Search Results

Search found 33869 results on 1355 pages for 'python install'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 160/1355 | < Previous Page | 156 157 158 159 160 161 162 163 164 165 166 167  | Next Page >

  • Python: Beginning problems

    - by Blogger
    ok so basically i very new to programming and have no idea how to go about these problems help if you will ^^ Numerologists claim to be able to determine a person’s character traits based on the “numeric value” of a name. The value of a name is determined by summing up the values of the letters of the name, where ‘a’ is 1, ‘b’ is 2, ‘c’ is 3 etc., up to ‘z’ being 26. For example, the name “Zelle” would have the value 26 + 5 + 12 + 12 + 5 = 60 (which happens to be a very suspicious number, by the way). Write a program that calculates the numeric value of a single name provided as input. Word count. A common utility on Unix/Linux systems is a small program called “wc”. This program counts the number of lines, words (strings of characters separated by blanks, tabs, or new lines), and characters in a file. Write your own version of this program. The program should accept a file name as input and then print three numbers showing the count of lines, words, and characters in the file.

    Read the article

  • Python thinks I'm a different IP

    - by Yongho
    I'm trying to set a page that displays the visitor's IP. All the methods I have tried show an IP different from the IP my computer has. I've tried: Looking up http://www.whatismyip.com/automation/n09230945.asp Using socket.getaddrinfo(socket.gethostname(), None)[0][4][0] How can I find the real IP of the visitor?

    Read the article

  • Sort a python dict

    - by ensnare
    I have a list of dictionaries: [{'title':'New York Times', 'title_url':'New_York_Times','id':4}, {'title':'USA Today','title_url':'USA_Today','id':6}, {'title':'Apple News','title_url':'Apple_News','id':2}] I'd like to sort it by the title, so elements with A go before Z: [{'title':'Apple News','title_url':'Apple_News','id':2}, {'title':'New York Times', 'title_url':'New_York_Times','id':4}, {'title':'USA Today','title_url':'USA_Today','id':6}] What's the best way to do this? Also, is there a way to ensure the order of each dictionary key stays constant, e.g., always title, title_url, then id? Thank you.

    Read the article

  • Add entry to list and remove first one in Python

    - by wagglewax
    I have a list of about 40 entries. And I frequently want to append an item to the start of the list (with id 0) and want to delete the last entry (with id 40) of the list. how do i do this the best? like: (example with 5 entries) [0] = "herp" [1] = "derp" [2] = "blah" [3] = "what" [4] = "da..." after adding "wuggah" and deleting last it should be like: [0] = "wuggah" [1] = "herp" [2] = "derp" [3] = "blah" [4] = "what" or appending one and deleting first. And I don't want to end up manually moving them one after another all of the entries to the next id.

    Read the article

  • Python large variable RAM useage

    - by PPTim
    Hi, Say there is a dict variable that grows very large during runtime- up into millions of key:value pairs. Does this variable get stored in RAM,effectively using up all the available memory and slowing down the rest of the system? Asking the interpreter to display the entire dict is a bad idea, but would it be okay as long as one key is accessed at a time? Tim

    Read the article

  • Hierarchy / Flyweight / Instancing Problem in Python

    - by Dan
    Here is the problem I am trying to solve, (I have simplified the actual problem, but this should give you all the relevant information). I have a hierarchy like so: 1.A 1.B 1.C 2.A 3.D 4.B 5.F (This is hard to illustrate - each number is the parent, each letter is the child). Creating an instance of the 'letter' objects is expensive (IO, database costs, etc), so should only be done once. The hierarchy needs to be easy to navigate. Children in the hierarchy need to have just one parent. Modifying the contents of the letter objects should be possible directly from the objects in the hierarchy. There needs to be a central store containing all of the 'letter' objects (and only those in the hierarchy). 'letter' and 'number' objects need to be possible to create from a constructor (such as Letter(**kwargs) ). It is perfectably acceptable to expect that when a letter changes from the hierarchy, all other letters will respect the same change. Hope this isn't too abstract to illustrate the problem. What would be the best way of solving this? (Then I'll post my solution) Here's an example script: one = Number('one') a = Letter('a') one.addChild(a) two = Number('two') a = Letter('a') two.addChild(a) for child in one: child.method1() for child in two: print '%s' % child.method2()

