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  • Unable to install gem "pg" on Ubuntu 12.10 (AMD64)

    - by Lynx_Eyes
    I've been (unsuccessfully) trying to install the "pg" gem on my ruby 1.9.3-p286 but nothing seems to work. I've already installed postgresql (9.1), libpq-dev and a few others like postgresql-server-dev-9.1. I've tried to pass the "with-pg-config" flag to the gem install but simply nothing seems to work. Every time I try to install the gem it outputs something like this: Building native extensions. This could take a while... ERROR: Error installing pg: ERROR: Failed to build gem native extension. /home/lynux/.rvm/rubies/ruby-1.9.3-p286/bin/ruby extconf.rb checking for pg_config... yes Using config values from /usr/bin/pg_config checking for libpq-fe.h... yes checking for libpq/libpq-fs.h... yes checking for pg_config_manual.h... yes checking for PQconnectdb() in -lpq... no checking for PQconnectdb() in -llibpq... no checking for PQconnectdb() in -lms/libpq... no Can't find the PostgreSQL client library (libpq) *** extconf.rb failed *** Could not create Makefile due to some reason, probably lack of necessary libraries and/or headers. Check the mkmf.log file for more details. You may need configuration options. Provided configuration options: --with-opt-dir --with-opt-include --without-opt-include=${opt-dir}/include --with-opt-lib --without-opt-lib=${opt-dir}/lib --with-make-prog --without-make-prog --srcdir=. --curdir --ruby=/home/lynux/.rvm/rubies/ruby-1.9.3-p286/bin/ruby --with-pg --without-pg --with-pg-dir --without-pg-dir --with-pg-include --without-pg-include=${pg-dir}/include --with-pg-lib --without-pg-lib=${pg-dir}/lib --with-pg-config --without-pg-config --with-pg_config --without-pg_config --with-pqlib --without-pqlib --with-libpqlib --without-libpqlib --with-ms/libpqlib --without-ms/libpqlib Gem files will remain installed in /home/lynux/.rvm/gems/ruby-1.9.3-p286@phisiodata/gems/pg-0.14.1 for inspection. Results logged to /home/lynux/.rvm/gems/ruby-1.9.3-p286@phisiodata/gems/pg-0.14.1/ext/gem_make.out What am I doing wrong? Is there something else that I should do before trying to install the gem? Thank you in advance. [EDIT] Ok, so joelparkerhenderson's answer set me to think that there might me something wrong with paths and libraries and a went on digging a little bit further.. I've found this awesome post and it solved! Basically the problem lies with RVM. So, my problem is solved and for anyone out there that might suffer from the same thing, follow the link!

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  • Power error handling inside of sql function

    - by user172062
    I have a power function call inside of a sql function. What is the correct way to handle overflow and underflow conditions since I cannot use a Try Catch inside of a function. I am also trying to avoid modifying the ARITHABORT, ANSI_WARNINGS, and ARITHIGNORE settings in the calling code. GO CREATE FUNCTION TestPow() RETURNS DECIMAL(30, 14) AS BEGIN DECLARE @result FLOAT SET @result = POWER(10.0, 300) RETURN @result END GO SELECT dbo.TestPow()

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  • What to name column in database table that holds versioning number

    - by rwmnau
    I'm trying to figure out what to call the column in my database table that holds an INT to specific "record version". I'm currently using "RecordOrder", but I don't like that, because people think higher=newer, but the way I'm using it, lower=newer (with "1" being the current record, "2" being the second most current, "3" older still, and so on). I've considered "RecordVersion", but I'm afraid that would have the same problem. Any other suggestions? "RecordAge"? I'm doing this because when I insert into the table, instead of having to find out what version is next, then run the risk of having that number stolen from me before I write, I just insert insert with a "RecordOrder" of 0. There's a trigger on the table AFTER INSERT that increments all the "RecordOrder" numbers for that key by 1, so the record I just inserted becomes "1", and all others are increased by 1. That way, you can get a person's current record by selection RecordOrder=1, instead of getting the MAX(RecordOrder) and then selecting that. PS - I'm also open to criticism about why this is a terrible idea and I should be incrementing this index instead. This just seemed to make lookups much easier, but if it's a bad idea, please enlighten me! Some details about the data, as an example: I have the following database table: CREATE TABLE AmountDue ( CustomerNumber INT, AmountDue DECIMAL(14,2), RecordOrder SMALLINT, RecordCreated DATETIME ) A subset of my data looks like this: CustomerNumber Amountdue RecordOrder RecordCreated 100 0 1 2009-12-19 05:10:10.123 100 10.05 2 2009-12-15 06:12:10.123 100 100.00 3 2009-12-14 14:19:10.123 101 5.00 1 2009-11-14 05:16:10.123 In this example, there are three rows for customer 100 - they owed $100, then $10.05, and now they owe nothing. Let me know if I need to clarify it some more. UPDATE: The "RecordOrder" and "RecordCreated" columns are not available to the user - they're only there for internal use, and to help figure out which is the current customer record. Also, I could use it to return an appropriately-ordered customer history, though I could just as easily do that with the date. I can accomplish the same thing as an incrementing "Record Version" with just the RecordCreated date, I suppose, but that removes the convenience of knowing that RecordOrder=1 is the current record, and I'm back to doing a sub-query with MAX or MIN on the DateTime to determine the most recent record.

