Search Results

Search found 33650 results on 1346 pages for 'line break'.

Page 169/1346 | < Previous Page | 165 166 167 168 169 170 171 172 173 174 175 176  | Next Page >

• How to delete just one LINE of text (NOT a table-row!) with a single KEYBOARD shortcut in Microsoft Office Word 2010?

  - by Sk8erPeter

  Are there any shortcuts to delete just one row (which is NOT a table row, just a single row in a text) in Microsoft Office Word 2010? If not, how can I assign one to do it? In worst case, can I make a macro (in VB) which could do the same with a custom shortcut? To clarify my problem: I would like to avoid multiple clicks and/or pushing multiple buttons, even if I click in the middle of the line of text. :) For example, in Notepad++ I can delete the entire current line with Ctrl+L, in NetBeans, I can delete an entire line with Ctrl+E, in Eclipse, I can delete current line with Ctrl+D, etc., where it doesn't really matter where my mouse cursor is actually... so there are these simple solutions, which I look for in Word too. It really would simplify my work in huge documents.

  Read the article

• ViewPager cycle between views?

  - by Erdem Azakli

  I want my ViewPager implementation to cycle between views instead of stopping at the last view. For example, if I have 3 views to display via a ViewPager, it should return back to the first View after the third View on fling instead of stopping at that third view. I want it to return to the first page/view when the user flings forward on the last page Thanks, Mypageradapter; package com.example.pictures; import android.content.Context; import android.media.AudioManager; import android.os.Parcelable; import android.support.v4.view.PagerAdapter; import android.support.v4.view.ViewPager; import android.view.LayoutInflater; import android.view.View; public class MyPagerAdapter extends PagerAdapter{ SoundManager snd; int sound1,sound2,sound3; boolean loaded = false; public int getCount() { return 6; } public Object instantiateItem(View collection, int position) { View view=null; LayoutInflater inflater = (LayoutInflater) collection.getContext() .getSystemService(Context.LAYOUT_INFLATER_SERVICE); this.setVolumeControlStream(AudioManager.STREAM_MUSIC); int resId = 0; switch (position) { case 0: resId = R.layout.picture1; view = inflater.inflate(resId, null); break; case 1: resId = R.layout.picture2; view = inflater.inflate(resId, null); break; case 2: resId = R.layout.picture3; view = inflater.inflate(resId, null); break; case 3: resId = R.layout.picture4; view = inflater.inflate(resId, null); break; case 4: resId = R.layout.picture5; view = inflater.inflate(resId, null); break; case 5: resId = R.layout.picture6; view = inflater.inflate(resId, null); break; } ((ViewPager) collection).addView(view, 0); return view; } @SuppressWarnings("unused") private Context getApplicationContext() { // TODO Auto-generated method stub return null; } private void setVolumeControlStream(int streamMusic) { // TODO Auto-generated method stub } @SuppressWarnings("unused") private Context getBaseContext() { // TODO Auto-generated method stub return null; } @SuppressWarnings("unused") private PagerAdapter findViewById(int myfivepanelpager) { // TODO Auto-generated method stub return null; } @Override public void destroyItem(View arg0, int arg1, Object arg2) { ((ViewPager) arg0).removeView((View) arg2); } @Override public boolean isViewFromObject(View arg0, Object arg1) { return arg0 == ((View) arg1); } @Override public Parcelable saveState() { return null; } public static Integer getItem(int position) { // TODO Auto-generated method stub return null; } } OnPageChangeListener; package com.example.pictures; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.support.v4.view.ViewPager; import android.support.v4.view.ViewPager.OnPageChangeListener; import android.view.View; import android.widget.Button; import android.widget.Toast; public class Pictures extends Activity implements OnPageChangeListener{ SoundManager snd; int sound1,sound2,sound3; View view=null; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.picturespage); MyPagerAdapter adapter = new MyPagerAdapter(); ViewPager myPager = (ViewPager) findViewById(R.id.myfivepanelpager); myPager.setAdapter(adapter); myPager.setCurrentItem(0); myPager.setOnPageChangeListener(this); snd = new SoundManager(this); sound1 = snd.load(R.raw.sound1); sound2 = snd.load(R.raw.sound2); sound3 = snd.load(R.raw.sound3); } public void onPageScrollStateChanged(int arg0) { // TODO Auto-generated method stub } public void onPageScrolled(int arg0, float arg1, int arg2) { // TODO Auto-generated method stub } public void onPageSelected(int position) { // TODO Auto-generated method stub switch (position) { case 0: snd.play(sound1); break; case 1: snd.play(sound2); break; case 2: snd.play(sound3); break; case 3: Toast.makeText(this, "1", Toast.LENGTH_SHORT).show(); break; case 4: Toast.makeText(this, "2", Toast.LENGTH_SHORT).show(); break; case 5: Toast.makeText(this, "3", Toast.LENGTH_SHORT).show(); break; } } };

