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  • onSubmit returning false is not working

    - by StuckOnSubmit
    I'm completely confused ... I'd swear this was working yesterday ... I woke up this morning and all my forms stopped to work in my project. All the forms have a "onsubmit" to a function that returns false since it's an ajax call, so the form is never sent. After a lot of tests, I simplified the question to this piece of code: <html> <head> <script type="text/javascript"> function sub() { alert ("MIC!"); return false; } </script> </head> <body> <form method = "post" id = "form1" onsubmit = "return sub()"> input: <input type="text" name="input1" > <a href="#" onClick="document.getElementById('form1').submit();">button</a> </form> </body> </html> I would swear that this works perfectly, but today is nor working :D Why if I press the button the form is sent ? I know it's a total newbie question, but I'm stuck Thank you !

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  • How do you reenable a validation control w/o it simultaneously perform an immediate validation?

    - by Velika2
    When I called this function to enable a validator from client javascript: `ValidatorEnable(document.getElementById('<%=valPassportOtherText.ClientID%>'), true); //enable` validation control the required validation control immediately performed it validation, found the value in the associated text box blank and set focus to the textbox (because SetFocusOnError was set to true). As a result, the side effect was that focus was shifted to the control that was associated with the Validation control, i teh example, txtSpecifyOccupation. <asp:TextBox ID="txtSpecifyOccupation" runat="server" AutoCompleteType="Disabled" CssClass="DefaultTextBox DefaultWidth" MaxLength="24" Rows="2"></asp:TextBox> <asp:RequiredFieldValidator ID="valSpecifyOccupation" runat="server" ControlToValidate="txtSpecifyOccupation" ErrorMessage="1.14b Please specify your &lt;b&gt;Occupation&lt;/b&gt;" SetFocusOnError="True">&nbsp;Required</asp:RequiredFieldValidator> Perhaps there is a way to enable the (required) validator without having it simultaneously perform the validation (at least until the user has tabbed off of it?) I'd like validation of the txtSpecifyOccupation textbox to occur only on a Page submit or when the user has tabbed of the required txtSpecifyoccupation textbox. How can I achieve this?

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  • Three20 TTSectionedDataSource row height

    - by Ward
    Hey there, I'm using Three20 to create a table with several textfields for user registration. I've found two possible methods using Three20. The first uses the TTSectionedDataSource's tableDidLoadModel method to manually add UI components and the second adds custom items that contains pre formatted UI components. The second option seems way more complex and I'm having a difficult time accessing the individual fields. So if one field is a textfield for the username, I need to access the field to submit the username and it doesn't seem like there's an easy answer. The first option gives me a lot of flexibility, but I can't figure out how to set the individual row heights. One row may have a label above a text field, another may have an image, etc. Is there a method that can be used in TTSectionedDataSource that will allow me to set the height for each row? Thus far, I'm using method one and creating UIViews to hold a label field and a text field. I've tried changing the frame of the uiview before it is added to the items array, but it has no affect. Any ideas?

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  • Help with Struts Action mapping

    - by nicotine
    I am having a problem with my struts application it is a class enrollment app and when the user clicks on a "show enrolled courses" button it is supposed to show the courses they are enrolled in but it shows nothing at the moment. Struts/Apache does not return any errors, it Just shows a blank page and I cannot figure out why. My action mapping in my struts-config: <action path="/showEnrolled" type="actions.ShowEnrolledAction" name="UserFormEnrolled" scope="request" validate="true" input="/students/StudentMenu.jsp"> <forward name="success" path="/students/enrolled.jsp"/> </action> My link to the jsp enrolled.jsp page: <li><html:form action="/showEnrolled"> <html:hidden property="id" value= "<%=request.getRemoteUser()%>"/> <html:submit value = "View Enrolled Classes"/> </html:form> </li> When I click the link I get nothing but my menu on the page. The text headings for the page are not even displayed.

