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  • chrome extension login security with iframe

    - by Weaver
    I should note, I'm not a chrome extension expert. However, I'm looking for some advice or high level solution to a security concern I have with my chrome extension. I've searched quite a bit but can't seem to find a concrete answer. The situation I have a chrome extension that needs to have the user login to our backend server. However, it was decided for design reasons that the default chrome popup balloon was undesirable. Thus I've used a modal dialog and jquery to make a styled popup that is injected with content scripts. Hence, the popup is injected into the DOM o the page you are visiting. The Problem Everything works, however now that I need to implement login functionality I've noticed a vulnerability: If the site we've injected our popup into knows the password fields ID they could run a script to continuously monitor the password and username field and store that data. Call me paranoid, but I see it as a risk. In fact,I wrote a mockup attack site that can correctly pull the user and password when entered into the given fields. My devised solution I took a look at some other chrome extensions, like Buffer, and noticed what they do is load their popup from their website and, instead, embed an iFrame which contains the popup in it. The popup would interact with the server inside the iframe. My understanding is iframes are subject to same-origin scripting policies as other websites, but I may be mistaken. As such, would doing the same thing be secure? TLDR To simplify, if I embedded an https login form from our server into a given DOM, via a chrome extension, are there security concerns to password sniffing? If this is not the best way to deal with chrome extension logins, do you have suggestions with what is? Perhaps there is a way to declare text fields that javascript can simply not interact with? Not too sure! Thank you so much for your time! I will happily clarify anything required.

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  • Authentication Problem - not recognizing 'else' - Ruby on rails...

    - by bgadoci
    I can't seem to figure out what I am doing wrong here. I have implemented the Super Simple Authentication from Ryan Bates tutorial and while the login portion is functioning correctly, I can't get an error message and redirect to happen correctly for a bad login. Ryan Bates admits in his comments he left this out but can't seem to implement his recommendation. Basically what is happening is that when someone logs in correctly it works. When a bad password is entered it does the same redirect and flashes 'successfully logged in' thought they are not. The admin links do not show (which is correct and are the links protected by the <% if admin? %) but I need it to say 'failed login' and redirect to login path. Here is my code: SessionsController class SessionsController < ApplicationController def create if session[:password] = params[:password] flash[:notice] = 'Successfully logged in' redirect_to posts_path else flash[:notice] = "whoops" redirect_to login_path end end def destroy reset_session flash[:notice] = 'Successfully logged out' redirect_to posts_path end end ApplicationController class ApplicationController < ActionController::Base helper_method :admin? protected def authorize unless admin? flash[:error] = "unauthorized request" redirect_to posts_path false end end def admin? session[:password] == "123456" end helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # end

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  • Generating All Permutations of Character Combinations when # of arrays and length of each array are

    - by Jay
    Hi everyone, I'm not sure how to ask my question in a succinct way, so I'll start with examples and expand from there. I am working with VBA, but I think this problem is non language specific and would only require a bright mind that can provide a pseudo code framework. Thanks in advance for the help! Example: I have 3 Character Arrays Like So: Arr_1 = [X,Y,Z] Arr_2 = [A,B] Arr_3 = [1,2,3,4] I would like to generate ALL possible permutations of the character arrays like so: XA1 XA2 XA3 XA4 XB1 XB2 XB3 XB4 YA1 YA2 . . . ZB3 ZB4 This can be easily solved using 3 while loops or for loops. My question is how do I solve for this if the # of arrays is unknown and the length of each array is unknown? So as an example with 4 character arrays: Arr_1 = [X,Y,Z] Arr_2 = [A,B] Arr_3 = [1,2,3,4] Arr_4 = [a,b] I would need to generate: XA1a XA1b XA2a XA2b XA3a XA3b XA4a XA4b . . . ZB4a ZB4b So the Generalized Example would be: Arr_1 = [...] Arr_2 = [...] Arr_3 = [...] . . . Arr_x = [...] Is there a way to structure a function that will generate an unknown number of loops and loop through the length of each array to generate the permutations? Or maybe there's a better way to think about the problem? Thanks Everyone!

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  • Ruby script/console and Ruby script/server using two different DBs?