  Read the article

• Calendar event problems

  - by Marin

  Goodmorning everybody! Can you please help me? I have a problem with this part of the script: $output = cal_top(); switch($action){ case "add": include("includes/event.php"); $output .= cal_event_form('add'); break; case "delete": include("includes/delete.php"); include('includes/viewdate.php'); $del_error = cal_del(); if($del_error!="") $output .= "<center><span class='failure'>$del_error</span></center><br>"; $output .= cal_display(); break; case "modify": include("includes/event.php"); $output .= cal_event_form('modify'); break; case "viewdate": include("includes/viewdate.php"); $output .= cal_display(); break; case "viewevent": include("includes/viewevent.php"); $output .= cal_display(); break; case "search": include("includes/search.php"); $output .= cal_search_form(); break; case "submitevent": include('includes/eventsub.php'); include('includes/viewdate.php'); $sub_error = cal_submit_event(); if($sub_error!="") $output .= "<center><span class='failure'>$sub_error</span></center><br>"; $output .= cal_display(); $_SESSION['cal_action'] = "viewdate"; break; case "admin": include('includes/admin.php'); $output .= cal_adminsection(); break; case "login": $_SESSION['cal_noautologin'] = 1; include('includes/login.php'); $output .= cal_login_page(); break; case "logout": cal_logout(); $_SESSION['cal_noautologin'] = 1; cal_clear_permissions(); cal_load_permissions(); It shows me this errors: Notice: Undefined variable: action in C:\wamp\www\ReeceCalendar_0.9\cal\index.php on line 145 Notice: Undefined variable: action in C:\wamp\www\ReeceCalendar_0.9\cal\index.php on line 149 Notice: Undefined variable: action in C:\wamp\www\ReeceCalendar_0.9\cal\index.php on line 156 Notice: Undefined variable: action in C:\wamp\www\ReeceCalendar_0.9\cal\index.php on line 160 Notice: Undefined variable: action in C:\wamp\www\ReeceCalendar_0.9\cal\index.php on line 164 Notice: Undefined variable: action in C:\wamp\www\ReeceCalendar_0.9\cal\index.php on line 168 Notice: Undefined variable: action in C:\wamp\www\ReeceCalendar_0.9\cal\index.php on line 172 Notice: Undefined variable: action in C:\wamp\www\ReeceCalendar_0.9\cal\index.php on line 180 Notice: Undefined variable: action in C:\wamp\www\ReeceCalendar_0.9\cal\index.php on line 184 Notice: Undefined variable: action in C:\wamp\www\ReeceCalendar_0.9\cal\index.php on line 189 Your help could be very helpful for me!Please Help me;)Thank you.

  Read the article

• Is there a standard way to encode a .NET string into javascript string for use in MS AJAX?

  - by Rich Andrews

  I'm trying to pass the output of a SQL Server exception to the client using the RegisterStartUpScript method of the MS ScriptManager. This works fine for some errors but when the exception contains single quotes the alert fails. I dont want to only escape single quotes though - Is there a standard function i can call to escape any special chars for use in Javascript? string scriptstring = "alert('" + ex.Message + "');"; ScriptManager.RegisterStartupScript(this, this.GetType(), "Alert", scriptstring , true); Thanks tpeczek, the code almost worked for me :) but with a slight amendment (the escaping of single quotes) it works a treat. I've included my amended version here... public class JSEncode { /// <summary> /// Encodes a string to be represented as a string literal. The format /// is essentially a JSON string. /// /// The string returned includes outer quotes /// Example Output: "Hello \"Rick\"!\r\nRock on" /// </summary> /// <param name="s"></param> /// <returns></returns> public static string EncodeJsString(string s) { StringBuilder sb = new StringBuilder(); sb.Append("\""); foreach (char c in s) { switch (c) { case '\'': sb.Append("\\\'"); break; case '\"': sb.Append("\\\""); break; case '\\': sb.Append("\\\\"); break; case '\b': sb.Append("\\b"); break; case '\f': sb.Append("\\f"); break; case '\n': sb.Append("\\n"); break; case '\r': sb.Append("\\r"); break; case '\t': sb.Append("\\t"); break; default: int i = (int)c; if (i < 32 || i > 127) { sb.AppendFormat("\\u{0:X04}", i); } else { sb.Append(c); } break; } } sb.Append("\""); return sb.ToString(); } } As mentioned below - original source: here

  Read the article

• Best way to simplify this code, more efficient

  - by Derek

  My question is, is there a way to make this code more efficient or write it in a simple way? javascript by the way. switch (tempvar1) { case 1: currentSlide = 'slide1'; showaslide('ppslide1'); break; case 2: currentSlide = 'slide2'; showaslide('ppslide2'); break; case 3: currentSlide = 'slide3'; showaslide('ppslide3'); break; case 4: currentSlide = 'slide4'; showaslide('ppslide4'); break; case 5: currentSlide = 'slide5'; showaslide('ppslide5'); break; case 6: currentSlide = 'slide6'; showaslide('ppslide6'); break; // 20 total cases }

  Read the article

• How to remove one instance of one string in PHP?

  - by Jane

  I have a open source editor on the cms that I am making that automatically inserts a <br /> tag at the beginning of the post it submits to the database. This makes validation a pain, since even though there is no real text being submitted, the form still accepts the break tag as input and prevents the "Please enter some text" error from showing. So I tried to remove the opening break tag by filtering my input like this: substr($_POST['content'], 6); This works as long as the user doesn't press the backspace a couple of times which removes the break tag in which case the first 8 characters of the post gets removed even if they are not a break tag. So how can I remove the first 6 characters of the input ONLY if those first 6 characters are composed of the break tag. Also I don't want to remove all break tags, only the one at the very beginning of the post.

  Read the article

• I asked this yesterday, after the input given I'm still having trouble implementing..

