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• WP7 - group of textboxes into some sort of template?

  - by Jeff V

  I'm still pretty new at Silverlight so there might be a way to do this, but I'm just unfamiliar with the terminology... I basically have this grouping of textboxes and textblocks and I would like to repeat this same grouping whenever the addNew button is clicked. Is there a way to do this by creating some sort of template? Or do I have to add each item individually. <Grid> <toolkit:ListPicker Height="70" HorizontalAlignment="Right" Name="listPicker1" VerticalAlignment="Top" Width="56" ItemTemplate="{StaticResource PickerItemTemplate}" FullModeItemTemplate="{StaticResource PickerFullModeItemTemplate}" Margin="0,97,167,0"></toolkit:ListPicker> <TextBlock Height="33" HorizontalAlignment="Left" Margin="10,7,0,0" Name="tbDate" Text="Date:" VerticalAlignment="Top" Width="266" /> <TextBlock Height="42" HorizontalAlignment="Left" Margin="9,55,0,0" Name="tbItem" Text="Item:" VerticalAlignment="Top" Width="90" /> <TextBox Height="75" HorizontalAlignment="Left" Margin="92,33,0,0" Name="tbItemName" Text="" VerticalAlignment="Top" Width="341" /> <TextBlock Height="42" HorizontalAlignment="Left" Margin="5,118,0,0" Name="tbServing" Text="Serving:" VerticalAlignment="Top" Width="99" /> <TextBox Height="70" HorizontalAlignment="Left" Margin="90,96,0,0" Name="tbServingValue" Text="" VerticalAlignment="Top" Width="75" /> <TextBlock Height="42" HorizontalAlignment="Left" Margin="156,120,0,0" Name="tbUOM" Text="UOM:" VerticalAlignment="Top" Width="60" /> <Button Content="" HorizontalAlignment="Right" Height="63" Margin="0,100,13,0" VerticalAlignment="Top" Width="132" RenderTransformOrigin="0.455,0.286" Style="{StaticResource wp7_buttonAddNew}" x:Name="btnAddNewItem" Click="btnAddNewItem_Click"/> </Grid> Thanks!

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• Does this query fetch unnecessary information? Should I change the query?

  - by Camran

  I have this classifieds website, and I have about 7 tables in MySql where all data is stored. I have one main table, called "classifieds". In the classifieds table, there is a column called classified_id. This is not the PK, or a key whatsoever. It is just a number which is used for me to JOIN table records together. Ex: classifieds table: fordon table: id => 33 id => 12 classified_id => 10 classified_id => 10 ad_id => 'bmw_m3_92923' This above is linked together by the classified_id column. Now to the Q, I use this method to fetch all records WHERE the column ad_id matches any of the values inside an array, called in this case $ad_arr: SELECT mt.*, fordon.*, boende.*, elektronik.*, business.*, hem_inredning.*, hobby.* FROM classified mt LEFT JOIN fordon ON fordon.classified_id = mt.classified_id LEFT JOIN boende ON boende.classified_id = mt.classified_id LEFT JOIN elektronik ON elektronik.classified_id = mt.classified_id LEFT JOIN business ON business.classified_id = mt.classified_id LEFT JOIN hem_inredning ON hem_inredning.classified_id = mt.classified_id LEFT JOIN hobby ON hobby.classified_id = mt.classified_id WHERE mt.ad_id IN ('$ad_arr')"; Is this good or would this actually fetch unnecessary information? Check out this Q I posted couple of days ago. In the comments HLGEM is commenting that it is wrong etc etc. What do you think? http://stackoverflow.com/questions/2782275/another-rookie-question-how-to-implement-count-here Thanks

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• "Invalid Object Format Name" in Crystal Reports

  - by cmays90

  When working with Crystal Report Field Objects and attempting to set "EnableSuppress" to False or alter the position or width of a field object is generating an "Invalid Object Format Name" error. The debugger shows all my code running without error until attempting to actually load the report. At that point, it will run the first couple without problem, then it fails when messing with a field object, and none of the rest will run. The code is shown below. Everything that generates an error is a FieldObject, but not all fieldObjects generate errors. In the code below, everything in Section2 is a TextObject and everything in Section3 is a FieldObject. If condition = True Then 'Lines marked as runs ok, only run when a line that generates an error is not present before it. Report.Section2.ReportObjects("Text7").Left = 7830 'Runs ok Report.Section3.ReportObjects("Field4").Left = 8085 'Runs ok Report.Section2.ReportObjects("Text13").ObjectFormat.EnableSuppress = False 'Runs ok Report.Section3.ReportObjects("Field28").ObjectFormat.EnableSuppress = False 'error Report.Section2.ReportObjects("Text9").Left = 10830 'Runs ok Report.Section3.ReportObjects("Field23").Left = 10830 'error Report.Section3.ReportObjects("Field23").Width = 615 'error Report.Section2.ReportObjects("Text10").Left = 11445 'Runs ok Report.Section3.ReportObjects("Field25").Left = 11445 'Runs ok End If

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• Python: Behavior of object in set operations

  - by Josh Arenberg

  I'm trying to create a custom object that behaves properly in set operations. I've generally got it working, but I want to make sure I fully understand the implications. In particular, I'm interested in the behavior when there is additional data in the object that is not included in the equal / hash methods. It seems that in the 'intersection' operation, it returns the set of objects that are being compared to, where the 'union' operations returns the set of objects that are being compared. To illustrate: class MyObject: def __init__(self,value,meta): self.value = value self.meta = meta def __eq__(self,other): if self.value == other.value: return True else: return False def __hash__(self): return hash(self.value) a = MyObject('1','left') b = MyObject('1','right') c = MyObject('2','left') d = MyObject('2','right') e = MyObject('3','left') print a == b # True print a == c # False for i in set([a,c,e]).intersection(set([b,d])): print "%s %s" % (i.value,i.meta) #returns: #1 right #2 right for i in set([a,c,e]).union(set([b,d])): print "%s %s" % (i.value,i.meta) #returns: #1 left #3 left #2 left Is this behavior documented somewhere and deterministic? If so, what is the governing principle?

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• how to get the child node in div using javascript

  - by Khushi

  Below is the structure of my div: <div id="ctl00_ContentPlaceHolder1_Jobs_dlItems_ctl01_a" onmouseup="checkMultipleSelection(this,event);"> <table cellpadding="0" cellspacing="0" border="0" width="100%"> <tr> <td style="width:50px; text-align:left;">09:15 AM</td> <td style="width:50px; text-align:left;">Item001</td> <td style="width:50px; text-align:left;">10</td> <td style="width:50px; text-align:left;">Address1</td> <td style="width:50px; text-align:left;">46545465</td> <td style="width:50px; text-align:left;">ref1</td> </tr> </table> </div> Now, if i have the id of the div, how can i get the time and address for this div using JavaScript? Thanks & Regards, Khushi

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• QUiLoader and ignored dynamic properties