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  • Mysql join two tables and add column values

    - by Mike
    My knowledge of mysql is not very in depth. If I have two tables that for example look like this: Table1 Date v1 v2 v3 05/01/2010 26 abc 45 05/02/2010 31 def 25 05/03/2010 50 ghi 46 Table2 Date v1 v2 v3 05/01/2010 42 jkl 15 05/02/2010 28 mno 14 05/03/2010 12 pqr 64 How can I join them in a query by their date and have the sum of table1.v1 and table2.v1 and also have the sum of table1.v3 and table2.v3. V2 should be ignored.

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  • Multiple labels in Navigation bar

    - by cmos
    I would like to create a view similar to the "Now Playing" page on the iPhone and have 3 lines of text in the Navigation bar. The only way I could find to do this was: UINavigationBar *bar = [self.navigationController navigationBar]; label = [[UILabel alloc] initWithFrame:CGRectMake(60, 2, 200, 14)]; label.tag = SONG_TAG; label.backgroundColor = [UIColor clearColor]; label.font = [UIFont boldSystemFontOfSize:14]; label.adjustsFontSizeToFitWidth = NO; label.textAlignment = UITextAlignmentCenter; label.textColor = [UIColor whiteColor]; label.highlightedTextColor = [UIColor blackColor]; [bar addSubview:label]; [label release]; //Create album label label = [[UILabel alloc] initWithFrame:CGRectMake(60, 17, 200, 12)]; label.tag = ALBUM_TAG; label.backgroundColor = [UIColor clearColor]; label.font = [UIFont systemFontOfSize:12]; label.adjustsFontSizeToFitWidth = NO; label.textAlignment = UITextAlignmentCenter; label.highlightedTextColor = [UIColor blackColor]; label.textColor = HEXCOLOR(0xA5A5A5ff); [bar addSubview:label]; [label release]; //Create artist label label = [[UILabel alloc] initWithFrame:CGRectMake(60, 30, 200, 12)]; label.tag = ARTIST_TAG; label.backgroundColor = [UIColor clearColor]; label.font = [UIFont systemFontOfSize:12]; label.adjustsFontSizeToFitWidth = NO; label.textAlignment = UITextAlignmentCenter; label.highlightedTextColor = [UIColor blackColor]; label.textColor = HEXCOLOR(0xA5A5A5ff); [bar addSubview:label]; [label release]; The problem with this is I have to remove them when the view changes. So, in -viewWillDisappear I have: UILabel *label; label = (UILabel *)[self.navigationController.navigationBar viewWithTag:SONG_TAG]; [label removeFromSuperview]; label = (UILabel *)[self.navigationController.navigationBar viewWithTag:ALBUM_TAG]; [label removeFromSuperview]; label = (UILabel *)[self.navigationController.navigationBar viewWithTag:ARTIST_TAG]; [label removeFromSuperview]; I think the way to do this is make a custom view that has the 3 labels in it, and add this to the title view. (here's the catch - you can only add 1 label or view to the title view spot on the nav bar) self.navigationItem.titleView = newViewIMadeWithThreeLabels

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  • javascript DOM how to know what node is?

