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• delete everything before last comma

  - by clankill3r

  I want to delete everything before the last tab (or comma). For example, in this sentence: Hoe treedt een gevestigd instituut als het Nederlands Openluchtmuseum, alom geassocieerd met ambacht en traditie, buiten zijn grenzen op zoek naar vernieuwing? should be naar vernieuwing? Ik heb ruim 6 weken geleden een boek besteld en ik wacht nog steeds,enig idee hoe lang dit wachten nog gaat duren? should be enig idee hoe lang dit wachten nog gaat duren? I tried this, "^(.*\t+)+" but that doesn't work.

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• MySQL Join Comma Separated Field

  - by neeraj

  I have two tables. First Table is a batch table that contain comma separated student id in field "batch" batch -------------- id batch -------------- 1 1,2 2 3,4 Second Table is marks marks ---------------------- id studentid subject marks 1 1 English 50 2 2 English 40 3 3 English 70 4 1 Math 65 5 4 English 66 6 5 English 75 7 2 Math 55 How we can find those students of first batch id =1 who have scored more than 45 marks in English without using sub query. Problem i found to get this done using a single query is that we can not use IN as an association operator in JOIN statement What changes are required in below query to make it work? SELECT * FROM batch INNER JOIN marks ON marks.studentid IN(batch.batch) where batch.id = 1

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• Which programming languages, other than C++, support operator overloading?

  - by vitaly.v.ch

  I know C++. Anything other?

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• Comma separated values in a database field

  - by John Doe

  I have a products table. Each row in that table corresponds to a single product and it's identified by a unique Id. Now each product can have multiple "codes" associated with that product. For example: Id | Code ---------------------- 0001 | IN,ON,ME,OH 0002 | ON,VI,AC,ZO 0003 | QA,PS,OO,ME What I'm trying to do is create a stored procedure so that I can pass in a codes like "ON,ME" and have it return every product that contains the "ON" or "ME" code. Since the codes are comma separated, I don't know how I can split those and search them. Is this possible using only TSQL? Edit: It's a mission critical table. I don't have the authority to change it.

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• How to specify comma , space unicode value in app.config(C#3.0)

  - by Newbie

  In the app.config file if I use <add key = "FileDelimeter" value ="&#2c;"/> as unicode for COMMA, it is throwing error Invalid character in a decimal number 'c' For SPACE, <add key = "FileDelimeter" value ="&#20;"/> the error is Character'', hex value 0*14 is illegal in xml while <add key = "FileDelimeter" value ="&#09;"/> for "\t" worked. Where is the mistake? Kindly give a generic solution. Thanks

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• String.Format with NumberGroupSeparator outputting 0xa0 not comma

  - by andrevdm

  I'm seeing strange results when doing a string.Format( "C" ); E.g. double val = 123456.78; Console.WriteLine( val.ToString( "C" ) ); This prints the thousand separator as 0xa0 rather than a comma (0x2c). I get the same result if I use string.Format( "{0:0,0.00}", 1234567.12D ); Here is the full output R 123ÿ456,78 52333A333233 201230456C78 My regional settings are English (South African) and I'm getting the same result on multiple machines. Any ideas? Thanks.

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• Script throwing unexpected operator when using mysqldump

  - by Astron

  A portion of a script I use to backup MySQL databases has stopped working correctly after upgrading a Debian box to 6.0 Squeeze. I have tested the backup code via CLI and it works fine. I believe it is in the selection of the databases before the backup occurs, possibly something to do with the $skipdb variable. If there is a better way to perform the function then I'm will to try something new. Any insight would be greatly appreciated. $ sudo ./script.sh [: 138: information_schema: unexpected operator [: 138: -1: unexpected operator [: 138: mysql: unexpected operator [: 138: -1: unexpected operator Using bash -x script here is one of the iterations: + for db in '$DBS' + skipdb=-1 + '[' test '!=' '' ']' + for i in '$IGGY' + '[' mysql == test ']' + : + '[' -1 == -1 ']' ++ /bin/date +%F + FILE=/backups/hostname.2011-03-20.mysql.mysql.tar.gz + '[' no = yes ']' + /usr/bin/mysqldump --single-transaction -u root -h localhost '-ppassword' mysql + /bin/tar -czvf /backups/hostname.2011-03-20.mysql.mysql.tar.gz mysql.sql mysql.sql + rm -f mysql.sql Here is the code. if [ $MYSQL_UP = "yes" ]; then echo "MySQL DUMP" >> /tmp/update.log echo "--------------------------------" >> /tmp/update.log DBS="$($MYSQL -u $MyUSER -h $MyHOST -p"$MyPASS" -Bse 'show databases')" for db in $DBS do skipdb=-1 if [ "$IGGY" != "" ] ; then for i in $IGGY do [ "$db" == "$i" ] && skipdb=1 || : done fi if [ "$skipdb" == "-1" ] ; then FILE="$DEST$HOST.`$DATE +"%F"`.$db.mysql.tar.gz" if [ $ENCRYPT = "yes" ]; then $MYSQLDUMP -u $MyUSER -h $MyHOST -p"$MyPASS" $db > $db.sql && $TAR -czvf - $db.sql | $OPENSSL enc -aes-256-cbc -salt -out $FILE.enc -k $ENC_PASS && rm -f $db.sql else $MYSQLDUMP --single-transaction -u $MyUSER -h $MyHOST -p"$MyPASS" $db > $db.sql && $TAR -czvf $FILE $db.sql && rm -f $db.sql fi fi done fi