  - by Googie

  I'm loading the .ui file, where one of the widgets (QComboBox) has a dynamic property (http://qt-project.org/doc/qt-5/properties.html#dynamic-properties). The UI file looks like this: <?xml version="1.0" encoding="UTF-8"?> <ui version="4.0"> <class>PopulateScriptConfig</class> <widget class="QWidget" name="PopulateScriptConfig"> <property name="geometry"> <rect> <x>0</x> <y>0</y> <width>400</width> <height>300</height> </rect> </property> <property name="windowTitle"> <string>Form</string> </property> <layout class="QVBoxLayout" name="verticalLayout"> <item> <widget class="QGroupBox" name="langGroup"> <property name="title"> <string>Language</string> </property> <layout class="QVBoxLayout" name="verticalLayout_3"> <item> <widget class="QComboBox" name="langCombo"> <property name="ScriptingLangCombo" stdset="0"> <bool>true</bool> </property> </widget> </item> </layout> </widget> </item> <item> <widget class="QGroupBox" name="codeGroup"> <property name="title"> <string>Implementation</string> </property> <layout class="QVBoxLayout" name="verticalLayout_2"> <item> <widget class="QPlainTextEdit" name="codeEdit"/> </item> </layout> </widget> </item> </layout> </widget> <resources/> <connections/> </ui> The important part is: <widget class="QComboBox" name="langCombo"> <property name="ScriptingLangCombo" stdset="0"> <bool>true</bool> </property> </widget> I'm loading the file with QUiLoader::load(). Note, that I have extended the QUiLoader class, but only to access createWidget() method, where I can query each widget like this: QWidget* UiLoader::createWidget(const QString& className, QWidget* parent, const QString& name) { QWidget* w = QUiLoader::createWidget(className, parent, name); qDebug() << w->dynamicPropertyNames(); return w; } As a result I see empty list displayed, so it seems like the dynamic property is completly ignored. Any ideas? P.S. I've made sure that I load correct file. 3 times.

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• The HTG Guide to Using a Bluetooth Keyboard with Your Android Device

  - by Matt Klein

  Android devices aren’t usually associated with physical keyboards. But, since Google is now bundling their QuickOffice app with the newly-released Kit-Kat, it appears inevitable that at least some Android tablets (particularly 10-inch models) will take on more productivity roles. In recent years, physical keyboards have been rendered obsolete by swipe style input methods such as Swype and Google Keyboard. Physical keyboards tend to make phones thick and plump, and that won’t fly today when thin (and even flexible and curved) is in vogue. So, you’ll be hard-pressed to find smartphone manufacturers launching new models with physical keyboards, thus rendering sliders to a past chapter in mobile phone evolution. It makes sense to ditch the clunky keyboard phone in favor of a lighter, thinner model. You’re going to carry around in your pocket or purse all day, why have that extra bulk and weight? That said, there is sound logic behind pairing tablets with keyboards. Microsoft continues to plod forward with its Surface models, and while critics continue to lavish praise on the iPad, its functionality is obviously enhanced and extended when you add a physical keyboard. Apple even has an entire page devoted specifically to iPad-compatible keyboards. But an Android tablet and a keyboard? Does such a thing even exist? They do actually. There are docking keyboards and keyboard/case combinations, there’s the Asus Transformer family, Logitech markets a Windows 8 keyboard that speaks “Android”, and these are just to name a few. So we know that keyboard products that are designed to work with Android exist, but what about an everyday Bluetooth keyboard you might use with Windows or OS X? How-To Geek wanted look at how viable it is to use such a keyboard with Android. We conducted some research and examined some lists of Android keyboard shortcuts. Most of what we found was long outdated. Many of the shortcuts don’t even apply anymore, while others just didn’t work. Regardless, after a little experimentation and a dash of customization, it turns out using a keyboard with Android is kind of fun, and who knows, maybe it will catch on. Setting things up Setting up a Bluetooth keyboard with Android is very easy. First, you’ll need a Bluetooth keyboard and of course an Android device, preferably running version 4.1 (Jelly Bean) or higher. For our test, we paired a second-generation Google Nexus 7 running Android 4.3 with a Samsung Series 7 keyboard. In Android, enable Bluetooth if it isn’t already on. We’d like to note that if you don’t normally use Bluetooth accessories and peripherals with your Android device (or any device really), it’s best practice to leave Bluetooth off because, like GPS, it drains the device’s battery more quickly. To enable Bluetooth, simply go to “Settings” -> “Bluetooth” and tap the slider button to “On”. To set up the keyboard, make sure it is on and then tap “Bluetooth” in the Android settings. On the resulting screen, your Android device should automatically search for and hopefully find your keyboard. If you don’t get it right the first time, simply turn the keyboard on again and then tap “Search for Devices” to try again. If it still doesn’t work, make sure you have fresh batteries and the keyboard isn’t paired to another device. If it is, you will need to unpair it before it will work with your Android device (consult your keyboard manufacturer’s documentation or Google if you don’t know how to do this). When Android finds your keyboard, select it under “Available Devices” … … and you should be prompted to type in a code: If successful, you will see that device is now “Connected” and you’re ready to go. If you want to test things out, try pressing the “Windows” key (“Apple” or “Command”) + ESC, and you will be whisked to your Home screen. So, what can you do? Traditional Mac and Windows users know there’s usually a keyboard shortcut for just about everything (and if there isn’t, there’s all kinds of ways to remap keys to do a variety of commands, tasks, and functions). So where does Android fall in terms of baked-in keyboard commands? There answer to that is kind of enough, but not too much. There are definitely established combos you can use to get around, but they aren’t clear and there doesn’t appear to be any one authority on what they are. Still, there is enough keyboard functionality in Android to make it a viable option, if only for those times when you need to get something done (long e-mail or important document) and an on-screen keyboard simply won’t do. It’s important to remember that Android is, and likely always will be a touch-first interface. That said, it does make some concessions to physical keyboards. In other words, you can get around Android fairly well without having to lift your hands off the keys, but you will still have to tap the screen regularly, unless you add a mouse. For example, you can wake your device by tapping a key rather than pressing its power button. However, if your device is slide or pattern-locked, then you’ll have to use the touchscreen to unlock it – a password or PIN however, works seamlessly with a keyboard – other things like widgets and app controls and features, have to be tapped. You get the idea. Keyboard shortcuts and navigation As we said, baked-in keyboard shortcut combos aren’t necessarily abundant nor apparent. The one thing you can always do is search. Any time you want to Google something, start typing from the Home screen and the search screen will automatically open and begin displaying results. Other than that, here is what we were able to figure out: ESC = go back CTRL + ESC = menu CTRL + ALT + DEL = restart (no questions asked) ALT + SPACE = search page (say “OK Google” to voice search) ALT + TAB (ALT + SHIFT + TAB) = switch tasks Also, if you have designated volume function keys, those will probably work too. There’s also some dedicated app shortcuts like calculator, Gmail, and a few others: CMD + A = calculator CMD + C = contacts CMD + E = e-mail CMD + G = Gmail CMD + L = Calendar CMD + P = Play Music CMD + Y = YouTube Overall, it’s not a long comprehensive list and there’s no dedicated keyboard combos for the full array of Google’s products. Granted, it’s hard to imagine getting a lot of mileage out of a keyboard with Maps but with something like Keep, you could type out long, detailed lists on your tablet, and then view them on your smartphone when you go out shopping. You can also use the arrow keys to navigate your Home screen over shortcuts and open the app drawer. When something on the screen is selected, it will be highlighted in blue. Press “Enter” to open your selection. Additionally, if an app has its own set of shortcuts, e.g. Gmail has quite a few unique shortcuts to it, as does Chrome, some – though not many – will work in Android (not for YouTube though). Also, many “universal” shortcuts such as Copy (CTRL + C), Cut (CTRL + X), Paste (CTRL + V), and Select All (CTRL + A) work where needed – such as in instant messaging, e-mail, social media apps, etc. Creating custom application shortcuts What about custom shortcuts? When we were researching this article, we were under the impression that it was possible to assign keyboard combinations to specific apps, such as you could do on older Android versions such as Gingerbread. This no long seems to be the case and nowhere in “Settings” could we find a way to assign hotkey combos to any of our favorite, oft-used apps or functions. If you do want custom keyboard shortcuts, what can you do? Luckily, there’s an app on Google Play that allows you to, among other things, create custom app shortcuts. It is called External Keyboard Helper (EKH) and while there is a free demo version, the pay version is only a few bucks. We decided to give EKH a whirl and through a little experimentation and finally reading the developer’s how-to, we found we could map custom keyboard combos to just about anything. To do this, first open the application and you’ll see the main app screen. Don’t worry about choosing a custom layout or anything like that, you want to go straight to the “Advanced settings”: In the “Advanced settings” select “Application shortcuts” to continue: You can have up to 16 custom application shortcuts. We are going to create a custom shortcut to the Facebook app. We choose “A0”, and from the resulting list, Facebook. You can do this for any number of apps, services, and settings. As you can now see, the Facebook app has now been linked to application-zero (A0): Go back to the “Advanced settings” and choose “Customize keyboard mappings”: You will be prompted to create a custom keyboard layout so we choose “Custom 1”: When you choose to create a custom layout, you can do a great many more things with your keyboard. For example, many keyboards have predefined function (Fn) keys, which you can map to your tablet’s brightness controls, toggle WiFi on/off, and much more. A word of advice, the application automatically remaps certain keys when you create a custom layout. This might mess up some existing keyboard combos. If you simply want to add some functionality to your keyboard, you can go ahead and delete EKH’s default changes and start your custom layout from scratch. To create a new combo, select “Add new key mapping”: For our new shortcut, we are going to assign the Facebook app to open when we key in “ALT + F”. To do this, we press the “F” key while in the “Scancode” field and we see it returns a value of “33”. If we wanted to use a different key, we can press “Change” and scan another key’s numerical value. We now want to assign the “ALT” key to application “A0”, previously designated as the Facebook app. In the “AltGr” field, we enter “A0” and then “Save” our custom combo. And now we see our new application shortcut. Now, as long as we’re using our custom layout, every time we press “ALT + F”, the Facebook app will launch: External Keyboard Helper extends far beyond simple application shortcuts and if you are looking for deeper keyboard customization options, you should definitely check it out. Among other things, EKH also supports dozens of languages, allows you to quickly switch between layouts using a key or combo, add up to 16 custom text shortcuts, and much more! It can be had on Google Play for $2.53 for the full version, but you can try the demo version for free. More extensive documentation on how to use the app is also available. Android? Keyboard? Sure, why not? Unlike traditional desktop operating systems, you don’t need a physical keyboard and mouse to use a mobile operating system. You can buy an iPad or Nexus 10 or Galaxy Note, and never need another accessory or peripheral – they work as intended right out of the box. It’s even possible you can write the next great American novel on one these devices, though that might require a lot of practice and patience. That said, using a keyboard with Android is kind of fun. It’s not revelatory but it does elevate the experience. You don’t even need to add customizations (though they are nice) because there are enough existing keyboard shortcuts in Android to make it usable. Plus, when it comes to inputting text such as in an editor or terminal application, we fully advocate big, physical keyboards. Bottom line, if you’re looking for a way to enhance your Android tablet, give a keyboard a chance. Do you use your Android device for productivity? Is a physical keyboard an important part of your setup? Do you have any shortcuts that we missed? Sound off in the comments and let us know what you think.     