    Read the article

  • Python GUI does not update until entire process is finished

    - by ccwhite1
    I have a process that gets a files from a directory and puts them in a list. It then iterates that list in a loop. The last line of the loop being where it should update my gui display, then it begins the loop again with the next item in the list. My problem is that it does not actually update the gui until the entire process is complete, which depending on the size of the list could be 30 seconds to over a minute. This gives the feeling of the program being 'hung' What I wanted it to do was to process one line in the list, update the gui and then continue. Where did I go wrong? The line to update the list is # Populate listview with drive contents. The print statements are just for debug. def populateList(self): print "populateList" sSource = self.txSource.Value sDest = self.txDest.Value # re-intialize listview and validated list self.listView1.DeleteAllItems() self.validatedMove = None self.validatedMove = [] #Create list of files listOfFiles = getList(sSource) #prompt if no files detected if listOfFiles == []: self.lvActions.Append([datetime.datetime.now(),"Parse Source for .MP3 files","No .MP3 files in source directory"]) #Populate list after both Source and Dest are chosen if len(sDest) > 1 and len(sDest) > 1: print "-iterate listOfFiles" for file in listOfFiles: sFilename = os.path.basename(file) sTitle = getTitle(file) sArtist = getArtist(file) sAlbum = getAblum(file) # Make path = sDest + Artist + Album sDestDir = os.path.join (sDest, sArtist) sDestDir = os.path.join (sDestDir, sAlbum) #If file exists change destination to *.copyX.mp3 sDestDir = self.defineDestFilename(os.path.join(sDestDir,sFilename)) # Populate listview with drive contents self.listView1.Append([sFilename,sTitle,sArtist,sAlbum,sDestDir]) #populate list to later use in move command self.validatedMove.append([file,sDestDir]) print "-item added to SourceDest list" else: print "-list not iterated"

    Read the article

  • Python regex on list

    - by Peter Nielsen
    Hi there I am trying to build a parser and save the results as an xml file but i have problems.. For instance i get a TypeError: expected string or buffer when i try to run the code.. Would you experts please have a look at my code ? import urllib2, re from xml.dom.minidom import Document from BeautifulSoup import BeautifulSoup as bs osc = open('OSCTEST.html','r') oscread = osc.read() soup=bs(oscread) doc = Document() root = doc.createElement('root') doc.appendChild(root) countries = doc.createElement('countries') root.appendChild(countries) findtags1 = re.compile ('<h1 class="title metadata_title content_perceived_text(.*?)</h1>', re.DOTALL | re.IGNORECASE).findall(soup) findtags2 = re.compile ('<span class="content_text">(.*?)</span>', re.DOTALL | re.IGNORECASE).findall(soup) for header in findtags1: title_elem = doc.createElement('title') countries.appendChild(title_elem) header_elem = doc.createTextNode(header) title_elem.appendChild(header_elem) for item in findtags2: art_elem = doc.createElement('artikel') countries.appendChild(art_elem) s = item.replace('<P>','') t = s.replace('</P>','') text_elem = doc.createTextNode(t) art_elem.appendChild(text_elem) print doc.toprettyxml()

    Read the article

  • Split a string in python taking care of quotes

    - by santu
    I want to extract key value pairs of some form elements in a html page for example name="frmLogin" method="POST" onSubmit="javascript:return validateAndSubmit();" action="TG_cim_logon.asp?SID=^YcMunDFDQUoWV32WPUMqPxeSxD4L_slp_rhc_rNvW7Fagp7FgH3l0uJR/3_slp_rhc_dYyJ_slp_rhc_vsPW0kJl&RegType=Lite_Home" is there any method using which I can safely get the key and value pairs. I tried using splitting by spaces and then using '=' characters but string inside quotes can also have '='. is there any different kind of split method which can also take care of quotes?

    Read the article

  • Python beginner, strange output problem

    - by Protean
    I'm having a weird problem with the following piece of code. from math import sqrt def Permute(array): result1 = [] result2 = [] if len(array) <= 1: return array for subarray in Permute(array[1:]): for i in range(len(array)): temp1 = subarray[:i]+array[0]+subarray[i:] temp2 = [0] for num in range(len(array)-1): temp2[0] += (sqrt(pow((temp1[num+1][1][0]-temp1[num][1][0]),2) + pow((temp1[num+1][1][1]-temp1[num][1][1]),2))) result1.append(temp1+temp2) return result1 a = [['A',[50,1]]] b = [['B',[1,1]]] c = [['C',[100,1]]] array = [a,b,c] result1 = Permute(array) for i in range(len(result1)): print (result1[i]) print (len(result1)) What it does is find all the permutations of the points abc and then returns them along with the sum of the distances between each ordered point. It does this; however, it also seems to report a strange additional value, 99. I figure that the 99 is coming from the computation of the distance between point a and c but I don't understand why it is appearing in the final output as it does.

