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  • Switching MySql Replication Format

    - by NNN
    I'm currently using statement-based replication. After upgrading to MySql 5.1, I'm considering using row-based replication. After reading the docs it seems that you can change the format of the master on the fly. Will the slave automatically adapt to whatever type of binary log it is sent? Do I have to make any changes to the slave or master to get ready for switching or can I simply modify the binlog_format variable on the master?

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  • Migrate MySQL database to Sql Server

    - by RPK
    I recently encountered a problem in my production database due to MySQL bug. The bug is in the TimeStamp column. To avoid any inconvenience, I want to migrate the database to either Sql Server. Is there any FREE tool to easily and reliably migrate data and table structures?

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  • accessing SQL syntax reference in mysql workbench

    - by dcompiled
    Finding it a little bit tedious migrating to the new Mysql Workbench (5.2.22) even though it has many more features than the older GUI tools. Right now I'm confused why I can't find an SQL reference when I open the Doc Library. Is there a way to access this info within the workbench, I'd prefer not to have to open a browser to access reference info on the web.

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  • Saving images in database mysql

    - by xRobot
    My client have created a script in php+mysql that saves images directly in the database and every images has url like this: www.example.com/image.php?id=421 In your opinion this is a very wrong solution ? Should I rebuild all the site ? There are about 1000 visits per day and about 600 images in the database. This is the site: http://tinyurl.com/3xkxdsw

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  • How to manually build mysql cache

    - by hamstar
    I have a table of over 150,000 rows of which most would be updated daily. I have mysql caching turned on so the pages load faster however everytime the database is updated the pages load slow again, which I assume is the cache building itself again. So at the moment I have resorted to doing a wget -m --delete-after http://localhost/ on the server however this takes about 4 hours to complete and moves something like 13 gig. Is there a better way to do this?

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  • How to version control data stored in mysql

    - by Shawn
    I'm trying to use a simple mysql database but tweak it so that every field is backed up up to an indefinite number of versions. The best way I can illustrate this is by replacing each and every field of every table with a stack of all the values this field has ever had (each of these values should be timestamped). I guess it's kind of like having customized version control for all my data.. Any ideas on how to do this?

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  • Not able to create a datasource registration with WAMP MysQL 5.0 in DBArtisan

    - by Alf Christophersen
    I try in a test version of DBArtisan to set up a datasource and register both servere as localhost, database to use, my username and password, but, when testing the connection, I get message that connection failed. Hooking up from eg. Delphi and other utilities run nicely. But not DBArtisan, Is MySQL 5.0 not supported yet ?? Or is it WAMP that is the culprit naming the service wampmysqld insted of just mysqld ??

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  • mysql category tree search

    - by ffffff
    I have the following schema on MySQL 5.1 CREATE TABLE `mytest` ( `category` varchar(32) , `item_name` varchar(255) KEY `key1` (`category`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; category column is filled with like that [:parent_parent_cat_id][:parent_cat_id][:leaf_cat_id] "10000200003000" if you can search all of the under categories :parent_parent_category_id SELECT * FROM mytest WHERE category LIKE "10000%"; it's using index key1; but How to use index when I wanna search :parent_cat_id? SELECT * FROM mytest WHERE category LIKE "%20000%"; Do you have a better solutions?

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  • changing mysql password via java

    - by Osama Abukmail
    I'm trying to change a user's password on mysql using java, i successfully changed it on phpmyadmin but same command doesnt work on java SET PASSWORD = PASSWORD('12345') this command will change the current logged in user, i have tried it on java like this statement = connect.createStatement(); statement.executeUpdate("SET PASSWORD = PASSWORD('12345')"); but nothing happened i also tried this with root logged in statement = connect.createStatement(); statement.executeUpdate("SET PASSWORD FOR 'username'@'localhost' = PASSWORD('123456')"); and nothing work,, any help please

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  • Efficient way to build a MySQL update query in Python

    - by ensnare
    I have a class variable called attributes which lists the instance variables I want to update in a database: attributes = ['id', 'first_name', 'last_name', 'name', 'name_url', 'email', 'password', 'password_salt', 'picture_id'] Each of the class attributes are updated upon instantiation. I would like to loop through each of the attributes and build a MySQL update query in the form of: UPDATE members SET id = self._id, first_name = self._first name ... Thanks.

