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  • Passing list and dictionary type parameter with Python

    - by prosseek
    When I run this code def func(x, y, *w, **z): print x print y if w: print w if z: print z else: print "None" func(10,20, 1,2,3,{'k':'a'}) I get the result as follows. 10 20 (1, 2, 3, {'k': 'a'}) None But, I expected as follows, I mean the list parameters (1,2,3) matching *w, and dictionary matching **z. 10 20 (1,2,3) {'k':'a'} Q : What went wrong? How can I pass the list and dictionary as parameters? Added func(10,20, 10,20,30, k='a') seems to be working

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  • How to display locale sensitive time format without seconds in python

    - by Tim Kersten
    I can output a locale sensitive time format using strftime('%X'), but this always includes seconds. How might I display this time format without seconds? >>> import locale >>> import datetime >>> locale.setlocale(locale.LC_ALL, 'en_IE.utf-8') 'en_IE.utf-8' >>> print datetime.datetime.now().strftime('%X') 12:22:43 >>> locale.setlocale(locale.LC_ALL, 'zh_TW.utf-8') 'zh_TW.utf-8' >>> print datetime.datetime.now().strftime('%X') 12?22?58? The only way I can think of doing this is attempting to parse the output of locale.nl_langinfo(locale.T_FMT) and strip out the seconds bit, but that brings it's own trickery. >>> print locale.nl_langinfo(locale.T_FMT) %H?%M?%S? >>> locale.setlocale(locale.LC_ALL, 'en_IE.utf-8') 'en_IE.utf-8' >>> print locale.nl_langinfo(locale.T_FMT) %T

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  • python- scipy optimization