    Read the article

  • How to control a subthread process in python?

    - by SpawnCxy
    Code first: '''this is main structure of my program''' from twisted.web import http from twisted.protocols import basic import threading threadstop = False #thread trigger,to be done class MyThread(threading.Thread): def __init__(self): threading.Thread.__init__(self) self.start() def run(self): while True: if threadstop: return dosomething() '''def some function''' if __name__ == '__main__': from twisted.internet import reactor t = MyThread() reactor.listenTCP(serverport,myHttpFactory()) reactor.run() As my first multithread program,I feel happy that it works as expected.But now I find I cannot control it.If I run it on front,Control+C can only stop the main process,and I can still find it in processlist;if I run it in background,I have to use kill -9 pid to stop it.And I wonder if there's a way to control the subthread process by a trigger variale,or a better way to stop the whole process other than kill -9.Thanks.

    Read the article

  • how to check the read write status of storing media in python

    - by mukul sharma
    Hi All, How can i check the read/ write permission of the file storing media? ie assume i have to write some file inside a directory and that directory may be available on read only media like (cd or dvd)or etc. So how can i check that storing media ( cd, hard disk) having a read only or read write both permission. I am using windows xp os. Thanks.

    Read the article

  • Python beginer having trouble running code

    - by Protean
    For some reason this code will not seem to run in the interpreter. When I hit F5 nothing happens, not even the debugger seems to recognize it. I assume it has something to do with the class, as when removed the interpreter seems to recognize the rest of the code. Please tell me what I am doing wrong. Edit: I have restarted the interpreter multiple times, any other piece of code I try to load runs fine, just this one is having trouble. print ('Why won't this work?') class sorting_class: def __init__(self): self.order = ['a', 'b', 'c', 'd'] self.globali = 0 self.orderi = 0 self.sortedlist = [] def sort(self, array): carry, leave = [] for arrayi in array: print ('run', arrayi) if self.order[self.orderi] == arrayi[self.globali]: carry.append(arrayi) else: if self.globali != 0: leave.append(arrayi) return carry, leave def srt(self, array): globalii = 0 carry, leave = my.sort(array) while len(self.sortedlist) != len(array): if len(self.carry) == 1: self.sortedlist.append(carry) arrayt = leave self.globali = 1 self.orderi = 0 carry, leave = my.sort(arrayt) elif len(self.carry) == 0: if len(self.leave) != 0: arrayt = leave self.globali = 1 self.orderi += 1 my.sort(arrayt) else: self.arrayt globalii += 1 self.orderi = globalii self.globali = 0 my.sort(arrayt) self.orderi = 0 else: arrayt = carry carry = [] self.globali += 1 carry, leave += my.sort(arrayt) my = sorting_class() x = ['ac', 'bc' ,'ab', 'da'] my.srt(x)

    Read the article

  • Python PyQT4 - Adding an unknown number of QComboBox widgets to QGridLayout

    - by ZZ
    Hi all, I want to retrieve a list of people's names from a queue and, for each person, place a checkbox with their name to a QGridLayout using the addWidget() function. I can successfully place the items in a QListView, but they just write over the top of each other rather than creating a new row. Does anyone have any thoughts on how I could fix this? self.chk_People = QtGui.QListView() items = self.jobQueue.getPeopleOffQueue() for item in items: QtGui.QCheckBox('%s' % item, self.chk_People) self.jobQueue.getPeopleOffQueue() would return something like ['Bob', 'Sally', 'Jimmy'] if that helps.