    - by aronchick
    Has anyone seen where script/console and script/server load two different databases (though both report using the same)? Here's the first output $ script/server => Booting WEBrick => Rails 2.3.5 application starting on http://0.0.0.0:3000 => Call with -d to detach => Ctrl-C to shutdown server [2010-03-21 15:54:05] INFO WEBrick 1.3.1 [2010-03-21 15:54:05] INFO ruby 1.8.7 (2010-01-10) [i386-mingw32] [2010-03-21 15:54:05] INFO WEBrick::HTTPServer#start: pid=7148 port=3000 No errors. I then run my standard code for entering a form - no problems. Checking the Dev Database (.yml at bottom): mysql> select * from books; [...] | 712 | Book | Book Name | 2010-03-21 22:29:22 | 2010-03-21 22:29:22 | [...] 712 rows in set (0.00 sec) The code CLEARLY saved it seconds ago And now here's the output of script/console: $ script/console Loading development environment (Rails 2.3.5) >> Books.all => [] Nothing. Further, upon further inspection, it's using the production database, but I can't figure out why. Any thoughts here? All consoles have been closed and reopened. UPDATE: Requested .yml file (can't see how it'd be helpful (user name and password are all the same for each)) - development: adapter: mysql database: BooksDBdev username: <user name> password: <long string> timeout: 5000 # Warning: The database defined as "test" will be erased and # re-generated from your development database when you run "rake". # Do not set this db to the same as development or production. test: adapter: mysql database: BooksDBtest username: <user name> password: <long string> timeout: 5000 production: adapter: mysql database: BooksDB username: <user name> password: <long string> timeout: 5000

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  • What is the best way to extend restful_authentication/AuthLogic to support lazy logins by an anonymo

    - by Kevin Elliott
    I'm building an iPhone application that talks to a Ruby on Rails backend. The Ruby on Rails application will also service web users. The restful_authentication plugin is an excellent way to provide quick and customizable user authentication. However, I would like users of the iPhone application to have an account created automatically by the phone's unique identifier ([[UIDevice device] uniqueIdentifier]) stored in a new column. Later, when users are ready to create a username/password, the account will be updated to contain the username and password, leaving the iPhone unique identifier intact. Users should not be able to access the website until they've setup their username/password. They can however, use the iPhone application, since the application can authenticate itself using it's identifier. What is the best way to modify restful_authentication to do this? Create a plugin? Or modify the generated code? What about alternative frameworks, such as AuthLogic. What is the best way to allow iPhones to get a generated auth token locked to their UUID's, but then let the user create a username/password later?

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  • Unit Testing (xUnit) an ASP.NET Mvc Controller with a custom input model?

    - by Danny Douglass
    I'm having a hard time finding information on what I expect to be a pretty straightforward scenario. I'm trying to unit test an Action on my ASP.NET Mvc 2 Controller that utilizes a custom input model w/ DataAnnotions. My testing framework is xUnit, as mentioned in the title. Here is my custom Input Model: public class EnterPasswordInputModel { [Required(ErrorMessage = "")] public string Username { get; set; } [Required(ErrorMessage = "Password is a required field.")] public string Password { get; set; } } And here is my Controller (took out some logic to simplify for this ex.): [HttpPost] public ActionResult EnterPassword(EnterPasswordInputModel enterPasswordInput) { if (!ModelState.IsValid) return View(); // do some logic to validate input // if valid - next View on successful validation return View("NextViewName"); // else - add and display error on current view return View(); } And here is my xUnit Fact (also simplified): [Fact] public void EnterPassword_WithValidInput_ReturnsNextView() { // Arrange var controller = CreateLoginController(userService.Object); // Act var result = controller.EnterPassword( new EnterPasswordInputModel { Username = username, Password = password }) as ViewResult; // Assert Assert.Equal("NextViewName", result.ViewName); } When I run my test I get the following error on my test fact when trying to retrieve the controller result (Act section): System.NullReferenceException: Object reference not set to an instance of an object. Thanks in advance for any help you can offer!

