' border='0' cellpadding='0' cellspacing='0' border='0' class='datatable1'>") myString.AppendLine("<th width='35%'>Name</th><th width='35%'>Commodity</th><th width='20%'>Supplier</a></th>") While nodes.MoveNext() Dim node As XPathNavigator = nodes.Current.SelectSingleNode("pf:NAME", namespaceManager) Dim supplier As XPathNavigator = nodes.Current.SelectSingleNode("pf:SUPPLIER", namespaceManager) Dim commodity As XPathNavigator = nodes.Current.SelectSingleNode("pf:COMMODITIES/pf:COMMODITY/pf:COMMODITYNAME", namespaceManager) Dim sChars As String = " " myString.AppendLine("<tr>") myString.AppendLine("<td>") myString.AppendLine(node.ToString()) myString.AppendLine("</td>") myString.AppendLine("<td>") myString.AppendLine(commodity.ToString()) myString.AppendLine("</td>") myString.AppendLine("<td>") myString.AppendLine(supplier.ToString()) myString.AppendLine("</td>") myString.AppendLine("</tr>") End While myString.AppendLine("</table>") Dim strOutput As String = myString.ToString() lblOutput.Text = strOutput Else lblOutput.Text = "No results for your search<br/>" End If

    Read the article

  • Sorted exsl:node-set. Return node by it position.

    - by kalininew
    Good afternoon, gentlemen. Help me solve a very simple task. I have a set of nodes <menuList> <mode name="aasdf"/> <mode name="vfssdd"/> <mode name="aswer"/> <mode name="ddffe"/> <mode name="ffrthjhj"/> <mode name="dfdf"/> <mode name="vbdg"/> <mode name="wewer"/> <mode name="mkiiu"/> <mode name="yhtyh"/> and so on... </menuList> I have it sorted now this way <xsl:variable name="rtf"> <xsl:for-each select="//menuList/mode"> <xsl:sort data-type="text" order="ascending" select="@name"/> <xsl:value-of select="@name"/> </xsl:for-each> </xsl:variable> Now I need to get an arbitrary element in the sorted array to the number of its position. I write code <xsl:value-of select="exsl:node-set($rtf)[position() = 3]"/> and get a response error. How to do it right?

    Read the article

  • Exclude first child with XSL-T

    - by zneak
    Hello, What I'm trying to do is fairly simple, but I can't find the way to. I just want to iterate over the children of a node excluding the first child. For instance, in this XML snippet, I would want all the <bar> elements, except the first one: <foo> <Bar>Example</Bar> <Bar>This is an example</Bar> <Bar>Another example</Bar> <Bar>Bar</Bar> </foo> There is no common attribute by which I can filter (like an id tag or something similar). Any suggestions?

    Read the article

  • TCL tDom Empty XML Tag

    - by pws5068
    I'm using tDom to loop through some XML and pull out each element's text(). set xml { <systems> <object> <type>Hardware</type> <name>Server Name</name> <attributes> <vendor></vendor> </attributes> </object> <object> <type>Hardware</type> <name>Server Two Name</name> <attributes> <vendor></vendor> </attributes> </object> </systems> }; set doc [dom parse $xml] set root [$doc documentElement] set nodeList [$root selectNodes /systems/object] foreach node $nodeList { set nType [$node selectNodes type/text()] set nName [$node selectNodes name/text()] set nVendor [$node selectNodes attributes/vendor/text()] # Etc... puts "Type: " puts [$nType data] # Etc .. puts [$nVendor data] } But when it tries to print out the Vendor, which is empty, it thows the error invalid command name "". How can I ignore this and just set $nVendor to an empty string?

    Read the article

  • Formatting datetime values returned in a SELECT..FOR XML statement

    - by TelJanini
    Consider the following table: Orders OrderId Date CustomerId 1000 2012-06-05 20:03:12.000 51 1001 2012-06-16 12:02:31.170 48 1002 2012-06-18 19:45:16.000 33 When I extract the Order data using FOR XML: SELECT OrderId AS 'Order/@Order-Id', Date AS 'Order/ShipDate', CustomerId AS 'Order/Customer' FROM Orders WHERE OrderId = 1000 FOR XML PATH ('') I get the following result: <Order Order-Id="1000"> <ShipDate>2010-02-20T16:03:12</ShipDate> <Customer>51</Customer> </Order> The problem is, the ShipDate value in the XML file needs to be in the format M/DD/YYYY H:mm:ss PM. How can I change the output of the ShipDate in the XML file to the desired format? Any help would be greatly appreciated!