  - by Josh

  I'm not sure how to fix this or what I did wrong, but whenever I enter in a value it just closes out the run prompt. So, seems I do have a problem somewhere in my coding. Whenever I run the program and input a variable, it always returns the same answer.."The content at location 76 is 0." On that note, someone told me that "I don't know, but I suspect that Program A incorrectly has a fixed address being branched to on instructions 10 and 11." - mctylr but I'm not sure how to fix that.. I'm trying to figure out how to incorporate this idea from R Samuel Klatchko.. I'm still not sure what I'm missing but I can't get it to work.. const int OP_LOAD = 3; const int OP_STORE = 4; const int OP_ADD = 5; ... const int OP_LOCATION_MULTIPLIER = 100; mem[0] = OP_LOAD * OP_LOCATION_MULTIPLIER + ...; mem[1] = OP_ADD * OP_LOCATION_MULTIPLIER + ...; operand = memory[ j ] % OP_LOCATION_MULTIPLIER; operation = memory[ j ] / OP_LOCATION_MULTIPLIER; I'm new to programming, I'm not the best, so I'm going for simplicity. Also this is an SML program. Anyway, this IS a homework assignment and I'm wanting a good grade on this. So I was looking for input and making sure this program will do what I'm hoping they are looking for. Anyway, here are the instructions: Write SML (Simpletron Machine language) programs to accomplish each of the following task: A) Use a sentinel-controlled loop to read positive number s and compute and print their sum. Terminate input when a neg number is entered. B) Use a counter-controlled loop to read seven numbers, some positive and some negative, and compute + print the avg. C) Read a series of numbers, and determine and print the largest number. The first number read indicates how many numbers should be processed. Without further a due, here is my program. All together. int main() { const int READ = 10; const int WRITE = 11; const int LOAD = 20; const int STORE = 21; const int ADD = 30; const int SUBTRACT = 31; const int DIVIDE = 32; const int MULTIPLY = 33; const int BRANCH = 40; const int BRANCHNEG = 41; const int BRANCHZERO = 41; const int HALT = 43; int mem[100] = {0}; //Making it 100, since simpletron contains a 100 word mem. int operation; //taking the rest of these variables straight out of the book seeing as how they were italisized. int operand; int accum = 0; // the special register is starting at 0 int j; // This is for part a, it will take in positive variables in a sent-controlled loop and compute + print their sum. Variables from example in text. memory [0] = 1010; memory [01] = 2009; memory [02] = 3008; memory [03] = 2109; memory [04] = 1109; memory [05] = 4300; memory [06] = 1009; j = 0; //Makes the variable j start at 0. while ( true ) { operand = memory[ j ]%100; // Finds the op codes from the limit on the memory (100) operation = memory[ j ]/100; //using a switch loop to set up the loops for the cases switch ( operation ){ case 10: //reads a variable into a word from loc. Enter in -1 to exit cout <<"\n Input a positive variable: "; cin >> memory[ operand ]; break; case 11: // takes a word from location cout << "\n\nThe content at location " << operand << "is " << memory[operand]; break; case 20:// loads accum = memory[ operand ]; break; case 21: //stores memory[ operand ] = accum; break; case 30: //adds accum += mem[operand]; break; case 31: // subtracts accum-= memory[ operand ]; break; case 32: //divides accum /=(memory[ operand ]); break; case 33: // multiplies accum*= memory [ operand ]; break; case 40: // Branches to location j = -1; break; case 41: //branches if acc. is < 0 if (accum < 0) j = 5; break; case 42: //branches if acc = 0 if (accum == 0) j = 5; break; case 43: // Program ends exit(0); break; } j++; } return 0; }

  Read the article

• How to add OnClickListener in ViewPager

  - by Erdem Azakli

  I have problem with ViewPager and can't find answer.I want to Toast a message when pictures(view) clicked. I can't make, please help me. Example: click on the picture1 --Message"Picture1" click on the picture2 --Message"Picture2" Thanks a lot, Mypageradapter; package com.example.pictures; import android.content.Context; import android.media.AudioManager; import android.os.Parcelable; import android.support.v4.view.PagerAdapter; import android.support.v4.view.ViewPager; import android.view.LayoutInflater; import android.view.View; public class MyPagerAdapter extends PagerAdapter{ public int getCount() { return 6; } public Object instantiateItem(View collection, int position) { View view=null; LayoutInflater inflater = (LayoutInflater) collection.getContext() .getSystemService(Context.LAYOUT_INFLATER_SERVICE); int resId = 0; switch (position) { case 0: resId = R.layout.picture1; view = inflater.inflate(resId, null); break; case 1: resId = R.layout.picture2; view = inflater.inflate(resId, null); break; case 2: resId = R.layout.picture3; view = inflater.inflate(resId, null); break; case 3: resId = R.layout.picture4; view = inflater.inflate(resId, null); break; case 4: resId = R.layout.picture5; view = inflater.inflate(resId, null); break; case 5: resId = R.layout.picture6; view = inflater.inflate(resId, null); break; } ((ViewPager) collection).addView(view, 0); return view; } @SuppressWarnings("unused") private Context getApplicationContext() { // TODO Auto-generated method stub return null; } private void setVolumeControlStream(int streamMusic) { // TODO Auto-generated method stub } @SuppressWarnings("unused") private Context getBaseContext() { // TODO Auto-generated method stub return null; } @SuppressWarnings("unused") private PagerAdapter findViewById(int myfivepanelpager) { // TODO Auto-generated method stub return null; } @Override public void destroyItem(View arg0, int arg1, Object arg2) { ((ViewPager) arg0).removeView((View) arg2); } @Override public boolean isViewFromObject(View arg0, Object arg1) { return arg0 == ((View) arg1); } @Override public Parcelable saveState() { return null; } public static Integer getItem(int position) { // TODO Auto-generated method stub return null; } } OnPageChangeListener; package com.example.pictures; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.support.v4.view.ViewPager; import android.support.v4.view.ViewPager.OnPageChangeListener; import android.view.View; import android.widget.Button; import android.widget.Toast; public class Pictures extends Activity implements OnPageChangeListener{ SoundManager snd; int sound1,sound2,sound3; View view=null; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.picturespage); MyPagerAdapter adapter = new MyPagerAdapter(); ViewPager myPager = (ViewPager) findViewById(R.id.myfivepanelpager); myPager.setAdapter(adapter); myPager.setCurrentItem(0); myPager.setOnPageChangeListener(this); snd = new SoundManager(this); sound1 = snd.load(R.raw.sound1); sound2 = snd.load(R.raw.sound2); sound3 = snd.load(R.raw.sound3); } public void onPageScrollStateChanged(int arg0) { // TODO Auto-generated method stub } public void onPageScrolled(int arg0, float arg1, int arg2) { // TODO Auto-generated method stub } public void onPageSelected(int position) { // TODO Auto-generated method stub switch (position) { case 0: snd.play(sound1); break; case 1: snd.play(sound2); break; case 2: snd.play(sound3); break; case 3: Toast.makeText(this, "1", Toast.LENGTH_SHORT).show(); break; case 4: Toast.makeText(this, "2", Toast.LENGTH_SHORT).show(); break; case 5: Toast.makeText(this, "3", Toast.LENGTH_SHORT).show(); break; } } };

