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  • "Inside Job"

    Embedded databases power back-end hardware, business applications, and portable devices everywhere. Find out how Oracle embedded databases live and work at the core of hardware, software, and other devices—and deliver cash, health, and security.

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  • NetworkManager detects no networks with a RTL8188CE

    - by Cormac O'Brien
    I'm on a 2011 Lenovo Thinkpad T420i with a Realtek RTL8188CE WiFi adapter. Here's the scenario: I pop in the Ubuntu LiveCD to install. Laptop detects all networks in range, I connect to my home network, internet working great. Once Ubuntu finishes installing, the home network I am connected to is the only one which appears in the applet list. Upon restarting or waking from suspend, NetworkManager does not detect any networks – it simply displays "Disconnected" under the Wireless Network section of the menu. I am able to connect to my home network by using the "Connect to Hidden Wireless Network" option and it works immediately. I have yet to test if this works with other SSIDs. I have tried reinstalling the entire OS as well as NetworkManager and my wireless drivers. For hardware info, I ran: cormac@cormac-T420:~$ sudo lshw -c network Here is the output for my wireless card: *-network description: Wireless interface product: RTL8188CE 802.11b/g/n WiFi Adapter vendor: Realtek Semiconductor Co., Ltd. physical id: 0 bus info: pci@0000:03:00.0 logical name: wlan0 version: 01 serial: d0:df:9a:08:73:50 width: 64 bits clock: 33MHz capabilities: pm msi pciexpress bus_master cap_list ethernet physical wireless configuration: broadcast=yes driver=rtl8192ce driverversion=3.2.0-26-generic firmware=N/A ip=192.168.1.138 latency=0 link=yes multicast=yes wireless=IEEE 802.11bgn resources: irq:17 ioport:5000(size=256) memory:f2500000-f2503fff I can provide more information if required. This was not a problem in Natty or Oneiric. I hope this can be fixed, I don't want to have to ask for an SSID wherever I need to connect.

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  • Microsoft Office tracking license marks/keys in saved files (doc/docx/xls etc.)?

    - by pawel159
    Does Microsoft Office use any marks/keys in saved files, that can track the computer and software license using which file was saved? E.g.: I use Office at work and save files on pendrive. When I'm home I recall to check something and introduce little modifications. I'd save this file using MS Office Home and Student license, but at work I will be redistributing this file and it should look as it was saved at work, with company's license (not my private). Will saving it at work once again wipe license marks from home (if any exist)?

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  • Can I move a copy of Windows 7 from one machine to another?

    - by Chopper3
    This is a pretty basic question sorry but I've looked in the 'related questions' and couldn't find an answer. When Windows 7 came out I bought a copy of Home Premium, the retail box with both 32 and 64 bit versions, to install via Boot Camp on my macbook. I've just got a retail (32 and 64 bit) copy of Windows 7 Ultimate that I'd like to install instead-of/over the Home Premium version and it struck me that I should, at least in principal be able to install the Home Premium version on my son's machine - is this the case and if so is there anything I should do first or once they're installed to let MS know I'm being a good guy about this? Sorry it's such a dim question but I'm a serverfault guy really and know very little about Windows. Thanks.

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  • Ubuntu in USB.. Boot from fixed HDD?

    - by Z9iT
    I am having Ubuntu 12.04 minimal installed on my USB pen-drive; which I use on several systems as portable OS. I was thinking to edit the boot parameters so that before the main Ubuntu OS is loaded, it shows an option to Boot from Hard Drive for 5 seconds, and then boots to Ubuntu. This way i'll be able to have an option to boot to the OS installed on the Hard-Drive, without removing or unplugging my ubuntu USB stick. How do I edit the boot parameters to achieve this?

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  • Help with user login on Centos 5.6

    - by Owen
    I added a user for the sole purpose of using SU for root. I did not allow the creation of a home directory when creating the user. So now when I login as this user I get the following: Could not chdir to home directory /home/MYUSERNAME: No such file or directory Couldn't resolve homedir for current user at - line 0 BEGIN failed--compilation aborted. Couldn't resolve homedir for current user at - line 0 BEGIN failed--compilation aborted. Is this an error, and if so how do I fix it so it is not looking to "resolve" the homedir?