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  • Django formset doesn't validate

    - by tsoporan
    Hello, I am trying to save a formset but it seems to be bypassing is_valid() even though there are required fields. To test this I have a simple form: class AlbumForm(forms.Form): name = forms.CharField(required=True) The view: @login_required def add_album(request, artist): artist = Artist.objects.get(slug__iexact=artist) AlbumFormSet = formset_factory(AlbumForm) if request.method == 'POST': formset = AlbumFormSet(request.POST, request.FILES) if formset.is_valid(): return HttpResponse('worked') else: formset = AlbumFormSet() return render_to_response('submissions/addalbum.html', { 'artist': artist, 'formset': formset, }, context_instance=RequestContext(request)) And the template: <form action="" method="post" enctype="multipart/form-data">{% csrf_token %} {{ formset.management_form }} {% for form in formset.forms %} <ul class="addalbumlist"> {% for field in form %} <li> {{ field.label_tag }} {{ field }} {{ field.errors }} </li> {% endfor %} </ul> {% endfor %} <div class="inpwrap"> <input type="button" value="add another"> <input type="submit" value="add"> </div> </form> What ends up happening is I hit "add" without entering a name then HttpResponse('worked') get's called seemingly assuming it's a valid form. I might be missing something here, but I can't see what's wrong. What I want to happen is, just like any other form if the field is required to spit out an error if its not filled in. Any ideas?

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  • Web framework with JasperReports integration?

    - by Dave Jarvis
    What web development frameworks natively support JasperReports? Consider the following form as an example: <form name="report" method="post"> <input type="hidden" name="REPORT_PATH" value="reports/Names" /> <input type="hidden" name="REPORT_FILE" value="List" /> <input type="hidden" name="REPORT_FORMAT" value="pdf" /> <input type="hidden" name="REPORT_EMBED" value="false" /> Name: <input type="text" name="report_Name" value="" /><br /> Date: <input type="text" name="report_Date" value="" /><br /> <input type="submit" name="View" value="View" /> </form> The framework would pass the report_ parameters to JasperReports, which in turn runs reports/Names/List.jasper, and then sends a PDF attachment to the browser. In general: Ability to configure report (i.e., the hidden REPORT_ variables) Web FORM for setting report parameters (i.e., the report_ variables) Framework handles configuring database connection, report execution, etc. I don't care about the technical minutia on how the integration works. The example above is just one possibility of many.

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  • How do I set up routes to enable me to call different actions on the same controller?

    - by Remnant
    I am building my first asp.net mvc application for learning and development purposes and have come across an issue that I'd like some guidance with. Suppose I have a controller with two actions as follows: public class MyController : Controller { public ActionResult Index() { dbData = GetData("DefaultParameter") return View(dbData); } public ActionResult UpdateView(string dbParameter) { dbData = GetData("dbParameter"); return View(dbData); } } On my webpage I have the following: <% using (Html.BeginForm("UpdateView", "MyController")) %> <% { %> <div class="dropdown"><%=Html.DropDownList("Selection", Model.List, new { onchange="this.form.submit();" })%></div> <% } %> I have the following route in Global.asax: public static void RegisterRoutes(RouteCollection routes) { routes.MapRoute("Default", "{controller}", new { controller = "MyController", action = "Index"}); } The issue I am having is as follows: When I use the dropdownlist I get an error saying that /MyController/UpdateView could not be found. It therefore seems that I need to add an additional route as follows: routes.MapRoute("Default", "{controller}", new { controller = "MyController", action = "UpdateView"}); However, this causes two new issues for me: Due to the hierachy within the routing list, the similarity of the routes means that the one that appears first in the list is always executed. I don't see why I need to create another route for UpdateView. All I want to do is to retrieve new data from the database and update the view. I don't see what this has to do with the URL schema. It feels like I have gone down the wrong track here and I have missed something quite fundamental?

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  • How do I create a selection list in ASP.NET MVC?

    - by Gary McGill
    I have a database table that records what publications a user is allowed to access. The table is very simple - it simply stores user ID/publication ID pairs: CREATE TABLE UserPublication (UserId INTEGER, PublicationID INTEGER) The presence of a record for a given user & publication means that the user has access; absence of a record implies no access. I want to present my admin users with a simple screen that allows them to configure which publications a user can access. I would like to show one checkbox for each of the possible publications, and check the ones that the user can currently access. The admin user can then check or un-check any number of publications and submit the form. There are various publication types, and I want to group the similarly-typed publications together - so I do need control over how the publications are presented (I don't want to just have a flat list). My view model obviously needs to have a list of all the publications (since I need to display them all regardless of the current selection), and I also need a list of the publications that the user currently has access to. (I'm not sure whether I'd be better off with a single list where each item includes the publication ID and a yes/no field?). But that's as far as I've got. I've really no idea how to go about binding this to some checkboxes. Where do I start?