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  • Php + mysql transactions examples

    - by Donator
    I really haven't found normal example of php file where mysql transactions are being used. Can you show me simple example of that? And one more question. I've already created a lot of programming and didn't use transaction, maybe I can put any php function or smth to header.php that if one mysql_query fails, then others too? Thank you.

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  • mysql query not running correctly from inside the application

    - by Mala
    I am completely stumped. Here is my php (CodeIgniter) code: function mod() { $uid = $this->session->userdata('uid'); $pid = $this->input->post('pid'); if ($this->_verify($uid,$pid)) { $name = $this->input->post('name'); $price = $this->input->post('price'); $curr = $this->input->post('curr'); $url = $this->input->post('url'); $query = $this->db->query("UPDATE items SET name=".$this->db->escape($name).", price=".$this->db->escape($price).", currency=".$this->db->escape($curr),", url=".$this->db->escape($url)." WHERE pid=".$this->db->escape($pid)." LIMIT 1"); } header('location: '.$this->session->userdata('current')); } The purpose of this code is to modify the properties (name, price, currency, url) of a row in the 'items' table (priary key is pid). However, for some reason, allowing this function to run once modifies the name, price, currency and url of ALL entries in the table, regardless of their pid and of the LIMIT 1 thing I tacked on the end of the query. It's as if the last line of the query is being completely ignored. As if this wasn't strance enough, I replaced "$query = $this->db->query(" with an "echo" to see the SQL query being run, and it outputs a query much like I would expect: UPDATE items SET name='newname', price='newprice', currency='newcurrency', url='newurl' WHERE pid='10' LIMIT 1 Copy-pasting this into a MySQL window acts exactly as I want: it modifies the row with the selected pid. What is going on here???

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  • NHibernate and MySql Keywords

    - by jalchr
    Why Nibernate HQL can not handle the following query: from Deal D where (D.ApprovalDate + INTERVAL 1 Year) < current_timestamp() < (D.RenewalDate + INTERVAL -1 Year) knowing that INTERVAL and YEAR are keywords in MySQL, so this is kind of mixing Sql within Hql (unless Hql can handle date functions like so and I don't know) . The dialect is MySQLDialect Its perfectly valid to execute this query SELECT '2005-01-01' + INTERVAL 1 Year;

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  • New table for every user?

    - by SonOfOmer
    Hi everyone, I want to crate new table for each new user on the web site and I assume that there will be many users, I am sure that search performance will be good, but what is with maintenance?? It is MySQL which has no limit in number of tables. Thanks a lot.

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  • MYSQL/PHP: Inserting data via HTML form, same "input name"

    - by Camen
    I'm new to MySQL and as a learning project I'd like to make a recipe database. I'd like to the user to be able to enter ingredients through a simple HTML form but I'm stuck in how to label the form so that I can enter several ingredients into the database at once. I'd like to do something like this: <form method="post" action="insert.php"> Ingredient 1: <input type="text" name="ingredient"><br /> Ingredient 2: <input type="text" name="ingredient"><br /> Ingredient 3: <input type="text" name="ingredient"><br /> <input type="submit" value="Submit"> </form> When I do this, I add rows to the table but they're all empty. I know it's got something to do with me using "ingredient" (the table value where I want to add the ingredient name) several times in the form, but I just don't know how to solve it. I would absolutely love some input on how to make it work.