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  • Sending basic authentication information via form

    - by VolatileStorm
    I am working on a site that currently uses a basic authentication dialog box login system, that is the type of dialog that you get if you go here: http://www.dur.ac.uk/vm.boatclub/password/index.php I did not set this system up and am not in a position to easily/quickly work around it, but it DOES work. The issue however is that the dialog box is not very helpful in telling you what login information you have to use (that is which username and password combination), and so I would like to replace it with a form. I had been thinking that this wasn't possible but I wanted to ask in order to find out. Is it possible to set up an HTML form that sends the data to the server such that it accepts it in the same way that it would using this dialog box? Alternatively is it possible to set up a PHP script that would take normal form data and process it somehow passing it to the server such that it logs in? Edit: After being told that this is basic authentication I went around and have managed to find a way that works and keeps the user persistently logged in. However, this does not work in internet explorer. The solution was simply to redirect the user to: http://username:[email protected]/vm.boatclub/password/index.php But Internet Explorer removed it due to phishing uses about 3 years ago. Is there a way to use javascript to get the browser to access the site in this way? Or will I have to simply change my UI?

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  • Rails CSS not Loading using Heroku

    - by eWizardII
    I have the following site set up here on Heroku - http://www.peerinstruction.net/users/sign_up the issue is that I have updated the css yet it is not being actively reflected on the site, it just shows a textbox, with some edited/custom fonts. I have attached the css file in the following gist - https://gist.github.com/f74b626c54ecbb60bbde The signup page controller: !!! Strict %html %head %title= yield(:title) || "Untitled" = stylesheet_link_tag 'application', 'web-app-theme/base', 'web-app-theme/themes/activo/style', 'web-app-theme/override' = javascript_include_tag :defaults = csrf_meta_tag = yield(:head) %body #container #header %h1 %a{:href => "/"} Peer Instruction Network #user-navigation %ul.wat-cf %li .content.login .flash - flash.each do |type, message| %div{ :class => "message #{type}" } %p= message = form_for(resource, :as => resource_name, :url => session_path(resource_name), :html => { :class => "form login" }) do |f| .group.wat-cf .left= f.label :email, :class => "label right" .right= f.text_field :email, :class => "text_field" .group.wat-cf .left= f.label :password, :class => "label right" .right= f.password_field :password, :class => "text_field" .group.wat-cf .right %button.button{ :type => "submit" } Login /= link_to "Sign In", destroy_user_session_path #box = yield The signup pages haml file: %h2 .block .content.login .flash - flash.each do |type, message| %div{ :class => "message #{type}" } %p= message = form_for(resource, :as => resource_name, :url => registration_path(resource_name)) do |f| = devise_error_messages! %div = f.label :firstname %br/ = f.text_field :firstname %div = f.label :middlename %br/ = f.text_field :middlename %div = f.label :lastname %br/ = f.text_field :lastname %div = f.label :email %br/ = f.email_field :email %div = f.label :password %br/ = f.password_field :password %div = f.label :academic %br/ = f.text_field :academic %div= f.submit "Continue" = render :partial => "devise/shared/links" I used web-app-theme to create an activo theme and then modify it.

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  • ASP.NET MVC: How do I validate a model wrapped in a ViewModel?

    - by Deniz Dogan
    For the login page of my website I would like to list the latest news for my site and also display a few fields to let the user log in. So I figured I should make a login view model - I call this LoginVM. LoginVM contains a Login model for the login fields and a List<NewsItem> for the news listing. This is the Login model: public class Login { [Required(ErrorMessage="Enter a username.")] [DisplayName("Username")] public string Username { get; set; } [Required(ErrorMessage="Enter a password.")] [DataType(DataType.Password)] [DisplayName("Password")] public string Password { get; set; } } This is the LoginVM view model: public class LoginVM { public Login login { get; set; } public List<NewsItem> newsItems { get; set; } } This is where I get stuck. In my login controller, I get passed a LoginVM. [HttpPost] public ActionResult Login(LoginVM model, FormCollection form) { if (ModelState.IsValid) { // What? In the code I'm checking whether ModelState is valid and this would work fine if the view model was actually the Login model, but now it's LoginVM which has no validation attributes at all. How do I make LoginVM "traverse" through its members to validate them all? Am I doing something fundamentally wrong using ModelState in this manner?

