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  • SQL Server Windows-only Authentication Strategy problem

    - by Mike Thien
    I would like to use Windows-only Authentication in SQL Server for our web applications. In the past we've always created the all powerful 1 SQL Login for the web application. After doing some initial testing we've decided to create Windows Active Directory groups that mimic the security roles of the application (i.e. Administrators, Managers, Users/Operators, etc...) We've created mapped logins in SQL Server to these groups and given them access to the database for the application. In addition, we've created SQL Server database roles and assigned each group the appropriate role. This is working great. My issue revolves around that for most of the applications, everyone in the company should have read access to the reports (and hence the data). As far as I can tell, I have 2 options: 1) Create a read-only/viewer AD group and put everyone in it. 2) Use the "domain\domain users" group(s) and assign them the correct roles in SQL. What is the best and/or easiest way to allow everyone read access to specific database objects using a Windows-only Authentication method?

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  • Query Optimizing Request

    - by mithilatw
    I am very sorry if this question is structured in not a very helpful manner or the question itself is not a very good one! I need to update a MSSQL table call component every 10 minutes based on information from another table call materials_progress I have nearly 60000 records in component and more than 10000 records in materials_progress I wrote an update query to do the job, but it takes longer than 4 minutes to complete execution! Here is the query : UPDATE component SET stage_id = CASE WHEN t.required_quantity <= t.total_received THEN 27 WHEN t.total_ordered < t.total_received THEN 18 ELSE 18 END FROM ( SELECT mp.job_id, mp.line_no, mp.component, l.quantity AS line_quantity, CASE WHEN mp.component_name_id = 2 THEN l.quantity*2 ELSE l.quantity END AS required_quantity, SUM(ordered) AS total_ordered, SUM(received) AS total_received , c.component_id FROM line l LEFT JOIN component c ON c.line_id = l.line_id LEFT JOIN materials_progress mp ON l.job_id = mp.job_id AND l.line_no = mp.line_no AND c.component_name_id = mp.component_name_id WHERE mp.job_id IS NOT NULL AND (mp.cancelled IS NULL OR mp.cancelled = 0) AND (mp.manual_override IS NULL OR mp.manual_override = 0) AND c.stage_id = 18 GROUP BY mp.job_id, mp.line_no, mp.component, l.quantity, mp.component_name_id, component_id ) AS t WHERE component.component_id = t.component_id I am not going to explain the scenario as it too complex.. could somebody please please tell me what makes this query this much expensive and a way to get around it? Thank you very very much in advance!!!

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  • SQL Server 2005 user permissions

    - by karl
    I have created a database and some dbo.tables. Now I want to create a user that are can read and write to these tables, but not modify or drop. However I want this user to be able to create own tables and let him do what he want with these. Is this possible? Could someone explain how this can be done?

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  • Migrating Windows 2003 File Server Cluster to Windows 2008 R2 Standalone?

    - by Tatas
    We have a situation where we have an aging Windows 2003 File Server Cluster that we'd like to move to a standalone Windows Server 2008 R2 VM that resides in our Hyper-V R2 installation. We see no need to keep the Clustering as Hyper-V is now providing our Failover/Redundancy. Usually, in a standalone file server migration we migrate the data, preserving NTFS permissions and then export the sharing permissions from the registry and import them on the new server. This does not appear possible in this instance, as the 2003 cluster stores the sharing permissions quite differently. My question is, how would one perform this type of migration? Is it even possible? My current lead is the File Server Migration Toolkit, however I can find no information on the net about migrating from cluster to standalone, only the opposite. Please help. UPDATE: We ended up getting the data copied over (permissions intact), but had to recreate the shares manually by hand. It was a bit of a pain but it did in the end work out.

