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• Error or not and insert to database mysql

  - by Azzyh

  Why wont this work? <?php include "top.php"; include "connect.php"; if(isset($_POST["submit"])) { $error = ""; if(empty($_POST["name"])) { $error .= "Du glömde märket!<br>"; if(empty($_POST["rating"])){ $error .= "Du glömde att bedömma märket!<br>"; if(empty($_POST["worth"])){ $error .= "Du glömde att välja vilken klass den hör till!<br>"; if(empty($_POST["username"])){ $error .= "Du glömde att skriva ditt namn!<br>"; if(empty($_POST["rating"])){ $error .= "Du glömde att skriva någonting?!!<br>"; }}}}} if(!empty($error)){ echo $error; }else{ $name = $_POST["name"]; $rating = $_POST["rating"]; $worth = $_POST["worth"]; $favorite = $_POST["favorite"]; $username = $_POST["username"]; $description = $_POST["description"]; mysql_query("INSERT INTO brands (name, rating, worth, favorite, username, description) VALUES ('$name', '$rating', '$worth', '$favorite', '$username', '$description')"); echo "<span style='color: green'>Yir yir, <a href='brand.php'>klicka här för att gå till Märken.</a></span>"; } } It doesnt come with errors it just say the succeed message like it has inserted to database

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• mysql to excel genration using php

  - by pmms

  <?php // DB Connection here mysql_connect("localhost","root",""); mysql_select_db("hitnrunf_db"); $select = "SELECT * FROM jos_users "; $export = mysql_query ( $select ) or die ( "Sql error : " . mysql_error( ) ); $fields = mysql_num_fields ( $export ); for ( $i = 0; $i < $fields; $i++ ) { $header .= mysql_field_name( $export , $i ) . "\t"; } while( $row = mysql_fetch_row( $export ) ) { $line = ''; foreach( $row as $value ) { if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data"; ? the above code is used for genrating mysql to excel sheet but we are getting following error the file youare trying to open, 'users.xls',is in a different format than specified by the file extension. verify that the file is not corrupted and is from a trusted source before opening the file. do you want to open the file now?

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• Array to Array pushing in Zend Session object

  - by kate-koopy

  Hello! I have some example of pushing array to array in session object: class someClass extends someOtherOne { ...////// some other code here that starts session and creates namespace public function __add2Session($a,$b) { $namespc = $this -> __getnewNameSpace(); //returns a Zend Session Namesapce (object) if (!isset($namespc -> {$a})) { $namespc -> {$a} = array(); } array_push($namespc -> {$a}, $b); } } ...///////////// $item=array(1=>"one",2=>"two",3=>"three",4=>"four",5=>"five",6=>"six",7=>"seven"); $k = new someClass(); $cart = new Zend_Session_Namespace('Cart'); $k -> __add2Session("items",$item); The result is when I reload the page several times - the value of $cart -> items in the session gets overwritten and not populated. Can somebody explain why it occurs and how do I fix this? I want to have $cart -> items to be an "array in array" like: $cart -> items = array(array(1=>"one",2=>"two"), array(1=>"two",2=>"three"));

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• AJAX filter MySQL results using checkboxes

  - by keepitnang

  I'm attempting to get to grips with displaying filterable MySQL data within a PHP page based on user checkbox selections. I have a database of domain names and the dates on which these will require renewal as per Nominet DAC information and I can get unfiltered data to display, but filtering results by domain extensions is proving tricky for me to accomplish. I should point out at this stage that I am a serious newcomer to many of the ideas I am trying to learn to work with here, so please be gentle. I have tried following some other articles on here also, but no dice. I have the following so far: HTML <input type="checkbox" class="extensions" name="extensions" value=".co.uk">.co.uk</input> <input type="checkbox" class="extensions" name="extensions" value=".org.uk">.org.uk</input> Script $('.extensions').live('click', function() { var all_boxes = $('.extensions'); var all_boxes_values = []; var i = 0; for (var i; i < all_boxes.length; i++) { if (all_boxes[i].checked) { all_boxes_values.push(all_boxes[i].value) } } var all_boxes_values_clean = all_boxes_values.join(", "); console.log(all_boxes_values_clean); $.get("sql-test.php", {q: all_boxes_values_clean}, function(result) { $("div#output").html(result); } )}); PHP $g = $_GET['q']; $extensionsql=""; $extension=1; if(isset($g)) { $extension=1; $param = "" . str_replace(",", "','", $_GET['q']) . ""; } And that's as far as I have gotten with my limited ability. What I would like to do next is search the column domainName for a string match and return the appropriate results to the user. Something to mimic something like the following but I'm not sure how to achieve it. Any help would be much appreciated: SELECT * FROM `refresh` WHERE `domainName` LIKE '%.co.uk%' AND renewalDate LIKE '%2012-06-30%' ORDER BY `domainName` ASC Thanks