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• What is the proper way to Windows 7/Ubuntu 10.10 Dual-Triple Boot Partitioning for Laptop OEM?

  - by Denja

  Hi Linux Community, I find my self struggling with the slowness of windows OS once again. It's Time to change with the Ubuntu 10.10 64bit for I like to use a faster Operating System. My Hard Disk laptop has a RECOVERY and HP_TOOLS partition they are both Primary. I Have the System Recovery DVD for Windows 64bit should anything bad happen. Here's the layout I used with windows before: * (C:) Windows 7 system partition NTFS - 284,89GB (Primary,ad Boot,Pagefile,Dump) * HP_TOOLS system partition FAT32 - 99MB (Primary) * (D:) RECOVERY partition NTFS - 12,90GB (Primary) * SYSTEM partition NTFS 199MB (Primary) Here's the layout I wanted to make: * (C:) Windows 7 system partition NTFS - 60GB (Primary) (sda1) * (D:) Windows DATA partition (user files) NTFS - 120GB(Primary)(sda2);wanna share with Linux * Linux root Ext4 - 10GB (Extended)(sda3) (Ubuntu 10.10 64bit) * Linux home Ext3 - 90GB (Extended)(sda4) (Ubuntu 10.10 64bit) * Linux swap swap- RAM size, 3GB (sda5) * Linux root Ext3- 18GB (Extended) (sda6) (OpenSuse or Puppy or kubuntu) Here is my New Ubuntu 10.10 64bit layout in use now: * SYSTEM partition NTFS 199MB (Primary) (sda1) * (C:) Windows 7 system partition NTFS - 90GB (Primary) (sda2) * (D:) Windows 7 RECOVERY partition NTFS - 12,90GB (Primary) (sda3) * Linux system partition EXTENDED - 195,1GB (Logical) * Linux root Ext4- 10GB (Extended) (sda4) * Linux swap swap- RAMx2 size, 6,1GB (sda5) * Linux home Ext3- 179GB (Extended) (sda6) When I installed Ubuntu,I didn't know if I could wipe all previous partitions,because of the RECOVERY partition. So I just made the space for my extended partition with GParted by deleting the HP_TOOLS (Fat32). By doing this I managed somehow to install Ubuntu 64 with Success. And I also made the partitions for the swap or a third Linux OS as Jordan suggested. But I couldn't actually make the partitions for the shared NTFS.(no option!) Question 1: What is the proper way to Windows 7/Ubuntu 10.10 Dual-Triple Boot Partitioning for Laptop OEM?? Thank you in advance for your advises and suggestions and Happy New Year to All!!

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• How to Omit the Page Number From the First Page of a Word 2013 Document Without Using Sections

  - by Lori Kaufman

  Normally, the first page, or cover page, of a document does not have a page number or other header or footer text. You can avoid putting a page number on the first page using sections, but there is an easier way to do this. If you don’t plan to use sections in any other part of your document, you may want to avoid using them completely. We will show you how to easily take the page number off the cover page and start the page numbering at one on the second page of your document by simply using a footer (or a header) and changing one setting. Click the Page Layout tab. In the Page Setup section of the Page Layout tab, click the Page Setup dialog box launcher icon in the lower, right corner of the section. On the Page Setup dialog box, click the Layout tab and select the Different first page check box in the Headers and footers section so there is a check mark in the box. Click OK. You’ll notice there is no page number on the first page of your document now. However, you might want the second page to be page one of your document, only to find it is currently page two. To change the page number on the second page to one, click the Insert tab. In the Header & Footer section of the Insert tab, click Page Number and select Format Page Numbers from the drop-down menu. On the Page Number Format dialog box, select Start at in the Page numbering section. Enter 0 in the edit box and click OK. This allows the second page of your document to be labeled as page one. You can use the drop-down menu on the Format Page Numbers button in the Header & Footer section of the Insert tab to add page numbers to your document as well. Easily insert formatted page numbers at the top or bottom of the page or in the page margins. Use the same menu to remove page numbers from your document.     