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  • Question about SQL Server HierarchyID depth-first performance

    - by AndalusianCat
    I am trying to implement hierarchyID in a table (dbo.[Message]) containing roughly 50,000 rows (will grow substantially in the future). However it takes 30-40 seconds to retrieve about 25 results. The root node is a filler in order to provide uniqueness, therefor every subsequent row is a child of that dummy row. I need to be able to traverse the table depth-first and have made the hierarchyID column (dbo.[Message].MessageID) the clustering primary key, have also added a computed smallint (dbo.[Message].Hierarchy) which stores the level of the node. Usage: A .Net application passes through a hierarchyID value into the database and I want to be able to retrieve all (if any) children AND parents of that node (besides the root, as it is filler). A simplified version of the query I am using: @MessageID hierarchyID /* passed in from application */ SELECT m.MessageID, m.MessageComment FROM dbo.[Message] as m WHERE m.Messageid.IsDescendantOf(@MessageID.GetAncestor((@MessageID.GetLevel()-1))) = 1 ORDER BY m.MessageID From what I understand, the index should be detected automatically without a hint. From searching forums I have seen people utilizing index hints, at least in the case of breadth-first indexes, as apparently CLR calls may be opaque to the query optimizer. I have spent the past few days trying to find a solution for this issue, but to no avail. I would greatly appreciate any assistance, and as this is my first post, I apologize in advance if this would be considered a 'noobish' question, I have read the MS documentation and searched countless forums, but have not came across a succinct description of the specific issue.

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  • Storing a set of criteria in another table

    - by bendataclear
    I have a large table with sales data, useful data below: RowID Date Customer Salesperson Product_Type Manufacturer Quantity Value 1 01-06-2004 James Ian Taps Tap Ltd 200 £850 2 02-06-2004 Apple Fran Hats Hats Inc 30 £350 3 04-06-2004 James Lawrence Pencils ABC Ltd 2000 £980 ... Many rows later... ... 185352 03-09-2012 Apple Ian Washers Tap Ltd 600 £80 I need to calculate a large set of targets from table containing values different types, target table is under my control and so far is like: TargetID Year Month Salesperson Target_Type Quantity 1 2012 7 Ian 1 6000 2 2012 8 James 2 2000 3 2012 9 Ian 2 6500 At present I am working out target types using a view of the first table which has a lot of extra columns: SELECT YEAR(Date) , MONTH(Date) , Salesperson , Quantity , CASE WHEN Manufacturer IN ('Tap Ltd','Hats Inc') AND Product_Type = 'Hats' THEN True ELSE False END AS IsType1 , CASE WHEN Manufacturer = 'Hats Inc' AND Product_Type IN ('Hats','Coats') THEN True ELSE False END AS IsType2 ... ... , CASE WHEN Manufacturer IN ('Tap Ltd','Hats Inc') AND Product_Type = 'Hats' THEN True ELSE False END AS IsType24 , CASE WHEN Manufacturer IN ('Tap Ltd','Hats Inc') AND Product_Type = 'Hats' THEN True ELSE False END AS IsType25 FROM SalesTable WHERE [some stuff here] This is horrible to read/debug and I hate it!! I've tried a few different ways of simplifying this but have been unable to get it to work. The closest I have come is to have a third table holding the definition of the types with the values for each field and the type number, this can be joined to the tables to give me the full values but I can't work out a way to cope with multiple values for each field. Finally the question: Is there a standard way this can be done or an easier/neater method other than one column for each type of target? I know this is a complex problem so if anything is unclear please let me know. Edit - What I need to get: At the very end of the process I need to have targets displayed with actual sales: Type Year Month Salesperson TargetQty ActualQty 2 2012 8 James 2000 2809 2 2012 9 Ian 6500 6251 Each row of the sales table could potentially satisfy 8 of the types. Some more points: I have 5 different columns that need to be defined against the targets (or set to NULL to include any value) I have between 30 and 40 different types that need to be defined, several of the columns could contain as many as 10 different values For point 2, if I am using a row for each permutation of values, 2 columns with 10 values each would give me 100 rows for each sales person for each month which is a lot but if this is the only way to define multiple values I will have to do this. Sorry if this makes no sense!

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  • How do I remove the on screen keyboard from the logon screen in Windows Remote Desktop Server 2008 R

    - by Gomibushi
    The on screen keyboard (OSK) from the "ease of access" tools pops up on EVERY connect to the server, even if you have not activated it. I can't seem to find a control panel or reg setting to switch it off. It is VERY "in your face" for linux users who connect at lower resolutions and do not provide all credentials, but have to type username and password. I'm running a 2008 R2 Terminal Server/Remote Desktop Server.

