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  • Please help me understand this PHP script.Noob here

    - by NissGTR
    I'm learning PHP,MySQL and came across this function today function get_director($director_id) { global $db; $query = 'SELECT people_fullname FROM people WHERE people_id = ' . $director_id; $result = mysql_query($query, $db) or die(mysql_error($db)); $row = mysql_fetch_assoc($result); extract($row); return $people_fullname; } I understand what functions are and I've created a few while learning PHP.But this one is a bit more complicated.I can't understand the WHERE people_id = ' . $director_id I'm new to MySQL.I guess the single quote ends the MySQL statement?And then it is concatenated with the argument? Please help me out.

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  • Help with PHP and associative arrays

    - by errata
    Hello. I have to do a simple calculator in php based on user's input and choice from select field, something like this: <?php $a = $_GET['a']; $b = $_GET['b']; $array = array( "option1" => 0.1, "option2" => 0.15, "option3" => 0.3, "option4" => 3, "option5" => 3, "option6" => 16, "option7" => 16, "option8" => 16 ); echo "<form action='calc.php' method='get'>"; echo "<input type='text' name='a' value='".$a."'> of "; echo "<select name='b'>"; foreach ($array as $k => $v) { echo "<option value='".$v."'>".$k."</option>"; } echo "</select> "; echo "<input type='submit' value='='> "; $total_volume = $a * $b; echo $total_volume; echo "</form>"; ?> Well, for now everything works fine, but the idea is that after user submits form, the page reloads with sent amount in input field and selected option which user actually selected... First thing is easy: I just put value="a" in my input field, but I'm not sure how to make a selected option in <select> field??? I started with this: foreach ($array as $k => $v) { echo "<option value='".$v."'"; if ($b == $v) { echo " selected "; } echo ">".$k."</option>"; } ...but this is obviously not working as expected... Please help me with this easy one :) Thanks!

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • Populate javascript array with PHP array of Variables

    - by user1704514
    The following code is used to populate a pie chart in javascript: <script type="text/javascript"> var agg = { label: 'Aggressive', pct: [60, 10, 6, 30, 14, 10] }, bal = { label: 'Balanced', pct: [24, 7, 2, 18, 13, 36] }, mod = { label: 'Moderate', pct: [12, 4, 2, 10, 11, 61] }, inc = { label: 'Income', pct: [ 0, 0, 0, 0, 0,100] }, </script> Instead of tm: [40, 60, 67, 30, 74, 50] as seen above, I would like to make each of 6 values a php variable. Like: tm: [$r1, $r2, $r3, $r4, $r5, $r6] . How do I do this? How do I do this with? A php array or json encode?

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  • Using PHP interfaces in Codeigniter

    - by John Stewart
    I am trying to find out how can I used PHP interfaces in my MVC design. I want to make sure that the design enforces an interface so that any new module would follow that. For example: <?php interface BaseAPI { public function postMessage($msg); } class ServiceAPI implements BaseAPI { public function postMessage($msg) { return $msg; } } class Service_Two_API implements BaseAPI { public function postMessage($msg) { return "can't do this: ".$msg; } } ?> I want to do this in CI. Is it possible? how should I design it?

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  • retrieved upload images in php

    - by hunter
    i want to retrieve image from client (ipod) programmed in objective c i use the following code $TARGET_PATH = "pics/"; $image = $_FILES['photo']; $TARGET_PATH =$TARGET_PATH . basename( $_FILES['photo']['name']); $TARGET_PATH =$TARGET_PATH.".jpg"; if(file_exists($TARGET_PATH)) { $TARGET_PATH =$TARGET_PATH .uniqid() . ".jpg"; } if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { $TARGET_PATH="http://www.".$_SERVER["SERVER_NAME"]."/abc/".$TARGET_PATH; echo $TARGET_PATH; echo "image upload successfully";} else{ echo "could not upload image"; } this code upload five to six images successfully and after that it gives me error i.e Notice: Undefined index: photo in /home/abc/public_html/abc.com/fish/mycatch_post.php on line 42 Notice: Undefined index: photo in /home/abc/public_html/abc.com/fish/mycatch_post.php on line 53 could not upload image

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  • simple php script

    - by Nerdysyntax
    New to php and taking a class for it. Bought php6 and mysql 6 bible to get started. Of course the hello world script is the first you get and it doesn't show. It just reads part of my script and I'm not sure the problem. Link to test - http://harden6615.com/ I am using a hosted server I bought for class, but I have also check it using MAMP. I figured my script is wrong, but I have copied and pasted and still no Hello World. Any suggestions? What I copied: <?php print("Hello, World<BR />\n"); phpinfo(); ?>

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  • Using PHP's $_COOKIE to create cookie.txt for cURL