    - by Fernando SBS
    here is the source code: <table id="movements" cellpadding="1" cellspacing="1"><thead><tr><th colspan="3">Movimentações de tropas:</th></tr></thead><tbody><tr> <td class="typ"><a href="build.php?gid=16"><img src="img/x.gif" class="att1" alt="Tropas atacantes chegando" title="Tropas atacantes chegando" /></a><span class="a1">&raquo;</span></td> <td><div class="mov"><span class="a1">1&nbsp;Ataque</span></div><div class="dur_r">em&nbsp;<span id="timer1">13:21:06</span>&nbsp;hrs.</div></div></td></tr><tr> <td class="typ"><a href="build.php?gid=16"><img src="img/x.gif" class="def1" alt="Tropas de reforço chegando" title="Tropas de reforço chegando" /></a><span class="d1">&raquo;</span></td> <td><div class="mov"><span class="d1">1&nbsp;Reforço</span></div><div class="dur_r">em&nbsp;<span id="timer2">0:14:55</span>&nbsp;hrs.</div></div></td></tr><tr> <td class="typ"><a href="build.php?gid=16"><img src="img/x.gif" class="att2" alt="Próprias tropas atacando" title="Próprias tropas atacando" /></a><span class="a2">&laquo;</span></td> <td><div class="mov"><span class="a2">1&nbsp;Ataque</span></div><div class="dur_r">em&nbsp;<span id="timer3">0:08:50</span>&nbsp;hrs.</div></div></td></tr><tr> <td class="typ"><a href="build.php?gid=16"><img src="img/x.gif" class="def2" alt="Próprias tropas reforçando" title="Próprias tropas reforçando" /></a><span class="d2">&laquo;</span></td> <td><div class="mov"><span class="d2">1&nbsp;Reforço</span></div><div class="dur_r">em&nbsp;<span id="timer4">2:50:45</span>&nbsp;hrs.</div></div></td></tr></tbody></table> and this is the View Source Chart of the document html (for easy DOM working): I would like to get to the 0:14:55 value coming from <span class="d1">, how to do it? EDIT Marcel Korpel: The value is always in the span in a div coming directly after a div containing a span with class d1, like: <div class="mov"><span class="d1">1&nbsp;Reforço</span></div><div class="dur_r">em&nbsp;<span id="timer2">0:14:55</span>&nbsp;hrs.</div>

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  • php date list for specified duration

    - by user301584
    hi is there any php classes or functions, which will gives us all the days from specific duration? for example, if i want a list of dates from 25/03/2010 (25th march 2010) to 15/05/2010 (15th May 2010), it will give me: 25/03/2010 26/03/2010 26/03/2010 .... .... .... 14/05/2010 15/05/2010 thanks a lot for any help!

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  • Parse lines of integers in C

    - by Jérôme
    This is a classical problem, but I can not find a simple solution. I have an input file like: 1 3 9 13 23 25 34 36 38 40 52 54 59 2 3 9 14 23 26 34 36 39 40 52 55 59 63 67 76 85 86 90 93 99 108 114 2 4 9 15 23 27 34 36 63 67 76 85 86 90 93 99 108 115 1 25 34 36 38 41 52 54 59 63 67 76 85 86 90 93 98 107 113 2 3 9 16 24 28 2 3 10 14 23 26 34 36 39 41 52 55 59 63 67 76 Lines of different number of integers separated by a space. I would like to parse them in an array, and separate each line with a marker, let say -1. The difficulty is that I must handle integers and line returns. Here my existing code, it loops upon the scanf loop (because scanf can not begin at a given position). #include <stdio.h> #include <stdlib.h> int main(int argc, char **argv) { if (argc != 4) { fprintf(stderr, "Usage: %s <data file> <nb transactions> <nb items>\n", argv[0]); return 1; } FILE * file; file = fopen (argv[1],"r"); if (file==NULL) { fprintf(stderr, "Error: can not open %s\n", argv[1]); fclose(file); return 1; } int nb_trans = atoi(argv[2]); int nb_items = atoi(argv[3]); int *bdd = malloc(sizeof(int) * (nb_trans + nb_items)); char line[1024]; int i = 0; while ( fgets(line, 1024, file) ) { int item; while ( sscanf (line, "%d ", &item )){ printf("%s %d %d\n", line, i, item); bdd[i++] = item; } bdd[i++] = -1; } for ( i = 0; i < nb_trans + nb_items; i++ ) { printf("%d ", bdd[i]); } printf("\n"); }

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  • Information on Hook Constants

    - by dsaccount1
    Anyone can explain what these hooks do? Especially WH_MIN and WH_MAX. http://msdn.microsoft.com/en-us/library/ms644959(VS.85).aspx WH_MIN = -1 WH_MSGFILTER = -1 WH_JOURNALRECORD = 0 WH_JOURNALPLAYBACK = 1 WH_KEYBOARD = 2 WH_GETMESSAGE = 3 WH_CALLWNDPROC = 4 WH_CBT = 5 WH_SYSMSGFILTER = 6 WH_MOUSE = 7 WH_HARDWARE = 8 WH_DEBUG = 9 WH_SHELL = 10 WH_FOREGROUNDIDLE = 11 WH_CALLWNDPROCRET = 12 WH_KEYBOARD_LL = 13 WH_MOUSE_LL = 14 WH_MAX = 15