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• How to print contents from a session variable by looping in a foreach statement

  - by itsover9000

  im trying to write a code where can print and loop through the contents of my session variable by using a foreach statement here is my code <form class="form form-inline" method = "post" action="reportmaker.php"> <select name="rfield"> <option value="">--Select Field--</option> <?php $sc2=mysql_query("SELECT * from searchcolumn s left join report_fields r on s.scol_id=r.field_id where s.category != 'wh'"); foreach($sc2 as $sc){ ?> <option value="<?php echo $sc[advsearch_col]; ?>"><?php echo $sc[advsearch_name]; ?></option> <?php } ?> </select> <button type="submit" value = "submit" id="add" name="add" class="btn pull-right">Add More</button> </form> <?php if(isset($_POST['add'])) { $_SESSION['temp'][]=$_POST['rfield']; } if($_SESSION[temp][]!=""){ foreach($_SESSION[temp][] as $temp) { echo $temp; } } ?> the error that appears with this code is Fatal error: Cannot use [] for reading the line where the error is is this if($_SESSION[temp][]!=""){ i need to print the contents of the session array and this is the only way i know how is there a way to fix this? thanks =========EDIT thanks for the answers guys i finally got it

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• Working with PHP and MySQL - need a good and secure design with OO design

  - by Andrew

  I am new to PHP- first time developer. I am working on my web application and it is nearly done; nevertheless, most of my sql was done directly via code using direct mysql requests. This is the way I approached it: In classes_db.php I declared the db settings and created methods that I use to open and close DB connections. I declare those objects on my regular pages: class classes_db { public $dbserver = 'server; public $dbusername = 'user'; public $dbpassword = 'pass'; public $dbname = 'db'; function openDb() { $dbhandle = mysql_connect($this->dbserver, $this->dbusername, $this->dbpassword); if (!$dbhandle) { die('Could not connect: ' . mysql_error()); } $selected = mysql_select_db($this->dbname, $dbhandle) or die("Could not select the database"); return $dbhandle; } function closeDb($con) { mysql_close($con); } } On my regular page, I do this: <?php require 'classes_db.php'; session_start(); //create instance of the DB class $db = new classes_db(); //get dbhandle $dbhandle = $db->openDb(); //process query $result = mysql_query("update user set username = '" . $usernameFromForm . "' where iduser= " . $_SESSION['user']->iduser); //close the connection if (isset($dbhandle)) { $db->closeDb($dbhandle); } ?> My questions is: how to do it right and make it OO and secure? I know that I need incorporate prepared queries- how to do it the best way? Please provide some code

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• Why does this sql statement keep saying it is a boolean and not a paramter? (php/Mysql)

  - by ggfan

  In this statement, I am trying to see if there if the latest posting in the database that has the exact same title, price, city, state, detail. If there is, then it would say to the user that the exact post has been already made; if not then insert the posting into the dbc. (This is one type of check so that users can't accidentally post twice. This may not be the best check, but this statement error is annoying me, so I want it to work :)) Why won't this sql work? I think it's not letting the title=$title and not getting the value in the $title... ERROR: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in postad.php on line 365 //there is a form that users fill out that has title, price, city, etc <form> blah blah </form> //if users click submit, then does all the checks and if all okay, insert to dbc if (isset($_POST['submit'])) { // Grab the pposting data from the POST and gets rid of any funny stuff $title = mysqli_real_escape_string($dbc, trim($_POST['title'])); $price = mysqli_real_escape_string($dbc, trim($_POST['price'])); $city = mysqli_real_escape_string($dbc, trim($_POST['city'])); $state = mysqli_real_escape_string($dbc, trim($_POST['state'])); $detail = mysqli_real_escape_string($dbc, trim($_POST['detail'])); if (!is_numeric($price) && !empty($price)) { echo "<p class='error'>The price can only be numbers. No special characters, etc</p>"; } //Error problem...won't let me set title=$title, detail=$detail, etc. //this statement after all the checks so that none of the variables are empty $query="Select * FROM posting WHERE user_id={$_SESSION['user_id']} AND title=$title AND price=$price AND city=$city AND state=$state AND detail=$detail"; $data = mysqli_query($dbc, $query); if(mysqli_num_rows($data)==1) { echo "You already posted this ad. Most likely caused by refreshing too many times."; } }

