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  • Populate javascript array with PHP array of Variables

    - by user1704514
    The following code is used to populate a pie chart in javascript: <script type="text/javascript"> var agg = { label: 'Aggressive', pct: [60, 10, 6, 30, 14, 10] }, bal = { label: 'Balanced', pct: [24, 7, 2, 18, 13, 36] }, mod = { label: 'Moderate', pct: [12, 4, 2, 10, 11, 61] }, inc = { label: 'Income', pct: [ 0, 0, 0, 0, 0,100] }, </script> Instead of tm: [40, 60, 67, 30, 74, 50] as seen above, I would like to make each of 6 values a php variable. Like: tm: [$r1, $r2, $r3, $r4, $r5, $r6] . How do I do this? How do I do this with? A php array or json encode?

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  • Ajax gets nothing back from the php.

    - by ShaMun
    Jquery i dont have alert and firefox i dont have anything in return. The code was working before, database query have successfull records also. What i am missing??? Jquery ajax. $.ajax({ type : "POST", url : "include/add_edit_del.php?model=teksten_display", data : "oper=search&ids=" + _id , dataType: "json", success : function(msg){ alert(msg); } }); PHP case 'teksten_display': $id = $_REQUEST['ids']; $res = $_dclass-_query_sql( "select a,b,id,wat,c,d from tb1 where id='" . $id . "'" ); $_rows = array(); while ( $rows = mysql_fetch_array ($res) ) { $_rows = $rows; } //header('Cache-Control: no-cache, must-revalidate'); //header('Expires: Mon, 26 Jul 1997 05:00:00 GMT'); header('Content-type: application/json'); echo utf8_encode( json_encode($_rows) ) ; //echo json_encode($_rows); //var_dump($_rows); //print_r ($res); break; Firefox response/request header Date Sat, 24 Apr 2010 22:34:55 GMT Server Apache/2.2.3 (CentOS) X-Powered-By PHP/5.1.6 Expires Thu, 19 Nov 1981 08:52:00 GMT Cache-Control no-store, no-cache, must-revalidate, post-check=0, pre-check=0 Pragma no-cache Content-Length 0 Connection close Content-Type application/json Host www.xxxx.be User-Agent Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.1.9) Gecko/20100330 Fedora/3.5.9-2.fc12 Firefox/3.5.9 Accept application/json, text/javascript, */* Accept-Language en-us,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 300 Connection keep-alive Content-Type application/x-www-form-urlencoded; charset=UTF-8 X-Requested-With XMLHttpRequest Referer http://www.xxxx.be/xxxxx Content-Length 17 Cookie csdb=2; codb=5; csdbb=1; codca=1.4; csdca=3; PHPSESSID=benunvkpecqh3pmd8oep5b55t7; CAKEPHP=3t7hrlc89emvg1hfsc45gs2bl2

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  • PHP exec error, possibly MAMP using ghostscript

    - by user1762526
    I have been trying to use ghostscript in PHP to convert pdf files to images (png, jpg). I don't really care as long as they are images. This is the code that I used. exec("gs -sDEVICE=jpeg -sOutputFile=/Applications/Mamp/htdocs/cover.jpg -r144 /Applications/Mamp/htdocs/test.pdf"); When I enter the exact same thing, without the exec and quotes obviously, into the command line it does exactly what I want. However, when I run the php file nothing happens. I am using a MAMP server and the server seems to work fine, whenever I run another file with it I have no issues. Anyone have any ideas why it might not execute right?

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  • Any valid use of goto in PHP?

    - by nikic
    I know, there are other questions about the goto statement introduced in PHP 5.3. But I couldn't find any decent answer in there, all were of the type "last resort", "xkcd", "evil", "bad", "EVIL!!!". But no valid example. Only statements that there aren't any uses. Or statements that there are some rare use cases (again, without examples). So, the question is: "Which are the valid uses of goto in PHP". Answers for "Is goto evil" are not welcome and will get downvoted. Thanks :) Or does somebody have a link to an RFC where the decision is explained - I couldn't find one.

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  • Most reliable method for uploading files in PHP w/ progress bar

    - by vanneto
    Hello everyone, I am interested in finding the most reliable method for uploading files in PHP. I need a progress bar with the upload. I have tried SWFUpload but it randomly issues an I/O Error. Even if the same file is uploaded sometimes there is an error and sometimes there is not. I have configured all the necessary INI/Mysql/Apache directives to accept large file uploads. So, I am looking for alternatives as a Flash based solution has not worked. Would Java be more relirable? I have also looked into PHP with APC. I definitely cannot afford these random errors, so any help on reliable software / suggestions on how to minimize them would be appreciated. Thank you.