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  • Mysql count columns

    - by Sergio
    I have a table for image gallery with four columns like: foid | uid | pic1 | pic2 | pic3 | date | ----------------------------------------------- 104 | 5 | 1.jpg | 2.jpg | 3.jpg | 2010-01-01 105 | 14 | 8.jpg | | | 2009-04-08 106 | 48 | x.jpg | y.jpg | | 2010-08-09 Mysql query for the user's galleries looks like: SELECT * FROM foto WHERE uid = $id order by foid DESC The thing that I want to do is count the number of images (PIC1, PIC2, PIC3) in every of the listed galleries. What is the best way for doing that?

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  • Generate lags R

    - by Btibert3
    Hi All, I hope this is basic; just need a nudge in the right direction. I have read in a database table from MS Access into a data frame using RODBC. Here is a basic structure of what I read in: PRODID PROD Year Week QTY SALES INVOICE Here is the structure: str(data) 'data.frame': 8270 obs. of 7 variables: $ PRODID : int 20001 20001 20001 100001 100001 100001 100001 100001 100001 100001 ... $ PROD : Factor w/ 1239 levels "1% 20qt Box",..: 335 335 335 128 128 128 128 128 128 128 ... $ Year : int 2010 2010 2010 2009 2009 2009 2009 2009 2009 2010 ... $ Week : int 12 18 19 14 15 16 17 18 19 9 ... $ QTY : num 1 1 0 135 300 270 300 270 315 315 ... $ SALES : num 15.5 0 -13.9 243 540 ... $ INVOICES: num 1 1 2 5 11 11 10 11 11 12 ... Here are the top few rows: head(data, n=10) PRODID PROD Year Week QTY SALES INVOICES 1 20001 Dolie 12" 2010 12 1 15.46 1 2 20001 Dolie 12" 2010 18 1 0.00 1 3 20001 Dolie 12" 2010 19 0 -13.88 2 4 100001 Cage Free Eggs 2009 14 135 243.00 5 5 100001 Cage Free Eggs 2009 15 300 540.00 11 6 100001 Cage Free Eggs 2009 16 270 486.00 11 7 100001 Cage Free Eggs 2009 17 300 540.00 10 8 100001 Cage Free Eggs 2009 18 270 486.00 11 9 100001 Cage Free Eggs 2009 19 315 567.00 11 10 100001 Cage Free Eggs 2010 9 315 569.25 12 I simply want to generate lags for QTY, SALES, INVOICE for each product but I am not sure where to start. I know R is great with Time Series, but I am not sure where to start. I have two questions: 1- I have the raw invoice data but have aggregated it for reporting purposes. Would it be easier if I didn't aggregate the data? 2- Regardless of aggregation or not, what functions will I need to loop over each product and generate the lags as I need them? In short, I want to loop over a set of records, calculate lags for a product (if possible), append the lags (as they apply) to the current record for each product, and write the results back to a table in my database for my reporting software to use. Any help you can provide will be greatly appreciated! Many thanks in advance, Brock

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  • width and height of Font

    - by shubha
    How to get Width and Height of a specified number of characters ,font Size , font type and font style. ex : font size = 14 font type = "Times New Roman" font style = "Regular" No of Characters = 50 What is the width and height ?

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  • SharePoint 2010 custom search from Layouts page

    - by Faiz
    Hi, I am querying SharePoint 2010 search using FullTextSqlQuery. The query returns results as long as i run it from the webpart. However, for some reason, i need to run the same query from a custom aspx page deployed under layouts. The query returns a wcf exception. Has anyone tried running custom queries from pages deployed to layouts folder under 14 hive? Thanks, Faiz

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  • Fixing VB6 inaccurate mathmetical results due to rounding

    - by jay
    Try running this in a .VBS file MsgBox(545.14-544.94) You get a neat little answer of 0.199999999999932! This rounding issue also occurs unfortunately in Sin(2 * pi) since VB can only ever see the (user defined) variable pi as accurate as 3.14159265358979. Is rounding it manually (and loosing accuracy) the only way to improve the result? What is the most effective way of dealing with this kind of problem?

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  • What's pcap_pkthdr there for?

    - by httpinterpret
    Code snippet from here: void packet_handler(u_char *param, const struct pcap_pkthdr *header, const u_char *pkt_data) { .... /* retireve the position of the ip header */ ih = (ip_header *) (pkt_data + 14); //length of ethernet header .... What's const struct pcap_pkthdr *header for, when do we need it, how is it populated (since there is no such info in the packet itself as below)?