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• supplied argument is not a valid MySQL result

  - by jasmine

  I have written a function: function selectWithPaging($where){ $pg = (int) (!isset($_GET["pg"]) ? 1 : $_GET["pg"]); $pg = ($pg == 0 ? 1 : $pg); $perpage = 10;//limit in each page $startpoint = ($pg * $perpage) - $perpage; $result = mysql_query("SELECT * FROM $where ORDER BY id ASC LIMIT $startpoint,$perpage"); return $result; } but when inserting in this function : function categories() { selectWithPaging('category') $text .='<h2 class="mainH">Categories</h2>'; $text .= '<table><tr class="cn"><td>ID</td><td class="name">Category</td> <td>Durum</td>'; while ($row = mysql_fetch_array($result)) { $home = $row['home']; $publish = $row['published']; $ID = $row['id']; $src = '<img src="'.ADMIN_IMG.'homec.png">'; ------------- } there is this error: supplied argument is not a valid MySQL result What is wrong in my first function? Thanks in advance

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• PHP Pass Dynamic Array name to function

  - by Brad

  How do I pass an array key to a function to pull up the right key's data? // The array <?php $var['TEST1'] = Array ( 'Description' => 'This is a Description', 'Version' => '1.11', 'fields' => Array( 'ID' => array( 'type' => 'int', 'length' =>'11', 'misc' =>'auto_increment' ), 'DATA' => array( 'type' => 'varchar', ' length' => '255' ) ); $var['TEST2'] = Array ( 'Description' =? 'This is the 2nd Description', 'Version' => '2.1', 'fields' => Array( 'ID' => array( 'type' => 'int', 'length' =>'11', 'misc' =>'auto_increment' ), 'DATA' => array( 'type' => 'varchar', ' length' => '255' ) ) // The function <?php $obj = 'TEST1'; print_r($schema[$obj]); // <-- Fives me output. But calling the function doesn't. echo buildStructure($obj); /** * @TODO to add auto_inc support */ function buildStructure($obj) { $output = ''; $primaryKey = $schema["{$obj}"]['primary key']; foreach ($schema["{$obj}"]['fields'] as $name => $tag) // #### ERROR #### Invalid argument supplied for foreach() { $type = $tag['type']; $length = $tag['length']; $default = $tag['default']; $description = $tag['description']; $length = (isset($length)) ? "({$length})" : ''; $default = ($default == NULL ) ? "NULL" : $default; $output .= "`{$name}` {$type}{$length} DEFAULT {$default} COMMENT `{$DESCRIPTION}`, "; } return $output; }

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• unicode convertion problem

  - by bhoomi-nature

  Hai frnds i am bhoomi new to php,i am having having below problem in my coding please can you help anyone 1.first i want to open one word document which is having content and i wann to edit it 2.for that i am opening word document from the server and at that time its opening with garbage value(i thing its not converting to utf8 format) 3.wen i delete that garbage value and insert something from textarea to that file it is going to insert and next time onwords its its getting open properly. 4.actually i wann that doc file should open with english words wats there in that doc instead of garbage value..first time opening only its giving problem. i am using below code for that please do the needful $filename = 'test.doc'; if(isset($_REQUEST['Submit'])){ $somecontent = stripslashes($_POST['somecontent']); // Let's make sure the file exists and is writable first. if (is_writable($filename)) { // In our example we're opening $filename in append mode. // The file pointer is at the bottom of the file hence // that's where $somecontent will go when we fwrite() it. if (!$handle = fopen($filename, 'w')) { echo "Cannot open file ($filename)"; exit; } // Write $somecontent to our opened file. if (fwrite($handle, $somecontent) === FALSE) { echo "Cannot write to file ($filename)"; exit; } echo "Success, wrote ($somecontent) to file ($filename) - Continue - "; fclose($handle); } else { echo "The file $filename is not writable"; } } else{ // get contents of a file into a string $handle = fopen($filename, 'r'); $somecontent = fread($handle, filesize($filename)); ? Edit file

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• Could this be considered a well-written class (am I using OOP correctly)?