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• Guru of the Week 2 no match for the operator==

  - by Adam

  From Guru of the Week 2. We have the function: string FindAddr(const list<Employee> l, string name) { for( list<Employee>::const_iterator i = l.begin(); i != l.end(); i++) { if( *i == name ) // here will be compilation error { return (*i).addr; } } return ""; } I added dummy Employee class to that: class Employee { string n; public: string addr; Employee(string name) : n(name) {} Employee() {} string name() const { return n; } operator string() { return n; } }; And got compilation error: error: no match for ‘operator==’ in ‘i.std::_List_iterator<_Tp>::operator* [with _Tp = Employee]() == name’ It works only if add operator== to Employee. But, Herb Sutter wrote that: The Employee class isn't shown, but for this to work it must either have a conversion to string or a conversion ctor taking a string. But Employee has a conversion function and conversion constructor as well. GCC version 4.4.3. Compiled normally, g++ file.cpp without any flags. There should be implicit conversion and it should work, why it doesn't?

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• operator << : std::cout << i << (i << 1);

  - by Oops

  Hi, I use the stream operator << and the bit shifting operator << in one line. I am a bit confused, why does code A) not produce the same output than code B)? A) int i = 4; std::cout << i << " " << (i << 1) << std::endl; //4 8 B) myint m = 4; std::cout << m << " " << (m << 1) << std::endl; //8 8 class myint: class myint { int i; public: myint(int ii) { i = ii; } inline myint operator <<(int n){ i = i << n; return *this; } inline operator int(){ return i; } }; thanks in advance Oops

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• Custom types as key for a map - C++

  - by Appu

  I am trying to assign a custom type as a key for std::map. Here is the type which I am using as key. struct Foo { Foo(std::string s) : foo_value(s){} bool operator<(const Foo& foo1) { return foo_value < foo1.foo_value; } bool operator>(const Foo& foo1) { return foo_value > foo1.foo_value; } std::string foo_value; }; When used with std::map, I am getting the following error. error C2678: binary '<' : no operator found which takes a left-hand operand of type 'const Foo' (or there is no acceptable conversion) c:\program files\microsoft visual studio 8\vc\include\functional 143 If I change the struct like the below, everything worked. struct Foo { Foo(std::string s) : foo_value(s) {} friend bool operator<(const Foo& foo,const Foo& foo1) { return foo.foo_value < foo1.foo_value; } friend bool operator>(const Foo& foo,const Foo& foo1) { return foo.foo_value > foo1.foo_value; } std::string foo_value; }; Nothing changed except making the operator overloads as friend. I am wondering why my first code is not working? Any thoughts?

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• defining < operator for map of list iterators

  - by Adrian

  I'd like to use iterators from an STL list as keys in a map. For example: using namespace std; list<int> l; map<list<int>::const_iterator, int> t; int main(int argv, char * argc) { l.push_back(1); t[l.begin()] = 5; } However, list iterators do not have a comparison operator defined (in contrast to random access iterators), so compiling the above code results in an error: /usr/include/c++/4.2.1/bits/stl_function.h:227: error: no match for ‘operator<’ in ‘__x < __y’ If the list is changed to a vector, a map of vector const_iterators compiles fine. What is the appropriate way to define the operator < for list::const_iterator?

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• Allow member to be const while still supporting operator= on the class

  - by LeopardSkinPillBoxHat

  I have several members in my class which are const and can therefore only be initialised via the initialiser list like so: class MyItemT { public: MyItemT(const MyPacketT& aMyPacket, const MyInfoT& aMyInfo) : mMyPacket(aMyPacket), mMyInfo(aMyInfo) { } private: const MyPacketT mMyPacket; const MyInfoT mMyInfo; }; My class can be used in some of our internally defined container classes (e.g. vectors), and these containers require that operator= is defined in the class. Of course, my operator= needs to do something like this: MyItemT& MyItemT::operator=(const MyItemT& other) { mMyPacket = other.mPacket; mMyInfo = other.mMyInfo; return *this; } which of course doesn't work because mMyPacket and mMyInfo are const members. Other than making these members non-const (which I don't want to do), any ideas about how I could fix this?