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• GLSL Normals not transforming propertly

  - by instancedName

  I've been stuck on this problem for two days. I've read many articles about transforming normals, but I'm just totaly stuck. I understand choping off W component for "turning off" translation, and doing inverse/traspose transformation for non-uniform scaling problem, but my bug seems to be from a different source. So, I've imported a simple ball into OpenGL. Only transformation that I'm applying is rotation over time. But when my ball rotates, the illuminated part of the ball moves around just as it would if direction light direction was changing. I just can't figure out what is the problem. Can anyone help me with this? Here's the GLSL code: Vertex Shader: #version 440 core uniform mat4 World, View, Projection; layout(location = 0) in vec3 VertexPosition; layout(location = 1) in vec3 VertexColor; layout(location = 2) in vec3 VertexNormal; out vec4 Color; out vec3 Normal; void main() { Color = vec4(VertexColor, 1.0); vec4 n = World * vec4(VertexNormal, 0.0f); Normal = n.xyz; gl_Position = Projection * View * World * vec4(VertexPosition, 1.0); } Fragment Shader: #version 440 core uniform vec3 LightDirection = vec3(0.0, 0.0, -1.0); uniform vec3 LightColor = vec3(1f); in vec4 Color; in vec3 Normal; out vec4 FragColor; void main() { diffuse = max(0.0, dot(normalize(-LightDirection), normalize(Normal))); vec4 scatteredLight = vec4(LightColor * diffuse, 1.0f); FragColor = min(Color * scatteredLight, vec4(1.0)); }

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• Algorithm for procedural city generation?

  - by Zove Games

  I am planning on making a (simple) procedural city generator using Java. I need ideas on whan algorithm to use for the layout, and the actual buildings. The city will mostly have skyscrapers, not really much complex stuff. For the layout I already have a simple algorithm implemented: Create a Map with java.awt.Point keys and Integer values. Fill it with all the points in the city's bounds with the value as -1 (unnassigned) Shuffle the map, and assign the 1st 10 of the keys IDs (from 1-10) Loop until all points have IDs: Loop though all points: Assign points next to an assigned point IDs of the point next to them, if 2 or more points border the point, then randomly choose which ID the point will get. You will end up with 10 random regions. Make roads bordering these regions. Fill the inside of each region with a randomly spaced and randomly rotated grid PROBLEM: This is not the fastest way to do it. What algorithm should I use for the layout. And what should I use to make each building's design? I don't even know how I'm going to do that yet (fractals maybe). I just need some ideas, not actual code.

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• Correct Display configuration. Errors while trying to arrange displays

  - by David Russell Parrish Bojrquez

  I am trying to set up my tv with my laptop trough a VGA cable. The display application in Ubuntu throws a lot of errors to me and I have given up in trying to do it myself. I try to apply the 1920 1080 display. The selected configuration for displays could not be applied Requested size (3200, 1080) exceeds 3D hardware limit (2048, 2048). You must either rearrange the displays so that they fit within a (2048, 2048) square or select the Ubuntu 2D session at login. And Also this: Failed to apply configuration: %s GDBus.Error:org.gtk.GDBus.UnmappedGError.Quark._gnome_2drr_2derror_2dquark.Code3: Requested size (3200, 1080) exceeds 3D hardware limit (2048, 2048). You must either rearrange the displays so that they fit within a (2048, 2048) square or select the Ubuntu 2D session at login. Please Help. @Leozitop No I don't see anything when connected to 1920 1080 because the setup fails before actually applying. Yes there are other resolutions which do work. I believe the problem has something to do with the rotation it is set up. My Ubuntu Display application has only clockwise and counterclockwise options for the TV display. I really don't know why this is happening. Basic procedure: Plug in cable, did not get the resolution I wanted. Changed settings, applied them. Re-peat until desired display is shown. I'm not a computer illiterate, really it baffles me that this is happening. Output of xrandr: david@LapUbuntu:~$ xrandr Screen 0: minimum 320 x 200, current 1880 x 800, maximum 4096 x 4096 LVDS1 connected 1280x800+0+0 (normal left inverted right x axis y axis) 331mm x 207mm 1280x800 60.0*+ 1024x768 60.0 800x600 60.3 56.2 640x480 59.9 VGA1 connected 600x800+1280+0 left (normal left inverted right x axis y axis) 1600mm x 900mm 1920x1080 60.0 + 1280x1024 60.0 1360x768 60.0 1280x720 60.0 1024x768 60.0 800x600 60.3* 640x480 60.0 TV1 unknown connection (normal left inverted right x axis y axis) 848x480 59.9 + 640x480 59.9 + 1024x768 59.9 800x600 59.9 Note that VGA says left and indeed it is, but no other option was available in the display. Also, note the TV1 unknown connection which I have no idea what it is. Note, also, that this has nothing to do with the display since W7 on the computer works fine and since while boot up, and also, before starting session in ubuntu the rotation is normal. I'll also mention that I HAVE re-installed Ubuntu since I had posted this question from a Live CD of 12.04 LTS. And that before the posting of the question also using 12.04 before another backup that I had to do, the VGA setup was fine without any problems.

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• Vote of Disconfidence to Entity Framework

  - by Ricardo Peres

  A friend of mine has found the following problem with Entity Framework 4: Two simple classes and one association between them (one to many): One condition to filter out soft-deleted entities (WHERE Deleted = 0): 100 records in the database; A simple query: 1: var l = ctx.Person.Include("Address").Where(x => (x.Address.Name == "317 Oak Blvd." && x.Address.Number == 926) || (x.Address.Name == "891 White Milton Drive" && x.Address.Number == 497)); Will produce the following SQL: 1: SELECT 2: [Extent1].[Id] AS [Id], 3: [Extent1].[FullName] AS [FullName], 4: [Extent1].[AddressId] AS [AddressId], 5: [Extent202].[Id] AS [Id1], 6: [Extent202].[Name] AS [Name], 7: [Extent202].[Number] AS [Number] 8: FROM [dbo].[Person] AS [Extent1] 9: LEFT OUTER JOIN [dbo].[Address] AS [Extent2] ON ([Extent2].[Deleted] = 0) AND ([Extent1].[AddressId] = [Extent2].[Id]) 10: LEFT OUTER JOIN [dbo].[Address] AS [Extent3] ON ([Extent3].[Deleted] = 0) AND ([Extent1].[AddressId] = [Extent3].[Id]) 11: LEFT OUTER JOIN [dbo].[Address] AS [Extent4] ON ([Extent4].[Deleted] = 0) AND ([Extent1].[AddressId] = [Extent4].[Id]) 12: LEFT OUTER JOIN [dbo].[Address] AS [Extent5] ON ([Extent5].[Deleted] = 0) AND ([Extent1].[AddressId] = [Extent5].[Id]) 13: LEFT OUTER JOIN [dbo].[Address] AS [Extent6] ON ([Extent6].[Deleted] = 0) AND ([Extent1].[AddressId] = [Extent6].[Id]) 14: ... 15: WHERE ((N'317 Oak Blvd.' = [Extent2].[Name]) AND (926 = [Extent3].[Number])) 16: ... And will result in 680 MB of memory being taken! Now, Entity Framework has been historically known for producing less than optimal SQL, but 680 MB for 100 entities?! According to Microsoft, the problem will be addressed in the following version, there is a Connect issue open. There is even a whitepaper, Performance Considerations for Entity Framework 5, which talks about some of the changes and optimizations coming on version 5, but by reading it, I got even more concerned: “Once the cache contains a set number of entries (800), we start a timer that periodically (once-per-minute) sweeps the cache.” Say what?! The next version of Entity Framework will spawn timer threads?! When Code First came along, I thought it was a step in the right direction. Sure, it didn’t include some things that NHibernate did for quite some time – for example, different strategies for Id generation that do not rely on IDENTITY columns, which makes INSERT batching impossible, or support for enumerated types – but I thought these would come with the time. Now, enumerated types have, but so did… timer threads! I’m afraid Entity Framework is becoming a monster.

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• What is this JavaScript gibberish?