    Read the article

  • python __import__ problem

    - by Anurag Uniyal
    I have a messages folder(package) with __init__.py file and another module messages_en.py inside it. In __init__.py if I import messages_en it works, but __import__ fails with "ImportError: No module named messages_en" import messages_en # it works messages = __import__('messages_en') # it doesn't ? I used to think 'import x' is just another way of saying __import__('x')

    Read the article

  • python multiprocess update dictionary synchronously

    - by user1050325
    I am trying to update one common dictionary through multiple processes. Could you please help me find out what is the problem with this code? I get the following output: inside function {1: 1, 2: -1} comes here inside function {1: 0, 2: 2} comes here {1: 0, 2: -1} Thanks. from multiprocessing import Lock, Process, Manager l= Lock() def computeCopyNum(test,val): l.acquire() test[val]=val print "inside function" print test l.release() return a=dict({1: 0, 2: -1}) procs=list() for i in range(1,3): p = Process(target=computeCopyNum, args=(a,i)) procs.append(p) p.start() for p in procs: p.join() print "comes here" print a

    Read the article

  • Python regular expression help

    - by dlw
    Hi SO, I can't seem to create the correct regular expression to extract the correct tokens from my string. Padding the beginning of the string with a space generates the correct output, but seems less than optimal: >>> import re >>> s = '-edge_0triggered a-b | -level_Sensitive c-d | a-b-c' >>> re.findall(r'\W(-[\w_]+)',' '+s) ['-edge_0triggered', '-level_Sensitive'] # correct output Here are some of the regular expressions I've tried, does anyone have a regex suggestion that doesn't involve changing the original string and generates the correct output >>> re.findall(r'(-[\w_]+)',s) ['-edge_0triggered', '-b', '-level_Sensitive', '-d', '-b', '-c'] >>> re.findall(r'\W(-[\w_]+)',s) ['-level_Sensitive'] Thanks -- DW

    Read the article

  • [Python]Download an image embedded in a mime multipart message

    - by michele
    Hi, I have to download some images from links. This links return me a file where is embedded a multipart mime and a tiff image. I have writed this code but it downloads the file with mime. How I can remove the mime from this file and have the image returned? Can I do this with wget or curl? My code: def download(url,local): import urllib urllib.urlretrieve(url,local) urllib.urlcleanup() Thanks a lot.

    Read the article

  • DEADLOCK_WRAP error when using Berkeley Db in python (bsddb)

    - by JiminyCricket
    I am using a berkdb to store a huge list of key-value pairs but for some reason when i try to access some of the data later i get this error: try: key = 'scrape011201-590652' contenttext = contentdict[key] except: print the error <type 'exceptions.KeyError'> 'scrape011201-590652' in contenttext = contentdict[key]\n', ' File "/usr/lib64/python2.5/bsddb/__init__.py", line 223, in __getitem__\n return _DeadlockWrap(lambda: self.db[key]) # self.db[key]\n', 'File "/usr/lib64/python2.5/bsddb/dbutils.py", line 62, in DeadlockWrap\n return function(*_args, **_kwargs)\n', ' File "/usr/lib64/python2.5/bsddb/__init__.py", line 223, in <lambda>\n return _DeadlockWrap(lambda: self.db[key]) # self.db[key]\n'] I am not sure what DeadlockWrap is but there isnt any other program or process accessing the berkdb or writing to it (as far as i know,) so not sure how we could get a deadlock, if its referring to that. Is it possible that I am trying to access the data to rapidly? I have this function call in a loop, so something like for i in hugelist: #try to get a value from the berkdb #do something with it I am running this with multiple datasets and this error only occurs with one of them, the largest one, not the others.

    Read the article

  • Best practice for Python Assert

    - by meade
    Is there a performance or code maintenance issue with using assert as part of the standard code instead of using it just for debugging purposes? Is assert x >= 0, 'x is less then zero' and better or worse then if x < 0: raise Exception, 'x is less then zero' Also, is there anyway to set a business rule like if x < 0 raise error that is always checked with out the try, except, finally so, if at anytime throughout the code x is < 0 an error is raised, like if you set assert x < 0 at the start of a function, anywhere within the function where x becomes less then 0 an exception is raised?

    Read the article

  • Python begineer confused by a piece of code

    - by Protean
    I understand the gist of the code, that it forms permutations; however, I was wondering if someone could explain exactly what is going on in the return statement. def perm(l): sz = len(l) print (l) if sz <= 1: print ('sz <= 1') return [l] return [p[:i]+[l[0]]+p[i:] for i in range(sz) for p in perm(l[1:])]

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 156 157 158 159 160 161 162 163 164 165 166 167  | Next Page >