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• Regex issue with comma's telling me there are 6 args, instead of intended 4

  - by Azher

  I have a scenario outline table that looks like the following: Scenario Outline: Verify Full ad details Given I am on the xxx classified home page And I have entered <headline> in the search field & clicked on search When I click on full details Then I should see <headline> <year> <mileage> <price> displaying correctly and successfully Examples: |headline |year |mileage |price | |alfa romeo 166 |2005 |73,000 |6,990 | When I run my scenario it spits out that I have 6 args. But what I thought, I should only have 4 args: headline, year, mileage and price. I am thinking that it is taking the comma's and what is before and after it as two seperate args. Is there any way that I can make cucumber think that there are only 4 args with the example below? I have looked at messing around with regex but I dont seem to be getting anywhere. Any help would be greatly appreciated.

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• Concatenation Operator

  - by Chaitanya

  This might be a silly question but it struck me, and here i ask. <?php $x="Hi"; $y=" There"; $z = $x.$y; $a = "$x$y"; echo "$z"."<br />"."$a"; ?> $z uses the traditional concatenation operator provided by php and concatenates, conversely $a doesn't, My questions: by not using the concatenation operator, does it effect the performance? If it doesn't why at all have the concatenation operator. Why have 2 modes of implementation when one does the work?

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• Concatenation Operator - PHP

  - by Chaitanya

  This might be a silly question but it struck me, and here i ask. <?php $x="Hi"; $y=" There"; $z = $x.$y; $a = "$x$y"; echo "$z"."<br />"."$a"; ?> $z uses the traditional concatenation operator provided by php and concatenates, conversely $a doesn't, My questions: a. by not using the concatenation operator, does it effect the performance? b. If it doesn't why at all have the concatenation operator. c. Why have 2 modes of implementation when one does the work?

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• Understanding pattern matching with cons operator

  - by Mathias

  In "Programming F#" I came across a pattern-matching like this one (I simplified a bit): let rec len list = match list with | [] -> 0 | [_] -> 1 | head :: tail -> 1 + len tail;; Practically, I understand that the last match recognizes the head and tail of the list. Conceptually, I don't get why it works. As far as I understand, :: is the cons operator, which appends a value in head position of a list, but it doesn't look to me like it is being used as an operator here. Should I understand this as a "special syntax" for lists, where :: is interpreted as an operator or a "match pattern" depending on context? Or can the same idea be extended for types other than lists, with other operators?

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• Cann Boost Program_options separate comma separated argument values

  - by lrm

  If my command line is: > prog --mylist=a,b,c Can Boost's program_options be setup to see three distinct argument values for the mylist argument? I have configured program_options as: namespace po = boost::program_options; po::options_description opts("blah") opts.add_options() ("mylist", std::vector<std::string>>()->multitoken, "description"); po::variables_map vm; po::store(po::parse_command_line(argc, argv, opts), vm); po::notify(vm); When I check the value of the mylist argument, I see one value as a,b,c. I'd like to see three distinct values, split on comma. This works fine if I specify the command line as: > prog --mylist=a b c or > prog --mylist=a --mylist=b --mylist=c Is there a way to configure program_options so that it sees a,b,c as three values that should each be inserted into the vector, rather than one? I am using boost 1.41, g++ 4.5.0 20100520, and have enabled c++0x experimental extensions.

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• Should I make OR operator to return const reference or just reference

  - by Yan Cheng CHEOK

  class error_code { public: error_code() : hi(0), lo(0) {} error_code(__int64 lo) : hi(0), lo(lo) {} error_code(__int64 hi, __int64 lo) : hi(hi), lo(lo) {} error_code& operator|=(const error_code &e) { this->hi |= e.hi; this->lo |= e.lo; return *this; } __int64 hi; __int64 lo; }; error_code operator|(const error_code& e0, const error_code& e1) { return error_code(e0.hi | e1.hi, e0.lo | e1.lo); } int main() { error_code e0(1); error_code e1(2); e0 |= e1; } I was wondering, whether I should make operator|= to return a const error_code& or error_code& ?