  - by W3Geek

  I am studying how to make a 2D game with JavaScript by reading open source JavaScript games and I came across this gibberish... aSpriteData = [ "}\"¹-º\"À+º\"À+º\"À+º\"¿¤À ~C_ +º\"À+º\"À+º\"À*P7²OK%¾+½u_\"À<¡a¡a¡bM@±@ª", // 0 ground "a ' ![± 7°³b£[mt<Nµ7z]~¨OR»[f_7l},tl},+}%XN²Sb[bl£[±%Y_¹ !@ $", // 1 qbox "!A % @,[] ±}°@;µn¦&X£ <$ §¤ 8}}@Prc'U#Z'H'@· ¶\"is ¤&08@£(", // 2 mario " ´!A.@H#q8¸»e-½n®@±oW:&X¢a<&bbX~# }LWP41}k¬#3¨q#1f RQ@@:4@$", // 3 mario jump " 40 q$!hWa-½n¦#_Y}a©,0#aaPw@=cmY<mq©GBagaq&@q#0§0t0¤ $", // 4 mario run "+hP_@", // 5 pipe left "¢,6< R¤", // 6 pipe right "@ & ,'+hP?>³®'©}[!»¹.¢_^¥y/pX¸#µ°=a¾½hP?>³®'©}[!»¹.¢_^ Ba a", // 7 pipe top left "@ , !] \"º £] , 8O #7a&+¢ §²!cº 9] P &O ,4 e", // 8 pipe top right " £ #! ,! P!!vawd/XO¤8¼'¤P½»¹²'9¨ \"P²Pa²(!¢5!N*(4´b!Gk(a", // 9 goomba " Xu X5 =ou!¯­¬a[Z¼q.°u#|xv ¸··@=~^H'WOJ!¯­¬a=Nu ²J <J a", // 10 coin // yui "@ & !MX ~L \"y %P *¢ 5a K w !L \"y %P *­a%¬¢ 4 a", // 11 ebox // yui "¢ ,\"²+aN!@ &7 }\"²+aN!XH # }\"²+aN!X% 8}\"²+aN!X%£@ (", // 12 bricks "} %¿¢!N° I¨²*<P%.8\"h,!Cg r¥ H³a4X¢*<P%.H#I¬ :a!u !q", // 13 block makeSpace(20) + "4a }@ }0 N( w$ }\" N! +aa", // 14 bush left " r \"²y!L%aN zPN NyN#²L}[/cy¾ N" + makeSpace(18) + "@", // 15 bush mid makeSpace(18) + "++ !R·a!x6 &+6 87L ¢6 P+ 8+ (", // 16 bush right " %©¦ +pq 7> \"³ s" + makeSpace(25) + "@", // 17 cloud bottom left "a/a_#².Q¥'¥b}8.£¨7!X\"K+5cqs%(" + makeSpace(18) + "0", // 18 cloud bottom mid "bP ¢L P+ 8%a,*a%§@ J" + makeSpace(22) + "(", // 19 cloud bottom right "", // 20 mushroom "", // koopa 16x24 "", // 22 star "", // 23 flagpole "", // 24 flag "", // 25 flagpole top " 6 ~ }a }@ }0 }( }$ }\" }! } a} @} 0} (} $} \"² $", // 26 hill slope "a } \"m %8 *P!MF 5la\"y %P" + makeSpace(18) + "(", // 27 hill mid makeSpace(30) + "%\" t!DK \"q", // 28 hill top "", // 29 castle bricks "", // 30 castle doorway bottom "", // 31 castle doorway top "", // 32 castle top "", // 33 castle top 2 "", // 34 castle window right "", // 35 castle window left "", // 36 castle flag makeSpace(19) + "8@# (9F*RSf.8 A¢$!¢040HD", // 37 goomba flat " *(!¬#q³¡[_´Yp~¡=<¥g=&'PaS²¿ Sbq*<I#*£Ld%Ryd%¼½e8H8bf#0a", // 38 mario dead " = ³ #b 'N¶ Z½Z Z½Z Z½Z Z½Z Z½Z Z½Z =[q ²@ ³ ¶ 0", // 39 coin step 1 " ?@ /q /e '¤ #³ !ºa }@ N0 ?( /e '¤ #³ ¿ _a \"", // 40 coin step 2 " / > ] º !² #¢ %a + > ] º !² #¢ 'a \"", // 41 coin step 3 " 7¢ +² *] %> \"p !Ga t¢ I² 4º *] %> \"p ¡ Oa \"" // 42 coin step 4 ], What does it do? If you want to look at the source file here it is: http://www.nihilogic.dk/labs/mario/mario.js Beware, there is more gibberish inside. I can't seem to make sense of any of it. Thank you.

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• 2D collision resolving

  - by Philippe Paré

  I've just worked out an AABB collision algorithm for my 2D game and I was very satisfied until I found out it only works properly with movements of 1 in X and 1 in Y... here it is: public bool Intersects(Rectanglef rectangle) { return this.Left < rectangle.Right && this.Right > rectangle.Left && this.Top < rectangle.Bottom && this.Bottom > rectangle.Top; } public bool IntersectsAny(params Rectanglef[] rectangles) { for (int i = 0; i < rectangles.Length; i++) { if (this.Left < rectangles[i].Right && this.Right > rectangles[i].Left && this.Top < rectangles[i].Bottom && this.Bottom > rectangles[i].Top) return true; } return false; } and here is how I use it in the update function of my player : public void Update(GameTime gameTime) { Rectanglef nextPosX = new Rectanglef(AABB.X, AABB.Y, AABB.Width, AABB.Height); Rectanglef nextPosY; if (Input.Key(Key.Left)) nextPosX.X--; if (Input.Key(Key.Right)) nextPosX.X++; bool xFree = !nextPosX.IntersectsAny(Boxes.ToArray()); if (xFree) nextPosY = new Rectanglef(nextPosX.X, nextPosX.Y, nextPosX.Width, nextPosX.Height); else nextPosY = new Rectanglef(AABB.X, AABB.Y, AABB.Width, AABB.Height); if (Input.Key(Key.Up)) nextPosY.Y--; if (Input.Key(Key.Down)) nextPosY.Y++; bool yFree = !nextPosY.IntersectsAny(Boxes.ToArray()); if (yFree) AABB = nextPosY; else if (xFree) AABB = nextPosX; } What I'm having trouble with, is a system where I can give float values to my movement and make it so there's a smooth acceleration. Do I have to retrieve the collision rectangle (the rectangle created by the other two colliding)? or should I do some sort of vector and go along this axis until I reach the collision? Thanks a lot!

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• Search option: jqGrid + PHP