  Read the article

• Java Program Compiles and Runs, but doesn't work

  - by Richard Long

  When I run this program I enter information in a text box, push the search button, but nothing happens. The program just sits there until I press Cntrl C to break it. It looks like it should work, but I can't figure out what is hanging the program up. Here is the code: First class: import java.io.*; import java.awt.*; import javax.swing.*; import java.awt.event.*; import java.util.*; public class NameGameFrame extends JFrame { public static String name; static JTextField textfield = new JTextField(20); static JTextArea textarea = new JTextArea(30,30); public static String num; public static String [] fields; public static int [] yearRank; public static boolean match; public static int getInts, marker, year, max; public static void main( String[] args) { JFrame frame = new JFrame(); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setTitle("Name Game"); frame.setLocation(500,400); frame.setSize(800,800); JPanel panel = new JPanel(new GridBagLayout()); GridBagConstraints c = new GridBagConstraints(); JLabel label = new JLabel("Enter the Name or Partial Name to search:"); c.gridx = 0; c.gridy = 0; c.insets = new Insets(2,2,2,2); panel.add(label,c); c.gridx = 0; c.gridy = 1; panel.add(textarea,c); JButton button = new JButton("Search"); c.gridx = 1; c.gridy = 1; panel.add(button,c); c.gridx = 1; c.gridy = 0; panel.add(textfield,c); frame.getContentPane().add(panel, BorderLayout.NORTH); frame.pack(); frame.setVisible(true); button.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent ae) { name = textfield.getText(); java.io.File file = new java.io.File("namesdata.txt"); try { Scanner input = new Scanner(file); num = input.nextLine(); NameRecord nr = new NameRecord(name); while (input.hasNext()) { if(match = num.toLowerCase().contains(name.toLowerCase())) { nr.getRank(); nr.getBestYear(marker); } } } catch(FileNotFoundException e) { System.err.format("File does not exist\n"); } textarea.setText(fields[0]); } }); } } This is the second class: import java.io.*; import java.util.*; public class NameRecord { public NameRecord( String name) { } public static int getBestYear(int marker) { switch (marker) { case 1: year = 1900; break; case 2: year = 1910; break; case 3: year = 1920; break; case 4: year = 1930; break; case 5: year = 1940; break; case 6: year = 1950; break; case 7: year = 1960; break; case 8: year = 1970; break; case 9: year = 1980; break; case 10: year = 1990; break; case 11: year = 2000; break; } return year; } public static int getRank() { fields = num.split(" "); max = 0; for (int i = 1; i<12; i++) { getInts = Integer.parseInt(fields[i]); if(getInts>max) { max = getInts; marker = i; } } return max; } }

  Read the article

• input / output error, drives randomly refusing to read / write

  - by ILMV

  I have an issue with one of our servers running Ubuntu 10.04, it is running BackupPC and collects backups from various machines / servers around the building. On the 8th minute (12:08, 12:18, 12:28 etc) the backups are transferred to an external hard drive, we have three and rotate one drive for another everyday. The problem we are having is we are randomly experiencing input / output errors, when this happens you cannot read / write to the drive, it hasn't unmounted so I can cd to the mount point /media/backup1. The drives are not faulty as it's happening on all of them, so I'm at a loss as to what the problem could be, here is an example of the many errors we get: gzip: stdout: Input/output error /var/lib/backuppc/backuppc_offline: line 47: /media/backup1/Tue/offline.log: Input/output error ls: cannot access /media/backup1/Tue/incr_1083_host1.something.co.uk.tar.gz: Input/output error ls: cannot access /media/backup1/Tue/incr_1088_host1.something.co.uk.tar.gz: Input/output error ls: cannot access /media/backup1/Tue/incr_1089_host1.something.co.uk.tar.gz: Input/output error ls: cannot access /media/backup1/Tue/incr_1090_host1.something.co.uk.tar.gz: Input/output error /var/lib/backuppc/backuppc_offline: line 39: /media/backup1/Tue/offline.log: Input/output error /var/lib/backuppc/backuppc_offline: line 44: /media/backup1/Tue/offline.log: Input/output error /var/lib/backuppc/backuppc_offline: line 45: /media/backup1/Tue/incr_1090_host1.something.co.uk.tar.gz: Input/output error /var/lib/backuppc/backuppc_offline: line 47: /media/backup1/Tue/offline.log: Input/output error ls: cannot access /media/backup1/Tue/incr_591_tech2.something.co.uk.tar.gz: Input/output error /var/lib/backuppc/backuppc_offline: line 44: /media/backup1/Tue/offline.log: Input/output error /var/lib/backuppc/backuppc_offline: line 45: /media/backup1/Tue/incr_591_tech2.something.co.uk.tar.gz: Input/output error /var/lib/backuppc/backuppc_offline: line 47: /media/backup1/Tue/offline.log: Input/output error ls: cannot access /media/backup1/Tue/incr_592_tech3.something.co.uk.tar.gz: Input/output error ls: cannot access /media/backup1/Tue/incr_593_tech3.something.co.uk.tar.gz: Input/output error /var/lib/backuppc/backuppc_offline: line 44: /media/backup1/Tue/offline.log: Input/output error /var/lib/backuppc/backuppc_offline: line 45: /media/backup1/Tue/incr_593_tech3.something.co.uk.tar.gz: Input/output error /var/lib/backuppc/backuppc_offline: line 47: /media/backup1/Tue/offline.log: Input/output error EDIT » Resolved So it turns out Quamis was right, even though I didn't think it was possible it was actually a problem with the drive. You see we have three drives all formatted to ext2, on two of them we were getting I/O errors frequently, I cam back to Quamis' answer and discovered the fsck command, so ran it against the problems drives: fsck /dev/sdb1 This found and fixed a load of problems on the drive, most probably caused by power outages / unsafe removal of drives etc, as the drives are in the xt2 format they aren't journalled and thus aren't protected against such issues. Drives are now working beautifully, thanks all! :D