    - by boogie
    Hi, I'm running Drupal and Mediawiki on my server under the same domain. They are connected to each other with extensions/modules. Meaning if I log in to Mediawiki, it automatically logs into Drupal also. Mediawiki has some extensions that filter the information shown on the page. What I want to do is to show that filtered information from Mediawiki on my Drupal page. I'm trying to fetch the data with PHP cURL, but I'm not able to force it to use the login information. How can I convert PHP's $_COOKIE into cURL cookie.txt format? I suppose after that I'm able to fetch the data from Mediawiki with the right permissions. This is what print_r($_COOKIE) outputs: [wiki_session] = gg05lhd6pcfs5g6iokhoo0gue7 [wikiUserName] = WikiSysop [wikiLoggedOut] = 20100510110913 [wikiUserID] = 1 [wikiToken] = 52cdb19a7b4a43e5a2f86939e4f54941 Thanks for any help!

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  • test php disabled caching

    - by user1691389
    My site had a problem in that certain browsers (especially opera and gecko) were "over-caching" (caching far too much for my taste). I've just added the following PHP snippet to hopefully disable caching in all browsers: <?php header("Expires: Tue, 01 Jan 2000 00:00:00 GMT"); header("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT"); header("Cache-Control: no-store, no-cache, must-revalidate, max-age=0"); header("Cache-Control: post-check=0, pre-check=0", false); header("Pragma: no-cache"); ?> Question: How would you test this out, to make sure it actually works?

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  • Pretty-print HTML via PHP without validation?

    - by brianjcohen
    I'd like to automatically pretty-print (indentation, mostly) the HTML output that my PHP scripts generate. I've been messing with Tidy, but have found that in its efforts to validate and clean my code, Tidy is changing way too much. I know Tidy's intentions are good but I'm really just looking for an HTML beautifier. Is there a simpler library out there that can run in PHP and just do the pretty-printing? Or, is there a way to configure Tidy to skip all the validation stuff and just beautify?

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  • All PHP files getting hacked

    - by nsearle
    Hey All, Like always, just want to say thank you for all of the help and input in advance. I have a particular site that I am the web developer for and am running into a unique problem. It seems that somehow something is getting into every single PHP file on my site and adding some malware code. I have deleted the code from every page multiple times and changed FTP and DB passwords, but to no avail. The code that is added looks like this - eval(base64_decode(string)) - which the string is 3024 characters. Not sure if anyone else has ran into this problem or if any one has ideas on how I can secure my php code up. Thanks again.

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  • Passing a String from PHP to a JavaScript function

    - by user635614
    Hello. am trying to write a code to pass a php string when clicked on the table : <?php . . . echo("<td onclick = 'print_("$file[$i]->Name");' >". $files[$i]->Name."</td>"); ... ?> where files[] is an array, and each element is a class with Name as a String, and it is put in a ''for'' loop, Am trying to pass it to a JavaScript function where i need the name there,and it's not working,i tried passing the i variable and it was passed correctly so i thought there should be a special syntax for dealing with strings... function print_(var x) { alert(x);}

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  • How to use PHP to POST to a web page then get the results back, locally

    - by Patrick Gates
    I have a page on my web server that is PHP that is set to do this if ($_POST['post'] == true) { echo: 'hello, world'; } I want to create a page that calls to that page, posts "post" equal to "true" and then returns the value "hello, world". I have a script that works, but only if the pages are on different servers. Unfortunately, both of these pages are on the same server, so, heres my code, and I'm hoping you guys can help me, Thank you :) function post($site, $post) { $ch = curl_init(); curl_setopt($ch, CURLOPT_URL,$site); curl_setopt($ch, CURLOPT_FAILONERROR,1); curl_setopt ($ch, CURLOPT_POST, 1); curl_setopt ($ch, CURLOPT_POSTFIELDS, $post); curl_setopt($ch, CURLOPT_FOLLOWLOCATION,1); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); curl_setopt($ch, CURLOPT_TIMEOUT, 15); $retValue = curl_exec($ch); curl_close($ch); return $retValue; } echo post('data.php', 'post=true');

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  • PHP troubleshooting unexpected T_PUBLIC error

    - by jasondavis
    PHP is driving me insane right now, please help me, I must be missing something. In this VERY BASIC example below I get this error... Parse error:syntax error, unexpected T_PUBLIC in C:\filename here on line 12 On this line.... public static function getInstance(){ The code... <?PHP class Session{ private static $instance; function __construct() { { session_start(); echo 'Session object created<BR><BR>'; } public static function getInstance(){ if (!self::$instance) { self::$instance = new Session(); } return self::$instance; } }

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  • Help with php custom popup

    - by user329394
    Hi i have create a custom popup using javascript to use in PHP file. thw popup will appear when user click My Special Website i need to change the title header. Can help me how to do it?? //function: function myPopup() { window.open( "<?=$CFG->wwwroot.'/example.php';?>" ,"myWindow", " height = 300, width = 600, statusbar=0, scrollbars=0,resizable=0, location=0,status=0, directories=0, menubar =0, toolbar =0 , left = 262,top = 234" ) } // call: <a href="#" onclick="myPopup() " >My Special WebSite </a> <span class="style1">*</span> See my sample page:

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  • Ajax gets nothing back from the php.