    - by pear
    In scipy fmin_slsqp (Sequential Least Squares Quadratic Programming), I tried reading the code 'slsqp.py' provided with the scipy package, to find what are the criteria to get the exit_modes 0? I cannot find which statements in the code produce this exit mode? Please help me 'slsqp.py' code as follows, exit_modes = { -1 : "Gradient evaluation required (g & a)", 0 : "Optimization terminated successfully.", 1 : "Function evaluation required (f & c)", 2 : "More equality constraints than independent variables", 3 : "More than 3*n iterations in LSQ subproblem", 4 : "Inequality constraints incompatible", 5 : "Singular matrix E in LSQ subproblem", 6 : "Singular matrix C in LSQ subproblem", 7 : "Rank-deficient equality constraint subproblem HFTI", 8 : "Positive directional derivative for linesearch", 9 : "Iteration limit exceeded" } def fmin_slsqp( func, x0 , eqcons=[], f_eqcons=None, ieqcons=[], f_ieqcons=None, bounds = [], fprime = None, fprime_eqcons=None, fprime_ieqcons=None, args = (), iter = 100, acc = 1.0E-6, iprint = 1, full_output = 0, epsilon = _epsilon ): # Now do a lot of function wrapping # Wrap func feval, func = wrap_function(func, args) # Wrap fprime, if provided, or approx_fprime if not if fprime: geval, fprime = wrap_function(fprime,args) else: geval, fprime = wrap_function(approx_fprime,(func,epsilon)) if f_eqcons: # Equality constraints provided via f_eqcons ceval, f_eqcons = wrap_function(f_eqcons,args) if fprime_eqcons: # Wrap fprime_eqcons geval, fprime_eqcons = wrap_function(fprime_eqcons,args) else: # Wrap approx_jacobian geval, fprime_eqcons = wrap_function(approx_jacobian, (f_eqcons,epsilon)) else: # Equality constraints provided via eqcons[] eqcons_prime = [] for i in range(len(eqcons)): eqcons_prime.append(None) if eqcons[i]: # Wrap eqcons and eqcons_prime ceval, eqcons[i] = wrap_function(eqcons[i],args) geval, eqcons_prime[i] = wrap_function(approx_fprime, (eqcons[i],epsilon)) if f_ieqcons: # Inequality constraints provided via f_ieqcons ceval, f_ieqcons = wrap_function(f_ieqcons,args) if fprime_ieqcons: # Wrap fprime_ieqcons geval, fprime_ieqcons = wrap_function(fprime_ieqcons,args) else: # Wrap approx_jacobian geval, fprime_ieqcons = wrap_function(approx_jacobian, (f_ieqcons,epsilon)) else: # Inequality constraints provided via ieqcons[] ieqcons_prime = [] for i in range(len(ieqcons)): ieqcons_prime.append(None) if ieqcons[i]: # Wrap ieqcons and ieqcons_prime ceval, ieqcons[i] = wrap_function(ieqcons[i],args) geval, ieqcons_prime[i] = wrap_function(approx_fprime, (ieqcons[i],epsilon)) # Transform x0 into an array. x = asfarray(x0).flatten() # Set the parameters that SLSQP will need # meq = The number of equality constraints if f_eqcons: meq = len(f_eqcons(x)) else: meq = len(eqcons) if f_ieqcons: mieq = len(f_ieqcons(x)) else: mieq = len(ieqcons) # m = The total number of constraints m = meq + mieq # la = The number of constraints, or 1 if there are no constraints la = array([1,m]).max() # n = The number of independent variables n = len(x) # Define the workspaces for SLSQP n1 = n+1 mineq = m - meq + n1 + n1 len_w = (3*n1+m)*(n1+1)+(n1-meq+1)*(mineq+2) + 2*mineq+(n1+mineq)*(n1-meq) \ + 2*meq + n1 +(n+1)*n/2 + 2*m + 3*n + 3*n1 + 1 len_jw = mineq w = zeros(len_w) jw = zeros(len_jw) # Decompose bounds into xl and xu if len(bounds) == 0: bounds = [(-1.0E12, 1.0E12) for i in range(n)] elif len(bounds) != n: raise IndexError, \ 'SLSQP Error: If bounds is specified, len(bounds) == len(x0)' else: for i in range(len(bounds)): if bounds[i][0] > bounds[i][1]: raise ValueError, \ 'SLSQP Error: lb > ub in bounds[' + str(i) +'] ' + str(bounds[4]) xl = array( [ b[0] for b in bounds ] ) xu = array( [ b[1] for b in bounds ] ) # Initialize the iteration counter and the mode value mode = array(0,int) acc = array(acc,float) majiter = array(iter,int) majiter_prev = 0 # Print the header if iprint >= 2 if iprint >= 2: print "%5s %5s %16s %16s" % ("NIT","FC","OBJFUN","GNORM") while 1: if mode == 0 or mode == 1: # objective and constraint evaluation requird # Compute objective function fx = func(x) # Compute the constraints if f_eqcons: c_eq = f_eqcons(x) else: c_eq = array([ eqcons[i](x) for i in range(meq) ]) if f_ieqcons: c_ieq = f_ieqcons(x) else: c_ieq = array([ ieqcons[i](x) for i in range(len(ieqcons)) ]) # Now combine c_eq and c_ieq into a single matrix if m == 0: # no constraints c = zeros([la]) else: # constraints exist if meq > 0 and mieq == 0: # only equality constraints c = c_eq if meq == 0 and mieq > 0: # only inequality constraints c = c_ieq if meq > 0 and mieq > 0: # both equality and inequality constraints exist c = append(c_eq, c_ieq) if mode == 0 or mode == -1: # gradient evaluation required # Compute the derivatives of the objective function # For some reason SLSQP wants g dimensioned to n+1 g = append(fprime(x),0.0) # Compute the normals of the constraints if fprime_eqcons: a_eq = fprime_eqcons(x) else: a_eq = zeros([meq,n]) for i in range(meq): a_eq[i] = eqcons_prime[i](x) if fprime_ieqcons: a_ieq = fprime_ieqcons(x) else: a_ieq = zeros([mieq,n]) for i in range(mieq): a_ieq[i] = ieqcons_prime[i](x) # Now combine a_eq and a_ieq into a single a matrix if m == 0: # no constraints a = zeros([la,n]) elif meq > 0 and mieq == 0: # only equality constraints a = a_eq elif meq == 0 and mieq > 0: # only inequality constraints a = a_ieq elif meq > 0 and mieq > 0: # both equality and inequality constraints exist a = vstack((a_eq,a_ieq)) a = concatenate((a,zeros([la,1])),1) # Call SLSQP slsqp(m, meq, x, xl, xu, fx, c, g, a, acc, majiter, mode, w, jw) # Print the status of the current iterate if iprint > 2 and the # major iteration has incremented if iprint >= 2 and majiter > majiter_prev: print "%5i %5i % 16.6E % 16.6E" % (majiter,feval[0], fx,linalg.norm(g)) # If exit mode is not -1 or 1, slsqp has completed if abs(mode) != 1: break majiter_prev = int(majiter) # Optimization loop complete. Print status if requested if iprint >= 1: print exit_modes[int(mode)] + " (Exit mode " + str(mode) + ')' print " Current function value:", fx print " Iterations:", majiter print " Function evaluations:", feval[0] print " Gradient evaluations:", geval[0] if not full_output: return x else: return [list(x), float(fx), int(majiter), int(mode), exit_modes[int(mode)] ]