  Read the article

• OSError : [Errno 38] Function not implemented - Django Celery implementation

  - by Jordan Messina

  I installed django-celery and I tried to start up the worker server but I get an OSError that a function isn't implemented. I'm running CentOS release 5.4 (Final) on a VPS: . broker -> amqp://guest@localhost:5672/ . queues -> . celery -> exchange:celery (direct) binding:celery . concurrency -> 4 . loader -> djcelery.loaders.DjangoLoader . logfile -> [stderr]@WARNING . events -> OFF . beat -> OFF [2010-07-22 17:10:01,364: WARNING/MainProcess] Traceback (most recent call last): [2010-07-22 17:10:01,364: WARNING/MainProcess] File "manage.py", line 11, in <module> [2010-07-22 17:10:01,364: WARNING/MainProcess] execute_manager(settings) [2010-07-22 17:10:01,364: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/django/core/management/__init__.py", line 438, in execute_manager [2010-07-22 17:10:01,364: WARNING/MainProcess] utility.execute() [2010-07-22 17:10:01,364: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/django/core/management/__init__.py", line 379, in execute [2010-07-22 17:10:01,365: WARNING/MainProcess] self.fetch_command(subcommand).run_from_argv(self.argv) [2010-07-22 17:10:01,365: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/django/core/management/base.py", line 191, in run_from_argv [2010-07-22 17:10:01,365: WARNING/MainProcess] self.execute(*args, **options.__dict__) [2010-07-22 17:10:01,365: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/django/core/management/base.py", line 218, in execute [2010-07-22 17:10:01,365: WARNING/MainProcess] output = self.handle(*args, **options) [2010-07-22 17:10:01,365: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/django_celery-2.0.0-py2.6.egg/djcelery/management/commands/celeryd.py", line 22, in handle [2010-07-22 17:10:01,366: WARNING/MainProcess] run_worker(**options) [2010-07-22 17:10:01,366: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/bin/celeryd.py", line 385, in run_worker [2010-07-22 17:10:01,366: WARNING/MainProcess] return Worker(**options).run() [2010-07-22 17:10:01,366: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/bin/celeryd.py", line 218, in run [2010-07-22 17:10:01,366: WARNING/MainProcess] self.run_worker() [2010-07-22 17:10:01,366: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/bin/celeryd.py", line 312, in run_worker [2010-07-22 17:10:01,367: WARNING/MainProcess] worker.start() [2010-07-22 17:10:01,367: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/worker/__init__.py", line 206, in start [2010-07-22 17:10:01,367: WARNING/MainProcess] component.start() [2010-07-22 17:10:01,367: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/concurrency/processes/__init__.py", line 54, in start [2010-07-22 17:10:01,367: WARNING/MainProcess] maxtasksperchild=self.maxtasksperchild) [2010-07-22 17:10:01,367: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/concurrency/processes/pool.py", line 448, in __init__ [2010-07-22 17:10:01,368: WARNING/MainProcess] self._setup_queues() [2010-07-22 17:10:01,368: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/concurrency/processes/pool.py", line 564, in _setup_queues [2010-07-22 17:10:01,368: WARNING/MainProcess] self._inqueue = SimpleQueue() [2010-07-22 17:10:01,368: WARNING/MainProcess] File "/usr/local/lib/python2.6/multiprocessing/queues.py", line 315, in __init__ [2010-07-22 17:10:01,368: WARNING/MainProcess] self._rlock = Lock() [2010-07-22 17:10:01,368: WARNING/MainProcess] File "/usr/local/lib/python2.6/multiprocessing/synchronize.py", line 117, in __init__ [2010-07-22 17:10:01,369: WARNING/MainProcess] SemLock.__init__(self, SEMAPHORE, 1, 1) [2010-07-22 17:10:01,369: WARNING/MainProcess] File "/usr/local/lib/python2.6/multiprocessing/synchronize.py", line 49, in __init__ [2010-07-22 17:10:01,369: WARNING/MainProcess] sl = self._semlock = _multiprocessing.SemLock(kind, value, maxvalue) [2010-07-22 17:10:01,369: WARNING/MainProcess] OSError [2010-07-22 17:10:01,369: WARNING/MainProcess] : [2010-07-22 17:10:01,369: WARNING/MainProcess] [Errno 38] Function not implemented Am I just totally screwed and should use a new kernel that has this implemented or is there an easy way to resolve this?

  Read the article

• How to insert a blank line above my copyright text inside the comment lines in intelliJ IDEA?

  - by tim_wonil

  I'm using intelliJ IDEA 9. It has a function to make a copyright profile and apply to all files I create. What I'm trying to do is to format the copyright comment right. Suppose I have a copyright text as this: Copyright (c) 2010 my.company. All rights reserved. I wish it to be inserted in files automatically as following: //////////////////////////////////////////////////////////////////////////////// // // Copyright (c) 2010 my.company. All rights reserved. // //////////////////////////////////////////////////////////////////////////////// But when I enter the line "Copyright (c) 2010 my.company. All rights reserved." in the copyright profile (without quotes) and configure the formatting to use line comment and borders, and so on, I can only make it to display as below: //////////////////////////////////////////////////////////////////////////////// // Copyright (c) 2010 my.company. All rights reserved. //////////////////////////////////////////////////////////////////////////////// Even when I put the copyright text with blank line above and below to the template, as following, it still comes out like above. Copyright (c) 2010 my.company. All rights reserved. It seems to ignore blank lines in the copyright template. Is there any way to configure it so the copyright text will have blank lines above and below within the comments?

  Read the article

• Django 1.4.1 error loading MySQLdb module when attempting 'python manage.py shell'

  - by Paul

  I am trying to set up MySQL, and can't seem to be able to enter the Django manage.py shell interpreter. Getting the output below: rrdhcp-10-32-44-126:django pavelfage$ python manage.py shell Traceback (most recent call last): File "manage.py", line 10, in <module> execute_from_command_line(sys.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 443, in execute_from_command_line utility.execute() File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 382, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 196, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 232, in execute output = self.handle(*args, **options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 371, in handle return self.handle_noargs(**options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/commands/shell.py", line 45, in handle_noargs from django.db.models.loading import get_models File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 40, in <module> backend = load_backend(connection.settings_dict['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 34, in __getattr__ return getattr(connections[DEFAULT_DB_ALIAS], item) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 92, in __getitem__ backend = load_backend(db['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 24, in load_backend return import_module('.base', backend_name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/backends/mysql/base.py", line 16, in <module> raise ImproperlyConfigured("Error loading MySQLdb module: %s" % e) django.core.exceptions.ImproperlyConfigured: Error loading MySQLdb module: No module named _mysql Any suggestions really appreciated.