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  • Using mod_rewrite for a Virtual Filesystem vs. Real Filesystem

    - by philtune
    I started working in a department that uses a CMS in which the entire "filesystem" is like this: create a named file or folder - this file is given a unique node (ex. 2345) as well as a default "filename" (ex. /WelcomeToOurProductsPage) and apply a template assign one or more aliases to the file for a URL redirect (ex. /home-page-products - can also be accessed by /home-page-products.aspx) A new Rewrite command is written on the .htaccess file for each and every alias Server accesses either /WelcomeToOurProductsPage or /home-page-products and redirects to something like /template.aspx?tmp=2&node=2345 (here I'm guessing what it does - I only have front-end access for now - but I have enough clues to strongly assume) Node 2345 grabs content stored in a SQL Db and applies it to the template. Note: There are no actual files being created on the filesystem. It's entirely virtual. This is probably a very common thing, but since I have never run across this kind of system before two months ago, I wanted to explain it in case it isn't common. I'm not a fan at all of ASP or closed-sourced systems, so it may be that this is common practice for ASP developers. My question, that has taken far too long to ask, is: what are the benefits of this kind of system, as opposed to creating an actual file hierarchy? Are there any drawbacks to having every single file server call redirected? To having the .htaccess file hold rewrite rules for every single alias?

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  • Managing multiple ssh keys

    - by Mathijs Kwik
    I have a lot of ssh keys, they are all passphrase protected and managed by ssh-agent. As a result of this, I am now getting "Too many authentication failures" on some connections. As has been explained on this site before, this is because ssh will try all keys the agent throws at it. The proposed solution is to use IdentitiesOnly in the config, together with an IdentityFile. While this indeed stops offering wrong keys, it seems it completely disables the agent in full, so now I have to type the passphrase on every connection. I could not find clear info about this. Does IdentitiesOnly just disable getting keys from ssh-agent in full? Or should it just block out the keys that aren't mentioned? Thanks, Mathijs # here's my config ~% cat .ssh/config Host bluemote HostName some.host.com IdentitiesOnly yes IdentityFile /home/mathijs/.ssh/keys/bluebook_ecdsa # I had the key loaded into the agent, shown here ~% ssh-add -L ecdsa-sha2-nistp521 SOME_LONG_BASE64_NUMBER== /home/mathijs/.ssh/keys/bluebook_ecdsa # but it doesn't seem to get used ~% ssh bluemote Enter passphrase for key '/home/mathijs/.ssh/keys/bluebook_ecdsa':

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  • Tricking Linux apps about current time with environment variables

    - by geek
    Sometimes it is possible to trick a Linux app by calling it like this: HOME=/tmp/foo myapp This would make myapp think /tmp/foo is the home directory, it won't try to get the user id, find its home directory via getpwent(). This is useful when myapp must be forced to dump some of its config files into a non-standard location different than ~. A similar trick can be done like this: LANG=foo LC_ALL=bar myapp This is useful when myapp needs to be called once with a different locale without having to make the change persistent by using the export bash built-in or even modify stuff in /etc/profile. Is it possible to pull the same trick with time and date? The goal is to make an app use another time than the system ones. The final goal - to make timestamps that appear in logs/commit messages not being tied to the system time.

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  • Scanner Review: Fujitsu ScanSnap S1300

    The world of computer peripherals moves almost as fast as a busy business traveler. Fujitsu keeps up with both with its new portable scanner complete with automatic document feeder and business card import to Outlook.

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  • Scanner Review: Fujitsu ScanSnap S1300

    The world of computer peripherals moves almost as fast as a busy business traveler. Fujitsu keeps up with both with its new portable scanner complete with automatic document feeder and business card import to Outlook.

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  • How to perform a nested mount when using chroot?

    - by user55542
    Note that this question is prompted by the circumstances detailed by me (as Xl1NntniNH7F) in http://www.linuxquestions.org/questions/linux-desktop-74/boot-failure-upon-updating-e2fsprogs-in-ubuntu-10-10-a-947328/. Thus if you could address the underlying cause of the boot failure, I would very much appreciate it. I'm trying to replicate the environment in my ubuntu installation (where the home folder is on a separate partition) in order to run make uninstall. I'm using a live cd. How to mount a dir in one partition (sda2, mounted in ubuntu as the home folder) into a directory on another mounted partition (sda3)? I did chroot /mnt/sda2 but I don't know how to mount sda3 to /home, and my various attempts didn't work. As I am unfamiliar with chroot, my approach could be wrong, so it would be great if you could suggest what I should do, given my circumstances.

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  • Disabling "Sign In " tab on startup

    - by Alois Mahdal
    No matter that in Settings → Basics → On startup, I have selected Open the home page Home page is set to my internal address Chrome still opens with two tabs: my Home page and a Sign in tab (in foreground!). How do I disable this Sign in thing? I do not ever want to use it. The version I'm using is Chrome 18.0.1025.168. (For purposes of testing, I'm intentionally using older version.)

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  • Network configuration for several LANs and a shared server

    - by Grodriguez
    I want to setup a network on a building to provide shared services to all homes within the building. This should work as follows: Each home has a private LAN (e.g. 192.168.0.x) and an ADSL router for Internet access. Private LANs from each home should not "see" each other. There will be a shared server on the building which must be accessible from every home. I am not sure what is the best way to achieve this. Can someone point in the right direction? Thanks.