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  • ASP.NET catching controls from html generated from the database

    - by Drahcir
    I have a set of websites that basically do the exact same thing in terms of functionality, the only thing that varies is the css and how the html is laid out. Is there a way to generate the html from a database (ie retreiving the html from a table) and then catching the controls (like buttons, textboxes etc) from the code behind? UPDATE: Here is an example of what I want to acheive: <html> <div id="generatedContent" runat="server"> <!-- the following content has been generated from the database on the page load event --> <div> This is a textbox <input id="tb1" runat="server" type="text" /> This is a button <input type="submit" id="btn1" runat="server" value="My Button" /> </div> </div> </html> This is the code behind var tb1 = new HtmlControls.HtmlInputText(); tb1 = FindControl("tb1"); var btn1 = new New HtmlControls.HtmlInputSubmit(); btn1 = FindControl("btn1"); Now obviously since the html has been generated from the database (ie after the page has already been initialised) the FindControl method will return null.

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  • How to return value using ajax

    - by Priyanka
    Hello. I have Ajax file in which code has written to accept values form user and then these values are taken in a Ajax function as follows: $(document).ready(function(){ $("#newsletterform").validate(); $('#Submit').click(function(){ var name = $('#newsletter_name').val(); var email = $('#newsletter_email').val(); sendValue(email,name); }); }); The function for paasing values and getting values from other file: function sendValue(str,name){ $.post( "newsletter/subscribe.php", //Ajax file { sendValue: str, sendVal: name }, function(data2){ $('#display').html(data2.returnValue); }, //How you want the data formated when it is returned from the server. "json" ); } and these values are passed to another file called "subscribe.php" in which insertion code to database is written and again I return the value to my first ajax function as follows: echo json_encode(array("returnValue"=$msg)); The msg is ging to contain my message to be displayed. But now, this works fine on localhost, I get the return values nad message properly but when I upload it on server this gives me an error as: data2 is null [Break on this error] $('#display').html(data2.returnValue); This only gives error for return value but insertion, sending mail functionality works fine. Please provide me with a good solution wherein I can be able to get back the return values without any error. Thanks in advance.

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  • How to tell which dataform button ended edit when using EventToCommand

    - by Rodd
    I'm new to SilverLight and Mvvm-Light. I have a DataForm on my view that displays/edits a SelectedPerson property (a Person object) of my view model. I want to execute a command on my viewmodel when the user clicks the Save button but don't want to take action if the user clicks cancel. I added the following to my ViewModel: public RelayCommand PersonEditEnded {get; set;} ... public void Initialize() { PersonEditEnded = new RelayCommand(DoSomething); ... } public void DoSomething() { } I added the following to my View: <toolkit:DataForm x:Name="PersonForm" ... CurrentItem="{Binding SelectedPerson, Mode=TwoWay}"> <i:Interaction.Triggers> <i:EventTrigger EventName="EditEnded"> <gs:EventToCommand Command="{Binding PersonEditEnded, Mode=OneWay}"/> </i:EventTrigger> </i:Interaction.Triggers> </toolkit:DataForm> This works and the DoSomething method is being called when the user presses Submit. However, DoSomething is also called when user presses Cancel. Is there a way to know which button was pressed or to supress the call when Cancel is pressed? Thanks for whatever help you can offer!

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  • django: How to make one form from multiple models containing foreignkeys