  Read the article

• "import numpy" tries to load my own package

  - by Sebastian

  I have a python (2.7) project containing my own packages util and operator (and so forth). I read about relative imports, but perhaps I didn't understand. I have the following directory structure: top-dir/ util/__init__.py (empty) util/ua.py util/ub.py operator/__init__.py ... test/test1.py The test1.py file contains #!/usr/bin/env python2 from __future__ import absolute_import # removing this line dosn't change anything. It's default functionality in python2.7 I guess import numpy as np It's fine when I execute test1.py inside the test/ folder. But when I move to the top-dir/ the import numpy wants to include my own util package: Traceback (most recent call last): File "tests/laplace_2d_square.py", line 4, in <module> import numpy as np File "/usr/lib/python2.7/site-packages/numpy/__init__.py", line 137, in <module> import add_newdocs File "/usr/lib/python2.7/site-packages/numpy/add_newdocs.py", line 9, in <module> from numpy.lib import add_newdoc File "/usr/lib/python2.7/site-packages/numpy/lib/__init__.py", line 4, in <module> from type_check import * File "/usr/lib/python2.7/site-packages/numpy/lib/type_check.py", line 8, in <module> import numpy.core.numeric as _nx File "/usr/lib/python2.7/site-packages/numpy/core/__init__.py", line 45, in <module> from numpy.testing import Tester File "/usr/lib/python2.7/site-packages/numpy/testing/__init__.py", line 8, in <module> from unittest import TestCase File "/usr/lib/python2.7/unittest/__init__.py", line 58, in <module> from .result import TestResult File "/usr/lib/python2.7/unittest/result.py", line 9, in <module> from . import util File "/usr/lib/python2.7/unittest/util.py", line 2, in <module> from collections import namedtuple, OrderedDict File "/usr/lib/python2.7/collections.py", line 9, in <module> from operator import itemgetter as _itemgetter, eq as _eq ImportError: cannot import name itemgetter The troublesome line is either from . import util or perhaps from operator import itemgetter as _itemgetter, eq as _eq What can I do?

  Read the article

• Does this use of Monitor.Wait/Pulse have a race condition?

  - by jw

  I have a simple producer/consumer scenario, where there is only ever a single item being produced/consumed. Also, the producer waits for the worker thread to finish before continuing. I realize that kind of obviates the whole point of multithreading, but please just assume it really needs to be this way (: This code doesn't compile, but I hope you get the idea: // m_data is initially null // This could be called by any number of producer threads simultaneously void SetData(object foo) { lock(x) // Line A { assert(m_data == null); m_data = foo; Monitor.Pulse(x) // Line B while(m_data != null) Monitor.Wait(x) // Line C } } // This is only ever called by a single worker thread void UseData() { lock(x) // Line D { while(m_data == null) Monitor.Wait(x) // Line E // here, do something with m_data m_data = null; Monitor.Pulse(x) // Line F } } Here is the situation that I am not sure about: Suppose many threads call SetData() with different inputs. Only one of them will get inside the lock, and the rest will be blocked on Line A. Suppose the one that got inside the lock sets m_data and makes its way to Line C. Question: Could the Wait() on Line C allow another thread at Line A to obtain the lock and overwrite m_data before the worker thread even gets to it? Supposing that doesn't happen, and the worker thread processes the original m_data, and eventually makes its way to Line F, what happens when that Pulse() goes off? Will only the thread waiting on Line C be able to get the lock? Or will it be competing with all the other threads waiting on Line A as well? Essentially, I want to know if Pulse()/Wait() communicate with each other specially "under the hood" or if they are on the same level with lock(). The solution to these problems, if they exist, is obvious of course - just surround SetData() with another lock - say, lock(y). I'm just curious if it's even an issue to begin with.

  Read the article

• System.ArgumentException: Invalid hex character at DecryptAssemblyResource

  - by Radu094

  My webapp is trowing these exceptions intermitently ever since we migrated to Mono + Apache: The error sounds more like a problem reading/processing some assembly, so I was wondering if I should be worried that there might be a problem with the hard-drive? System.ArgumentException: Invalid hex character at System.Web.Configuration.MachineKeySectionUtils.ToHexValue (Char c, Boolean high) [0x00000] in <filename unknown>:0 at System.Web.Configuration.MachineKeySectionUtils.GetBytes (System.String key, Int32 len) [0x00000] in <filename unknown>:0 at System.Web.Handlers.ScriptResourceHandler.GetBytes (System.String val) [0x00000] in <filename unknown>:0 at System.Web.Handlers.ScriptResourceHandler.DecryptAssemblyResource (System.String val, System.String& asmName, System.String& resName) [0x00000] in <filename unknown>:0 at System.Web.Handlers.ScriptResourceHandler.ProcessRequest (System.Web.HttpContext context) [0x00000] in <filename unknown>:0 at System.Web.Handlers.ScriptResourceHandler.System.Web.IHttpHandler.ProcessRequest (System.Web.HttpContext context) [0x00000] in <filename unknown>:0 at System.Web.HttpApplication+<Pipeline>c__Iterator2.MoveNext () [0x00000] in <filename unknown>:0 at System.Web.HttpApplication.Tick () [0x00000] in <filename unknown>:0 Method: Void Application_Error(System.Object, System.EventArgs) at File: at Line Number: 0 Method: Void ProcessError(System.Exception) at File: at Line Number: 0 Method: Void Tick() at File: at Line Number: 0 Method: Void Start(System.Object) at File: at Line Number: 0 Method: Void System.Web.IHttpHandler.ProcessRequest(System.Web.HttpContext) at File: at Line Number: 0 Method: Void Process(System.Web.HttpWorkerRequest) at File: at Line Number: 0 Method: Void RealProcessRequest(System.Object) at File: at Line Number: 0 Method: Void ProcessRequest(System.Web.HttpWorkerRequest) at File: at Line Number: 0 Method: Void ProcessRequest() at File: at Line Number: 0 Method: Void ProcessRequest(Mono.WebServer.MonoWorkerRequest) at File: at Line Number: 0 Method: Void ProcessRequest(Int32, System.String, System.String, System.String, System.String, System.String, Int32, System.String, Int32, System.String, System.String[], System.String[], System.Object) at File: at Line Number: 0 Method: Void InnerRun(System.Object) at File: at Line Number: 0 Method: Void Run(System.Object) at File: at Line Number: 0