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  • Python - Blackjack

    - by user335932
    def showCards(): #SUM sum = playerCards[0] + playerCards[1] #Print cards print "Player's Hand: " + str(playerCards) + " : " + "sum print "Dealer's Hand: " + str(compCards[0]) + " : " + "sum" compCards = [Deal(),Deal()] playerCards = [Deal(),Deal()] How can i add up the interger element of a list containing to values? under #SUM error is can combine lists like ints...

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  • [Python] - Getting data from external program

    - by Kenny M.
    Hey, I need a method to get the data from an external editor. def _get_content(): from subprocess import call file = open(file, "w").write(some_name) call(editor + " " + file, shell=True) file.close() file = open(file) x = file.readlines() [snip] I personally think this is a very ugly way. You see I need to interact with an external editor and get the data. Do you know any better approaches/have better ideas?

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  • Python: deleting rows in a text file

    - by Jenny
    A sample of the following text file i have is: > 1 -4.6 -4.6 -7.6 > > 2 -1.7 -3.8 -3.1 > > 3 -1.6 -1.6 -3.1 the data is separated by tabs in the text file and the first column indicates the position. I need to iterate through every value in the text file apart from column 0 and find the lowest value. once the lowest value has been found that value needs to be written to a new text file along with the column name and position. Column 0 has the name "position" Column 1 "fifteen", column 2 "sixteen" and column 3 "seventeen" for example the lowest value in the above data is "-7.6" and is in column 3 which has the name "seventeen". Therefore "7.6", "seventeen" and its position value which in this case is 1 need to be written to the new text file. I then need a number of rows deleted from the above text file. E.G. the lowest value above is "-7.6" and is found at position "1" and is found in column 3 which as the name "seventeen". I therefore need seventeen rows deleted from the text file starting from and including position 1 so the the column in which the lowest value is found denotes the amount of rows that needs to be deleted and the position it is found at states the start point of the deletion

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  • strange behavior in python

    - by fsm
    The tags might not be accurate since I am not sure where the problem is. I have a module where I am trying to read some data from a socket, and write the results into a file (append) It looks something like this, (only relevant parts included) if __name__ == "__main__": <some init code> for line in file: t = Thread(target=foo, args=(line,)) t.start() while nThreads > 0: time.sleep(1) Here are the other modules, def foo(text): global countLock, nThreads countLock.acquire() nThreads += 1 countLock.release() """connect to socket, send data, read response""" writeResults(text, result) countLock.acquire() nThreads -= 1 countLock.release() def writeResults(text, result): """acquire file lock""" """append to file""" """release file lock""" Now here's the problem. Initially, I had a typo in the function 'foo', where I was passing the variable 'line' to writeResults instead of 'text'. 'line' is not defined in the function foo, it's defined in the main block, so I should have seen an error, but instead, it worked fine, except that the data was appended to the file multiple times, instead of being written just once, which is the required behavior, which I got when I fixed the typo. My question is, 1) Why didn't I get an error? 2) Why was the writeResults function being called multiple times?

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  • Python: Figure out local timezone

    - by Adam Matan
    I want to compare UTC timestamps from a log file with local timestamps. When creating the local datetime object, I use something like: >>> local_time=datetime.datetime(2010, 4, 27, 12, 0, 0, 0, tzinfo=pytz.timezone('Israel')) I want to find an automatic tool that would replace thetzinfo=pytz.timezone('Israel') with the current local time zone. Any ideas?