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  • When FTPing into CentOS server, it will drop me into 2 different directores based upon FTP access tool

    - by Jonezin
    I have a fresh install of CentOS 5.7. I created a new user 'ftpuser' with a home directory set to '/var/ftp'. If I FTP to the server using a FTP client it drops me into that home directory(good). If I use IE and use 'ftp://myserver' it drops me into the root of the server(?what?). First: why is this happening, this doesn't seem like correct behavior. Second: How do I prevent this, how do I force 'home' directory no matter what FTP access mechanism? Thanks for any assistance!

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  • Migrate from MySQL to PostgreSQL on Linux (Kubuntu)

    - by Dave Jarvis
    A long time ago in a galaxy far, far away... Trying to migrate a database from MySQL to PostgreSQL. All the documentation I have read covers, in great detail, how to migrate the structure. I have found very little documentation on migrating the data. The schema has 13 tables (which have been migrated successfully) and 9 GB of data. MySQL version: 5.1.x PostgreSQL version: 8.4.x I want to use the R programming language to analyze the data using SQL select statements; PostgreSQL has PL/R, but MySQL has nothing (as far as I can tell). A New Hope Create the database location (/var has insufficient space; also dislike having the PostgreSQL version number everywhere -- upgrading would break scripts!): sudo mkdir -p /home/postgres/main sudo cp -Rp /var/lib/postgresql/8.4/main /home/postgres sudo chown -R postgres.postgres /home/postgres sudo chmod -R 700 /home/postgres sudo usermod -d /home/postgres/ postgres All good to here. Next, restart the server and configure the database using these installation instructions: sudo apt-get install postgresql pgadmin3 sudo /etc/init.d/postgresql-8.4 stop sudo vi /etc/postgresql/8.4/main/postgresql.conf Change data_directory to /home/postgres/main sudo /etc/init.d/postgresql-8.4 start sudo -u postgres psql postgres \password postgres sudo -u postgres createdb climate pgadmin3 Use pgadmin3 to configure the database and create a schema. The episode continues in a remote shell known as bash, with both databases running, and the installation of a set of tools with a rather unusual logo: SQL Fairy. perl Makefile.PL sudo make install sudo apt-get install perl-doc (strangely, it is not called perldoc) perldoc SQL::Translator::Manual Extract a PostgreSQL-friendly DDL and all the MySQL data: sqlt -f DBI --dsn dbi:mysql:climate --db-user user --db-password password -t PostgreSQL > climate-pg-ddl.sql mysqldump --skip-add-locks --complete-insert --no-create-db --no-create-info --quick --result-file="climate-my.sql" --databases climate --skip-comments -u root -p The Database Strikes Back Recreate the structure in PostgreSQL as follows: pgadmin3 (switch to it) Click the Execute arbitrary SQL queries icon Open climate-pg-ddl.sql Search for TABLE " replace with TABLE climate." (insert the schema name climate) Search for on " replace with on climate." (insert the schema name climate) Press F5 to execute This results in: Query returned successfully with no result in 122 ms. Replies of the Jedi At this point I am stumped. Where do I go from here (what are the steps) to convert climate-my.sql to climate-pg.sql so that they can be executed against PostgreSQL? How to I make sure the indexes are copied over correctly (to maintain referential integrity; I don't have constraints at the moment to ease the transition)? How do I ensure that adding new rows in PostgreSQL will start enumerating from the index of the last row inserted (and not conflict with an existing primary key from the sequence)? How do you ensure the schema name comes through when transforming the data from MySQL to PostgreSQL inserts? Resources A fair bit of information was needed to get this far: https://help.ubuntu.com/community/PostgreSQL http://articles.sitepoint.com/article/site-mysql-postgresql-1 http://wiki.postgresql.org/wiki/Converting_from_other_Databases_to_PostgreSQL#MySQL http://pgfoundry.org/frs/shownotes.php?release_id=810 http://sqlfairy.sourceforge.net/ Thank you!

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  • Django - no module named app