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• comma separated values in oracle function body

  - by dmitry

  I've got following oracle function but it does not work and errors out. I used Ask Tom's way to convert comma separated values to be used in select * from table1 where col1 in <> declared in package header: TYPE myTableType IS table of varchar2 (255); Part of package body: l_string long default iv_value_with_comma_separated|| ','; l_data myTableType := myTableType(); n NUMBER; begin begin LOOP EXIT when l_string is null; n := instr( l_string, ',' ); l_data.extend; l_data(l_data.count) := ltrim( rtrim( substr( l_string, 1, n-1 ) ) ); l_string := substr( l_string, n+1 ); END LOOP; end; OPEN my_cursor FOR select * from table_a where column_a in (select * from table (l_data)); CLOSE my_cursor END; above fails but it works fine when I remove select * from table (l_data) Can someone please tell me what I might be doing wrong here??

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• XSL - How to match consecutive comma-separated tags

  - by PocketLogic

  I'm trying to match a series of xml tags that are comma separated, and to then apply an xslt transformation on the whole group of nodes plus text. For example, given the following partial XML: <p>Some text here <xref id="1">1</xref>, <xref id="2">2</xref>, <xref id="3">3</xref>. </p> I would like to end up with: <p>Some text here ^1,2,3.</p> A much messier alternate would also be acceptable at this point: <p>Some text here ¹^,²^,³.</p> I have the transformation to go from a single xref to a sup: <xsl:template match="xref""> ^{<xsl:apply-templates/>} </xsl:template> But I'm at a loss as to how to match a group of nodes separated by commas. Thanks.

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• Does dynamic_cast work inside overloaded operator delete ?

  - by iammilind

  I came across this: struct Base { void* operator new (size_t); void operator delete (void*); virtual ~Base () {} // <--- polymorphic }; struct Derived : Base {}; void Base::operator delete (void *p) { Base *pB = static_cast<Base*>(p); if(dynamic_cast<Derived*>(pB) != 0) { /* ... NOT reaching here ? ... */ } free(p); } Now if we do, Base *p = new Derived; delete p; Surprisingly, the condition inside the Base::delete is not satisfied Am I doing anything wrong ? Or casting from void* looses the information of Derived* ?

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• (C++) What's the difference between these overloaded operator functions?

  - by cv3000

  What is the difference between these two ways of overloading the != operator below. Which is consider better? Class Test { ...// private: int iTest public: BOOL operator==(const &Test test) const; BOOL operator!=(const &Test test) const; } BOOL operator==(const &Test test) const { return (iTest == test.iTest); } //overload function 1 BOOL Test::operator!=(const &Test test) const { return !operator==(test); } //overload function 2 BOOL Test::operator!=(const &Test test) const { return (iTest != test.iTest); } I've just recently seen function 1's syntax for calling a sibling operator function and wonder if writing it that way provides any benefits.

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• Can Boost Program_options separate comma separated argument values

  - by lrm

  If my command line is: > prog --mylist=a,b,c Can Boost's program_options be setup to see three distinct argument values for the mylist argument? I have configured program_options as: namespace po = boost::program_options; po::options_description opts("blah") opts.add_options() ("mylist", std::vector<std::string>>()->multitoken, "description"); po::variables_map vm; po::store(po::parse_command_line(argc, argv, opts), vm); po::notify(vm); When I check the value of the mylist argument, I see one value as a,b,c. I'd like to see three distinct values, split on comma. This works fine if I specify the command line as: > prog --mylist=a b c or > prog --mylist=a --mylist=b --mylist=c Is there a way to configure program_options so that it sees a,b,c as three values that should each be inserted into the vector, rather than one? I am using boost 1.41, g++ 4.5.0 20100520, and have enabled c++0x experimental extensions.

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• Why can't we have an immutable version of operator[] for map

  - by Yan Cheng CHEOK

  The following code works fine : std::map<int, int>& m = std::map<int, int>(); int i = m[0]; But not the following code : // error C2678: binary '[' : no operator... const std::map<int, int>& m = std::map<int, int>(); int i = m[0]; Most of the time, I prefer to make most of my stuff to become immutable, due to reason : http://www.javapractices.com/topic/TopicAction.do?Id=29 I look at map source code. It has mapped_type& operator[](const key_type& _Keyval) Is there any reason, why std::map unable to provide const mapped_type& operator[](const key_type& _Keyval) const

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• Is the "==" operator required to be defined to use std::find

  - by user144182

  Let's say I have: class myClass std::list<myClass> myList where myClass does not define the == operator and only consists of public fields. In both VS2010 and VS2005 the following does not compile: myClass myClassVal = myList.front(); std::find( myList.begin(), myList.end(), myClassVal ) complaining about lack of == operator. I naively assumed it would do a value comparison of the myClass object's public members, but I am almost positive this is not correct. I assume if I define a == operator or perhaps use a functor instead, it will solve the problem. Alternatively, if my list was holding pointers instead of values, the comparison would work. Is this right or should I be doing something else?

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