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  • Pretty-print HTML via PHP without validation?

    - by brianjcohen
    I'd like to automatically pretty-print (indentation, mostly) the HTML output that my PHP scripts generate. I've been messing with Tidy, but have found that in its efforts to validate and clean my code, Tidy is changing way too much. I know Tidy's intentions are good but I'm really just looking for an HTML beautifier. Is there a simpler library out there that can run in PHP and just do the pretty-printing? Or, is there a way to configure Tidy to skip all the validation stuff and just beautify?

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  • Stopping an if clause along with the whole PHP script, but not HTML

    - by user626816
    Hello there, I've been having this problem for around an hour, and have searched the internet for answers. I've checked the PHP documentation, looked around, Googled, nothing. Anyways, my problem is that after I try to validate something (and it's wrong), if I use exit; it will also stop the HTML after. Here's what I'm talking about: if ($_POST['exampleEmail'] == "") { echo "Please enter an e-mail."; //Now I want only the PHP script to stop, however... exit; //If I use exit, then the HTML after this script (footer) doesn't show. } If anyone can help, please do. I've tried using break, but to no avail, since it's only for loops and switches. If there is a better/more correct (or simply correct if this is the wrong way), please share. I've had this problem in the past, and I just used exit then. Thanks.

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  • Instantiating class by string using PHP 5.3 namespaces

    - by Kevin
    I can't get around an issue instantiating a new class by using a string variable and PHP 5.3. namespaces. For example, this works; $class = 'Reflection'; $object = new $class(); However, this does not; $class = '\Application\Log\MyClass'; $object = new $class(); A fatal error gets thrown stating the class cannot be found. However it obviously can be instantiated if using the FQN i.e.; $object = new \Application\Log\MyClass; I've found this to be aparrent on PHP 5.3.2-1 but not not in later versions. Is there a work around for this?

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  • stream output of a command continuously run in php

    - by chandan kharbanda
    i am running this simple command { ./a.out < in; } & output.txt using exec and i want to output what's coming in output.txt through ajax request continuously. Also i want a way to turn off my output buffering.I tried flush() and ob functions but didn't succedded.In my /etc/php5/apache2/php.ini php.ini value of output_buffering = 4096.When I change it to Off and restart my apache2 server it fails to restart.P.S. I am using lamp server.

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • How to check if a checkbox/ radio button is checked in php

    - by user225269
    I have this html code: <tr> <td><label><input type="text" name="id" class="DEPENDS ON info BEING student" id="example">ID</label></td> </tr> <tr> <td> <label> <input type="checkbox" name="yr" class="DEPENDS ON info BEING student"> Year</label> </td> </tr> But I don't have any idea on how do I check this checkboxes if they are checked using php, and then output the corresponding data based on the values that are checked. Please help, I'm thinking of something like this. But of course it won't work, because I don't know how to equate checkboxes in php if they are checked: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $id = mysql_real_escape_string($_POST['idnum']); if($_POST['id'] == checked & $_POST['yr'] ==checked ){ $result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> </tr>"; while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?>

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  • Please help me understand this PHP script.Noob here

    - by NissGTR
    I'm learning PHP,MySQL and came across this function today function get_director($director_id) { global $db; $query = 'SELECT people_fullname FROM people WHERE people_id = ' . $director_id; $result = mysql_query($query, $db) or die(mysql_error($db)); $row = mysql_fetch_assoc($result); extract($row); return $people_fullname; } I understand what functions are and I've created a few while learning PHP.But this one is a bit more complicated.I can't understand the WHERE people_id = ' . $director_id I'm new to MySQL.I guess the single quote ends the MySQL statement?And then it is concatenated with the argument? Please help me out.

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  • retrieve value from db in php

    - by wangdoo
    I have a db in which 1 column value will be always null.I want it to pass to next page but it is passing all values of other column except this null value column. This is my code $row=mysql_query("SELECT * FROM `thirdpartycategorymaster` WHERE ISNULL(`delete`)"); while($row1=mysql_fetch_array($row)) { <td><b><a href="catdel.php?head1=<?php echo $row1['ThirdPartyCategoryName'] . '&&msg1=' . $row1['ThirdPartyCategoryID'] . '&&ctdel=' . $row1['delete']; ?> ">Delete</a></b></td> This my db table ThirdPartyCategoryID ThirdPartyCategoryName delete 29 ecommerce NULL

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  • All PHP files getting hacked

    - by nsearle
    Hey All, Like always, just want to say thank you for all of the help and input in advance. I have a particular site that I am the web developer for and am running into a unique problem. It seems that somehow something is getting into every single PHP file on my site and adding some malware code. I have deleted the code from every page multiple times and changed FTP and DB passwords, but to no avail. The code that is added looks like this - eval(base64_decode(string)) - which the string is 3024 characters. Not sure if anyone else has ran into this problem or if any one has ideas on how I can secure my php code up. Thanks again.

