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  • python multiprocess update dictionary synchronously

    - by user1050325
    I am trying to update one common dictionary through multiple processes. Could you please help me find out what is the problem with this code? I get the following output: inside function {1: 1, 2: -1} comes here inside function {1: 0, 2: 2} comes here {1: 0, 2: -1} Thanks. from multiprocessing import Lock, Process, Manager l= Lock() def computeCopyNum(test,val): l.acquire() test[val]=val print "inside function" print test l.release() return a=dict({1: 0, 2: -1}) procs=list() for i in range(1,3): p = Process(target=computeCopyNum, args=(a,i)) procs.append(p) p.start() for p in procs: p.join() print "comes here" print a

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  • Working with OAuth on Google with Python

    - by Dan Loewenherz
    I'm having a very frustrating time creating a valid signature for Google's OAuth implementation. I have narrowed it all down to the fact that my signature-generation code has an error of some sort; what it is I have no idea. This is the signature base string in its entirety: GET&https%3A%2F%2Fwww.google.com%2Faccounts%2FOAuthGetAccessToken&oauth_consumer_key%3Ddlosplayground.appspot.com%26oauth_nonce%3D72815d55697cb24301fab03e1f7f1d66%26oauth_signature_method%3DHMAC-SHA1%26oauth_timestamp%3D1274327867%26oauth_token%3D4%252FX2cZ54JuseQbgRwzTBzZ7lqIwqof%26oauth_verifier%3Dihf0F2Fx%252FpnCmwbVQnk2xMre%26oauth_version%3D1.0 The OAuth Playground returns an oauth_signature of gF8qAfWjpdKjKb4KR%2FvA2Gy0vhU%3D. My code gives me ikMpIKJQJ58jseg%2BKPBTecjmYPE%3D, so obviously I'm doing something wrong. Here's my signature generation code (equivalent to that of the standard oauth.py library): binascii.b2a_base64(hmac.new(CONSUMER_SECRET, BASE_STRING, hashlib.sha1).digest())[:-1] Any thoughts?

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  • Dynamic dispatch and inheritance in python

    - by Bill Zimmerman
    Hi, I'm trying to modify Guido's multimethod (dynamic dispatch code): http://www.artima.com/weblogs/viewpost.jsp?thread=101605 to handle inheritance and possibly out of order arguments. e.g. (inheritance problem) class A(object): pass class B(A): pass @multimethod(A,A) def foo(arg1,arg2): print 'works' foo(A(),A()) #works foo(A(),B()) #fails Is there a better way than iteratively checking for the super() of each item until one is found? e.g. (argument ordering problem) I was thinking of this from a collision detection standpoint. e.g. foo(Car(),Truck()) and foo(Truck(), Car()) and should both trigger foo(Car,Truck) # Note: @multimethod(Truck,Car) will throw an exception if @multimethod(Car,Truck) was registered first? I'm looking specifically for an 'elegant' solution. I know that I could just brute force my way through all the possibilities, but I'm trying to avoid that. I just wanted to get some input/ideas before sitting down and pounding out a solution. Thanks

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  • calling a function from another function in python

    - by user1040503
    I have written this function that takes to strings in order to see if they are anagrams: def anagram_check(str_x, str_y): x = string1.replace(" ","") y = string2.replace(" ","") lower1 = x.lower() lower2 = y.lower() sorted1 = sorted(lower1) sorted2 = sorted(lower2) if sorted1 == sorted2: return True else: return False this function works fine, the problem is that now I need to use this function in another function in order to find anagrams in a text file. I want to print a list of tuples with all the anagrams in it. this is what i have done so far def anagrams_finder(words_num): anagrams = [] f = open("words.txt") a = list(f) list1 = ([s.replace('\n', '') for s in a]) list2 = ([i.lower() for i in list1]) list3 = list2[0:words_num] #number of words from text that need to be checked. for i in list3: .... I tried using for loops, while loops, appand.... but nothing seems to work. how can I use the first function in order to help me with the second? Please help...

