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  • test php disabled caching

    - by user1691389
    My site had a problem in that certain browsers (especially opera and gecko) were "over-caching" (caching far too much for my taste). I've just added the following PHP snippet to hopefully disable caching in all browsers: <?php header("Expires: Tue, 01 Jan 2000 00:00:00 GMT"); header("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT"); header("Cache-Control: no-store, no-cache, must-revalidate, max-age=0"); header("Cache-Control: post-check=0, pre-check=0", false); header("Pragma: no-cache"); ?> Question: How would you test this out, to make sure it actually works?

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  • Force freeing memory in PHP

    - by DBa
    Hi everybody, in a PHP program, I sequentially read a bunch of files (with file_get_contents), gzdecode them, json_decode the result, analyze the contents, throw the most of it away, and store about 1% in an array. Unfortunately, with each iteration (I traverse over an array containing the filenames), there seems to be some memory lost (according to memory_get_peak_usage, about 2-10 MB each time). I have double- and triplechecked my code, I am not storing unneded data in the loop (and the needed data hardly exceeds about 10MB overall), but I am frequently rewriting (actually, strings in an array). Apparently, PHP does not free the memory correctly, thus using more and more RAM until it hits the limit. Is there any way to do a forced garbage collection? Or, at least, to find out where the memory is used? Thanks in advance, Dmitri

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  • javascript not loading after output of PHP file_get_contents() string

    - by mives
    I have the following structure: -uploadpage.html -index.php -resources -jquery.1.4.2.min.js On my index.php, I get the contents then output uploadpage.html through this code: $output = file_get_contents("uploadpage.html"); echo $output; My upload.html has the javascript at the bottom: <script type="text/javscript" src="./resources/jquery-1.4.2.min.js"></script> <script type="text/javascript"> $(document).ready( function() { callSomething(); } ); function callSomething() {return true;} </script> However this results in an error "$ is not defined" which means that the jquery js file is not loaded. Any ideas?

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • ASP.NET equivalent of this PHP code

    - by moiz217
    Please provide asp.net equivalent of this php code. $ip = $_REQUEST['ip']?$_REQUEST['ip']:$_SERVER["REMOTE_ADDR"]; $client = new SoapClient(null, array( 'location' => "http://www.itistimed.com/soap/whois-city.php", 'uri' => "http://www.itistimed.com/soap/req")); $data = $client->ipToCountryCity($ip); var_dump($data); Will display something like: array(7) { ["status"]= int(1) ["status_text"]= string(7) "Success" ["country"]= string(2) "US" ["city"]= string(13) "Mountain View" ["state"]= string(2) "CA" ["zip"]= string(5) "94043" ["org"]= string(11) "Google Inc."} thanks.

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  • simple php script

    - by Nerdysyntax
    New to php and taking a class for it. Bought php6 and mysql 6 bible to get started. Of course the hello world script is the first you get and it doesn't show. It just reads part of my script and I'm not sure the problem. Link to test - http://harden6615.com/ I am using a hosted server I bought for class, but I have also check it using MAMP. I figured my script is wrong, but I have copied and pasted and still no Hello World. Any suggestions? What I copied: <?php print("Hello, World<BR />\n"); phpinfo(); ?>

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  • how to get the value of checksum in php header

    - by sumit
    I have a header in php which contains a link like <?php header("Location: "."https://abc.com/ppp/purchase.do?version=3.0&". "merchant_id=<23255>&merchant_site_id<21312>&total_amount=<69.99>&". "currency=<USD>&item_name_1=<incidentsupporttier1>&item_amount_1=<1>&". "time_stamp=<2010-06-14.14:34:33>&**checksum=<calculated_checksum>**"); ?> when i run this page the value of checksum is calculated and the link is opened now how checksum is calculated? calculated_checksum=md5(abc); md5 is an algorithm which calculates the value of checksum based on certain values inside the bracket. now i want to know how can i pass the value of checksum in the header url

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  • .net equivalent for php preg_replace

    - by Hath
    What is the c#.net equivalent for php's preg_replace function? php code is like this: const ALLOW_VALUES = '[^a-z0-9àáâäèéêëìíîïòóôöùûwýÿyÁÂÄÈÉÊËÌÎÏÒÓÔÖÙÛÜWYÝ]'; public function streetTownHash($data, $hashCheck = false, $updateRecord = false) { foreach($data as $key=>$value){ try{ $value = mb_convert_case($value, MB_CASE_LOWER, "UTF-8"); } catch(Exception $e) { echo "Requires extension=php_mbstring.dll enabled ! - $e"; } $valueConcat .= preg_replace('/'.self::ALLOW_VALUES.'/','',$value); # Remove punctuation etc } $streetTownHash = sha1($valueConcat); .... this is as far as i've got but not sure about it.. private SHA1 hash = SHA1.Create(); private string hashAllowed = "[^a-z0-9àáâäèéêëìíîïòóôöùûwýÿyÁÂÄÈÉÊËÌÎÏÒÓÔÖÙÛÜWYÝ]"; public string HashString(string value) { value = // = regex not sure this part var bytes = ASCIIEncoding.UTF8.GetBytes(value); var hashed = hash.ComputeHash(bytes); return ASCIIEncoding.UTF8.GetString(hashed); }