  - by Ben Dauphinee

  I have been learning OOP principals on my own for a while, and taken a few cracks at writing classes. What I really need to know now is if I am actually using what I have learned correctly, or if I could improve as far as OOP is concerned. I have chopped a massive portion of code out of a class that I have been working on for a while now, and pasted it here. To all you skilled and knowledgeable programmers here I ask: Am I doing it wrong? class acl extends genericAPI{ // -- Copied from genericAPI class protected final function sanityCheck($what, $check, $vars){ switch($check){ case 'set': if(isset($vars[$what])){return(1);}else{return(0);} break; } } // --------------------------------- protected $db = null; protected $dataQuery = null; public function __construct(Zend_Db_Adapter_Abstract $db, $config = array()){ $this->db = $db; if(!empty($config)){$this->config = $config;} } protected function _buildQuery($selectType = null, $vars = array()){ // Removed switches for simplicity sake $this->dataQuery = $this->db->select( )->from( $this->config['table_users'], array('tf' => '(CASE WHEN count(*) > 0 THEN 1 ELSE 0 END)') )->where( $this->config['uidcol'] . ' = ?', $vars['uid'] ); } protected function _sanityRun_acl($sanitycheck, &$vars){ switch($sanitycheck){ case 'uid_set': if(!$this->sanityCheck('uid', 'set', $vars)){ throw new Exception(ERR_ACL_NOUID); } $vars['uid'] = settype($vars['uid'], 'integer'); break; } } private function user($action = null, $vars = array()){ switch($action){ case 'exists': $this->_sanityRun_acl('uid_set', $vars); $this->_buildQuery('user_exists_idcheck', $vars); return($this->db->fetchOne($this->dataQuery->__toString())); break; } } public function user_exists($uid){ return($this->user('exists', array('uid' => $uid))); } } $return = $acl_test->user_exists(1);

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• Appending a TR to Table Not Formatting Correctly

  - by TimNguyenBSM

  My PHP script is sending back an array: $currentStatus = ( isset( $status ) ) ? "1" : "0"; $html = "<tr><td>" . $email . "</td><td>" . ( ( $status->type == 0 ) ? "View Only" : ( ( $status->type == 1 ) ? "View & Mark" : "View, Mark & Edit" ) ) . "</td><td>Invited</td></tr>"; echo json_encode( array( $html, $currentStatus ) ); Then my jquery is appending this to the table: ... success: function( result ) { var resultArray = eval( result ); $( "#myTable tr:last").append( resultArray[0] ); ... } Problem is, when it prints, it prints the following extra marks: [email protected]<\/td> View Only<\/td> Invited<\/td><\/tr>","1"] If I only echo the HTML it appends to table just fine, but I cant do that because I need the $currentStatus back too to do something with it. Thanks!

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• Big task - problems with page refresh and ajax