    - by Koran
    Hi, I have been trying to get an application written in django working - but it is not working at all. I have been working on for some time too - and it is working on dev-server perfectly. But I am unable to put in the production env (apahce). My project name is apstat and the app name is basic. I try to access it as following Blockquote http://hostname/apstat But it shows the following error: MOD_PYTHON ERROR ProcessId: 6002 Interpreter: 'domU-12-31-39-06-DD-F4.compute-1.internal' ServerName: 'domU-12-31-39-06-DD-F4.compute-1.internal' DocumentRoot: '/home/ubuntu/server/' URI: '/apstat/' Location: '/apstat' Directory: None Filename: '/home/ubuntu/server/apstat/' PathInfo: '' Phase: 'PythonHandler' Handler: 'django.core.handlers.modpython' Traceback (most recent call last): File "/usr/lib/python2.6/dist-packages/mod_python/importer.py", line 1537, in HandlerDispatch default=default_handler, arg=req, silent=hlist.silent) File "/usr/lib/python2.6/dist-packages/mod_python/importer.py", line 1229, in _process_target result = _execute_target(config, req, object, arg) File "/usr/lib/python2.6/dist-packages/mod_python/importer.py", line 1128, in _execute_target result = object(arg) File "/usr/lib/pymodules/python2.6/django/core/handlers/modpython.py", line 228, in handler return ModPythonHandler()(req) File "/usr/lib/pymodules/python2.6/django/core/handlers/modpython.py", line 201, in __call__ response = self.get_response(request) File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py", line 134, in get_response return self.handle_uncaught_exception(request, resolver, exc_info) File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py", line 154, in handle_uncaught_exception return debug.technical_500_response(request, *exc_info) File "/usr/lib/pymodules/python2.6/django/views/debug.py", line 40, in technical_500_response html = reporter.get_traceback_html() File "/usr/lib/pymodules/python2.6/django/views/debug.py", line 114, in get_traceback_html return t.render(c) File "/usr/lib/pymodules/python2.6/django/template/__init__.py", line 178, in render return self.nodelist.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py", line 779, in render bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py", line 81, in render_node raise wrapped TemplateSyntaxError: Caught an exception while rendering: No module named basic Original Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/template/debug.py", line 71, in render_node result = node.render(context) File "/usr/lib/pymodules/python2.6/django/template/debug.py", line 87, in render output = force_unicode(self.filter_expression.resolve(context)) File "/usr/lib/pymodules/python2.6/django/template/__init__.py", line 572, in resolve new_obj = func(obj, *arg_vals) File "/usr/lib/pymodules/python2.6/django/template/defaultfilters.py", line 687, in date return format(value, arg) File "/usr/lib/pymodules/python2.6/django/utils/dateformat.py", line 269, in format return df.format(format_string) File "/usr/lib/pymodules/python2.6/django/utils/dateformat.py", line 30, in format pieces.append(force_unicode(getattr(self, piece)())) File "/usr/lib/pymodules/python2.6/django/utils/dateformat.py", line 175, in r return self.format('D, j M Y H:i:s O') File "/usr/lib/pymodules/python2.6/django/utils/dateformat.py", line 30, in format pieces.append(force_unicode(getattr(self, piece)())) File "/usr/lib/pymodules/python2.6/django/utils/encoding.py", line 71, in force_unicode s = unicode(s) File "/usr/lib/pymodules/python2.6/django/utils/functional.py", line 201, in __unicode_cast return self.__func(*self.__args, **self.__kw) File "/usr/lib/pymodules/python2.6/django/utils/translation/__init__.py", line 62, in ugettext return real_ugettext(message) File "/usr/lib/pymodules/python2.6/django/utils/translation/trans_real.py", line 286, in ugettext return do_translate(message, 'ugettext') File "/usr/lib/pymodules/python2.6/django/utils/translation/trans_real.py", line 276, in do_translate _default = translation(settings.LANGUAGE_CODE) File "/usr/lib/pymodules/python2.6/django/utils/translation/trans_real.py", line 194, in translation default_translation = _fetch(settings.LANGUAGE_CODE) File "/usr/lib/pymodules/python2.6/django/utils/translation/trans_real.py", line 180, in _fetch app = import_module(appname) File "/usr/lib/pymodules/python2.6/django/utils/importlib.py", line 35, in import_module __import__(name) ImportError: No module named basic My settings.py is as follows: INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'apstat.basic', 'django.contrib.admin', ) If I remove the apstat.basic, it goes through, but that is not a solution. Is it something I am doing in apache? My apache - settings are - <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot /home/ubuntu/server/ <Directory /> Options None AllowOverride None </Directory> <Directory /home/ubuntu/server/apstat> AllowOverride None Order allow,deny allow from all </Directory> <Location "/apstat"> SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE apstat.settings PythonOption django.root /home/ubuntu/server/ PythonDebug On PythonPath "['/home/ubuntu/server/'] + sys.path" </Location> </VirtualHost> I have now sat for more than a day on this. If someone can help me out, it would be very nice.