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  • Problems setting up AuthLogic

    - by sscirrus
    Hi all, I'm trying to set up a simple login using AuthLogic into my User table. Every time I try, the login fails and I don't know why. I'm sure this is a simple error but I've been hitting a brick wall with it for a while. #user_sessions_controller def create @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Login successful!" else flash[:notice] = "We couldn't log you in. Please try again!" redirect_to :controller => "index", :action => "index" end end #_user_login.html.erb (this is the partial from my index page where Users log in) <% form_tag user_session_path do %> <p><label for="login">Login:</label> <%= text_field_tag "login", nil, :class => "inputBox", :id => "login", </p> <p><label for="password">Password: </label> <%= password_field_tag "password", nil, :class => "inputBox", :id => "password", </p> <p><%= submit_tag "submit", :class => "submit" %></p> <% end %> I had Faker generate some data for my user table but I cannot log in! Every time I try it just redirects to index. Where am I going wrong? Thanks everybody.

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  • Cucumber-rails on jruby installs gem into my apps root directory with bundler

    - by brad
    Just installed cucumber 0.7.2 and cucumber-rails 0.3.1 with jruby-1.4.0 on OSX. When I run a bundle install, it places a cucumber-rails directory in my main app with all of the gem code/dependencies. First off, this is definitely not what I want and I'm not sure why this happens for cucumber-rails only. Second, if I delete this folder and just manually install cucumber-rails, when I run script/generate feature blah I get /Users/bradrobertson/.rvm/rubies/jruby-1.4.0/lib/ruby/site_ruby/1.8/rubygems/source_index.rb:344:in `refresh!': source index not created from disk (RuntimeError) from /Users/bradrobertson/.rvm/gems/jruby-1.4.0/gems/rails-2.3.5/lib/rails/vendor_gem_source_index.rb:34:in `refresh!' from /Users/bradrobertson/.rvm/gems/jruby-1.4.0/gems/rails-2.3.5/lib/rails/vendor_gem_source_index.rb:29:in `initialize' from /Users/bradrobertson/.rvm/gems/jruby-1.4.0/gems/rails-2.3.5/lib/rails/gem_dependency.rb:21:in `new' from /Users/bradrobertson/.rvm/gems/jruby-1.4.0/gems/rails-2.3.5/lib/rails/gem_dependency.rb:21:in `add_frozen_gem_path' from /Users/bradrobertson/.rvm/gems/jruby-1.4.0/gems/rails-2.3.5/lib/initializer.rb:298:in `add_gem_load_paths' from /Users/bradrobertson/.rvm/gems/jruby-1.4.0/gems/rails-2.3.5/lib/initializer.rb:132:in `process' from /Users/bradrobertson/.rvm/gems/jruby-1.4.0/gems/rails-2.3.5/lib/initializer.rb:113:in `run' from /Users/bradrobertson/Repos/app/source/trunk/config/environment.rb:13 from /Users/bradrobertson/Repos/app/source/trunk/config/environment.rb:1:in `require' from /Users/bradrobertson/.rvm/gems/jruby-1.4.0/gems/rails-2.3.5/lib/commands/generate.rb:1 from /Users/bradrobertson/.rvm/gems/jruby-1.4.0/gems/rails-2.3.5/lib/commands/generate.rb:3:in `require' from script/generate:3 Similarly running rake cucumber I get rake aborted! source index not created from disk So something obviously doesn't work. If I add that cucumber-rails directory back in, then my rake cucumber actually runs. Can someone tell me why it would need to install the gem right in my rails app? I've never seen this before. setup jruby-1.4.0 cucumber-0.7.2 cucumber-rails 0.3.1 bundler 0.9.23 webrat 0.7.1

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  • automating hudson builds with ant throwing 403

    - by Christopher Dancy
    We have a hudson server which deploys builds. We have a few services which we want to be able to remotely tell hudson to deploy a certain build ... these services are using ant. So I'm trying to get it working but keeping getting a 403 response when giving a build number like so... <ac:post to="http://hostname:8080/hudson/job/test_release_indexes/build?" verbose="true" wantresponse="true"> <prop name="token" value="indexes"/> <prop name="BUILDNUMBER" value="0354"/> </ac:post> this throws the 403. I've also tried passing it props for the username and password like so ... <ac:post to="http://srulesre2:8080/hudson/job/test_dartmouth_indexes/build?" verbose="true" wantresponse="true"> <prop name="token" value="indexes"/> <prop name="BUILDNUMBER" value="0354"/> <prop name="username" value="test"/> <prop name="password" value="test"/> </ac:post> I've tried a hundred different variations on username and password ... like j_username and j_password or user and pass ... but nothing is working ... keep getting the same 403. And the username and password are valid because I can manually log in with admin privileges. Any ideas would be great

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  • How to add custom header to ASMX web service call using jquery?