  - by user1830414

  I have a navigation which load dynamically content via ajax. But if I refresh the page or visit another url and go back the current content is away and I see the old content under the first menu tab. Now I have to solve this problem. The index.php include the elements header_registrated.inc.php, navigation.inc.php and main_container.inc.php index.php: <?php include("inc/incfiles/header_registrated.inc.php"); ?> <?php if (!isset($_SESSION["userLogin"])) { echo "<meta http-equiv=\"refresh\" content=\"0; url=http://localhost/project\">"; } else { echo ""; } ?> <?php include("inc/incfiles/navigation.inc.php"); ?> <?php include("inc/incfiles/main_container.inc.php"); ?> <?php include("inc/incfiles/footer.inc.php"); ?> header_registrated.inc.php: <?php include ("inc/scripts/mysql_connect.inc.php"); session_start(); $user = $_SESSION["userLogin"]; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>title</title> <link href="css/style.css" rel="stylesheet" type="text/css" /> <script language="JavaScript" src="js/framework/jquery.js"></script> <script language="JavaScript" src="js/dropdown/window.js"></script> <script language="JavaScript" src="js/navigation/navigation.js"></script> </head> <body> </body> navigation.inc.php: <div class="navigation"> <ul> <li id="1"> <div id="menuImage1" class="menuImage"></div> <div class="menuText"><p>Punkt 1</p></div> <div class="navigationDart"></div> </li> <li id="2"> <div id="menuImage2" class="menuImage"></div> <div class="menuText"><p>Punkt 2</p></div> </li> <li id="3"> <div id="menuImage3" class="menuImage"></div> <div class="menuText"><p>Punkt 3</p></div> </li> <li id="4"> <div id="menuImage4" class="menuImage"></div> <div class="menuText"><p>Punkt 4</p></div> </li> <li id="5"> <div id="menuImage5" class="menuImage"></div> <div class="menuText"><p>Punkt 5</p></div> </li> <li id="6"> <div id="menuImage6" class="menuImage"></div> <div class="menuText"><p>Punkt 6</p></div> </li> </ul> </div> main_container.inc.php: <div class="mainContainer"> <div class="containerHeader"> <div class="contentHeader"> </div> </div> <div class="contentContainer"> <div class="content"> </div> <div class="advertisement"> </div> </div> </div> Now the divs content, cnotentHeader and advertisement (in file main_content.inc.php) is filled via ajax. Also the navigation has some jquery effects which also have to be the same after page refresh. navigation.js: $(document).ready(function() { $.get('inc/incfiles/content_container/header/1.php', function(data) { $('.contentHeader').html(data); }); $.get('inc/incfiles/content_container/content/1.php', function(data) { $('.content').html(data); }); $.get('inc/incfiles/content_container/advertisement/1.php', function(data) { $('.advertisement').html(data); }); var current = '1.php'; $(".navigation li").click(function() { var quelle = $(this).attr('id') + ".php"; // the current content doesn't load again if(current === quelle) { return; } current = quelle; // content $(".content").fadeOut(function() { $(this).load("inc/incfiles/content_container/content/" + quelle).fadeIn('normal'); }) // advertisement $(".advertisement").fadeOut(function() { $(this).load("inc/incfiles/content_container/advertisement/" + quelle).fadeIn('normal'); }) // header $(".contentHeader").fadeOut(function() { $(this).load("inc/incfiles/content_container/header/" + quelle).fadeIn('normal'); }) }); $(".navigation li").click(function() { $(".menuImage").removeClass("menuImageActive1"); $(".menuImage").removeClass("menuImageActive2"); $(".menuImage").removeClass("menuImageActive3"); $(".menuImage").removeClass("menuImageActive4"); $(".menuImage").removeClass("menuImageActive5"); $(".menuImage").removeClass("menuImageActive6"); }); $("#1").mousedown(function() { $("#menuImage1").addClass("menuImageClick1"); // new class on mouse button press }); $("#1").mouseup(function() { $("#menuImage1").removeClass("menuImageClick1"); //remove class after mouse button release }); $("#1").click(function() { $("#menuImage1").addClass("menuImageActive1"); }); $("#2").mousedown(function() { $("#menuImage2").addClass("menuImageClick2"); // new class on mouse button press }); $("#2").mouseup(function() { $("#menuImage2").removeClass("menuImageClick2"); //remove class after mouse button release }); $("#2").click(function() { $("#menuImage2").addClass("menuImageActive2"); }); $("#3").mousedown(function() { $("#menuImage3").addClass("menuImageClick3"); // new class on mouse button press }); $("#3").mouseup(function() { $("#menuImage3").removeClass("menuImageClick3"); //remove class after mouse button release }); $("#3").click(function() { $("#menuImage3").addClass("menuImageActive3"); }); $("#4").mousedown(function() { $("#menuImage4").addClass("menuImageClick4"); // new class on mouse button press }); $("#4").mouseup(function() { $("#menuImage4").removeClass("menuImageClick4"); //remove class after mouse button release }); $("#4").click(function() { $("#menuImage4").addClass("menuImageActive4"); }); $("#5").mousedown(function() { $("#menuImage5").addClass("menuImageClick5"); // new class on mouse button press }); $("#5").mouseup(function() { $("#menuImage5").removeClass("menuImageClick5"); //remove class after mouse button release }); $("#5").click(function() { $("#menuImage5").addClass("menuImageActive5"); }); $("#6").mousedown(function() { $("#menuImage6").addClass("menuImageClick6"); // new class on mouse button press }); $("#6").mouseup(function() { $("#menuImage6").removeClass("menuImageClick6"); //remove class after mouse button release }); $("#6").click(function() { $("#menuImage6").addClass("menuImageActive6"); }); $("#1").click(function(){ $(".navigationDart").animate({ top: "16px" }, 500 ); }); $("#2").click(function(){ $(".navigationDart").animate({ top: "88px" }, 500 ); }); $("#3").click(function(){ $(".navigationDart").animate({ top: "160px" }, 500 ); }); $("#4").click(function(){ $(".navigationDart").animate({ top: "232px" }, 500 ); }); $("#5").click(function(){ $(".navigationDart").animate({ top: "304px" }, 500 ); }); $("#6").click(function(){ $(".navigationDart").animate({ top: "376px" }, 500 ); }); }); My idea was it to work with if(isset($_SESSION['ajaxresponse'])) but I don't no how to do this. Please help me. I have the feeling that I've searched the whole web to find an answer.