    - by Tim
    I am trying to make a form on one page that uses multiple models. The models reference each other. I am having trouble getting the form to validate because I cant figure out how to get the id of two of the models used in the form into the form to validate it. I used a hidden key in the template but I cant figure out how to make it work in the views My code is below: views: def the_view(request, a_id,): if request.method == 'POST': b_form= BForm(request.POST) c_form =CForm(request.POST) print "post" if b_form.is_valid() and c_form.is_valid(): print "valid" b_form.save() c_form.save() return HttpResponseRedirect(reverse('myproj.pro.views.this_page')) else: b_form= BForm() c_form = CForm() b_ide = B.objects.get(pk=request.b_id) id_of_a = A.objects.get(pk=a_id) return render_to_response('myproj/a/c.html', {'b_form':b_form, 'c_form':c_form, 'id_of_a':id_of_a, 'b_id':b_ide }) models class A(models.Model): name = models.CharField(max_length=256, null=True, blank=True) classe = models.CharField(max_length=256, null=True, blank=True) def __str__(self): return self.name class B(models.Model): aid = models.ForeignKey(A, null=True, blank=True) number = models.IntegerField(max_length=1000) other_number = models.IntegerField(max_length=1000) class C(models.Model): bid = models.ForeignKey(B, null=False, blank=False) field_name = models.CharField(max_length=15) field_value = models.CharField(max_length=256, null=True, blank=True) forms from mappamundi.mappa.models import A, B, C class BForm(forms.ModelForm): class Meta: model = B exclude = ('aid',) class CForm(forms.ModelForm): class Meta: model = C exclude = ('bid',) B has a foreign key reference to A, C has a foreign key reference to B. Since the models are related, I want to have the forms for them on one page, 1 submit button. Since I need to fill out fields for the forms for B and C & I dont want to select the id of B from a drop down list, I need to somehow get the id of the B form into the form so it will validate. I have a hidden field in the template, I just need to figure how to do it in the views

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  • How to show jQuery is working/waiting/loading ?

    - by Kim
    How do I show a loading picture and/or message to the user ? If possible, would I like to know how to make it full screen with grey-dimmed background. Kinda like when viewing the large picture from some galleries (sorry, no example link). Currently do I add a CSS class which has the image and other formating, but its not working for some reason. Results from the search do get inserted into the div. HTML <div id="searchresults"></div> CSS div.loading { background-image: url('../img/loading.gif'); background-position: center; width: 80px; height: 80px; } JS $(document).ready(function(){ $('#searchform').submit(function(){ $('#searchresults').addClass('loading'); $.post('search.php', $('#'+this.id).serialize(),function(result){ $('#searchresults').html(result); }); $('#searchresults').removeClass('loading'); return false; }); });

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  • Subscribe through API .net C#

    - by Younes
    I have to submit subscription data to another website. I have got documentation on how to use this API however i'm not 100% sure of how to set this up. I do have all the information needed, like username / passwords etc. This is the API documentation: https://www.apiemail.net/api/documentation/?SID=4 How would my request / post / whatever look like in C# .net (vs 2008) when i'm trying to acces this API? This is what i have now, I think i'm not on the right track: public static string GArequestResponseHelper(string url, string token, string username, string password) { HttpWebRequest myRequest = (HttpWebRequest)WebRequest.Create(url); myRequest.Headers.Add("Username: " + username); myRequest.Headers.Add("Password: " + password); HttpWebResponse myResponse = (HttpWebResponse)myRequest.GetResponse(); Stream responseBody = myResponse.GetResponseStream(); Encoding encode = System.Text.Encoding.GetEncoding("utf-8"); StreamReader readStream = new StreamReader(responseBody, encode); //return string itself (easier to work with) return readStream.ReadToEnd(); Hope someone knows how to set this up properly. Thx!

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  • Password Confirmation in zend framework

    - by Behrang
    I add this class to library/My/Validate/PasswordConfirmation.php <?php require_once 'Zend/Validate/Abstract.php'; class My_Validate_PasswordConfirmation extends Zend_Validate_Abstract { const NOT_MATCH = 'notMatch'; protected $_messageTemplates = array( self::NOT_MATCH => 'Password confirmation does not match' ); public function isValid($value, $context = null) { $value = (string) $value; $this->_setValue($value); if (is_array($context)) { if (isset($context['password']) && ($value == $context['password'])) { return true; } } elseif (is_string($context) && ($value == $context)) { return true; } $this->_error(self::NOT_MATCH); return false; } } ?> then I create two field in my form like this : $userPassword = $this->createElement('password', 'user_password'); $userPassword->setLabel('Password: '); $userPassword->setRequired('true'); $this->addElement($userPassword); //create the form elements user_password repeat $userPasswordRepeat = $this->createElement('password', 'password_confirm'); $userPasswordRepeat->setLabel('Password repeat: '); $userPasswordRepeat->setRequired('true'); $userPasswordRepeat->addPrefixPath('My_Validate','My/Validate','validate'); $userPasswordRepeat->addValidator('PasswordConfirmation'); $this->addElement($userPasswordRepeat) everything is good but when i submit form always I get the 'Password confirmation does not match' message ? What's Wrong in my code