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  • Accessing Class Variables from a List in a nice way in Python

    - by Dennis
    Suppose I have a list X = [a, b, c] where a, b, c are instances of the same class C. Now, all these instances a,b,c, have a variable called v, a.v, b.v, c.v ... I simply want a list Y = [a.v, b.v, c.v] Is there a nice command to do this? The best way I can think of is: Y = [] for i in X Y.append(i.v) But it doesn't seem very elegant ~ since this needs to be repeated for any given "v" Any suggestions? I couldn't figure out a way to use "map" to do this.

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  • Most efficient way to search the last x lines of a file in python

    - by Harley
    I have a file and I don't know how big it's going to be (it could be quite large, but the size will vary greatly). I want to search the last 10 lines or so to see if any of them match a string. I need to do this as quickly and efficiently as possible and was wondering if there's anything better than: s = "foo" last_bit = fileObj.readlines()[-10:] for line in last_bit: if line == s: print "FOUND"

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  • python object AttributeError: type object 'Track' has no attribute 'title'

    - by ccwhite1
    I apologize if this is a noob question, but I can't seem to figure this one out. I have defined an object that defines a music track (NOTE: originally had the just ATTRIBUTE vs self.ATTRIBUTE. I edited those values in to help remove confusion. They had no affect on the problem) class Track(object): def __init__(self, title, artist, album, source, dest): """ Model of the Track Object Contains the followign attributes: 'Title', 'Artist', 'Album', 'Source', 'Dest' """ self.atrTitle = title self.atrArtist = artist self.atrAlbum = album self.atrSource = source self.atrDest = dest I use ObjectListView to create a list of tracks in a specific directory ....other code.... self.aTrack = [Track(sTitle,sArtist,sAlbum,sSource, sDestDir)] self.TrackOlv.AddObjects(self.aTrack) ....other code.... Now I want to iterate the list and print out a single value of each item list = self.TrackOlv.GetObjects() for item in list: print item.atrTitle This fails with the error AttributeError: type object 'Track' has no attribute 'atrTitle' What really confuses me is if I highlight a single item in the Object List View display and use the following code, it will correctly print out the single value for the highlighted item list = self.TrackOlv.GetSelectedObject() print list.atrTitle

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  • Extract strings in python

    - by shadyabhi
    Basically, I want to extract the strings "AAA", "BBB", "CCC", "DDD" from a text file.. ...... (other text goes here)..... <TD align="left" class=texttd><font class='textfont'>AAA</font></TD> ..... (useless text here)..... <TD align="left" class=texttd><font class='textfont'>BBB</font></TD> ....(more text)..... <TD align="left" class=texttd><font class='textfont'>CCC</font></TD> <TD align="left" class=texttd><font class='textfont'>DDD</font></TD> ......(more text)..... I want something like if I do:- data = foo("file.txt") i get:- data = ['AAA','BBB','CCC','DDD'] What is the best possible way? My file is not big..

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  • Python - Nested List to Tab Delimited File?

    - by Seafoid
    Hi, I have a nested list comprising ~30,000 sub-lists, each with three entries, e.g., nested_list = [['x', 'y', 'z'], ['a', 'b', 'c']]. I wish to create a function in order to output this data construct into a tab delimited format, e.g., x y z a b c Any help greatly appreciated! Thanks in advance, Seafoid.

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  • python appengine form-posted utf8 file issue

    - by khany
    hi, i am trying to form-post a sql file that consists on many INSERTS, eg. INSERT INTO `TABLE` VALUES ('abcdé', 2759); then i use re.search to parse it and extract the fields to put into my own datastore. The problem is that, although the file contains accented characters (see the e is a é), once uploaded it loses it and either errors or stores a bytestring representation of it. Heres what i am currently using (and I have tried loads of alternatives): form = cgi.FieldStorage() uFile = form['sql'] uSql = uFile.file.read() lineX = uSql.split("\n") # to get each line and so on. has anyone got a robust way of making this work? remember i am on appengine so access to some libraries is restricted/forbidden

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  • Python nested function scopes