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  • SQL Server JDBC Exception

    - by user267581
    When using ANT to build my Java application I keep getting this error. I have tried multiple times to use SQLJDBC.JAR and SQLJDBC4.JAR but continually receive this error message. I am completely stumpped why this error is received even after upgrading to sqljdbc4.jar. [javadoc] java.lang.UnsupportedOperationException: Java Runtime Environment (JRE) version 1.6 is not supported by this driver. Use the sqljdbc4.jar class library, which provides support for JDBC 4.0.

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  • Counting number of children in hierarchical SQL data

    - by moontear
    Hello, for a simple data structure such as so: ID parentID Text Price 1 Root 2 1 Flowers 3 1 Electro 4 2 Rose 10 5 2 Violet 5 6 4 Red Rose 12 7 3 Television 100 8 3 Radio 70 9 8 Webradio 90 For reference, the hierarchy tree looks like this: ID Text Price 1 Root |2 Flowers |-4 Rose 10 | |-6 Red Rose 12 |-5 Violet 5 |3 Electro |-7 Television 100 |-8 Radio 70 |-9 Webradio 90 I'd like to count the number of children per level. So I would get a new column "NoOfChildren" like so: ID parentID Text Price NoOfChildren 1 Root 8 2 1 Flowers 3 3 1 Electro 3 4 2 Rose 10 1 5 2 Violet 5 0 6 4 Red Rose 12 0 7 3 Television 100 0 8 3 Radio 70 1 9 8 Webradio 90 0 I read a few things about hierarchical data, but I somehow get stuck on the multiple inner joins on the parentIDs. Maybe someone could help me out here. moon

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  • SQL 2008 Replication over Internet

    - by Akash Kava
    We have decided to put our servers in data centers on east and west coast of US, to keep high level redundancy. After evaluating number of replication options, apart from VPN there is no other way to do replication for SQL Server. We are investigating VPN but I have following questions. Our Large DB consists of media information (pictures/movies/audio/pdf) etc, so we are not very concerned about security because they are not financial sensitive data. SQL 2005 supports or can be configured to support replication over internet? If Yes then should we downgrade to 2005? If SQL 2008 Publisher is configured for Web Sync, can we write an automatic program (C# Windows Service) to act as pull subscriber and run on the subscriber server and replicate subscriber database? Or are there any API available in SQL where we can write our own program to do replication in very generic way? (In a nut shell, can we write our own C# Windows Service based Subscriber program?)

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  • Multi-base conversion - using all combinations for URL shortener

    - by Guffa
    I am making an URL shortener, and I am struggling with the optimal way of encoding a number (id) into a character string. I am using the characters 0-9,A-Z,a-z so it will basically be a base-62 encoding. That is pretty basic, but it doesn't make use of all possible codes. The codes that it would produce would be: 0, 1, ... y, z, 10, 11, ... zy, zz, 100, 101, ... Notice that the codes 00 to 0z is not used, the same for 000 to 0zz, and so on. I would like to use all the codes, like this: 0, 1, ... y, z, 00, 01, ... zy, zz, 000, 001, ... It would be some combination of base-62 and base-63, with different bases depending on the position... Using base-62 is easy, for example: create procedure tiny_GetCode @UrlId int as set nocount on declare @Code varchar(10) set @Code = '' while (@UrlId > 0 or len(@Code) = 0) begin set @Code = substring('0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz', @UrlId % 62 + 1, 1) + @Code set @UrlId = @UrlId / 62 end select @Code But I haven't yet managed to make a multi-base conversion out of it, to make use of all the codes.