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  • JavaScript alert not working in Android WebView

    - by user655192
    In my application I am using WebView and in that I am using JavaScript alert( ) method but its not working, no pop-up appears. in my manifest file I have added <uses-permission android:name="android.permission.INTERNET"></uses-permission> and in activity file I have added mWebView = (WebView) findViewById(R.id.webview); mWebView.getSettings().setJavaScriptEnabled(true); mWebView.loadUrl("file:///android_asset/demo.html"); In layout xml file I have added <WebView android:id="@+id/webview" android:layout_width="fill_parent" android:layout_height="fill_parent" /> Any clue how to enable full JavaScript in WebView. Update Thanks mark the alert() method in the html file are working now :) . Now there are two issues in WebView : 1: I am using a in the html file that i am loading in WebView , and trying to write in Hindi language font in it, but when i try to write Hindi text it displays as symbols ( rectangle symbols like [] ) . when i do the same in firefox browser on desktop it works fine. any clue how to give support for multiple language in textarea in WebView ? 2: When I am clicking submit and trying to open the value of text in alert() method in another java script it doesn't work , does it mean even after using WebChromeClient its applicable only for current loaded html page and not java scripts called from that page ?

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  • Strange resource not found issue?

    - by xBroak
    i seem to be having a very strange problem, when the app is run on my test phone it works perfectly, and plays a sound from the raw folder via soundpool on button press, however when i submit my app to testing after building it it crashes on 120+ devices for 'Resource not found' codes below: Please also note, the file is in fact there, in both the R file, in the compiled APK file and i have also cleaned numerous times. http://www.appthwack.com/public/FUVGFZn42q '01-03 21:09:36.828 26762 26762 W System.err: java.lang.RuntimeException: Unable to start activity ComponentInfo{appinventor.ai_Broak.PaintballWiz/com.muo.paintballwiz.PaintballWiz}: android.content.res.Resources$NotFoundException: File res/raw/pballshot.ogg from drawable resource ID #0x7f050000 - 1 occurrence' soundPool = new SoundPool(4, AudioManager.STREAM_MUSIC, 100); //soundPoolMap = new SparseIntArray(); soundPoolMap = new HashMap<Integer, Integer>(); // soundPoolMap.put(soundID, soundPool.load(this, R.raw.midi_sound, 1)); int myAudioFile = getResId("pballshot", R.raw.class); soundPoolMap.put(soundID, soundPool.load(PaintballWiz.this, myAudioFile, 1)); audioManager = (AudioManager) getSystemService(Context.AUDIO_SERVICE); curVolume = audioManager .getStreamVolume(AudioManager.STREAM_MUSIC); maxVolume = audioManager .getStreamMaxVolume(AudioManager.STREAM_MUSIC); leftVolume = curVolume / maxVolume; rightVolume = curVolume / maxVolume; soundPool.play(soundID, leftVolume, rightVolume, priority, no_loop, normal_playback_rate); soundPool.play(soundID, 0, 0, 1, -1, 1f);

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  • MVC2 DataAnnotations on ViewModel - Don't understand using it with MVVM pattern

    - by ScottSEA
    I have an MVC2 Application that uses MVVM pattern. I am trying use Data Annotations to validate form input. In my ThingsController I have two methods: [HttpGet] public ActionResult Index() { return View(); } public ActionResult Details(ThingsViewModel tvm) { if (!ModelState.IsValid) return View(tvm); try { Query q = new Query(tvm.Query); ThingRepository repository = new ThingRepository(q); tvm.Things = repository.All(); return View(tvm); } catch (Exception) { return View(); } } My Details.aspx view is strongly typed to the ThingsViewModel: <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<Config.Web.Models.ThingsViewModel>" %> The ViewModel is a class consisting of a IList of returned Thing objects and the Query string (which is submitted on the form) and has the Required data annotation: public class ThingsViewModel { public IList<Thing> Things{ get; set; } [Required(ErrorMessage="You must enter a query")] public string Query { get; set; } } When I run this, and click the submit button on the form without entering a value I get a YSOD with the following error: The model item passed into the dictionary is of type 'Config.Web.Models.ThingsViewModel', but this dictionary requires a model item of type System.Collections.Generic.IEnumerable`1[Config.Domain.Entities.Thing]'. How can I get Data Annotations to work with a ViewModel? I cannot see what I'm missing or where I'm going wrong - the VM was working just fine before I started mucking around with validation.