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  • Give a reference to a python instance attribute at class definition

    - by Guenther Jehle
    I have a class with attributes which have a reference to another attribute of this class. See class Device, value1 and value2 holding a reference to interface: class Interface(object): def __init__(self): self.port=None class Value(object): def __init__(self, interface, name): self.interface=interface self.name=name def get(self): return "Getting Value \"%s\" with interface \"%s\""%(self.name, self.interface.port) class Device(object): interface=Interface() value1=Value(interface, name="value1") value2=Value(interface, name="value2") def __init__(self, port): self.interface.port=port if __name__=="__main__": d1=Device("Foo") print d1.value1.get() # >>> Getting Value "value1" with interface "Foo" d2=Device("Bar") print d2.value1.get() # >>> Getting Value "value1" with interface "Bar" print d1.value1.get() # >>> Getting Value "value1" with interface "Bar" The last print is wrong, cause d1 should have the interface "Foo". I know whats going wrong: The line interface=Interface() line is executed, when the class definition is parsed (once). So every Device class has the same instance of interface. I could change the Device class to: class Device(object): interface=Interface() value1=Value(interface, name="value1") value2=Value(interface, name="value2") def __init__(self, port): self.interface=Interface() self.interface.port=port So this is also not working: The values still have the reference to the original interface instance and the self.interface is just another instance... The output now is: >>> Getting Value "value1" with interface "None" >>> Getting Value "value1" with interface "None" >>> Getting Value "value1" with interface "None" So how could I solve this the pythonic way? I could setup a function in the Device class to look for attributes with type Value and reassign them the new interface. Isn't this a common problem with a typical solution for it? Thanks!

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  • Youtube python: get thumbnail

    - by dkgirl
    Is there a simple way to get the default thumbnail from a youtube entry object gdata.youtube.YouTubeVideoEntry? I tried entry.media.thumbnail, but that gives me four thumbnail objects. Can I always trust that there are four? Can I know which is the default thumbnail that would also appears on the youtube search page? And how would I get that one? Or do I have to alter one of the other ones? When I know the video_id I use: http://i4.ytimg.com/vi/{{video_id}}/default.jpg so, it would also be helpful to get the video_id. Do I really have to parse one of the url's to get at the video_id ? It seems strange that they don't provide this information directly.

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  • Calling a method with getattr in Python

    - by brain_damage
    How to call a method using getattr? I want to create a metaclass, which can call non-existing methods of some other class that start with the word 'oposite_'. The method should have the same number of arguments, but to return the opposite result. def oposite(func): return lambda s, *args, **kw: not oposite(s, *args, **kw) class Negate(type): def __getattr__(self, name): if name.startswith('oposite_'): return oposite(self.__getattr__(name[8:])) def __init__(self,*args,**kwargs): self.__getattr__ = Negate.__getattr__ class P(metaclass=Negate): def yep(self): return True But the problem is that self.__getattr__(sth) returns a NoneType object. >>> p = P() >>> p.oposite_yep() Traceback (most recent call last): File "<pyshell#115>", line 1, in <module> p.oposite_yep() TypeError: <lambda>() takes at least 1 positional argument (0 given) How to deal with this?

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  • Appengine (python) returns empty for valid queries

    - by Grant
    I've got an app with around half a million 'records', each of which only stores three fields. I'd like to look up records by a string field with a query, but I'm running into problems. If I visit the console page, manually view a record and save it (without making changes) it shows up in a query: SELECT * FROM wordEntry WHERE wordStr = 'SomeString' If I don't do this, I get 'no results'. Does appengine need time to update? If so, how much? (I was also having trouble batch deleting and modifying data, but I was able to break the problem up into smaller chunks.)

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  • searching a list of tuples in python

    - by hdx
    So I have a list of tuple like: [(1,"juca"),(22,"james"),(53,"xuxa"),(44,"delicia")] I want this list for a tuple whose number value is equal to something. So that if I do search(53) it will return 2 Is is an easy way to do that?