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  • C++ virtual functions.Problem with vtable

    - by adivasile
    I'm doing a little project in C++ and I've come into some problems regarding virtual functions. I have a base class with some virtual functions: #ifndef COLLISIONSHAPE_H_ #define COLLISIONSHAPE_H_ namespace domino { class CollisionShape : public DominoItem { public: // CONSTRUCTOR //------------------------------------------------- // SETTERS //------------------------------------------------- // GETTERS //------------------------------------------------- virtual void GetRadius() = 0; virtual void GetPosition() = 0; virtual void GetGrowth(CollisionShape* other) = 0; virtual void GetSceneNode(); // OTHER //------------------------------------------------- virtual bool overlaps(CollisionShape* shape) = 0; }; } #endif /* COLLISIONSHAPE_H_ */ and a SphereShape class which extends CollisionShape and implements the methods above /* SphereShape.h */ #ifndef SPHERESHAPE_H_ #define SPHERESHAPE_H_ #include "CollisionShape.h" namespace domino { class SphereShape : public CollisionShape { public: // CONSTRUCTOR //------------------------------------------------- SphereShape(); SphereShape(CollisionShape* shape1, CollisionShape* shape2); // DESTRUCTOR //------------------------------------------------- ~SphereShape(); // SETTERS //------------------------------------------------- void SetPosition(); void SetRadius(); // GETTERS //------------------------------------------------- cl_float GetRadius(); cl_float3 GetPosition(); SceneNode* GetSceneNode(); cl_float GetGrowth(CollisionShape* other); // OTHER //------------------------------------------------- bool overlaps(CollisionShape* shape); }; } #endif /* SPHERESHAPE_H_ */ and the .cpp file: /*SphereShape.cpp*/ #include "SphereShape.h" #define max(a,b) (a>b?a:b) namespace domino { // CONSTRUCTOR //------------------------------------------------- SphereShape::SphereShape(CollisionShape* shape1, CollisionShape* shape2) { } // DESTRUCTOR //------------------------------------------------- SphereShape::~SphereShape() { } // SETTERS //------------------------------------------------- void SphereShape::SetPosition() { } void SphereShape::SetRadius() { } // GETTERS //------------------------------------------------- void SphereShape::GetRadius() { } void SphereShape::GetPosition() { } void SphereShape::GetSceneNode() { } void SphereShape::GetGrowth(CollisionShape* other) { } // OTHER //------------------------------------------------- bool SphereShape::overlaps(CollisionShape* shape) { return true; } } These classes, along some other get compiled into a shared library. Building libdomino.so g++ -m32 -lpthread -ldl -L/usr/X11R6/lib -lglut -lGLU -lGL -shared -lSDKUtil -lglut -lGLEW -lOpenCL -L/home/adrian/AMD-APP-SDK-v2.4-lnx32/lib/x86 -L/home/adrian/AMD-APP-SDK-v2.4-lnx32/TempSDKUtil/lib/x86 -L"/home/adrian/AMD-APP-SDK-v2.4-lnx32/lib/x86" -lSDKUtil -lglut -lGLEW -lOpenCL -o build/debug/x86/libdomino.so build/debug/x86//Material.o build/debug/x86//Body.o build/debug/x86//SphereShape.o build/debug/x86//World.o build/debug/x86//Engine.o build/debug/x86//BVHNode.o When I compile the code that uses this library I get the following error: ../../../lib/x86//libdomino.so: undefined reference to `vtable for domino::CollisionShape' ../../../lib/x86//libdomino.so: undefined reference to `typeinfo for domino::CollisionShape' Command used to compile the demo that uses the library: g++ -o build/debug/x86/startdemo build/debug/x86//CMesh.o build/debug/x86//CSceneNode.o build/debug/x86//OFF.o build/debug/x86//Light.o build/debug/x86//main.o build/debug/x86//Camera.o -m32 -lpthread -ldl -L/usr/X11R6/lib -lglut -lGLU -lGL -lSDKUtil -lglut -lGLEW -ldomino -lSDKUtil -lOpenCL -L/home/adrian/AMD-APP-SDK-v2.4-lnx32/lib/x86 -L/home/adrian/AMD-APP-SDK-v2.4-lnx32/TempSDKUtil/lib/x86 -L../../../lib/x86/ -L"/home/adrian/AMD-APP-SDK-v2.4-lnx32/lib/x86" (the -ldomino flag) And when I run the demo, I manually tell it about the library: LD_LIBRARY_PATH=../../lib/x86/:$AMDAPPSDKROOT/lib/x86:$LD_LIBRARY_PATH bin/x86/startdemo After reading a bit about virtual functions and virtual tables I understood that virtual tables are handled by the compiler and I shouldn't worry about it, so I'm a little bit confused on how to handle this issue. I'm using gcc version 4.6.0 20110530 (Red Hat 4.6.0-9) (GCC) Later edit: I'm really sorry, but I wrote the code by hand directly here. I have defined the return types in the code. I apologize to the 2 people that answered below. I have to mention that I am a beginner at using more complex project layouts in C++.By this I mean more complex makefiles, shared libraries, stuff like that.