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  • How to get MySQL database to appear on index.php

    - by Teddy Truong
    Hi, I have a submission form on my website (index.php) and I have the data(user submissions) being stored into a MySQL database. Right now, I have the user submitting a post and then the page directs them to an update.php which shows what they inputed. However, I want all of the data in the database in MySQL to be shown on the index.php. It's a lot like a comment system. User submits a post... and sees their post above the other submitted posts all on the same page. I think I'm missing AJAX... ? Here is the code for index.php <div align="center"> <p>&nbsp;</p> <h2 align="center" class="Title"><em><strong>REDACTED</strong></em></h2> <form id="form1" name="form1" method="post" action="update.php"> <hr /> <label><br /> <form action="update.php" method="post"> REDACTED: <input type="text" name="text" /> <input type="submit" /> </form> </label> </form> </div> On update.php I have this: ?php $text = $_POST['text']; $myString = "REDACTED"; mysql_connect ("db----.net", "-----3", "------------") or die ('Error: ' . mysql_error()); mysql_select_db ("-----------"); $query="INSERT INTO TextArea (ID, text) VALUES ('NULL', '".$text."')"; mysql_query($query) or die ('Error updating database'); echo " $myString "," $text "; ?> Thanks a lot!

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  • Auto complete from database using CodeIgniter (Active Record)

    - by Ralph David Abernathy
    I have a form on my website in which one is able to submit a cat. The form contains inputs such as "Name" and "Gender", but I am just trying to get the auto completion to work with the "Name" field. Here is what my jquery looks like : $(document).ready(function() { $( "#tags" ).autocomplete({ source: '/Anish/auto_cat' }); }); Here is what my model looks like: public function auto_cat($search_term) { $this->db->like('name', $search_term); $response = $this->db->get('anish_cats')->result_array(); // var_dump($response);die; return $response; } } Here is my controller: public function auto_cat(){ $search_term = $this->input->get('term'); $cats = $this->Anish_m->auto_cat($search_term); } And here is my view: <head> <link rel="stylesheet" href="http://code.jquery.com/ui/1.10.3/themes/smoothness/jquery-ui.css" /> <script src="http://code.jquery.com/jquery-1.9.1.js"></script> <script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script> <link rel="stylesheet" href="/resources/demos/style.css" /> </head> <h1>Anish's Page</h1> <form action="/Anish/create" method="POST"> <div class="ui-widget"> <label for="tags">Name</label><input id="tags" type="text" name="name"> </div> <div> <label>Age</label><input type="text" name="age"> </div> <div> <label>Gender</label><input type="text" name="gender"> </div> <div> <label>Species</label><input type="text" name="species"> </div> <div> <label>Eye Color</label><input type="text" name="eye_color"> </div> <div> <label>Color</label><input type="text" name="color"> </div> <div> <label>Description</label><input type="text" name="description"> </div> <div> <label>marital status</label><input type="text" name="marital_status"> </div> <br> <button type="submit" class="btn btn-block btn-primary span1">Add cat</button> </form> <br/><br/><br/><br/> <table class="table table-striped table-bordered table-hover"> <thead> <tr> <th>Name</th> <th>Gender</th> <th>Age</th> <th>Species</th> <th>Eye Color</th> <th>Color</th> <th>Description</th> <th>Marital Status</th> <th>Edit</th> <th>Delete</th> </tr> </thead> <tbody> <?php foreach ($cats as $cat):?> <tr> <td> <?php echo ($cat['name']);?><br/> </td> <td> <?php echo ($cat['gender']);?><br/> </td> <td> <?php echo ($cat['age']);?><br/> </td> <td> <?php echo ($cat['species']);?><br/> </td> <td> <?php echo ($cat['eye_color']);?><br/> </td> <td> <?php echo ($cat['color']);?><br/> </td> <td> <?php echo ($cat['description']);?><br/> </td> <td> <?php echo ($cat['marital_status']);?><br/> </td> <td> <form action="/Anish/edit" method="post"> <input type="hidden" value="<?php echo ($cat['id']);?>" name="Anish_id_edit"> <button class="btn btn-block btn-info">Edit</button> </form> </td> <td> <form action="/Anish/delete" method="post"> <input type="hidden" value="<?php echo ($cat['id']);?>" name="Anish_id"> <button class="btn btn-block btn-danger">Delete</button> </form> </td> </tr> <?php endforeach;?> </tbody> </table> I am stuck. In my console, I am able to see this output when I type the letter 'a' if I uncomment the var_dump in my model: array(4) { [0]=> array(9) { ["id"]=> string(2) "13" ["name"]=> string(5) "Anish" ["gender"]=> string(4) "Male" ["age"]=> string(2) "20" ["species"]=> string(3) "Cat" ["eye_color"]=> string(5) "Brown" ["color"]=> string(5) "Black" ["description"]=> string(7) "Awesome" ["marital_status"]=> string(1) "0" } [1]=> array(9) { ["id"]=> string(2) "16" ["name"]=> string(5) "Anish" ["gender"]=> string(2) "fe" ["age"]=> string(2) "23" ["species"]=> string(2) "fe" ["eye_color"]=> string(2) "fe" ["color"]=> string(2) "fe" ["description"]=> string(2) "fe" ["marital_status"]=> string(1) "1" } [2]=> array(9) { ["id"]=> string(2) "17" ["name"]=> string(1) "a" ["gender"]=> string(1) "a" ["age"]=> string(1) "4" ["species"]=> string(1) "a" ["eye_color"]=> string(1) "a" ["color"]=> string(1) "a" ["description"]=> string(1) "a" ["marital_status"]=> string(1) "0" } [3]=> array(9) { ["id"]=> string(2) "18" ["name"]=> string(4) "Matt" ["gender"]=> string(6) "Female" ["age"]=> string(2) "80" ["species"]=> string(6) "ferret" ["eye_color"]=> string(4) "blue" ["color"]=> string(4) "pink" ["description"]=> string(5) "Chill" ["marital_status"]=> string(1) "0" } }

