How to avoid my this facebook app api login page?
- by user1035140
I got a problem regrading with my apps which is once I go to my apps, it sure will show me a login page instead of allow page?
it always display the login page 1st then only display allow page, I had tried other apps, if I am 1st time user, It sure will appear the allow page only, it did not show me the login page.
my question is how to I avoid my login page direct go to allow page?
here is my login page picture
here is my apps link
https://apps.facebook.com/christmas_testing/
here is my facebook php jdk api coding
<?php
$fbconfig['appid' ] = "XXXXXXXXXXXXX";
$fbconfig['secret'] = "XXXXXXXXXXXXX";
$fbconfig['baseUrl'] = "myserverlink";
$fbconfig['appBaseUrl'] = "http://apps.facebook.com/christmas_testing/";
if (isset($_GET['code'])){
header("Location: " . $fbconfig['appBaseUrl']);
exit;
}
if (isset($_GET['request_ids'])){
//user comes from invitation
//track them if you need
header("Location: " . $fbconfig['appBaseUrl']);
}
$user = null; //facebook user uid
try{
include_once "facebook.php";
}
catch(Exception $o){
echo '<pre>';
print_r($o);
echo '</pre>';
}
// Create our Application instance.
$facebook = new Facebook(array(
'appId' => $fbconfig['appid'],
'secret' => $fbconfig['secret'],
'cookie' => true,
));
//Facebook Authentication part
$user = $facebook->getUser();
$loginUrl = $facebook->getLoginUrl(
array(
'scope' => 'email,publish_stream,user_birthday,user_location,user_work_history,user_about_me,user_hometown'
)
);
if ($user) {
try {
// Proceed knowing you have a logged in user who's authenticated.
$user_profile = $facebook->api('/me');
} catch (FacebookApiException $e) {
//you should use error_log($e); instead of printing the info on browser
d($e); // d is a debug function defined at the end of this file
$user = null;
}
}
if (!$user) {
echo "<script type='text/javascript'>top.location.href = '$loginUrl';</script>";
exit;
}
//get user basic description
$userInfo = $facebook->api("/$user");
function d($d){
echo '<pre>';
print_r($d);
echo '</pre>';
}
?