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  • ssh permission denied

    - by Gitmo
    I am trying to ssh into a remote machine and I get the following debug messages: debug1: Reading configuration data /etc/ssh/ssh_config debug1: Applying options for * debug2: ssh_connect: needpriv 0 debug1: Connecting to xxx.xxx.x.xx [xxx.xxx.xx.x] port 22. debug1: Connection established. debug3: Not a RSA1 key file /home/hadoop/.ssh/id_rsa. debug2: key_type_from_name: unknown key type '-----BEGIN' debug3: key_read: missing keytype debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug3: key_read: missing whitespace debug2: key_type_from_name: unknown key type '-----END' debug3: key_read: missing keytype debug1: identity file /home/hadoop/.ssh/id_rsa type 1 debug1: Checking blacklist file /usr/share/ssh/blacklist.RSA-2048 debug1: Checking blacklist file /etc/ssh/blacklist.RSA-2048 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.1p1 Debian-6ubuntu2 debug1: match: OpenSSH_5.1p1 Debian-6ubuntu2 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.1p1 Debian-6ubuntu2 debug2: fd 3 setting O_NONBLOCK debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug2: kex_parse_kexinit: diffie-hellman-group-exchange-sha256,diffie-hellman-group-exchange-sha1,diffie-hellman-group14-sha1,diffie-hellman-group1-sha1 debug2: kex_parse_kexinit: ssh-rsa,ssh-dss debug2: kex_parse_kexinit: aes128-cbc,3des-cbc,blowfish-cbc,cast128-cbc,arcfour128,arcfour256,arcfour,aes192-cbc,aes256-cbc,[email protected],aes128-ctr,aes192-ctr,aes256-ctr debug2: kex_parse_kexinit: aes128-cbc,3des-cbc,blowfish-cbc,cast128-cbc,arcfour128,arcfour256,arcfour,aes192-cbc,aes256-cbc,[email protected],aes128-ctr,aes192-ctr,aes256-ctr debug2: kex_parse_kexinit: hmac-md5,hmac-sha1,[email protected],hmac-ripemd160,[email protected],hmac-sha1-96,hmac-md5-96 debug2: kex_parse_kexinit: hmac-md5,hmac-sha1,[email protected],hmac-ripemd160,[email protected],hmac-sha1-96,hmac-md5-96 debug2: kex_parse_kexinit: none,[email protected],zlib debug2: kex_parse_kexinit: none,[email protected],zlib debug2: kex_parse_kexinit: debug2: kex_parse_kexinit: debug2: kex_parse_kexinit: first_kex_follows 0 debug2: kex_parse_kexinit: reserved 0 debug2: kex_parse_kexinit: diffie-hellman-group-exchange-sha256,diffie-hellman-group-exchange-sha1,diffie-hellman-group14-sha1,diffie-hellman-group1-sha1 debug2: kex_parse_kexinit: ssh-rsa,ssh-dss debug2: kex_parse_kexinit: aes128-cbc,3des-cbc,blowfish-cbc,cast128-cbc,arcfour128,arcfour256,arcfour,aes192-cbc,aes256-cbc,[email protected],aes128-ctr,aes192-ctr,aes256-ctr debug2: kex_parse_kexinit: aes128-cbc,3des-cbc,blowfish-cbc,cast128-cbc,arcfour128,arcfour256,arcfour,aes192-cbc,aes256-cbc,[email protected],aes128-ctr,aes192-ctr,aes256-ctr debug2: kex_parse_kexinit: hmac-md5,hmac-sha1,[email protected],hmac-ripemd160,[email protected],hmac-sha1-96,hmac-md5-96 debug2: kex_parse_kexinit: hmac-md5,hmac-sha1,[email protected],hmac-ripemd160,[email protected],hmac-sha1-96,hmac-md5-96 debug2: kex_parse_kexinit: none,[email protected] debug2: kex_parse_kexinit: none,[email protected] debug2: kex_parse_kexinit: debug2: kex_parse_kexinit: debug2: kex_parse_kexinit: first_kex_follows 0 debug2: kex_parse_kexinit: reserved 0 debug2: mac_setup: found hmac-md5 debug1: kex: server->client aes128-cbc hmac-md5 none debug2: mac_setup: found hmac-md5 debug1: kex: client->server aes128-cbc hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug2: dh_gen_key: priv key bits set: 128/256 debug2: bits set: 511/1024 debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug3: check_host_in_hostfile: filename /home/hadoop/.ssh/known_hosts debug3: check_host_in_hostfile: match line 20 debug1: Host '192.168.1.63' is known and matches the RSA host key. debug1: Found key in /home/hadoop/.ssh/known_hosts:20 debug2: bits set: 511/1024 debug1: ssh_rsa_verify: signature correct debug2: kex_derive_keys debug2: set_newkeys: mode 1 debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug2: set_newkeys: mode 0 debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug2: service_accept: ssh-userauth debug1: SSH2_MSG_SERVICE_ACCEPT received debug2: key: /home/hadoop/.ssh/id_rsa (0x241c110) debug1: Authentications that can continue: publickey,password debug3: start over, passed a different list publickey,password debug3: preferred gssapi-keyex,gssapi-with-mic,gssapi,publickey,keyboard-interactive debug3: authmethod_lookup publickey debug3: remaining preferred: keyboard-interactive debug3: authmethod_is_enabled publickey debug1: Next authentication method: publickey debug1: Offering public key: /home/hadoop/.ssh/id_rsa debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug1: Authentications that can continue: publickey,password debug2: we did not send a packet, disable method debug1: No more authentication methods to try. Permission denied (publickey,password). What seems to be the problem?? I have tried everything, this is driving me nuts.