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  • How do I grab and use a variables coming back through ValueList from an AJAX call?

    - by Mel
    I'm trying the following code to execute a search and it's not working. On the search.cfm page, the only value coming back is the value I input into the search field (even if I click an autosuggest value, it's not coming back; only the letters I actually type myself come back). <cfform class="titleSearchForm" id="searchForm" action="search.cfm?GameID=#cfautosuggestvalue.GameID#" method="post"> <fieldset> <cfinput type="text" class="titleSearchField" name="TitleName" onChange="form.submit()" autosuggest="cfc:gz.cfcomp.search.AutoSuggestSearch({cfautosuggestvalue})"> <input type="button" class="titleSearchButton" value=" " /> </fieldset> </cfform> Query in CFC: <cfquery name="SearchResult" datasource="myDSN"> SELECT CONCAT(titles.TitleName, ' on ', platforms.PlatformAbbreviation) AS sResult, games.GameID FROM games Inner Join platforms ON games.PlatformID = platforms.PlatformID Inner Join titles ON titles.TitleID = games.TitleID WHERE UCase(titleName) LIKE Ucase('#ARGUMENTS.SearchString#%') ORDER BY titleName ASC; </cfquery> Two things: First of all, I would like to get the GameID back to the page making the AJAX request; I know why it is not coming back: Because I'm only returning sResult var, which does not include the GameID. Is there a way to return the GameID value without displaying it? The second thing: How to I grab a value from the auto-suggest once it is returned? Say I want to grab the GameID, or if I can't do that, the "TitleName" to use that in my query? I tried passing it to the form this way: action="search.cfm?GameID=#cfautosuggestvalue.GameID#" - but that does not work. How do I reference the autosuggestionvalue varaibles for use? Thanks

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  • Rails form with a better URL