  - by Felix Guerrero

  Hi, I'm trying to get work this code: $("#list").jqGrid({ url: 'docente.php', datatype: 'json', mtype: 'POST', postData: {c : "", n: "", a: "", d: "", t: "", e: "", f: "", g: $('#selectD').value(), p: "", call: "report"}, colNames: ['C&eacute;dula','Nombres', 'Apellidos', 'Direcci&oacute;n', 'E-mail','Tel&eacute;fono', 'Profesi&oacute;n'], colModel: [ { name:'rows.cedula', index: 'cedula', search:true, jsonmap: 'cedula', width: 150, align: 'left', sortable:true}, { name:'rows.nombre', index: 'nombre', jsonmap: 'nombre', width: 150, align: 'left'}, { name:'rows.apellido', index: 'apellido', jsonmap: 'apellido', width: 240, align: 'left'}, { name:'rows.direccion', index: 'direccion', jsonmap: 'direccion', width: 330, align: 'left'}, { name:'rows.email', index: 'email', jsonmap: 'email',width: 200, align: 'left'}, { name:'rows.telefono', index: 'telefono', jsonmap: 'telefono', width: 170, align: 'left'}, { name:'rows.descripcion_profesion', index: 'descripcion_profesion', jsonmap: 'descripcion_profesion',width: 120, align: 'left'}], pager: '#pager', rowNum: 8, autowidth: true, rowList: [10, 20], sortname: 'cedula', sortorder: 'asc', viewrecords: true, caption: 'Docentes', jsonReader : { root: "rows", repeatitems: false }, height: 350, width: 900 }); $("#list").jqGrid('navGrid','#pager',{search:true, searchtext: "buscar",edit:false,add:false,del:false}); The HMTL I'm using: <div id="reporte"> <table id="list"></table> <div id="pager"> </div> <div> And the PHP code: $total_pages = 0; $limit=10; $count = Profesor::CountAll(); if($count> 0) $total_pages= ceil($count/$limit); else $total_pages=0; $cnx = new PDO("mysql:host=localhost;dbname=appsms","root",""); $rows = array(); $strQuery="select cedula, nombre, apellido, direccion, telefono, email, descripcion_profesion from Profesor join Profesion on " . " (profesor.profesion_id = profesion.id) and (profesor.grado_id_grado = '" .$this->grado . "') order by cedula;"; $stmt = $cnx->prepare($strQuery); $stmt->execute(array("reporte")); $rows = $stmt->fetchAll(PDO::FETCH_ASSOC); $response->page = 1; $response->total= $total_pages; $response->records = sizeof($rows); $i=0; foreach($rows as $result){ $response->rows[$i] = $result; $i++; } echo json_encode($response); The JSON I get: {"page":1,"total":1,"records":2, "rows":[{"cedula":"v-108984103","nombre":"Soneia","apellido":"Rond\u00f3n Contreras","direccion":"El Rosal, calle 2-44","telefono":"04544247008457","email":"[email protected]","descripcion_profesion":"Docente"}, {"cedula":"v-135254741","nombre":"Judith","apellido":"Rangel M\u00e1rquez","direccion":"Sabaneta","telefono":"04247644152499","email":"","descripcion_profesion":"Docente"}]} It loads the query from PHP but the search option doesn't work neither the sorting function on "cedula"'s column. What I need to do?. Thanks in advance.

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• Jquery flowplayer - tabs - content inside div tags not displaying

  - by Gublooo

  Hey guys, I'm looking for a simple example of JQuery tabs in which I am planning to show two different forms. I came across this example http://flowplayer.org/tools/demos/tabs/index.htm which is perfect for my needs. So I implemented the simple example. The code in question is: <div class="panes" <divFirst tab content. Tab contents are called "panes"</div <divSecond tab content</div <divThird tab content</div </div Now my content for the first tab is a form which has several of its own div tags - when I put that form with div tags as the content for the first tab - nothing appears. So I made a simple change and added another div tag to the content of the first tab as shown below and still nothing appears: <div class="panes" <div<divFirst tab content. Tab contents are called "panes"</div</div <divSecond tab content</div <divThird tab content</div </div Is there a simple way to fix this. This is the content that I want to display in my first tab - Thanks for your help <div id="formbox" class="formbox" <form id="shopping_form" method="post" <div id="3" style="width:520px;" <textarea id="message" name="message" rows="3" cols="50"</textarea </div <div id="store_row" style="width:220px;float:left;padding-bottom:10px;"<bStore</b <input type="text" id="store" name="store" class="required" size="20" / <input type="hidden" id="store_id"/ </div <div id="city_column" style="width:200px;float:left;padding-bottom:10px;"<bCity</b <input type="text" id="city" name="city" size="15"/ </div <div id="findbutton_column" style="vertical-align:top;width:80px;float:left;" <input class="find_address" id="findaddress" type="button" value="Find Store"/ </div <div id="googlerow" style="width:120px;float:left;padding-bottom:10px;" <bSelect Store</b<select id="google_stores" name="google_stores"</select <input type="hidden" id="google_address"/ </div <div id="google_message" style="float:left;padding-bottom:10px;display:none;"</div <div id="locationrow" style="float:left;padding-bottom:10px;display:none;" <bAddress/Country</b <input type="text" id="address" name="address" size="20" / <input type="text" id="country" name="country" size="20"/ </div <div style="width:520px;float:left;padding-bottom:10px;" <bPrice    <input type="text" id="price" name="price" size="20" / </div <div id="buttonrow" style="width:200px;float:right;display:none;" <input id="it" type="image" src="http://images.pe.com.s3.amazonaws.com/it.png" height="35px"/ </div </form </div

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• Binary Search Tree in C

  - by heapzero

  Hi, I'm a Python guy. Learning C language and I've been trying to implement Binary Search Tree in C. I wrote down the code, and I've been trying from few hours but, not able to get the output as expected. Please help! Please correct me. #include<stdlib.h> #include<stdio.h> typedef int ElementType; typedef struct TreeNode { ElementType element; struct TreeNode *left, *right; } TreeNode; TreeNode *createTree(){ //Create the root of tree TreeNode *tempNode; tempNode = malloc(sizeof(TreeNode)); tempNode->element = 0; tempNode->left = NULL; tempNode->right = NULL; return tempNode; } TreeNode *createNode(ElementType X){ //Create a new leaf node and return the pointer TreeNode *tempNode; tempNode = malloc(sizeof(TreeNode)); tempNode->element = X; tempNode->left = NULL; tempNode->right = NULL; return tempNode; } TreeNode *insertElement(TreeNode *node, ElementType X){ //insert element to Tree if(node==NULL){ return createNode(X); } else{ if(X < node->element){ node->left = insertElement(node->left, X); } else if(X > node->element){ node->right = insertElement(node->right, X); } else if(X == node->element){ printf("Oops! the element is already present in the tree."); } } } TreeNode *displayTree(TreeNode *node){ //display the full tree if(node==NULL){ return; } displayTree(node->left); printf("| %d ", node->element); displayTree(node->right); } main(){ //pointer to root of tree #2 TreeNode *TreePtr; TreeNode *TreeRoot; TreeNode *TreeChild; //Create the root of tree TreePtr = createTree(); TreeRoot = TreePtr; TreeRoot->element = 32; printf("%d\n",TreeRoot->element); insertElement(TreeRoot, 8); TreeChild = TreeRoot->left; printf("%d\n",TreeChild->element); insertElement(TreeRoot, 2); insertElement(TreeRoot, 7); insertElement(TreeRoot, 42); insertElement(TreeRoot, 28); insertElement(TreeRoot, 1); insertElement(TreeRoot, 4); insertElement(TreeRoot, 5); // the output is not as expected :( displayTree(TreeRoot); }

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• Lightbox image / link URL

  - by GSTAR

  Basically I have a slightly non-standard implementation of FancyBox. By default you have to include a link to the large version of the image so that the Lightbox can display it. However, in my implementation, the image link URLs point to a script rather than directly to the image file. So for example, instead of: <a href="mysite/images/myimage.jpg" rel="gallery"> I have: <a href="mysite/photos/view/abc123" rel="gallery"> The above URL points to a function: public function actionPhotos($view) { $photo=Photo::model()->find('name=:name', array(':name'=>$view)); if(!empty($photo)) { $this->renderPartial('_photo', array('photo'=>$photo, true)); } } The "$this-renderPartial()" bit simply calls a layout file which includes a standard HTML tag to output. Now when the user clicks on a thumbnail, the above function is called and the large image is displayed in the Lightbox. Now if the user right clicks on the thumbnail and selects "open in new tab/window" then the image is displayed in the browser as per normal, i.e. just the image. I want to change this so that it displays the image within a layout. In the above code I can include the following and put it in an IF statement: $this->render('photos', array('photo'=>$photo)); This will call the layout file "photos" which contains the layout to display the image in. I have a specific limitation for this - the image URL must remain the same, i.e. no additional GET variables in the URL. However if we can pass in a GET variable in the background then that is OK. I will most likely need to change my function above so that it calls a different file for this functionality. EDIT: To demonstrate exactly what I am trying to do, check out the following: http://www.starnow.co.uk/KimberleyMarren Go to the photos tab and hover over a thumbnail - note the URL. Click the thumbnail and it will open up in the Lightbox. Next right click on that same thumbnail and select "open in new tab/new window". You will notice that the image is now displayed in a layout. So that same URL is used for displaying the image in the Lightbox and on its own page. The way StarNow have done this is using some crazy long JavaScript functionality, which I'm not too keen on replicating.