    - by Mike
    I have a web service with the following contract: POST /Service/service.asmx HTTP/1.1 Host: xxx.xxx.xxx Content-Type: text/xml; charset=utf-8 Content-Length: length SOAPAction: "xxx.xxx.xxx/Service/Method" <?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Header> <Request xmlns="xxx.xxx.xxx/Service/"> <transactiontype>string</transactiontype> <username>string</username> <password>string</password> </Request> </soap:Header> <soap:Body> <Method xmlns="xxx.xxx.xxx/Service/"> <xml>xml</xml> </Method> </soap:Body> </soap:Envelope> And I am trying to call the service using jquery. This is my code: $.ajax({ url: serverUrl + 'Method', type: "POST", dataType: "xml", data: { xml: "xml" }, beforeSend: function (req) { req.setRequestHeader('Header', '<Request xmlns="xxx.xxx.xxx/Service/">' +'<transactiontype>4</transactiontype>' +'<agencyName>name</agencyName>' +'<username>user</username>' +'<password>pass</password>' +'</Request>'); }, success: function (data) { alert(data.text); }, error: function (request, status, errorThrown) { alert(status); } }); However, the header content is not passed to the web service? How would I go about passing the header credentials to my web service call?

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  • Creating a smart text generator

    - by royrules22
    I'm doing this for fun (or as 4chan says "for teh lolz") and if I learn something on the way all the better. I took an AI course almost 2 years ago now and I really enjoyed it but I managed to forget everything so this is a way to refresh that. Anyway I want to be able to generate text given a set of inputs. Basically this will read forum inputs (or maybe Twitter tweets) and then generate a comment based on the learning. Now the simplest way would be to use a Markov Chain Text Generator but I want something a little bit more complex than that as the MKC basically only learns by word order (which word is more likely to appear after word x given the input text). I'm trying to see if there's something I can do to make it a little bit more smarter. For example I want it to do something like this: Learn from a large selection of posts in a message board but don't weight it too much For each post: Learn from the other comments in that post and weigh these inputs higher Generate comment and post See what other users' reaction to your post was. If good weigh it positively so you make more posts that are similar to the one made, and vice versa if negative. It's the weighing and learning from mistakes part that I'm not sure how to implement. I thought about Artificial Neural Networks (mainly because I remember enjoying that chapter) but as far as I can tell that's mainly used to classify things (i.e. given a finite set of choices [x1...xn] which x is this given input) not really generate anything. I'm not even sure if this is possible or if it is what should I go about learning/figuring out. What algorithm is best suited for this? To those worried that I will use this as a bot to spam or provide bad answers to SO, I promise that I will not use this to provide (bad) advice or to spam for profit. I definitely will not post it's nonsensical thoughts on SO. I plan to use it for my own amusement. Thanks!

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  • Javascript check of a form, not waiting for ajax response

    - by Y.G.J
    this is a part of the check in my form function check(theform) { var re = /^\w[0-9A-Za-z]{5,19}$/; if (!re.test(theform.username.value)) { alert("not valid username"); theform.username.focus(); return false; } $.ajax({ type: "POST", url: "username.asp", data: "username="+theform.username.value, success: function(msg){ username = msg; if (!username) { alert("username already in use"); return false; } } }); var re = /^\w[0-9A-Za-z]{5,19}$/; if (!re.test(theform.password.value)) { alert("not valid password"); theform.password.focus(); return false; } } for some reason of sync... it check the username then duplicated username with the ajax and not waiting for respond and jump to the password check. i don't want to insert the rest of the code to isreadystate (or what ever it is) because i might move the username duplicate check to the end... and then the function will end before the ajax anyway what should i do?