    - by Sam
    Wow, switching to REST is a different paradigm for sure and is mainly a headache right now. view <% form_tag (businesses_path, :method => "get") do %> <%= select_tag :business_category_id, options_for_select(@business_categories.collect {|bc| [bc.name, bc.id ]}.insert(0, ["All Containers", 0]), which_business_category(@business_category) ), { :onchange => "this.form.submit();"} %> <% end %> controller def index @business_categories = BusinessCategory.find(:all) if params[:business_category_id].to_i != 0 @business_category = BusinessCategory.find(params[:business_category_id]) @businesses = @business_category.businesses else @businesses = Business.all end respond_to do |format| format.html # index.html.erb format.xml { render :xml => @businesses } end end routes map.resources What I want to to is get a better URL than what this form is presenting which is the following: http://localhost:3000/businesses?business_category_id=1 Without REST I would have do something like http://localhost:3000/business/view/bbq bbq as permalink or I would have done http://localhost:300/business_categories/view/bbq and get the business that are associated with the category but I don't really know the best way of doing this. So the two questions are what is the best logic of finding a business by its categories using the latter form and number two how to get that in a pretty URL all through RESTful routes in Rails.

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  • Sorting a list in PHP

    - by Andy
    Alright, so I've just (almost) finished my first little php script. Basically all it does is handling forms. It writes whatever the user put in to the fields of the form to a text file, then I include that text file in the index of the little page I have set up. So, currently it writes to the beginning of the text file (but doesn't overwrite previous data). But, several users wants this list to be alphabetically sorted instead. So what I want to do is make whatever they submit fall into the list in alphabetical order. The thing here is also that all I use in the text file are divs. The list is basically 'divided' into 3 parts. 'Title', 'Link', and 'Poster'. All I have done is positioned them with css. So, can I sort this list (the titles, in this case) alphabetically and still have the 'link' and 'poster' information assigned the way they already are, but just with the titles sorted? It don't use databases at all on my site, so there is no database handling at all used in this script (mainly because I'm not experienced at all in this).

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  • Add child to existing parent record in entity framework.

    - by Shawn Mclean
    My relationship between the parent and child is that they are connected by an edge. It is similiar to a directed graph structure. DAL: public void SaveResource(Resource resource) { context.AddToResources(resource); //Should also add children. context.SaveChanges(); } public Resource GetResource(int resourceId) { var resource = (from r in context.Resources .Include("ToEdges").Include("FromEdges") where r.ResourceId == resourceId select r).SingleOrDefault(); return resource; } Service: public void AddChildResource(int parentResourceId, Resource childResource) { Resource parentResource = repository.GetResource(parentResourceId); ResourceEdge inEdge = new ResourceEdge(); inEdge.ToResource = childResource; parentResource.ToEdges.Add(inEdge); repository.SaveResource(parentResource); } Error: An object with the same key already exists in the ObjectStateManager. The existing object is in the Unchanged state. An object can only be added to the ObjectStateManager again if it is in the added state. Image: I have been told this is the sequence in submitting a child to an already existing parent: Get parent - Attach Child to parent - submit parent. That is the sequence I used. The code above is extracted from an ASP.NET MVC 2 application using the repository pattern.

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  • Unable to send '+' through AJAX post?

    - by Harish Kurup
    I am using Ajax POST method to send data, but i am not able to send '+'(operator to the server i.e if i want to send 1+ or 20k+ it will only send 1 or 20k..just wipe out '+') HTML code goes here.. <form method='post' onsubmit='return false;' action='#'> <input type='input' name='salary' id='salary' /> <input type='submit' onclick='submitVal();' /> </form> and javascript code goes here, function submitVal() { var sal=document.getElementById("salary").value; alert(sal); var request=getHttpRequest(); request.open('post','updateSal.php',false); request.setRequestHeader("Content-Type","application/x-www-form-urlencoded"); request.send("sal="+sal); if(request.readyState == 4) { alert("update"); } } function getHttpRequest() { var request=false; if(window.XMLHttpRequest) { request=new XMLHttpRequest(); } else if(window.ActiveXObject) { try { request=new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) { try { request=new ActiveXObject("Microsoft.XMLHTTP"); } catch(e) { request=false; } } } return request; } in the function submitVal() it first alert's the salary value as it is(if 1+ then alerts 1+), but when it is posted it just post's value without '+' operator which is needed... is it any problem with query string, as the PHP backend code is working fine...

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