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• .NET OCRing an Image

  - by Kirschstein

  I'm trying to use MODI to OCR a window's program. It works fine for screenshots I grab programmatically using win32 interop like this: public string SaveScreenShotToFile() { RECT rc; GetWindowRect(_hWnd, out rc); int width = rc.right - rc.left; int height = rc.bottom - rc.top; Bitmap bmp = new Bitmap(width, height); Graphics gfxBmp = Graphics.FromImage(bmp); IntPtr hdcBitmap = gfxBmp.GetHdc(); PrintWindow(_hWnd, hdcBitmap, 0); gfxBmp.ReleaseHdc(hdcBitmap); gfxBmp.Dispose(); string fileName = @"c:\temp\screenshots\" + Guid.NewGuid().ToString() + ".bmp"; bmp.Save(fileName); return fileName; } This image is then saved to a file and ran through MODI like this: private string GetTextFromImage(string fileName) { MODI.Document doc = new MODI.DocumentClass(); doc.Create(fileName); doc.OCR(MODI.MiLANGUAGES.miLANG_ENGLISH, true, true); MODI.Image img = (MODI.Image)doc.Images[0]; MODI.Layout layout = img.Layout; StringBuilder sb = new StringBuilder(); for (int i = 0; i < layout.Words.Count; i++) { MODI.Word word = (MODI.Word)layout.Words[i]; sb.Append(word.Text); sb.Append(" "); } if (sb.Length > 1) sb.Length--; return sb.ToString(); } This part works fine, however, I don't want to OCR the entire screenshot, just portions of it. I try cropping the image programmatically like this: private string SaveToCroppedImage(Bitmap original) { Bitmap result = original.Clone(new Rectangle(0, 0, 250, 250), original.PixelFormat); var fileName = "c:\\" + Guid.NewGuid().ToString() + ".bmp"; result.Save(fileName, original.RawFormat); return fileName; } and then OCRing this smaller image, however MODI throws an exception; 'OCR running error', the error code is -959967087. Why can MODI handle the original bitmap but not the smaller version taken from it?

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• z-index of DIV positioned on top of another div

  - by Elie

  I have two div containers which are structured as follows: <div class="outer-div"> <img src="images/point.png" class="img-a1"> <img src="images/point.png" class="img-a2"> Lots of text goes here. </div> <div class="outer-div"> <img src="images/point.png" class="img-a1"> <img src="images/point.png" class="img-b2"> Some more text goes here </div> The styles associated with this are as follows: .outer-div { position: absolute; top: 0px; left: 0px; width: 500px; } .img-a1 { float:left; z-index:-1; position:relative; margin-left: 250px; margin-bottom: 100px; } .img-b1 { float:right; z-index:-1; position:relative; margin-left: 250px; margin-bottom: 100px; } img-a2 { float:left; z-index:-1; position:relative; margin-left: 400px; margin-bottom: 200px; } img-b2 { float:right; z-index:-1; position:relative; margin-left: 400px; margin-bottom: 200px; } The result of this is to produce something like the following, where ... is the text from div-a and ||| is the text from div-b: .....||||| .....||||| .. || .. || However, since the second div is placed immediately above the first div, none of the text in the second div can be selected, although it can be seen since there is just empty space, and a 1x1 px image above it. Is there a way to get the text from the lower div to be selectable, without making the upper div unselectable?

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• Redundant margins when adding ImageView to ScrollView in Android.

  - by Shmuel Meymann

  Hi.. I have been trying to use a ScrollView on a single ImageView with a JPG (~770 x 1024) over an AVD that's 600x800. My main.xml is: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" > <ScrollView android:id="@+id/scroller" android:layout_width="fill_parent" android:layout_height="wrap_content" /> </LinearLayout> Now, I add a single ImageView with setContentView(R.layout.main); ScrollView sv = (ScrollView)findViewById( R.id.scroller ); ImageView iv = new ImageView(this); iv.setImageDrawable( new BitmapDrawable( "/sdcard/770x1024.jpg" ) ); // same happens with ScaleDrawable. iv.setScaleType( ScaleType.CENTER_INSIDE ); sv.addView( sv ); // and it does not go any better if I use Linear Layout between the ScrollView and the ImageView. The result is The image was displayed in a middle of a ScrollView, wrapped with background area on top and bottom as following: ##### ##### image . . . ##### ##### Where ##### stands for background area I tried to set the background of the ImageView red, and it verified that the blank margins were ImageView background. iv.setBackgroundColor( color.Red ); Where I would expect the image to take no more than its size (scaled to the AVD size) and I expect the ScrollView to let me scroll over the remainder (if any). For some reason, I see that the drawable size is 600x1024. Moreover I tried to add a LinearLayout with a dummy text view such as the linear layout is a parent to the ImageView and the TextView, and the ScrollView is a parent to the LinearLayout. LinearLayout dummy = new LinearLayout( this ); dummy.addView(iv); TextView someTextView = new TextView( this ); someTextView.setLayoutParams(new LayoutParams( LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT )); dummy.addView( someTextView ); sv.addView( dummy ); The result was very peculiar: The entire layout was set into the width of a text-less text view (19). It is important for me to avoid stretching the image. What is the recommended way to implement a display of a page that can be potentially scrolled? Do I have to do it manually with a plain layout and scrolling upon OnMove events? Thanks Shmuel

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• My listview is not gaining the keyboard focus in Qt

  - by Solitaire

  Hi, i am trying to operate the listview itesm through keyboard focus, its not moving.. can you folks suggest where i am wrong. if i click on the listview from mouse, listview is gaining the focus. i dont no what is wrong. #include <QtGui> #include <QApplication> class Newlist : public QListView { public: Newlist(QWidget *parent = 0); ~Newlist(){}; public: QListView *list; QStringListModel *model; }; Newlist::Newlist(QWidget *parent) : QListView(parent) { list = new QListView(this); list->setViewMode(QListView::ListMode); list->setSelectionMode(QAbstractItemView::SingleSelection); list->setMinimumSize(300,500); model = new QStringListModel(this); QStringList strlist; strlist<<"Test"<<"fest"<<"mest"; list->setModel(model); model->setStringList(strlist); QModelIndex index = model->index(1,0); list->setCurrentIndex(index); QVBoxLayout *layout = new QVBoxLayout(this); layout->addWidget(list); setLayout(layout); list->setFocus(); } class Test : public QMainWindow { public: Test(QWidget *parent = 0); ~Test(){}; private: Mylistview *newlist; QVBoxLayout *layout; }; Test::Test(QWidget *parent) : QMainWindow(parent) { layout = new QVBoxLayout(); newlist = new Mylistview(); this->setCentralWidget(newlist); } int main(int argc, char *argv[]) { QApplication a(argc, argv); Test test; test.showMaximized(); return a.exec(); } Thanks in advance

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• [NSIS] Custom radio-buttom INI page via Eclipse