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• php session_start() error

  - by tooepic

  Hi, i've used a sample found on online and applied it to my code: <?php session_start(); if (isset($_REQUEST["email"])) { $_SESSION["name"] = true; $host = $_SERVER["HTTP_HOST"]; $path = dirname($_SERVER["PHP_SELF"]); $sid = session_name() . "=" . session_id(); header("Location: index.php?$sid"); exit; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> ... ... and rest of the html code When I open this page, I got an error: Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /data/server/user/directory/sub-directory/login.php:1) in /data/server/user/directory/sub-directory/login.php on line 2 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /data/server/user/directory/sub-directory/login.php:1) in /data/server/user/directory/sub-directory/login.php on line 2 I looked around to resolve this issue and saw few posts about this in this site also, but I just can't get a good grip on this...can't find the answer. Please help. Thanks.

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• Prevent empty form input array from being posted?

  - by user355295

  Sorry if this has been answered somewhere; I'm not quite sure how to phrase the problem to even look for help. Anyway, I have a form with three text input boxes, where the user will input three song titles. I have simple PHP set up to treat those input boxes as an array (because I may want, say, 100 song titles in the future) and write the song titles to another document. <form method="post"> <input type="text" name="songs[]" value="" /> <input type="text" name="songs[]" value="" /> <input type="text" name="songs[]" value="" /> <button type="submit" name="submit" value="submit">Submit</button> </form> <?php if (isset($_POST['submit'])) { $open = fopen("test.html", "w"); if(empty($_POST['songs'])) { } else { $songs = $_POST['songs']; foreach($songs as $song) { fwrite($open, $song."<br />"); }; }; }; ?> This correctly writes the song titles to an external file. However, even when the input boxes are empty, the external file will still be written to (just with the <br />'s). I'd assumed that the if statement would ensure nothing would happen if the boxes were blank, but that's obviously not the case. I guess the array's not really empty like I thought it was, but I'm not really sure what implications that comes with. Any idea what I'm doing wrong? (And again, I am clueless when it comes to PHP, so forgive me if this has been answered a million times before, if I described it horribly, etc.)

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• opening word document contailning macros using textarea

  - by avani-nature

  Hai frnds i am avani here,actually 1.i amhaving one word document which contains macros i wann to open it in textarea.. 2.i am able to open the word document which is not containing macros 3.i am not able to open the document which contains macros 4.i am using below code 5.please do help me anyone i am thinking its some what impossible { //echo $aud; $filename = 'C:/xampp/htdocs/mts/sites/default/files/a.doc'; //echo $filename; if(isset($_REQUEST['Save'])){ $somecontent = stripslashes($_POST['somecontent']); // Let's make sure the file exists and is writable first. if (is_writable($filename)) { // In our example we're opening $filename in append mode. // The file pointer is at the bottom of the file hence // that's where $somecontent will go when we fwrite() it. if (!$handle = fopen($filename, 'w')) { echo "Cannot open file ($filename)"; exit; } // Write $somecontent to our opened file. if (fwrite($handle, $somecontent) === FALSE) { echo "Cannot write to file ($filename)"; exit; } echo "Success, wrote ($somecontent) to file ($filename) - Continue - "; fclose($handle); } else { echo "The file $filename is not writable"; } } else{ // get contents of a file into a string $handle = fopen($filename, "r"); $somecontent = fread($handle, filesize($filename)); $word = new COM("word.application") or die ("Could not initialise MS Word object."); $word-Documents-Open(realpath("$filename")); // Extract content. $somecontent = (string) $word-ActiveDocument-Content; //echo $somecontent; $word-ActiveDocument-Close(false); $word-Quit(); $word = null; unset($word); fclose($handle); } ? Edit file -------- ?

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• Want to convert whole PHP script in RUBY ON RAILS