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  • Create unique links for indvidual elements of a PHP generated table

    - by typoknig
    I have a table generated from some PHP code that lists a SMALL amount of important information for employees. I want to make it so each row, or at least one element in each row can be clicked on so the user will be redirected to ALL of the information (pulled from MySQL database) related to the employee who was clicked on. I am not sure how would be the best way to go about this, but I am open to suggestions. I would like to stick to PHP and/or JavaScript. Below is the code for my table: <table> <tr> <td id="content_heading" width="25px">ID</td> <td id="content_heading" width="150px">Last Name</td> <td id="content_heading" width="150px">First Name</td> <td id="content_heading" width="75px">SSN</td> </tr> <?php $user = 'user'; $pass = 'pass'; $server = 'localhost'; $link = mysql_connect($server, $user, $pass); if (!$link){ die('Could not connect to database!' . mysql_error()); } mysql_select_db('mydb', $link); $query = "SELECT * FROM employees"; $result = mysql_query($query); mysql_close($link); $num = mysql_num_rows($result); for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr class=".$class.">"; echo "<td>".$row[id]."</td>"; echo "<td>".$row[l_name]."</td>"; echo "<td>".$row[f_name]."</td>"; echo "<td>".$row[ssn]."</td>"; echo "</tr>"; } ?> </table>

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  • PHP Zip Archive sporadically creating multiple files

    - by user516558
    I have a PHP script (running PHP 5.2 on Apache 2.2) that creates a zip archive of files for a user to download. Everything seems to work just fine; the only issue I have is that periodically multiple files will be created before the ZIP archive is successfully finished. Example: archive-name.zip archive-name.zip.a09600 archive-name.zip.b09600 archive-name.zip.c09600 This does not happen every single time; only periodically - the file is still created but sometimes these extra 'files' are left on the server after it finishes. The code that creates the ZIP archive is as follows: $zip_archive = new ZipArchive(); $zip_archive->open($archiveFullName,ZIPARCHIVE::CREATE); if(!file_exists($archiveFullName)) { foreach ($completed_file_arr as $zip_file) { $isFiller = substr($zip_file,-8) == "_err.txt"; if(!$isFiller) { $zip_archive->addFile($zip_file,$localname); } else $zip_archive->addFromString ($zip_file, "The requested source file could not be found."); } } while(!$zip_archive->close()) sleep(1); //ensure that the ZIP file finishes closing

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  • How to know record has been updated successfully in php

    - by Lisa Ray
    $sql = "UPDATE...."; if(mysql_query($sql)) { $_SESSION['Trans']="COMMIT"; header("location:result.php"); exit; } else { $_SESSION['Trans']="FAIL"; $_SESSION['errors'] = "Error: Sorry! We are unable to update your Profile, Please contact to PNP HelpDesk."; header("location:result.php"); exit; }//end IF data is getting updated then why compiler is not coming inside IF condition.

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  • Help with php custom popup

    - by user329394
    Hi i have create a custom popup using javascript to use in PHP file. thw popup will appear when user click My Special Website i need to change the title header. Can help me how to do it?? //function: function myPopup() { window.open( "<?=$CFG->wwwroot.'/example.php';?>" ,"myWindow", " height = 300, width = 600, statusbar=0, scrollbars=0,resizable=0, location=0,status=0, directories=0, menubar =0, toolbar =0 , left = 262,top = 234" ) } // call: <a href="#" onclick="myPopup() " >My Special WebSite </a> <span class="style1">*</span> See my sample page:

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  • PHP OOP problem

    - by Isis
    Hello <?php class Templater { var $params = array(); public static function assign($name, $value) { $this->params[] = array($name => $value); } public static dunction draw() { return $this->params; } } <?php $test = Templater::assign('key', 'value')->draw(); print_r($test); I need to function "assign" was static, but $params was common for the whole class.. BUt this code is not working(( Fatal error: Using $this when not in object context Any ideas?