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  • optimizing an sql query using inner join and order by

    - by Sergio B
    I'm trying to optimize the following query without success. Any idea where it could be indexed to prevent the temporary table and the filesort? EXPLAIN SELECT SQL_NO_CACHE `groups`.* FROM `groups` INNER JOIN `memberships` ON `groups`.id = `memberships`.group_id WHERE ((`memberships`.user_id = 1) AND (`memberships`.`status_code` = 1 AND `memberships`.`manager` = 0)) ORDER BY groups.created_at DESC LIMIT 5;` +----+-------------+-------------+--------+--------------------------+---------+---------+---------------------------------------------+------+----------------------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------------+--------+--------------------------+---------+---------+---------------------------------------------+------+----------------------------------------------+ | 1 | SIMPLE | memberships | ref | grp_usr,grp,usr,grp_mngr | usr | 5 | const | 5 | Using where; Using temporary; Using filesort | | 1 | SIMPLE | groups | eq_ref | PRIMARY | PRIMARY | 4 | sportspool_development.memberships.group_id | 1 | | +----+-------------+-------------+--------+--------------------------+---------+---------+---------------------------------------------+------+----------------------------------------------+ 2 rows in set (0.00 sec) +--------+------------+-----------------------------------+--------------+-----------------+-----------+-------------+----------+--------+------+------------+---------+ | Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | +--------+------------+-----------------------------------+--------------+-----------------+-----------+-------------+----------+--------+------+------------+---------+ | groups | 0 | PRIMARY | 1 | id | A | 6 | NULL | NULL | | BTREE | | | groups | 1 | index_groups_on_name | 1 | name | A | 6 | NULL | NULL | YES | BTREE | | | groups | 1 | index_groups_on_privacy_setting | 1 | privacy_setting | A | 6 | NULL | NULL | YES | BTREE | | | groups | 1 | index_groups_on_created_at | 1 | created_at | A | 6 | NULL | NULL | YES | BTREE | | | groups | 1 | index_groups_on_id_and_created_at | 1 | id | A | 6 | NULL | NULL | | BTREE | | | groups | 1 | index_groups_on_id_and_created_at | 2 | created_at | A | 6 | NULL | NULL | YES | BTREE | | +--------+------------+-----------------------------------+--------------+-----------------+-----------+-------------+----------+--------+------+------------+---------+ +-------------+------------+----------------------------------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+ | Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | +-------------+------------+----------------------------------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+ | memberships | 0 | PRIMARY | 1 | id | A | 2 | NULL | NULL | | BTREE | | | memberships | 0 | grp_usr | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 0 | grp_usr | 2 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | grp | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | usr | 1 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | grp_mngr | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | grp_mngr | 2 | manager | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 2 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 3 | status_code | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 4 | manager | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | index_memberships_on_user_id_and_status_code_and_manager | 1 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | index_memberships_on_user_id_and_status_code_and_manager | 2 | status_code | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | index_memberships_on_user_id_and_status_code_and_manager | 3 | manager | A | 2 | NULL | NULL | YES | BTREE | | +-------------+------------+----------------------------------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+

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  • Best practices for SQL Server audit trail

    - by Ducain
    I'm facing a situation today where it would be very beneficial to me and my company if we knew who had logged into SQL and performed some deletions. We have a situation where at least 2 (sometimes 3) people login to SQL using SQL Server Management Studio, and perform various functions. What we need is an audit trail. If someone deletes records (mistakenly or otherwise), I'd like to know what was done. Is there any way to make this happen?

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  • Error: An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAV

    - by brz dot net
    I have to find the indentid from the status table based on below two conditions: 1. If there are more than one record having same indentid in status table and the same indentID has count1 in feasibilitystatus table then I don't want to display the record. 2. If there is only one record of indentid in status table and the same indentID has count0 in feasibilitystatus table then I don't want to display the record. Query: select distinct s.indentid from status s where s.status='true' and s.indentid not in( select case when count(s.indentid)>1 then (select indentid from feasibilitystatus group by indentid having count(indentid)>1) else (select indentid from feasibilitystatus group by indentid having count(indentid)>0) end as indentid from status) Error: An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING clause or a select list, and the column being aggregated is an outer reference.

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  • How can I tell if a KB or newer has been installed for Windows?