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  • Using ZLib unit to compress files vs using ZipForge

    - by user193655
    There are many questions on zipping in Delphi, anyway this is not a duplicate. I am using ZipForge for zip/unzip capability in my application. Currently I use 2 features of ZipForge: 1) zip and unzip (!) 2) password protect the archives Now I am removing the password from all the archives so I need only to zip and unzip files. I zip them just for minimizing bandwith when uploading/downloading files from the server. So my idea is to process all files once for unzipping them (with password) and rezipping them without password. I have nothing against ZipForge, anyway it is an extra component, every time I upgrade to a newest Delphi version I have to wait for the new IDE support and moreover the more components the more problems during the installation. So since what I do is very simple I'd like to replace ZipForge with 2 simple functinos using the ZLib unit. I found (and tested) the functions here on Torry's. What do you think of using Zlib unit? Do you see any potential problem that I would not have with ZipForge? Can you comment on speed?

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  • Comparing textbox.text value to value in SQL Server

    - by Anicho
    Okay so I am trying to compare a login textbox password and username with a custom validator using linq to get information from the database it always returns false though on the validator could someone please tell me where my code below is going wrong. This will be very much appreciated... thank you in advanced... protected void LoginValidate(object source, ServerValidateEventArgs args) { TiamoDataContext context = new TiamoDataContext(); var UsernameCheck = from User in context.Users where User.Username == TextBoxLoginUsername.Text && User.Password == TextBoxLogInPassword.Text select User.Username; var PasswordCheck = from User in context.Users where User.Username == TextBoxLoginUsername.Text && User.Password == TextBoxLogInPassword.Text select User.Password; String test1 = PasswordCheck.ToString(); String test2 = UsernameCheck.ToString(); if (test1 == TextBoxLogInPassword.Text && test2 == TextBoxLoginUsername.Text) { args.IsValid = true; Session["Username"] = TextBoxLoginUsername; Response.Redirect("UserProfile.aspx"); } else { args.IsValid = false; } } I dont know where I am going wrong I know its most probably some sort of silly mistake and me being inexperienced at this...

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  • Trying to use HttpWebRequest to load a page in a file.

    - by Malcolm
    Hi, I have a ASP.NET MVC app that works fine in the browser. I am using the following code to be able to write the html of a retrieved page to a file. (This is to use in a PDF conversion component) But this code errors out continually but not in the browser. I get timeout errors sometimes asn 500 errors. Public Function GetPage(ByVal url As String, ByVal filename As String) As Boolean Dim request As HttpWebRequest Dim username As String Dim password As String Dim docid As String Dim poststring As String Dim bytedata() As Byte Dim requestStream As Stream Try username = "pdfuser" password = "pdfuser" docid = "docid=inv12154" poststring = String.Format("username={0}&password={1}&{2}", username, password, docid) bytedata = Encoding.UTF8.GetBytes(poststring) request = WebRequest.Create(url) request.Method = "Post" request.ContentLength = bytedata.Length request.ContentType = "application/x-www-form-urlencoded" requestStream = request.GetRequestStream() requestStream.Write(bytedata, 0, bytedata.Length) requestStream.Close() request.Timeout = 60000 Dim response As HttpWebResponse Dim responseStream As Stream Dim reader As StreamReader Dim sb As New StringBuilder() Dim line As String = String.Empty response = request.GetResponse() responseStream = response.GetResponseStream() reader = New StreamReader(responseStream, System.Text.Encoding.ASCII) line = reader.ReadLine() While (Not line Is Nothing) sb.Append(line) line = reader.ReadLine() End While File.WriteAllText(filename, sb.ToString()) Catch ex As Exception MsgBox(ex.Message) End Try Return True End Function

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  • curl cookie not creating on success

    - by Bin
    Hi I'm using cUrl(PHP) to post a login request and store response in cookie file. In my second request I'm passing cookie in header and post data to verify it. Issue is that cookie file is not created in first succesful request results in failure for second request. Please suggest me where I'm doing wrong. $cookiefile="/var/www/html/dimdim/cook.txt"; $url_log="http://my.dimdim.com/api/auth/login"; $p_log='request={"account":"bin6k","password":"password","group":"all"}'; $url_ver="http://my.dimdim.com/api/auth/verify"; $p_ver='request={"account":"bin6k","password":"password","group":"all"}'; $ch = curl_init(); //curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_COOKIEJAR, $cookiefile); curl_setopt($ch, CURLOPT_URL,$url_log); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $p_log); ob_start(); // prevent any output $retval=curl_exec ($ch); // execute the curl command ob_end_clean(); // stop preventing output curl_close ($ch); //print_r($retval); unset($ch); $ch = curl_init(); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); curl_setopt($ch, CURLOPT_COOKIEFILE, $cookiefile); curl_setopt($ch, CURLOPT_URL,$url_ver); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $p_log); $buf2 = curl_exec ($ch); curl_close ($ch); echo "".htmlentities($buf2);

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  • Coding Practices which enable the compiler/optimizer to make a faster program.