    - by Thomas O
    I have code like this: def write_postcodes(self): """Write postcodes database. Write data to file pointer. Data is ordered. Initially index pages are written, grouping postcodes by the first three characters, allowing for faster searching.""" status("POSTCODE", "Preparing to sort...", 0, 1) # This function returns the key of x whilst updating the displayed # status of the sort. ctr = 0 def keyfunc(x): ctr += 1 status("POSTCODE", "Sorting postcodes", ctr, len(self.postcodes)) return x sort_res = self.postcodes[:] sort_res.sort(key=keyfunc) But ctr responds with a NameError: Traceback (most recent call last): File "PostcodeWriter.py", line 53, in <module> w.write_postcodes() File "PostcodeWriter.py", line 47, in write_postcodes sort_res.sort(key=keyfunc) File "PostcodeWriter.py", line 43, in keyfunc ctr += 1 UnboundLocalError: local variable 'ctr' referenced before assignment How can I fix this? I thought nester scopes would have allowed me to do this. I've tried with 'global', but it still doesn't work.

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  • Python: date, time formatting

    - by TarGz
    I need to generate a local timestamp in a form of YYYYMMDDHHmmSSOHH'mm'. That OHH'mm' is one of +, -, Z and then there are hourhs and minutes followed by '. Please, how do I get such a timestamp, denoting both local time zone and possible daylight saving?

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  • How to read a string one letter at a time in python

    - by dan
    I need to convert a string inputed by a user into morse code. The way our professor wants us to do this is to read from a morseCode.txt file, seperate the letters from the morseCode into two lists, then convert each letter to morse code (inserting a new line when there is a space). I have the beginning. What it does is reads the morseCode.txt file and seperates the letters into a list [A, B, ... Z] and the codes into a list ['– – . . – –\n', '. – . – . –\n'...]. We haven't learned "sets" yet, so I can't use that. How would I then take the string that they inputed, go through letter by letter, and convert it to morse code? I'm a bit caught up. Here's what I have right now (not much at all...) morseCodeFile = open('morseCode.txt', 'r') letterList = [] codeList = [] line = morseCodeFile.readline() while line != '': letterList.append(line[0]) codeList.append(line[2:]) line = morseCodeFile.readline() morseCodeFile.close() userInput = input("Enter a string to be converted to morse code or press <enter> to quit ")

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  • Calling/selecting variables (float valued) with user input in Python

    - by Jonathan Straus
    I've been working on a computational physics project (plotting related rates of chemical reactants with respect to eachother to show oscillatory behavior) with a fair amount of success. However, one of my simulations involves more than two active oscillating agents (five, in fact) which would obviously be unsuitable for any single visual plot... My scheme was hence to have the user select which two reactants they wanted plotted on the x-axis and y-axis respectively. I tried (foolishly) to convert string input values into the respective variable names, but I guess I need a radically different approach if any exist? If it helps clarify any, here is part of my code: def coupledBrusselator(A, B, t_trial,display_x,display_y): t = 0 t_step = .01 X = 0 Y = 0 E = 0 U = 0 V = 0 dX = (A) - (B+1)*(X) + (X**2)*(Y) dY = (B)*(X) - (X**2)*(Y) dE = -(E)*(U) - (X) dU = (U**2)*(V) -(E+1)*(U) - (B)*(X) dV = (E)*(U) - (U**2)*(V) array_t = [0] array_X = [0] array_Y = [0] array_U = [0] array_V = [0] while t <= t_trial: X_1 = X + (dX)*(t_step/2) Y_1 = Y + (dY)*(t_step/2) E_1 = E + (dE)*(t_step/2) U_1 = U + (dU)*(t_step/2) V_1 = V + (dV)*(t_step/2) dX_1 = (A) - (B+1)*(X_1) + (X_1**2)*(Y_1) dY_1 = (B)*(X_1) - (X_1**2)*(Y_1) dE_1 = -(E_1)*(U_1) - (X_1) dU_1 = (U_1**2)*(V_1) -(E_1+1)*(U_1) - (B)*(X_1) dV_1 = (E_1)*(U_1) - (U_1**2)*(V_1) X_2 = X + (dX_1)*(t_step/2) Y_2 = Y + (dY_1)*(t_step/2) E_2 = E + (dE_1)*(t_step/2) U_2 = U + (dU_1)*(t_step/2) V_2 = V + (dV_1)*(t_step/2) dX_2 = (A) - (B+1)*(X_2) + (X_2**2)*(Y_2) dY_2 = (B)*(X_2) - (X_2**2)*(Y_2) dE_2 = -(E_2)*(U_2) - (X_2) dU_2 = (U_2**2)*(V_2) -(E_2+1)*(U_2) - (B)*(X_2) dV_2 = (E_2)*(U_2) - (U_2**2)*(V_2) X_3 = X + (dX_2)*(t_step) Y_3 = Y + (dY_2)*(t_step) E_3 = E + (dE_2)*(t_step) U_3 = U + (dU_2)*(t_step) V_3 = V + (dV_2)*(t_step) dX_3 = (A) - (B+1)*(X_3) + (X_3**2)*(Y_3) dY_3 = (B)*(X_3) - (X_3**2)*(Y_3) dE_3 = -(E_3)*(U_3) - (X_3) dU_3 = (U_3**2)*(V_3) -(E_3+1)*(U_3) - (B)*(X_3) dV_3 = (E_3)*(U_3) - (U_3**2)*(V_3) X = X + ((dX + 2*dX_1 + 2*dX_2 + dX_3)/6) * t_step Y = Y + ((dX + 2*dY_1 + 2*dY_2 + dY_3)/6) * t_step E = E + ((dE + 2*dE_1 + 2*dE_2 + dE_3)/6) * t_step U = U + ((dU + 2*dU_1 + 2*dY_2 + dE_3)/6) * t_step V = V + ((dV + 2*dV_1 + 2*dV_2 + dE_3)/6) * t_step dX = (A) - (B+1)*(X) + (X**2)*(Y) dY = (B)*(X) - (X**2)*(Y) t_step = .01 / (1 + dX**2 + dY**2) ** .5 t = t + t_step array_X.append(X) array_Y.append(Y) array_E.append(E) array_U.append(U) array_V.append(V) array_t.append(t) where previously display_x = raw_input("Choose catalyst you wish to analyze in the phase/field diagrams (X, Y, E, U, or V) ") display_y = raw_input("Choose one other catalyst from list you wish to include in phase/field diagrams ") coupledBrusselator(A, B, t_trial, display_x, display_y) Thanks!