  Read the article

• Trying to build the basic python extension example fails (windows)

  - by Alexandros

  Hello, I have Python 2.6 and Visual Studio 2008 running on a Win7 x64 machine. When I try to build the basic python extension example in c "example_nt" as found in the python 2.6 sources distribution, it fails: python setup.py build And this results in: running build running build_ext building 'aspell' extension Traceback (most recent call last): File "setup.py", line 7, in <module> ext_modules = [module1]) File "C:\Python26\lib\distutils\core.py", line 152, in setup dist.run_commands() File "C:\Python26\lib\distutils\dist.py", line 975, in run_commands self.run_command(cmd) File "C:\Python26\lib\distutils\dist.py", line 995, in run_command cmd_obj.run() File "C:\Python26\lib\distutils\command\build.py", line 134, in run self.run_command(cmd_name) File "C:\Python26\lib\distutils\cmd.py", line 333, in run_command self.distribution.run_command(command) File "C:\Python26\lib\distutils\dist.py", line 995, in run_command cmd_obj.run() File "C:\Python26\lib\distutils\command\build_ext.py", line 343, in run self.build_extensions() File "C:\Python26\lib\distutils\command\build_ext.py", line 469, in build_extensions self.build_extension(ext) File "C:\Python26\lib\distutils\command\build_ext.py", line 534, in build_extension depends=ext.depends) File "C:\Python26\lib\distutils\msvc9compiler.py", line 448, in compile self.initialize() File "C:\Python26\lib\distutils\msvc9compiler.py", line 358, in initialize vc_env = query_vcvarsall(VERSION, plat_spec) File "C:\Python26\lib\distutils\msvc9compiler.py", line 274, in query_vcvarsall raise ValueError(str(list(result.keys()))) ValueError: [u'path'] What can I do to fix this? Any help will be appreciated

  Read the article

• Java: Match tokens between two strings and return the number of matched tokens

  - by Cryssie

  Need some help to find the number of matched tokens between two strings. I have a list of string stored in ArrayList (example given below): Line 0 : WRB VBD NN VB IN CC RB VBP NNP Line 1 : WDT NNS VBD DT NN NNP NNP Line 2 : WRB MD PRP VB DT NN IN NNS POS JJ NNS Line 3 : WDT NN VBZ DT NN IN DT JJ NN IN DT NNP Line 4 : WP VBZ DT JJ NN IN NN Here, you can see each string consists of a bunch of tokens separated by spaces. So, there's three things I need to work with.. Compare the first token (WRB) in Line 0 to the tokens in Line 1 to see if they match. Move on to the next tokens in Line 0 until a match is found. If there's a match, mark the matched tokens in Line 1 so that it will not be matched again. Return the number of matched tokens between Line 0 and Line 1. Return the distance of the matched tokens. Example: token NN is found on position 3 on line 0 and position 5 on Line 1. Distance = |3-5| = 2 I've tried using split string and store it to String[] but String[] is fixed and doesn't allow shrinking or adding of new elements. Tried Pattern Matcher but with disasterous results. Tried a few other methods but there's some problems with my nested for loops..(will post part of my coding if it will help). Any advice or pointers on how to solve this problem this would be very much appreciated. Thank you very much.

  Read the article

• How do I stop the m2eclipse plugin interfering with command line mvn builds?

  - by locka

  I use the m2eclipse plugin in Eclipse so that I can import a Maven project. The plugin reads the pom.xml and sorts out the dependencies in the projects in an Eclipse friendly way so I'm not looking at a sea of broken references and errors. I use Eclipse for code development however I usually build the projects from the command line, e.g. "mvn clean install". Unfortunately when I do this, m2eclipse detects disk activity and attempts to rebuild the workspace. This interferes with the command line build and sometimes results in a race condition. For example the command line might be in its clean phase but fails because it tries to delete a file or directory which is locked during the workspace rebuild. Aside from that workspace rebuilding is incredibly slow, and between failed builds and wasted CPU my build process is 2-3x longer than it should be. It isn't an option to not use Eclipse (e.g. to use Netbeans), or to disable m2eclipse. It is a useful plugin except for this behaviour. So my question is, how do I stop m2eclipse from rebuilding the workspace all the time? Can I invoke a manual refresh and otherwise disable this behaviour?

  Read the article

• What does the subversion error "Could not read status line" mean?

  - by Jergason

  Exact duplicate: SVN: Could not read status line: connection was closed by server This is not an exact duplicate. The other question was asking about getting the error in a specific situation, and the answer was vauge at best. This is a fairly basic question, but it is driving me nuts. I have set up a brand new repository at beanstalk.com. They give me the url, http://.svn.beanstalkapp.com/blog. They also automatically create the tag, trunk and branches folder in the repository. I have checked out the trunk folder and used svn add to add the new file. I am trying to do my first commit, but I get this error: Commit failed (details follow): CHECKOUT of '/foo/!svn/bln/1': Could not read status line: connection was closed by server. (http://user_name@my_name.svn.beanstalkapp.com) What does this mean, and what causes it? I have googled for a definition of what "Could not read status line" means, but was unable to find anything explaining it. edit: I was getting this error while trying to manipulate my repository from behind a firewall. I still don't know what was causing it, but I don't have this problem at home. Strangeness.

  Read the article

• Java: how to tell if a line in a text file was supposed to be blank?