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  • python decorator to add function to list in current scope

    - by AlexH
    Goal: Make a decorator which can modify the scope that it is used in. If it worked: class Blah(): # or perhaps class Blah(ParentClassWhichMakesThisPossible) def one(self): pass @decorated def two(self): pass Blah.decorated ["two"] Why? I essentially want to write classes which can maintain specific dictionaries of methods, so that I can retrieve lists of available methods of different types on a per class basis. errr..... I want to do this: class RuleClass(ParentClass): @rule def blah(self): pass @rule def kapow(self): pass def shazam(self): class OtherRuleClass(ParentClass): @rule def foo(self): pass def bar(self): pass RuleClass.rules.keys() ["blah", "kapow"] OtherRuleClass.rules.keys() ["foo"]

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  • problem with hierarchical clustering in Python

    - by user248237
    I am doing a hierarchical clustering a 2 dimensional matrix by correlation distance metric (i.e. 1 - Pearson correlation). My code is the following (the data is in a variable called "data"): from hcluster import * Y = pdist(data, 'correlation') cluster_type = 'average' Z = linkage(Y, cluster_type) dendrogram(Z) The error I get is: ValueError: Linkage 'Z' contains negative distances. What causes this error? The matrix "data" that I use is simply: [[ 156.651968 2345.168618] [ 158.089968 2032.840106] [ 207.996413 2786.779081] [ 151.885804 2286.70533 ] [ 154.33665 1967.74431 ] [ 150.060182 1931.991169] [ 133.800787 1978.539644] [ 112.743217 1478.903191] [ 125.388905 1422.3247 ]] I don't see how pdist could ever produce negative numbers when taking 1 - pearson correlation. Any ideas on this? thank you.

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  • Python decorator question

    - by nsharish
    decorator 1: def dec(f): def wrap(obj, *args, **kwargs): f(obj, *args,**kwargs) return wrap decorator 2: class dec: def __init__(self, f): self.f = f def __call__(self, obj, *args, **kwargs): self.f(obj, *args, **kwargs) A sample class, class Test: @dec def disp(self, *args, **kwargs): print(*args,**kwargs) The follwing code works with decorator 1 but not with decorator 2. a = Test() a.disp("Message") I dont understand why decorator 2 is not working here. Can someone help me with this?

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  • Python: For loop problem

    - by James
    I have a PSP page with html embedded. I need to place another for loop so i can insert another %s next to background-color: which will instert a appropriate colour to colour in the html table. For example i need to insert for z in colours so it can loop over the colours list and insert the correct colour. Where ever i try to insert the for loop it doesnt seem to work it most commonly colours each cell in the table 60 times then moves onto the next cell and repeats itself and crashes my web browser. The colours are held in a table called colours. code below: <table> <% s = ''.join(aa[i] for i in table if i in aa) for i in range(0, len(s), 60): req.write('<tr><td><TT>%04d</td>' % (i+1)); for k in s[i:i+60]: req.write('<TT><td><TT><font style="background-color:">%s<font></td>' % (k)); req.write('</TT></tr>') #end %> </table>

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  • Regex replace (in Python) - a more simple way?

    - by Evan Fosmark
    Any time I want to replace a piece of text that is part of a larger piece of text, I always have to do something like: "(?P<start>some_pattern)(?P<replace>foo)(?P<end>end)" And then concatenate the start group with the new data for replace and then the end group. Is there a better method for this?

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  • python list directory , subdirectory and files

    - by thomytheyon
    Hi Alls, I'm trying to make a script to list all directory, subdirectory, and files in a given directory. I tried this : import sys,os root="/home/patate/directory/" path=os.path.join(root,"targetdirectory") for r,d,f in os.walk(path): for file in f: print os.path.join(root,file) Unfortunatly it doesn't work properly, i get all the files, but not them complete path. like : if the dir struct would be : /home/patate/directory/targetdirectory/123/456/789/file.txt It would print: /home/patate/directory/targetdirectory/file.txt What i need is the first result, any help would be greatly appreciated ! Thanks

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  • python global variable not working in apache