  - by user303058

  // set image quality (from 0 to 100, not applicable to gif) $imgquality = 100; // get data from $_POST or $_GET ? $data = &$_POST; // get image dimensions $width = (int) $data['width']; $height = (int) $data['height']; // create image object $img = imagecreatetruecolor($width, $height); // populate image with pixels for ($y = 0; $y < $height; $y++) { // innitialize $x = 0; // get row data $row = explode(',', $data['r'.$y]); // place row pixels $cnt = sizeof($row); for ($r = 0; $r < $cnt; $r++) { // get pixel(s) data $pixel = explode(':', $row[$r]); // get color $pixel[0] = str_pad($pixel[0], 6, '0', STR_PAD_LEFT); $cr = hexdec(substr($pixel[0], 0, 2)); $cg = hexdec(substr($pixel[0], 2, 2)); $cb = hexdec(substr($pixel[0], 4, 2)); // allocate color $color = imagecolorallocate($img, $cr, $cg, $cb); // place repeating pixels $repeat = isset($pixel[1]) ? (int) $pixel[1] : 1; for ($c = 0; $c < $repeat; $c++) { // place pixel imagesetpixel($img, $x, $y, $color); // iterate column $x++; } } } // set proper content type header('Content-type: image/'.$imgtype); header('Content-Disposition: attachment; filename="chart.'.$imgtype.'"'); // stream image $function = 'image'.$imgtype; if ($imgtype == 'gif') { $function($img); } else { $function($img, null, $imgquality); } // destroy imagedestroy($img); ?

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• Problem with mysql query in paging

  - by jasmine

  I have a very simple paging and mysql query. Im not sure that my query is right: $perPage =4; $page= (isset($GET['page']) && is_numeric($GET['page'])) ? $_GET['page'] : 1; $start = ($page * $perPage ) - $perPage ; if (is_numeric($_GET['cID'])){$cid = $_GET['cID'];} $totalCount = sprintf("SELECT COUNT(*) as 'Total' FROM content WHERE catID = %d", $cid ) ; $count = mysql_query($totalCount); $rowCount = mysql_fetch_array($count); $sql = sprintf("SELECT id, title, abstract, content_image FROM content WHERE catID = %d ORDER BY id DESC LIMIT %d, %d", $cid, $start, $perPage ); $query = mysql_query($sql) or die(mysql_error()); while($row = mysql_fetch_array($query)){ echo $row['id'].' : '. $row['title'] .'<br>'; } with /categories.php?cID=1&page=2 and /categories.php?cID=1&page=1 The output is: 95 : titlev 94 : titlex 93 : titlec 92 : titleb and not changed. What is wrong in my query? Thanks in advance

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• php import larg table to phpmyadmin database

  - by safaali

  hi, I am so worry :( I dropped one of the tables from the database accidentally. fortunately, I have back-up. (I have used the "Auto backup for mysql") The back-up of the table is stored as .txt file (56 Megabytes) on my PC. I tried to import it by PhpMyAdmin and the import failed because the file is too large to import. then I uploaded the file to /home/tablebk directory. I have some experiences in php. I know that I would import it with this code, but i don't know the sql statment for this import. what is have to put as $line variable? please help me :( :( <?php $dbhost = 'localhost'; $dbuser = 'mysite'; $dbpw = 'password'; $dbname = 'databasename'; $file = @fopen('country.txt', 'r'); if ($file) { while (!feof($file)) { $line = trim(fgets($file)); $flag = mysql_query($line); if (isset($flag)) { echo 'Insert Successfully<br />'; } else { echo mysql_error() . '<br/>'; } flush(); } fclose($file); } echo '<br />End of File'; ?>

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• PHP & HTML Purifier Error: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given

  - by TaG

  I'm trying to Integrate HTML Purifier http://htmlpurifier.org/ to filter my user submitted data but I get the following error below. And I was wondering how can I fix this problem? I get the following error. on line 22: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given line 22 is. if (mysqli_num_rows($dbc) == 0) { Here is the php code. if (isset($_POST['submitted'])) { // Handle the form. require_once '../../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); // replace with your encoding $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); // replace with your doctype $purifier = new HTMLPurifier($config); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, profile.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $about_me = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['about_me'])); $interests = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['interests'])); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO profile (user_id, about_me, interests) VALUES ('$user_id', '$about_me', '$interests')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE profile SET about_me = '$about_me', interests = '$interests' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } }

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• Can I use php SESSIONS in spotify apps?

  - by user1593846

  since PHP can't be used in Spotify apps directly I am using it on my server only, but I am having problems getting the sessions to work, is it possible to use sessions even? I want to use it to see if a user is registered in my database or not so I am doing it like this: session_start(); $query="SELECT * FROM user WHERE facebookID = {$fbid}"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result); $num_results = mysql_num_rows($result); if ($num_results > 0) { echo"THERE IS A USER!"; $row['facebookID'] = $_SESSION[fid]; } else { echo"THERE IS NO USER!"; } the authentication to the server works fine but the session does not seem to be working, on another PHP page witch is being called after the above code has been called with some ajax code I simply wanted to try this: session_start(); if(isset($_SESSION['fid'])) { echo"SESSION EXIST"; } else { echo"NO SESSION"; } anyways is there a special way to do this in Spotify apps or do I have to do this in some other way?