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  • Python - Bitmap won't draw/display

    - by Wallter
    I have been working on this project for some time now - it was originally supposed to be a test to see if, using wxPython, I could build a button 'from scratch.' From scratch means: that i would have full control over all the aspects of the button (i.e. controlling the BMP's that are displayed... what the event handlers did... etc.) I have run into several problems (as this is my first major python project.) Now, when the all the code is working for the life of me I can't get an image to display. Basic code - not working dc = wx.BufferedPaintDC(self) dc.SetFont(self.GetFont()) dc.SetBackground(wx.Brush(self.GetBackgroundColour())) dc.Clear() dc.DrawBitmap(wx.Bitmap("/home/wallter/Desktop/Mouseover.bmp"), 100, 100) self.Refresh() self.Update() Full Main.py import wx from Custom_Button import Custom_Button from wxPython.wx import * ID_ABOUT = 101 ID_EXIT = 102 class MyFrame(wx.Frame): def __init__(self, parent, ID, title): wxFrame.__init__(self, parent, ID, title, wxDefaultPosition, wxSize(400, 400)) self.CreateStatusBar() self.SetStatusText("Program testing custom button overlays") menu = wxMenu() menu.Append(ID_ABOUT, "&About", "More information about this program") menu.AppendSeparator() menu.Append(ID_EXIT, "E&xit", "Terminate the program") menuBar = wxMenuBar() menuBar.Append(menu, "&File"); self.SetMenuBar(menuBar) # The call for the 'Experiential button' self.Button1 = Custom_Button(parent, -1, wx.Point(100, 100), wx.Bitmap("/home/wallter/Desktop/Mouseover.bmp"), wx.Bitmap("/home/wallter/Desktop/Normal.bmp"), wx.Bitmap("/home/wallter/Desktop/Click.bmp")) # The following three lines of code are in place to try to get the # Button1 to display (trying to trigger the Paint event (the _onPaint.) # Because that is where the 'draw' functions are. self.Button1.Show(true) self.Refresh() self.Update() # Because the Above three lines of code did not work, I added the # following four lines to trigger the 'draw' functions to test if the # '_onPaint' method actually worked. # These lines do not work. dc = wx.BufferedPaintDC(self) dc.SetFont(self.GetFont()) dc.SetBackground(wx.Brush(self.GetBackgroundColour())) dc.DrawBitmap(wx.Bitmap("/home/wallter/Desktop/Mouseover.bmp"), 100, 100) EVT_MENU(self, ID_ABOUT, self.OnAbout) EVT_MENU(self, ID_EXIT, self.TimeToQuit) def OnAbout(self, event): dlg = wxMessageDialog(self, "Testing the functions of custom " "buttons using pyDev and wxPython", "About", wxOK | wxICON_INFORMATION) dlg.ShowModal() dlg.Destroy() def TimeToQuit(self, event): self.Close(true) class MyApp(wx.App): def OnInit(self): frame = MyFrame(NULL, -1, "wxPython | Buttons") frame.Show(true) self.SetTopWindow(frame) return true app = MyApp(0) app.MainLoop() Full CustomButton.py import wx from wxPython.wx import * class Custom_Button(wx.PyControl): def __init__(self, parent, id, Pos, Over_BMP, Norm_BMP, Push_BMP, **kwargs): wx.PyControl.__init__(self,parent, id, **kwargs) self.Bind(wx.EVT_LEFT_DOWN, self._onMouseDown) self.Bind(wx.EVT_LEFT_UP, self._onMouseUp) self.Bind(wx.EVT_LEAVE_WINDOW, self._onMouseLeave) self.Bind(wx.EVT_ENTER_WINDOW, self._onMouseEnter) self.Bind(wx.EVT_ERASE_BACKGROUND,self._onEraseBackground) self.Bind(wx.EVT_PAINT,self._onPaint) self.pos = Pos self.Over_bmp = Over_BMP self.Norm_bmp = Norm_BMP self.Push_bmp = Push_BMP self._mouseIn = False self._mouseDown = False def _onMouseEnter(self, event): self._mouseIn = True def _onMouseLeave(self, event): self._mouseIn = False def _onMouseDown(self, event): self._mouseDown = True def _onMouseUp(self, event): self._mouseDown = False self.sendButtonEvent() def sendButtonEvent(self): event = wx.CommandEvent(wx.wxEVT_COMMAND_BUTTON_CLICKED, self.GetId()) event.SetInt(0) event.SetEventObject(self) self.GetEventHandler().ProcessEvent(event) def _onEraseBackground(self,event): # reduce flicker pass def Iz(self): dc = wx.BufferedPaintDC(self) dc.DrawBitmap(self.Norm_bmp, 100, 100) def _onPaint(self, event): # The printing functions, they should work... but don't. dc = wx.BufferedPaintDC(self) dc.SetFont(self.GetFont()) dc.SetBackground(wx.Brush(self.GetBackgroundColour())) dc.Clear() dc.DrawBitmap(self.Norm_bmp) # This never printed... I don't know if that means if the EVT # is triggering or what. print '_onPaint' # draw whatever you want to draw # draw glossy bitmaps e.g. dc.DrawBitmap if self._mouseIn: # If the Mouse is over the button dc.DrawBitmap(self.Over_bmp, self.pos) else: # Since the mouse isn't over it Print the normal one # This is adding on the above code to draw the bmp # in an attempt to get the bmp to display; to no avail. dc.DrawBitmap(self.Norm_bmp, self.pos) if self._mouseDown: # If the Mouse clicks the button dc.DrawBitmap(self.Push_bmp, self.pos) This code won't work? I get no BMP displayed why? How do i get one? I've gotten the staticBitmap(...) to display one, but it won't move, resize, or anything for that matter... - it's only in the top left corner of the frame? Note: the frame is 400pxl X 400pxl - and the "/home/wallter/Desktop/Mouseover.bmp"