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  • Symfony 2 - Updating a table based on newly inserted record in another table

    - by W00d5t0ck
    I'm trying to create a small forum application using Symfony 2 and Doctrine 2. My ForumTopic entity has a last_post field (oneToOne mapping). Now when I persist my new post with $em->persist($post); I want to update my ForumTopic entity so its last_post field would reference this new post. I have just realised that it cannot be done with a Doctrine postPersist Listener, so I decided to use a small hack, and tried: $em->persist($post); $em->flush(); $topic->setLastPost($post); $em->persist($post); $em->flush(); but it doesn't seem to update my topics table. I also took a look at http://docs.doctrine-project.org/projects/doctrine-orm/en/2.1/reference/working-with-associations.html#transitive-persistence-cascade-operations hoping it will solve the problem by adding cascade: [ 'persist' ] to my Topic.orm.yml file, but it didn't help, either. Could anyone point me to a solution or an example class? My ForumTopic is: FrontBundle\Entity\ForumTopic: type: entity table: forum_topics id: id: type: integer generator: strategy: AUTO fields: title: type: string(100) nullable: false slug: type: string(100) nullable: false created_at: type: datetime nullable: false updated_at: type: datetime nullable: true update_reason: type: text nullable: true oneToMany: posts: targetEntity: ForumPost mappedBy: topic manyToOne: created_by: targetEntity: User inversedBy: articles nullable: false updated_by: targetEntity: User nullable: true default: null topic_group: targetEntity: ForumTopicGroup inversedBy: topics nullable: false oneToOne: last_post: targetEntity: ForumPost nullable: true default: null cascade: [ persist ] uniqueConstraint: uniqueSlugByGroup: columns: [ topic_group, slug ] And my ForumPost is: FrontBundle\Entity\ForumPost: type: entity table: forum_posts id: id: type: integer generator: strategy: AUTO fields: created_at: type: datetime nullable: false updated_at: type: datetime nullable: true update_reason: type: string nullable: true text: type: text nullable: false manyToOne: created_by: targetEntity: User inversedBy: forum_posts nullable: false updated_by: targetEntity: User nullable: true default: null topic: targetEntity: ForumTopic inversedBy: posts

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  • Unique text field in MySQL and php

    - by Jonathan
    I've created a salt using; md5(rand(0,10000000)); (there is probably a better way?) There doesn't seem to be possible to make a text field unique in MYSQL. So how do I check if the salt has already been used for a previous user? Or should I generate the salt based on the current date/time? as it is impossible for 2 users to register at exactly the same time correct?

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  • easy mysql query question

    - by Ahmet vardar
    Hi, here is the "msg" table on mysql sent_to customer msg read ------- -------- ------ ----- 45 3 bla 0 34 4 bla 1 34 6 bla 0 45 3 bla 0 56 7 bla 1 45 8 bla 0 for example user whose id number is 45 logs in, i want him to see this, you have 2 unread msg to your "number 3" customer you have 1 unread msg to your "number 8" customer like a news feed what query should i use for this ? thx

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  • ORDERING A MYSQL QUERY WITH JOINS AND GROUPS

    - by Oliver
    I have this mysql query: SELECT * FROM Customer c JOIN eHRDemographic ehD ON ehD.CxID = c.CustomerID JOIN CustPrimaryWeight cpW ON cpW.CxID = c.CustomerID WHERE c.CustomerID =22703 GROUP BY c.CustomerID ORDER BY cpW.CustPrimaryWeightID DESC This doesn't really work correctly as the CustPrimaryWeight table has multiple enteries and it's simply joining the first entry and not the more recent one as the ORDER statement doesn't seem to do anything. Any ideas?

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  • mysql php problem: no error message despite error_reporting(E_ALL) line

    - by herrturtur
    index.php <html> <head> <title>Josh's Online Playground</title> </head> <body> <form method="POST" action="action.php"> <table> <tr> <td>"data for stuff"</td> <td><input type="text" ?></td> </tr> <tr> <td><input type="submit"></td> </tr> </table> </form> </body> </html> action.php <?php error_reporting(E_ALL); ini_sit("display_errors", 1); $mysqli = new mysqli('localhost', 'root', 'password', 'website'); $result = $mysqli->query("insert into stuff (data) values (' .$_POST['data'] ."'); echo $mysqli->error(); if($result = $mysqli->query("select data from stuff")){ echo 'There are '.$result->num_rows.' results.'; } while ($row = $result->fetch_object()){ echo 'stuff' . $row->data; } ?> Despite the first two lines in action.php, I get no error or warning messages. Instead I get a blank page after clicking the submit button. Do I have to do something differently to insert data?

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