    - by Suhail
    I am facing issue with the global variable, when i run in the django development server it works fine, but in apache it doesn't work here is the code below: red= "/foodfolio3/test/" def showAddRecipe(request): #global objc if "userid" in request.session: objc["ErrorMsgURL"]= "" try: urlList= request.POST URL= str(urlList['url']) URL= URL.strip('http://') URL= "http://" + URL recipe= __addRecipeUrl__(URL) if (recipe == 'FailToOpenURL') or (recipe == 'Invalid-website-URL'): #request.session["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" objc["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" print "here global_context =", objc arurl= HttpResponseRedirect("/foodfolio3/add/import/") arurl['ErrorMsgURL']= objc["ErrorMsgURL"] #return HttpResponseRedirect("/foodfolio3/add/import/") #return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) return (arurl) else: objc["recipe"] = recipe return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) except: objc["recipe"] = "" return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/" return HttpResponseRedirect("/foodfolio3/login") def showAddRecipeUrl(request): if "userid" in request.session: return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/import/" return HttpResponseRedirect("/foodfolio3/login") def showLogin(request): obj = {} obj["error_message"] = "" obj["registered"] = "" if request.method == "POST": if (red == "/foodfolio3/test"): next= '/foodfolio3/recipes' else: next= red try: username = request.POST['username'] password = request.POST['password'] user = authenticate(username=username, password=password) except: user = authenticate(request=request) if user is not None: if user.is_active: login(request, user) request.session["userid"] = user.id # Redirect to a success page. return HttpResponseRedirect(next) this code works fine in django development server, but in apache, the url is getting redirected to '/foodfolio3/recipes'

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  • Find&Replace using Python - Binary file

    - by Aaron Hoffman
    Hello, I'm attempting to do a "find and replace" in a file on a Mac OS X computer. Although it appears to work correctly. It seems that the file is somehow altered. The text editor that I use (Text Wrangler) is unable to even open the file once this is completed. Here is the code as I have it: import fileinput for line in fileinput.FileInput("testfile.txt",inplace=1): line = line.replace("newhost",host) print line, When I view the file from the terminal, it does say "testfile" may be a binary file. See it anyway? Is there a chance that this replace is corrupting the file? Do I have another option for this to work? I really appreciate the help. Thank you, Aaron UPDATE: the actual file is NOT a .txt file it is a .plist file which is preference file in Mac OS X if that makes any difference

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  • Problem with dictionary key in Python

    - by Hossein
    Hi all, For some project I have to make a dictionary in which the keys are urls,among which I have this url: http://www.microsoft.com/isapi/redir.dll prd=windows&sbp=mediaplayer&ar=Media&sba=Guide&pver=6.2 the url is too long to fit in here I guess in one single line. there is a space between .dll and prd. I can build a dictionary without any errors this url is also a key. but for some reason when I want to extract the values associated to this key(url). I cannot, I get and error "error key:...." Does someone know what is wrong with this url? Are dictionary keys sensitive to some stuff? thanks

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  • Python:Comparing Two Dictionaries

    - by saun jean
    The first Dict is fixed.This Dict will remain as it is List of Countries with there Short Names. firstDict={'ERITREA': 'ER', 'LAOS': 'LA', 'PORTUGAL': 'PT', "D'IVOIRE": 'CI', 'MONTENEGRO': 'ME', 'NEW CALEDONIA': 'NC', 'SVALBARD AND JAN MAYEN': 'SJ', 'BAHAMAS': 'BS', 'TOGO': 'TG', 'CROATIA': 'HR', 'LUXEMBOURG': 'LU', 'GHANA': 'GH'} However This Tuple result has multiple Dict inside it.This is the format in which MySQLdb returns result: result =({'count': 1L, 'country': 'Eritrea'}, {'count': 1L, 'country': 'Togo'}, {'count': 1L, 'country': 'Sierra Leone'}, {'count': 3L, 'country': 'Bahamas'}, {'count': 1L, 'country': 'Ghana'}) Now i want to compare these both results With COUNTRY Names and If 'Country' in Result is present in firstDict then put the value.else put the 0 The result desired is: mainRes={'ER':1,'TG':1,'BS':3,'GH':0,'LU':0}

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