    - by EvilTeach
    Many years ago, C compilers were not particularly smart. As a workaround K&R invented the register keyword, to hint to the compiler, that maybe it would be a good idea to keep this variable in an internal register. They also made the tertiary operator to help generate better code. As time passed, the compilers matured. They became very smart in that their flow analysis allowing them to make better decisions about what values to hold in registers than you could possibly do. The register keyword became unimportant. FORTRAN can be faster than C for some sorts of operations, due to alias issues. In theory with careful coding, one can get around this restriction to enable the optimizer to generate faster code. What coding practices are available that may enable the compiler/optimizer to generate faster code? Identifying the platform and compiler you use, would be appreciated. Why does the technique seem to work? Sample code is encouraged. Here is a related question [Edit] This question is not about the overall process to profile, and optimize. Assume that the program has been written correctly, compiled with full optimization, tested and put into production. There may be constructs in your code that prohibit the optimizer from doing the best job that it can. What can you do to refactor that will remove these prohibitions, and allow the optimizer to generate even faster code? [Edit] Offset related link

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  • autologin component doesn't work on remote server

    - by user606521
    I am using autologin component from http://milesj.me/code/cakephp/auto-login (v 3.5.1). It works on my localhost WAMP server but fails on remote server. I am using this settings in beforeFilter() callback: $this->AutoLogin->settings = array( // Model settings 'model' => 'User', 'username' => 'username', 'password' => 'password', // Controller settings 'plugin' => '', 'controller' => 'users', // Cookie settings 'cookieName' => 'rememberMe', 'expires' => '+1 month', // Process logic 'active' => true, 'redirect' => true, 'requirePrompt' => true ); On remote server it simply doesn't autolog users after the browser was closed. I can't figure out what may cause the problem. -------------------- edit I figured out what is causing the problem but I don't know how to fix this. First of all cookie is set like this: $this->Cookie->write('key',array('username' => 'someusername', 'hash' => 'somehash', ...) ); Then it's readed like this: $cookie = $this->Cookie->read('key'); On my WAMP server $cookie is array('username' => 'someusername', 'hash' => 'somehash', ...) and on remote server returned $cookie is string(159) "{\"username\":\"YWxlay5iYXJzsdsdZXdza2ldssd21haWwuY29t\",\"password\":\"YWxlazc3ODEy\",\"hash\":\"aa15bffff9ca12cdcgfgb351d8bfg2f370bf458\",\"time\":1339923926}" and it should be: array( 'username' => "YWxlay5iYXJzsdsdZXdza2ldssd21haWwuY29t", 'password' => "YWxlazc3ODEy", ...) Why the retuned cookie is string not array?

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  • python global variable not working in apache

    - by Suhail
    I am facing issue with the global variable, when i run in the django development server it works fine, but in apache it doesn't work here is the code below: red= "/foodfolio3/test/" def showAddRecipe(request): #global objc if "userid" in request.session: objc["ErrorMsgURL"]= "" try: urlList= request.POST URL= str(urlList['url']) URL= URL.strip('http://') URL= "http://" + URL recipe= __addRecipeUrl__(URL) if (recipe == 'FailToOpenURL') or (recipe == 'Invalid-website-URL'): #request.session["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" objc["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" print "here global_context =", objc arurl= HttpResponseRedirect("/foodfolio3/add/import/") arurl['ErrorMsgURL']= objc["ErrorMsgURL"] #return HttpResponseRedirect("/foodfolio3/add/import/") #return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) return (arurl) else: objc["recipe"] = recipe return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) except: objc["recipe"] = "" return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/" return HttpResponseRedirect("/foodfolio3/login") def showAddRecipeUrl(request): if "userid" in request.session: return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/import/" return HttpResponseRedirect("/foodfolio3/login") def showLogin(request): obj = {} obj["error_message"] = "" obj["registered"] = "" if request.method == "POST": if (red == "/foodfolio3/test"): next= '/foodfolio3/recipes' else: next= red try: username = request.POST['username'] password = request.POST['password'] user = authenticate(username=username, password=password) except: user = authenticate(request=request) if user is not None: if user.is_active: login(request, user) request.session["userid"] = user.id # Redirect to a success page. return HttpResponseRedirect(next) this code works fine in django development server, but in apache, the url is getting redirected to '/foodfolio3/recipes'