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  • Passing a String from PHP to a JavaScript function

    - by user635614
    Hello. am trying to write a code to pass a php string when clicked on the table : <?php . . . echo("<td onclick = 'print_("$file[$i]->Name");' >". $files[$i]->Name."</td>"); ... ?> where files[] is an array, and each element is a class with Name as a String, and it is put in a ''for'' loop, Am trying to pass it to a JavaScript function where i need the name there,and it's not working,i tried passing the i variable and it was passed correctly so i thought there should be a special syntax for dealing with strings... function print_(var x) { alert(x);}

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  • Using PHP interfaces in Codeigniter

    - by John Stewart
    I am trying to find out how can I used PHP interfaces in my MVC design. I want to make sure that the design enforces an interface so that any new module would follow that. For example: <?php interface BaseAPI { public function postMessage($msg); } class ServiceAPI implements BaseAPI { public function postMessage($msg) { return $msg; } } class Service_Two_API implements BaseAPI { public function postMessage($msg) { return "can't do this: ".$msg; } } ?> I want to do this in CI. Is it possible? how should I design it?

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  • retrieved upload images in php

    - by hunter
    i want to retrieve image from client (ipod) programmed in objective c i use the following code $TARGET_PATH = "pics/"; $image = $_FILES['photo']; $TARGET_PATH =$TARGET_PATH . basename( $_FILES['photo']['name']); $TARGET_PATH =$TARGET_PATH.".jpg"; if(file_exists($TARGET_PATH)) { $TARGET_PATH =$TARGET_PATH .uniqid() . ".jpg"; } if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { $TARGET_PATH="http://www.".$_SERVER["SERVER_NAME"]."/abc/".$TARGET_PATH; echo $TARGET_PATH; echo "image upload successfully";} else{ echo "could not upload image"; } this code upload five to six images successfully and after that it gives me error i.e Notice: Undefined index: photo in /home/abc/public_html/abc.com/fish/mycatch_post.php on line 42 Notice: Undefined index: photo in /home/abc/public_html/abc.com/fish/mycatch_post.php on line 53 could not upload image

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  • Help with PHP and associative arrays

    - by errata
    Hello. I have to do a simple calculator in php based on user's input and choice from select field, something like this: <?php $a = $_GET['a']; $b = $_GET['b']; $array = array( "option1" => 0.1, "option2" => 0.15, "option3" => 0.3, "option4" => 3, "option5" => 3, "option6" => 16, "option7" => 16, "option8" => 16 ); echo "<form action='calc.php' method='get'>"; echo "<input type='text' name='a' value='".$a."'> of "; echo "<select name='b'>"; foreach ($array as $k => $v) { echo "<option value='".$v."'>".$k."</option>"; } echo "</select> "; echo "<input type='submit' value='='> "; $total_volume = $a * $b; echo $total_volume; echo "</form>"; ?> Well, for now everything works fine, but the idea is that after user submits form, the page reloads with sent amount in input field and selected option which user actually selected... First thing is easy: I just put value="a" in my input field, but I'm not sure how to make a selected option in <select> field??? I started with this: foreach ($array as $k => $v) { echo "<option value='".$v."'"; if ($b == $v) { echo " selected "; } echo ">".$k."</option>"; } ...but this is obviously not working as expected... Please help me with this easy one :) Thanks!

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  • test php disabled caching

    - by user1691389
    My site had a problem in that certain browsers (especially opera and gecko) were "over-caching" (caching far too much for my taste). I've just added the following PHP snippet to hopefully disable caching in all browsers: <?php header("Expires: Tue, 01 Jan 2000 00:00:00 GMT"); header("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT"); header("Cache-Control: no-store, no-cache, must-revalidate, max-age=0"); header("Cache-Control: post-check=0, pre-check=0", false); header("Pragma: no-cache"); ?> Question: How would you test this out, to make sure it actually works?

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  • How to know record has been updated successfully in php

    - by Lisa Ray
    $sql = "UPDATE...."; if(mysql_query($sql)) { $_SESSION['Trans']="COMMIT"; header("location:result.php"); exit; } else { $_SESSION['Trans']="FAIL"; $_SESSION['errors'] = "Error: Sorry! We are unable to update your Profile, Please contact to PNP HelpDesk."; header("location:result.php"); exit; }//end IF data is getting updated then why compiler is not coming inside IF condition.

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