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  • How do i convert a string to a JSON object in JQuery?

    - by Rob
    I have a string in my db I want to pull into my page and convert to a json object. [ {id: 1,title: "Long Event", start: new Date(2009, 5, 6, 14, 0),end: new Date(2009, 5, 11)}, {id: 2,title: "Repeating Event", start: new Date(2009, 5, 2)}, {id: 3,title: "Meeting", start: new Date(2009, 5, 20, 9, 0)}, {id: 4,title: "Click for Facebook", start: new Date(2009, 5, 27, 16),end: new Date(2009, 5, 29), url: "http://facebook.com/"} ] How can I do this using JQuery?

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  • Mult-line Svg tooltip

    - by John Vaughan
    I have created numerous polygon shapes in SVG format. and grouped them together. When the user hovers over the group a tooltip box appear. I have used ecmascript. What i am looking to do is make the tooltip box a multiline box. Any ideas how to do this? <script type="text/ecmascript"> <![CDATA[ function init(evt) { if ( window.svgDocument == null ) { svgDocument = evt.target.ownerDocument; } tooltip = svgDocument.getElementById('tooltip'); tooltip_bg = svgDocument.getElementById('tooltip_bg'); } function ShowTooltip(evt, mouseovertext) { tooltip.setAttributeNS(null,"x",evt.clientX+17); tooltip.setAttributeNS(null,"y",evt.clientY+14); tooltip.firstChild.data = mouseovertext; tooltip.setAttributeNS(null,"visibility","visible"); length = tooltip.getComputedTextLength(); tooltip_bg.setAttributeNS(null,"width",length+8); tooltip_bg.setAttributeNS(null,"x",evt.clientX+14); tooltip_bg.setAttributeNS(null,"y",evt.clientY+1); tooltip_bg.setAttributeNS(null,"visibility","visibile"); } function HideTooltip(evt) { tooltip.setAttributeNS(null,"visibility","hidden"); tooltip_bg.setAttributeNS(null,"visibility","hidden"); } ]]> </script> <SVG> <g onmousemove="ShowTooltip(evt, 'GHANA 2000')" onmouseout="HideTooltip(evt)"> <path fill="#EEEEEE" d="M250,0c47,0,85.183,10.506,125,33.494L250,250V0z"/> <path id="score" d="M250,57c36.284,0,65.761,8.11,96.5,25.857L250,250V57z"/> <path fill="none" stroke="#FFFFFF" stroke-width="2" stroke-miterlimit="10" d="M250,0c47,0,85.183,10.506,125,33.494L250,250V0z"/> <text transform="matrix(1 0 0 1 283.9883 92.0024)" fill="#FFFFFF" font-family="'WalkwayBlack'" font-size="16">62</text> </g> <rect class="tooltip_bg" id="tooltip_bg" x="0" y="0" width="55" height="17" visibility="hidden"/> <text class="tooltip" id="tooltip" x="0" y="0" visibility="hidden">Tooltip</text> <SVG>

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  • MYSQL JOIN SELECT Statment - omit duplicated

    - by mouthpiec
    Hi, I am tying to join the following 2 queries but I am having duplicated .... it is possible to remove duplacted fro this: ( SELECT bar_id, bar_name, town_name, bar_telephone, (subscription_type_id *2) AS subscription_type_id FROM bar, sportactivitybar, towns, subscriptiontype WHERE sport_activity_id_fk =14 AND bar_id = bar_id_fk AND town_id = town_id_fk AND subscription_type_id = subscription_type_id_fk ) UNION ( SELECT bar_id, bar_name, town_name, bar_telephone, subscription_type_id FROM bar, towns, subscriptiontype WHERE town_id = town_id_fk AND subscription_type_id = subscription_type_id_fk ) ORDER BY subscription_type_id DESC , RAND( ) Please note that I need to omit those duplicates that will have a lower subscription_type_id

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  • JS text to array

    - by Sonny
    Hi i got this text 2/92/20 3/32/32 4/62/6 5/22/28 6/60/61 7/33/32 8/34/31 9/31/19 10/19/19 11/34/39 12/32/32 14/19/25 15/45/37 16/32/32 17/84/36 18/72/33 and i need it to be like // 2/92/20 chars[0][0]=2; chars[0][1]=92; chars[0][2]=20; How should i make that PS: the split must be in $.ajax({ type: "POST", url: "char_info2.php", dataType: "html", success: function(data) { //here }

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