    - by IguyKing
    I have a Windows system that I need to audit. The requirements is that (for example) KB2160329 has been installed onto the system. I know from lots of digging that KB2731847 that we have installed in the environment superseded the earlier KB. MSkbfiles.com works if you know the file name such as TCPIP.SYS. Doesn't do anything if you are just looking for KB Hotfixes. How can I say feed in a script that I'm looking for KB2160329 and it can check for superseded patches? Or is there a website somewhere that I'm missing? [Edited 7 May 2014 8:54am CST] I'm looking for a way to say that KB2731847 which is on the system does fix the same issue (plus more fixes) as KB2160329 which is not in the list as being installed on the system.

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  • How to use Hardware RAID in Ubuntu Server

    - by user2071938
    I have an Adaptec RAID-Controller and created an RAID-1(Mirroring) succesfully. Now I have installed Ubuntu Server 12.04.3. When I type fdisk -l I get this output: bf@fileserver:~$ sudo fdisk -l Disk /dev/sda: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Disk /dev/sda doesn't contain a valid partition table Disk /dev/sdb: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Disk /dev/sdb doesn't contain a valid partition table Disk /dev/sdc: 80.0 GB, 80026361856 bytes 255 heads, 63 sectors/track, 9729 cylinders, total 156301488 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x0004c454 Device Boot Start End Blocks Id System /dev/sdc1 * 2048 499711 248832 83 Linux /dev/sdc2 501758 156301311 77899777 5 Extended /dev/sdc5 501760 156301311 77899776 8e Linux LVM Disk /dev/mapper/fileserver--vg-root: 75.6 GB, 75606523904 bytes 255 heads, 63 sectors/track, 9191 cylinders, total 147668992 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/fileserver--vg-root doesn't contain a valid partition table Disk /dev/mapper/ddf1_Data: 1000.1 GB, 1000065728512 bytes 255 heads, 63 sectors/track, 121584 cylinders, total 1953253376 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Disk /dev/mapper/ddf1_Data doesn't contain a valid partition table Disk /dev/mapper/fileserver--vg-swap_1: 4160 MB, 4160749568 bytes 255 heads, 63 sectors/track, 505 cylinders, total 8126464 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/fileserver--vg-swap_1 doesn't contain a valid partition table The 80 GB HDD is for the System The 1000.2 GB HDD should be for my data. But I'm a bit confused becauser there are listed two 1000.2 GB HDDs, due the Hardware RAID shoudln't there be only one HDD vissible to the OS? (I have two 1000.2 GB HDDs in an Raid-1 Array) dmraid gives me bf@fileserver:~$ sudo dmraid -r /dev/sdb: ddf1, ".ddf1_disks", GROUP, ok, 1953253376 sectors, data@ 0 /dev/sda: ddf1, ".ddf1_disks", GROUP, ok, 1953253376 sectors, data@ 0 so It seems to be ok? But how do I partitionate this disks and which one should I mount(sdb or sda?) Hope you can help me thx Florian

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  • How can I fill SQL Server table from excel only using sql query?

    - by Phsika
    How can I do that with Microsoft.ACE.OLEDB.12.0? CREATE TABLE [dbo].[Addresses_Temp] ( [FirstName] VARCHAR(20), [LastName] VARCHAR(20), [Address] VARCHAR(50), [City] VARCHAR(30), [State] VARCHAR(2), [ZIP] VARCHAR(10) ) GO INSERT INTO [dbo].[Address_Temp] ( [FirstName], [LastName], [Address], [City], [State], [ZIP] ) SELECT [FirstName], [LastName], [Address], [City], [State], [ZIP] FROM OPENROWSET('Microsoft.ACE.OLEDB.12.0', 'Excel 12.0;Database=C:\Source\Addresses.xlsx;IMEX=1', 'SELECT * FROM [Sayfa1$]') How can I do that?

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  • Recursive Query Help

    - by Josh
    I have two tables in my database schema that represent an entity having a many-to-many relationship with itself. Role --------------------- +RoleID +Name RoleHasChildRole --------------------- +ParentRoleID +ChildRoleID Essentially, I need to to be able to write a query such that: Given a set of roles, return the unique set of all related roles recursively. This is an MSSQL 2008 Database.

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