    - by ShaMun
    Jquery i dont have alert and firefox i dont have anything in return. The code was working before, database query have successfull records also. What i am missing??? Jquery ajax. $.ajax({ type : "POST", url : "include/add_edit_del.php?model=teksten_display", data : "oper=search&ids=" + _id , dataType: "json", success : function(msg){ alert(msg); } }); PHP case 'teksten_display': $id = $_REQUEST['ids']; $res = $_dclass-_query_sql( "select a,b,id,wat,c,d from tb1 where id='" . $id . "'" ); $_rows = array(); while ( $rows = mysql_fetch_array ($res) ) { $_rows = $rows; } //header('Cache-Control: no-cache, must-revalidate'); //header('Expires: Mon, 26 Jul 1997 05:00:00 GMT'); header('Content-type: application/json'); echo utf8_encode( json_encode($_rows) ) ; //echo json_encode($_rows); //var_dump($_rows); //print_r ($res); break; Firefox response/request header Date Sat, 24 Apr 2010 22:34:55 GMT Server Apache/2.2.3 (CentOS) X-Powered-By PHP/5.1.6 Expires Thu, 19 Nov 1981 08:52:00 GMT Cache-Control no-store, no-cache, must-revalidate, post-check=0, pre-check=0 Pragma no-cache Content-Length 0 Connection close Content-Type application/json Host www.xxxx.be User-Agent Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.1.9) Gecko/20100330 Fedora/3.5.9-2.fc12 Firefox/3.5.9 Accept application/json, text/javascript, */* Accept-Language en-us,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 300 Connection keep-alive Content-Type application/x-www-form-urlencoded; charset=UTF-8 X-Requested-With XMLHttpRequest Referer http://www.xxxx.be/xxxxx Content-Length 17 Cookie csdb=2; codb=5; csdbb=1; codca=1.4; csdca=3; PHPSESSID=benunvkpecqh3pmd8oep5b55t7; CAKEPHP=3t7hrlc89emvg1hfsc45gs2bl2

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  • PHP HTML variable

    - by Abakiz Myth
    In Coldfusion we have the variable: <cfsavecontent name="HTML_content"> <div class="test_div" style="color:#FFF;">Test</div> </cfsavecontent> Within PHP there seems to be no way of doing this without some really hacky function or escaping double quotes. I'm trying to create emails (large html documents) within the same page by saving the email content and simply mailing it but it seems like there's no way of doing this within PHP without using $var = "\"crap\""; Can somebody point me in the right direction?

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  • Most reliable method for uploading files in PHP w/ progress bar

    - by vanneto
    Hello everyone, I am interested in finding the most reliable method for uploading files in PHP. I need a progress bar with the upload. I have tried SWFUpload but it randomly issues an I/O Error. Even if the same file is uploaded sometimes there is an error and sometimes there is not. I have configured all the necessary INI/Mysql/Apache directives to accept large file uploads. So, I am looking for alternatives as a Flash based solution has not worked. Would Java be more relirable? I have also looked into PHP with APC. I definitely cannot afford these random errors, so any help on reliable software / suggestions on how to minimize them would be appreciated. Thank you.

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  • removing index.php of codeigniter on local

    - by Aldi Aryanto
    i'm trying to remove index.php,in my localhost, but it seems doesn't working,its on http://localhost/testing i put .htacces in 'testing' directory under the htdocs LoadModule rewrite_module modules/mod_rewrite.so at apache/conf also already uncheck here my .htaccess RewriteEngine On RewriteBase /testing/ RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ /testing/index.php/$1 [L] here my config $config['base_url'] = "http://localhost/testing"; $config['index_page'] = ''; $config['uri_protocol'] = 'AUTO'; when i access login controller, it's not found Not Found The requested URL /testing/login was not found on this server. I really don't know what to try next. Any help would be appreciated.

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  • How to check if a checkbox/ radio button is checked in php

    - by user225269
    I have this html code: <tr> <td><label><input type="text" name="id" class="DEPENDS ON info BEING student" id="example">ID</label></td> </tr> <tr> <td> <label> <input type="checkbox" name="yr" class="DEPENDS ON info BEING student"> Year</label> </td> </tr> But I don't have any idea on how do I check this checkboxes if they are checked using php, and then output the corresponding data based on the values that are checked. Please help, I'm thinking of something like this. But of course it won't work, because I don't know how to equate checkboxes in php if they are checked: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $id = mysql_real_escape_string($_POST['idnum']); if($_POST['id'] == checked & $_POST['yr'] ==checked ){ $result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> </tr>"; while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?>

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