  - by Omegazero

  I'm using Eclipse's create InstallOptions menu to create a custom INI page with radio-buttons for repackaging the Blackberry Desktop installer. There are 2 sections for each type: "Internet" and "Enterprise". I need a user to select 1 of the 2 options and depending on their selection, the page will carry over the selection chosen in the custom page, jump to the INSTFILES page, and continue onto the end. I couldn't find any concrete documentation on getting INI pages to load in the script (I'm probably searching incorrectly), and then pass data from one page to the next (according to fields I guess?) Any help is appreciated. Even if it's to tell me I'm blind and can't read a doc (though a link would help :) ) Here's the INI code: ; Auto-generated by EclipseNSIS InstallOptions Script Wizard ; Jul 29, 2009 5:42:56 PM [Settings] NumFields=7 Title=RIM BlackBerry Desktop 5.0 installation CancelEnabled=1 [Field 1] Type=RadioButton Left=15 Top=28 Right=100 Bottom=38 Text=Internet State= Flags=NOTIFY [Field 4] Type=RadioButton Left=15 Top=95 Right=100 Bottom=105 Text=Enterprise Flags=NOTIFY [Field 2] Type=GroupBox Left=0 Top=10 Right=300 Bottom=75 Text= [Field 5] Type=Label Left=30 Top=42 Right=235 Bottom=52 Text=For users who are NOT on the Enterprise (Exchange) server [Field 6] Type=Label Left=30 Top=111 Right=235 Bottom=121 Text=Choose this only if you are on the Exchange server [Field 3] Type=GroupBox Left=0 Top=75 Right=300 Bottom=140 [Field 7] Type=Label Left=0 Top=0 Right=130 Bottom=10 Text=Please choose your installation method ...And here's the NSI code: Auto-generated by EclipseNSIS Script Wizard Jul 29, 2009 5:42:16 PM Name "BlackBerry Desktop" RequestExecutionLevel admin General Symbol Definitions !define VERSION 5.0.0.11 !define COMPANY RIM !define URL http://www.blackberry.com MUI Symbol Definitions !define MUI_ICON BBD.ico !define MUI_LICENSEPAGE_RADIOBUTTONS Included files !include Sections.nsh !include MUI2.nsh Reserved Files ReserveFile "${NSISDIR}\Plugins\AdvSplash.dll" Installer pages !insertmacro MUI_PAGE_WELCOME !insertmacro MUI_PAGE_LICENSE license.txt !insertmacro MUI_PAGE_COMPONENTS !insertmacro MUI_PAGE_INSTFILES !insertmacro MUI_PAGE_FINISH Installer languages !insertmacro MUI_LANGUAGE English Installer attributes OutFile RIM_BlackBerry_Desktop_5.0.exe InstallDir "$TEMP\RIM BlackBerry Desktop 5.0 Setup Files" CRCCheck on XPStyle on ShowInstDetails hide VIProductVersion 5.0.0.11 VIAddVersionKey /LANG=${LANG_ENGLISH} ProductName "BlackBerry Desktop" VIAddVersionKey /LANG=${LANG_ENGLISH} ProductVersion "${VERSION}" VIAddVersionKey /LANG=${LANG_ENGLISH} CompanyName "${COMPANY}" VIAddVersionKey /LANG=${LANG_ENGLISH} CompanyWebsite "${URL}" VIAddVersionKey /LANG=${LANG_ENGLISH} FileVersion "${VERSION}" VIAddVersionKey /LANG=${LANG_ENGLISH} FileDescription "" VIAddVersionKey /LANG=${LANG_ENGLISH} LegalCopyright "" Installer sections Section /o Main SEC0000 SetOutPath $INSTDIR SetOverwrite ifdiff ; TESTING PHASE SectionEnd SectionGroup /e "BlackBerry Desktop Section" Section /o Internet SEC0001 SetOutPath $INSTDIR\DRIVERS SetOverwrite ifdiff ; Execwait 'msiexec /i "$INSTDIR\BlackBerry USB and Modem Drivers_ENG (DM5.0b28).msi" /passive' SetOutPath $INSTDIR SetOverwrite ifdiff ; File /r * ; ExecWait '"$INSTDIR\Setup.exe" /S/v/qb!' SectionEnd Section /o Enterprise SEC0002 SetOutPath $INSTDIR\DRIVERS SetOverwrite ifdiff ; Execwait 'msiexec /i "$INSTDIR\BlackBerry USB and Modem Drivers_ENG (DM5.0b28).msi" /passive' SetOutPath $INSTDIR SetOverwrite ifdiff ; File /r * ; Delete /REBOOTOK "$INSTDIR\Setup.ini" ; Rename /REBOOTOK "$INSTDIR\Setup_Enterprise.ini" "$INSTDIR\Setup.ini" ; ExecWait '"$INSTDIR\Setup.exe" /S/v/qb!' SectionEnd SectionGroupEnd Section Descriptions !insertmacro MUI_FUNCTION_DESCRIPTION_BEGIN !insertmacro MUI_DESCRIPTION_TEXT ${SEC0000} $(SEC0000_DESC) !insertmacro MUI_DESCRIPTION_TEXT ${SEC0001} $(SEC0001_DESC) !insertmacro MUI_FUNCTION_DESCRIPTION_END Installer Language Strings TODO Update the Language Strings with the appropriate translations. LangString SEC0000_DESC ${LANG_ENGLISH} "Installation for non-Exchange/Enterprise BlackBerry Users" LangString SEC0001_DESC ${LANG_ENGLISH} "Installation for Exchange/Enterprise BlackBerry Users"

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• Java problem cant find image file

  - by user363035

  I am a student working on a homework project. I spent DAYS trying to get the following code to display an image on my new windows 7 laptop. I compiled it and ran it on my old xp pc and it worked! I really want to use my laptop. Any suggestions on how to get it to display the image? import java.awt.*; import java.applet.*; import java.awt.event.*; import java.awt.image.*; public class MoveIt extends Applet implements ActionListener { // set variables and componets private Image cup; Panel keypad = new Panel(); public int top = 15; public int left = 15; private Button keysArray[]; public void init() { cup = getImage(getDocumentBase(), "cup.gif"); Canvas myCanvas = new Canvas(); keysArray = new Button[5]; setLayout(new BorderLayout(5,5)); setBackground(Color.blue); // set up keypad layout keypad.setLayout(new BorderLayout(0,0)); keysArray[0] = new Button("Up"); keysArray[1] = new Button("Left"); keysArray[2] = new Button("Center"); keysArray[3] = new Button("Right"); keysArray[4] = new Button("Down"); // add buttons to the keypad panel keypad.add(keysArray[0], BorderLayout.NORTH); keysArray[0].addActionListener(this); keypad.add(keysArray[1], BorderLayout.EAST); keysArray[1].addActionListener(this); keypad.add(keysArray[2], BorderLayout.CENTER); keysArray[2].addActionListener(this); keypad.add(keysArray[3], BorderLayout.WEST); keysArray[3].addActionListener(this); keypad.add(keysArray[4], BorderLayout.SOUTH); keysArray[4].addActionListener(this); // add canvas and keypad to the BorderLayout add(myCanvas, BorderLayout.NORTH); add(keypad, BorderLayout.SOUTH); } public void paint(Graphics g) { g.drawImage( cup, left, top, this ); } public void actionPerformed(ActionEvent e) { // test for menu item clicks String arg = e.getActionCommand(); if (arg == "Up") top -=15; else if (arg == "Down") top +=15; else if (arg == "Left") left -=15; else if (arg == "Right") left +=15; else { top = 60; left =125; } repaint(); } }

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