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  • Help getting PHP sessions to persist after being taken off-site

    - by Rob
    Hi, we're working on a payment gateway system with PHP. We use sessions to store the shopping cart data. The system takes you off-site to the payment processor's site, and then return you to your site. On most hosts, we have no issues when we arrive back at our site and having the session data still be there. On those with an issue, turning off the PHP session referer_check has worked in the past. We don't really want to have to include the PHPSESSID as a GET variable, and hope to avoid that. What I'm looking for is what other server configurations would cause the session to be killed, and any other workarounds there might be. Thanks for your help.

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  • PHP HTML variable

    - by Abakiz Myth
    In Coldfusion we have the variable: <cfsavecontent name="HTML_content"> <div class="test_div" style="color:#FFF;">Test</div> </cfsavecontent> Within PHP there seems to be no way of doing this without some really hacky function or escaping double quotes. I'm trying to create emails (large html documents) within the same page by saving the email content and simply mailing it but it seems like there's no way of doing this within PHP without using $var = "\"crap\""; Can somebody point me in the right direction?

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  • Executing ffmpeg from php running in apache

    - by foobar
    I was executing ffmpeg from php running inside apache. I used to get the error " error while loading shared libraries: libavdevice.so.52: cannot open shared object file: No such file or directory". It used to work perfectly if the php script was executed from the command prompt or ffpmeg was directly invoked from the command prompt. I followed the below steps to fix the apache error: Step 1: Check if the file “libavdevice.so.52? exists in the server using the following command. find / -name ‘libavdevice.so.*’ Step 2: You will get the directory in which the file “libavdevice.so.52? exists from the above command. Suppose the directory is “/usr/local/lib/” in this example. Step 3: You have to add the directory name in the file “/etc/ld.so.conf”. Step 4: Execute the command “ldconfig”. How did doing the above make a difference to apache?

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  • removing index.php of codeigniter on local

    - by Aldi Aryanto
    i'm trying to remove index.php,in my localhost, but it seems doesn't working,its on http://localhost/testing i put .htacces in 'testing' directory under the htdocs LoadModule rewrite_module modules/mod_rewrite.so at apache/conf also already uncheck here my .htaccess RewriteEngine On RewriteBase /testing/ RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ /testing/index.php/$1 [L] here my config $config['base_url'] = "http://localhost/testing"; $config['index_page'] = ''; $config['uri_protocol'] = 'AUTO'; when i access login controller, it's not found Not Found The requested URL /testing/login was not found on this server. I really don't know what to try next. Any help would be appreciated.

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  • Help with PHP and associative arrays

    - by errata
    Hello. I have to do a simple calculator in php based on user's input and choice from select field, something like this: <?php $a = $_GET['a']; $b = $_GET['b']; $array = array( "option1" => 0.1, "option2" => 0.15, "option3" => 0.3, "option4" => 3, "option5" => 3, "option6" => 16, "option7" => 16, "option8" => 16 ); echo "<form action='calc.php' method='get'>"; echo "<input type='text' name='a' value='".$a."'> of "; echo "<select name='b'>"; foreach ($array as $k => $v) { echo "<option value='".$v."'>".$k."</option>"; } echo "</select> "; echo "<input type='submit' value='='> "; $total_volume = $a * $b; echo $total_volume; echo "</form>"; ?> Well, for now everything works fine, but the idea is that after user submits form, the page reloads with sent amount in input field and selected option which user actually selected... First thing is easy: I just put value="a" in my input field, but I'm not sure how to make a selected option in <select> field??? I started with this: foreach ($array as $k => $v) { echo "<option value='".$v."'"; if ($b == $v) { echo " selected "; } echo ">".$k."</option>"; } ...but this is obviously not working as expected... Please help me with this easy one :) Thanks!

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  • Create table with PHP and populate from MySQL

    - by typoknig
    Hi all, I am creating a table to display on a web page and that table is populated from data in a MySQL database. I am trying to do a couple of things that are making it difficult for me. First I am trying to have call the PHP code that exists in a separate file in HTML via JavaScript. I think I have that working right but I am not 100% sure (because the table will not display). I think it is working right because some of the code for the table (which is in the PHP file) displays in FireBug. Second I am trying to make it so the rows alternate colors for easy viewing too. My PHP code so far is below. The table does not display at all in any browser. $query = "SELECT * FROM employees"; $result = mysql_query($query); $num = mysql_num_rows($result); echo '<table>'; for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $id = $row['id']; $l_name = $row['l_name']; $f_name = $row['f_name']; $ssn = $row['ssn']; $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr>"; echo "<td class=" . $class . ">$wrap_id</td>"; echo "<td class=" . $class . ">$wrap_l_name</td>"; echo "<td class=" . $class . ">$wrap_f_name</td>"; echo "<td class=" . $class . ">$wrap_ssn</td>"; echo "</tr>"; } echo '</table>'; mysql_close($link); }

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