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  • Python: split a list based on a condition?

    - by Parand
    What's the best way, both aesthetically and from a performance perspective, to split a list of items into multiple lists based on a conditional? The equivalent of: good = [x for x in mylist if x in goodvals] bad = [x for x in mylist if x not in goodvals] is there a more elegant way to do this? Update: here's the actual use case, to better explain what I'm trying to do: # files looks like: [ ('file1.jpg', 33L, '.jpg'), ('file2.avi', 999L, '.avi'), ... ] IMAGE_TYPES = ('.jpg','.jpeg','.gif','.bmp','.png') images = [f for f in files if f[2].lower() in IMAGE_TYPES] anims = [f for f in files if f[2].lower() not in IMAGE_TYPES]

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  • how to get obj2.name via obj1.categories(), thanks (gae python)

    - by zjm1126
    i using google-app-engine webapp ,code is : class Post(db.Model): title = db.StringProperty(required=True) def categories(self): return (x.category for x in self.postcategory_set) class Category(db.Model): name = db.StringProperty() class PostCategory(db.Model): post = db.ReferenceProperty(Post) category = db.ReferenceProperty(Category) class sss(webapp.RequestHandler): def get(self): obj1 = Post(title='hhaa') #obj1.title = 'haha' obj1.put() obj2 = Category() obj2.name='haha-kao' obj2.put() obj3=PostCategory() obj3.post=obj1 obj3.category=obj2 obj3.put() self.response.out.write(obj1.categories().get().name) the error is : Traceback (most recent call last): File "D:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 511, in __call__ handler.get(*groups) File "D:\zjm_code\helloworld\a.py", line 131, in get self.response.out.write(obj1.categories().get().name) AttributeError: 'generator' object has no attribute 'get' so how to get the obj2.name via obj1's method thanks

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  • python multithreading for dummies

    - by albruno
    trying to find a simple example that clearly shows a single task being divided for multi-threading. Quite frankly... many of the examples are overly sophisticated thus.... making the flow tougher to play with... anyone care to share their breakthrough sample or point to an example? As well, what is the best docs? many google lookups are too specific (for me at this stage) Thanks in advance.

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