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  • Apache is looking for htaccess and htpasswd files that aren't there

    - by user1094092
    Having an issue where Apache is requesting authentication, and looking for an .htpasswd file, based on instructions from an .htaccess file that's no longer in DocumentRoot. Background: In my DocumentRoot, I'd previously copied an .htaccess and .htpasswd file from another machine (along with all of the other website files). .htaccess contents: AuthType Basic AuthName "Password is required" AuthUserFile /some/directory/that/was/on/the/other/server/not/this/one/.htpasswd Require valid-user Here's the catch: I moved .htaccess and .htpasswd out of DocumentRoot and even renamed the files. There is no longer an .htaccess file in DocumentRoot at all. But, when I try to access localhost from a browser, I am prompted to enter the login and password. When I enter the login and password (from the old, not-in-DocumentRoot .hpasswd file), I get a 500 Internal Server error and the log shows: [error] [client 127.0.0.1] (2)No such file or directory: Could not open password file: /some/directory/that/was/on/the/other/server/not/this/one/.htpasswd This has been quite a puzzle, because there's no longer a .htaccess or .htpasswd file anywhere in DocumentRoot !! Have tried several apache restarts and also tried using a blank .htaccess file in the DocumentRoot. Even grepped the entire machine for references to AuthType Basic to see if I missed anything. httpd.conf looks normal enough...I can post that if needed, but this question seems long enough as it is :) Thanks for any assistance you can provide

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  • How do you verify that 2 copies of a VB 6 executable came from the same code base?

    - by Tim Visher
    I have a program under version control that has gone through multiple releases. A situation came up today where someone had somehow managed to point to an old copy of the program and thus was encountering bugs that have since been fixed. I'd like to go back and just delete all the old copies of the program (keeping them around is a company policy that dates from before version control was common and should no longer be necessary) but I need a way of verifying that I can generate the exact same executable that is better than saying "The old one came out of this commit so this one should be the same." My initial thought was to simply MD5 hash the executable, store the hash file in source control, and be done with it but I've come up against a problem which I can't even parse. It seems that every time the executable is generated (method: Open Project. File Make X.exe) it hashes differently. I've noticed that Visual Basic messes with files every time the project is opened in seemingly random ways but I didn't think that would make it into the executable, nor do I have any evidence that that is indeed what's happening. To try to guard against that I tried generating the executable multiple times within the same IDE session and checking the hashes but they continued to be different every time. So that's: Generate Executable Generate MD5 Checksum: md5sum X.exe > X.md5 Verify MD5 for current executable: md5sum -c X.md5 Generate New Executable Verify MD5 for new executable: md5sum -c X.md5 Fail verification because computed checksum doesn't match. I'm not understanding something about either MD5 or the way VB 6 is generating the executable but I'm also not married to the idea of using MD5. If there is a better way to verify that two executables are indeed the same then I'm all ears. Thanks in advance for your help!

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  • a + sing in email address

    - by d.andreykiv
    Hi. I need to submit an email address with a "+" sign and validate in on server. But server receives email like "[email protected]" as "aaa [email protected]". I send all data as POST request with following code NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"%@%@", url, @"/signUp"]]; NSString *post = [NSString stringWithFormat:@"&email=%@&userName=%@&password=%@", user.email, user.userName, user.password]; NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:NO]; NSData* data = [self sendRequest:url postData:postData]; post variable before encoding has value &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf after encoding it is same &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf Method I use to send request looks like following code: -(id) sendRequest:(NSURL*) url postData:(NSData*)postData { // Create request NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:postData]; NSURLResponse *urlResponse; NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:nil]; [request release]; return data; }

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