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• Upload image from URL to FTP server using PHP

  - by user1807556

  I want to upload a picture from another site to my FTP server using PHP. Example: File to upload("http://page.mi.fu-berlin.de/krudolph/stuff/stackoverflow.png") FTP-path("pictures/") This is what I've already tried: 1 $image = file_get_contents("http://img.youtube.com/vi/Rz8KW4Tveps/1.jpg"); file_put_contents("imgfolder/imgID.jpg", $image); 2 copy('http://img.youtube.com/vi/Rz8KW4Tveps/1.jpg', 'imgfolder/imgID.jpg'); 3 <?php set_time_limit (24 * 60 * 60); if (!isset($_POST['submit'])) die(); $file = fopen ($url, "rb"); if ($file) { $newf = fopen ($newfname, "wb"); if ($newf) while(!feof($file)) { fwrite($newf, fread($file, 1024 * 2000 ), 1024 * 2000 ); } } if ($file) { fclose($file); } if ($newf) { fclose($newf); } ?> 4 http://www.teckdevil.com/php-server-to-server-transfer-script-to-remotely-transfer-files/ 5 (kinda the same as first linked) Download files directly to my server # I don't get any errors when I'm running the scripts and I have chmod the directory to 777.

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• Password protect user image album

  - by Poland Rocks

  Hi Im making i photo sharint site I want to give the ability for my users to prevent the public to acces their albums with a password. Then they can give the password to the ones they want to be able to see it. To password protect their albums. Im thinking something like this, cant test it on this computer, should work ok. but as im a php/mysql beginner i wanna hear what you experts think if theres a better way/approach Albums id name owner password (if it isnt null the album is considered password protected) The code $id = isset($_GET['albumID']) ? intval($_GET['albumID']) : 0; $result = mysql_query("SELECT * FROM albums WHERE id = $id"); $row = mysql_fetch_object($result); // IS it password protected? if ($row->password != NULL) { echo "This album is password protected."; // User pressed "Enter" if (!empty($_POST['password'])) { $result = mysql_query("SELECT password FROM albums WHERE password = '".mysql_real_escape_string($_POST['password'])."'"); // Was It right password? if (mysql_num_rows($result) == 1) { $authed=1; } echo << <form method="post"> <input type="text" name="password" /> EOT; exit; } else $authed=1; if $authed==1 { // render albumimages etc }

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• MySQL/PHP Search Efficiency

  - by iMaster

  Hi! I'm trying to create a small search for my site. I've tried using full-text index search, but I could never get it to work. Here is what I've come up with: if(isset($_GET['search'])) { $search = str_replace('-', ' ', $_GET['search']); $result = array(); $titles = mysql_query("SELECT title FROM Entries WHERE title LIKE '%$search%'"); while($row = mysql_fetch_assoc($titles)) { $result[] = $row['title']; } $tags = mysql_query("SELECT title FROM Entries WHERE tags LIKE '%$search%'"); while($row = mysql_fetch_assoc($tags)) { $result[] = $row['title']; } $text = mysql_query("SELECT title FROM Entries WHERE entry LIKE '%$search%'"); while($row = mysql_fetch_assoc($text)) { $result[] = $row['title']; } $result = array_unique($result); } So basically, it searches through all the titles, body-text, and tags of all the entries in the DB. This works decently well, but I'm just wondering how efficient would it be? This would only be for a small blog, too. Either way I'm just wondering if this could be made any more efficient.

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• Logging in with sha1() encryption.

  - by Samir Ghobril

  Hey guys, I added this to my sign up code : $password=mysql_real_escape_string(sha1($_POST['password'])); and now it inserts the password into the database while its encrypted. But signing in doesn't seem to work anymore. Here is the login code. function checklogin($username, $password){ global $mysqli; $password=sha1($password); $result = $mysqli->prepare("SELECT * FROM users WHERE username = ? and password=?"); $result->bind_param("ss", $username, $password); $result->execute(); if($result != false){ $dbArray=$result->fetch(); if(!$dbArray){ echo '<p class="statusmsg">The username or password you entered is incorrect, or you haven\'t yet activated your account. Please try again.</p><br/><input class="submitButton" type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } $_SESSION['username']=$username; if(isset($_POST['remember'])){ setcookie("jmuser",$username,time()+60*60*24*356); setcookie("jmpass",$password ,time()+60*60*24*356); } redirect(); }

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