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  • Post calls RedirectToAction but view specified in RedirectToAction is not rendered

    - by W4IK
    Here's some of the html <form id="frmSubmit" action="/Viewer" style="display:none;"> <div id="renderSubmit" class="renderReport"> <input type="hidden" name="reportYear" id="reportYear" value="" /> <input type="hidden" name="reportMonth" id="reportMonth" value="" /> <input type="hidden" name="propIds" id="propIds" value="" /> <input type="hidden" name="reportName" id="reportName" value="" /> <input type="hidden" name="reportYearFrom" id="reportYearFrom" value="" /> <input type="hidden" name="reportMonthFrom" id="reportMonthFrom" value="" /> <input type="hidden" name="reportYearTo" id="reportYearTo" value="" /> <input type="hidden" name="reportMonthTo" id="reportMonthTo" value="" /> </div> </form> a little further down the page <div id="reportList" class="renderReport"> <fieldset style="width:105%;"> <legend class="reportStepLegend">Step 3. <br /> Click a report name below to view a report</legend> <br /> <% foreach (ReportMetaData item in (ReportMetaDataContainer)ViewData.Model) { %> <div> <input id=<%=item.SSRSName%> type="button" class="reportLink" value="<%=item.DisplayName%>" /> </div> <%}%> </fieldset> </div> Here's the javascript that gets called when the button is clicked $('.reportLink').click(function() { if (CheckDateAndProps() === true) { $('#reportName').val(this.id); var formData = $("#frmSubmit").serializeArray(); $.post('Home/PostViewer/', formData); } }); Note...i did have the $.post like so earlier...but it didn't seem to make any difference $.post('Home/PostViewer/', formData, function(data) { alert(data.Result); }, "json"); Here's the controller code [AcceptVerbs(HttpVerbs.Post)] public ActionResult PostViewer(string reportYear, string reportMonth, string propIds, string reportName, string reportYearFrom, string reportMonthFrom, string reportYearTo, string reportMonthTo) { return RedirectToAction("Viewer"); } All is good in the world up to this point..I'm hitting the above method and all the values are populated. Here's the get ActionResult method [AcceptVerbs(HttpVerbs.Get)] public ActionResult Viewer(string reportYear, string reportMonth, string propIds, string reportName, string reportYearFrom, string reportMonthFrom, string reportYearTo, string reportMonthTo) { return View(); } I'm hitting this too...not seeing any values in the parameters...but that's just because I haven't passed them in yet...I don't think that's whats keeping the Viewer page from displaying.? Now...one would one expect the Viewer view to be rendered...right?...well all I see is the page that this was called from...it never displays the Viewer page???!!?!? Here's the routes from global.asax routes.MapRoute( "Viewer", // Route name "Home/Viewer", // URL with parameters new { controller = "Home", action = "Viewer" } // Parameter defaults ); routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = "" } // Parameter defaults ); I can browse directly to the page http://localhost:50083/Home/Viewer and when I do so I hit the get ActionResult method and the page renders just fine. Any help is greatly appreciated!

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