  - by defn

  I'm working on a project in which I have to read in a Grammar file (breaking it up into my data structure), with the goal of being able to generate a random "DearJohnLetter". My problem is that when reading in the .txt file, I don't know how find out whether the file was supposed to be a completely blank line or not, which is detrimental to the program. Here is an example of part of the file, How do i tell if the next line was supposed to be a blank line? (btw I'm just using a buffered reader) Thanks! <start> I have to break up with you because <reason> . But let's still <disclaimer> . <reason> <dubious-excuse> <dubious-excuse> , and also because <reason> <dubious-excuse> my <person> doesn't like you I'm in love with <another> I haven't told you this before but <harsh> I didn't have the heart to tell you this when we were going out, but <harsh> you never <romantic-with-me> with me any more you don't <romantic> any more my <someone> said you were bad news

  Read the article

• I want to read program content from command line.

  - by Alexandre Dominos

  I am trying to update a program which was wrotten in 1995 with pascal or c. I am not sure about programming language. Command line program. Now I am coded in C#. And I want to read program command line content. Is it possible? I tried something. But not succesfull. They are: private void aboutToolStripMenuItem_Click(object sender, EventArgs e) { // Redirect the output stream of the child process. p.StartInfo.UseShellExecute = false; p.StartInfo.RedirectStandardOutput = true; p.StartInfo.FileName = "osl.exe"; p.Start(); logs.AppendText("Timer Started\n"); timer1.Enabled = true; } private void timer1_Tick(object sender, EventArgs e) { // write somethingg and read what is the program doing on command line? // What is the program printint? etc... // I try this code but not enough for mo. // logs.AppendText("d:" + p.StandardOutput.ReadToEnd()+"\n"); } private void p_Exited(object sender, EventArgs e) { timer1.Enabled = false; } i am open to any idea in java,cpp,c,c#.

  Read the article

• Delphi trace tool

  - by Max

  I was wondering if there's a tool or a component for Delphi that can trace method execution line by line and create a log file. With this kind of tool it is easy to compare how method performs on two sets of input data by comparing two log files. EDIT: Let's say there is a function 10: function MyFunction(aInput: Integer): Integer; 11: begin 12: if aInput 10 then 13: Result := 10 14: else 15: Result := 0; 16: end; I'm looking for a tool that would give the log which whould be similar to the following: When aInput parameter is 1: Line 10: 'function MyFunction(aInput: Integer): Integer;' Line 11: 'begin' Line 12: 'if aInput 10 then' Line 15: 'Result := 0;' Line 16: 'end;' and when aInput parameter is 11: Line 10: 'function MyFunction(aInput: Integer): Integer;' Line 11: 'begin' Line 12: 'if aInput 10 then' Line 13: 'Result := 10;' Line 16: 'end;' The only information that should be required by the tool is the function name. It's like stepping through the method under debugger, but in an automatic manner with logging every line of code.

  Read the article

• Controlling Movie Clips from the main time line instead of using their individual time lines?

  - by Jess

  I have a Flash website template (four pages) that I made using AS 3.0 and Flash CS4. It is for an assignment involving movie clips. Currently on the main time line there is only one frame, and three layers: actions/menu/content. The actionscript on the main time line is simply: content_mc.stop (); There is a movie clip on the stage called “Content” that contains the content for each of the pages. Inside of that there is a “Menu” movie clip that contains and controls all of the navigation buttons. The actionscript for the Menu movie clip is: function homeBtnPress (event:MouseEvent):void{ //comments here //comments here MovieClip(parent).content_mc.gotoAndStop("home"); } function aboutBtnPress (event:MouseEvent): void{ MovieClip(parent).content_mc.gotoAndStop ("about"); } function servicesBtnPress (event:MouseEvent): void{ MovieClip (parent).content_mc.gotoAndStop ("services"); } function contactBtnPress (event:MouseEvent): void{ MovieClip (parent).content_mc.gotoAndStop ("contact"); } function portfolioBtnPress (event:MouseEvent): void{ MovieClip (parent).content_mc.gotoAndStop ("portfolio"); } home.addEventListener(MouseEvent.CLICK, homeBtnPress); about.addEventListener(MouseEvent.CLICK, aboutBtnPress); services.addEventListener(MouseEvent.CLICK, servicesBtnPress); contact.addEventListener(MouseEvent.CLICK, contactBtnPress); portfolio.addEventListener(MouseEvent.CLICK, portfolioBtnPress); So everything works fine, but my instructor wants me to control the menu/content from the main time line by using the target path tool. What exactly would I target – just the “menu” and “content” movie clips, and what code would I use? Sorry if I'm not explaining very well, I'm pretty confused. Here is the feedback from my instructor: “While we learned how to control the main timeline and the timeline of another movie clip from within a movie clip, this is not the most intuitive way to script and makes for difficult debugging. So you will need to explore how to target your buttons inside of your menu movie clip and the frames within the content movie clip from the main timeline. “ Thanks so much in advance!

  Read the article

• how do I get a new line, after using float:left?

  - by codeman73

  What I am trying to do is have rows of images, 6 images in each row. Some of these images need to have another image floating on top of them (flush with the lower-right corner). I was able to get that to work from this thread: http://stackoverflow.com/questions/48474/how-do-i-position-one-image-on-top-of-another-in-html However, now I'm unable to get the new row after the 6th image. Neither <BR> or <P> create a new line. They simply push the next image down several pixels, but the image is still in the same line. It seems like the float style is interfering with the <BR> and/or <P>. I tried using different styles for the image that starts a new row, like float:none and display:block, but neither worked. The odd thing is that the new line starts after the 7th image. Here's what I'm using so far: <style type="text/css"> .containerdiv { float: left; position: relative; } .containerdivNewLine { float: none; display: block; position: relative; } .cornerimage { position: absolute; bottom: 0; right: 0; } </style> <div class="containerdiv"> <img border="0" height="188" src="myImg" width="133" /> <img class="cornerimage" height="140" src="imageOnTop" width="105" /> </div> For the 7th image, when I'm trying to start a new row, I'm simply replacing the 'containerdiv' class with 'containerdivNewLine'.

  Read the article

< Previous Page | 165 166 167 168 169 170 171 172 173 174 175 176  | Next Page >