    Read the article

  • Select XML nodes as rows

    - by Bjørn
    I am selecting from a table that has an XML column using T-SQL. I would like to select a certain type of node and have a row created for each one. For instance, suppose I am selecting from a people table. This table has an XML column for addresses. The XML is formated similar to the following: <address> <street>Street 1</street> <city>City 1</city> <state>State 1</state> <zipcode>Zip Code 1</zipcode> </address> <address> <street>Street 2</street> <city>City 2</city> <state>State 2</state> <zipcode>Zip Code 2</zipcode> </address> How can I get results like this: Name         City         State Joe Baker   Seattle      WA Joe Baker   Tacoma     WA Fred Jones  Vancouver BC

    Read the article

  • using XSL to replace XML nodes with new nodes

    - by iHeartGreek
    I need an XSL solution to replace XML nodes with new nodes. Say I have the following existing XML structure: <root> <criteria> <criterion>AAA</criterion> </criteria> </root> And I want to replace the one criterion node with: <criterion>BBB</criterion> <criterion>CCC</criterion> <criterion>DDD</criterion> So that the final XML result is: <root> <criteria> <criterion>BBB</criterion> <criterion>CCC</criterion> <criterion>DDD</criterion> </criteria> </root> I have tried using substring-before and substring-after to just copy the first half of the structure, then just copy the second half (in order to fill in my new nodes in between the two halves) but it appears that the substring functions only recognize text in between the nodes' tags, and not the tags themselves like I want them to. :( :( Any other solutions?

    Read the article

  • How to copy child nodes to another xml document?

    - by Alex
    Below is my xml XML1 <?xml version="1.0" encoding="ISO-8859-1" ?> <CATALOG> <CD> <TITLE>1</TITLE> <ARTIST>Bob Dylan</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>Columbia</COMPANY> <PRICE>10.90</PRICE> <YEAR>1985</YEAR> </CD> <CD> <TITLE>2</TITLE> <ARTIST>Bonnie Tyler</ARTIST> <COUNTRY>UK</COUNTRY> <COMPANY>CBS Records</COMPANY> <PRICE>9.90</PRICE> <YEAR>1988</YEAR> </CD> </CATALOG> XML2 <?xml version="1.0" encoding="ISO-8859-1" ?> <CATALOG> <CD> <TITLE>3</TITLE> <ARTIST>Dolly Parton</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>RCA</COMPANY> <PRICE>9.90</PRICE> <YEAR>1982</YEAR> </CD> </CATALOG> i need output like this <?xml version="1.0" encoding="ISO-8859-1" ?> <CATALOG> <CD> <TITLE>1</TITLE> <ARTIST>Bob Dylan</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>Columbia</COMPANY> <PRICE>10.90</PRICE> <YEAR>1985</YEAR> </CD> <CD> <TITLE>2</TITLE> <ARTIST>Bonnie Tyler</ARTIST> <COUNTRY>UK</COUNTRY> <COMPANY>CBS Records</COMPANY> <PRICE>9.90</PRICE> <YEAR>1988</YEAR> </CD> <CD> <TITLE>3</TITLE> <ARTIST>Dolly Parton</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>RCA</COMPANY> <PRICE>9.90</PRICE> <YEAR>1982</YEAR> </CD> </CATALOG> How i write this in classic asp ?

    Read the article

  • Trying to use an Xslt for an xml in asp.net

    - by Josemalive
    Hello, i have the following xslt sheet: <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:variable name="nhits" select="Answer[@nhits]"></xsl:variable> <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <div> <xsl:call-template name="resultsnumbertemplate"/> </div> </xsl:template> <xsl:template name="resultsnumbertemplate"> <xsl:value-of select="$nhits"/> matches found </xsl:template> </xsl:stylesheet> And this is the xml that im trying to mix with the previous xslt: <Answer xmlns="exa:com.exalead.search.v10" context="n%3Dsl-ocu%26q%3Dlavadoras" last="9" estimated="false" nmatches="219" nslices="0" nhits="219" start="0"> <time> <Time interrupted="false" overall="32348" parse="0" spell="0" exec="1241" synthesis="15302" cats="14061" kwds="14061"> <sliceTimes>15272 </sliceTimes> </Time> </time> </Answer> Im using a xslcompiledtransform and that's working fine: XslCompiledTransform transformer = new XslCompiledTransform(); transformer.Load(HttpContext.Current.Server.MapPath("xslt\\" + requestvariables["xslsheet"].ToString())); transformer.Transform(xmlreader, null, writer); My problems comes when im trying to put into a variable the "nhits" attribute value placed on the Answer element, but i'm not rendering anything using my xslt sheet. Do you know what could be the cause? Could be the xmlns attribute in my xml file? Thanks in advance. Best Regards. Jose

    Read the article

< Previous Page | 12 13 14 15 16 17 18 19 20 21 22 23  | Next Page >